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LEBRAT CE F IN SO G SAMPLE PAPER SYLLABUS 2023-24 CLASS Total Questions : 50 Section PATTERN & MARKING SCHEME (1) Physics & Chemistry (2) Achievers Section Time : 1 hr. (3) Mathematics or 12 Biology SOF NATIONAL SCIENCE OLYMPIAD No. of Questions 25 5 20 Marks per Ques. 1 3 1 SYLLABUS Section – 1 : Physics : Electricity and Magnetism, Electromagnetic Induction, Alternating current, Electromagnetic waves, Optics, Modern Physics, Semiconductor Electronics, Communication Systems. Chemistry : The Solid State, Solutions, Electrochemistry, Chemical Kinetics, Surface Chemistry, General Principles and Processes of Isolation of Elements, The p-Block Elements (Group 15 to 18), The d- and f-Block Elements, Coordination Compounds, Haloalkanes and Haloarenes, Alcohols, Phenols and Ethers, Aldehydes, Ketones and Carboxylic Acids, Amines, Biomolecules, Polymers, Chemistry in Everyday Life. Section – 2 : Higher Order Thinking Questions - Syllabus as per Section – 1. Section – 3 : Relations and Functions, Inverse Trigonometric Functions, Matrices and Determinants, Continuity and Differentiability, Application of Derivatives, Integrals, Application of Integrals, Differential Equations, Vector Algebra, Three Dimensional Geometry, Probability, Linear Programming. OR Section – 3 : Reproduction, Genetics and Evolution, Biology in Human Welfare, Biotechnology, Ecology. PHYSICS AND CHEMISTRY 1. A ray of light passes from vacuum into a medium (B) The sine of the angle of refraction of the of refractive index m. If the angle of incidence is emergent ray will be less than 0.8. found to be twice the angle of refraction, then the (C) The ray will be internally reflected. angle of incidence is (D) None of these (A) cos–1 (m/2) (B) 2cos–1 (m/2) (C) 2sin–1 m (D) 2sin–1(m/2). 4. An ore after levigation is found to have basic impurities. Which of the following can be used as 2. A capacitor of capacitance C 0 is charged to a a flux? potential V0 and then isolated. A small capacitor of (A) MgO (B) CaCO3 capacitance C is then charged from C0, discharged (C) SiO2 (D) FeO and charged again, the process being repeated n times. Due to this, potential of the larger capacitor 5. 1.00 g of a non-electrolyte solute dissolved in 50 g is decreased to V. The value of C is of benzene lowered the freezing point of benzene by 0.40 K. The freezing point depression constant V 1/ n V 1/ n (A) C0 0 (B) C0 0 − 1 of benzene is 5.12 K kg mol–1. The molar mass V V of the solute is n (A) 456 kg/mol (B) 352 g/mol V n (C) C0 0 − 1 (D) C0 V0 − 1 . (C) 256 g/mol (D) 240 g/mol. V V 6. When a compound ‘X’ is reacted with PCl5 and 3. A ray of light in a liquid of refractive index 1.4, then with NH3, it gives ‘Y’. When ‘Y’ is treated with approaches the boundary surface between the Br2 and KOH, it produces ‘Z’. ‘Z’ on treatment with liquid and air at an angle of incidence whose sine NaNO2 and HCl at 0°C and then on warming with is 0.8. Which of the following statements is correct water produces ortho-cresol. Compound ‘X’ is about the behavior of the light ? (A) o-toluic acid (A) It is impossible to predict the behavior of (B) o-chlorotoluene the light ray on the basis of the information (C) o-bromotoluene supplied. (D) m-toluic acid. Sample Paper | Class-12 | 1
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ACHIEVERS SECTION 7. A long straight wire carries a current i. A particle 8. Observe the given graph carefully. having a positive charge q and mass m, kept at distance x0 from the wire is projected towards it with speed v as shown in the figure. The closest distance of approach (xmin) of charged particle to Energy x the wire is R y P z Reaction path The activation energy of the backward reaction, heat of reaction and threshold energy of the reaction (A) xmin = x0 e −2 πmv / µ0qi respectively are (A) x – y, y and x + y – z (B) xmin = x0 e mv / µ0qi (B) x + y + z, y + z and z (C) xmin = x0 e − πmv / µ0qi (C) x + y, y and x + y + z − mv / µ0q 2i (D) xmin = x0 e (D) x + y, y and x – y – z. MATHEMATICS 9. If (1 − x 6 ) + (1 − y 6 ) = a ( x 3 − y 3 ) and 10. For non-zero vectors a, b, c; | (a × b ) . c = | a | | b | | c | 1− y6 a, b, c | (a × b ) . c = | a | | b | | c | holds iff dy = f ( x, y ) , then dx 1 − x 6 (A) a . b = 0, b . c = 0 y y2 (B) b . c = 0, c . a = 0 (A) f ( x, y ) = (B) f ( x, y ) = x x2 (C) c . a = 0, a . b = 0 2y 2 x2 (C) f ( x, y ) = (D) f ( x, y ) = (D) a . b = b . c = c . a = 0 x2 y2 BIOLOGY 9. In which of the following embryonic stages does indicates evolutionary relationship with that animal. the implantation take place? The following experimental results were obtained : Species: Human (H) - 100%; M - 37%; N - 75%; (A) (B) O - 79%; P - 17% Which phylogenetic tree would best represent these results? (C) (D) (A) (B) 10. Human blood, when mixed with antibodies present in human blood, give maximum precipitation. If another animal’s blood is mixed with antibodies (C) (D) present in human blood, the percentage of precipitation ANSWERS NSO – (PHYSICS AND CHEMISTRY) 1. (B) 2. (B) 3. (C) 4. (C) 5. (C) 6. (A) 7. (A) 8. (C) (MATHEMATICS) 9. (D) 10. (D) (BIOLOGY) 9. (A) 10. (A) 2 | Sample Paper | Class-12