Tamil Nadu 11th Std Model Question Paper Physics

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No. of Printed Pages : 11
3417 (NS)
!3417NSIstYearPhysics! £vÄ Gs
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PART - III
C¯Ø¤¯À / PHYSICS

( uªÌ ©ØÖ® B[Q» ÁÈ / Tamil & English Version)

Põ» AÍÄ : 3.00 ©o ÷|µ® ] [ ö©õzu ©v¨ö£sPÒ : 70
Time Allowed : 3.00 Hours ] [ Maximum Marks : 70

AÔÄøµPÒ : (1) AøÚzx ÂÚõUPЮ \›¯õP¨ £vÁõQ EÒÍuõ GߣuøÚa
\›£õºzxU öPõÒÍÄ®. Aa_¨£vÂÀ SøÓ°¸¨¤ß, AøÓU
PsPõo¨£õÍ›h® EhÚi¯õPz öu›ÂUPÄ®.
(2) }»® AÀ»x P¸¨¦ ø©°øÚ ©mk÷© GÊxÁuØS®
AiU÷PõikÁuØS® £¯ß£kzu ÷Ásk®. £h[PÒ ÁøµÁuØS
ö£ß]À £¯ß£kzuÄ®.

Instructions : (1) Check the question paper for fairness of printing. If there is any lack of
fairness, inform the Hall Supervisor immediately.

(2) Use Blue or Black ink to write and underline and pencil to draw diagrams.

£Sv – I / PART - I
SÔ¨¦ : (i) AøÚzx ÂÚõUPÐUS® Âøh¯ÎUPÄ®. 15x1=15
(ii) öPõkUP¨£mkÒÍ ©õØÖ ÂøhPÎÀ ªPÄ® Hئøh¯
Âøhø¯z ÷uº¢öukzxU SÔ±mkhß Âøh°øÚ²® ÷\ºzx
GÊuÄ®.
Note : (i) Answer all the questions.
(ii) Choose the most appropriate answer from the given four alternatives and
write the option code and the corresponding answer.

[ v¸¨¦P / Turn over

3417 (NS) 2

1. J¸•øÚ ‰i-¯ PõØ-Öz u®-£® JßÖ 83 Hz AvºöÁs Eøh¯ Avº-Ä-Ö®
ö£õ-¸-Ð-hß Jz-u-vºÄ Aøh-Q-Óx GÛÀ, PõØ-Öz u®-£z-vß }Í® : (PõØ-ÔÀ
J¼-°ß vø\-÷Á-P® = 332 ms−1)

(-A) 1.5 m (B) 0.5 m (C) 2.0 m (D) 1.0 m
An air column in a pipe which is closed at one end, is in resonance with the vibrating
body of frequency 83 Hz. Then the length of the air column is : (velocity of sound in
air = 332 ms−1)

(a) 1.5 m (b) 0.5 m (c) 2.0 m (d) 1.0 m

2. 20 kg {øÓ-²-øh¯ J¸ ö£õ-¸Ò 10 ms−1 ÷ÁPz-vÀ ÁÊ-Áʨ-£õÚ J¸
Qøhz-uÍ £µ¨-¤À C¯[-QU öPõs-i-¸US® ÷£õx _¸Ò ©õ-Ô¼ 5 N/m
öPõsh J¸ {øÓ¯ØÓ _¸Ò ÂÀ-÷»õk ÷©õ-xQÓx. ÷©õv¯ ¤ß A¢u
{øÓ°ß C¯U- P ® {ßÖ Âk- Q - Ó - x GÛÀ, _¸Ò- Â À- ¼ ß A•U- P ¨- £ mh
öuõ-ø»Ä GßÚ ?

(-A) 10 m (B) 50 m (C) 5 m (D) 20 m
A body of mass 20 kg moving with a speed of 10 ms−1 on a horizontal smooth surface
collides with a massless spring of spring constant 5 N/m. If the mass stops after
collision, distance of compression of the spring will be :

(a) 10 m (b) 50 m (c) 5m (d) 20 m

3. ©Ûu ö\Â En- µ U- T - i ¯ Aø»- } Í ö|kU- P ® (PõØ- Ô À J¼- ° ß
vø\-÷Á-P® = 340 ms−1 ) :

(-A) 17 m •uÀ 170 m (B) 0.17 m •u-À 17 m

(C) 0.017 m •uÀ 17 m (D) 1.7 m •uÀ 17 m
Human audible wavelength range (velocity of sound in air = 340 ms−1) is :

(a) 17 m to 170 m (b) 0.17 m to 17 m

(c) 0.017 m to 17 m (d) 1.7 m to 17 m

3 3417 (NS)

4. ö£õ-¸-öÍõß-Ôß }Í® 3.51 m GÚ AÍ-Âh¨-£m-kÒÍx. xÀ-¼-¯z-ußø©
0.01 m GÛÀ, AÍ-Ãm-iß ÂÊUPõm-k¨-¤øÇ :

(-A) 0.035% (B) 351% (C) 1% (D) 0.28%

The length of a body is measured as 3.51 m. If the accuracy is 0.01 m, then the percentage
error in the measurement is :

(a) 0.035% (b) 351% (c) 1% (d) 0.28%

5. {ø»-©z v¸¨-¦z-v-Ó-Ûß £›-©õn Áõ´¨-£õk :

(-A) ML−1T−1 (B) ML2T−2 (C) MLT2 (D) ML2

The dimensional formula for Moment of Inertia :

(a) ML−1T−1 (b) ML2T−2 (c) MLT2 (d) ML2

6. RÌU-Põ-q® AÍ-Ä-P-ÎÀ Gx ì÷P-»õº ?

(-A) ÷ÁP® (B) vø\-÷Á-P®

(C) Ch¨-ö£-¯ºa-] (D) ÷|ºU-÷Põmk E¢-u®

Which one of the following is a scalar quantity ?

(a) Speed (b) Velocity

(c) Displacement (d) Linear momentum

[ v¸¨¦P / Turn over

3417 (NS) 4

7. ¤ß-Á-¸-Á-Ú-ÁØ-ÖÒ Gx Kµ-»-S öÁU-hº ?

∧ ∧ ∧ ∧
∧ j
(-A) i + j i
∧ ∧
(B) i + j (C) (D) k−
2 2 2

Identify the unit vector in the following :

∧ ∧ ∧ ∧
i+ j ∧ ∧ i ∧ j
(a) (b) i+ j (c) (d) k−
2 2 2

8. ¦ÂU-S® `›-¯-ÝU-S-ª-øh÷¯ EÒÍ öuõ-ø»Ä C¸-©-h[-Põ-ÚõÀ, Kµõsk
Gß-£x Gz-uøÚ |õm-PÒ ?

(-A) 730 (B) 1032 (C) 64.5 (D) 182.5

If the distance between the Earth and Sun is twice its present value, the number of
days in a year will be :

(a) 730 (b) 1032 (c) 64.5 (d) 182.5

9. J¸ SÔ¨- ¤ mh öÁ¨- £ - { - ø »- ° À Áõ² ‰»U- T - Ö - P - Î ß- \µõ- \ › C¸- © i
‰» ÷Á- P ® ©Ø- Ö ® ªP- Ä ® \õz- v - ¯ - © õÚ ÷ÁP[- P - Ð US Cøh- ÷ ¯- ¯ õÚ
ÂQ-u®:

(-A) 2 2 : 1 (B) 3: 2 (C) 2: 3 (D) 1:2 2

The ratio between the rms speed and most probable speed of gas molecules at a given
temperature is :

(a) 2 2: 1 (b) 3: 2 (c) 2: 3 (d) 1:2 2

5 3417 (NS)

10. öPõ- k U- P ¨- £ mh P-V Áøµ- £ - h z- v À AÊz- u ® ©õ- Ó õ A•UP {PÌ- ø ÁU
SÔ¨-£x Gx ?

(-A) (B)

(C) (D)

Which one of the following P-V diagrams corresponds to isobaric compression ?

(a) (b)

(c) (d)

[ v¸¨¦P / Turn over

3417 (NS) 6

11. ÁøÍ-Äa \õø» Jß-ÔÀ Põº JßÖ vj-öµßÖ Ch-x ¦Ó-©õ-Pz v¸®¦® ÷£õx
AU-Põ-›-¾ÒÍ £¯-o-PÒ Á»-x ¦Ó-©õ-Pz uÒͨ-£-k-Á-uØS, ¤ß-Á-¸-Á-Ú-ÁØ-ÖÒ
Gx Põ-µ-n-©õP Aø©-²® ?
(-A) {ø»-©-©ØÓ uß-ø© (B) vø\-°À {ø»-©®
(C) -C-¯U-Pz-vÀ {ø»-©® (D) K´-ÂÀ {ø»-©®
When a car takes a sudden left turn on a curved road, passengers are pushed towards
the right due to :
(a) absence of inertia (b) inertia of direction
(c) inertia of motion (d) inertia of rest

12. k GßÓ Âø\©õ- Ô ¼ öPõsh J¸ _- ¸ Ò- Â À J¸xsk ©Ø- ö Óõß- ø Ó- Â h
C¸-©-h[S }Í® EÒÍ-ÁõÖ C¸-xs-k-PÍõP öÁm-h¨-£-k-Q-Óx. }Í-©õÚ
xsk ö£Ø-ÖÒÍ Âø\ ©õ-Ô-¼-¯õ-Úx :
2 3
(-A) 6k (B) 3 k (C) 2 k (D) 3k
A spring of force constant k is cut into two pieces such that the length of one piece is
double the length of the other. Then the longer piece will have a force constant of :
2 3
(a) 6k (b) k (c) k (d) 3k
3 2

13. M {øÓ, l }Í® ©Ø-Ö® r Bµ® öPõsh J¸ vs© E¸-øÍ-°ß Aaø\
£Ø-Ô¯ {ø»© v¸¨¦vÓß :
 r2 l2 
(-A) M  +  (B) Mr2
 2 12 

1 1
(C) 4 Mr 2 (D) 2
Mr 2

Moment of inertia of a solid cylinder of Mass M, length l and radius r about its own axis
is :

 r2 l2 
(a) M +  (b) Mr2
 2 12 

1 1
(c) Mr 2 (d) Mr 2
4 2

7 3417 (NS)

14. }›ß, EøÓ {ø»U-S®, Auß öPõv {ø»U-S® Cøh-÷¯ C¯[-S® öÁ¨£
C¯¢-v-µz-vß £¯Ý-Öz-v-Óß :
(-A) 12.5% (B) 6.25% (C) 20% (D) 26.8%
The efficiency of a heat engine working between the freezing point and boiling point of
water is :
(a) 12.5% (b) 6.25% (c) 20% (d) 26.8%

15. 278C öÁ¨-£-{-ø»-°À øím-µ-áß ‰»U-T-Ôß \µõ-\› C¸-©i ‰» ÷ÁP® :
(-A) 193 kms−1 (B) 1.93 kms−1
(C) 19.3 kms−1 (D) 0.193 kms−1
rms speed of hydrogen molecule at 278C :
(a) 193 kms−1 (b) 1.93 kms−1
(c) 19.3 kms−1 (d) 0.193 kms−1

£Sv & II /PART - II
SÔ¨¦ : GøÁ÷¯Ý® BÖ ÂÚõUPÐUS Âøh¯ÎUPÄ®. ÂÚõ Gs 24 &US
Pmhõ¯©õP Âøh¯ÎUPÄ®. 6x2=12
Note : Answer any six questions. Q. No. 24 is compulsory.

1
16. mv 2 =mgh GßÓ \©ß- £ õmøh £›- © õ- n ¨ £S¨- £ õ´Ä •øÓ¨- £ i
2
\›-¯õ-Ú-uõ GÚ Ps-h-Ô-P.
1
Check the correctness of the equation mv 2 =mgh using dimensional analysis.
2

17. Ph¢-uz öuõ-ø»Ä ©Ø-Ö® Ch¨-ö£-¯ºa-]ø¯ Áøµ-¯-ÖU-P-Ä®.
Define distance and displacement.

18. JÆ-öÁõ¸ ©õ-u-•® \¢-v-µ-Q-µ-P-n-•® `›-¯ Qµ-P-n-•® |øh-ö£-Ö-Áx CÀø».
Hß ?
Why there is no lunar eclipse and solar eclipse every month ?

[ v¸¨¦P / Turn over

3417 (NS) 8

19. ÷Põn E¢u ©õ-Óõ Âv-ø¯U TÖ-P.
State the law of conservation of angular momentum.

20. «m-]-¯-Ψ¦ Sn-P® Gß-ÓõÀ GßÚ ?
What is coefficient of restitution ?

21. J¸ öÁ¨£ C¯¢- v - µ ® Auß _ÇØ] {PÌ- Â ß ÷£õx 500 J öÁ¨- £ zøu
öÁ¨£ ‰»z-v-¼-¸¢x ö£Ø-ÖU öPõsk J¸ SÔ¨-¤mh ÷Áø»-ø¯ ö\´u
¤ß- Ú º 300 J öÁ¨- £ z- ø u `Ç- ¾ US (öÁ¨£ HØ- ¤ US) öPõ- k U- Q - Ó x.
C¢-{-£¢-u-øÚ-P-Îß-£i A¢u öÁ¨£ C-¯¢-v-µz-vß £¯-Ý-Ö vÓ-øÚU Põs-P.
During a cyclic process, a heat engine absorbs 500 J of heat from a hot reservoir, does
work and ejects an amount of heat 300 J into the surroundings (cold reservoir). Calculate
the efficiency of the heat engine.

22. ¦Â-°ß ÁÎ-©s-h-»z-vÀ øím-µ-áß Áõ-²-ÁØÓ {ø» Hß EÒÍx ?
Why there is no hydrogen in the earth’s atmosphere ?

23. Áõ² Jß-ÔÀ, J¼-°ß vø\-÷Á-Pzøu £õ-vU-S® Põ-µ-o-PøÍ GÊ-x-P.
Write down the factors affecting velocity of sound in gases.

24. J¸ uÛ F\-¼ß }Í® Auß öuõ-hUP }Íz-v-¼-¸¢x 44% Av-P-›U-Q-Óx GÛÀ,
uÛ-F-\-¼ß Aø»-Ä-÷|-µ® Av-P-›U-S® \u-Ã-uzøu PnU-Q-kP.
If the length of the simple pendulum is increased by 44% from its original length,
calculate the percentage increase in time period of the pendulum.

£Sv & III /PART - III
SÔ¨¦ : GøÁ÷¯Ý® BÖ ÂÚõUPÐUS Âøh¯ÎUPÄ®. ÂÚõ Gs 33 &US
Pmhõ¯©õP Âøh¯ÎUPÄ®. 6x3=18
Note : Answer any six questions. Q. No. 33 is compulsory.

25. ªP }sh öuõ-ø»øÁ AÍU-S® ÷µhõº xi¨¦ •øÓ £ØÔ ÂÁ-›U-P-Ä®.
Explain RADAR Pulse method for determining large distances.

9 3417 (NS)

26. GÔ-ö£õ-¸-öÍõßÖ 308 GÔ-÷Põ-nz-vÀ GÔ-¯¨-£-k-Q-Óx. Auß Bµ®-£z-vø\
÷ÁP® 5 ms−1 GÛÀ GÔ-ö£õ-¸Ò Aøh¢u ö£¸© E¯-µ® ©Ø-Ö® Qøhz-uÍ
ö|kU-Pz-øuU PnU-Q-k-P.
An object is thrown with initial speed 5 ms−1 with an angle of projection 308. Calculate
the maximum height reached and the horizontal range.

27. Q›U-öPm õº, ÷ÁP-©õP Á¸® £¢-vøÚ ¤iU-S® ÷£õx AÁ-›ß Pµ[-PøÍ
£¢x Á¸® vø\-°-÷»÷¯ £i¨-£-i-¯õP uõÌz-x-Á-uß Põ-µ-n® GßÚ ?
When a cricket player catches the ball, he pulls his hands in the direction of the ball’s
motion. Why ?

28. öP¨Í-›ß ‰ßÖ Âv-PøÍU TÖ-P.
State Kepler’s three laws.

29. SÖU-P-ø»-PÒ ©Ø-Ö® ö|m-h-ø»-PøÍ ÷ÁÖ-£-kz-x-P.
Write the differences between transverse and longitudinal waves.

30. ö©ß £õ-Ú[-PøÍU Si¨-£-uØS |õ® EÔg_ SÇõ-ø¯¨ £¯ß-£-kz-x-Q-÷Óõ®.
Hß ?
We use straw to suck soft drinks. Why ?

31. Jz-u-vºÄ ÂÍU-SP. Gkz-xU-Põmk u¸-P.
Explain Resonance. Give an example.

32. «Ò {PÌÄ |øh-ö£-Ö-Á-uØ-PõÚ {£¢-u-øÚ-PÒ ¯õøÁ ?
What are the conditions for reversible process ?

33. ( 4 i − 3 j + 5 k ) N Âø\-¯õ-Úx (7 i + 4 j − 2 k ) m GßÓ ¦Ò-Î-°À Aø©¢u {ø»
∧ ∧ ∧ ∧ ∧ ∧

öÁU- h - › ß «x ö\¯À- £ - k - Q - Ó x. Bv- ø ¯¨ ö£õ- Ö zx v¸¨¦ Âø\- ° ß
©v¨-ø£U PõsP.

A force of ( 4 i − 3 j + 5 k ) N is applied at a point whose position vector is
∧ ∧ ∧

(7 i + 4 j − 2 k ) m . Find the torque of force about the origin.
∧ ∧ ∧

[ v¸¨¦P / Turn over

3417 (NS) 10

£Sv & IV /PART - IV
SÔ¨¦ : AøÚzx ÂÚõUPÐUS® Âøh¯ÎUPÄ®. 5x5=25
Note : Answer all questions.

34. (A) ø©¯ ÷|õUS •-kU-Pz-vØ-PõÚ ÷Põ-øÁ-ø¯¨ ö£Ö-P.
AÀ-»-x
(B) ÷Áø» BØ-ÓÀ uz-x-Áz-øuU TÔ ÂÍU-SP. AuØS H÷u-Ý® ‰ßÖ
Euõ-µ-n[-PøÍU TÖ-P.
(a) Derive the expression for centripetal acceleration.
OR
(b) State and explain work energy theorem. Mention any three examples for it.

35. (A) ¤øÇ-P-Îß ö£¸U-P® £ØÔ }º AÔ¢-ux GßÚ ? C¸ AÍ-Ä-PøÍ
ÁS¨-£-uõÀ HØ-£-k® ¤øÇ-PÒ ¯õøÁ ?
AÀ-»-x
(B) öÁ¨- £ - ¨ £- › - © õØ- Ó - ª À- » õ {PÌ-  À ö\´- ¯ ¨- £ mh ÷Áø»U- P õÚ
\©ß-£õm-øh¨ ö£Ö-P.
(a) What do you mean by propagation of errors ? Explain propagation of errors in
division of two quantities.
OR
(b) Derive the work done in an adiabatic process.

36. (A) (i) ¦Â-£µ- ¨-¤¼ - ¸
- ¢-x ¦Â-°ß BÇzøu (d) \õº¢x Dº¨-¤ß •kU-P® (g)
©õ-Ö-£-k-Á-u-ØPõ-Ú ÷Põ-øÁø¯ Á¸-Â.
(ii) ¦Â£µ¨- ¤ - ¼ - ¸ ¢x R/2 E¯- µ z- v À ¦Â- D º¨¦ •kU- P z- v ØS®,
¦Â-£-µ¨-¤-¼-¸¢x R/2 BÇz-vÀ ¦Â-Dº¨¦ •-kU-Pz-vØ-S® EÒÍ
ÂQ-u® PõsP. (R &¦-Â-°ß Bµ®)
AÀ-»-x
(B) Ám- h ¨- £ õ- ø u- ° À ªv- Á si Km- k - £ - Á º ÂÇõ- © - ¼ - ¸ UP AÁº \õ- ² ®
÷Põ-nz-vØ-Põ-Ú ÷Põ-øÁø¯ u¸-ÂU-P-Ä®.
(a) (i) Derive the expression for the variation of acceleration due to gravity (g)
with depth from the surface of the earth (d).
(ii) Find the ratio of the acceleration due to gravity at a height R/2 from the
surface of the earth to the value at a depth R/2 from the surface of the
earth (R - radius of the earth).
OR
(b) Explain bending of cyclist in curves and arrive at an expression for angle of
bending.

11 3417 (NS)

37. (A) usk Jß-Ôß {ø»-ø©z v¸¨-¦z-v-ÓøÚ Auß ø©¯® ÁÈ-¯õ-P-Ä®,
us-iØS ö\[-Sz-uõ-P-Ä® ö\À-¾® Aa-ø\¨ ö£õ-¸z-u-x-©õÚ \©ß-£õmøh
ÂÁ-›-UP-Ä®.
AÀ-»-x
(B) Aø»-Ä-P-Îß |õßS ÁøP-PøÍ Â›-ÁõP ÂÍU-S-P.

(a) Derive the expression for moment of inertia of a thin uniform rod about an axis
passing through the centre and perpendicular to its length.
OR
(b) Explain in detail the four different types of oscillations.

38. (A) (i) •U-÷Põn •øÓ-°ß ‰»® J¸ ö£õ-¸-Îß E¯-µzøu AÍ-Â-k-P.
(ii) uøµ-°À J¸ ¦Ò-Î-°-¼-¸¢x J¸ ©µz-vß Ea-]-¯õ-Úx 608 HØ-ÓU
÷Põ-nz-vÀ ÷uõß-Ö-Q-Óx. ©µz-vØ-S® A¨-¦Ò-ÎU-S® Cøh¨-£mh
yµ® 50 «. GÛÀ ©µz-vß E¯-µz-øuU Põs-P.
AÀ-»-x
(B) ì÷hõU Âv-ø¯¨ £¯ß-£-kzv Av-P £õ-S-{ø» öPõsh vµ-Áz-vÀ
C¯[- S ® ÷Põ- n z- v ß •Ø- Ö z- v - ø \- ÷ Á- P z- v Ø- P õÚ \©ß- £ õm- ø hz
u¸-ÂU-P-Ä®.
(a) (i) Determine the height of an accessible object using Triangulation method.

(ii) From a point on the ground, the top of a tree is seen to have an angle of
elevation 608. The distance between the tree and a point is 50 m. Calculate
the height of the tree.
OR
(b) Derive the expression for the terminal velocity of a sphere moving in a high viscous
fluid, using Stokes’ formula.

-oOo-

[ v¸¨¦P / Turn over