Page 1
SAMPLE PAPER SYLLABUS 2022-23 CLASS Total Questions : 50 PATTERN & MARKING SCHEME 6 Time : 1 hr. (1) Logical (2) Mathematical (3) Everyday (4) Achievers Section Reasoning Reasoning Mathematics Section SOF INTERNATIONAL No. of Questions 15 20 10 5 MATHEMATICS OLYMPIAD Marks per Ques. 1 1 1 3 SYLLABUS Section – 1 : Verbal and Non-Verbal Reasoning. Section – 2 : Knowing our Numbers, Whole Numbers, Playing with Numbers, Basic Geometrical Ideas, Understanding Elementary Shapes, Integers, Fractions, Decimals, Data Handling, Mensuration, Algebra, Ratio and Proportion, Symmetry, Practical Geometry. Section – 3 : Syllabus as per Section – 2. Section – 4 : Higher Order Thinking Questions - Syllabus as per Section – 2. LOGICAL REASONING 1. Find the next term in the series given below. (C) 14 3F, 6G, 11I, 18L, ? (D) 17 (A) 21O 3. How many dots lie opposite to the face having (B) 25N four dots, when the given net of cube is folded? (C) 27P (D) 27Q 2. Find the minimum number of straight lines required to draw the given figure. (A) 2 (B) 1 (A) 15 (C) 5 (B) 16 (D) 6 MATHEMATICAL REASONING 4. The given table shows the temperature of a city 5. To balance the scale, find the missing fraction. for 7 consecutive hours. 1 7 ? 18 112 Hour 1 2 3 4 5 6 7 Temperature 11 10 –6 15 –2 23 12 0 –4 (A) (B) (°C) 24 24 Calculate the difference between the highest 5 1 and the lowest temperature of the city over the (C) (D) 24 24 7 hour period. (A) 17°C 6. Evaluate : (B) 29°C – 1 + 55 – (– 29) + (– 1) – (– 82) + (– 3) (C) 21°C (A) 161 (B) – 161 (D) 25°C (C) 158 (D) – 158 Sample Paper | Class-6 | 1
Page 2
EVERYDAY MATHEMATICS 7. On a hill, the temperature at 8 p.m. was 2°C 8. Vishal jogged around a rectangular field but at the mid-night of the same day, it fell 4 times. If the rectangular field was 135 m long down to –3°C. By how many degrees did the and 78 m wide, then how far did Vishal jog? temperature fall? (A) 426 m (A) 6°C (B) 5°C (B) 852 m (C) 2°C (C) 1278 m (D) 3°C (D) 1704 m ACHIEVERS SECTION 9. Figure P is made up of six identical squares. P +Q Two squares were removed from figure 10. Find the value of . × S. R P to form figure Q. The perimeter of figure P (i) 100 lakhs = Q millions is 240 cm. What is the perimeter of figure Q? (ii) R crores = 100 millions (A) 220 cm (iii) 100 thousands = P lakhs (B) 180 cm (iv) 10 crores = S millions (C) 200 cm (A) 10 (B) 100 (D) 160 cm Figure P Figure Q (C) 110 (D) 1 SPACE FOR ROUGH WORK ANSWERS 1. (C) 2. (B) 3. (C) 4. (B) 5. (A) 6. (A) 7. (B) 8. (D) 9. (C) 10. (C) 2 | Sample Paper | Class-6