UPSEE 2020 Question Paper 8

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ss  PAPER-8 àíZnwpñVH$m H«$‘m§H$ àíZnwpñVH$m H$moS> ss
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AA
Question Booklet Sr. No.
AZwH«$‘m§H$ / Roll No.
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ss CÎma-erQ> H«$‘m§H$ / OMR Answer Sheet No. ss
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ss KmofUm : / Declaration : ss
‘¢Zo n¥îR> g§»¶m 1 na {X¶o J¶o {ZX}em| H$mo n‹T>H$a g‘P {b¶m h¡& narjm Ho$ÝÐmܶj H$s ‘moha
ss I have read and understood the instructions given on page No. 1 Seal of Superintendent of Examination Centre ss
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narjmWu H$m hñVmja /Signature of Candidate
ss (AmdoXZ nÌ Ho$ AwZgma /as signed in application) H$j {ZarjH$ Ho$ hñVmja /Signature of the Invigilator ss
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narjmWu H$m Zm‘/
Name of Candidate :

narjmWu H$mo {X¶o n¡amJ«m’$ H$s ZH$b ñd¶§ H$s hñV{b{n ‘| ZrMo {X¶o J¶o [a³V ñWmZ na ZH$b (H$m°nr) H$aZr h¡&
""Amn ghr ì¶dgm¶ ‘| h¢, ¶h Amn V^r OmZ|Jo O~ : Amn H$m‘ na OmZo Ho$ {bE qM{VV h¢, Amn {Z˶ AnZm H$m‘ g~go AÀN>m H$aZm MmhVo h¢, Am¡a Amn AnZo H$m¶© Ho$
‘hËd H$mo g‘PVo h¢&'' AWdm / OR
To be copied by the candidate in your own handwriting in the space given below for this purpose is compulsory.
‘‘You will know you are in the right profession when : you wake anxious to go to work, you want to do your best daily, and you know your work is
important.”

* Bg n¥îR> H$m D$nar AmYm ^mJ H$mQ>Zo Ho$ ~mX drjH$ Bgo N>mÌ H$s OMR sheet Ho$ gmW gwa{jV aIo&
* After cutting half upper part of this page, invigilator preserve it along with student’s OMR sheet.

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nwpñVH$m ‘| ‘wIn¥îR> g{hV n¥îR>m| H$s g§»¶m g‘¶ 2 K§Q>o A§H$ / Marks nwpñVH$m ‘| àíZm| H$s g§»¶m
No. of Pages in Booklet including title
24 Time 2 Hours 400 No. of Questions in Booklet
100

PAPER-8 àíZnwpñVH$m H«$‘m§H$/ Question Booklet Sr. No.

AZwH«$‘m§H$ / Roll No.
H$j {ZarjH$ Ho$ hñVmja /Signature of the Invigilator
àíZnwpñVH$m H$moS>
narjmWu H$m Zm‘/
Name of Candidate : AA
Q. Booklet Code
narjm{W©¶m| Ho$ {bE {ZX}e /INSTRUCTIONS TO CANDIDATE
Aä¶{W©¶m| hoVw Amdí¶H$ {ZX}e : Instructions for the Candidate :
1. Amo.E‘.Ama. CÎma n{ÌH$m ‘| Jmobm| VWm g^r à{dpîQ>¶m| H$mo ^aZo Ho$ {bE Ho$db 1. Use BLUE or BLACK BALL POINT PEN only for all entries and for filling
Zrbo ¶m H$mbo ~mb ßdmB§Q> noZ H$m hr Cn¶moJ H$a|& the bubbles in the OMR Answer Sheet.
2. SECURITY SEAL ImobZo Ho$ nhbo Aä¶Wu AnZm Zm‘, AZwH«$‘m§H$ (A§H$m| 2. Before opening the SECURITY SEAL of the question booklet, write your
Name, Roll Number (In figures), and OMR Answer-sheet Number in the
‘|) Ed§ Amo.E‘.Ama. CÎma-erQ> H$m H«$‘m§H$ Bg àíZ-nwpñVH$m Ho$ D$na {X¶o J¶o space provided at the top of the Question Booklet. Non-compliance
ñWmZ na {bI|& ¶{X do Bg {ZX}e H$m nmbZ Zht H$a|Jo Vmo CZH$s CÎma-erQ> H$m of these instructions would mean that the Answer Sheet can not be
‘yë¶m§H$Z Zhr hmo gHo$Jm VWm Eogo Aä¶Wu A¶mo½¶ Kmo{fV hmo Om¶|Jo& evaluated leading the disqualification of the candidate.
3. à˶oH$ àíZ Mma A§H$m| H$m h¡& {Og àíZ H$m CÎma Zht {X¶m J¶m h¡, Cg na H$moB© 3. Each question carries FOUR marks. No marks will be awarded for
A§H$ Zht {X¶m Om¶oJm& JbV CÎma na A§H$ Zht H$mQ>m OmEJm& unattempted questions. There is no negative marking on wrong answer.
4. Each multiple choice questions has only one correct answer and marks
4. g^r ~hþ{dH$ënr¶ àíZm| ‘| EH$ hr {dH$ën ghr h¡, {Ogna A§H$ Xo¶ hmoJm& shall be awarded for correct answer.
5. JUH$, bm°J Q>o{~b, ‘mo~mBb ’$moZ, Bbo³Q´>m°{ZH$ CnH$aU VWm ñbmBS> ê$b Am{X 5. Use of calculator, log table, mobile phones, any electronic gadget and
H$m à¶moJ d{O©V h¡& slide rule etc. is strictly prohibited.
6. Aä¶Wu H$mo narjm H$j N>moS>Zo H$s AZw‘{V narjm Ad{Y H$s g‘mpßV na hr Xr 6. Candidate will be allowed to leave the examination hall at the end of
Om¶oJr& examination time period only.
7. ¶{X {H$gr Aä¶Wu Ho$ nmg nwñVH|$ ¶m Aݶ {b{IV ¶m N>nr gm‘J«r, {Oggo do 7. If a candidate is found in possession of books or any other printed or
ghm¶Vm bo gH$Vo/gH$Vr h¢, nm¶r Om¶oJr, Vmo Cgo A¶mo½¶ Kmo{fV H$a {X¶m Om written material from which he/she might derive assistance, he/she is
gH$Vm h¡& Bgr àH$ma, ¶{X H$moB© Aä¶Wu {H$gr ^r àH$ma H$s ghm¶Vm {H$gr ^r liable to be treated as disqualified. Similarly, if a candidate is found
ómoV go XoVm ¶m boVm (¶m XoZo H$m ¶m boZo H$m à¶mg H$aVm) hþAm nm¶m Om¶oJm, giving or obtaining (or attempting to give or obtain) assistance from any
source, he/she is liable to be disqualified.
Vmo Cgo ^r A¶mo½¶ Kmo{fV {H$¶m Om gH$Vm h¡&
8. {H$gr ^r ^«‘ H$s Xem ‘| àíZ-nwpñVH$m Ho$ A§J«oOr A§e H$mo hr ghr d A§{V‘ 8. English version of questions paper is to be considered as authentic and
‘mZm Om¶oJm& final to resolve any ambiguity.
9. OMR sheet Bg Paper Ho$ ^rVa h¡ VWm Bgo ~mha {ZH$mbm Om gH$Vm h¡ naÝVw 9. OMR sheet is placed within this paper and can be taken out from this
Paper H$s grb Ho$db nona ewé hmoZo Ho$ g‘¶ na hr Imobm Om¶oJm& paper but seal of paper must be opened only at the start of paper.

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PAPER-8
Aptitude Test for
Lateral Entry in Engineering
(Diploma Holders)
(Q. 1 to Q. 100)

001. 
A train 150 meters long, is running at 001. 150 ‘rQ>a b§~r EH$ Q´>oZ 72 {H$‘r/K§Q>o H$s aâVma
72 km/hour. Find the time taken to pass a go Mb ahr h¡& kmV H$ao {H$ ßboQ>’$m‘© na I‹S>o EH$
man standing on a platform AmX‘r H$mo nma H$aZo ‘| ¶h {H$VZm g‘¶ boJr.
(A) 7.5 sec (B) 20 sec (A) 7.5 goH§$S> (B) 20 goH§$S>
(C) 30 sec (D) 35 sec (C) 30 goH§$S> (D) 35 goH§$S>

002. What percentage of 80 is 240% of 30: 002. 80 H$m {H$VZo à{VeV 30 H$m 240% h¡?
(A) 60 (B) 90 (A) 60 (B) 90
(C) 72 (D) 100 (C) 72 (D) 100

8-AA ] [2] [ Contd...

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003. If Umesh salary is 20% less than Rakesh’s
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003. ¶{X C‘oe H$m doVZ amHo$e Ho$ doVZ go 20% H$‘ h¡, ss
salary, by what percentage Rakesh’s salary is Vmo amHo$e H$m doVZ C‘oe Ho$ doVZ go {H$VZo à{VeV ss
more than Umesh’s salary?
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A{YH$ h¡? ss
(A) 20% (B) 22% (A) 20% (B) 22% ss
(C) 25% (D) 27%
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(C) 25% (D) 27% ss
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004. If a:b = 5:6 and b:c = 7:9 find a:c
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004. ¶{X a:b = 5:6 VWm b:c = 7:9 Vmo a:c H$m ‘mZ ss
(A) 35:54 (B) 54:35 {ZH$m{bE&
(C) 17:19 (D) 15:14 (A) 35:54 (B) 54:35
(C) 17:19 (D) 15:14

005. If LCM of two numbers is 750 and their 005. ¶{X Xmo g§»¶mAm| H$m bKwÎm‘ g‘mndV©H$ 750 h¡ Am¡a
product is 18750, find the HCF of the CZH$m JwUZ’$b 18750 h¡, Vmo g§»¶mAm| H$m ‘hÎm‘
numbers. g‘mnd˶© kmV H$s{OE&
(A) 50 (B) 30 (A) 50 (B) 30
(C) 125 (D) 25 (C) 125 (D) 25

006. In a class of 60 students, 25 students play 006. 60 {dÚm{W©¶m| H$s EH$ H$jm ‘| 25 {dÚmWu {H«$Ho$Q,>
cricket and 20 students play tennis, and 10 20 {dÚmWu Q>o{Zg Am¡a 10 {dÚmWu XmoZm| hr Ioc
students play both the games. Then, the IocVo h¢, Vmo XmoZm| ‘| go H$moB© ^r Ioc Zht IocZo
number of students who play neither is: dmco {dÚm{W©¶m| H$s g§»¶m-
(A) 0 (B) 25 (A) 0 (B) 25
(C) 35 (D) 45 (C) 35 (D) 45

007. Domain of a2 - x 2 (a > 0) is: 007. a2 - x 2 (a > 0) H$m àm§V h¡&
(A) (– a, a) (B) [– a, a] (A) (– a, a) (B) [– a, a]
(C) [0, a] (D) (– a, 0] (C) [0, a] (D) (– a, 0]

008. The minimum value of 3 cosx + 4 sinx + 8 is: 008. 3 cosx + 4 sinx + 8 H$m ݶyZV‘ ‘mZ h¡&
(A) 5 (B) 9 (A) 5 (B) 9
(C) 7 (D) 3 (C) 7 (D) 3

8-AA ] [3] [ P.T.O.

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ss 009. The value of cos 12° + cos 84° + cos 156° +
ss 009. cos 12° + cos 84° + cos 156° + cos 132° H$m
ss cos 132° is: ‘mZ h¡&
ss (A) 1/2 (B) 1
ss (A) 1/2 (B) 1
ss (C) –1/2 (D) 1/8 (C) –1/2 (D) 1/8
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ss 010. The longest side of a triangle is twice the 010. {H$gr {Ì^wO H$s g~go ~‹S>r ^wOm g~go N>moQ>r ^wOm
ss shortest side and the third side is 2cm longer
ss go XþJZr h¡ Ed§ Vrgar ^wOm g~go N>moQ>r ^wOm go
than the shortest side. If the perimeter of the 2 go‘r A{YH$ h¡& ¶{X {Ì^wO H$m n[a‘mn 166 go‘r
triangle is more than 166 cm then find the go A{YH$ h¡ Vmo g~go N>moQ>r ^wOm H$s ݶyZV‘ c§~mB©
minimum length of the shortest side. kmV H$s{OE&
(A) 41 (B) 40 (A) 41 (B) 40
(C) 51 (D) 39 (C) 51 (D) 39

011. In a class, there are 27 boys and 14 girls. 011. {H$gr H$jm ‘| 27 c‹S> Ho$ Am¡a 14 c‹S>{H$¶m± h¢& {H$gr
The teacher wants to select 1 boy and 1 H$m¶©H«$‘ Ho$ {cE, H$jm H$m à{V{Z{YËd H$aZo Ho$ {cE
girl to represent the class for a function. In {ejH$ H$mo 1 c‹S>Ho$ Am¡a 1 c‹S>H$s H$m MwZmd H$aZm
how many ways can the teacher make this MmhVm h¡& {ejH$ ¶h MwZmd {H$VZo àH$ma go H$a
selection? gH$Vm h¡?
(A) 370 (B) 372 (A) 370 (B) 372
(C) 378 (D) 390 (C) 378 (D) 390

012. A student has to answer 10 questions, 012. {H$gr {dÚmWu H$mo 10 àíZm|o$ Ho$ CÎma XoZo h¢, O~{H$
choosing atleast 4 from each of Parts A and Cgo à˶oH$ ^mJ A Am¡a B ‘| go H$‘ go H$‘ 4 àíZ
B. If there are 6 questions in Part A and 7 in MwZZo h¢& ¶{X ^mJ A ‘| 6 àíZ h¢ Am¡a ^mJ B ‘| 7
Part B, in how many ways can the student àíZ h¢, Vmo dh {dÚmWu {H$VZo àH$ma go 10 àíZ MwZ
choose 10 questions ? gH$Vm h¡?
(A) 206 (B) 222 (A) 206 (B) 222
(C) 256 (D) 266 (C) 256 (D) 266

8-AA ] [4] [ Contd...

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013. The total number of terms in the expansion of
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013. (x + a)51 – (x – a)51 Ho$ àgma ‘| gacrH$aU Ho$ ~mX ss
(x + a)51 – (x – a)51 after simplification is: nXm| H$s g§»¶m h¡& ss
(A) 102 (B) 25
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(A) 102 (B) 25 ss
(C) 26 (D) None of these (C) 26 (D) None of these ss
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014. If the coefficients of 2nd, 3rd and the 4th terms 014. ¶{X (1 + x) Ho$ àgma ‘| Xÿgao, Vrgao Am¡a Mm¡Wo nXm| ss
n

in the expansion of (1 + x)n are in A.P., then
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Ho$ JwUm§H$ g‘m§Va loUr ‘| h¢, Vmo n H$m ‘mZ h¡: ss
value of n is: (A) 5 (B) 7
(A) 5 (B) 7 (C) 11 (D) 14
(C) 11 (D) 14

015. In a G.P. of even number of terms, the sum of 015. EH$ JwUmoÎma loUr ‘| nXm| H$s g§»¶m g‘ h¡& ¶{X g^r
all terms is 5 times the sum of the odd terms. nXm| H$m ¶moJ {df‘ nXm| Ho$ ¶moJ H$m 5 JwZm h¡, Vmo
The common ratio of the G.P. is: JwUmoÎma loUr H$m gmd©AZwnmV h¢:
(A) – 4/5 (B) 1/5 (A) – 4/5 (B) 1/5
(C) 4 (D) None of these (C) 4 (D) None of these

016. The lengths of three unequal edges of a 016. cH$‹S>r Ho$ R>mog Am¶VmH$ma I§S> Ho$ VrZ Ag‘mZ
rectangular solid block are in G.P. The {H$Zmam| H$s c§~mB© JwUmoÎma loUr ‘| h¡& Cg cH$‹S>r
volume of the block is 216 cm3 and the total Ho$ I§S> H$m Am¶VZ 216 KZ go‘r Ed§ Hw$b n¥ð>r¶
surface area is 252 cm2. The length of the joÌ’$c 252 dJ© go‘r h¡& Vmo g~go c§~o {H$Zmao H$s
longest edge is: c§~mB© h¡&
(A) 12 cm (B) 6 cm (A) 12 cm (B) 6 cm
(C) 18 cm (D) 3 cm (C) 18 cm (D) 3 cm

017. The intercept cut off by a line from y-axis 017. {H$gr aoIm Ûmam y-Aj na H$mQ>m J¶m A§V: I§S>,
is twice than that from x-axis, and the line x-Aj na H$mQ>o J¶o A§V: I§S> go XmoJwZm h¡ Am¡a ¶h
passes through the point (1, 2). The equation aoIm q~Xþ (1, 2) go OmVr h¡& Vmo aoIm H$m g‘rH$aU
of the line is: h¡:
(A) 2x + y = 4 (B) 2x + y + 4 = 0 (A) 2x + y = 4 (B) 2x + y + 4 = 0
(C) 2x – y = 4 (D) 2x – y + 4 = 0 (C) 2x – y = 4 (D) 2x – y + 4 = 0

8-AA ] [5] [ P.T.O.

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ss 018. Equations of diagonals of the square formed
ss 018. aoImAm| x = 0, y = 0, x = 1 Ed§ y = 1 Ûmam {Z{‘©V dJ©
ss by the lines x = 0, y = 0, x = 1 and y = 1 are: Ho$ {dH$Um] Ho$ g‘rH$aU h¢:
ss (A) y = x, y + x = 1
ss (A) y = x, y + x = 1
ss (B) y = x, x + y = 2 (B) y = x, x + y = 2
ss (C) 2y = x, y + x =1/3
ss (C) 2y = x, y + x =1/3
ss (D) y = 2x, y + 2x = 1 (D) y = 2x, y + 2x = 1
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019. The perpendicular distance of the point 019. q~Xþ P (6, 7, 8) H$s xy - Vc go cå~dV² Xÿar h¡:
P (6, 7, 8) from xy – plane is: (A) 8 (B) 7
(A) 8 (B) 7 (C) 6 (D) None of these
(C) 6 (D) None of these

lim sec x - 2 is:
2
lim sec x - 2 H$m ‘mZ h¡:
2
020. tan x - 1 020.
x" r x" r tan x - 1
4 4
(A) 3 (B) 1 (A) 3 (B) 1
(C) 0 (D) 2 (C) 0 (D) 2

sin x + 9 dy x+9 dy
021. If y = cos x then dx 021. ¶{X y = sincos x Vmo x = 0 na dx H$m ‘mZ h¡:
at x = 0 is
(A) cos 9 (B) sin 9
(A) cos 9 (B) sin 9 (C) 0 (D) 1
(C) 0 (D) 1

022. The converse of the statement “If sun is not 022. H$WZ ""¶{X gy¶© Zht M‘H$ ahm h¡, Vmo AmH$me
shining, then sky is filled with clouds” is: ~mXcm| go ^am (AmÀN>m{XV) h¡&'' H$m {dcmo‘ H$WZ
(A) If sky is filled with clouds, then the sun h¡:
is not shining. (A) ¶{X AmH$me ~mXcm| go ^am h¡, Vmo gy¶© Zht
(B) If sun is shining, then sky is filled with M‘H$ ahm h¡&
clouds. (B) ¶{X gy¶© M‘H$ ahm h¡, Vmo AmH$me ~mXcm| go
(C) If sky is clear, then sun is shining. ^am h¡&
(D) If sun is not shining, then sky is not (C) ¶{X AmH$me gm’$ h¡, Vmo gy¶© M‘H$ ahm h¡&
filled with clouds. (D) ¶{X gy¶© Zht M‘H$ ahm h¡, Vmo AmH$me ~mXcm|
go Zht ^am h¡&

8-AA ] [6] [ Contd...

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023. Coefficient of variation of two distributions
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023. Xmo ~§Q>Zm| Ho$ {dMaU JwUm§H$ 50 Ed§ 60 h¡ Am¡a ss
are 50 and 60, and their arithmetic means are Ho$ ‘mܶ H«$‘e: 30 Ed§ 25 h¢, Vmo CZHo$ ‘mZH$ ss
30 and 25 respectively. Difference of their
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{dMcZm| H$m AÝVa h¡: ss
standard deviation is: (A) 0 (B) 1 ss
(A) 0 (B) 1
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(C) 1.5 (D) 2.5 ss
(C) 1.5 (D) 2.5 ss
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024. If the marks obtained by 9 students in a 024. ¶{X J{UV Ho$ EH$ Q>oñQ> ‘| 9 {dÚm{W©¶m| Ûmam àmá A§H$
mathematics test are: 50, 69, 20, 33, 53, 39, {ZåZ{cpIV h¡: 50, 69, 20, 33, 53, 39, 40, 65,
40, 65, 59. Then the mean deviation from the 59 Vmo CnamoŠV Ho$ {cE ‘mpܶH$m go ‘mܶ {dMcZ
median is: h¢ &
(A) 9 (B) 10.5 (A) 9 (B) 10.5
(C) 12.67 (D) 14.76 (C) 12.67 (D) 14.76

025. If A and B are mutually exclusive events, 025. ¶{X KQ>ZmE± A VWm B nañna AndOu h¢, Vmo
then: (A) P (A) ≤ P ^ B h (B) P (A) ≥ P ^ B h
(A) P (A) ≤ P ^ B h (B) P (A) ≥ P ^ B h (C) P (A) < P ^ B h (D) None of these
(C) P (A) < P ^ B h (D) None of these

026. If A, B, C are three mutually exclusive and 026. ¶{X A, B, C {H$gr narjU H$s VrZ nañna
exhaustive events of an experiment such that AndOu Am¡a {Z:eof KQ>ZmE± Bg àH$ma h¢ {H$
3P(A) = 2P(B) = P(C), then P(A) is equal to: 3P(A) = 2P(B) = P(C), Vmo P(A) {ZåZ{cpIV ‘|
(A) 1/11 (B) 2/11 go {H$g Ho$ g‘mZ h¡:
(C) 5/11 (D) 6/11 (A) 1/11 (B) 2/11
(C) 5/11 (D) 6/11

027. Without repetition of the numbers, four-digit 027. A§H$m| 0, 2, 3, 5 go, {~Zm nwZamd¥{Îm {H$E, Mma
numbers are formed with the numbers 0, 2, 3, A§H$m| H$s g§»¶mE± ~ZmB© OmVr h¢& Bg àH$ma ~Zr
5. The probability of such a number divisible g§»¶m Ho$ 5 go ^mÁ¶ hmoZo H$s àm{¶H$Vm h¡:
by 5 is: (A) 1/5 (B) 4/5
(A) 1/5 (B) 4/5 (C) 5/9 (D) 3/9
(C) 5/9 (D) 3/9

8-AA ] [7] [ P.T.O.

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ss 028. LAN stands for. the following:
ss 028. LAN H$m ‘Vb~ h¡&
ss (A) Limited Area Network (A) gr{‘V joÌ ZoQ>dH©$
ss (B) Logical Area Network
ss (B) bm°{OH$b E[a¶m ZoQ>dH©$
ss (C) Local Area Network (C) bmoH$b E[a¶m ZoQ>dH©$
ss (D) Large Area Network
ss (D) ~S>m joÌ ZoQ>dH©$
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ss 029. Hardware or software designed to guard
ss 029. H§$߶yQ>a na AZ{YH¥$V nhþ§M go ~Mmd Ho$ {bE {S>µOmBZ
against unauthorized access to a computer {H$¶m J¶m hmS>©do¶a ¶m gm°âQ>do¶a ZoQ>dH©$ H$mo {H$g
network is known as : ê$n ‘| OmZm OmVm h¡:
(A) Hacker-proof program. (A) h¡H$a ày’$ àmoJ«m‘
(B) Firewall (B) ’$m¶adm°b
(C) Hacker-resistant server (C) h¡H$a à{VamoYr gd©a
(D) Encryption safe wall. (D) EpÝH«$ßeZ gwa{jV Xrdma

030. Which of the following does not store data 030. {ZåZ{bpIV ‘| go H$m¡Z S>oQ>m H$mo ñWm¶r ê$n go g§J«hrV
permanently? Zht H$aVm h¡&
(A) ROM (B) RAM (A) ROM (B) RAM
(C) Floppy Disk (D) Hard Disk (C) âbm°nr {S>ñH$ (D) hmS>© {S>ñH$

031. The speed of modem is measured in: 031. ‘moS>‘ H$s J{V ‘mnr OmVr h¡&
(A) Gbps (B) Tbps (A) Or~rnrEg (B) Q>r~rnrEg
(C) Kbps (D) Pbps (C) Ho$~rnrEg (D) nr~rnrEg

032. URL stands for: 032. ¶yAmaEc H$m AW© h¡&
(A) Uniform Research Limited (A) ¶y{Z’$mo‘© [agM© {b{‘Q>oS>
(B) Uniform Resource Locator (B) ¶y{Z’$mo‘© [agmog© bmoHo$Q>a
(C) Uniline Resource Labs (C) ¶y{ZbmBZ [agmog© b¡ãg
(D) Uniform Research Locator (D) ¶y{Z’$mo‘© [agM© bmoHo$Q>a

8-AA ] [8] [ Contd...

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033. E-commerce, e-learning, e-banking,
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033. B©-H$m°‘g©, B©-c{ZªJ, B©-~¡qH$J, E‘-H$m°‘g© h¢& ss
m-commerce are some of the (A) B©-g{d©goO ss
(A) e-services
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(B) B§Q>aZoQ> g{d©goO ss
(B) Internet services (C) ¶yOa g{d©goO ss
(C) User services
ss
(D) ì¶mnma godmE± ss
(D) Business services ss
ss
ss
034. GPRS is used in mobile phones for 034. ‘mo~mBc ’$moZ ‘| OrnrAmaEg à¶moJ hmoVm h¡&
(A) Data communication (A) S>mQ>m g§Mma Ho$ {bE
(B) Voice communication (B) Üd{Z g§Mma Ho$ {bE
(C) Send SMS (C) EgE‘Eg ^oOZo Ho$ {bE
(D) None of the above (D) Cn¶w©³V ‘| go H$moB© Zht

035. Broadband is a convergence technology for 035. ~«m°S>~¢S> A{^gaU àm¡Úmo{JH$s h¡&
(A) Voice, data and video (A) Üd{Z S>mQ>m Am¡a dr{S>¶mo
(B) Only data (B) Ho$db S>mQ>m
(C) Only voice (C) Ho$db Üd{Z
(D) Only video (D) Ho$db dr{S>¶mo

036. What is decimal value of binary number 036. ¶w½‘H$ g§»¶m 101001012 H$m Xe‘cd ‘mZ ³¶m
101001012 hmoJm&
(A) 165 (B) 155 (A) 165 (B) 155
(C) 004 (D) 124 (C) 004 (D) 124

037. The result of binary division 00101010 ÷ 037. ¶w½‘H$ 00101010 ÷ 00000110 ^mJ H$m ‘mZ hmoJm&
00000110 is: (A) 00000111 (B) 01000111
(A) 00000111 (B) 01000111 (C) 00100111 (D) 00010111
(C) 00100111 (D) 00010111

8-AA ] [9] [ P.T.O.

ss
ss
ss
ss 038. The drawing in which the view is drawn at an
ss 038. dh S´>mB§J {Og‘| Ñí¶ 30° Am¡a 150° Ho$ H$moU na
ss angle 30° and 150° is called : ItMm OmVm h¡:
ss (A) Auxiliary view
ss (A) ghm¶H$ Ñí¶
ss (B) Front view (B) gm‘Zo H$m Ñí¶
ss (C) Isometric view
ss (C) g‘{‘Vr¶ Ñí¶
ss (D) Perspective view (D) n[aàoú¶
ss
ss
039. The model which is created by using basic 039. Xmo Am¶m‘m| H$s ~w{Z¶mXr g§ñWmAm| H$m Cn¶moJ H$aHo$
entities of two dimensioning is called: ~Zm¶m OmZo dmbm ‘m°S>b H$hbmVm h¡&
(A) Surface model (A) ga’o$g ‘m°S>b
(B) Wire frame model (B) dm¶a ’«o$‘ ‘m°S>b
(C) Solid model (C) R>mog ‘m°S>b
(D) Isometric model (D) AmBgmo‘o{Q´>H$ ‘m°S>b

040. For a Whitworth external thread, the distance 040. pìhQ>dW© ~mhar W«oS> Ho$ {bE, {eIm Am¡a O‹S> Ho$ ~rM
between the crest and root (d) when pitch (p) H$s Xÿar (d) O~ {nM (p) Ûmam Xr OmVr h¡:
is given by: (A) d = 0.75 p (B) d = 0.5 p
(A) d = 0.75 p (B) d = 0.5 p (C) d = 0.61 p (D) d = 0.64 p
(C) d = 0.61 p (D) d = 0.64 p

041. If a nut, when turned in clockwise direction 041. ¶{X EH$ ZQ> H$mo O~ EH$ ~moëQ> na ³dm°H$dmBO {Xem
screws on a bolt, the thread is a left-hand ‘| Kw‘m¶m OmVm h¡, Vmo W«oS> H$mo boâQ> h¢S> W«oS> ‘mZm
thread, this statement is: OmVm h¡, ¶h H$WZ
(A) True (A) g˶ h¡
(B) False (B) JbV h¡
(C) Cannot be decided (C) {ZU©¶ Zht {H$¶m Om gH$Vm h¡
(D) None of the above (D) Cnamo³V ‘| go H$moB© Zht

042. For a dc shunt motor of 5 kW, running at 042. 5 {H$bmodmQ> H$s S>rgr e§Q> ‘moQ>a, Omo 1000 rpm na
1000 rpm, the induced torque will be: Mb ahr h¡, Vmo ào[aV Q>mH©$ hmoJm:
(A) 47.76 N (B) 57.76 N (A) 47.76 N (B) 57.76 N
(C) 35.76 N (D) 37.76 N (C) 35.76 N (D) 37.76 N

8-AA ] [ 10 ] [ Contd...

ss
ss
ss
043. A current of 5A flows in a resistor of
ss
043. ¶{X 5A H$s Ymam H$m àdmh EH$ 2 Amo‘ Ho$ EH$ ss
2 ohms. Calculate the energy dissipated in ao{gñQ>a ‘| ~hVr h¡ Vmo ao{gñQ>a ‘| 300 goH§$S> ‘| ss
300 seconds in the resistor.
ss
{dK{Q>V D$Om© H$s JUZm H$a|& ss
(A) 15kJ (B) 15000kJ (A) 15kJ (B) 15000kJ ss
(C) 1500J (D) 15J
ss
(C) 1500J (D) 15J ss
ss
044. Calculate the work done in a resistor of
ss
044. ¶{X 20 Amoh‘ Ho$ EH$ ao{g{gQ>a ‘| 5A H$s Ymam H$m ss
20 ohm carrying 5A of current in 3 hours. àdmh 3 K§Q>o VH$ hmoVm h¡ Vmo {H$¶m J¶m H$m¶© {H$VZm
hmoJm&
(A) 1.5J (B) 15J
(A) 1.5J (B) 15J
(C) 1.5kWh (D) 15kWh
(C) 1.5kWh (D) 15kWh

045. Earthing is required for protection from 045. A{WªJ {H$g Xmof go àmoQ>oŠeZ Ho$ {bE Amdí¶H$ h¡&
which defect? (A) dmoëQ>oO ‘| n[adV©Z
(A) Change in voltage (B) Amoda bmoqS>J
(B) Over loading (C) {dÚwV PQ>H$mo go IVao
(C) Danger from electric shock (D) H§$S>³Q>a H$m CÀM Vmn
(D) High temperature in conductor

046. Which alternator has the least speed: 046. {H$g AëQ>aZoQ>a H$s ñnrS> g~go H$‘ hmoVr h¡&
(A) 
alternator coupled with hydraulic (A) hmBS´>mo{bH$ Q>a~m¶Z Ho$ gmW H$nëS> AëQ>aZoQ>a
turbine (B) ñQ>r‘ B§OZ Ho$ gmW H$nëS> AëQ>aZoQ>a
(B) alternator coupled with steam engine (C) ñQ>r‘ Q>a~m¶Z Ho$ gmW H$nëS> AëQ>aZoQ>a
(C) alternator coupled with steam turbine (D) Cnamo³V ‘| go H$moB© Zht.
(D) None of the above

047. The efficiency of thermal power plant 047. W‘©b nm°da ßbm§Q> H$s XjVm ~T>Vr h¡:
increases by: (A) A{YH$ ‘mÌ ‘| H$mo¶bm XhZ H$aZo na
(A) burning more quantity of coal (B) Ob H$s ‘mÌ A{YH$ à¶moJ H$aZo na
(B) Using excessive amount of water (C) ßbm§Q> na ^ma H$‘ H$aZo na
(C) Reducing the load on the plant (D) ^mn H$m CÀM X~ à¶w³V H$aZo na
(D) Using steam at high pressure

8-AA ] [ 11 ] [ P.T.O.

ss
ss
ss
ss 048. If the frequency of the emf generated by an
ss 048. ¶{X 3000 rpm na n[a^«‘U H$a aho EH$ AmëQ>aZoQ>a
ss alternator revolving at 3000 rpm is 50 Hz, Ûmam CËnÞ emf H$s Amd{Îm© 50 Hz h¡, Vmo Y«wdm| H$s
ss what will be the number of poles?
ss g§»¶m Š¶m hmoJr?
ss (A) 8 (B) 6 (A) 8 (B) 6
ss (C) 4 (D) 2
ss (C) 4 (D) 2
ss
ss 049. If a dc class motor is connected to the ac
ss 049. ¶{X EH$ dc loUr H$s ‘moQ>a H$mo ac gßbmB© go H$ZoŠQ>
supply then: {H$¶m Omdo V~:
(A) the motor will not start (A) ‘moQ>a ñQ>mQ>© Zht hmoJr
(B) The motor will start but stop immediately (B) ‘moQ>a ñQ>mQ>© hmo OmEJr naÝVw Vwa§V éH$ OmdoJr
(C) The motor will start but will not work (C)  ‘moQ>a ñQ>mQ>© hmo OmEJr naÝVw g§VmofOZH$ H$m¶©
satisfactorily Zht H$aoJr
(D) None of the above (D) Cnamoº$ ‘| go H$moB© Zht

050. The single-phase motor has a characteristic 050. qgJb ’o$O ‘moQ>a H$m EH$ A{^bjU h¡-
(A) It does not start automatically (A) ¶h ñdV… ñQ>mQ>© Zht hmoVr
(B) It starts automatically (B) ¶h ñdV… ñQ>mQ>© hmoVr h¡
(C) It requires only one winding (C) Bg‘| Ho$db EH$ {dpÝS§>J H$s Amdí¶H$Vm hmoVr h¡
(D) It can rotate in one direction only (D) ¶h Ho$db EH$ {Xem ‘| amoQ>oQ> H$a gH$Vr h¡

051. The percentage of carbon in cast iron is: 051. T>bdm bmoho ‘| H$m~©Z H$s à{VeV ‘mÌm ahVr h¡:
(A) 0% (A) 0%
(B) less than 1% (B) 1% go H$‘
(C) less than 2% (C) 2% go H$‘
(D) More than 2% (D) 2% go Á¶mXm

052. Which of the following ferrous material is 052. H$nmobm ^Å>r ‘| {ZåZ{bpIV ‘| go H$m¡Z gm nXmW©
made in cupola furnace: ~Zm¶m OmVm h¡:
(A) Pig Iron (A) {nJ Am¶aZ
(B) Cast Iron (B) T>bdm bmohm
(C) Wrought Iron (C) {nQ>dm§ bmohm
(D) Steel (D) BñnmV

8-AA ] [ 12 ] [ Contd...

ss
ss
ss
053. Which material is used for making Bicycle
ss
053. ~mB{gH$b ’«o$‘ Ho$ nmBn {H$g nXmW© go ~Zm¶o OmVo ss
frames? h¢? ss
(A) Hot rolled steel
ss
(A) hm°Q> amoëS> BñnmV ss
(B) Cold rolled steel (B) R>§S>m amoëS> BñnmV ss
(C) forged steel
ss
(C) ’$moµO}S> BñnmV ss
(D) Cast steel (D) T>bdm BñnmV ss
ss
ss
054. The nichrome used in heating element is 054. hrqQ>J E{b‘|Q> ‘| à¶wº$ ZmB©H«$mo‘ BZ VËdm| H$m Ebm¶
alloy of following: h¡:
(A) nickel & copper (A) {ZH$b d Vm§~m
(B) nickel & magnese (B) {ZH$b d ‘¡JZrO
(C) nickel & chromium (C) {ZH$b d H«$mo{‘¶‘
(D) chromium & magnese (D) H«$mo{‘¶‘ d ‘¡JZrO

055. The wire used in soldering is alloy of: 055. gmoëS>[a¨J ‘| à¶wº$ dm¶a {H$gH$m Ebm¶ h¡:
(A) lead and tin (A) grgm d {Q>Z
(B) lead and copper (B) grgm d Vm§~m
(C) tin and copper (C) {Q>Z d Vm§~m
(D) lead and antimony (D) grgm d E§Q>r‘Zr

056. In gas welding the maximum flame 056. J¡g dopëS§>J ‘| A{YH$V‘ Ádmbm Vmn‘mZ hmoVm h¡&
temperature is at: (A) AmV§[aH$ e§Hw$ na
(A) inner cone (B) Ádmbm Ho$ {gao na
(B) tip of flame (C) AmV§[aH$ e§Hw$ Ho$ R>rH$ ~mha
(C) next to inner cone (D) ~mø e§Hw$ na
(D) at the outer cone

057. Which material has highest shrinkage 057. {ZåZ ‘| go {H$g YmVw H$m g§H$moMZ AbmC§g A{YH$
allowance: hmoVm h¡&
(A) Lead (B) Steel (A) grgm (B) BñnmV
(C) Aluminium (D) cast iron (C) Eë¶w‘r{Z¶‘ (D) T>bdm bmohm

8-AA ] [ 13 ] [ P.T.O.

ss
ss
ss
ss 058. In lathe operations, in which operation the
ss 058. IamX na {ZåZ g§{H«$¶mAmo ‘| {H$g‘o g~go Yr‘r Mmb
ss cutting speed is kept minimum: aIr OmVr h¡&
ss (A) Thread cutting (B) Taper turning
ss (A) My‹S>r H$V©Z (B) Q>ona Q>{ZªJ
ss (C) Normal turning (D) Knurling (C) gm‘mݶ IamXZ (D) ZaqbJ
ss
ss
ss 059. Speed of sound wave in air 059. dm¶w ‘| Üd{Z H$s Va§Jm| H$s Mmc
ss (A) is independent of temperature.
ss (A) Vmn na {Z^©a Zht H$aVr&
(B) increases with pressure. (B) Xm~ Ho$ gmW ~‹T>Vr h¡&
(C) increases with increase in humidity (C) AmЩVm ~‹T>Zo go ~‹T> Vr h¡&
(D) decreases with increase in humidity. (D) AmЩVm ~‹T>Zo go KQ>Vr h¡&

060. A hemisphere is uniformly charged positively. 060. H$moB© AY©Jmobm EH$g‘mZ ÜZmdo{eV h¡& Jmoco Ho$ Ho$ÝÐ
The electric field at a point on a diameter go nao BgHo$ {H$gr ì¶mg na pñWV {~ÝXþ na Omo Ho$ÝÐ
away from the centre is directed go Xÿa h¡, {dÚwV joÌ H$s {Xem
(A) perpendicular to the diameter (A) Bg ì¶mg Ho$ bå~dV h¡&
(B) parallel to the diameter (B) Bg ì¶mg Ho$ g‘mÝVa h¡&
(C) at an angle tilted towards the diameter (C) Bg ì¶mg H$s Amoa {H$gr H$moU na PwH$s h¡&
(D) at an angle tilted away from the diameter. (D) Bg ì¶mg go Xÿa {H$gr H$moU na PwH$s h¡&

061. Equipotentials at a great distance from a 061. Hw$N> Amdoem| Ho$ EH$ g‘yh H$m Hw$b ¶moJ eyݶ Zht h¡&
collection of charges whose total sum is not Bggo A{YH$ Xÿar na ~ZZo dmco g‘{d^d n¥ð> hm|Jo
zero are approximately (A) Jmobo (B) g‘Vb
(A) spheres (B) planes (C) nadb¶O (D) XrK©d¥ÎmO
(C) paraboloids (D) ellipsoids

062. In a region of constant potential 062. {Z¶V {d^d do’$ {H$gr àXoe ‘|
(A) the electric field is uniform (A) {dÚwV joÌ EH$g‘mZ hmoVm h¡&
(B) the electric field is zero (B) {dÚwV joÌ eyݶ hmoVm h¡&
(C) 
there can be no charge outside the (C) àXoe Ho$ ~mha H$moB© Amdoe Zht hmo gH$Vm&
region. (D) ¶{X Amdoe àXoe Ho$ ~mha pñWV h¡ Vmo Adí¶
(D) the electric field shall necessarily change n[ad[V©V hmoJm&
if a charge is placed outside the region.

8-AA ] [ 14 ] [ Contd...

ss
ss
ss
063. If a conductor has a potential V≠0 and there
ss
063. ¶{X {H$gr MmcH$ H$m {d^d V≠0 h¡ VWm CgHo$ n¥ð> ss
are no charges anywhere else outside, then go nao H$ht ^r H$moB© Amdoe Zht h¡, V~ ss
(A) there must be charges on the surface or
ss
(A)  MmbH$ Ho$ n¥îR> AWdm BgHo$ ^rVa Amdoe hmoZo ss
inside itself. Mm{hE& ss
(B) 
there must be charges only on the
ss
(B)  Ho$db MmbH$ Ho$ n¥îR> na hr Amdoe hmoZo ss
surface. Mm{hE& ss
(C) there must be charges inside the surface.
ss
(C)  MmbH$ Ho$ n¥îR> Ho$ ^rVa na hr Amdoe hmoZo ss
(D) None of the above Mm{hE&
(D) BZ‘o go H$moB© ^r Zht

064. A piece of wood having no vessels (trachea) 064. H$mð> H$m EH$ Qw>H$‹S>m {Og‘| dm{hH$mE Zht hmoVr h¢,
must be belong to ¶h {ZåZ{cpIV ‘| {H$ggo g§~§{YV h¡?
(A) Teak (B) Mango (A) Q>rH$ (B) Am‘
(C) Pine (D) Palm (C) Mr‹S> (D) nm‘

065. Which one of the following is not a connective 065. {ZåZ{cpIV ‘| go H$m¡Z EH$ g§¶moOr D$VH$ Zht h¡?
tissue? (A) A{ñW (B) CnmpñW
(A) Bone (B) Cartilage (C) a³V (D) noer
(C) Blood (D) Muscles

066. Which metal ion is a constituent of 066. H$m¡Z-gm YVw Am¶Z Šbmoamo{nµ’$c H$m EH$ KQ>H$ h¡?
chlorophyll? (A) Am¶aZ (B) H$m°na
(A) Iron (B) Copper (C) ‘¢JZr{e¶‘ (D) qOH$
(C) Magnesium (D) Zinc

067. One of the following is not a common 067. {ZåZ{cpIV ‘| go H$m¡Z-gm {dH$ma nmMZ V§Ì go
disorder associated with digestive system g§~§{YV Zht h¡?
(A) Tetanus (B) Diarrhoea (A) {Q>Q>Zog (B) XñV
(C) Jaundice (D) Dysentery (C) nr{b¶m (D) no{Me

8-AA ] [ 15 ] [ P.T.O.

ss
ss
ss
ss 068. It is known that exposure to carbon monoxide
ss 068. ¶h {d{XV h¢ {H$ H$m~©Z ‘moZmoAm°ŠgmBS> H$m àm{U¶m|
ss is harmful to animals because: na Xþîà^md hmoVm h¡ Š¶m|{H$
ss (A) It reduces CO2 transport
ss (A) BgHo$ H$maU CO2 n[adhZ H$‘ hmo OmVm h¡&
ss (B) It reduces O2 transport (B) BgHo$ H$maU O2 n[adhZ H$‘ hmo OmVm h¡&
ss (C) It increases CO2 transport
ss (C) BgHo$ H$maU CO2 n[adhZ ~‹T> OmVm h¡&
ss (D) It destroys hemoglobin (D) BgHo$ H$maU hr‘mo½bmo{~Z ZîQ> hmo OmVm h¡&
ss
ss
069. The following substances are the excretory 069. {ZåZ{cpIV nXmW© àm{U¶m| Ho$ CËgOu CËnmX h¢& BZ‘|
products in animals. Choose the least toxic go g~go H$‘ A{dfmcw nXmW© Mw{ZE&
form among them? (A) ¶y[a¶m (B) ¶y[aH$ Aåb
(A) Urea (B) Uric acid (C) A‘mo{Z¶m (D) H$m~©Z S>mB©-Am°³gmBS>
(C) Ammonia (D) Carbon dioxide

070. Knee joint and elbow joints are examples of 070. KwQ>H$-g§{Y Am¡a H$mohZr-g§{Y {H$g àH$ma H$s g§{Y
(A) Saddle joint Ho$ CXmhaU h¢?
(B) Ball and socket joint (A) g¡S>b g§{Y
(C) Pivot joint (B) d§’$ÐþH$-IpëbH$m g§{Y
(D) Hinge joint (C) YwamJ« g§{Y
(D) H$ãOm g§{Y

071. Two cells of emf’s approximately 5V and 071. 5V VWm 10V gpÝZH$Q> emf Xmo gocm| H$s VwcZm
10V are to be accurately compared using a
n[aewX²Y ê$n go 400cm cå~mB© Ho$ {d^d‘mnr Ûmam
potentiometer of length 400 cm.
H$s OmZr h¡&
(A) The battery that runs the potentiometer
(A)  {d^d‘mnr ‘| Cn¶moJ hmoZodmbr ~¡Q>ar H$s
should have voltage of 8V.
(B) The battery of potentiometer can have dmoëQ>Vm 8V hmoZr Mm{hE&
a voltage of 15V and R adjusted so (B)  {d^d‘mnr H$s dmoëQ>Vm 15V hmo gH$Vr h¡ VWm R
that the potential drop across the wire H$mo Bg àH$ma g‘m¶mo{OV H$a gH$Vo h¢ {H$ Vma
slightly exceeds 10V. Ho$ {gam| na {d^dnmV 10V go Wmo‹S>m A{YH$ hmo&
(C) The first portion of 50 cm of wire itself (C)  ñd¶§ Vma Ho$ nhbo 50 cm ^mJ na {d^dnmV
should have a potential drop of 10V. 10V hmoZm Mm{hE&
(D) 
Potentiometer is usually used for
(D)  {d^d‘mnr H$m Cn¶moJ àm¶: à{VamoY| H$s VwbZm
comparing resistances and not voltages.
Ho$ {bE {H$¶m OmVm h¡, {d^dm| Ho$ {bE Zht&

8-AA ] [ 16 ] [ Contd...

ss
ss
ss
072. An electron is projected with uniform
ss
072. EH$ BcoŠQ´>m°Z H$mo {H$gr cå~r Yamdmhr n[aZm{cH$m ss
velocity along the axis of a current carrying Ho$ Aj Ho$ AZw{Xe EH$g‘mZ doJ go àjo{nV {H$¶m ss
long solenoid. Which of the following is true? ss
OmVm h¡& {ZåZ{cpIV ‘| H$m¡Z gm àH$WZ g˶ h¡? ss
(A) The electron will be accelerated along
(A) Bbo³Q´>m°Z Aj Ho$ AZw{Xe Ëd[aV hmoJm& ss
the axis. ss
(B) Aj Ho$ n[aV: Bbo³Q´>m°Z H$m nW d¥ÎmmH$ma hmoJm& ss
(B) The electron path will be circular about
(C) Bbo³Q´>m°Z Aj go 45° na ~b AZw^d ss
the axis. ss
(C) 
The electron will experience a force H$aoJm Am¡a Bg àH$ma Hw§$S>{bZr nW na J‘Z ss
at 45° to the axis and hence execute a H$aoJm&
helical path. (D) Bbo³Q´>m°Z n[aZ{bH$m Ho$ Aj Ho$ AZw{Xe
(D) The electron will continue to move with EH$g‘mZ doJ go J{V H$aVm ahoJm&
uniform velocity along the axis of the
solenoid.

073. The primary origin(s) of magnetism lies in 073. Mwå~H$Ëd H$m ‘yc CX²^d g«moV h¡&
(A) intrinsic spin of electron. (A) Bbo³Q´>m°Z H$m Z¡O MH«$U
(B) Pauli exclusion principle. (B) nmCbr-AndO©Z {gX²Ym§V
(C) polar nature of molecules (C) AUw H$s Y«wdr¶ àH¥${V
(D) None of the above (D) BZ‘| go H$moB© Zht

074. The self inductance L of a solenoid of length 074. {H$gr AZwàñW H$mQ> Ho$ joÌ’$c A VWm {Z¶V ’o$am|
l and area of crosssection A, with a fixed H$s g§»¶m N dmcr l cå~mB© H$s n[aZm{cH$m H$m
number of turns N increases as ñdàoaH$Ëd L ~‹T> OmVm h¡:
(A) l and A increase. (A) l VWm A ‘| d¥X²{Y Ho$ gmW
(B) l decreases and A increases. (B) l ‘| H$‘r VWm A ‘| d¥X²{Y Ho$ gmW.
(C) l increases and A decreases. (C) l d¥X²{Y VWm A ‘| H$‘r Ho$ gmW.
(D) both l and A decrease (D) l VWm A ‘| H$‘r Ho$ gmW

075. If the rms current in a 50 Hz ac circuit is 5A, 075. ¶{X 50 hQ²>©µO ac n[anW ‘| 5A H$s rms Ymam àdm{hV
the value of the current 1/300 seconds after hmo ahr hmo, Vmo Ymam n[a‘mU eyݶ hmoZo Ho$ 1/300
its value becomes zero is goH§$S> níMmV BgH$m ‘mZ hmoJm&
(A) 5 2A (B) 5 3/2 A (A) 5 2A (B) 5 3/2 A
(C) 5/6 A (D) 5/ 2 A (C) 5/6 A (D) 5/ 2 A

8-AA ] [ 17 ] [ P.T.O.

ss
ss
ss
ss 076. The output of a step-down transformer is
ss 076. {H$gr AnMm¶r Q´>m±g’$m‘©a H$m {ZJ©‘ 12w àH$me
ss measured to be 24 V when connected to a ~ë~ H$mo g§¶mo{OV H$aZo na 24 V ‘mnm OmVm h¡&
ss 12 watt light bulb. The value of the peak
ss {eIa Yam H$m ‘mZ h¡:
ss current is (A) 1/ 2 A. (B) 2 A.
ss (A) 1/ 2 A. (B) 2 A.
ss (C) 2 A. (D) 2 2 A.
ss (C) 2 A. (D) 2 2 A.
ss
ss
077. The source of electromagnetic waves can be 077. d¡ÚwVMwå~H$s¶ Va§Jm| H$m g«moV hmo gH$Vm h¡ H$moB©
a charge Amdoe
(A) moving with a constant velocity. (A) Omo {Z¶V doJ go Mb ahm hmo&
(B) moving in a circular orbit. (B) Omo d¥Îmr¶ H$jm ‘| Mb ahm hmo&
(C) at rest. (C) Omo {dam‘mdñWm ‘| hmo&
(D) none of the above (D) BZ‘o go H$moB© Zht

078. A short pulse of white light is incident from 078. ídoV àH$me H$m EH$ cKw ñn§X dm¶w go H$m±M Ho$
air to a glass slab at normal incidence. After EH$ ñc¡~ na cå~dV Amn{VV hmoVm h¡& ñc¡~ go
travelling through the slab, the first colour to JwµOaZo Ho$ níMmV² g~go nhco {ZJ©V hmoZo dmcm dU©
emerge is hmoJm&
(A) blue (B) green (A) Zrbm (B) ham
(C) violet (D) red (C) ~¢JZr (D) bmb

079. An object approaches a convergent lens from 079. EH$ q~~ {H$gr A{^gmar c|g Ho$ ~mBª Amoa go 5 m/s
the left of the lens with a uniform speed 5 m/s H$s EH$g‘mZ Mmc go CnJ‘Z H$aVm h¡ Am¡a ’$moH$g
and stops at the focus. The image na OmH$a éH$ OmVm h¡& à{Vq~~
(A) 
moves away from the lens with a (A) 5 m/s H$s EH$g‘mZ Mmb go b|g go Xÿa J{V
uniform speed 5 m/s. H$aVm h¡&
(B) 
moves away from the lens with a (B) EH$g‘mZ ËdaU go b|g go Xÿa J{V H$aVm h¡&
uniform accleration. (C) Ag‘mZ ËdaU go b|g go Xÿa J{V H$aVm h¡&
(C) moves away from the lens with a non- (D) Ag‘mZ ËdaU go b|g H$s Amoa J{V H$aVm h¡&
uniform acceleration.
(D) 
moves towards the lens with a non-
uniform acceleration

8-AA ] [ 18 ] [ Contd...

ss
ss
ss
080. Heavy stable nucle have more neutrons than
ss
080. ñWm¶r ^mar Zm{^H$m| ‘| ݶyQ´>m°Zm| H$s g§»¶m àmoQ>m°Zm| go ss
protons. This is because of the fact that A{YH$ hmoVr h¡& BgH$m H$maU ¶h h¡ {H$ ss
(A) neutrons are heavier than protons.
ss
(A) ݶyQ´>m°Z àmoQ>m°Z go A{YH$ ^mar hmoVo h¢& ss
(B) electrostatic force between protons are (B) àmoQ>m°Zm| Ho$ ~rM pñWa {dÚwV ~b à{VH$f©UmË‘H$ ss
repulsive.
ss
hmoVm h¡& ss
(C) 
neutrons decay into protons through (C) β {dKQ>Z Ûmam ݶyQ´>m°Z àmoQ>m°Zm| ‘| {dK{Q>V hmo ss
beta decay.
ss
OmVo h¡& ss
(D) 
nuclear forces between neutrons are (D) ݶyQ´>m°Zm| Ho$ ~rM Zm{^H$s¶ ~b àmoQ>m°Z Ho$ ~rM
weaker than that between protons. Zm{^H$s¶ ~b H$s Anojm Xþ~©b hmoVm h¡&

081. Hole is 081. hmoc hmoVm h¡
(A) an anti-particle of electron. (A) Bbo³Q´>m°Z H$m à{VH$U&
(B) 
a vacancy created when an electron (B) ghg§¶moOr Am~§Y go EH$ Bbo³Q´>m°Z Xÿa {N>Q>H$
leaves a covalent bond. OmZo na CËnÝZ [ap³V&
(C) absence of free electrons. (C) ‘w³V Bbo³Q´>m°Zm| H$s AZwnpñW{V
(D) an artifically created particle. (D) H¥${Ì‘ ê$n go g¥{OV H$moB© H$U&

082. A male voice after modulation-transmission 082. EH$ nwéf H$s dmUr, ‘mSw>crH$aU d àofU Ho$ níMmV,
sounds like that of a female to the receiver. J«mhr H$mo ‘{hcm H$s dmUr H$s ^m±{V gwZmB© XoVr (àVrV
The problem is due to hmoVr) h¡& BgH$m H$maU h¡-
(A) 
poor selection of modulation index (A)  AZwn¶w³V ‘mSw>bZ gyMH$m§H$ H$m MwZmd ( 0 < m
(selected 0 < m < 1) < 1 MwZm J¶m)
(B) poor bandwidth selection of amplifiers. (B)  Amdh©H$m| Ho$ {bE AZwn¶w³V ~¡ÊS> Mm¡‹S>mB© H$m
(C) poor selection of carrier frequency MwZmd
(D) loss of energy in transmission. (C) dmhH$ Va§Jm| H$s Amd¥{Îm H$m AZwn¶w³V MwZmd
(D) g§MaU ‘| COm©-hm{Z

083. The mean length of an object is 5 cm. Which 083. {H$gr qnS> H$s Am¡gV c§~mB© 5 cm h¡& {ZåZ{cpIV
of the following measurements is most ‘| H$m¡Z-gm ‘mn gdm©{YH$ ¶WmW© h¡?
accurate? (A) 4.9 cm (B) 4.805 cm
(A) 4.9 cm (B) 4.805 cm (C) 5.25 cm (D) 5.4 cm
(C) 5.25 cm (D) 5.4 cm

8-AA ] [ 19 ] [ P.T.O.

ss
ss
ss
ss 084. A lift is coming from 8th floor and is just
ss 084. EH$ {bâQ> AmR>dt ‘§{Oc go ZrMo Am ahr h¡ Am¡a
ss about to reach 4th floor. Taking ground floor Mm¡Wr ‘§{Oc na nhþ±MZo dmcr h¡& ¶{X g^r am{e¶m| Ho$
ss as origin and positive direction upwards for
ss {cE ^yVc H$mo ‘yc q~Xþ VWm D$na H$s Amoa YZmË‘H$
ss all quantities, which one of the following is {Xem c| Vmo {ZåZ{cpIV ‘| H$m¡Z ghr h¡?
ss correct?
ss (A) x < 0, v < 0, a > 0
ss (A) x < 0, v < 0, a > 0 (B) x > 0, v < 0, a < 0
ss (B) x > 0, v < 0, a < 0
ss (C) x > 0, v < 0, a > 0
(C) x > 0, v < 0, a > 0 (D) x > 0, v > 0, a < 0
(D) x > 0, v > 0, a < 0

085. At a metro station, a girl walks up a stationary 085. {H$gr ‘oQ´>mo ñQ>oeZ na H$moB© c‹S>H$s EH$ éHo$ hþE
escalator in time t1. If she remains stationary EñHo$boQ>a na t1 goH§$S> ‘| D$na M‹T>Vr h¡& ¶{X dh
on the escalator, then the escalator takes her EñHo$boQ>a na I‹S>r aho Vmo EñHo$boQ>a Cgo t2 goH§$S> ‘|
up in time t2. The time taken by her to walk D$na co OmVm h¡& ¶{X dh McVo hþE EñHo$boQ>a na
up on the moving escalator will be AnZr nyd© J{V go hr D$na M‹T>o Vmo CgH$mo D$na VH$
(A) (t1 + t2)/2 (B) t1 t2/( t2– t1) nhþ±MZo ‘| cJZo dmcm g‘¶ hmoJm&
(C) t1 t2/( t2+ t1) (D) t1– t2 (A) (t1 + t2)/2 (B) t1 t2/( t2– t1)
(C) t1 t2/( t2+ t1) (D) t1– t2

086. It is found that |A+B| = |A|. This necessarily 086. ¶h nm¶m J¶m h¡ {H$ |A+B| = |A| V~ Bggo
implies, A{Zdm¶©V: ¶h Üd{Z hmoVr h¡ {H$
(A) B = 0 (A) B = 0
(B) A,B are antiparallel (B) A, B à{V g‘m§Va h¡
(C) A,B are perpendicular (C) A, B b§~dV² h¡&
(D) A.B ≤ 0 (D) A.B ≤ 0

087. A mass of 5 kg is moving along a circular 087. 5 kg Ð춑mZ H$m EH$ qnS> 1 m {ÌÁ¶m Ho$ d¥ÎmmH$ma
path of radius 1 m. If the mass moves with nW na J{V‘mZ h¡& ¶{X ¶h qnS> à{V {‘ZQ> 300
300 revolutions per minute, its kinetic energy MŠH$a cJmVm hmo Vmo BgH$s J{VO D$Om© hmoJr
would be (A) 250 π2 (B) 100 π2
(A) 250 π2 (B) 100 π2 (C) 5 π2 (D) 0
(C) 5 π2 (D) 0

8-AA ] [ 20 ] [ Contd...

ss
ss
ss
088. A copper and a steel wire of the same diameter
ss
088. g‘mZ ì¶mg Ho$ H$m°na Ed§ ñQ>rc Ho$ Vmam| H$mo {gao go ss
are connected end to end. A deforming force {gam {‘cmH$a Omo‹S>m J¶m h¡& Bg g§¶wŠV Vma na H$moB© ss
F is applied to this composite wire which
ss
{dê$nH$ ~c F Amamo{nV {H$¶m OmVm h¡ Omo Bg‘| ss
causes a total elongation of 1cm. The two 1cm H$s Hw$b d¥X²{Y H$a XoVm h¡& BZ XmoZm| Vmam| ‘|- ss
wires will have:
ss
(A) g‘mZ à{V~b hmoVm h¡ Ed§ {d{^ÝZ {dH¥${V¶m°& ss
(A) the same stress but different strain (B) {d{^ÝZ à{V~b hmoVm h¡& ss
(B) different stress
ss
(C) g‘mZ {dH¥${V hmoVr h¡& ss
(C) same strain (D) Cnamo³V ‘| go H$moB© Zht&
(D) None of the above

089. With increase in temperature, the viscosity of 089. Vmn ~‹T>Zo na
(A) gases and liquid decreases. (A) J¡gm| Am¡a Ðdm| H$s í¶mZVm KQ>Vr h¡&
(B) liquids and gas increases. (B) Ðdm| Am¡a J¡gm| H$s í¶mZVm ~‹T>Vr h¡&
(C) gases increase and liquid decreases. (C) J¡gm| H$s í¶mZVm ~‹T>Vr h¡ Am¡a Ðdm| H$s í¶mZVm
(D) liquids decrease and gas increases. KQ>Vr h¡&
(D) Ðdm| H$s í¶mZVm KQ>Vr h¡ Am¡a J¡gm| H$s í¶mZVm
~‹T>Vr h¡&

090. Which of the following statements about the 090. BcoŠQ´>m°Z Ho$ g§X^© ‘| {ZåZ{cpIV ‘| go H$m¡Z-gm
electron is incorrect? H$WZ JcV h¡?
(A) It is a negatively charged particle. (A) ¶h F$Umdo{eV H$U hmoVm h¡&
(B) The mass of electron is equal to the mass (B) Bbo³Q´>m°Z H$m Ð춑mZ ݶyQ´>m°Z Ho$ Ð춑mZ Ho$
of neutron. ~am~a hmoVm h¡&
(C) It is a basic constituent of all atoms. (C) ¶h g^r na‘mUwAm| H$m ‘yb Ad¶d hmoVm h¡&
(D) It is a constituent of cathode rays. (D) ¶h H¡$WmoS> {H$aUm| H$m Ad¶d hmoVm h¡&

091. Which of the following have no unit? 091. {ZåZ{cpIV ‘| go {H$ZH$s H$moB© BH$mB© Zht hmoVr h¡?
(A) Electronegativity (A) {dX¶wV F$UmË‘H$Vm
(B) Electron gain enthalpy (B) Bbo³Q´>m°Z bpãY EÝW¡ënr
(C) Ionisation enthalpy (C) Am¶ZZ EÝW¡ënr
(D) None of the above (D) Cnamo³V ‘| go H$moB© Zht

8-AA ] [ 21 ] [ P.T.O.

ss
ss
ss
ss 092. A person living in Shimla observed that
ss 092. {e‘cm ‘| ahZo dmco EH$ ì¶pŠV Zo AdcmoH$Z {H$¶m
ss cooking food without using pressure {H$ {~Zm àoea Hw$H$a H$m à¶moJ {H$E ^moOZ nH$mZo ‘|
ss cooker takes more time. The reason for this
ss A{YH$$ g‘¶ cJVm h¡& Bg AdcmoH$Z H$m H$maU
ss observation is that at high altitude: ¶h h¡ {H$ D±$MmBª dmco ñWmZm| na
ss (A) pressure increases
ss (A) Xm~ ~‹T>Vm h¡
ss (B) temperature decreases (B) Vmn KQ>Vm h¡
ss (C) pressure decreases
ss (C) Xm~ KQ>Vm h¡
(D) temperature increases (D) Vmn ~‹T>Vm h¡

093. Which of the following property of water can 093. dfm© H$s ~y±Xm| H$m Jmocr¶ AmH$ma g‘PmZo Ho$ {cE Oc
be used to explain the spherical shape of rain Ho$ {ZåZ{cpIV ‘| go {H$g JwU H$m Cn¶moJ {H$¶m Om
droplets? gH$Vm h¡?
(A) viscosity (A) í¶mZVm
(B) surface tension (B) n¥îR> VZmd
(C) critical phenomena (C) H«$m§{VH$ n[aKQ>Zm
(D) pressure (D) Xm~

094. At a particular temperature and atmospheric 094. EH$ {deof Vmn Am¡a dm¶w‘ÊS>cr¶ Xm~ na ewX²Y
pressure, the solid and liquid phases of a pure nXmW© H$s R>mog VWm Ðd àmdñWmE± gmå¶ ‘| hmo gH$Vr
substance can exist in equilibrium. Which of h¢& Bg Vmn H$mo Š¶m H$hVo h¢?
the following term defines this temperature? (A) gm‘mݶ JbZm§H$ ¶m {h‘m§H$
(A) Normal melting point or Freezing point (B) gmå¶ Vmn
(B) Equilibrium temperature (C) ³dWZm§H$
(C) Boiling point (D) BZ‘o go H$moB© Zht
(D) None of the above

095. Hydrogen peroxide is: 095. hmBS´>moOZ nam°ŠgmBS> h¡-
(A) an oxidising agent (A) Am°³grH$aU H$‘©H$
(B) a reducing agent (B) AnM¶Z H$‘©H$
(C) both an oxidising and a reducing agent (C) Am°³grH$aU H$‘©H$ VWm AnM¶Z H$‘©H$ XmoZmo
(D) neither oxidising nor reducing agent (D)  Z Vmo Am°³grH$aU H$‘©H$ Am¡a Z hr AnM¶Z
H$‘©H$

8-AA ] [ 22 ] [ Contd...

ss
ss
ss
096. By adding gypsum to cement
ss
096. gr‘oÝQ> ‘| {Oßg‘ {‘cmZo go- ss
(A) setting time of cement becomes less. (A) gr‘|Q> H$m AmÑ‹T>Z g‘¶ H$‘ hmo OmVm h¡& ss
(B) setting time of cement increases.
ss
(B) gr‘|Q> H$m AmÑ‹T>Z g‘¶ ~‹T> OmVm h¡& ss
(C) colour of cement becomes light. (C) gr‘|Q> H$m a§J hbH$m hmo OmVm h¡& ss
(D) shining surface is obtained
ss
(D) n¥îR> H$m a§J M‘H$Zo bJVm h¡& ss
ss
097. Dry ice is
ss
097. ewîH$ ~’©$ h¡- ss
(A) Solid NH3 (A) R>mog NH3
(B) Solid SO2 (B) R>mog SO2
(C) Solid CO2 (C) R>mog CO2
(D) Solid N2 (D) R>mog N2

098. Quartz is extensively used as a piezoelectric 098. ³dmQ>©µO H$m Xm~{dÚwV² ~ZmZo Ho$ {cE ~hþVm¶V ‘|
material, because it contains the following: Cn¶moJ hmoVm h¡ ³¶m|H$s Bg‘| {ZåZ{b{IV hmoVm h¡&
(A) Pb (B) Si (A) Pb (B) Si
(C) Ti (D) Sn (C) Ti (D) Sn

099. Which of the following gases is not a green 099. {ZåZ{cpIV ‘| go H$m¡Z-gr J¡g h[aVJ¥h J¡g Zht h¡?
house gas? (A) CO (B) O3
(A) CO (B) O3 (C) CH4 (D) H2O dmîn
(C) CH4 (D) H2O vapour

100. Sewage containing organic waste should 100. O¡d An{eï> ¶wŠV dm{hV‘c H$m {ZnQ>mZ Ocme¶m|
not be disposed in water bodies because it ‘| Zht {H$¶m OmZm Mm{hE Š¶m|{H$ Eogm H$aZo go
causes major water pollution. Fishes in such A˶{YH$ Oc àXÿfU CËnÝZ hmoVm h¡& Eogo àXÿ{fV
a polluted water die because of Oc ‘| ‘N>{c¶m| Ho$ ‘aZo H$m H$maU h¡-
(A) Large number of mosquitoes. (A) ~‹S>r g§»¶m ‘| ‘ÀN>a
(B) 
Increase in the amount of dissolved (B) Ob ‘| {dbrZ Am°³grOZ H$s ‘mÌm ‘| d¥X²{Y
oxygen. (C) Ob ‘| {dbrZ Am°³grOZ H$s ‘mÌm ‘| H$‘r
(C) 
Decrease in the amount of dissolved (D) H$sM‹S> Ûmam ‘N>br Ho$ {Jbm| H$m AdéX²Y hmo
oxygen in water. OmZm&
(D) Cloggingof gills by mud.

8-AA ] [ 23 ] [ P.T.O.

ss ss
ss ss
ss SPACE FOR ROUGH WORK / H$ÀMo H$m‘ Ho$ {b¶o OJh ss
ss ss
ss ss
ss ss
ss ss
ss ss
ss ss
ss ss
ss ss
ss ss
ss ss
ss ss

8-AA ] [ 24 ]