TBSE Class 10 Model Question Paper 2021 Maths Basic

Model Question
Class - X : Mathematics (Basic) : 80 Marks : 2020-2021
!Ó˲yàÈüÈܲ : ≤Ã!ï˛!ê˛ ≤Èϟ¿Ó˚ ÙylÈüÈ1 : 1 x 20 = 20
I) Choose the correct answer : 1x10
1. !mâyï˛ §Ù#ܲÓ˚î x – 4 = 0 ~Ó˚ Ó#çmÎ˚ •° û
2

a) 2, 2 (b) –2, 2 (c) –2, –2 (d) 2, 0
2. 2x – 3y = 5 §Ù#ܲÓ˚ˆÏî y ~Ó˚ Ùyl 3 •ˆÏ° x ~Ó˚ Ùyl •ˆÏÓ û
a) –7 (b) 14 (c) 7 (d) –14

3 1 1 3
3. , , − , − , ........ §Ùyhs˝Ó˚ ≤Ãà!ï˛Ó˚ §yôyÓ˚î xhs˝Ó˚ •° û
2 2 2 2

a) –1 (b) 2 (c) 1 (d) 4
4. Ù)° !Ó®% ˆÌˆÏܲ P (–6, 0) !Ó®%Ó˚ ò)Ó˚c •° Èû

a) 36 b) 3 (c) 6 (d) –6

5. Î!ò ~ܲ!ê˛ ˆày°ˆÏܲÓ˚ Óƒy§yô≈ r ˆ§!Ù •Î˚ñ ï˛ˆÏÓ ï˛yÓ˚ xyÎ˚ï˛l •ˆÏÓ û
4 3 3
(a) 4π r 3 ˆ§!Ù3 (b) π r ˆ§!Ù3 (c) 4π r 2 ˆ§!Ù3 (d) π r 3 ˆ§!Ù3
3 4
II) Answer the following quesitons : 1x5
6. ≤Ãò_ !ã˛ˆÏe AB •° Ó,ˆÏ_Ó˚ ~ܲ!ê˛ flõ¢≈ܲ O
~ÓÇ OB Óƒy§yô≈ñ ï˛y•ˆÏ° ∠ OBA ~Ó˚ Ùyl û.

A
7. cos 600 ~Ó˚ Ùyl •° û B

8.≤Ãò_ !ã˛ˆÏe DE || BC– Î!ò AE=1.8 ˆ§!Ùñ EC = 5.4 ˆ§!Ù •Î˚ñ ~ÓÇ BD=7.2 ˆ§!Ù •Î˚ ï˛ˆÏÓ AD=?
A
1.8 ˆ§!Ù

D E
7.2 ˆ§!Ù

B C
9. (0,0) ~ÓÇ Q (3, –6) !Ó®%ò%!ê˛Ó˚ §ÇˆÏÎyçܲ ˆÓ˚áyLjϢÓ˚ Ùôƒ!Ó®% •° _______.
10. !lˆÏ¡¨ ≤Ãò_ ˛õ!Ó˚§Çáƒy !Ó˲yçl!ê˛Ó˚ ˆ«˛ˆÏe

ˆ◊!î 0–5 5–10 10–15 15–20 20–25

˛õ!Ó˚§Çáƒy 8 10 19 25 8

§Çáƒyà%Ó˚% ˆ◊!îÓ˚ ˛í˛zôÁ≈§#Ùy •° ÈüÈ
III) Fill in the blanks :
11. Ó•%˛õò Ó˚y!¢Ùy°y ax2 – 2x ~ܲ!ê˛ ¢)lƒ 2 •ˆÏ° ‘a’ ˆÓ˚ Ùyl •ˆÏÓ _______–
12. Î!ò ∆ ABC ~Ó˚ xyÎ˚ï˛ˆÏ«˛e ¢)lƒ •Î˚ñ ï˛ˆÏÓ A , B ~ÓÇ C !Ó®%à%ˆÏ°y ____ •ˆÏÓ–
xÌÓy
(2, 3) ~ÓÇ (4, 1) !Ó®% ò%!ê˛Ó˚ ÙôƒÓï˛#≈ ò)Ó˚c •° ______–
13. Î!ò 6, x, 8 §Ùyhs˝Ó˚ ≤Ãà!ï˛ˆÏï˛ ÌyˆÏܲ ï˛ˆÏÓ x ~Ó˚ Ùyl •ˆÏÓ _____–
14. r Óƒy§yô≈ !Ó!¢T˛ Ó,ˆÏ_Ó˚ ˛õ!Ó˚!ô •° ______–
15. Î!ò cos A= sin 420 •Î˚ñ ï˛ˆÏÓ A ~Ó˚ Ùyl •° _____–
IV) Answer to the following questions
16. Ó•%˛õò Ó˚y!¢Ùy°y p(x) ~Ó˚ çlƒ y = p(x) ~Ó˚ ˆ°á!ã˛e l#ˆÏã˛ ˆòGÎ˚y xyˆÏSÈ– p(x) ~Ó˚ ¢)lƒ §Çáƒy !lî≈Î˚ ܲˆÏÓ˚y–
Y
→

X≈ → → X
→

Y≈
17. 140 §Çáƒy!ê˛ˆÏܲ ˆÙÔ!°Ü˛ í˛zͲõyòˆÏܲÓ˚ à%îÊ˛ˆÏ° ≤Ãܲy¢ ܲˆÏÓ˚y–
18. ~ܲ!ê˛ ¢AÜ%˛Ó˚ Óƒy§yô≈ 3 ˆ§!Ù ~ÓÇ í˛zFã˛ï˛y 7ˆ§!Ù– ~!ê˛Ó˚ xyÎ˚ï˛l !lî≈Î˚ܲˆÏÓ˚y–
D xÌÓy
Î!ò ~ܲ!ê˛ xô≈ ˆày°ˆÏܲÓ˚ Óƒy§yô≈ 2.1 ˆ§!Ù •Î˚ñ ï˛ˆÏÓ ~!ê˛Ó˚ xyÎ˚ï˛l !lî≈Î˚ ܲˆÏÓ˚y–
19. ≤Ãò_ !ã˛ˆÏe ∆ODC ∼ ∆OBA, ∠BOC = 1250 ~ÓÇ ∠CDO = 700 .
∠OAB !lî≈Î˚ ܲˆÏÓ˚y– →D C →
0
70

O 1250

→ →
20. ˛Î!ò P (E) = 1/3 •Î˚ñ ï˛ˆÏÓ ‘E lÎ˚Û ~Ó˚ §Ω˛yÓly Ü˛ï˛ ⁄ A B

!Ó˲yàÈüÈá : Each Question Carries 2 marks : 2x6=12
21. k ~Ó˚ ˆÏܲyl ÙyˆÏlÓ˚ çlƒ x–3y=7 ~ÓÇ kx+6y=5 ~Ó˚ § Ùyôyl ÌyˆÏܲ ly–
22. !mâyï˛ Ó•%˛õò Ó˚y!¢Ùy°y!ê˛ !lî≈Î˚ ܲˆÏÓ˚y ÎyÓ˚ ¢)lƒà)ˆÏ°yÓ˚ ˆÎyàÊ˛° G à%îÊ˛° ÎÌyܲˆÏÙ 6 ~ÓÇ –2–
D xÌÓy
p(x) = x2+x+1 ~Ó˚ Ùyl !lî≈Î˚ ܲˆÏÓ˚yñ Îál x = –1.
23. ≤Ãò_ !ã˛ˆÏeñ Ë)˛!ÙÓ˚ í˛z˛õÓ˚ ~ܲ!ê˛ !Ó®% B ˆÌˆÏܲ ~ܲ!ê˛ !ÙlyÓ˚ AC ~Ó˚ í˛zߨ!ï˛ ˆÜ˛yî 600, Î!ò !ÙlyÓ˚!ê˛Ó˚ í˛zFã˛ï˛y 20!Ùê˛yÓ˚ •Î˚
ï˛ˆÏÓ !ÙlyˆÏÓ˚Ó˚ ˛õyòˆÏò¢ ˆÌˆÏܲ !Ó®%!ê˛Ó˚ ò)Ó˚c !lî≈Î˚ ܲˆÏÓ˚y–

C

20 !Ù

A 600 (
B

24. ~ܲ!ê˛ °%ˆÏí˛yÓ˚ SÈE˛y ~ܲÓyÓ˚ !lˆÏ«˛˛õ ܲÓ˚y •°– ï˛y•ˆÏ° (i) ~ܲ!ê˛ ˆÙÔ!°Ü˛ §Çáƒy (ii) ~ܲ!ê˛ xÎ%@¬ §Çáƒy ˛õyGÎ˚yÓ˚ §Ω˛yÓly
!lî≈Î˚ ܲˆÏÓ˚y–
D xÌÓy
ò%!ê˛ Ù%oy ~ܲ§yˆÏÌ ê˛§‰ ܲÓ˚y •°– ï˛y•ˆÏ° (i) Ü˛Ù˛õˆÏ«˛ ~ܲ!ê˛ ˆ•í‰˛ (ii) ~ܲ!ê˛G ˆ•í‰˛ ly ˛õyGÎ˚yÓ˚ §Ω˛yÓly ܲï˛⁄

25. 17, 23 ~ÓÇ 29 ~Ó˚ ° §y à% !lî≈Î˚ ܲˆÏÓ˚y–

26. Î!ò tan A = cot B •Î˚ñ ï˛ˆÏÓñ ≤ÃÙyÙ Ü˛ˆÏÓ˚y ˆÎ A + B = 900.

!Ó˲yàÈüÈà : Each Question Carries 3 Marks : 3x8=24
27. Î!ò ~ܲ!ê˛ §Ùyhs˝Ó˚ ≤Ãà!ï˛Ó˚ ï,˛ï˛#Î˚ ~ÓÇ lÓÙ ˛õò ÎÌyܲˆÏÙ 4 ~ÓÇ –8 •Î˚ñ ï˛ˆÏÓ ~•z §Ùyhs˝Ó˚ ≤Ãà!ï˛Ó˚ ˆÜ˛yl ˛õò!ê˛ ¢)lƒ⁄
28. (–4, –2), (–3,–5) G (3,–2) !Ó®%à%ˆÏ°y ܲÙyß∫ˆÏÎ˚ Î%=˛ ܲˆÏÓ˚ ˆÎ !eË%˛ç!ê˛ ˛õyGÎ˚y ÎyÎ˚ ï˛yÓ˚ ˆ«˛eÊ˛° !lî≈Î˚ ܲˆÏÓ˚y–

29. Ùyl !lî≈Î˚ ܲˆÏÓ˚y Èü/ 5 cos2600 + 4 sec2300 – tan2450
D xÌÓy
7 (1 + sin θ )(1 − sin θ )
Î!ò cot θ = •Î˚ñ ï˛ˆÏÓñ (1 + cos θ )(1 − cos θ ) ~Ó˚ Ùyl !lî≈Î˚ ܲˆÏÓ˚y–
8

30. ~ܲ!ê˛ Ó,_yܲyÓ˚ Ùyë˛ˆÏܲ ˆÓí˛¸y !òˆÏÎ˚ !âÓ˚ˆÏï˛ ≤Ã!ï˛ !Ùê˛yˆÏÓ˚ 24 ê˛yܲy !•ˆÏ§ˆÏÓ 5280 ê˛yܲy áÓ˚ã˛ •Î˚– Ùyë˛!ê˛ˆÏܲ ã˛y£Ï ܲÓ˚ˆÏï˛ ≤Ã!ï˛
22
Óà≈!Ùê˛yˆÏÓ˚ 0.50 ê˛yܲy ܲˆÏÓ˚ áÓ˚ã˛ •Î˚– Ùyë˛!ê˛ˆÏܲ ã˛y£Ï ܲÓ˚ˆÏï˛ ˆÙyê˛ Ü˛ï˛ áÓ˚ã˛ •ˆÏÓ⁄ ( π = ôˆÏÓ˚y ä–
7
D xÌÓy
~ܲ!ê˛ ày!í˛¸Ó˚ ≤Ã!ï˛!ê˛ ã˛yܲyÓ˚ Óƒy§ 80ˆ§!Ù– Î!ò ày!í˛¸!ê˛Ó˚ à!ï˛ˆÏÓà ârê˛yÎ˚ 66 !ܲ!Ù •Î˚ñ ï˛ˆÏÓ 10 !Ù!lê˛ §ÙˆÏÎ˚ ày!í˛¸Ó˚ ≤Ã!ï˛!ê˛ ã˛yܲy
ܲï˛ÓyÓ˚ ˛õ)î≈ xyÓï≈˛l §¡õߨ ܲÓ˚ˆÏÓ⁄

31. §Ùyôyl ܲˆÏÓ˚y / 100x2 – 20x +1 =0
D xÌÓy
1
x+ = 3, x=0
x

32. •zLjÏÓ˚!ç Óî≈Ùy°y ˆÌˆÏܲ ΈÏÌFSÈ˲yˆÏÓ ~ܲ!ê˛ Óî≈≈ !lÓ≈yã˛l ܲÓ˚y •°– ~!ê˛ ~ܲ!ê˛ fl∫Ó˚Óî≈ •GÎ˚yÓ˚ §Ω˛yÓly Ü˛ï˛ ⁄

!Ó˲yàÈüÈâ

33. ≤ÃÙyî ܲˆÏÓ˚y ˆÎ 3 ~ܲ!ê˛ xÙ)°ò §Çáƒy–
34. Ë)˛!ÙÓ˚ í˛z˛õÓ˚ ˆÜ˛yˆÏly ~ܲ!ê˛ !Ó®% (P) ˆÌˆÏܲ 20 !Ùê˛yÓ˚ í˛zÑã%˛ ~ܲ!ê˛ Óy!í˛¸Ó˚ (BC) í˛z˛õÓ˚ òu˛yÎ˚Ùyl ~ܲ!ê˛ §¡±ã˛yÓ˚ !ÙlyˆÏÓ˚Ó˚
˛õyòˆÏò¢ (B) G ¢#ˆÏ£Ï≈Ó˚ (A) í˛zߨ!ï˛ ˆÜ˛yî ÎÌyܲˆÏÙ 450 ~ÓÇ 600– !ÙlyˆÏÓ˚Ó˚ í˛zFã˛ï˛y !lî≈Î˚ ܲˆÏÓ˚y–
A

B

20m
)
) 450 60
0
C
P

!Ó˲yàÈüÈâ : Each Question Carries 4 Marks : 4x6=24

35. §Ùyôyl ܲˆÏÓ˚y / 3x + 4y = 10
2x – 2y = 3

xÌÓy
5 3
− =2
x y
7 4
− =3
x y

36. ≤ÃÙyî ܲˆÏÓ˚y ˆÎñ ˆÜ˛yˆÏly §ÙˆÏܲyî# !eË%˛ˆÏçÓ˚ x!ï˛Ë)˛ˆÏçÓ˚ Óà≈ ~!ê˛Ó˚ x˛õÓ˚ ò%!ê˛ Óy•%Ó˚ ÓˆÏà≈Ó˚ §Ù!T˛Ó˚ §Ùyl •Î˚–

37. 6 ˆ§!Ù Óƒy§yô≈ !Ó!¢T˛ ~ܲ!ê˛ Ó,_ xAܲl ܲˆÏÓ˚y– Ó,ˆÏ_Ó˚ ˆÜ˛w ˆÌˆÏܲ 10 ˆ§!Ù ò)Ó˚Óï˛#≈ ~ܲ!ê˛ !Ó®% ˆÌˆÏܲ Ó,_!ê˛Ó˚ í˛z˛õÓ˚
flõ¢≈ܲmÎ˚ xAܲl ܲˆÏÓ˚y– å¢%ô%Ùye xAܲl ≤Ãîy°# !°áˆÏÓñ ≤ÃÙyî !òˆÏï˛ •ˆÏÓ ly– xAܲl !ã˛•´à%ˆÏ°y §%flõT˛ •ˆÏï˛ •ˆÏÓ–ä

38. ≤ÃÙyî ܲˆÏÓ˚y ˆÎñ Ó!•ıfiÌ ˆÜ˛yˆÏly !Ó®% ˆÌˆÏܲ Ó,ˆÏ_Ó˚ í˛z˛õÓ˚ x!AÜ˛ï˛ flõ¢≈ܲà%ˆÏ°yÓ˚ ˜òâ≈ƒ §Ùyl ~ÓÇ ï˛yÓ˚y ˆÜ˛ˆÏw §Ùyl ˆÜ˛yî
í˛zͲõߨ ܲˆÏÓ˚–

D xÌÓy

≤ÃÙyî ܲˆÏÓ˚y ˆÎñ Ó!•ıfiÌ ˆÜ˛yˆÏly !Ó®% ˆÌˆÏܲ Ó,ˆÏ_Ó˚ í˛z˛õÓ˚ x!AÜ˛ï˛ flõ¢≈ܲ ò%!ê˛Ó˚ ÙôƒÓï˛#≈ ˆÜ˛yîñ flõ¢≈!Ó®% ~ÓÇ ˆÜ˛ˆÏwÓ˚ §ÇˆÏÎyçܲ
ˆÓ˚áyLjϢÓ˚ ÙôƒÓï˛#≈ ˆÜ˛yˆÏîÓ˚ §¡õ)Ó˚ܲ–

39. ~ܲ!ê˛ Å£ÏˆÏôÓ˚ ܲƒy˛õ§%° ˆã˛y.yÜ,˛!ï˛ñ ÎyÓ˚ ≤Ã!ï˛!ê˛ ≤ÃyˆÏhs˝ ~ܲ!ê˛ xô≈ˆÏày°Ü˛ xyê˛Ü˛yˆÏly xyˆÏSÈ å!ã˛e ˆòˆÏáyä– Ü˛ƒy˛õ§%°!ê˛Ó˚ ˆÙyê˛
˜ò⃠14 !Ù!Ù ~ÓÇ Óƒy§ 5!Ù!Ù – ~!ê˛Ó˚ ˛õ,¤˛ï˛ˆÏ°Ó˚ ˆ«˛eÊ˛° !lî≈Î˚ ܲˆÏÓ˚y–

5 mm

14 mm

40. !lˆÏã˛Ó˚ ˛õ!Ó˚§Çáƒy !Ó˲yçˆÏlÓ˚ ÙôƒÙy !lî≈Î˚ ܲˆÏÓ˚y û
í˛zFã˛ï˛y 刧!ÙÈä 160–162 163–165 166–168 169–171 172–174

˛õ!Ó˚§Çáƒy 15 117 136 118 14

D xÌÓy
l#ˆÏã˛Ó˚ ˛õ!Ó˚§Çáƒy !Ó˲yçl §yÓ˚î#Ó˚ àí˛¸Ùyl 62.8 •ˆÏ° x ~Ó˚ Ùyl !lî≈Î˚ ܲÓ˚–

ˆ◊!î ˛õ!Ó˚§Çáƒy

0–20 5

20–40 8

40–60 x

60–80 12

80–100 7

100–120 8

˛D x!ï˛!Ó˚=˛ ≤ß¿Ó°#

Model Question
Class - X : Mathematics (Basic) : 80 Marks : 2020-2021
ÈSection- A : Each Question Carries 1 Mark : 1 x 20 = 20
I) Choose the correct answer : 1x5
1. The two roots of the quadratic equation x2 – 4 = 0 are
a) 2, 2 (b) –2, 2 (c) –2, –2 (d) 2, 0
2. In the equation 2x – 3y = 5 if the value of y is 3 then the value of x is
a) –7 (b) 14 (c) 7 (d) –14
3 1 1 3
3. In the AP : , , − , − , ........ the common difference is
2 2 2 2
a) –1 (b) 2 (c) 1 (d) 4
4. The distance of the point˛ P (–6, 0) from the origin is
a) 36 b) 3 (c) 6 (d) –6
5. If the radius of a sphere is 3cm, then its volume is
4 3 3 3
(a) 4π r 3 cm3 (b) π r cm (c) 4π r 2 cm3 (d) π r 3 cm3
3 4
II) Answer the following questions : 1x5
6. In the given figure AB is a tangent to the circle and O
OB is the radius, then Find ∠ OBA .
A
B
7. The value of cos 600

8. In the given figure DE || BC, If AE=1.8 cmñ EC = 5.4 cm, and BD=7.2 then AD=?
A
1.8cm
D E
7.2cm 5.4cm

A C

9. The mid-point of the line segment joining (0,0) and (3, –6) is _______.

10. For the following frequency distribution

Class 0–5 5–10 10–15 15–20 20–25

Frequency 8 10 19 25 8

The upper limit of mode class is ______.

III) Fill in the Blanks : 1x5
11. If 2 is a zero of the polynomial ax2 – 2x , then the value of ‘a’ is _____.
12. If area of ∆ ABC is zero, then the points A , B and C are ______.
* OR
The distance between the point (a,b) and (–a, –b) is equal to _____.
13. If 6, x, 8 are in A.P. then x is equal to _____.
14. Perimeter of a circle with radius r is _____.
15. If cos A= sin 420 , then the value of A is ______.
IV) Answer to the following questions : 1x5
16. The graph y = p(x) is given below for the polynomial p(x) . Find the number of zeros of p(x).
Y
→

X≈ → → X
→

Y≈
17. Express the number 140 as a product of its prime factors.
18. The radius of a cone is 3cm and height is 7cm. Find its volume.
OR
If the radius of a hemisphere is 2.1cm, then find its volume.
19. In the given figure ∆ODC ∼ ∆OBA, ∠BOC = 1250 and ∠CDO = 700 .
Find ∠OAB . C
→D →
700

O 1250

20. ˛If P (E) = 1/3 , What is the probability of ‘not E’ ⁄ → →
A B
Section- B : Each Question Carries 2 marks : 2x6=12

21. For what value of k, x–3y=7 and kx+6y=5 will have no solution.
22. Find the quadratic polynomial whose sum and product of zeros are 6 and –2 respectively.
OR
Find the value of p(x) = x2+x+1 when x = –1.
23. In the given figure, the angle of elevation of the top of a tower AC from a point B on the ground is
600. If the height of the tower is 20m, find the distance of the point from the foot of the tower.

C

20 m

A 600 (
B

24. A die is thrown once. Find the probability of getting (i) a prime number (ii) an odd number.
* OR
Two coins are tossed simaltaneously. What is the probability of getting (i) at lest one head (ii) no head?

25. Find the L.C.M of 17, 23 and 29 .

26. If tan A = cot B, Prove that A + B = 900.

Section-C : Each Question Carries 3 Marks : 3x8=24

27. If the 3rd and the 9th terms of an AP are 4 and –8 respectively, which term of this AP is zero ?
28. Find the area of the triangle whose vertices, taken in order are (–4, –2), (–3,–5) & (3,–2) .

29. Evaluate Èü/ 5 cos2600 + 4 sec2300 – tan2450
* OR
7 (1 + sin θ )(1 − sin θ )
If cot θ = then evaluate .
8 (1 + cos θ )(1 − cos θ )

30. The cost of fencing a circular field at the rate of Rs. 24 per metre is Rs. 5280. The field is ploughed
22
at the rate of Rs. 0.50 per m2. Find the cost of ploughing the field. ( take π = ä–
7
* OR
The wheels of a car are of diameter 80 cm each. How many complete revolutions does each wheel
make in 10 minutes when the car is travelling at a speed of 66 km per hour ?

31. Solve / 100x2 – 20x +1 =0
* OR

1
x+ = 3, x ≠ 0
x

32. A letter is selected at random frm the set of English alphabets. What is the probability that it is a
vowel ?

33. Prove that 3 is an irrational number.
34. From a point (P) on the ground, the angles of elevation of the bottom (B) and the top (A) of a
transmission tower fined at the top of a 20m high building (BC) are 450 and 600 respectively. Find the
height of the tower.
A

B

20m
)
) 450 60
0
C
P

Section-D : Each Question Carries 4 Marks : 4x6=24

35. Solve / 3x + 4y = 10
2x – 2y = 3

* OR
5 3
− =2
x y
7 4
− =3
x y

36. Prove that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the
other two sides.

37.Draw a circle of radius 6cm. From a point 10 cm away from its centre, construct the pair of tangents
to the circle. (Write only the constructional procedure but no proof in to be given. Traces of construc-
tion must be clear).

38. Prove that the lengths of tengents drawn from an external point to a circle are equal and they
subtend equal angles at the centre.

* OR

Prove that the angle between the two tangents drawn from an external point to a circle is supplemen-
tary to the angle subtended by the line-segment joining the points of contact at the centre.

39. A medicine capsule is in the shape of a cylinder with two hemispheres stuck to each of its ends (see
figure). The length of the entire capsule is 14 mm and the diameter of the capsule is 5mm. Find its
surface area.

5 mm

14 mm

40. Find the median for the following frequency distribution :
Height (in cm) 160–162 163–165 166–168 169–171 172–174

˛Frequency 15 117 136 118 14

* OR
The mean of the following distribution is 62.8. Find the value of x.

Class Frequency

0–20 5

20–40 8

40–60 x

60–80 12

80–100 7

100–120 8

* Additional Questions