aglasem.com
Home Schools Admission Career Mock Test PDF Docs Playground
ClassChoose class
StateSelect state

Class 7 Maths Notes for Simple Equations

Download Class 7 Maths Notes for Simple Equations in PDF format. Access concise and easy-to-understand short notes for 7th Class from aglasem.com to help you excel in your studies. More Detail
Class 7 Maths Notes for Simple Equations - Page 1 of 8

Finished viewing? Save it for later —

Download Class 7 Maths Notes for Simple Equations (PDF · 8 pages)
Downloaded 76 times

About Class 7 Maths Notes for Simple Equations

Class 7 Maths Notes for Simple Equations is available here for free download. Published by AglaSem for Class 7, this notes can be viewed online or downloaded as a PDF (8 pages). Candidates preparing for Class 7 can use Class 7 Maths Notes for Simple Equations to understand the exam pattern, the type of questions asked, and the overall difficulty level.

Frequently Asked Questions

How can I download Class 7 Maths Notes for Simple Equations?

Open this page and click the Download button to save Class 7 Maths Notes for Simple Equations as a PDF. It is completely free on AglaSem Docs.

Is Class 7 Maths Notes for Simple Equations free to download?

Yes. Class 7 Maths Notes for Simple Equations can be viewed online and downloaded as a PDF free of cost on AglaSem Docs.

How many pages does Class 7 Maths Notes for Simple Equations have?

Class 7 Maths Notes for Simple Equations contains 8 pages, which you can read online or download together as a single PDF.

Where can I find more Class 7 study material?

You can find more Class 7 question papers, sample papers, syllabus, and answer keys on AglaSem Docs.

Class 7 Maths Notes for Simple Equations – Text

Read the full text of this notes below — useful to quickly search, copy and reference the content online without downloading the PDF.

📄 View text version (8 pages)

Page 1

NOTES

CLASS 7
MATHS

Study Material

DOWNLOAD PDF

Page 2

SIMPLE EQUATIONS
I. Important Concepts / Results
An equation is a condition on a variable. A variable is something that can vary. It assumes
different numerical values; its value is not fixed. These are usually denoted by letters of the
English alphabet, such as x, y, z, l, m, n, p, etc. From variables, we form expression by
performing operation like addition, subtraction, multiplication and division on them.

What Equation Is?
An equation is a condition on a variable. The condition is that two expressions should have equal
value. Note at least one of the two expressions must contain the variable.
An equation remains the same when the expressions on the left and on the right are interchanged.
This property is often useful in solving equations.

Solving an Equation
For any balanced numerical equation, if we either:

 add the same number to both sides,
 or subtract the same number from both sides,
 or multiply by the same number to both sides,
 or divide by the same number both its sides, the balance is undisturbed.

Examples

i) MCQ
1) Write the Simple equation of the statement ― The sum of three times x and 10 is 13‖
a) 3x + 10 = 13 b) 3x – 10 = 13 c) 3x + 13 = 10 d) None
Ans :- a) 3x + 10 = 13
2) Write the Simple equation of the statement ― Taking away 5 from x gives 10‖
a) x + 5 = 10 b) x – 10 = 5 c) x – 5 = 10 d) None
Ans: - c) x – 5 = 10
3) Write the Simple equation of the statement ― Add 1 to three times p to get 7‖
a) 1 + p = 7 b) 3 + p = 7 c) 7 + p = 3 d) 1 + 3p = 7
Ans: - d) 1 + 3p = 7
4) The solution of the equation x + 3 = 0 is
a) 3 b) - 3 c) 0 d) 1
Ans: - b) -3
5) The solution of the equation 7n + 5 = 12 is
a) 0 b) -1 c) 1 d) 5
Ans :c) 1

37

Page 3

ii) Case Study Based Questions:-
NUMBER GAME
1. I am a number. If you multiply me by 3 and subtract 2 from me, I become 10 more than
my double. What is my value?
(a) 4 (b) 8 (c) 10 (d) 12
Ans: d) 12
2. What minimum positive integral value must be added to the number obtained in question1 to
make it a perfect cube.
(a) 15 (b) 4 (c) 3 (d) 13
Ans: a) 15
3. If 6 is added, only to the right hand side of the equation obtained in question 1, will the value
of the number also increase by 6. Justify your answer.
Ans: - Yes, Justification: 3x-2=2x+10+6 ⇒x=18=12+6

Short Answer type Questions:-
1)Write the following statements in the form of equations:
(i) The sum of three times x and 11 is 32.
(ii) If you subtract 5 from 6 times a number, you get 7.
Solution:
(i) Three times x is 3x. Sum of 3x and 11 is 3x + 11. The sum is 32.
The equation is 3x + 11 = 32.
(ii) Let us say the number is z; z multiplied by 6 is 6z. Subtracting 5 from 6z, one gets 6z – 5.
The result is 7. The equation is 6z – 5
2) Convert the following equations in statement form: (i) x – 5 = 9 (ii) 5p = 20
Solution: (i) Taking away 5 from x gives 9.
(ii) Five times a number p is 20.
3) Solve : x + 5 = 7
Solution: add -5 on both sides, we get x + 5 – 5 = 7 – 5
X=2

Long Answer type Questions
1) Find a number, such that one-fourth of the number is 3 more than 7.
Solution :
y
Let us take the unknown number to be y; one-fourth of y is 4
y
This number 4 is more than 7 by 3.
y
Hence we get the equation for y as 4 – 7 = 3
y
To solve this equation, first transpose 7 to RHS We get, 4= 3 + 7 = 10.
We then multiply both sides of the equation by 4, to get
y
× 4 = 10 × 4 or y = 40 (the required number)
4

38

Page 4

2) Raju‘s father‘s age is 5 years more than three times Raju‘s age. Find Raju‘s age, if his father is
44 years old.
Solution :
The equation that gives Raju's age is 3y + 5 = 44
To solve it, we first transpose 5, to get 3y = 44 – 5 = 39
Dividing both sides by 3, we get y = 13
Hence Raju‘s age is 13 years.

III. Questions for Practice
i) MCQ
1. Write the following statement in the form of equation one eight of x is 5 more than 3.
(a) x/8 + 5 = 3(b) x/8 – 3 = 5(c) 3/x – 8 = 5(d) x/8 – 5 = 3
2. Add 9 to three times P to get 100.
(a) 3P + 9 = 100(b) 3P – 100 = 9(c) 3P + 100 = 9(d) 3P – 9 = 100
3. Shweta‘s mother‘s age is 7 years more than four times of shweta‘s age. Shweta‘s mother‘s age
is 55 years old. Set up an equation to find shweta‘s age.
(a) 4m +7 = 55(b) 4m – 7 = 55(c) 4m + 55 = 7(d) 4m – 55 = 7
4. he sum of three times x and 13 is 34.
(a) 3x – 13 = 34(b) 3x + 13(c) 3x – 34 = 3(d) 3x + 13 = 34
5. Choose the correct value of variable which satisfy following equation.
4n + 17 = 25
(a) 1(b) 2(c) 3(d) 4
6. Write the following equation in statement forms.7x + 8 = 53
(a) Seven times of x plus 8 gives 53(b) 8 times of y plus + 7 gives = 53
(c) Seven times of x plus 9 gives 63(d) 8 times of x minus 7 gives 53
7. Solve 3P – 6 = 18 and find the value of P?
(a) 4(b) 2(c) 8(d) 3
8. Solve m/5 + 20 = 45 find the value of m?
(a) m = 45(b) m = 20(c) m = 120(d) m = 125
9. Solve the following equation 2(x + 5) = 14
(a) 3(b) 4(c) 2(d) 1
10. Solve the equation x/7 + 20 = 34
(a) 98(b) 72(c) 84(d) 70

39

Page 5

ii) Short Answer Type Questions:-
1. Solve the following equation.
Add 6 to four times a number you get 62.
2. Solve the equation x/7 + 20 = 34
3. In an isosceles triangle, the base angle are equal. The vertex angle is 80°. What are the base
angles of the triangle?
4. If k + 7 = 10, find the value of 9k – 50.
5. If 5 is added to twice a number, the result is 29. Find the number.
6. Write the following statements in the form of equations.
One-fourth of a number is 2 more than 5.
7. Convert the following equations in statement form:
(a) 5x = 20
(b) 3y + 7 = 1
Long Answer type Questions:-
1. The sum of three consecutive multiples of 2 is 18. Find the numbers.
2. Each of the 2 equal sides of an isosceles triangle is twice as large as the third side. If the
perimeter of the triangle is 30 cm, find the length of each side of the triangle.
3. A man travelled two-fifth of his journey by train, one-third by bus, one-fourth by car and the
remaining 3 km on foot. What is the length of his total journey?
4. The length of a rectangle is twice its breadth. If its perimeter is 60 cm, find the length and the
breadth of the rectangle.
5. Solve 4(m + 3) = 18
6. Set up the equation and solve the following statement
5
Anwar thinks of a number. If he takes away 7 from2 of the number, the result is 23
Case Study Based Questions:-
1. BANANAS
A school was celebrating Republic day.On that day, school decided to give some refreshment to
the students after all the events. They decided to give 2 bananas per student. But, on the
celebration day, 300 students were absent. As a result, each student got 1 extra banana.
a) Find the minimum number of bananas school has to bring for total‗s‘
number of students.
b) Find total number of students in the school.
c) Suppose on that day 600 students were absent then how many extra
bananas will each student get?
d) School funded Rs3000 for the bananas. The cost of one banana is Rs2.
After some discount, seller got ready to give the minimum number of
bananas required by the school for Rs 3000. Find the cost of one banana.
2. SPORTS CLUB
Rajeev pays Rs225 in advance on his account at a sports club. Each time, he visits the club, Rs 9
is deducted from the account.
a) Which of the following equations represent the balance ―x‖ left in his account after ―t‖
number of days?

40

Page 6

(a) t=225+9x (b) x=9+225t (c) x=225-9t (d) t= 225-9x
b) How much balance (in Rs) is left in Rajeev‘s account after 20 visits?
(a) 54 (b) 45 (c) 36 (d) 60
c) After how many days, Rajeev have to recharge his account?
Answers for III. Questions for Practice
MCQ S.A L.A Case Study Based
Questions
1) b 1) 14 1) 4, 6, 8 1) a) 2x
2) a 2) 98 2) 6, 12, 12 b) 2x /(x-300)
3) a 3) 50 3) 180 km c) 4
4) d 4) k = -23 4) 10 , 20 d) 1.66 approx
5) b 5) 12 5) 3/2
6) a 6) ¼ x = 7 6) 23 2) a) c
7) c 7) (a) Five times a number x gives 20. b) b
(b) Add 7 to three times a number y gives 1.

8) d c) 25 days
9) c
10) a
Chapter Test Marks : 20
I Choose the correct answer:- 2 x 1 =2 marks
1. Add 9 to three times P to get 100.
(a) 3P + 9 = 100(b) 3P – 100 = 9(c) 3P + 100 = 9(d) 3P – 9 = 100
3. Shweta‘s mother‘s age is 7 years more than four times of shweta‘s age. Shweta‘s mother‘s age
is 55 years old. Set up an equation to find shweta‘s age.
(a) 4m +7 = 55(b) 4m – 7 = 55(c) 4m + 55 = 7(d) 4m – 55 = 7
II. Answer the following : 3 X 2 = 6 Marks
3. If k + 7 = 10, find the value of 9k – 50.
4. If 5 is added to twice a number, the result is 29. Find the number.
5. Write the following statements in the form of equations.
One-fourth of a number is 2 more than 5.
III. Answer the following:- 3 x 4 = 12 Marks
6. A man travelled two-fifth of his journey by train, one-third by bus, one-fourth by car and the
remaining 3 km on foot. What is the length of his total journey?
7. The length of a rectangle is twice its breadth. If its perimeter is 60 cm, find the length and the
breadth of the rectangle.
8. Solve 4(m + 3) = 18

41

Page 7

Chapter Test Marks : 30
I Choose the correct answer:- 4 x 1 =4 marks
1) ) Write the Simple equation of the statement ― The sum of three times x and 10 is 13‖
a) 3x + 10 = 13 b) 3x – 10 = 13 c) 3x + 13 = 10 d) None
2) Write the Simple equation of the statement ― Taking away 5 from x gives 10‖
a) x + 5 = 10 b) x – 10 = 5 c) x – 5 = 10 d) None
3) Write the Simple equation of the statement ― Add 1 to three times p to get 7‖
a) 1 + p = 7 b) 3 + p = 7 c) 7 + p = 3 d) 1 + 3p = 7
4) The solution of the equation x + 3 = 0 is
a) 3 b) - 3 c) 0 d) 1
II. Answer the following : 3 X 2 = 6 Marks
5. Solve the following equation.
Add 6 to four times a number you get 62.
6. Solve the equation x/7 + 20 = 34
7. In an isosceles triangle, the base angle are equal. The vertex angle is 80°. What are the base
angles of the triangle?
III. Answer the following:-3x 4 = 12Marks
8. The sum of three consecutive multiples of 2 is 18. Find the numbers.
9. Set up the equation and solve the following statement
5
Anwar thinks of a number. If he takes away 7 from2 of the number, the result is 23
10.Raju‘s father‘s age is 5 years more than three times Raju‘s age. Find Raju‘s age, if his father
is 44 years old.
Case Study Based Questions :- 2 x 4 = 8 marks
11. BANANAS
A school was celebrating Republic day.On that day, school decided to give some refreshment to
the students after all the events. They decided to give 2 bananas per student. But, on the
celebration day, 300 students were absent. As a result, each student got 1 extra banana.
a) Find the minimum number of bananas school has to bring for total‗s‘ number of students.
b) Find total number of students in the school.
c) Suppose on that day 600 students were absent then how many extra bananas will each student get?
d) School funded Rs3000 for the bananas. The cost of one banana is Rs2. After some discount,
seller got ready to give the minimum number of bananas required by the school for Rs 3000.
Find the cost of one banana.
12. SPORTS CLUB
Rajeev pays Rs225 in advance on his account at a sports club. Each time, he visits the club, Rs 9
is deducted from the account.
a) Which of the following equations represent the balance ―x‖ left in his account after ―t‖
number of days?
(a) t=225+9x (b) x=9+225t (c) x=225-9t (d) t= 225-9x
b) How much balance (in Rs) is left in Rajeev‘s account after 20 visits?
(a) 54 (b) 45 (c) 36 (d) 60
c) After how many days, Rajeev have to recharge his account?

42

Page 8

Study Materials
Notes

Model Papers Class 6 Notes

Sample Papers Class 7 Notes
Half Yearly Sample Papers Class 8 Notes

Class 9 Notes
Important Resources
Class 10 Notes
Periodic Table
Class 11 Notes
Writing Skills / Formats

Maps of India / World Class 12 Notes

Books and Solutions

NCERT Books
NCERT Book Solutions
HC Verma Chapter Wise Solutions
RD Sharma Solutions
CGBSE Solutions

Document Details

Board / OrgAglasem
ExamClass 7
TypeNotes
Pages8
Languageenglish
Updated24 Sep 2026