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HBSE Class 10 Question Paper 2017 Maths

Board of School Education Haryana (HBSE) Previous Year question Paper. Here you can download HBSE Class 10 Question Paper 2017 Maths PDF More Detail
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Page 1

CLASS : 10th (Secondary) Code No. 1903
Series : Sec. M/2017
Roll No. SET : A
xf.kr
MATHEMATICS
(Academic/Open)
[ fgUnh ,oa vaxzsth ek/;e ]
[ Hindi and English Medium ]
(Only for Fresh Candidates)
(Morning Session)
le; % 3 ?k.Vs ] [ iw.kkZad % 80
Time allowed : 3 hours ] [ Maximum Marks : 80

• Ñi;k tk¡p dj ysa fd bl iz'u-i= esa eqfnzr iz'u 32 gSaA
Please make sure that the printed this question paper are it contains
32 questions.

• iz'u-i= esa nkfgus gkFk dh vksj fn;s x;s dksM uEcj rFkk lsV dks Nk= mÙkj-iqfLrdk ds eq[;-
i`"B ij fy[ksaA
The Code No. and Set on the right side of the question paper should be
written by the candidate on the front page of the answer-book.
• Ñi;k iz'u dk mÙkj fy[kuk 'kq: djus ls igys] iz'u dk Øekad vo'; fy[ksaA
Before beginning to answer a question, its Serial Number must be written.
• mÙkj-iqfLrdk ds chp esa [kkyh iUuk / iUus u NksMsa+A
Don’t leave blank page/pages in your answer-book.
• mÙkj-iqfLrdk ds vfrfjDr dksbZ vU; 'khV ugha feysxhA vr% vko';drkuqlkj gh fy[ksa vkSj fy[kk
mÙkj u dkVsaA
Except answer-book, no extra sheet will be given. Write to the point and do
not strike the written answer.
• ijh{kkFkhZ viuk jksy ua0 iz'u&i= ij vo'; fy[ksaA

1903/(Set : A) P. T. O.

Page 2

(2) 1903/(Set : A)
Candidates must write their Roll Number on the question paper.
• d`i;k iz'uksa dk mÙkj nsus lss iwoZ ;g lqfuf'pr dj ysa fd iz'u-i= iw.kZ o lgh gS] ijh{kk ds
mijkUr bl lEcU/k esa dksbZ Hkh nkok Lohdkj ugha fd;k tk;sxkA
Before answering the questions, ensure that you have been supplied the
correct and complete question paper, no claim in this regard, will be
entertained after examination.
lkekU; funsZ'k %
General Instruction :
(i) lHkh iz'u vfuok;Z gSaA
All questions are compulsory.
(ii) bl iz'u-i= esa dqy 32 iz'u gSa tks fd pkj [k.Mksa v] c] l vkSj n esa ck¡Vs x;s gSa %
This question paper consists of 32 questions in all which are
divided into four Sections : A, B, C and D :
[k.M v % bl [k.M esa 1 ls 16 rd dqy 16 iz'u gSa] izR;sd iz'u 1 vad dk gSA
Section A : There are 16 questions from 1 to 16, each of 1 mark.

[k.M c % bl [k.M esa 17 ls 21 rd dqy 5 iz'u gSa] izR;sd iz'u 3 vad dk gSA
Section B : There are 5 questions from 17 to 21, each of 3 marks.

[k.M l % bl [k.M esa 22 ls 27 rd dqy 6 iz'u gSa] izR;sd iz'u 4 vad dk gSA
Section C : There are 6 questions from 22 to 27, each of 4 marks.

[k.M n % bl [k.M esa 28 ls 32 rd dqy 5 iz'u gSa] izR;sd iz'u 5 vad dk gSA
Section D : There are 5 questions from 28 to 32, each of 5 marks.

(iii) [k.M n esa nks iz'uksa esa vkUrfjd fodYi fn;s x;s gSaA mlesa ls ,d iz'u dks pquuk gSA
Section D contains two questions where internal choice have been
provided. You have to choose one of them.

1903/(Set : A)

Page 3

(3) 1903/(Set : A)
[k.M & v
SECTION – A

1. ;fn 306 vkSj 657 dk HCF 9 gS] rks mldk LCM gS % 1
(A) 2482 (B) 22338
(C) 2754 (D) 5913

If HCF of 306 and 657 is 9, then its LCM is :
(A) 2482 (B) 22338
(C) 2754 (D) 5913

2. 6x 2 – 7x – 3 ds 'kwU;d gSa % 1
1 3 7 3
(A) − , (B) − ,−
3 2 3 6
7 3
(C) ,− (D) buesa ls dksbZ ugha
6 6
The zeros of 6x 2 – 7x – 3 are :
1 3 7 3
(A) − , (B) − ,−
3 2 3 6
7 3
(C) ,− (D) None of these
6 6

a1 b1 c1
3. lehdj.kksa a1x + b1y + c1 = 0 vkSj a 2x + b2y + c 2 = 0 esa = = , rks
a 2 b2 c 2
fuEufyf[kr esa dkSu-lk lR; gS \ 1
(A) vf}rh; gy (B) dksbZ gy ugha
(C) vifjfer gy (D) buesa ls dksbZ ugha
a1 b1 c1
If in equations a1x + b1y + c1 = 0 and a 2 x + b2y + c 2 = 0 , = = ,
a 2 b2 c 2
then which of the following is true ?

1903/(Set : A) P. T. O.

Page 4

(4) 1903/(Set : A)
(A) Unique solution (B) No solution

(C) Infinite solutions (D) None of these

1 5 9 13
4. A. P. , , , ……… dk 15ok¡ in gS % 1
3 3 3 3

61
(A) (B) 6
3

(C) 5 (D) 19

1 5 9 13
15th term of A. P. , , , is :
3 3 3 3

61
(A) (B) 6
3

(C) 5 (D) 19

5. ;fn A. P. dk rhljk in 5 vkSj 7ok¡ in 13 gS] rks mldk lkoZ varj (common
difference) gS % 1

(A) 1 (B) 2

(C) 3 (D) 4

If 3rd term of an A. P. is 5 and 7th term is 13, then its common
difference is :

(A) 1 (B) 2

(C) 3 (D) 4

6. nh xbZ vkÑfr esa ∆ODC ~ ∆OAB, ∠BOC = 100°, ∠ODC = 60°, rks
∠OAB dk eku gS % 1

1903/(Set : A)

Page 5

D C (5) 1903/(Set : A)
60°
O 100°

A B
(A) 20° (B) 80°
(C) 60° (D) 40°
In the given figure ∆ODC ~ ∆OAB, ∠BOC = 100°, ∠ODC = 60°,
then ∠OAB is equal to :

D C
60°
O 100°

A B

(A) 20° (B) 80°
(C) 60° (D) 40°

7. ;fn nks le:i f=Hkqtksa dh Hkqtkvksa dk vuqikr 2 : 3 gS] rks muds {ks=Qyksa dk vuqikr gS %
1
(A) 2: 3 (B) 2:3
(C) 4:9 (D) bues ls dksbZ ugha
If ratio of the sides of two similar, triangles is 2 : 3, then the ratio of
their areas is :
(A) 2: 3 (B) 2:3
(C) 4:9 (D) None of these

8. ;fn fdlh fcUnq P ls o`Ùk ds Åij [khaph xbZ] Li'kZ js[kk dh yEckbZ 24 lseh gS vkSj fcUnq dh
dsUnz ls nwjh 25 lseh gS] rks o`Ùk dh f=T;k dh yEckbZ gS % 1
(A) 12 lseh (B) 12.5 lseh
(C) 1 lseh (D) 7 lseh

1903/(Set : A) P. T. O.

Page 6

(6) 1903/(Set : A)
From a point P, the length of tangent to a circle is 24 cm and distance
of P from the centre is 25 cm. The radius of the circle is :
(A) 12 cm (B) 12.5 cm
(C) 1 cm (D) 7 cm

9. ,d o`Ùk ij lekarj Li'kZ js[kkvksa dh vf/kdre la[;k gS % 1
(A) 1 (B) 2
(C) 3 (D) 4
The maximum number of parallel tangents to a circle is :
(A) 1 (B) 2
(C) 3 (D) 4

10. ewy fcUnq ls (5, –7) dh nwjh gS % 1

(A) 74 (B) –2
(C) 2 (D) 12
The distance of point (5, –7) from origin is :
(A) 74 (B) –2
(C) 2 (D) 12

11. f=Hkqt ftlds 'kh"kZ (1, –1), (–4, 6) vkSj (–3, –5) gS] mldk {ks=Qy gS % 1

43
(A) (B) 8
2
(C) 24 (D) buesa ls dksbZ ugha
The area of triangle whose vertices are (1, –1), (–4, 6) and (–3, –5)
is :

43
(A) (B) 8
2

1903/(Set : A)

Page 7

(7) 1903/(Set : A)
(C) 24 (D) None of these

12. ;fn tan A = 5 , rks cos A dk eku gS % 1
12
5 12 13 12
(A) (B) (C) (D)
13 5 5 13

5
If tan A = , then the value of cos A is :
12
5 12 13 12
(A) (B) (C) (D)
13 5 5 13

1 − tan2 30
13. dk eku gS % 1
1 + tan2 30
(A) cos 60° (B) tan 60°
(C) sin 60° (D) tan 30°

1 − tan2 30
The value of is :
1 + tan2 30
(A) cos 60° (B) tan 60°
(C) sin 60° (D) tan 30°

14. o`Ùk dh ifjf/k vkSj O;kl dk vuqikr gS % 1
(A) 2π : 1 (B) π:1
(C) 1:1 (D) buesa ls dksbZ ugha
The ratio of circumference and diameter of a circle is :

(A) 2π : 1 (B) π:1

(C) 1:1 (D) None of these

1903/(Set : A) P. T. O.

Page 8

(8) 1903/(Set : A)
 22 
15. ,d 'kadq ds vk/kkj dh f=T;k 7 lseh vkSj Å¡pkbZ 6 lseh gS] rks mldk vk;ru gS  π = 
 7 
% 1

924 lseh 308 lseh
3 3
(A) (B)

1232 lseh buesa ls dksbZ ugha
3
(C) (D)

The radius of the base of a cone is 7 cm and the height is 6 cm. Its
 22 
volume is  π =  :
 7 

(A) 924 cm3 (B) 308 cm3

(C) 1232 cm3 (D) None of these

16. ;fn P(E) = 0.05, rks P (E ugha) gS % 1

(A) 0.05 (B) 0.5

(C) 0.95 (D) buesa ls dksbZ ugha
If P(E) = 0.05, then the P (not E) is :

(A) 0.05 (B) 0.5

(C) 0.95 (D) None of these

[k.M & c
SECTION – B

17. fl) dhft, fd 6 + 2 ,d vifjes; la[;k gSA 3

Prove that 6 + 2 is an irrational number.

18. ,d f}?kkr cgqin Kkr dhft, ftlds 'kwU;d –4 vkSj 2 gksaA 3

1903/(Set : A)

Page 9

(9) 1903/(Set : A)
Find a quadratic polynomial whose zeros are –4 and 2.

19. nks [kaHks ftldh Å¡pkb;k¡ 7 eh vkSj 12 eh gS ,d lery Hkwfe ij [kM+s gSa ;fn buds fupys
fljksa ds chp dh nwjh 12 eh gS] rks buds Åijh fljksa ds chp dh nwjh Kkr dhft,A 3
Two poles of heights 7 m and 12 m stand on a plane ground. If the
distance between the feet of the poles be 12 m, then find the distance
between their tops.

20. ;fn tan (A + B) = 3 vkSj tan (A – B) = 1 , 0° < A + B ≤ 90°, A
3
> B, rks A vkSj B dk eku Kkr dhft,A 3
1
If tan (A + B) = 3 and tan (A – B) = , 0° < A + B ≤ 90°,
3
A > B, then find the value of A and B.

21. 4 lseh f=T;k okys ,d o`Ùk ds f=T;k[kaM (sector) dk {ks=Qy Kkr dhft, ftldk dsUnz ij
dks.k 45° gksA (π = 3.14) 3
Find the area of the sector of a circle with radius 4 cm and the angle
at the centre is 45°. (π = 3.14)

[k.M & l
SECTION – C

22. fuEufyf[kr lehdj.kksa dks gy dhft, % 4
3x 5y
− = −2
2 3
x y 13
+ =
3 2 6

Solve the following equations :

1903/(Set : A) P. T. O.

Page 10

( 10 ) 1903/(Set : A)
3x 5y
− = −2
2 3
x y 13
+ =
3 2 6
23. ,d ledks.k f=Hkqt dh ledks.k cukus okyh ,d Hkqtk nwljh ls 17 lseh de gSA ;fn d.kZ dh
yEckbZ 25 lseh gS] rks nksuksa Hkqtkvksa dh yEckbZ Kkr dhft,A 4

The side of a right angle triangle is 17 cm less than the other side. If
length of hypoteneuse is 25 cm, find the length of sides.

24. ,d A. P. ds igys 7 inksa dk ;ksx 49 vkSj igys 17 inksa dk ;ksx 289 gS] rks ml A. P.
ds n inksa dk ;ksx Kkr dhft,A 4

If the sum of first 7 terms of A. P. is 49 and sum of first 17 terms is
289, then find the sum of n terms of A. P.

25. fdlh cká fcUnq ls o`Ùk ij [khaph xbZ Li'kZ js[kkvksa dh yEckb;k¡ cjkcj gksrh gSa] fl) dhft,A
4

Prove that the length of tangents drawn from an external point to a
circle are equal.

26. ,d ckWDl esa 5 yky] 8 lQsn vkSj 4 gjh xsansa gSaA ,d xsan ckWDl esa ls fcuk ns[ks fudkyh
tkrh gSA bl xsan ds yky gksus dh izkf;drk Kkr dhft,A bl xsan ds gjh u gksus dh Hkh
izkf;drk Kkr dhft,A 4

A box contains 5 red, 8 white and 4 green balls. A ball is drawn at
random. Find the probability of getting a red ball. Also find the
probability that the ball is not green.

1903/(Set : A)

Page 11

( 11 ) 1903/(Set : A)
27. (5, –6) vkSj (–1, –4) dks feykus okyh js[kk dks y-v{k fdl vuqikr esa foHkkftr djrk gS

\ foHkkftr djus okys fcUnq ds funsZ'kkad Hkh Kkr dhft,A 4

Find the ratio in which the line joining (5, –6) and (–1, –4) is divided by
y-axis. Also find the coordinates of the point of intersection.

[k.M & n
SECTION – D

28. ,d jsyxkM+h ,dleku pky ls 360 fdeh pyrh gSA ;fn mldh pky 5 fdeh/?k.Vk vf/kd
gks] rks mls bruh nwj tkus esa 1 ?kaVk de yxrk gS \ xkM+h dh pky Kkr dhft,A 5

A train travels 360 km at a uniform speed. If the speed had been 5
km/hour more, it would have taken 1 hour less for the same journey.
Find the speed of the train.

29. fl) dhft, % 5

1 + sec A sin2 A
=
sec A 1 − cos A

Prove that :

1 + sec A sin2 A
=
sec A 1 − cos A

vFkok
OR

1903/(Set : A) P. T. O.

Page 12

( 12 ) 1903/(Set : A)
,d lery tehu ij [kM+h ehukj dh Nk;k ml fLFkfr esa 40 eh vf/kd yEch

gks tkrh gS tcfd lw;Z dk mUu;u dks.k 60° ls ?kVdj 30° gks tkrk gSA ehukj dh Å¡pkbZ
Kkr dhft,A

The shadow of a tower standing on a level ground is found to be 40 m
longer when the altitude (the angle of elevation) of sun changes from
60° to 30°. Find the height of tower.

30. ,d f=Hkqt dh jpuk dhft, ftldh nks Hkqtk,¡ 6 lseh vkSj 5 lseh gksa vkSj muds chp dk dks.k
60° gks, bl f=Hkqt ds le:i nwljs f=Hkqt dh jpuk dhft,] ftldh Hkqtk,¡ bl f=Hkqt dh

3
gksaA 5
4

Draw a triangle whose two sides are 6 cm and 5 cm and the angle
3
between them is 60°, construct another triangle whose sides are of
4
the corresponding sides of first triangle.

31. f=T;k 4.2 lseh okys /kkrq ds ,d xksys dks fi?kykdj 6 lseh f=T;k okys ,d 'kadq ds :i esa
<kyk tkrk gSA 'kadq dh špkbZ Kkr dhft,A 5

A metallic sphere of radius 4.2 cm is melted and recast into a shape of
cone of radius 6 cm. Find the height of the cone.

32. uhps fn;k gqvk caVu ,d d{kk ds 30 fo|kfFkZ;ksa dk Hkkj n'kkZ jgk gSA fo|kfFkZ;ksa dk ek/;d
Hkkj Kkr dhft, % 5

Hkkj ¼fdyksxzke esa½ 40-45 45-50 50-55 55-60 60-65 65-70 70-75

1903/(Set : A)

Page 13

( 13 ) 1903/(Set : A)
fo|kfFkZ;ksa dh la[;k 2 3 8 6 6 3 2

The distribution below gives the weight of 30 students of a class. Find
the median weight of the students :

Weight (in Kg.) 40-45 45-50 50-55 55-60 60-65 65-70 70-75

No. of Students 2 3 8 6 6 3 2

vFkok
OR

fdlh eksgYys ds 25 ifjokjksa dk Hkkstu ij O;; fuEufyf[kr gSA Hkkstu ij gqvk ek/; O;;
Kkr dhft, %

[kpZ ¼#i;s esa½ 100-150 150-200 200-250 250-300 300-350

ifjokjksa dh la[;k 4 5 12 2 2

The table below shows daily expenditure on food of 25 households in a
locality. Find the mean daily expenditure.

Expenditure (in Rs.) 100-150 150-200 200-250 250-300 300-350

No. of households 4 5 12 2 2

S
1903/(Set : A) P. T. O.

Document Details

Board / OrgHaryana Board
ExamClass 10
TypeQuestion Paper
Pages13
Updated30 Apr 2026