HBSE Class 12 Question Paper 2024 Physics

Haryana Board

QUESTIONPDF

PAPERS
2024

HBSE PYQP

CLASS : 12th (Sr. Secondary) Code No. 1229
Series : SS/Annual Exam.-2024
Roll No. SET : A
HkkSfrd foKku
PHYSICS
[ Hindi and English Medium ]
ACADEMIC/OPEN
(Only for Fresh/Re-appear/Improvement/Additional Candidates)
Time allowed : 3 hours ] [ Maximum Marks : 70
• Ñi;k tk¡p dj ysa fd bl iz'u&i= esa eqfnzr i`"B 24 rFkk iz'u 35 gSaA
Please make sure that the printed pages in this question paper are 24 in number
and it contains 35 questions.
• iz'u&i= esa nkfgus gkFk dh vksj fn;s x;s dksM uEcj rFkk lsV dks Nk= mÙkj&iqfLrdk ds eq[;&i`"B ij
fy[ksaA
The Code No. and Set on the right side of the question paper should be written by
the candidate on the front page of the answer-book.

• Ñi;k iz'u dk mÙkj fy[kuk 'kq: djus ls igys] iz'u dk Øekad vo'; fy[ksaA
Before beginning to answer a question, its Serial Number must be written.
• mÙkj&iqfLrdk ds chp esa [kkyh iUuk@iUus u NksMas+A
Don’t leave blank page/pages in your answer-book.
• mÙkj&iqfLrdk ds vfrfjDr dksbZ vU; 'khV ugha feysxhA vr% vko';drkuqlkj gh fy[ksa vkSj fy[kk mÙkj u
dkVsaA
Except answer-book, no extra sheet will be given. Write to the point and do not
strike the written answer.
• ijh{kkFkhZ viuk jksy ua0 iz'u&i= ij vo'; fy[ksaA jksy ua0 ds vfrfjDr iz'u&i= ij vU; dqN Hkh u
fy[ksa vkSj oSdfYid iz'uksa ds mÙkjksa ij fdlh izdkj dk fu'kku u yxk,¡A
Candidates must write their Roll No. on the question paper. Except Roll No. do not
write anything on question paper and don't make any mark on answers of objective
type questions.

1229/(Set : A) P. T. O.

(2) 1229/(Set : A)
• d`i;k iz'uksa dk mÙkj nsus lss iwoZ ;g lqfuf'pr dj ysa fd iz'u&i= iw.kZ o lgh gS] ijh{kk ds mijkUr bl
lEcU/k esa dksbZ Hkh nkok Lohdkj ugha fd;k tk;sxkA
Before answering the questions, ensure that you have been supplied the correct and
complete question paper, no claim in this regard, will be entertained after
examination.

lkekU; funsZ'k %
(i) bl ç'u-i= esa dqy 35 ç'u gS]a ftUgsa ik¡p [k.Mksa % ^v*]
^v* ^c*]
^c* ^l*]
^l* ^n* rFkk ^;* esa ck¡Vk x;k gS %
[k.M – v esa ç'u la[;k 1 ls 18 rd 1 vad okys oLrqfu"B ç'u gSAa ftlesa pkSng (1-14)
cgqfodYih; ç'u rFkk pkj (15-18) vfHkdFku-dkj.k ij vk/kkfjr ç'u gSAa
[k.M – c esa ç'u la[;k 19 ls 25 rd 2 vadksa okys vfry?kq mÙkjh; ç'u gSAa
[k.M – l esa ç'u la[;k 26 ls 30 rd 3 vadksa okys y?kq mÙkjh; ç'u gSAa
[k.M – n esa ç'u la[;k 31 ls 33 rd 5 vadksa okys nh?kZ mÙkjh; ç'u gSAa
[k.M – ; esa ç'u la[;k 34 ,oa 35 4 vadksa okys dsl LVMh vk/kkfjr ç'u gSAa

(ii) lHkh ç'u vfuok;Z gSA
(iii)ç'u-i= esa lexz :i ls dksbZ fodYi ugha gSA rFkkfi [k.M c] l] n vkSj ; ds dqN ç'uksa esa vkarfjd
p;u çnku fd;k x;k gSA ,sls ç'uksa esa vkidks fn, x, p;u esa ls dsoy ,d gh ç'u djuk gSA
(iv) dSy~D;qyV
s j ds mi;ksx dh vuqefr ugha gSA
(v) tgk¡ vko';d gks vki fuEufyf[kr HkkSfrd fu;rkadksa ds ekuksa dk mi;ksx dj ldrs gSa %
c = 3 × 108 m/s µ 0 = 4π × 10 −7 Tm A −1

1
h = 6.63 × 10 −34 Js = 9 × 10 9 Nm 2C − 2
4π ∈0

e = 1.6 × 10 −19 C me = 9.1 × 10 −31 kg

1229/(Set : A)

(3) 1229/(Set : A)
General Instructions :

(i) This question-paper consists of 35 questions, which are divided into five
Sections : 'A', 'B', 'C', 'D', & 'E' :

Section–A consists of Question No. 1 to 18 objective type questions of 1 mark
each, in which fourteen (1-14) are multiple choice type and four (15-18)
Assertion-Reason based questions.
Section–B consists of Question Nos. 19 to 25 very short answer type
questions of 2 marks each.
Section–C consists of Question Nos. 26 to 30 short answer type questions of
3 marks each.
Section–D consists of Question Nos. 31 to 33 long answer type questions of
5 marks each.
Section–E consists of Question Nos. 34 & 35 case study based questions of
4 marks each.

(ii) All questions are compulsory.
(iii) There is no overall choice. However, an internal choice has been provided in
some questions of Section – B, C, D and E. You have to attempt only one of
the given choice in such questions.
(iv) Use of Calculators is not permitted
(v) You may use the following values of physical constants whenever
necessary :

c = 3 × 108 m/s µ 0 = 4π × 10 −7 Tm A −1

1
h = 6.63 × 10 −34 Js = 9 × 10 9 Nm 2C − 2
4π ∈0
e = 1.6 × 10 −19 C me = 9.1 × 10 −31 kg

1229/(Set : A) P. T. O.

(4) 1229/(Set : A)
[k.M – v
SECTION – A
[ oLrqfu"B iz'u ]
[ Objective Type Questions ]

fuEufyf[kr cgqfodYih; ç'uksa ¼1 ls 14½ ds lgh fodYi pqfu, %
Select the correct option of the following multiple choice questions (1 to 14) :

1. +1 µC vkSj −4 µC ds nks fcanq vkos'k ,d-nwljs ls dqN nwjh ij ok;q esa fLFkr gSaA mu ij yxus okys
cyksa dk vuqikr gS % 1
(A) 1:4 (B) 4:1
(C) 1 : 16 (D) 1:1
Two point charges +1 µC and −4 µC are situated at some distance in air. The
ratio of forces acting on them is :
(A) 1:4 (B) 4:1
(C) 1 : 16 (D) 1:1

2. fdlh 2 kΩ çfrjks/k ds pkyd ls 1 mA fo|qr~ /kkjk cg jgh gSA blesa fdruh 'kfDr dk {k; gksrk gS \ 1
(A) 0.2 W (B) 2 mW
(C) 2W (D) 2 kW
1 mA current is flowing through a conductor of 2 kΩ resistance. How much
power is lost in it ?
(A) 0.2 W (B) 2 mW
(C) 2W (D) 2 kW

3. 4 kΩ çfrjks/kd ds fljksa ds chp 12 V dk foHkokUrj yxk;k x;k gSA blesa ls fdruh fo|qr~ /kkjk cg
jgh gS \ 1

(A) 3 mA (B) 3A

(C) 4A (D) 48 mA

1229/(Set : A)

(5) 1229/(Set : A)
A potential difference of 12 V is applied across the ends of a 4 kΩ resistor. How
much current is flowing through it ?
(A) 3 mA (B) 3A
(C) 4A (D) 48 mA

4. fdlh /kkrq ds rkj ds fy, nks rkiekuksa T1 o T2 ij /kkjk-oksYVst (I-V) xzkQ fp= ¼ç0 la0 4½ esa
n'kkZ;s x;s gSaA rc % I T1
1

T2

V

fp= ¼ç0 la0 4½
(A) T1 = T2 (B) T1 > T2
(C) T2 > T1 (D) mijksDr esa ls dksbZ ugha

The current-voltage (I-V) graphs for a given metallic wire at two temperatures
T1 and T2 are shown in Fig. (Q. No. 4). Then :
I T1

T2

V

Fig. (Q. No. 4)
(A) T1 = T2 (B) T1 > T2
(C) T2 > T1 (D) None of the above

1229/(Set : A) P. T. O.

(6) 1229/(Set : A)
5. fdlh NM+ pqacd ds pqacdh; f}/kzqo vk?kw.kZ dk SI ek=d gS % 1
(A) Am−2 (B) Am −1

(C) Am (D) Am2
The SI unit of magnetic dipole moment of a bar magnet is :
(A) Am−2 (B) Am −1
(C) Am (D) Am2

6. fdlh pqacdh; inkFkZ dh pqca dh; ço`fÙk χ rFkk vkisf{kd pqacd'khyrk µr esa laca/k gS % 1
(A) µr = 1 + χ (B) µr = 1 + χ 2
1
(C) µr = (D) µr = 1 − χ 2
χ
The relation between magnetic susceptibility χ and relative permeability µr of a
magnetic material is :
(A) µr = 1 + χ (B) µr = 1 + χ 2
1
(C) µr = (D) µr = 1 − χ 2
χ

7. fdlh çfrjks/kd R ls çokfgr çR;korhZ /kkjk i = I 0 sin ωt ds fy, twy rkiu ds dkj.k ek/; 'kfDr {k;
fdruk gksrk gS \ 1

1 2
(A) I 2R (B) I R
0 2 0

(C) 4 I 2R (D) 2 I 2R
0 0

For an alternating current i = I 0 sin ωt passing through a resistor R, how much
is the average power loss due to Joule heating ?

1 2
(A) I 2R (B) I R
0 2 0
(C) 4 I 2R (D) 2 I 2R
0 0

1229/(Set : A)

(7) 1229/(Set : A)
8. fdlh Js.khc) LCR ifjiFk esa vuquknh vko`fÙk ω0 dk eku fdruk gksrk gS \ 1
1
(A) LC (B)
LC
1
(C) LC (D)
LC
What is the value of resonant frequency ω0 of a series LCR circuit ?
1
(A) LC (B)
LC
1
(C) LC (D)
LC

9. fuokZr esa fuEu esa ls fdldh rjaxnS?;Z lcls de gS \ 1

(A) vojDr rjaxsa (B) X-fdj.ksa

(C) n`';çdk'k rjaxsa (D) jsfM;ks rjaxsa

Which of the following have lowest wavelength in vacuum ?

(A) Infrared waves (B) X-rays

(C) Visible light waves (D) Radio waves

10. 60° ds Økafrd dks.k okys fdlh ek/;e dk viorZukad gS % 1

3 2
(A) (B)
2 3

1 1
(C) (D)
3 2

1229/(Set : A) P. T. O.

(8) 1229/(Set : A)
The refractive index of a medium having critical angle of 60° is :
3 2
(A) (B)
2 3
1 1
(C) (D)
3 2
11. m æO;eku ds fdlh xfreku d.k dh xfrt ÅtkZ K gSA bl d.k ds lkFk tqM+h ns-czkWXyh rjaxnS?;Z λ gS % 1
h h
(A) (B)
K 2K
2h h
(C) (D)
2mK 2mK
K is the kinetic energy of a moving particle of mass m. The de-Broglie wavelength
λ associated with this particle is :
h h
(A) (B)
K 2K
2h h
(C) (D)
2mK 2mK

12. gkbMªkstu ijek.kq ds LisDVªe esa dkSu-lh Js.kh n`'; {ks= esa vkrh gS \ 1

(A) ckej Js.kh (B) ykbeSu Js.kh
(C) ik'ku Js.kh (D) czSdsV Js.kh
Which spectral series of hydrogen atom lies in the visible region ?

(A) Balmer series (B) Lyman series

(C) Paschen series (D) Bracket series

13. fdlh Z ijek.kq Øekad ds ijek.kq ij dqy fdruk vkos'k gksrk gS \ 1
(A) +Ze (B) − Ze
(C) 'kwU; (D) +(Z − 1)e

1229/(Set : A)

(9) 1229/(Set : A)
The net charge on an atom of atomic number Z as a whole is :

(A) +Ze (B) − Ze

(C) Zero (D) +(Z − 1)e

14. ,d ijek.kq æO;eku ek=d (1u) ds cjkcj gksrk gS % 1

(A) 1.660539 × 10 −27 kg (B) 1.660539 × 10 −23 kg

(C) 1.660539 × 10 −17 kg (D) 1.660539 × 10 −13 kg

One atomic mass unit (1u) equals :

(A) 1.660539 × 10 −27 kg (B) 1.660539 × 10 −23 kg

(C) 1.660539 × 10 −17 kg (D) 1.660539 × 10 −13 kg

15. fuEufyf[kr dFkuksa dks /;kuiwoZd if<+, % 1

vfHkdFku (A) : tc 'osr çdk'k dk dksbZ ladh.kZ çdk'k iqat fdlh dk¡p ds fçTe ij vkifrr gksrk gS]
rc çdk'k dk ifj{ksi.k gksrk gSA
dkj.k (R) : ek/;e dk viorZukad fofHkUu rjaxnS?;ks± ¼o.kks½± ds fy, fHkUu-fHkUu gksrk gSA
fuEufyf[kr fodYiksa esa ls lgh mÙkj pqfu, %
(A) vfHkdFku (A) o dkj.k (R) nksuksa lR; gSa rFkk dkj.k (R), vfHkdFku (A) dk lgh Li"Vhdj.k gSA
(B) vfHkdFku (A) o dkj.k (R) nksuksa lR; gSa ysfdu dkj.k (R), vfHkdFku (A) dk lgh Li"Vhdj.k ugha
gSA
(C) vfHkdFku (A) lR; gS ysfdu dkj.k (R) vlR; gSA
(D) vfHkdFku (A) rFkk dkj.k (R) nksuksa vlR; gSaA
1229/(Set : A) P. T. O.

( 10 ) 1229/(Set : A)
Read the following statements carefully :

Assertion (A) : When a narrow beam of white light passes through a glass
prism, it undergoes dispersion.

Reason (R) : The refractive index of medium for different wavelengths (colours)
is different.

Select the correct answer from the options given below :

(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct
explanation of Assertion (A).

(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the
correct explanation of Assertion (A).

(C) Assertion (A) is true, but Reason (R) is false.

(D) Both Assertion (A) and Reason (R) are false.

16. fuEufyf[kr dFkuksa dks /;kuiwoZd if<+, % 1

vfHkdFku (A) : ,do.khZ çdk'k iqta ds fdlh /kkrq i`"B ij vkifrr gksus ls mRiUu çdkf'kd bysDVªkWuksa dh
xfrt ÅtkZ esa forj.k (LçsM) gksrk gSA
dkj.k (R) : dk;Z-Qyu /kkrq ls ckgj fudyus ds fy, fdlh bysDVªkuW ds }kjk visf{kr U;wure ÅtkZ gSA
fuEufyf[kr fodYiksa esa ls lgh mÙkj pqfu, %
(A) vfHkdFku (A) o dkj.k (R) nksuksa lR; gSa rFkk dkj.k (R), vfHkdFku (A) dk lgh Li"Vhdj.k gSA
(B) vfHkdFku (A) o dkj.k (R) nksuksa lR; gSa] ysfdu dkj.k (R), vfHkdFku (A) dk lgh Li"Vhdj.k
ugha gSA
(C) vfHkdFku (A) lR; gS] ysfdu dkj.k (R) vlR; gSA
(D) vfHkdFku (A) rFkk dkj.k (R) nksuksa vlR; gSaA

1229/(Set : A)

( 11 ) 1229/(Set : A)
Read the following statements carefully :
Assertion (A) : The photoelectrons produced by a monochromatic light beam
incident on a metal surface have a spread in their kinetic
energies.
Reason (R) : Work function is the least energy required by an electron to come
out of the metal.

Select the correct answer from the options given below :
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct
explanation of Assertion (A).
(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the
correct explanation of Assertion (A).

(C) Assertion (A) is true, but Reason (R) is false.
(D) Both Assertion (A) and Reason (R) are false.

17. fuEufyf[kr dFkuksa dks /;kuiwoZd if<+, % 1

vfHkdFku (A) : rkieku ds c<+us ij fdlh n-çdkj ds v/kZpkyd dh çfrjks/kdrk de gks tkrh gSA
dkj.k (R) : rkieku ds c<+us ij eqDr bysDVªkWuksa rFkk vk;uksa ds chp Vdjkus dh nj c<+ tkrh gSA
fuEufyf[kr fodYiksa esa ls lgh mÙkj pqfu, %
(A) vfHkdFku (A) o dkj.k (R) nksuksa lR; gSa rFkk dkj.k (R), vfHkdFku (A) dk lgh Li"Vhdj.k gSA
(B) vfHkdFku (A) o dkj.k (R) nksuksa lR; gSa] ysfdu dkj.k (R), vfHkdFku (A) dk lgh Li"Vhdj.k
ugha gSA
(C) vfHkdFku (A) lR; gS] ysfdu dkj.k (R) vlR; gSA
(D) vfHkdFku (A) rFkk dkj.k (R) nksuksa vlR; gSaA
1229/(Set : A) P. T. O.

( 12 ) 1229/(Set : A)
Read the following statements carefully :
Assertion (A) : The resistivity of a n-type semiconductor decreases with an
increase in temperature.
Reason (R) : The rate of collision between free electrons and the ions increase
with an increase in temperature.
Select the correct answer from the options given below :
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct
explanation of Assertion (A).
(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the
correct explanation of Assertion (A).

(C) Assertion (A) is true, but Reason (R) is false.
(D) Both Assertion (A) and Reason (R) are false.

18. fuEufyf[kr dFkuksa dks /;kuiwoZd if<+, % 1

vfHkdFku (A) : fdlh 'kq) v/kZpkyd dh fo|qr~ pkydrk vifeJ.k djus ls c<+ tkrh gSA
dkj.k (R) : fdlh 'kq) v/kZpkyd dh vifeJ.k djus ls ges'kk eqDr bysDVªkuW ksa dh la[;k esa o`f) gksrh gSA
fuEufyf[kr fodYiksa esa ls lgh mÙkj pqfu, %
(A) vfHkdFku (A) o dkj.k (R) nksuksa lR; gSa rFkk dkj.k (R), vfHkdFku (A) dk lgh Li"Vhdj.k gSA
(B) vfHkdFku (A) o dkj.k (R) nksuksa lR; gSa] ysfdu dkj.k (R), vfHkdFku (A) dk lgh Li"Vhdj.k
ugha gSA
(C) vfHkdFku (A) lR; gS] ysfdu dkj.k (R) vlR; gSA
(D) vfHkdFku (A) rFkk dkj.k (R) nksuksa vlR; gSaA

1229/(Set : A)

( 13 ) 1229/(Set : A)
Read the following statements carefully :

Assertion (A) : The electrical conductivity of an intrinsic semiconductor
increases on doping.

Reason (R) : Doping always increases the number of free electrons in a pure
semiconductor.

Select the correct answer from the options given below :

(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct
explanation of Assertion (A).

(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the
correct explanation of Assertion (A).

(C) Assertion (A) is true, but Reason (R) is false.

(D) Both Assertion (A) and Reason (R) are false.

[k.M – c
SECTION – B
[ vfry?kq
vfry?kq mÙkjh; iz'u ]
[ Very Short Answer Type Questions ]

19. /kkrqvksa esa eqDr bysDVªkuW ksa ds Jkafrdky dks ifjHkkf"kr dhft,A eqDr bysDVªkWuksa ds viokg osx ,oa Jkafrdky
esa laca/k fyf[k,A 2
Define relaxation time of free electrons in a metal. Write the relation between
drift velocity of free electrons and their relaxation time.

20. ,sfEi;j ds ifjiFkh; fu;e dks ifjHkkf"kr dj fp= dh lgk;rk ls la{ksi esa le>kb,A 2

State Ampere's circuital law and explain it briefly using a diagram.

1229/(Set : A) P. T. O.

( 14 ) 1229/(Set : A)
vFkok
OR

ck;ks-lkoVZ ds fu;e dks fp= lfgr ifjHkkf"kr dhft,A 2
State Biot-Savart's law using a diagram.

21. 30 µF dk ,d la/kkfj= 220 V, 50 Hz lzksr ls tksM+k x;k gSA ifjiFk dk la/kkfj=h; çfr?kkr rFkk blesa
çokfgr gksus okyh /kkjk dk rms eku Kkr dhft,A 2
A 30 µF capacitor is connected to a 220 V, 50 Hz source. Find the capacitive
reactance and the rms value of the current in the circuit.
vFkok
OR
,d 'kfDr laçs"k.k ykbu vip;h VªkalQkeZj esa ftldh çkFkfed dqaMyh esa 4000 Qsjs gS]a 2200 oksYV ij
'kfDr fuosf'kr djrh gSA 220 oksYV dh fuxZr 'kfDr çkIr djus ds fy, f}rh;d esa fdrus Qsjs gksus
pkfg, \ 2

A power transmission line feeds input power at 2200 V to a step down
transformer with its primary windings having 4000 turns. What should be the
number of turns in the secondary in order to get output power at 220 V ?

22. oS|qr~pqacdh; rjaxsa D;k gSa \ budh çÑfr dSlh gS \ 2

What are electromagnetic waves ? What is their nature ?

23. 1.5 viorZukad ds ,d mÙky ysal dh ok;q esa Qksdl nwjh 15 lseh gSA bls 4/3 viorZukad ds æO; esa
Mqcksus ij bldh Qksdl nwjh fdruh gksxh \ 2

A convex lens of refractive index 1.5 has a focal length of 15 cm in air. What will
be its focal length when it is immersed in a liquid of refractive index 4/3 ?

1229/(Set : A)

( 15 ) 1229/(Set : A)
24. fdj.k vkjs[k }kjk iw.kZ vkarfjd ijkorZu dks le>kb,A 2
Explain total internal reflection by a ray diagram.

25. gkbMªkstu ijek.kq ds bysDVªkWu dh noha d{kk esa dqy ÅtkZ En = − 132.6 eV gSA bl d{kk esa bl
n
bysDVªkWu dh xfrt o fLFkfrt ÅtkZ dk eku Kkr dhft,A 2

The total energy of the electron in the nth orbit of hydrogen atom is
13.6
En = − eV . Calculate its kinetic and potential energies in this orbit.
n2

[k.M – l
SECTION – C

[ y?kq
y?kq mÙkjh;
Ùkjh; iz'u ]
[ Short Answer Type Questions ]

26. fLFkjoS|qfrdh ds fy, xkml dk fu;e fyf[k,A bl fu;e }kjk fl) dhft, fd fdlh ,dleku vkosf'kr
irys xksyh; [kksy ds vanj fo|qr~ {ks= 'kwU; gksrk gSA 3

State the Gauss's law of electrostatics. Using it prove that electric field inside a
uniformly charged thin spherical shell is zero.

vFkok
OR

(a) fo|qr~ {ks= esa fdlh fcanq ij fLFkjoS|qr~ foHko dks ifjHkkf"kr dhft,A 1

Define electrostatic potential at a point in an electric field.

1229/(Set : A) P. T. O.

( 16 ) 1229/(Set : A)
(b) 600 µF ds fdlh la/kkfj= dks 10 V dh cSVjh ls vkosf'kr fd;k x;k gSA la/kkfj= esa lafpr dqy
fLFkj oS|qr~ ÅtkZ fdruh gS \ 2

A 600 µF capacitor is charged by a 10 V battery. How much electrostatic
energy is stored in the capacitor ?

27. ehVj lsrq dk fl)kar fyf[k,A blds }kjk fdlh vKkr çfrjks/k dk eku Kkr djus ds fy, ifjiFk fp=
cukb,A 3

Write the principle of meter bridge. Draw its circuit diagram to determine the
value of an unknown resistance.

vFkok

OR

fo|qr~ ifjiFk ds fdjpkWQ dk fu;e fyf[k,A 3
Write Kirchoff's Law of Electrical Circuit.

28. ;ax ds f}f>jh ç;ksx esa nks f>fj;ksa dh pkSM+kbZ dk vuqikr 4 : 1 gSA O;frdj.k iSVuZ esa vf/kdre rFkk
U;wure rhozrk ds vuqikr dks Kkr dhft,A 3

In Young's double slit experiment, the ratio of width of two slits is 4 : 1 . Find
the ratio of maximum and minimum intensities in the interference pattern.

29. fujks/kh foHko ij vkifrr fofdj.k dh vko`fÙk dk çHkko n'kkZus okyk vkjs[k [khafp,A bls vkbaLVhu ds
çdk'k-fo|qr~ lehdj.k dk mi;ksx djds le>kb,A 3

Draw a graph showing effect of frequency of incident radiation on stopping
potential. Explain it by using Einstein's photoelectric equation.

1229/(Set : A)

( 17 ) 1229/(Set : A)
30. cksg~j ds gkbMªkstu ijek.kq ds vfHkx`ghr fyf[k,A 3

State Bohr Postulates of Hydrogen atom.

[k.M – n
SECTION – D

[ nh?kZ mÙkjh; iz'u ]

[ Long Answer Type Questions ]

31. fdlh pydqaMyh xSYosuksehVj ds fl)kar dks fyf[k,A bls ,sehVj esa dSls cnyk tkrk gS \ bldh /kkjk
lqxkz fgrk dk O;atd fyf[k,A 5

Write the principle of a moving coil galvanometer. How is it converted into an
ammeter ? Write the expression for its current sensitivity.

vFkok
OR

fdlh pydqaMyh xSYosuksehVj ds fl)kar dks fyf[k,A bls oksYVehVj esa dSls cnyk tkrk gS \ bldh oksYVrk
lqxzkfgrk dk O;atd fyf[k,A 5

Write the principle of a moving coil galvanometer. How is it converted into a
voltmeter ? Write the expression for its voltage sensitivity.

32. fdlh viorZd [kxksyh; nwjchu esa çfrfcac cuus dk ukekafdr fdj.k vkjs[k cukdj le>kb,A bldh
vko/kZu {kerk dks ifjHkkf"kr dhft, rFkk blds fy, O;atd fyf[k,A 5

1229/(Set : A) P. T. O.

( 18 ) 1229/(Set : A)
Draw a labelled ray diagram showing the image formation in a refracting
astronomical telescope and explain it. Define its magnifying power and write
expression for it.

vFkok

OR

fdlh la;qDr lw{en'khZ esa çfrfcac cuus dk ukekafdr fdj.k vkjs[k cukdj le>kb,A bldh vko/kZu {kerk
dks ifjHkkf"kr dhft, rFkk blds fy, O;atd fyf[k,A 5

Draw a labelled ray diagram showing the image formation in a compound
microscope and explain it. Define its magnifying power and write expression for
it.

33. fn"Vdkjh D;k gksrk gS \ ,d iw.kZrjax fn"Vdkjh dk ifjiFk vkjs[k cukb,A buds fuos'kh rFkk fuxZr
oksYVrkvksa ds rjax:i dks le>kb,A 5

What is a rectifier ? Draw the circuit diagram of a full-wave rectifier. Explain its
input and output voltage waveforms.
vFkok
OR

fdlh p-n laf/k Mk;ksM ds vxzfnf'kd rFkk i'pfnf'kd ck;l esa I-V vfHkyk{kf.kd [khafp,A bUgsa mfpr
ifjiFk vkjs[kksa dh lgk;rk ls le>kb,A 5
Draw the I-V characteristics of a p-n junction diode in forward and reverse bias.
Explain them using appropriate circuit diagrams.

1229/(Set : A)

( 19 ) 1229/(Set : A)
[k.M – ;
SECTION – E

[ dsl LVMh vk/kkfjr ç'u ]
[ Case Study Based Questions ]

34. fuEu vuqPNsn ¼iSjkxzkQ½ dks if<+, rFkk blds ckn fn;s x;s ç'uksa ds mÙkj nhft, %
fo|qr~ {ks= js[kk,¡ % fo|qr~ {ks= js[kk,¡ vkos'kksa ds vfHkfoU;kl ds pkjksa vksj fo|qr~ {ks= ds fp=kRed fu:i.k
dk ,d mik; gSA O;kid :i esa] fo|qr~ {ks= js[kk ,d ,slk oØ gksrk gS ftlds fdlh Hkh fcanq ij [khapk
x;k Li'khZ (tangent) ml fcanq ij usV fo|qr~ {ks= dh fn'kk dks fu:fir djrk gSA fo|qr~ {ks= js[kk ,d
fnd~LFkku oØ (space curve) gksrh gSA fofHkUu fcanqvksa ij fo|qr~ {ks= js[kkvksa dk vkisf{kd la[;k ?kuRo
¼vFkkZr fudVrk½ mu fcanv q ksa ij fo|qr~ {ks= E dh vkisf{kd çcyrk dks bafxr djrk gSA fo|qr~ {ks= js[kk,¡
/kukos'k ls vkjEHk gksdj _.kkos'k ij lekIr gksrh gSaA fdlh vkos'k eqDr {ks= esa fo|qr~ {ks= js[kkvksa dks
,sls larr oØ ekuk tk ldrk gS tks dgha ugha VwVrsA fLFkjoS|qr~ {ks= js[kk,¡ can ywi ugha cukrhaA

Read the following paragraph and answer the questions that follow :

Electric Field Lines : Electric field lines are a way of pictorially mapping
electric field around a configuration of charges. An electric field line is in
general, a curve drawn in such a way that tangent to it at any point gives the
direction of the net electric field at that point. An electric field line is a space
curve. Relative density (i.e. closeness) of electric field lines at different points
indicate the relative strength of electric field at those points. Electric field lines
start from positive charge and end at negative charge. In a charge free region
electric field lines may be taken to be continuous curves without any break.
Electrostatic field lines do not form any closed loops.

1229/(Set : A) P. T. O.

( 20 ) 1229/(Set : A)
(i) ,dy /kukRed vkos'k ds dkj.k fo|qr~ {ks= js[kk,¡ gksrh gSa % 1
(A) o`Ùkkdkj] okekorZ (B) o`Ùkkdkj] nf{k.kkorZ
(C) f=T;r%] vareqZ[kh (D) f=T;r%] cfgeqZ[kh
Electric field lines about a positive point charge are :
(A) circular, anticlockwise (B) circular, clockwise
(C) radial, inward (D) radial, outward
(ii) fp= {ç0 lala0 34(ii)} esa fdlh fo|qr~ {ks= dks {ks= js[kkvksa }kjk n'kkZ;k x;k gSA ;fn E A , E B
vkSj EC Øe'k% A, B o C fcanqvksa ij fo|qr~ {ks= dh çcyrk gks] rks % 1

A B C

fp= {ç0 la
l0a 34(ii)}
(A) E A > E B > EC (B) E A = E B = EC
(C) E A = EC > EB (D) E A = EC < E B

Fig. {Q. No. 34(ii)} shows some of the field lines corresponding to the
electric field. If E A , E B and EC be the electric fields at points A, B and C
respectively, then :

A B C

Fig. {Q. No. 34(ii)}
(A) E A > E B > EC (B) E A = E B = EC
(C) E A = EC > EB (D) E A = EC < E B

(iii) fo|qr~ {ks= js[kkvksa ds nks xq.k fy[ksaA 2

Write two properties of Electric Field Lines.

1229/(Set : A)

( 21 ) 1229/(Set : A)
vFkok
OR

fo|qr~ {ks= D;k gS \ bldk ek=d fy[ksaA 2
What is Electric Field ? Write its unit.

35. fuEu vuqPNsn ¼iSjkxzkQ½ dks if<+, rFkk blds ckn fn;s x;s ç'uksa ds mÙkj nhft, %
pqacdh; ¶yDl rFkk QSjkMs dk çsj.k dk fu;e % ;fn fdlh A {ks=Qy okys lrg ds fofHkUu Hkkxksa ij
pqacdh; {ks= B ds ifj.kke rFkk fn'kk,¡ fHkUu-fHkUu gksa] fp= ¼ç0 la0 35½ rks lrg ls gksdj xqtjus
okyk pqacdh; ¶yDl φB dks bl rjg vfHkO;Dr fd;k tkrk gS %
→ →
φB = ∫ B . d A
A

→
B
→
dA
fp= ¼ç0 la0 35½
çk;ksfxd çs{k.kksa ds vk/kkj ij QSjkMs bl fu"d"kZ ij igq¡ps fd tc fdlh dqaMyh esa ls pqacdh; ¶yDl le;
ds lkFk ifjofrZr gksrk gS rc dqaMyh esa fo|qr~ okgd cy çsfjr gksrk gSA QSjkMs us vius bl fu"d"kZ dks
,d fu;e ds :i esa O;Dr fd;k ftls QSjkMs dk oS|qr~pqpqacdh; çsj.k dk fu;e dgrs gSaA bl fu;e dks
xf.krh; :i esa fuEu çdkj ls vfHkO;Dr fd;k x;k gS %

1229/(Set : A) P. T. O.

( 22 ) 1229/(Set : A)
dφ
ε=− B
dt

tcfd ε çsfjr fo|qr~ okgd cy gS rFkk _.k fpg~u ε dh fn'kk rFkk ifj.kker% can ywi esa çsfjr /kkjk dh
fn'kk O;Dr djrk gSA ikl-ikl yisVs gq, N Qsjksa okyh dqMa yh ds çR;sd Qsjs ls lac) ¶yDl esa ,dleku
ifjorZu gksrk gSA blfy, dqy çsfjr fo|qr~ okgd cy dk O;atd gksxk %
dφ B
ε = −N
dt
;gk¡ φB dqaMyh ds ,d Qsjs ls lac) pqacdh; ¶yDl gSA
Read the following paragraph and answer the questions that follow :

Magnetic flux and Faraday's Law of induction : If a magnetic field has
different magnitudes and directions at various parts of a surface Fig. (Q. No. 35),
then the magnetic flux through the surface is given by :

→ →
φB = ∫ B . d A
A

→
B
→
dA
Fig. (Q. No. 35)
On the basis of experimental observations, Faraday concluded that an emf is
induced in a coil when magnetic flux through it changes with time. Faraday
stated his conclusion in the form of a law called Faraday's law of electromagnetic
induction. This law is expressed mathematically as :

1229/(Set : A)

( 23 ) 1229/(Set : A)
dφ
ε=− B
dt

where ε is the induced emf and the negative sign indicates the direction of
induced emf ε and hence the direction of induced current in a closed loop. In the
case of a closely wound coil of N turns, change of flux associated with each turn
is the same. So the total induced emf is given by :
dφ
ε = −N B
dt
Here φ B is the magnetic flux associated with one turn of the coil.
(i) pqca dh; ¶yDl dk SI ek=d gS % 1
(A) VsLyk (B) xkml
(C) vksLVsZM (D) oscj
SI unit of magnetic flux is :
(A) Tesla (B) Gauss
(C) Oersted (D) Weber

(ii) lrg {ks=Qy A dh ,d oxkZdkj pknj PQRS gSA bl pknj ds dsoy vk/ks {ks=
→
{fp= ç0 la0 35(ii)} ij ,dleku pqacdh; {ks= B yxk gqvk gSA bl pknj PQRS ls lac)
pqacdh; ¶yDl gS % 1

P Q

→
B

S R
{fp= ç0 la0 35(ii)}
(A) 1/2 BA (B) BA
(C) 0 (D) 2 BA

1229/(Set : A) P. T. O.

( 24 ) 1229/(Set : A)
→
PQRS is a square sheet of surface area A. A uniform magnetic field B
parallel to plane of PQRS acts only in half of the region as shown in
(Fig. Q. No. 35(ii)}. The magnetic flux linked with PQRS is :
P Q

→
B

S R
{Fig. Q. No. 35(ii)}
(A) 1/2 BA (B) BA
(C) 0 (D) 2 BA

(iii) pqca dh; ¶yDl D;k gS \ 2
What is Magnetic Flux ?

vFkok
OR

1000 Qsjksa okyh dqaMyh ds fljksa ds chp 2 V dk fo|qr~ okgd cy (emf) çsfjr gksrk gSA çR;sd
Qsjs dk {ks=Qy 10 cm2 gSA pqca dh; {ks= cnyus dh nj fudkfy,A 2
An emf of 2 V is induced across the ends of 1000 turns coil. Area of each
turn is 10 cm2 . Determine at which rate the magnetic field is changing.

S
1229/(Set : A)

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