DUET Question Paper 2019 for Ph.D Informatics
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DUET Question Paper 2019 for Ph.D Informatics – Text
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Page 1
DU PhD in informa cs IIC
Topic:- DU_J19_PHD_INFO
1) If the differential voltage gain and the common mode voltage gain of a differential amplifier are 48dB and
2dB respectively, then its common rejection ratio is [Question ID = 25541]
1. 23dB [Option ID = 42159]
2. 46dB [Option ID = 42162]
3. 50dB [Option ID = 42161]
4. 25dB [Option ID = 42160]
23dB [Option ID = 42159]
2) A video transmission system transmits 625 picture frames per second. Each frame consists of a 400×400
pixel grid with 64 intensity levels per pixel. The data rate of the system is [Question ID = 25555]
1. 600Mbps [Option ID = 42218]
2. 6.4Gbps [Option ID = 42216]
3. 100Mbps [Option ID = 42217]
4. 16Mbps [Option ID = 42215]
16Mbps [Option ID = 42215]
3) The minimum number of comparators required to build an 8-bit flash ADC is [Question ID = 25550]
1. 256 [Option ID = 42198]
2. 255 [Option ID = 42197]
3. 8 [Option ID = 42195]
4. 63 [Option ID = 42196]
8 [Option ID = 42195]
4) The minimum number of MOS transistors required to make a dynamic RAM cell is [Question ID = 25549]
1. 2 [Option ID = 42192]
2. 1 [Option ID = 42191]
3. 3 [Option ID = 42193]
4. 4 [Option ID = 42194]
1 [Option ID = 42191]
x y z
5) Two 2’s complement numbers having signs bits and are added and the sign bit of the result is . Then,
the occurrence of overflow is indicated by the Boolean function
[Question ID = 25545]
1. [Option ID = 42175]
2. [Option ID = 42178]
3. [Option ID = 42176]
4. [Option ID = 42177]
Topic:- DU_J19_PHD_INFO
1) If the differential voltage gain and the common mode voltage gain of a differential amplifier are 48dB and
2dB respectively, then its common rejection ratio is [Question ID = 25541]
1. 23dB [Option ID = 42159]
2. 46dB [Option ID = 42162]
3. 50dB [Option ID = 42161]
4. 25dB [Option ID = 42160]
23dB [Option ID = 42159]
2) A video transmission system transmits 625 picture frames per second. Each frame consists of a 400×400
pixel grid with 64 intensity levels per pixel. The data rate of the system is [Question ID = 25555]
1. 600Mbps [Option ID = 42218]
2. 6.4Gbps [Option ID = 42216]
3. 100Mbps [Option ID = 42217]
4. 16Mbps [Option ID = 42215]
16Mbps [Option ID = 42215]
3) The minimum number of comparators required to build an 8-bit flash ADC is [Question ID = 25550]
1. 256 [Option ID = 42198]
2. 255 [Option ID = 42197]
3. 8 [Option ID = 42195]
4. 63 [Option ID = 42196]
8 [Option ID = 42195]
4) The minimum number of MOS transistors required to make a dynamic RAM cell is [Question ID = 25549]
1. 2 [Option ID = 42192]
2. 1 [Option ID = 42191]
3. 3 [Option ID = 42193]
4. 4 [Option ID = 42194]
1 [Option ID = 42191]
x y z
5) Two 2’s complement numbers having signs bits and are added and the sign bit of the result is . Then,
the occurrence of overflow is indicated by the Boolean function
[Question ID = 25545]
1. [Option ID = 42175]
2. [Option ID = 42178]
3. [Option ID = 42176]
4. [Option ID = 42177]
Page 2
[Option ID = 42175]
6) A 0 and 6 counter consists of 3 flip flops and a combination circuit of 2 input gate(s). The combination
circuit consists of [Question ID = 25547]
1. one OR gate [Option ID = 42184]
2. two AND gate [Option ID = 42186]
3. one AND gate and one OR gate [Option ID = 42185]
4. one AND gate [Option ID = 42183]
one AND gate [Option ID = 42183]
7) X=01110 and Y=11001 are two 5-bit binary numbers represented in two’s complement format. The sum of
X and Y represented in two’s complement format using 6 bits is
[Question ID = 25543]
1. 001000 [Option ID = 42168]
2. 100111 [Option ID = 42167]
3. 101001 [Option ID = 42170]
4. 000111 [Option ID = 42169]
100111 [Option ID = 42167]
8) In an M/M/1 queue for arrival rate λ and service rate μ, the average number of customer in the system is
given by [Question ID = 25572]
1. [Option ID = 42286]
2. [Option ID = 42284]
3. [Option ID = 42285]
4. [Option ID = 42283]
[Option ID = 42283]
9) The depth of penetration of electromagnetic wave in a medium having conductivity σ at a frequency of
1MHz cm
is 25 . The depth of penetration at a frequency of 4 MHz
will be [Question ID = 25528]
1. 12.50 cm [Option ID = 42109]
2. 6.25 cm [Option ID = 42107]
3. 50.0 cm [Option ID = 42108]
4. 100.0 cm [Option ID = 42110]
cm [Option ID = 42107]
6.25
10) Three identical amplifiers with each one having a voltage gain of 50, input resistance of 1kΩ and output
resistance of 250Ω, are cascaded. The open circuit voltage gain of the combined amplifier is [Question ID =
25542]
1. 98dB [Option ID = 42164]
2. 102dB [Option ID = 42166]
3. 51dB [Option ID = 42165]
6) A 0 and 6 counter consists of 3 flip flops and a combination circuit of 2 input gate(s). The combination
circuit consists of [Question ID = 25547]
1. one OR gate [Option ID = 42184]
2. two AND gate [Option ID = 42186]
3. one AND gate and one OR gate [Option ID = 42185]
4. one AND gate [Option ID = 42183]
one AND gate [Option ID = 42183]
7) X=01110 and Y=11001 are two 5-bit binary numbers represented in two’s complement format. The sum of
X and Y represented in two’s complement format using 6 bits is
[Question ID = 25543]
1. 001000 [Option ID = 42168]
2. 100111 [Option ID = 42167]
3. 101001 [Option ID = 42170]
4. 000111 [Option ID = 42169]
100111 [Option ID = 42167]
8) In an M/M/1 queue for arrival rate λ and service rate μ, the average number of customer in the system is
given by [Question ID = 25572]
1. [Option ID = 42286]
2. [Option ID = 42284]
3. [Option ID = 42285]
4. [Option ID = 42283]
[Option ID = 42283]
9) The depth of penetration of electromagnetic wave in a medium having conductivity σ at a frequency of
1MHz cm
is 25 . The depth of penetration at a frequency of 4 MHz
will be [Question ID = 25528]
1. 12.50 cm [Option ID = 42109]
2. 6.25 cm [Option ID = 42107]
3. 50.0 cm [Option ID = 42108]
4. 100.0 cm [Option ID = 42110]
cm [Option ID = 42107]
6.25
10) Three identical amplifiers with each one having a voltage gain of 50, input resistance of 1kΩ and output
resistance of 250Ω, are cascaded. The open circuit voltage gain of the combined amplifier is [Question ID =
25542]
1. 98dB [Option ID = 42164]
2. 102dB [Option ID = 42166]
3. 51dB [Option ID = 42165]
Page 3
4. 49dB [Option ID = 42163]
49dB [Option ID = 42163]
11) A master-slave flip-flop has the characteristic that [Question ID = 25548]
1. change in the output occurs when the state of the slave is affected. [Option ID = 42189]
2. change in the output occurs when the state of the master is affected. [Option ID = 42188]
3. change in the input immediately reflected in the output [Option ID = 42187]
4. both the master and the slave states are affected at the same time. [Option ID = 42190]
change in the input immediately reflected in the output [Option ID = 42187]
12) For an energy state E of a photon gas , the density of states is proportional to [Question ID = 25536]
1. [Option ID = 42141]
2. [Option ID = 42140]
3. [Option ID = 42139]
4. [Option ID = 42142]
[Option ID = 42139]
13) The equation of motion of a bead sliding on a uniform rod rotating in a force free space is [Question ID =
25525]
1. [Option ID = 42095]
2. [Option ID = 42098]
3. [Option ID = 42096]
4. [Option ID = 42097]
[Option ID = 42095]
14) The line code that has zero dc component for pulse transmission of random binary data is [Question ID =
25554]
1. alternate mark inversion (AMI) [Option ID = 42213]
2. non-return to zero (NRZ) [Option ID = 42211]
3. return to zero(RZ) [Option ID = 42212]
4. none of these [Option ID = 42214]
non-return to zero (NRZ) [Option ID = 42211]
15)
49dB [Option ID = 42163]
11) A master-slave flip-flop has the characteristic that [Question ID = 25548]
1. change in the output occurs when the state of the slave is affected. [Option ID = 42189]
2. change in the output occurs when the state of the master is affected. [Option ID = 42188]
3. change in the input immediately reflected in the output [Option ID = 42187]
4. both the master and the slave states are affected at the same time. [Option ID = 42190]
change in the input immediately reflected in the output [Option ID = 42187]
12) For an energy state E of a photon gas , the density of states is proportional to [Question ID = 25536]
1. [Option ID = 42141]
2. [Option ID = 42140]
3. [Option ID = 42139]
4. [Option ID = 42142]
[Option ID = 42139]
13) The equation of motion of a bead sliding on a uniform rod rotating in a force free space is [Question ID =
25525]
1. [Option ID = 42095]
2. [Option ID = 42098]
3. [Option ID = 42096]
4. [Option ID = 42097]
[Option ID = 42095]
14) The line code that has zero dc component for pulse transmission of random binary data is [Question ID =
25554]
1. alternate mark inversion (AMI) [Option ID = 42213]
2. non-return to zero (NRZ) [Option ID = 42211]
3. return to zero(RZ) [Option ID = 42212]
4. none of these [Option ID = 42214]
non-return to zero (NRZ) [Option ID = 42211]
15)
Page 4
[Question ID = 25565]
1. [Option ID = 42257]
2. [Option ID = 42256]
3. [Option ID = 42258]
4. [Option ID = 42255]
[Option ID = 42255]
16)
[Question ID = 25561]
1. 0.3, -2.5, 0.5 [Option ID = 42239]
2. 4.0, 3.0, 2.0 [Option ID = 42242]
3. 0.0, 3.0, 2.0 [Option ID = 42240]
4. 0.3, 0.33, 0.5 [Option ID = 42241]
0.3, -2.5, 0.5 [Option ID = 42239]
17)
[Question ID = 25568]
1. [Option ID = 42267]
2. [Option ID = 42269]
3. [Option ID = 42268]
4. [Option ID = 42270]
[Option ID = 42267]
18)
1. [Option ID = 42257]
2. [Option ID = 42256]
3. [Option ID = 42258]
4. [Option ID = 42255]
[Option ID = 42255]
16)
[Question ID = 25561]
1. 0.3, -2.5, 0.5 [Option ID = 42239]
2. 4.0, 3.0, 2.0 [Option ID = 42242]
3. 0.0, 3.0, 2.0 [Option ID = 42240]
4. 0.3, 0.33, 0.5 [Option ID = 42241]
0.3, -2.5, 0.5 [Option ID = 42239]
17)
[Question ID = 25568]
1. [Option ID = 42267]
2. [Option ID = 42269]
3. [Option ID = 42268]
4. [Option ID = 42270]
[Option ID = 42267]
18)
Page 5
[Question ID = 25567]
1. [Option ID = 42266]
2. [Option ID = 42265]
3. [Option ID = 42264]
4. [Option ID = 42263]
[Option ID = 42263]
19)
[Question ID = 25559]
1. [Option ID = 42232]
2. [Option ID = 42231]
3. [Option ID = 42233]
4. [Option ID = 42234]
[Option ID = 42231]
20)
[Question ID = 25531]
1. [Option ID = 42120]
2. [Option ID = 42122]
3. [Option ID = 42121]
4. [Option ID = 42119]
1. [Option ID = 42266]
2. [Option ID = 42265]
3. [Option ID = 42264]
4. [Option ID = 42263]
[Option ID = 42263]
19)
[Question ID = 25559]
1. [Option ID = 42232]
2. [Option ID = 42231]
3. [Option ID = 42233]
4. [Option ID = 42234]
[Option ID = 42231]
20)
[Question ID = 25531]
1. [Option ID = 42120]
2. [Option ID = 42122]
3. [Option ID = 42121]
4. [Option ID = 42119]
Page 6
[Option ID = 42119]
21)
[Question ID = 25537]
1. 0.51MeV [Option ID = 42143]
2. 1.04MeV [Option ID = 42144]
3. 7.17MeV [Option ID = 42146]
4. 2.08NeV [Option ID = 42145]
0.51MeV [Option ID = 42143]
22)
[Question ID = 25540]
1. [Option ID = 42157]
2. [Option ID = 42155]
3. [Option ID = 42158]
4. [Option ID = 42156]
[Option ID = 42155]
23)
[Question ID = 25535]
1. [Option ID = 42135]
2. [Option ID = 42138]
3. [Option ID = 42137]
4. [Option ID = 42136]
[Option ID = 42135]
24)
21)
[Question ID = 25537]
1. 0.51MeV [Option ID = 42143]
2. 1.04MeV [Option ID = 42144]
3. 7.17MeV [Option ID = 42146]
4. 2.08NeV [Option ID = 42145]
0.51MeV [Option ID = 42143]
22)
[Question ID = 25540]
1. [Option ID = 42157]
2. [Option ID = 42155]
3. [Option ID = 42158]
4. [Option ID = 42156]
[Option ID = 42155]
23)
[Question ID = 25535]
1. [Option ID = 42135]
2. [Option ID = 42138]
3. [Option ID = 42137]
4. [Option ID = 42136]
[Option ID = 42135]
24)
Page 7
[Question ID = 25571]
1. 0.379 [Option ID = 42280]
2. 0.479 [Option ID = 42281]
3. 0.579 [Option ID = 42282]
4. 0.279 [Option ID = 42279]
0.279 [Option ID = 42279]
25)
[Question ID = 25529]
1. 5.0 MHz [Option ID = 42114]
2. 5.0 GHz [Option ID = 42113]
3. 6.25 GHz [Option ID = 42111]
4. 6.25 MHz [Option ID = 42112]
6.25 GHz [Option ID = 42111]
26)
[Question ID = 25530]
1. [Option ID = 42117]
2. [Option ID = 42116]
3. [Option ID = 42118]
4. [Option ID = 42115]
[Option ID = 42115]
27)
[Question ID = 25570]
1. 0.379 [Option ID = 42280]
2. 0.479 [Option ID = 42281]
3. 0.579 [Option ID = 42282]
4. 0.279 [Option ID = 42279]
0.279 [Option ID = 42279]
25)
[Question ID = 25529]
1. 5.0 MHz [Option ID = 42114]
2. 5.0 GHz [Option ID = 42113]
3. 6.25 GHz [Option ID = 42111]
4. 6.25 MHz [Option ID = 42112]
6.25 GHz [Option ID = 42111]
26)
[Question ID = 25530]
1. [Option ID = 42117]
2. [Option ID = 42116]
3. [Option ID = 42118]
4. [Option ID = 42115]
[Option ID = 42115]
27)
[Question ID = 25570]
Page 8
1. [Option ID = 42278]
2. [Option ID = 42277]
3. [Option ID = 42276]
4. [Option ID = 42275]
[Option ID = 42275]
28)
[Question ID = 25546]
1. X [Option ID = 42179]
2. X+Y [Option ID = 42182]
3. XY [Option ID = 42181]
4. Y [Option ID = 42180]
X [Option ID = 42179]
29)
[Question ID = 25527]
1. [Option ID = 42105]
2. [Option ID = 42103]
3. [Option ID = 42106]
4. [Option ID = 42104]
[Option ID = 42103]
30)
[Question ID = 25524]
1. [Option ID = 42093]
2. [Option ID = 42277]
3. [Option ID = 42276]
4. [Option ID = 42275]
[Option ID = 42275]
28)
[Question ID = 25546]
1. X [Option ID = 42179]
2. X+Y [Option ID = 42182]
3. XY [Option ID = 42181]
4. Y [Option ID = 42180]
X [Option ID = 42179]
29)
[Question ID = 25527]
1. [Option ID = 42105]
2. [Option ID = 42103]
3. [Option ID = 42106]
4. [Option ID = 42104]
[Option ID = 42103]
30)
[Question ID = 25524]
1. [Option ID = 42093]
Page 9
2. [Option ID = 42094]
3. [Option ID = 42091]
4. [Option ID = 42092]
[Option ID = 42091]
31)
[Question ID = 25551]
1. [Option ID = 42199]
2. [Option ID = 42202]
3. [Option ID = 42200]
4. [Option ID = 42201]
[Option ID = 42199]
32)
[Question ID = 25553]
1. 0.5 [Option ID = 42210]
2. 0.333 [Option ID = 42208]
3. 1 [Option ID = 42207]
4. 3 [Option ID = 42209]
1 [Option ID = 42207]
33)
[Question ID = 25558]
1. [Option ID = 42228]
3. [Option ID = 42091]
4. [Option ID = 42092]
[Option ID = 42091]
31)
[Question ID = 25551]
1. [Option ID = 42199]
2. [Option ID = 42202]
3. [Option ID = 42200]
4. [Option ID = 42201]
[Option ID = 42199]
32)
[Question ID = 25553]
1. 0.5 [Option ID = 42210]
2. 0.333 [Option ID = 42208]
3. 1 [Option ID = 42207]
4. 3 [Option ID = 42209]
1 [Option ID = 42207]
33)
[Question ID = 25558]
1. [Option ID = 42228]
Page 10
2. [Option ID = 42230]
3. [Option ID = 42229]
4. [Option ID = 42227]
[Option ID = 42227]
34)
[Question ID = 25534]
1. [Option ID = 42132]
2. [Option ID = 42133]
3. [Option ID = 42131]
4. [Option ID = 42134]
[Option ID = 42131]
35)
[Question ID = 25562]
1. [Option ID = 42244]
2. [Option ID = 42245]
3. [Option ID = 42246]
4. [Option ID = 42243]
[Option ID = 42243]
3. [Option ID = 42229]
4. [Option ID = 42227]
[Option ID = 42227]
34)
[Question ID = 25534]
1. [Option ID = 42132]
2. [Option ID = 42133]
3. [Option ID = 42131]
4. [Option ID = 42134]
[Option ID = 42131]
35)
[Question ID = 25562]
1. [Option ID = 42244]
2. [Option ID = 42245]
3. [Option ID = 42246]
4. [Option ID = 42243]
[Option ID = 42243]
Page 11
36)
[Question ID = 25563]
1. Circles and Hyperbolas [Option ID = 42250]
2. Hyperbolas and Circles [Option ID = 42248]
3. Hyperbolas and Parabolas [Option ID = 42247]
4. Parabolas and Circles [Option ID = 42249]
Hyperbolas and Parabolas [Option ID = 42247]
37)
[Question ID = 25526]
1. [Option ID = 42101]
2. [Option ID = 42102]
3. [Option ID = 42100]
4. [Option ID = 42099]
[Option ID = 42099]
38)
[Question ID = 25538]
1. zero and half integer [Option ID = 42147]
2. half integer and zero [Option ID = 42148]
3. Both half integer [Option ID = 42150]
4. an integer and half integer [Option ID = 42149]
zero and half integer [Option ID = 42147]
39)
[Question ID = 25564]
1. [Option ID = 42252]
2. [Option ID = 42251]
[Question ID = 25563]
1. Circles and Hyperbolas [Option ID = 42250]
2. Hyperbolas and Circles [Option ID = 42248]
3. Hyperbolas and Parabolas [Option ID = 42247]
4. Parabolas and Circles [Option ID = 42249]
Hyperbolas and Parabolas [Option ID = 42247]
37)
[Question ID = 25526]
1. [Option ID = 42101]
2. [Option ID = 42102]
3. [Option ID = 42100]
4. [Option ID = 42099]
[Option ID = 42099]
38)
[Question ID = 25538]
1. zero and half integer [Option ID = 42147]
2. half integer and zero [Option ID = 42148]
3. Both half integer [Option ID = 42150]
4. an integer and half integer [Option ID = 42149]
zero and half integer [Option ID = 42147]
39)
[Question ID = 25564]
1. [Option ID = 42252]
2. [Option ID = 42251]
Page 12
3. [Option ID = 42253]
4. [Option ID = 42254]
[Option ID = 42251]
40)
[Question ID = 25560]
1. 2 [Option ID = 42237]
2. 0 [Option ID = 42236]
3. 1 [Option ID = 42235]
4. 3 [Option ID = 42238]
1 [Option ID = 42235]
41)
[Question ID = 25532]
1. [Option ID = 42123]
2. [Option ID = 42126]
3. [Option ID = 42125]
4. [Option ID = 42124]
[Option ID = 42123]
42)
4. [Option ID = 42254]
[Option ID = 42251]
40)
[Question ID = 25560]
1. 2 [Option ID = 42237]
2. 0 [Option ID = 42236]
3. 1 [Option ID = 42235]
4. 3 [Option ID = 42238]
1 [Option ID = 42235]
41)
[Question ID = 25532]
1. [Option ID = 42123]
2. [Option ID = 42126]
3. [Option ID = 42125]
4. [Option ID = 42124]
[Option ID = 42123]
42)
Page 13
[Question ID = 25533]
1. zero [Option ID = 42127]
2. 4a [Option ID = 42130]
3. a [Option ID = 42129]
4. 2a [Option ID = 42128]
zero [Option ID = 42127]
43)
[Question ID = 25557]
1. [Option ID = 42223]
2. [Option ID = 42224]
3. [Option ID = 42225]
4. [Option ID = 42226]
[Option ID = 42223]
44) A solid uniform drum of mass M radius R rolls without slipping down a plane inclined at an angle θ. Find
its acceleration?
[Question ID = 25523]
1. [Option ID = 42088]
2. [Option ID = 42089]
3. [Option ID = 42090]
4. [Option ID = 42087]
[Option ID = 42087]
1. zero [Option ID = 42127]
2. 4a [Option ID = 42130]
3. a [Option ID = 42129]
4. 2a [Option ID = 42128]
zero [Option ID = 42127]
43)
[Question ID = 25557]
1. [Option ID = 42223]
2. [Option ID = 42224]
3. [Option ID = 42225]
4. [Option ID = 42226]
[Option ID = 42223]
44) A solid uniform drum of mass M radius R rolls without slipping down a plane inclined at an angle θ. Find
its acceleration?
[Question ID = 25523]
1. [Option ID = 42088]
2. [Option ID = 42089]
3. [Option ID = 42090]
4. [Option ID = 42087]
[Option ID = 42087]
Page 14
45) Which of the following functions is analytic over the entire complex plane? [Question ID = 25566]
1. [Option ID = 42259]
2. [Option ID = 42261]
3. [Option ID = 42262]
4. [Option ID = 42260]
[Option ID = 42259]
T
46) The probability that an electron in a metal occupies the fermi level , at any temperature ( >0)
[Question ID = 25539]
1. 1 [Option ID = 42152]
2. 2.0 [Option ID = 42154]
3. 0 [Option ID = 42151]
4. 0.5 [Option ID = 42153]
0 [Option ID = 42151]
47) The Laplace transform of a unit ramp function starting at t=a, is
[Question ID = 25569]
1. [Option ID = 42272]
2. [Option ID = 42274]
3. [Option ID = 42273]
4. [Option ID = 42271]
[Option ID = 42271]
48) An equivalent 2’s complement representation of 2’s complement number 1101 is [Question ID = 25544]
1. 110111 [Option ID = 42173]
2. 001101 [Option ID = 42172]
3. 110100 [Option ID = 42171]
4. 111101 [Option ID = 42174]
110100 [Option ID = 42171]
49) An FM signal with modulation index 9 is applied to a frequency tripler. The modulation index in the output
signal will be [Question ID = 25552]
1. 0 [Option ID = 42203]
2. 9 [Option ID = 42206]
3. 27 [Option ID = 42204]
1. [Option ID = 42259]
2. [Option ID = 42261]
3. [Option ID = 42262]
4. [Option ID = 42260]
[Option ID = 42259]
T
46) The probability that an electron in a metal occupies the fermi level , at any temperature ( >0)
[Question ID = 25539]
1. 1 [Option ID = 42152]
2. 2.0 [Option ID = 42154]
3. 0 [Option ID = 42151]
4. 0.5 [Option ID = 42153]
0 [Option ID = 42151]
47) The Laplace transform of a unit ramp function starting at t=a, is
[Question ID = 25569]
1. [Option ID = 42272]
2. [Option ID = 42274]
3. [Option ID = 42273]
4. [Option ID = 42271]
[Option ID = 42271]
48) An equivalent 2’s complement representation of 2’s complement number 1101 is [Question ID = 25544]
1. 110111 [Option ID = 42173]
2. 001101 [Option ID = 42172]
3. 110100 [Option ID = 42171]
4. 111101 [Option ID = 42174]
110100 [Option ID = 42171]
49) An FM signal with modulation index 9 is applied to a frequency tripler. The modulation index in the output
signal will be [Question ID = 25552]
1. 0 [Option ID = 42203]
2. 9 [Option ID = 42206]
3. 27 [Option ID = 42204]
Page 15
4. 3 [Option ID = 42205]
0 [Option ID = 42203]
R kbits/s
50) The bit rate of digital communication system is . The modulation used is 32-QAM. The minimum
bandwidth required for ISI free transmission is [Question ID = 25556]
1. [Option ID = 42222]
2. [Option ID = 42221]
3. [Option ID = 42219]
4. [Option ID = 42220]
[Option ID = 42219]
0 [Option ID = 42203]
R kbits/s
50) The bit rate of digital communication system is . The modulation used is 32-QAM. The minimum
bandwidth required for ISI free transmission is [Question ID = 25556]
1. [Option ID = 42222]
2. [Option ID = 42221]
3. [Option ID = 42219]
4. [Option ID = 42220]
[Option ID = 42219]