UPSEE 2019 Paper 3

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UU PAPER-3 àíZnwpñVH$m H«$‘m§H$ àíZnwpñVH$m H$moS> UU
UU AZwH«$‘m§H$ / Roll No.
Question Booklet Sr. No. UU
UU AA UU
UU Q. Booklet Code
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CÎma-erQ> H«$‘m§H$ / OMR Answer Sheet No.
UU UU
UU UU
UU KmofUm : / Declaration : UU
UU ‘¢Zo n¥îR> g§»¶m 1 na {X¶o J¶o {ZX}em| H$mo n‹T>H$a g‘P {b¶m h¡&
I have read and understood the instructions given on page No. 1
narjm Ho$ÝÐmܶj H$s ‘moha
Seal of Superintendent of Examination Centre
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UU narjmWu H$m hñVmja /Signature of Candidate UU
(AmdoXZ nÌ Ho$ AwZgma /as signed in application) H$j {ZarjH$ Ho$ hñVmja /Signature of the Invigilator
UU UU
narjmWu H$m Zm‘/
Name of Candidate :

narjmWu H$mo {X¶o n¡amJ«m’$ H$s ZH$b ñd¶§ H$s hñV{b{n ‘| ZrMo {X¶o J¶o [a³V ñWmZ na ZH$b (H$m°nr) H$aZr h¡&
""Amn ghr ì¶dgm¶ ‘| h¢, ¶h Amn V^r OmZ|Jo O~ : Amn H$m‘ na OmZo Ho$ {bE qM{VV h¢, Amn {Z˶ AnZm H$m‘ g~go AÀN>m H$aZm MmhVo h¢, Am¡a Amn AnZo H$m¶© Ho$
‘hËd H$mo g‘PVo h¢&'' AWdm / OR
To be copied by the candidate in your own handwriting in the space given below for this purpose is compulsory.
‘‘You will know you are in the right profession when : you wake anxious to go to work, you want to do your best daily, and you know your work is
important.”

* Bg n¥îR> H$m D$nar AmYm ^mJ H$mQ>Zo Ho$ ~mX drjH$ Bgo N>mÌ H$s OMR sheet Ho$ gmW gwa{jV aIo&
* After cutting half upper part of this page, invigilator preserve it along with student’s OMR sheet.

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nwpñVH$m ‘| ‘wIn¥îR> g{hV n¥îR>m| H$s g§»¶m g‘¶ 2.30 K§Q>o A§H$ / Marks nwpñVH$m ‘| àíZm| H$s g§»¶m 100 Questions &
No. of Pages in Booklet including title
32 Time 2.30 Hours 600 No. of Questions in Booklet Drawing sheet

Part A - 32 Pages àíZnwpñVH$m H«$‘m§H$/ Question Booklet Sr. No.
PAPER-3 : Part B - 04 Pages

AZwH«$‘m§H$ / Roll No.
H$j {ZarjH$ Ho$ hñVmja /Signature of the Invigilator
àíZnwpñVH$m H$moS>
narjmWu H$m Zm‘/
Name of Candidate : AA
Q. Booklet Code
narjm{W©¶m| Ho$ {bE {ZX}e /INSTRUCTIONS TO CANDIDATE
Aä¶{W©¶m| hoVw Amdí¶H$ {ZX}e : Instructions for the Candidate :
1. Amo.E‘.Ama. CÎma n{ÌH$m ‘| Jmobm| VWm g^r à{dpîQ>¶m| H$mo ^aZo Ho$ {bE Ho$db Zrbo ¶m 1. Use BLUE or BLACK BALL POINT PEN only for all entries and for filling the
H$mbo ~mb ßdmB§Q> noZ H$m hr Cn¶moJ H$a|& bubbles in the OMR Answer Sheet.
2. SECURITY SEAL ImobZo Ho$ nhbo Aä¶Wu AnZm Zm‘, AZwH«$‘m§H$ (A§H$m| ‘|) 2. Before opening the SECURITY SEAL of the question booklet, write your
Name, Roll Number (In figures), OMR Answer-sheet Number in the space
Amo.E‘.Ama. CÎma-erQ> H$m H«$‘m§H$ Bg àíZ-nwpñVH$m Ho$ D$na {X¶o J¶o ñWmZ na {bI|& provided at the top of the Question Booklet. Non-compliance of these
¶{X do Bg {ZX}e H$m nmbZ Zht H$a|Jo Vmo CZH$s CÎma-erQ> H$m ‘yë¶m§H$Z Zhr hmo gHo$Jm instructions would mean that the Answer Sheet can not be evaluated leading
VWm Eogo Aä¶Wu A¶mo½¶ Kmo{fV hmo Om¶|Jo& the disqualification of the candidate.
3. PART A H$m à˶oH$ àíZ nm±M A§H$m| H$m h¡& {Og àíZ H$m CÎma Zht {X¶m J¶m h¡, Cg 3. Each question of PART A carries FIVE marks. No marks will be awarded for
na H$moB© A§H$ Zht {X¶m Om¶oJm& JbV CÎma na A§H$ Zht H$mQ>m OmEJm& unattempted questions. There is no negative marking on wrong answer.
4. Each multiple choice questions has only one correct answer and marks shall
4. g^r ~hþ{dH$ënr¶ àíZm| ‘| EH$ hr {dH$ën ghr h¡, {Ogna A§H$ Xo¶ hmoJm& be awarded for correct answer.
5. PART B ‘| Xmo àíZ h¢& à˶oH$ àíZ 50 A§H$mo H$m h¡& 5. PART B contists of TWO questions of FIFTY marks each
6. JUH$, bm°J Q>o{~b, ‘mo~mBb ’$moZ, Bbo³Q´>m°{ZH$ CnH$aU VWm ñbmBS> ê$b Am{X H$m 6. Use of calculator, log table, mobile phones, any electronic gadget and slide
à¶moJ d{O©V h¡& rule etc. is strictly prohibited.
7. Candidate will be allowed to leave the examination hall at the end of
7. Aä¶Wu H$mo narjm H$j N>moS>Zo H$s AZw‘{V narjm Ad{Y H$s g‘mpßV na hr Xr Om¶oJr& examination time period only.
8. ¶{X {H$gr Aä¶Wu Ho$ nmg nwñVH|$ ¶m Aݶ {b{IV ¶m N>nr gm‘J«r, {Oggo do ghm¶Vm 8. If a candidate is found in possession of books or any other printed or written
bo gH$Vo/gH$Vr h¢, nm¶r Om¶oJr, Vmo Cgo A¶mo½¶ Kmo{fV H$a {X¶m Om gH$Vm h¡& Bgr material from which he/she might derive assistance, he/she is liable to be
àH$ma, ¶{X H$moB© Aä¶Wu {H$gr ^r àH$ma H$s ghm¶Vm {H$gr ^r ómoV go XoVm ¶m boVm treated at disqualified. Similarly, if a candidate is found giving or obtaining (or
(¶m XoZo H$m ¶m boZo H$m à¶mg H$aVm) hþAm nm¶m Om¶oJm, Vmo Cgo ^r A¶mo½¶ Kmo{fV {H$¶m attempting to give or obtain) assistance from any source, he/she is liable to
be disqualified.
Om gH$Vm h¡&
9. {H$gr ^r ^«‘ H$s Xem ‘| àíZ-nwpñVH$m Ho$ A§J«oOr A§e H$mo hr ghr d A§{V‘ ‘mZm 9. English version of questions paper is to be considered as authentic and final
Om¶oJm& to resolve any ambiguity.
10. OMR sheet Bg Paper Ho$ ^rVa h¡ VWm Bgo ~mha {ZH$mbm Om gH$Vm h¡ naÝVw 10. OMR sheet is placed within this paper and can be taken out from this paper
Paper H$s grb Ho$db nona ewé hmoZo Ho$ g‘¶ na hr Imobm Om¶oJm& but seal of paper must be opened only at the start of paper.

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UU PAPER-3
Aptitude Test for Architecture & Design
Mathematics & Aesthetic Sensitivity – Part A : Q. 1 to 100
Drawing Aptitude – Part B : Q. 1 & 2

PART-A / ^mJ-A
MATHEMATICS & AESTHETIC SENSITIVITY / J{UV Am¡a EñWo{Q>H$ g|{gQ>r{dQ>r

001. The distance between the points of intersection 001. aoIm y = 12 x - 52 Am¡a nadb`
1 5 1
of the line y = 2 x - 2 and the parabola y = - 2 (x - 1) (x - 2) Ho$ à{VÀN>oX {~ÝXwAm|
1
y = - 2 (x - 1) (x - 2) is Ho$ ~rM H$s Xyar h¡&
(A) 5 (B) 2 5 (A) 5 (B) 2 5
(C) 3 5 (D) 4 5 (C) 3 5 (D) 4 5

1
002. If f (x) = x - 1 , then the domain of 002. `{X f (x) = x -1 1 , V~ (f % f) (x) H$m àm§V
(f % f) (x) is (domain) h¡&
(A) # x ! R x ! 1 - (A) # x ! R x ! 1 -
(B) # x ! R x ! 1, 2 - (B) # x ! R x ! 1, 2 -
(C) # x ! R x ! 0, 1 - (C) # x ! R x ! 0, 1 -
(D) # x ! R x ! 2 - (D) # x ! R x ! 2 -

3-AA ] [2] [ Contd...

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1 1
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003. If x = 2 + 3 then the value of x- 003. `{X x = 2 + 3 V~ x- H$m ‘mZ h¡& UU
x x
is UU
(A) 2 6 (B) 6 UU
(A) 2 6 (B) 6 UU
(C) 2 2 (D) 2 (C) 2 2 (D) 2 UU
UU
UU
1- i UU
004. Let z1 = 1 + 2i, z2 = 2 , z3 = - 2 + i , The 004. ‘mZm {H$ z1 = 1 + 2i, z2 = 1 -2 i , z3 = - 2 + i UU
zz
real part of 4z 1-2 z is zz
2 3 V~ 4z 1-2 z H$m dmñV{dH$ ^mJ (real part) h¡&
7 9 2 3
(A) 50 (B) 50 7 9
(A) 50 (B) 50
11 13
(C) 50 (D) 50 11 13
(C) 50 (D) 50

005. Sum of real and imaginary parts of the 005. gpå‘l g§»`m (complex number) z , Omo
complex number z which satisfies the {ZåZ{bpIV g‘rH$aU H$mo g§Vwï> H$aVr h¡
following equation z - 1 + 2iz - i = 0 is z - 1 + 2iz - i = 0 Ho$ dmñV{dH$ Am¡a H$mën{ZH$
2 2
(A) 3 (B) – 3 ^mJm| H$m `moJ h¡&
(C) 0 (D) 1 2 2
(A) 3 (B) – 3
(C) 0 (D) 1

006. The modulus of 13 - 6i is
006. 13 - 6i H$m ‘mnm§H$ (modulus) h¡&
(A) 1 (B) 3
(A) 1 (B) 3
(C) 5 (D) 7
(C) 5 (D) 7

007. Let P, Q be n × n matrices. Let O and I be, 007. ‘mZm {H$ n × n Amì`yh (matrix) P, Q h¢& ‘mZm
the zero and identity matrices of order n, {H$ O Am¡a I H«$‘e… eyÝ` Amì`yh (zero matrix)
respectively. Suppose P + Q = I and PQ = 0 VWm VËg‘H$ (identity matrix) h¢& ‘mZm {H$
Then which of the following options is P + Q = I and PQ = 0
always CORRECT? V~ {ZåZ {dH$ënm| ‘| go H$m¡Z gm gX¡d gË` h¡?
2 2 2 2 2 2 2 2
(A) P + Q = 0 (B) P +Q = I (A) P + Q = 0 (B) P +Q = I
2 2 2 2 2 2 2 2
(C) P - Q = 0 (D) P -Q = I (C) P - Q = 0 (D) P -Q = I

3-AA ] [3] [ P.T.O.

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UU 008. If the system of linear equations 008. `{X a¡pIH$ g‘rH$aUm| Ho$ {ZH$m` (system of
UU
> H> H = > H has infinitely many
x1
H> H = > H Ho$
t - 2t 0
linear equations) >
UU t - 2t x1 0
UU 3 6t x2 0 3 6t x2 0
UU solutions, then the possible values of t are
UU AZ§V hb (infinitely many solutions) h¢, Vmo t
UU (A) 0, –1 (B) 0, 1 Ho$ gå^m{dV ‘mZ (possible values) h¢&
UU (C) 1, 2 (D) 1, – 2
UU (A) 0, –1 (B) 0, 1
UU (C) 1, 2 (D) 1, – 2

R V R V
S1 1 1 W S1 1 1 W
009. If det SS 1 2 8 WW= 0 , then the values of t are 009. `{X SS1 2 8 WW= 0
SS 1 t t3 WW SS 1 t t3 WW
T X T X
(A) 1, 2, 3 (B) 1, 2, – 3 V~ t Ho$ ‘mZ h¢&
(C) 1, – 2, 3 (D) –1, 2, 3 (A) 1, 2, 3 (B) 1, 2, – 3
(C) 1, – 2, 3 (D) –1, 2, 3

010. The number of real solutions of the equation 010. g‘rH$aU 2 + 2x - 3 = 3x + 7
2 + 2x - 3 = 3x + 7 is Ho$ dmñV{dH$ ‘mZm| (real solutions) {H$ g§»`m h¡
(A) 0 (B) 1 (A) 0 (B) 1
(C) 2 (D) 3 (C) 2 (D) 3

011. A root of the equation 011. g‘rH$aU 2x = 2x + 5 + 1 , H$m EH$ ‘yb
2x = 2x + 5 + 1 , (root) {H$g g‘rH$aU H$m ^r EH$ ‘yb h¡
is also a root of the equation
2 2
(A) 2x - x - 1 = 0 (A) 2x - x - 1 = 0
2 2
(B) x - 3x + 2 = 0 (B) x - 3x + 2 = 0
2 2
(C) 2x + 5x - 2 = 0 (C) 2x + 5x - 2 = 0
2 2
(D) 2x + 3x - 1 = 0 (D) 2x + 3x - 1 = 0

3-AA ] [4] [ Contd...

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012. Let a1, a2, a3, .... be an arithmetic progression 012. ‘mZm {H$ a1, a2, a3, .... EH$ g‘m§Va loUr ‘| h¢ UU
UU
with nonzero common difference. It is given {OgH$m gmd© A§Va (common difference) AeyÝ` UU
17
(nonzero) h¡& {X`m J`m h¡ {H$ UU
that / ai = 66 and ak = 8 for some k 17 UU
i= 5
/ ai = 66 Am¡a {H$gr k Ho$ {bE ak = 8 V~ k UU
Then the value of k is i= 5 UU
(A) 8 (B) 9 H$m ‘mZ h¡ UU
(C) 10 (D) 11 (A) 8 (B) 9 UU
UU
(C) 10 (D) 11

013. Let S be the set of all right angled triangles 013. ‘mZm {H$ S CZ g‘H$moU {Ì^wOm| (right angled
with integer sides forming consecutive terms triangles) H$m EH$ gå‘wM` h¡ {OZH$s ^wOmE§ EH$
of an arithmetic progression. The number of g‘m§Va loUr Ho$ bJmVma nX (consecutive terms )
triangles in S with perimeter less than 70 is ~ZmVo h¢& gå‘wM` S Ho$ CZ {Ì^wOm| {H$ g§»`m {OZH$s
(A) 0 (B) 1 n[a{Y (perimeter) 70 go H$‘ h¡, h¡
(C) 3 (D) 5 (A) 0 (B) 1
(C) 3 (D) 5

a - b cos x 1
014. It is given that lim 2 = 2 014. {X`m J`m h¡ {H$
x"0 x
The value of a + b is
lim a - b2cos x = 1 V~ a + b H$m ‘mZ h¡
(A) 0 (B) 1 x"0 x 2
(A) 0 (B) 1
(C) 2 (D) 3
(C) 2 (D) 3

015. The sum of intercepts on the axes of the 015. dH«$ x + y = 2 3 H$s (3,3) na ñne©aoIm
tangent to the curve x+ y = 2 3 at (tangent) Ho$ Ajm| (axes) na A§V:I§S>
(3, 3) is (intercepts) H$m `moJ h¡
(A) 4 (B) 8 (A) 4 (B) 8
(C) 12 (D) 16 (C) 12 (D) 16

3-AA ] [5] [ P.T.O.

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UU 1 2
UU 016. If f (x) = 2 x - x then the function f 016. `{X f (x) = 12 x2 - x V~ ’$bZ function f
UU (A) increases monotonically in (– ∞, 0) (A) (– ∞, 0) ‘| {Za§Va dY©‘mZ
UU
UU (B) decreases monotonically in (1, ∞ ) (increases monotonically) h¡
UU (C) attains its maximum value at x = 0 (B) (1, ∞ ) ‘| {Za§Va õmg‘mZ h¡
UU (D) attains its minimum value at x = 1 (C) x = 0 na CÀMV‘ ‘mZ àmßV H$aVm h¡
UU
UU (D) x = 1 na {ZåZV‘ ‘mZ àmßV H$aVm h¡
UU
If the function f (x) = * 3
x + 2, x#c
017. 017. `{X ’$bZ (function)
x -4 x2c
f (x) = * 3
x + 2, x#c
is continuous then the value of f (c) is
x -4 x2c
(A) 2 (B) 3
g§VV (continuous) h¡, V~ f (c) H$m ‘mZ h¡
(C) 4 (D) 5
(A) 2 (B) 3
(C) 4 (D) 5

If it is known that dx _ f (2x) i = x , then the _ f (2x) i = x
d 2 d 2
018. 018. `{X `h kmV h¡ {H$ dx
value of f ′ (1) is V~ f ′ (1) H$m ‘mZ h¡
1 1 1 1
(A) 4 (B) 8 (A) 4 (B) 8
1 1 1 1
(C) 12 (D) 16 (C) 12 (D) 16

2
019. The area enclosed by the curves x = 2y and 019. dH«$m| x2 = 2y Am¡a y2 = 16x go {Kam joÌ’$b
2
y = 16x is (area) h¡
31 32 31 32
(A) 3 (B) 3 (A) 3 (B) 3
34 35 34 35
(C) 3 (D) 3 (C) 3 (D) 3

3-AA ] [6] [ Contd...

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020. If [y] denotes the greatest integer less than or 020. `{X y ! R go H$‘ `m y Ho$ ~am~a ‘hÎm‘ nyUmªH$ UU
UU
equal to y for all y ! R , then the value of the J«hU H$aZo dmbo ’$bZ H$mo [y] go {Zé{nV {H$`m UU
integral J`m hmo Vmo g‘mH$bZ (integral) UU
2 UU
w 7 x2 Adx is
2

w 7 x Adx H$m ‘mZ h¡
2
UU
1 1 UU
(A) 5 + 3 - 2 (A) 5 + 3 - 2 UU
UU
(B) 5 - 3 + 2 (B) 5 - 3 + 2 UU
(C) 5 + 3 + 2 (C) 5 + 3 + 2
(D) 5 - 3 - 2 (D) 5 - 3 - 2

r r
021. The value of w sinxdx+ is 021. w sinxdx+ H$m ‘mZ h¡
-r
e 1 e 1
-r
r
(A) 2 (B) π r
(A) 2 (B) π
(C) 0 (D) 1
(C) 0 (D) 1

5r 3 5r 3
5r 3 5r 3

022. If . = w e cosx dx then w x e cosx dx is 022. `{X . = w e cosx
dx V~ w x e cosx dx h¡
r 3 r 3
r 3 r 3

r 2r r 2r
(A) 3 . (B) (A) 3 . (B) 3 .
3 .
5r 5r
(C) (D) (C) 3 . (D) r.
3 . r.

023. If the solution of the differential equation 023. `{X AdH$b g‘rH$aU (differential equation)
dy dy
x dx - 2 (y + k) = 0 represents a family of x dx - 2 (y + k) = 0

parabola having vertex at (0, 0) and axis H$m hb nadb`m| Ho$ Hw$b (family of
along the x-axis, then the value of k is parabola) {OZH$m erf© (0,0) Am¡a H|$Ð x - Aj

(A) 0 (B) 1 na hmo H$mo {Zé{nV H$aVm h¡, V~ k H$m ‘mZ h¡
(C) 2 (D) 3 (A) 0 (B) 1
(C) 2 (D) 3

3-AA ] [7] [ P.T.O.

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UU 024. The solution of the differential equation 024. AdH$b g‘rH$aU (differential equation)
UU 2 dy 2 2 dy 2
UU x + 2xy dx = y represents the family of x + 2xy dx = y
UU curves given by the equation H$m hb CZ dH«$m| Ho$ Hw$b (family of curves) H$mo
UU 2
(A) x + (y - k) = k
2 2
{Zé{nV H$aVm h¡ {OZH$s g‘rH$aU Xr OmVr h¡
UU 2 2 2 2 2 2
UU (B) x + k = k (A) x + (y - k) = k
UU 2
(C) (x - k) + (y - k) = k
2 2 2
(B) x + k = k
2 2

UU 2 2 2 2 2 2
(D) (x - k) + y = k (C) (x - k) + (y - k) = k
UU
2 2 2
(D) (x - k) + y = k

025. A curve C is drawn such that the slope at a 025. EH$ dH«$ Bg Vah ItMm OmVm h¡ {H$ EH$ q~Xw
x x
point P(x, y) is equal to y . Then the curve P(x, y) na {OgH$s T>mb y Ho$ ~am~a h¡& V~ dH«$
represents a family of {H$g Hw$b H$mo {Zé{nV H$aVm h¡
(A) circles (B) parabolas (A) d¥Îm (circles)
(C) ellipses (D) hyperbolas (B) nadb` (parabolas)
(C) XrK©d¥Îm (ellipses)
(D) A{Vnadb` (hyperbolas)

2 2
026. Two pairs of straight lines 12x - xy - y = 0 026. gab aoImAm| (pairs of straight lines) Ho$ Xmo Omo‹S>o
2 2 2 2
and 3x - 13xy + 4y = 0 represent 12x - xy - y = 0 Am¡a
2 2
(A) four distinct lines passing through 3x - 13xy + 4y = 0 {Zé{nV H$aVo h¢
the origin (A) ‘yb q~Xw go JwOaZo dmbr Mma AbJ-AbJ
(B) one common line and two other lines aoImE§
parallel to each other (B) EH$ C^`{Zð> aoIm (common line) VWm Xmo
(C) one common line and two other lines AÝ` EH$ Xygao Ho$ g‘mZm§Va aoImE§ (parallel
perpendicular to each other lines)
(D) one common line and two other lines at (C) EH$ C^`{Zð> aoIm VWm Xmo AÝ` EH$ Xygao go
an angle 60° to each other b§~dV aoImE§ (perpendicular lines)
(D) EH$ C^`{Zð> aoIm VWm Xmo AÝ` aoImE§ EH$
Xygao go 60° Ho$ H$moU na

3-AA ] [8] [ Contd...

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027. A circle C passing through the origin 027. ‘yb q~Xw go hmoH$a JwOaZo dmbm EH$ d¥Îm (circle)C, UU
2 2 UU
intersects circles x + y - 6x + 8 = 0 and d¥Îmm| x2 + y2 - 6x + 8 = 0 Am¡a UU
2 2
x + y - 2x - 2y = 7 orthogonally. Then 2 2
x + y - 2x - 2y = 7 H$mo bå~dV UU
the area of C is
UU
(orthogonally) H$Q>Vm h¡& V~ C H$m joÌ’$b h¡ UU
475 617 475 617
(A) (B) (A) 36 r (B) 36 r UU
36 r 36 r
UU
905 955 905 955 UU
(C) (D) (C) 36 r (D) 36 r
36 r 36 r UU

028. A circle passing through points of intersection 028. EH$ d¥Îm C, d¥Îmm| x2 + y2 = 2x Am¡a
2 2 2 2 2 2
of circles x + y = 2x and x + y = 2y and x + y = 2y Ho$ à{VÀN>oX q~Xw go hmoH$a JwOaVm
its centre lies on the line x - y = 2 . The h¡ VWm CgH$m H|$Ð aoIm x - y = 2 h¡& V~ C H$s
radius of C is {ÌÁ`m (radius) h¡
5 7 5 7
(A) (B) (A) 2 (B) 2
2 2
11 13 11 13
(C) (D) (C) 2 (D) 2
2 2

029.
2
Normals to the parabola y = 64x at points 029. nadb¶ y2 = 64x Ho$ q~Xþ P = (1, – 8) Am¡a Q =
P = (1, – 8) and Q = (4, 16) intersect at R . (4, 16) na A{^bå~, R na à{VÀN>oX H$aVo h¢& R Ho$

The coordinates of R are {ZX}em§H$ h¢&
(A) a 35, 2 k
1
(A) a 35, 2 k
1 (B) (25, 1)
(B) (25, 1)

(C) (15, 3) (D) (5, 4) (C) (15, 3) (D) (5, 4)

030. If the line y = x + c touches the ellipse 030. ¶{X aoIm y = x + c XrK©d¥Îm 2x2 + 3y2 = 1 H$mo
2 2
2x + 3y = 1 , then the value of c is ñne© H$aVr h¡, V~ c H$m ‘mZ h¡&
5 4 5 4
(A) ! 6 (B) ! 5 (A) ! (B) !
6 5
3 2 3 2
(C) ! 4 (D) ! 3 (C) ! (D) !
4 3

3-AA ] [9] [ P.T.O.

UU
UU
UU
UU 031. The perpendicular bisector of the chord of 2
y
2
UU 031. A{Vnadb¶ x
x
2
y
2
16 - 25 = 1
UU the hyperbola 16 25 = 1
-
UU H$s Ordm {OgH$m ‘ܶq~Xþ (5, 3) h¡, H$m b§~dV
whose midpoint (5, 3), is given by
UU {Û^mOH$ (perpendicular bisector) h¡&
UU (A) 48x + 125y = 360
(A) 48x + 125y = 360
UU (B) 48x – 125y = 230
UU (B) 48x – 125y = 230
(C) 48x + 125y = 615
UU (C) 48x + 125y = 615
UU (D) – 48x + 125y = 440
(D) – 48x + 125y = 440

032. If a = 3it + mjt - kt and b = 2it + tj + nkt 032. `{X a = 3it + mjt - kt Am¡a b = 2it + tj + nkt
are orthogonal with a = b , then 6 (m + n) bå~dV (orthogonal) h¢ VWm a = b V~
is equal to 6 (m + n) ~am~a h¡
(A) 3 (B) 5 (A) 3 (B) 5
(C) 6 (D) 12 (C) 6 (D) 12

033. Let a = 4it - 8tj + kt, b = 2it + tj - 2kt , and 033. ‘mZm {H$ a = 4it - 8tj + kt, b = 2it + tj - 2kt
c = 3it - 4tj + 12kt . Then _ a # b i # c Am¡a c = 3it - 4tj + 12kt . V~ _ a # b i # c
is equal to ~am~a h¡
(A) 250 (B) 300 (A) 250 (B) 300
(C) 400 (D) 500 (C) 400 (D) 500

034. Let c be the unit vector perpendicular to 034. ‘mZm {H$ c EH$ EH$H$ g{Xe (unit vector) h¡
a = 3it + tj + 2kt and b = 2it - 2tj + 4kt . Omo a = 3it + tj + 2kt Am¡a b = 2it - 2tj + 4kt na
it + tj - kt
it + tj - kt bå~dV h¡& V~ c Am¡a Ho$ ~rM H$m
The angle between c and is 3
3 H$moU h¡
(A) sin–1 a 3 k cos–1 a 3 k
1 1
(A) sin–1 a 3 k cos–1 a 3 k
(B) 1 1
(B)
(C) cos–1 a 3 k cos–1 a 4 k
2 3
(C) cos–1 a 3 k cos–1 a 4 k
(D) 2 3
(D)

3-AA ] [ 10 ] [ Contd...

UU
UU
UU
035. If the area of the parallelogram determined UU
035. `{X g{Xe (vectors) a = x (it + 2tj + 3kt) Am¡a UU
by the vectors a = x (it + 2tj + 3kt) and b = x (- 3it - 2tj + kt) Ûmam {ZYm©[aV g‘m§Va UU
b = x (- 3it - 2tj + kt) is 12 5 units, then MVw^w©O (parallelogram) H$m joÌ’$b (area) 12 UU
x is equal to
UU
5 BH$mB© h¡ V~ x H$m ‘mZ h¡ UU
(A) 1 (B) 2 (A) 1 (B) 2 UU
(C) 3 (D) 4 UU
(C) 3 (D) 4
UU
UU
036. If the sum of coefficients in the expansion 036. `{X (1 + x)n Ho$ àgma (expansion) Ho$ nXm| Ho$
of (1 + x)n is 2048 then the difference in the JwUm§H$m| (coefficients) H$m `moJ 2048 h¢ V~ 7 d|
coefficients of 7th and 3rd terms is Am¡a 3 d| nXm| Ho$ JwUm§H$m| H$m A§Va (difference) h¡
(A) 407 (B) 398 (A) 407 (B) 398
(C) 315 (D) 276 (C) 315 (D) 276

037. If the coefficient of x3 in the expansion of 037. `{X
4 4
d 1 + x + x + ... + x n
2 50
d 1 + x + x + ... + x n
2 50

1! 2! 50! 1! 2! 50!

is T 1 and the coefficient of x4 in the Ho$ àgma ‘| x3 H$m JwUm§H$ T 1 Am¡a
3 3
expansion of d 1 + 1! + 2! + ... + 100! n
2 100
d 1 + x + x + ... + x n
2 100
x x x
1! 2! 100!
is T 2, then T1 /T2 is
Ho$ àgma ‘| x4 H$m JwUm§H$ T 2 h¡, V~ T1 /T2 h¡
(A) a 4 k a4k
4 3
3
(A) a 4 k a4k
(B) 3 3 4 3
(B) 3
(C) a 3 k a3k
4 4 3

(C) a 3 k a3k
(D) 4 4 4 3
(D) 4

038. Four cards are drawn at random without 038. 52 nÎmm| H$s AÀN>r Vah ’|$Q>r J`r JÈ>r ‘| go Mma nÎmo
replacement from a well shuffled deck of 52 {~Zm à{VñWm{nV {H$E {ZH$mbo JE& 2 nÎmo bmb hmoZo
cards. The probability that 2 cards are red is H$s àm{`H$Vm (probability) h¡

325 225 325 225
(A) 833 (B) (A) 833 (B) 733
733
125 25 125 25
(C) 433 (D) (C) 433 (D) 133
133

3-AA ] [ 11 ] [ P.T.O.

UU
UU
UU
UU 039. A biased coin has probability of coming 039. EH$ A{^ZV (biased) {g¸o$ Ho$ {MÎm (head)
UU 2
UU up heads as 3 . It is tossed three times. At AmZo H$s àm{`H$Vm (probability) 32 h¡& BgH$mo
UU the same time an unbiased dice is tossed VrZ ~ma CN>mbm OmVm h¡& Cgr g‘` EH$ AZ{^ZV
UU independently. Then the probability that the
UU (unbiased) nmgm ñdV§Ì ê$n go ’|$H$m OmVm h¡& nmgo
UU number on the dice is less than the number of na g§»`m {MÎm (head) AmZo H$s g§»`m go H$‘ hmoZo
UU heads is H$s àm{`H$Vm (probability) h¡
UU
23 19 23 19
UU (A) 81 (B) 81 (A) 81 (B) 81
14 11 14 11
(C) 81 (D) 81 (C) 81 (D) 81

040. Two tanks T 1 and T 2 bomb a target in 040. Xmo Q>¢H$ T 1 Am¡a T 2 EH$ bú` na EH$ Ho$ ~mX
succession. The probabilities of hitting the EH$ ~‘ ’|$H$Vo h¢& T 1 Am¡a T 2 Ho$ {bE bú` H$mo
target are 0.3 and 0.4 respectively for T 1 ‘maZo H$s àm{`H$VmE H«$‘e… 0.3 Am¡a 0.4 h¢ & Q>¢H$
and T 2. The tank T 2 will attempt only if T 1 T 2 Ho$db V^r à`mg H$aoJm O~ T 1 bú` go MyH$
misses the target. Then the probability that OmEJm& V~ bú` Ho$ T 2 Ûmam ‘mao OmZo H$s àm{`H$Vm
the target is hit by T 2 is (probability) h¡
(A) 0.12 (B) 0.28 (A) 0.12 (B) 0.28
(C) 0.18 (D) 0.42 (C) 0.18 (D) 0.42

041. Probability that a doctor diagnoses a disease 041. EH$ S>m°ŠQ>a Ûmam EH$ ~r‘mar H$m ghr {ZXmZ
correctly is 0.6. The probability that the (diagnoses) H$aZo H$s àm{`H$Vm (probability)
patient dies by his/her treatment after correct 0.6 h¡& CgHo$ BbmO go ghr {ZXmZ Ho$ ~mX amoJr
diagnosis is 0.3 and the probability of death Ho$ ‘aZo H$s àm{`H$Vm 0.3 h¡ Am¡a JbV {ZXmZ go
by wrong diagnosis is 0.7. A patient of the ‘¥Ë`w H$s àm{`H$Vm 0.7 h¡& S>m°ŠQ>a Ho$ EH$ ‘arO H$s
doctor who had the disease dies. Then the ~r‘mar go ‘¥Ë`w hmo OmVr h¡& V~ S>m°ŠQ>a Zo ghr {ZXmZ
probably that the doctor diagnosed correctly {H$`m Wm BgH$s àm{`H$Vm h¡
is 9 3
(A) 23 (B) 10
9 3
(A) 23 (B) 10 6 8
(C) 13 (D) 15
6 8
(C) 13 (D) 15

3-AA ] [ 12 ] [ Contd...

UU
UU
UU
cos 13A - cos 9A + cos A - cos 5A cos 13A - cos 9A + cos A - cos 5A
UU
042. The value sin A - sin 5A + sin 9A - sin 13A 042. sin A - sin 5A + sin 9A - sin 13A H$m ‘mZ h¡ UU
is UU
(A) tan2A (B) tan4A UU
(A) tan2A (B) tan4A UU
(C) cot2A (D) cot4A
(C) cot2A (D) cot4A UU
UU
UU
043. The sum of all solutions of the equations 043. g‘rH$aU tan2θ = cotθ Ho$ A§Vamb 9 - 2 , 2 C ‘| UU
r r
UU
tan2θ = cotθ in the interval 9 - 2 , 2 C is g^r ‘ybm| H$m `moJ h¡
r r
2r r
2r r (A) 3 (B) 2
(A) 3 (B) 2 r
r (C) 6 (D) 0
(C) 6 (D) 0

044. If the sides a, b, c of a triangle ABC are in 044. `{X EH$ {Ì^wO ABC H$s ^wOmE§ a, b, c g‘m§Va loUr
arithmetic progression then ‘| h¢ V~
A B C A B C
(A) cot 2 , cot 2 , cot 2 are in arithmetic (A) cot 2 , cot 2 , cot 2 g‘m§Va loUr
progression ( arithmetic progression) ‘| h¢

A B C A B C
(B) cot 2 , cot 2 , cot 2 are in geometric (B) cot 2 , cot 2 , cot 2 JwUmoÎma loUr

progression (geometric progression) ‘| h¢
A B C A B C
(C) cot 2 , cot 2 , cot 2 are in harmonic (C) cot 2 , cot 2 , cot 2 hamˑH$ loUr
progression
(harmonic progression) ‘| h¢
A C B
(D) cot 2 – cot 2 = 2cot 2 A C B
(D) cot 2 – cot 2 = 2cot 2

045. The smallest angle of the triangle with sides 045. {Ì^wO {OgH$s ^wOmE§ 3,5,7 h¢ H$m g~go N>moQ>m H$moU
3, 5, 7 is h¡

(A) cos–1 a 14 k sin–1 a 7 k (A) cos–1 a 14 k sin–1 a 7 k
11 6 11 6
(B) (B)

(C) cos–1 a 14 k sin–1 a 14 k (C) cos–1 a 14 k sin–1 a 14 k
13 13 13 13
(D) (D)

3-AA ] [ 13 ] [ P.T.O.

UU
UU
UU
UU 046. The angles of depression to the top and base 046. EH$ 30 ‘rQ>a D$±Mr {H$gr nhm‹S>r H$s MmoQ>r go {H$gr
UU
of a tower from the top of a hill of height 30 ‘rZma Ho$ {gao Ed§ nX Ho$ AdZ‘Z H$moU H«$‘e…
UU
UU meter are 30° and 60° respectively. Then the 30Amo Am¡a 60Amo h¢& Vmo ‘rZma H$s D$±MmB© h¡
UU height of the tower (in meters) is (A) 10 (B) 20
UU (A) 10 (B) 20 (C) 30 (D) 40
UU
(C) 30 (D) 40
UU
UU
UU 047. A ball is thrown vertically upwards from the 047. 24.5 ‘rQ>a D$§Mr ‘rZma H$s MmoQ>r go EH$ J|X H$mo
top of a tower of height 24.5 meters with the 19.6 m/s2 Ho$ doJ go D$na H$s Amoa (vertically)
initial velocity 19.6 m/s2. The time it will ’|$H$m J`m & Cgo n¥Ïdr VH$ nhþ±MZo ‘| bJZo dmbm
take to reach the earth is g‘` h¡ (‘mZm {H$ g = 9.8 m/s2)
(assume g = 9.8 m/s2) (A) 4 seconds (B) 5 seconds
(A) 4 seconds (B) 5 seconds (C) 10 seconds (D) 12 seconds
(C) 10 seconds (D) 12 seconds

048. A particle moving at constant acceleration 048. EH$ H$U (particle) Mma goH§$S> VH$ EH$ g‘mZ
travels 272 meters in 4 seconds. Then ËdaU (acceleration) go MbVm h¡ Amoa 272 ‘rQ>a
acceleration becomes zero and it travels 528 OmVm h¡& V~ ËdaU Zï> hmo OmVm h¡ Amoa AJbo 4
meters in next 4 seconds. The initial velocity
goH§$S> ‘| 528 ‘rQ>a OmVm h¡& H$U H$m Ama§{^H$ doJ
of the particle is
(initial velocity) h¡
(A) 2 m/s (B) 4 m/s
(A) 2 m/s (B) 4 m/s
(C) 6 m/s (D) 8 m/s
(C) 6 m/s (D) 8 m/s

049. Three forces P , Q , R , are acting at a point 049. VrZ ~b P , Q , R EH$ g‘Vb ‘| EH$ q~Xw na bJ
in plane. If the angle between P and Q is aho h¢& `{X P Am¡a Q Ho$ ~rM H$m H$moU 120° h¡
120° whereas the angle between Q and R is O~{H$ P Am¡a Q Ho$ ~rM H$m H$moU 150° Amo h¡ V~
150° then for the equilibrium, magnitude P, g§VwbZ (equilibrium) Ho$ {bE, ~bmo Ho$ n[a‘mU
Q, R of the forces are in the ratio P, Q, R {H$g AZwnmV ‘| h¢
(A) 1 : 2 : 3 (B) 1:2:3 (A) 1 : 2 : 3 (B) 1:2:3
(C) 1 : 2 :3 (D) 1: 3:2 (C) 1 : 2 :3 (D) 1: 3:2

050. The magnitude of the resultant of the two forces 050. Xmo ~b (two forces) à˶oH$ 2N Ho$ ~am~a h¢ VWm
each equal to 2N inclined at angle 120° is EH$ Xÿgao Ho$ gmW 120° na PwHo$ h¢ Ho$ n[aUm‘r ~b
H$ma n[a‘mU (magnitude) h¡
(A) 1 N (B) 2N
(A) 1 N (B) 2N
(C) 3 N (D) 4N
(C) 3 N (D) 4N

3-AA ] [ 14 ] [ Contd...

UU
UU
UU
051. Count the no of surfaces of the figure given 051. {M{ÌV dñVw H$s gVhmo H$s {JZVr ~VmE& UU
UU
below: UU
UU
UU
UU
UU
UU
UU
UU

(A) 10 (B) 13 (A) 10 (B) 13
(C) 15 (D) 14 (C) 15 (D) 14

052. Out of the five given pieces in (X), which 052. {MÌ ‘X’ ‘| {XE J¶o Qw>H$‹S>mo go {X¶o {MÌm| ‘| go ³¶m
form can be formed from (1) (2) (3) (4)? ~Zm¶m Om gH$Vm h¡&

(X) (1) (2) (3) (4) (X) (1) (2) (3) (4)
(A) 1 (B) 2 (A) 1 (B) 2
(C) 3 (D) 4 (C) 3 (D) 4

053. Select the best figure alternative which would 053. ‘D’ Ho$ ñWmZ na H$m¡Z gm {MÌ R>rH$ ahoJm&
rightly replace (?) sign in ‘D’.

?.
?.
A B C D
A B C D

1 2 3 4
1 2 3 4 (A) 1 (B) 2
(A) 1 (B) 2 (C) 3 (D) 4
(C) 3 (D) 4

3-AA ] [ 15 ] [ P.T.O.

UU
UU
UU
UU 054. Identify the famous fort from the picture. 054. {MÌ ‘o {XE {H$bo H$mo nhMm{Z¶o&
UU
UU
UU
UU
UU
UU
UU
UU
(A) Jodhpur Fort (B) Gwalior fort (A) OmoYnwa {H$bm (B) ½dm{b¶a {H$bm
UU
(C) Lal Qila (D) Amer fort (C) bmb {H$bm (D) Am‘oa {H$bm

055. Identify the world-famous monument in the 055. {MÌ ‘o {XE {díd à{gÕ ñ‘maH$ H$mo nhMm{Z¶o
picture below:

(A) H$mobmo{g¶‘
(A) Colosseum (B) {‘bmd H¡$WoS>oab
(B) Milan Cathedral (C) Ho$gb hmdS>©
(C) Castle Howard (D) ZmoQ>a S>mo‘
(D) Notre Dame

3-AA ] [ 16 ] [ Contd...

UU
UU
UU
056. Identify the famous Architect in the picture 056. {MÌ ‘| {XE ‘ehÿa dmñVw{dX H$m Zm‘ ~VmB¶o& UU
UU
below. UU
UU
UU
UU
UU
UU
UU
UU

(A) Mmb©g H$mo[a¶m
(A) Charles Correa (B) AZÝV amOo
(B) Anant Raje (C) ~r dr Xmoer
(C) B. V. Joshi (D) hg‘wI nQ>ob
(D) Hasmukh C. Patel

057. Find the alternative image containing the 057. {MÌ ‘X’ ‘o {X JB© AmH¥${V H$m {H$g A{V[a³V
figure (X) as its part AmH¥${V ‘| à¶moJ {H$¶m J¶m h¡&

(A) 1 (B) 2 (A) 1 (B) 2
(C) 3 (D) 4 (C) 3 (D) 4

058. Name the defense wall of a castle normally 058. {H$gr {H$bo Ho$ ~Mmd Ho$ {bE ~Zr nËWa H$s Xrdmb
built in stone H$m Zm‘ nhMm{Z¶o&
(A) Trombe Wall (B) Moat (A) Q´>moå~ Xrdmb (B) ‘moQ>
(C) Rampart (D) Bastion (C) a¡‘nQ>© (D) d¡ñQ>Z

3-AA ] [ 17 ] [ P.T.O.

UU
UU
UU
UU 059. Select the appropriate option which may 059. dh AmH¥${V nhMm{Z¶o Omo Imbr ñWmZ na R>rH$
UU
UU complete the figure matrix? ~¡R>|Jr&
UU
UU
UU
UU
UU ? ?
UU
UU

(1) (2) (3) (4) (1) (2) (3) (4)

(A) 1 (B) 2 (A) 1 (B) 2
(C) 3 (D) 4 (C) 3 (D) 4

060. Identify the architectural symbol below: 060. ZrMo {X¶m {MÌ {H$g H$s dmñVw{dXr¶ {MÝh h¡&

(A) Door (B) Window (A) XadmOm (B) {I‹S>H$s
(C) Wardrobe (D) Wall
(C) Ab‘mar (D) Xrdmb

061. Sun Temple Modhera belongs to which 061. ‘moT>oam H$m gy¶© ‘§{Xa {H$g amOd§e ‘o ~Zm Wm&
dynasty? (A) Mmobm amOd§e
(A) Chola Dynasty (B) nëbd amOd§e
(B) Pallava Dynasty
(C) MmbwH$m amOd§e
(C) Chaulukya Dynasty
(D) nm§S>d amOd§e
(D) Pandava Dynasty

062. J«oZmBQ> {H$g àH$ma H$m nËWa h¡?
062. Granite is:
(A) H¡$bgo[a¶g
(A) Calcareous rock
(B) Metamorphic rock (B) ‘oQ>m‘moa{’$H$
(C) Sedimentary rock (C) goS>r‘oÝQ´>r
(D) Igneous rock (D) BJ{Z¶g

3-AA ] [ 18 ] [ Contd...

UU
UU
UU
063. Identify the 2D drawing of the illustrated 3D 063. {MÌ ‘| {XImB© 3D AmH¥${V H$s ghr 2D AmH¥${V UU
UU
problem figure: nhMm{Z¶o UU
Problem Problem UU
Figure Answer Figures Figure Answer Figures UU
UU
UU
UU
(A) (B) (C) (D) (A) (B) (C) (D) UU
UU

064. Identify the bridge in the picture below. 064. {MÌ ‘| {X¶m J¶m nwb nhMm{Z¶o

(A) Hawai Jhula (A) hdmB© Pwbm
(B) Great bridge of India (B) ^maV H$m ‘hmZ nwb
(C) London bridge (C) b§XZ nwb
(D) Bandra – Worli Sea Link (D) ~mÝXm dabr nwb

065. An error 2% in excess is made while measuring 065. EH$ g‘ MVw©^wO Ho$ ‘mnZo ‘o 2% H$s JbVr go CgHo$
the side of a square. The percentage of error joÌ’$b ‘o {H$VZr JbVr hmoJr&
in the calculated area of the square is: (A) 4.04% (B) 2%
(A) 4.04% (B) 2% (C) 2.02% (D) 4%
(C) 2.02% (D) 4%

3-AA ] [ 19 ] [ P.T.O.

UU
UU
UU
UU 066. Identify the figure which is odd from rest of 066. {ZåZ {MÌ ‘o g~go AbJ AmH¥${V H$mo nhMm{Z¶o&
UU
UU the figures
UU
UU
UU
UU
(A) 1 (B) 2
UU
UU (A) 1 (B) 2 (C) 3 (D) 4
UU (C) 3 (D) 4
067. EH$ B§M {H$gHo$ ~am~a h¡?
067. An Inch equals. (A) 2.54 cm (B) 5 cm
(A) 2.54 cm (B) 5 cm (C) 20 mm (D) 15.67 mm
(C) 20 mm (D) 15.67 mm

068. Name the Architect to receive Padma Award 068. 2019 ‘o {H$g dmñVw{dX Zo nÙ‘ nwañH$ma àmßV {H$¶m&
2019 ? (A) ~r. ìhr. Xmoer
(A) B.V.Doshi (B) {~‘b nQ>ob
(B) Bimal Patel (C) Zmar Jm§Yr
(C) Nari Gandhi (D) {H«$Q>mo’$a Mmëg© ~oqZJa
(D) Christopher Charles Benninger

069. How many A2 sheets can be cut from a A0 069. EH$ A0 ‘mn Ho$ H$mJO go {H$VZo A2 ‘mn Ho$ H$mJO
sheet of paper. H$mQ>o Om gH$Vo h¡&
(A) 5 (B) 4 (A) 5 (B) 4
(C) 16 (D) 8 (C) 16 (D) 8

3-AA ] [ 20 ] [ Contd...

UU
UU
UU
070. Identify the building 070. {MÌ ‘| {X¶o ^dZ H$mo nhMm{Z¶o& UU
UU
UU
UU
UU
UU
UU
UU
UU
UU

(A) Sydney Opera House (A) {gS>Zr Amonoamo ^dZ
(B) Bahai house of worship (B) ~hmB© nyOm ^dZ
(C) Guggenheim Museum (C) JÚo{Z¶‘ g§J«hmb¶
(D) Temple of Karnak (D) H$maZmH$ H$m Ԥ{Xa

071. Gol Gumbaz is a 071. Jmob Jwå~O EH$
(A) Mosque (B) Mausoleum (A) ‘pñOX² h¡ (B) ‘H$~am h¡
(C) Museum (D) Monastery (C) AOm¶~ Ka h¡ (D) ‘moZoñQ´>r h¡

072. Identify the Temple 072. ‘§{Xa H$mo nhMm{Z¶o

(A) Brihadeshwara Temple (A) {~¥hXoída ‘§{Xa
(B) Nageshwar Temple (B) ZmJoída ‘§{Xa
(C) Bodhi Temple (C) ~moYr Ԥ{Xa
(D) Kandariya Mahadev Temple (D) H§$Xm[a¶m ‘hmXod ‘§{Xa

3-AA ] [ 21 ] [ P.T.O.

UU
UU
UU
UU 073. These tiles are better used for 073. Xem©B JB© Q>mBbmo Ho$ C{MV à¶moJ H$m ñWmZ
UU
UU
UU
UU
UU
UU
UU
UU
UU

(A) Bathroom (B) Lounge (A) ~mWé‘ (B) bmC§O
(C) Pavement (D) Road (C) nod‘|Q> (D) g‹S>H$

074. Kota stone is 074. H$moQ>m ñQ>moZ H$m a§J H¡$gm hmoVm h¡&
(A) Black (B) White (A) H$mbm (B) g’o$X
(C) Spotted (D) Green (C) XmZoXma (D) ham

075. Identify the temple 075. ‘§{Xa nhMm{Z¶o

(A) Kedarnath Temple (A) Ho$XmaZmW Ԥ{Xa
(B) Kailash Temple (B) H¡$bme ‘§{Xa
(C) Lingraja Temple (C) qbJamO Ԥ{Xa
(D) Shore Temple (D) emoa Ԥ{Xa

3-AA ] [ 22 ] [ Contd...

UU
UU
UU
076. If the paper is folded along the dotted lines 076. ¶{X EH$ H$mJO H$mo S>mQ>oB bmBZ na ‘mo‹S>m Om¶o Am¡a UU
UU
and punched as shown in the picture, identify {XImE {MÌ Ho$ AZwgma {~{ÐV {H$¶m OmE Vmo dh UU
the picture that would appear after unfolding it. IwbZo na H¡$gm bJoJm& UU
UU
UU
UU
UU
UU
UU

a b c d a b c d
(A) a (B) b (A) a (B) b
(C) c (D) d (C) c (D) d

077. What material is used for Meenakshi Temple? 077. ‘rZmjr ‘§{Xa H$mo ~ZmZo ‘o {H$g nËWa H$m à¶moJ
(A) Laterite (B) Sand Stone {H$¶m J¶m h¡?
(C) Granite (D) Brick Masonry (A) boQ>oamBQ> (B) g¢S> ñQ>moZ
(C) J«oZmBQ> (D) B§Q> H$s MwZmB©

078. Identify the building shown 078. ZrMo {X¶o ^dZ H$mo nhMm{Z¶o

(A) Basilica of Bom Jesus, Goa (A) d¡{g{bH$m ~m¡‘ Zrg‘, JmoAm
(B) St. Cathedral, Goa (B) g|Q> H¡$WS>ab JmoAm
(C) St Aloysius Chapel, Managlore (C) g|Q> Ebmo{g¶g M¡nob ‘¢Jbmoa
(D) Jewish museum, Cochin (D) Á¶y g§J«hmb¶ H$moMrZ

3-AA ] [ 23 ] [ P.T.O.

UU
UU
UU
UU 079. Identify the award given to the Architect 079. ZrMo {XE JE dmñVwH$ma H$mo ³¶m nwañH$ma {‘bm
UU
UU below
UU
UU
UU
UU
UU
UU
UU

(A) Zmo~ob nwañH$ma
(A) Nobel Prize Winner (B) Am°ñH$a nwañH$ma
(B) Oscar Award Winner (C) {àQ>O²H$a nwañH$ma
(C) Pritzker Prize Winner (D) ñQ>aqbJ nwañH$ma
(D) Stirling Prize Winner

080. Identify the number of oblique surfaces 080. {MÌ H$s Q>oT>r gVhmo H$s g§»¶m nhMm{Z¶o&

(A) 4 (B) 3 (A) 4 (B) 3
(C) 6 (D) 7 (C) 6 (D) 7

081. Gandhi Labor Institute Ahmadabad was 081. Jm§Yr bo~a B§ñQ>r{Q>¶yQ> Ho$ dmñVwH$ma H$m Zm‘ h¡
designed by (A) gVre JwOamb
(A) Satish Gujral (B) Mmëg© H$mo[a¶m
(B) Charles Correa (C) Zo{‘Z ’$mñQ>a
(C) Norman Foster (D) ~r. dr. Xmoer
(D) B. V. Doshi

3-AA ] [ 24 ] [ Contd...

UU
UU
UU
082. Which of the following is a wide four centered 082. {ZåZ ‘| go {H$g AmM© Ho$ Mma Ho$ÝÐ VWm EH$ {eIa UU
UU
arch with a pointed apex? hmoVm h¡& UU
(A) Tudor Arch (A) Q>çyS>a AmM© UU
(B) Lancet Arch
UU
(B) boZgoQ> AmM© UU
(C) Horseshoe Arch (C) hm°g© ey AmM© UU
(D) Ogee Arch (D) AmoOr AmM© UU
UU
UU
083. From the answer figures, identify the one 083. CÎma Ho$ {MÌ ‘| {X¶o JE hþE {MÌm| go H$m¡Zgm {MÌ
which cannot be placed in the problem figure. gdmb Ho$ {MÌ ‘o Zhr bJm¶m Om gH$Vm h¡&

a b c d a b c d
(A) a (B) b (A) a (B) b
(C) c (D) d (C) c (D) d

084. Select Elevation from Arrow Side 084. {ZåZ {MÌ Vra H$s Amoa go H¡$gm {XIoJm

a b c d a b c d
(A) a (B) b (A) a (B) b
(C) C (D) d (C) C (D) d

3-AA ] [ 25 ] [ P.T.O.

UU
UU
UU
UU 085. Identify the figure next in sequence: 085. {ZåZ {MÌ Ho$ H«$‘ ‘o H$m¡Z-gm {MÌ AmEJm
UU
UU
UU
UU ? ?
UU
UU
UU
UU
UU
a b c d a b c d
(A) a (B) b (A) a (B) b
(C) c (D) d (C) c (D) d

086. Minimum width of main door is 086. ‘w»¶ XadmOo H$s ݶyZV‘ Mm¡‹S>mB© ³¶m hmoVr h¡&
(A) 3 ft (B) 3 ft 6 inches (A) 3 ft (B) 3 ft 6 inches
(C) 2 ft 6 inches (D) 4 ft (C) 2 ft 6 inches (D) 4 ft

087. How the Figure shall appear from the arrow 087. {ZåZ {MÌ Vra H$s Amoa go H¡$gm {XIoJm&
side

a b
a b

c d
c d

(A) a (B) b
(A) a (B) b
(C) c (D) d
(C) c (D) d

3-AA ] [ 26 ] [ Contd...

UU
UU
UU
088. Mera was born on March 6, 1993. The same 088. ‘ram H$m OÝ‘ 6 ‘mM© 1993 H$mo hþAm& Cghr df© UU
UU
year Independence Day was celebrated on ñdV§ÝÌVm {Xdg BVdma H$mo ‘Zm¶m J¶m& ‘ram Ho$ OÝ‘ UU
Sunday. On which day Mera was born? H$m {XZ ~VmB¶o UU
(A) Friday (B) Saturday
UU
(A) ewH«$dma (B) e{Zdma UU
(C) Monday (D) Tuesday (C) gmo‘dma (D) ‘§Jbdma UU
UU
UU
089. Identify the building given below 089. {ZåZ ^dZ H$mo nhMm{Z¶o& UU

(A) Akbar’s Tomb (A) AH$~a H$m ‘H$~am
(B) Bibi ka Maqbara (B) ~r~r H$m ‘H$~am
(C) Taj Mahal (C) VmO‘hb
(D) Jehangir’s Tomb (D) Ohm§Jra H$m ‘H$~am

090. Count the number of vertices 090. {MÌ Ho$ H$moZo nhMm{Z¶o

(A) 3 (B) 5 (A) 3 (B) 5
(C) 7 (D) 6 (C) 7 (D) 6

3-AA ] [ 27 ] [ P.T.O.

UU
UU
UU
UU 091. Identify the Logo 091. {MÌ Ho$ àVrH$ {MÝh H$mo nhMm{Z¶o&
UU
UU
UU
UU
UU
UU
UU
UU
UU
(A) Danone; (B) Starbucks; (A) XmoZmoZ (B) ñQ>ma ~H$
(C) Lego (D) Mitsubishi (C) brJmo (D) {‘Vgy{~gr

092. Insert the correct missing number from the 092. Imbr Ho$ {b¶o ghr Zå~a H$m Mm¶Z H$a|&
choices given below.

7 7
? 15 ? 15

127 31 127 31
63 63

(A) 190 (B) 221 (A) 190 (B) 221
(C) 236 (D) 255 (C) 236 (D) 255

3-AA ] [ 28 ] [ Contd...

UU
UU
UU
093. Which option shows the Correct view in the 093. Vra H$s Cnmoa go H$m¡Z gm {MÌ ghr h¡ UU
UU
direction of arrow UU
UU
UU
UU
UU
UU
UU
a b UU
a b

c d
c d

(A) a (B) b
(A) a (B) b
(C) c (D) d
(C) c (D) d

094. R.C.C stands for
094. Ama.gr.gr. {H$gHo$ {b¶o à¶moJ hmoVm h¡&
(A) reinforced cement concrete (A) arBZ’$moB©S> gr‘oÝQ> H§$H«$sQ>

(B) refined cement concrete (B) [a’$mB§S> gr‘oÝQ> H§$H«$sQ>
(C) rejoining cement concrete (C) [aÁdmB§S> gr‘oÝQ> H§$H«$sQ
(D) none of these (D) H$moB© Zhr

095. Find the material for which the symbol belongs 095. {MÝh ³¶m Xem©Vm h¡

(A) Stone (B) Wood (A) nËWa (B) bH$‹S>r
(C) Brick (D) Plastic (C) BªQ> (D) ßbmpñQ>H$

096. In a row, 25 trees are planted at equal distance
096. EH$ bmBZ ‘| 25 d¥j ~am~a Xÿar na bJmE J¶o h¡&
from each other. The distance between 1st
and 25th tree is 30 m .What is the distance nhbo VWm 25th d¥j H$s Xÿar 30 ‘rQ>a h¡& 3rd VWm
between 3rd and 15th tree? 15th d¥j H$s Xÿar ~VmE&
(A) 8m (B) 15m (A) 8m (B) 15m

(C) 16m (D) 18m (C) 16m (D) 18m

3-AA ] [ 29 ] [ P.T.O.

UU
UU
UU
UU 097. A solid cube is made using 64 small cubes. In 097. EH$ ³¶y~ 64 N>moQ>o ³¶y~ {‘bmH$a ~Zm h¡& {H$VZo N>moQ>o
UU
UU how many small cubes two sides are seen? ³¶y~ Ho$ Xmo nhby {XImB© X|Jo&
UU (A) 24; (B) 32; (A) 24 (B) 32
UU (C) 40; (D) 42
UU (C) 40 (D) 42
UU
UU 098. Identify the isometric view of the given 098. {XImE nhbwAmo go H$m¡Zgr AmH¥${V ~ZoJr&
UU
figure?
UU

Top
Top

Front Side
Front Side

(A) (B) (C) (D)
(A) (B) (C) (D)

099. What is the name of tall building? 099. {MÌ ‘| Xem©E D±$Mo ^dZ H$m Zm‘ ³¶m h¡?

(A) The Gherkin (A) X Koa{H$Z
(B) Taipei 101 (B) VmB©noB© 101
(C) Chrysler Building (C) {H«$gba ^dZ
(D) Space Needle (D) ñnog ZrS>b

3-AA ] [ 30 ] [ Contd...

UU
UU
UU
100. Which of the following figure is the correct 100. H$m¡Z gm {MÌ {XImE {MÌ H$m ghr à{V{~å~ h¡? UU
UU
mirror image of the given figure? UU
UU
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UU
UU
UU
UU
(A) (A)

(B) (B)

(C) (C)

(D) (D)

3-AA ] [ 31 ] [ P.T.O.

UU UU
UU UU
UU SPACE FOR ROUGH WORK / H$ÀMo H$m‘ Ho$ {b¶o OJh UU
UU UU
UU UU
UU UU
UU UU
UU UU
UU UU
UU UU
UU UU
UU UU
UU UU

3-AA ] [ 32 ]