Jharkhand EECE LE 2026 Answer Key (Final)

FOR JHARKHAND EECE LE EXAM PREPARATION

Jharkhand EECE LE 2026
Answer Key (Final)
EXAM YEAR TYPE

Jharkhand EECE LE 2026 Answer Key (Final)

Notes · Sample Papers · Previous Year Papers · Mock Tests

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. c key of Engineering Entrance Competitive Examination (Lateral
e m Entry) – 2026 held on 28.06.2026 la
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Final Answer
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Set Code Q1 Q2 Q3 Q4 Q5 Q6 Q7 Q8 Q9 Q10 Q11 Q12 Q13 Q14 Q15 Q16 Q17 Q18 Q19 Q20 Q21 Q22 Q23 Q24 Q25 Q26 Q27 Q28 Q29 Q30 Q31 Q32 Q33 Q34 Q35 Q36 Q37 Q38 Q39 Q40 Q41 Q42 Q43 Q44 Q45 Q46 Q47 Q48 Q49 Q50

A B B B A C A A C B B B B B C B B A A B B B C A A D Deleted B C A C A B B C C B A D C A B A D B B B B C A

Q51 Q52 Q53 Q54 Q55 Q56 Q57 Q58 Q59 Q60 Q61 Q62 Q63 Q64 Q65 Q66 Q67 Q68 Q69 Q70 Q71 Q72 Q73 Q74 Q75 Q76 Q77 Q78 Q79 Q80 Q81 Q82 Q83 Q84 Q85 Q86 Q87 Q88 Q89 Q90 Q91 Q92 Q93 Q94 Q95 Q96 Q97 Q98 Q99 Q100

A C A A C C C A C C B B D B B B A B A D C A B B B A&B B B B B C B A A B C B B D B B B D D B B B D D D B

Q101 Q102 Q103 Q104 Q105 Q106 Q107 Q108 Q109 Q110 Q111 Q112 Q113 Q114 Q115 Q116 Q117 Q118 Q119 Q120 Q121 Q122 Q123 Q124 Q125 Q126 Q127 Q128 Q129 Q130 Q131 Q132 Q133 Q134 Q135 Q136 Q137 Q138 Q139 Q140 Q141 Q142 Q143 Q144 Q145 Q146 Q147 Q148 Q149 Q150

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D A C C D C B A D D D C D B A B B C B B D B A A C A A B C B A D A C A D A C A B D B B B A D B A C D

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Set Code Q1 Q2 Q3 Q4 Q5 Q6 Q7 Q8 Q9 Q10 Q11 Q12 Q13 Q14 Q15 Q16 Q17 Q18 Q19 Q20 Q21 Q22 Q23 Q24 Q25 Q26 Q27 Q28 Q29 Q30 Q31 Q32 Q33 Q34 Q35 Q36 Q37 Q38 Q39 Q40 Q41 Q42 Q43 Q44 Q45 Q46 Q47 Q48 Q49 Q50

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C B B A B B A B C B A D Deleted A C A B A C B C B B C D A A B C D B A B B B A C B A B B C A A A B C B B B

a Q51 Q52 Q53 Q54 Q55 Q56 Q57 Q58 Q59 Q60 Q61 Q62 Q63 Q64 Q65 Q66 Q67 Q68 Q69 Q70 Q71 Q72 Q73 Q74 Q75 Q76 Q77 Q78 Q79 Q80 Q81 Q82 Q83 Q84 Q85 Q86 Q87 Q88 Q89 Q90 Q91 Q92 Q93 Q94 Q95 Q96 Q97 Q98 Q99 Q100

B B A D A A B C B B B B A&B B C B A B B A B C B B D B D B B D B B D D B D A A C C C C C C A B B B D B B

Q101 Q102 Q103 Q104 Q105 Q106 Q107 Q108 Q109 Q110 Q111 Q112 Q113 Q114 Q115 Q116 Q117 Q118 Q119 Q120 Q121 Q122 Q123 Q124 Q125 Q126 Q127 Q128 Q129 Q130 Q131 Q132 Q133 Q134 Q135 Q136 Q137 Q138 Q139 Q140 Q141 Q142 Q143 Q144 Q145 Q146 Q147 Q148 Q149 Q150

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A B B B B B D C A A B A A C C B A B A C D D A C A B D B A B A D B A C D B A C D D C B C D D A C D D

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Set Code Q1 Q2 Q3 Q4 Q5 Q6 Q7 Q8 Q9 Q10 Q11 Q12 Q13 Q14 Q15 Q16 Q17 Q18 Q19 Q20 Q21 Q22 Q23 Q24 Q25 Q26 Q27 Q28 Q29 Q30 Q31 Q32 Q33 Q34 Q35 Q36 Q37 Q38 Q39 Q40 Q41 Q42 Q43 Q44 Q45 Q46 Q47 Q48 Q49 Q50

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A B C C A C B B C B A D B C A B A D B B B C A A B B B A C A A C B B B B B B C B A A B B B C D Deleted A A

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Q51 Q52 Q53 Q54 Q55 Q56 Q57 Q58 Q59 Q60 Q61 Q62 Q63 Q64 Q65 Q66 Q67 Q68 Q69 Q70 Q71 Q72 Q73 Q74 Q75 Q76 Q77 Q78 Q79 Q80 Q81 Q82 Q83 Q84 Q85 Q86 Q87 Q88 Q89 Q90 Q91 Q92 Q93 Q94 Q95 Q96 Q97 Q98 Q99 Q100

C A B C B B D B B B D D B B B D D D B A C A C C C C A C B B D B B B A D A B B C A B B B A&B B C B B B A

Q101 Q102 Q103 Q104 Q105 Q106 Q107 Q108 Q109 Q110 Q111 Q112 Q113 Q114 Q115 Q116 Q117 Q118 Q119 Q120 Q121 Q122 Q123 Q124 Q125 Q126 Q127 Q128 Q129 Q130 Q131 Q132 Q133 Q134 Q135 Q136 Q137 Q138 Q139 Q140 Q141 Q142 Q143 Q144 Q145 Q146 Q147 Q148 Q149 Q150

B A B C C D A A C A D D B A B A D B B C D B A C D A C B C D D A D D D C B B B A B D C B A B A A C A

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Set Code Q1 Q2 Q3 Q4 Q5 Q6 Q7 Q8 Q9 Q10 Q11 Q12 Q13 Q14 Q15 Q16 Q17 Q18 Q19 Q20 Q21 Q22 Q23 Q24 Q25 Q26 Q27 Q28 Q29 Q30 Q31 Q32 Q33 Q34 Q35 Q36 Q37 Q38 Q39 Q40 Q41 Q42 Q43 Q44 Q45 Q46 Q47 Q48 Q49 Q50

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D A C A B A D B B B B A C B A B B C A A A B C B B B B C B A B B A B C B Deleted A A D B C A A C B B C B C

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Q51 Q52 Q53 Q54 Q55 Q56 Q57 Q58 Q59 Q60 Q61 Q62 Q63 Q64 Q65 Q66 Q67 Q68 Q69 Q70 Q71 Q72 Q73 Q74 Q75 Q76 Q77 Q78 Q79 Q80 Q81 Q82 Q83 Q84 Q85 Q86 Q87 Q88 Q89 Q90 Q91 Q92 Q93 Q94 Q95 Q96 Q97 Q98 Q99 Q100

D B D B B D B B D D B D
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C A A C C C A C C B B B D B B D A B A C A B B B A&B B B B B C A B B A B C B B D

Q101 Q102 Q103 Q104 Q105 Q106 Q107 Q108 Q109 Q110 Q111 Q112 Q113 Q114 Q115 Q116 Q117 Q118 Q119 Q120 Q121 Q122 Q123 Q124 Q125 Q126 Q127 Q128 Q129 Q130 Q131 Q132 Q133 Q134 Q135 Q136 Q137 Q138 Q139 Q140 Q141 Q142 Q143 Q144 Q145 Q146 Q147 Q148 Q149 Q150

C A D A B A B D D B B A D B A C D A C B C D C A D D D C D B B A B D C B B B A A C A A A B C B D A C

Note :- 1) Set-A-Q27 / Set-B-Q13 / Set-C-Q48 / Set-D-Q37: Marks will be awarded to all candidates for these questions.

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2) Set-A-Q75 / Set-B-Q62 / Set-C-Q94 / Set-D-Q86: Both Answer A and Answer B are correct. Therefore, candidates who selected either Answer A or Answer B will be awarded marks.

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Clarification of Objections
Mas Remarks Given by Candidates Final Clarification and Reference Given by Subject Expert
Secti Secti Objection
on on Bklet/ Status Final Answer Given By
Set Question Description as per Master Set (Set-A) er Objection
Num Nam Q. No. Valid/ Subject Expert
ber e Invalid
o.
Printing/Typographical error in the question statement The definition of sound intensity would be the amount of sound energy per second passing through a unit surface area normal to the
Elaboration: The phrase "passing each sound through unit area" is not direction of propagation. It seems that the word “sound” should have been “second.”
meaningful in physics terminology. The standard definition of sound intensity is
"the amount of sound energy passing through unit area per second". It appears Std 9, Science, Ch 12 Sound, Page 166
that the word "second" was mistakenly replaced by "sound".

Due to this printing error, the wording of the question is defective and may
reasonably confuse candidates regarding the intended physical quantity. Thus, I
Physi respectfully request the Board to treat this as a defective question and take Question Should be
1 27 D-37 C Incorrect Question Valid
cs appropriate action, including awarding appropriate marks to affected Deleted
candidates, if deemed fit under the Board's examination policy.

In reflection from a real surface, the intensity of the reflected ray is less than the incident ray because a part of the incident light is
absorbed, scattered, or transmitted by the surface. Therefore, the intensity of the reflected ray decreases.
In standard physics, unless the word "ideal" or "perfectly reflecting" is explicitly mentioned, you must assume the laws of practical,
real-world physics.

Std 12, Physics, Ch 9, Ray Optics and Optical Instruments, Page 320

Physi
1 33 D-46 B Incorrect Question Ambiguous question due to omission of the nature of the reflecting surface Invalid (B)
cs

The mass of the nucleus determined due to protons and neutrons only. Protons and neutrons present in the nucleus are collectively
known as nucleons which decides the Atomic weight/ mass number.

When a neutron is added to the nucleus of an atom, the number of protons remains unchanged; therefore, the atomic number does
not change. The number of electrons around the nucleus also does not necessarily change. However, since a neutron has mass,
addition of a neutron increases the mass of the atom. Hence, the atomic weight/atomic mass changes.

Che
2 mistr 53 D-64 A Mass Number ≠ Atomic Mass ≠ Atomic Weight Invalid (A)
y

NCERT Book Class-XI Chemistry Part-1, Chapter: 02, Atomic Structure, Page No.352.2.3 Atomic Number and Mass Number

For more Question Papers, Sample Papers, Notes & Syllabus visit Page 2 of 8

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Remarks Given by Candidates Final Clarification and Reference Given by Subject Expert
Secti Secti Objection

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The question asks for the proper symbol of the species on the basis of the given numbers of electrons, protons and neutrons. Since
the species has 16 protons, it is sulphur. Since it has 18 electrons, it has two electrons more than the neutral sulphur atom and
therefore carries a charge of 2−. Hence the correct symbol is S²⁻.
This question is about identifying the charged ionic species, not assigning oxidation state. Therefore, the objection regarding
oxidation state notation is not applicable.

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Oxidation states (AI+³, S-²) & Charged lon Species (AI³+, S²) are not the same

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2 mistr 54 D-65 C Invalid (c)

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thing.

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ag NCERT Book Class-XI Chemistry Part-1, Chapter: 02, Intext Question, Problem 2.2 “The number of electrons, protons and neutrons in
a species are equal to 18, 16 and 16 respectively. Assign the proper symbol to the species”
NCERT Book Class-XI Chemistry Part-1, Chapter: 02, Atomic Structure, Problem 2.2 (Intext Question) Page No.36

Respected Sir/Madam, As per Arrhenius theory, acids and bases are defined on the basis of their ionization in aqueous solution. Acids ionize to give
hydrogen/hydronium ions and bases ionize to give hydroxyl ions.
I respectfully submit this objection regarding Question No. 62 of Set A in the
provisional answer key. According to Arrhenius acid-base theory, acids and bases produce ions in aqueous solution. Acids ionize in water to give hydrogen

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ions/hydronium ions, while bases ionize in water to give hydroxyl ions.

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The provisional answer key marks Option (D) "lonization in aqueous solution" as The reference of NCERT also clearly explains the ionization of acid HX and base MOH in aqueous solution. Therefore, in the context of

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the correct answer. However, according to the Arrhenius acid-base theory, the Arrhenius theory, the strength of acids and bases is related to their ionization in aqueous solution.

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strength of an acid or base depends on the extent (degree) of dissociation in

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aqueous solution. Strong acids and bases dissociate almost completely in water, Ref: Std 11, Chemistry, Unit 6, Equilibrium, Page 190

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while weak acids and bases dissociate only partially. Therefore, the strength is

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determined by the extent of dissociation.

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Che Option (A), "Extent of dissociation in aqueous solution," directly expresses this

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2 mistr 62 A-62 D (A) is correct answer concept and is widely used in chemistry textbooks. Invalid (D)

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In view of the above, I kindly request the Board to review Question No. 62 and
consider Option (A) as the correct answer, or take appropriate action if the
question is found to be ambiguous.

Thank you for your time and consideration.

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In Set C, question number 80 the answer would be both A & D As per Arrhenius theory, acids and bases are defined on the basis of their ionization in aqueous solution. Acids ionize to give

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hydrogen/hydronium ions and bases ionize to give hydroxyl ions.

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According to Arrhenius acid-base theory, acids and bases produce ions in aqueous solution. Acids ionize in water to give hydrogen

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ions/hydronium ions, while bases ionize in water to give hydroxyl ions.

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The reference of NCERT also clearly explains the ionization of acid HX and base MOH in aqueous solution. Therefore, in the context of

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Arrhenius theory, the strength of acids and bases is related to their ionization in aqueous solution.

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Ref: Std 11, Chemistry, Unit 6, Equilibrium, Page 190

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(A) and (D) is correct
2 mistr 62 C-80 D Invalid (D)
answer
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las a g For more Question Papers, Sample Papers, Notes & Syllabus visit Page 3 of 8

Mas Remarks Given by Candidates Final Clarification and Reference Given by Subject Expert
Secti Secti Objection
on on Bklet/ Status Final Answer Given By
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Good morning sir As per Arrhenius theory, acids and bases are defined on the basis of their ionization in aqueous solution. Acids ionize to give
hydrogen/hydronium ions and bases ionize to give hydroxyl ions.
Set A question no. 62 has been answered incorrectly, it has been given in the
answer key but According to Arrhenius acid-base theory, acids and bases produce ions in aqueous solution. Acids ionize in water to give hydrogen
ions/hydronium ions, while bases ionize in water to give hydroxyl ions.
ar swer a hoga The reference of NCERT also clearly explains the ionization of acid HX and base MOH in aqueous solution. Therefore, in the context of
Arrhenius theory, the strength of acids and bases is related to their ionization in aqueous solution.

Ref: Std 11, Chemistry, Unit 6, Equilibrium, Page 190

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2 mistr 62 A-62 D (A) is correct answer Invalid (D)
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Respected Sir/Madam, As per Arrhenius theory, acids and bases are defined on the basis of their ionization in aqueous solution. Acids ionize to give
hydrogen/hydronium ions and bases ionize to give hydroxyl ions.
I respectfully submit this objection regarding Question No. 62 of Set A in the
Provisional Answer Key of D2D 2026. According to Arrhenius acid-base theory, acids and bases produce ions in aqueous solution. Acids ionize in water to give hydrogen
ions/hydronium ions, while bases ionize in water to give hydroxyl ions.
Your provisional answer key has marked Option (D) - "lonization in aqueous The reference of NCERT also clearly explains the ionization of acid HX and base MOH in aqueous solution. Therefore, in the context of
solution" as the correct answer. But, I found that this is incorrect in many Arrhenius theory, the strength of acids and bases is related to their ionization in aqueous solution.
sources.
Ref: Std 11, Chemistry, Unit 6, Equilibrium, Page 190
Because According to the Arrhenius acid-base theory, the strength of an acid or
base depends on the extent (degree) of dissociation in aqueous solution. Strong
acids and bases dissociate almost completely in water, whereas weak acids and
Che bases dissociate only partially. Therefore, the strength of an acid or base is
2 mistr 62 A-62 D (A) is correct answer determined by the extent of dissociation, not merely by the process of Invalid (D)
y ionization.

Option (A) - "Extent of dissociation in aqueous solution" directly expresses this
concept and is the standard terminology used in chemistry textbooks.

In view of the above, I kindly request the Board to review Question No. 62 and
consider Option (A) as the correct answer, or take appropriate action if the
question is found to be ambiguous.

Thank you for your time and consideration.

Respected sir/Madam, As per Arrhenius theory, acids and bases are defined on the basis of their ionization in aqueous solution. Acids ionize to give
hydrogen/hydronium ions and bases ionize to give hydroxyl ions.
I respectfully submitted this objection regarding Question NO:80 of set C in
provisional answer key of D2D 2026. According to Arrhenius acid-base theory, acids and bases produce ions in aqueous solution. Acids ionize in water to give hydrogen
ions/hydronium ions, while bases ionize in water to give hydroxyl ions.
Your provisional answer key has marked option(D)_"ionization in aqueous The reference of NCERT also clearly explains the ionization of acid HX and base MOH in aqueous solution. Therefore, in the context of
solution" as correct answer. But, I found that this is incorrect in according to Arrhenius theory, the strength of acids and bases is related to their ionization in aqueous solution.
your question.
Ref: Std 11, Chemistry, Unit 6, Equilibrium, Page 190
Arrhenius Acid-Base Theory

Based on the Arrhenius theory, the correct answer to question 80 is:
Che
2 mistr 62 C-80 D (A) is correct answer (A) extent of dissociation in aqueous solution Invalid (D)
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Explanation

The Arrhenius theory defines acids as substances that dissociate in water to yield
hydrogen ions (\(H^{+}\)) and bases as substances that dissociate in water to
yield hydroxide ions (\(OH^{-}\)).

Strong acids/bases dissociate or ionize completely in aqueous solution.

Weak acids/bases dissociate only partially.

Therefore, the "strength" is directly measured by the extent of dissociation (how
much of the substance breaks apart into ions) when dissolved in water.

For more Question Papers, Sample Papers, Notes & Syllabus visit Page 4 of 8

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Remarks Given by Candidates Final Clarification and Reference Given by Subject Expert
Secti Secti Objection

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Num Nam Q. No. Valid/ Subject Expert

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Respected Sir/Madam, As per Arrhenius theory, acids and bases are defined on the basis of their ionization in aqueous solution. Acids ionize to give
hydrogen/hydronium ions and bases ionize to give hydroxyl ions.
I am a candidate who appeared for the Engineering Entrance Competitive
Examination (Lateral Entry) 2026, and I wish to raise an objection against the According to Arrhenius acid-base theory, acids and bases produce ions in aqueous solution. Acids ionize in water to give hydrogen
provisional answer key published for the exam. ions/hydronium ions, while bases ionize in water to give hydroxyl ions.
The reference of NCERT also clearly explains the ionization of acid HX and base MOH in aqueous solution. Therefore, in the context of
Candidate details: Arrhenius theory, the strength of acids and bases is related to their ionization in aqueous solution.

Roll No.: 2602104568 Ref: Std 11, Chemistry, Unit 6, Equilibrium, Page 190

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Set: D

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Che Question No.: 74

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2 mistr 62 D-74 D (A) is correct answer Invalid (D)

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y Correct answer - (option A)

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Given (option D), which is wrong

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Question: "According to Arrhenius acid-base theory, the strength of acid and

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base depends on the -"

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(A) extent of dissociation in aqueous solution

(B) magnitude of accepting proton

(C) magnitude of donating proton

(D) ionization
I would like toinbring
aqueous solution
to your kind attention that in the official answer key for Set As per Arrhenius theory, acids and bases are defined on the basis of their ionization in aqueous solution. Acids ionize to give
B published by the correct answer for question no. 98 has been marked as hydrogen/hydronium ions and bases ionize to give hydroxyl ions.
Option D. However, based on the attached supporting evidence, Option A
appears to be the more appropriate and correct answer. According to Arrhenius acid-base theory, acids and bases produce ions in aqueous solution. Acids ionize in water to give hydrogen

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ions/hydronium ions, while bases ionize in water to give hydroxyl ions.

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I have attached the relevant proof for your kind reference. I kindly request you The reference of NCERT also clearly explains the ionization of acid HX and base MOH in aqueous solution. Therefore, in the context of

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to review the same and take the necessary action. Arrhenius theory, the strength of acids and bases is related to their ionization in aqueous solution.

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Kind regards, Ref: Std 11, Chemistry, Unit 6, Equilibrium, Page 190

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Aniket Kumar Singh

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Che Document from Aniket Singh.pdf

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2 mistr 62 B-98 D (A) is correct answer 944K Invalid (D)

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Qno. As per Arrhenius theory, acids and bases are defined on the basis of their ionization in aqueous solution. Acids ionize to give

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hydrogen/hydronium ions and bases ionize to give hydroxyl ions.

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80. Correct answer: A. extent of dissociation in aqueous solution*

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According to Arrhenius acid-base theory, acids and bases produce ions in aqueous solution. Acids ionize in water to give hydrogen

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"Explanation with logic:* ions/hydronium ions, while bases ionize in water to give hydroxyl ions.

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The reference of NCERT also clearly explains the ionization of acid HX and base MOH in aqueous solution. Therefore, in the context of
"Step 1: Arrhenius definition* Arrhenius theory, the strength of acids and bases is related to their ionization in aqueous solution.

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Arrhenius 1884 theory only works for water: Ref: Std 11, Chemistry, Unit 6, Equilibrium, Page 190

1. "Acid gives $H^+$ in water: $HA \rightarrow H^+ + A^-$

Che 2. "Base* gives $OH^-S in water: SBOH \rightarrow B^+ + OH^-$
2 mistr 62 C-80 D (A) is correct answer Invalid (D)
y "Step 2: How does he define "strength"?*

Strength = power to give $H^+$ or $OH^-$ ions.

More $H^+$ ions = Stronger acid

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More $OH^-$ ions = Stronger base

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"Step 3: What controls number of ions?*

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The number of ions depends on "extent of dissociation" = how much % of

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acid/base molecules break into ions in water.

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Formula: $\alpha = \frac{\text{No. of molecules dissociated}}{\text{Total no. of

a For more Question Papers, Sample Papers, Notes & Syllabus visit Page 5 of 8

Mas Remarks Given by Candidates Final Clarification and Reference Given by Subject Expert
Secti Secti Objection
on on Bklet/ Status Final Answer Given By
Num Nam Q. No. Valid/ Subject Expert
ber e Invalid
o.
Ambiguous chemical nomenclature in option (d) As per Arrhenius theory, acids and bases are defined on the basis of their ionization in aqueous solution. Acids ionize to give
hydrogen/hydronium ions and bases ionize to give hydroxyl ions.

According to Arrhenius acid-base theory, acids and bases produce ions in aqueous solution. Acids ionize in water to give hydrogen
ions/hydronium ions, while bases ionize in water to give hydroxyl ions.
The reference of NCERT also clearly explains the ionization of acid HX and base MOH in aqueous solution. Therefore, in the context of
Arrhenius theory, the strength of acids and bases is related to their ionization in aqueous solution.

Ref: Std 11, Chemistry, Unit 6, Equilibrium, Page 190

Che
2 mistr 62 A-62 D Incorrect Key Invalid (D)
y

A few elements like carbon, sulphur, gold and noble gases, occur in free state while others are found in combined forms in the
earth’s crust.

NCERT Std 10, Science, Ch 3,Page 49-50

Che
More than one
2 mistr 75 D-86 A More than one scientifically correct option Valid (A) & (B)
correct answer
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Dear sir/mam Although Vulcanisation of rubber is heationg it with different concentration of sulphur but for manufacturing TYRE RUBBER, 5% of
I would like to draw your kind attention towards the answer key published for sulphur is used. It is clearly mentioned tn NCERT Text book.
Engineering lateral entry examination 2026. https://cdn1.byjus.com/wp-content/uploads/2019/10/NCERT-Book-for-Class-12-Chemistry-Chapter-15.pdf
In this I found a question whose answer is not correct. So I'm mentioning the OLD NCERT Book Class-XII Chemistry Part-II,
question along with Set, alongwith I am also sharing the question with the proof Chapter: 15, POLYMERS,
of correct answer and request you to review it by your own side to the depth. Page No.441
SET-A TOPIC: 15.2.4 : Rubber,
Question number - 94 Vulcanisation of rubber
In this question it is asked that what percentage of sulphur is added during
vulcanisation to get rubber for Tyre?
Options given,
A-30%
Che B-5%
(B) and (D) is correct C-55%
2 mistr 94 A-94 B Invalid (B)
answer D-3%
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It's answer as given in answer key is 5%
Objection - This answer (5%) is not perfect because a tyre should have sulphur
addition between (3-5)%.
In the options provided both 3 & 5% is in option B and D so both the answers
should be correct.
I request the concerned authority to take an eye on this by reviewing it from
renowned books of chemistry (Nirali, Jhunjhunwala) in every single book 3-5% is
mentioned or by the help of Google, as a single marks can decide the future of a
child.
Yours hopefully

For more Question Papers, Sample Papers, Notes & Syllabus visit Page 6 of 8

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Remarks Given by Candidates Final Clarification and Reference Given by Subject Expert
Secti Secti Objection

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Num Nam Q. No. Valid/ Subject Expert

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Qno. Carbon dioxide, ozone and methane are recognized greenhouse gases. The option “nitrogen oxide” in the question refers to common
66, Which one of the following is not a greenhouse gas?* nitrogen oxides such as nitric oxide/nitrogen monoxide (NO) and nitrogen dioxide (NO₂), which are generally treated as air pollutants
*Correct answer: Trick question - All of them are greenhouse gases and not listed as principal greenhouse gases at this level. Nitrous oxide, N₂O, is a greenhouse gas; however, it is specifically called
"Explanation: nitrous oxide, not simply “nitrogen oxide.” Since the question uses the term “nitrogen oxide” and not “nitrous oxide,” the intended
Greenhouse gases = gases that trap heat in atmosphere by absorbing infrared answer is clear in the given context.
radiation.
Check each option:
1. *(A) Carbon dioxide $CO_2$* - Yes, main greenhouse gas.76% of total GHG
emissions
2. *(B) Ozone SO_3$ - Yes. Ground-level ozone/tropospheric ozone is a

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greenhouse gas. Only stratospheric ozone "good ozone" protects from UV. But

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chemically $O_3$ does trap heat

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Che 3. (C) Methane $CH_4$* - Yes. 2nd biggest after $CO_2$. Traps 25x more heat

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than $CO_2$ per molecule 4. "(D) Nitrogen oxide - Yes. $N_20$ = Nitrous oxide is

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2 mistr 98 C-66 D Incorrect Question Invalid (D)

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y a greenhouse gas. $NO_x$ also contribute indirectly

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"Why confusion happens:*

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Books often teach "main GHGs = $CO_2, CH_4, N_20, CFCs$". Students then

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think ozone isn't one. But IPCC also lists SO_35 as greenhouse gas.

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So if your exam forces you to choose one, the question is wrong. If it's from a

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source that expects "Ozone", they mean "ozone layer isn't the main one we talk

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about for global warming". But scientifically, option B is still a greenhouse gas.

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Bottom line: By strict science, "none of the above" is correct.

Please find the attached google doc containing the consolidated list of objections Carbon dioxide, ozone and methane are recognized greenhouse gases. The option “nitrogen oxide” in the question refers to common
(with supporting evidence) against the released Answer Keys of Engineering nitrogen oxides such as nitric oxide/nitrogen monoxide (NO) and nitrogen dioxide (NO₂), which are generally treated as air pollutants
Entrance Competitive Examination (Lateral Entry) - 2026 held on 28.06.2026 and not listed as principal greenhouse gases at this level. Nitrous oxide, N₂O, is a greenhouse gas; however, it is specifically called
(keys released on 01.07.2026) nitrous oxide, not simply “nitrogen oxide.” Since the question uses the term “nitrogen oxide” and not “nitrous oxide,” the intended

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The objections are based on the question paper SET D, and includes question answer is clear in the given context.

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numbers 37, 46, 58, 74 & 86.

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JD2D 2026 - Answer Key Objections

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I have also attached below a pdf version of the google doc if you would rather

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use that instead.

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PDF JD2D 2026 - Answer Key Objections.pdf

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Regards,

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Priyanshu Kumar

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Che Exam Roll No.: 2602102188

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2 mistr 98 C-66 D (B) is correct answer Invalid (D)

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Carbon dioxide, ozone and methane are recognized greenhouse gases. The option “nitrogen oxide” in the question refers to common

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nitrogen oxides such as nitric oxide/nitrogen monoxide (NO) and nitrogen dioxide (NO₂), which are generally treated as air pollutants

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and not listed as principal greenhouse gases at this level. Nitrous oxide, N₂O, is a greenhouse gas; however, it is specifically called

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nitrous oxide, not simply “nitrogen oxide.” Since the question uses the term “nitrogen oxide” and not “nitrous oxide,” the intended

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answer is clear in the given context.

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2 mistr 98 D-58 D Incorrect Key Ambiguous chemical nomenclature in option (d) Invalid (D)
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las a g For more Question Papers, Sample Papers, Notes & Syllabus visit Page 7 of 8

Mas Remarks Given by Candidates Final Clarification and Reference Given by Subject Expert
Secti Secti Objection
on on Bklet/ Status Final Answer Given By
Set Question Description as per Master Set (Set-A) er Objection
Num Nam Q. No. Valid/ Subject Expert
ber e Invalid
o.
Objection: While the question asks for the cross product of →a & →b (which Although the question states a × b, the answer choices are all scalar quantities. It is evident from the options that the examination
would give a vector), the options given are all scalars. intended to ask for the magnitude of the cross product, which is a common convention in objective-type examinations.

Given:

a = i + j + k = (1, 1, 1)

b = i − j + k = (1, −1, 1)

a × b = (2, 0, −2)

Math Therefore,
3 emat 129 D-146 C Incorrect Question Invalid (C)
ics |a × b| = √(2² + 0² + (−2)²)

= √8

= 2√2

Hence, Option (C) is the correct answer.

The intent of the question is clear from the answer options, and there is no ambiguity in determining the correct response.
Therefore, the objection is not sustainable.

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