Karnataka SSLC Model Question Paper 2024 Science

ACADEMIC YEAR

2024

Karnataka
Board
Model Paper

PÜ®ÝìoPÜ ÍÝÇÝ ±ÜÄàûæ ÊÜáñÜᤠÊÜåèƯ|ì¿á ÊÜáívÜÈ
ÊÜáÇæÉàÍÜÌÃÜí, ¸æíWÜÙÜãÃÜá & 560 003
KARNATAKA SCHOOL EXAMINATION AND ASSESSMENT BOARD
Malleshwaram, Bengaluru – 560 003

2023-24 ÃÜ GÓ….GÓ….GÇ….Ô. ÊÜÞ¨ÜÄ ±ÜÅÍ氱ܣÅPæ
S.S.L.C. MODEL QUESTION PAPER – 2023-24

…Œ⁄æ⁄fl : …e¤k´⁄
Subject : SCIENCE
(»èñÜ ËþÝ®Ü, ÃÜÓÝ¿á®Ü ËþÝ®Ü ÊÜáñÜᤠiàÊÜ ËþÝ®Ü / Physics, Chemistry & Biology )
( AMV⁄« »⁄·¤®⁄¥¿»⁄fl / English Medium )

ÓÜÊÜá¿á : 3 WÜípæ 15 ¯ËáÐÜWÜÙÜá ] ËÐÜ¿á ÓÜíPæàñÜ : 83-E
WÜÄÐÜu AíPÜWÜÙÜá : 80 ] Subject Code : 83-E

CCE-RF : ÍÝÇÝ Ë¨Ý¦ìWÜÙÜá / Regular Fresh

General Instructions to the Candidate :
1. There are three parts in the question paper :
Part A : Physics, Part B : Chemistry, Part C : Biology.
2. This question paper consists of 38 questions.
3. Question paper has been sealed by reverse jacket. You have to cut on
the right side to open the paper at the time of commencement of the
examination. Check whether all the pages of the question paper are
intact.
4. Follow the instructions given against the questions.
5. Figures in the right hand margin indicate maximum marks for the
questions.
6. The maximum time to answer the paper is given at the top of the
question paper. It includes 15 minutes for reading the question paper.

[ Turn over

83-E 2 CCE RF

PART – A
( PHYSICS )

I. Four alternatives are given for each of the following questions /

incomplete statements. Choose the correct alternative and write

the complete answer along with its letter of alphabet. 4×1=4

1. The type of the lens used to correct near-sightedness is

(A) Convex lens

(B) Concave lens

(C) Bifocal lens

(D) Concavo-Convex lens

2. The rule that helps to determine the direction of magnetic field

around a current carrying straight conductor is

(A) Right hand thumb rule

(B) Fleming’s right hand rule

(C) Law of magnetic poles

(D) Fleming’s left hand rule

83-E 3 CCE RF

3. The colour of the sky from the surface of the moon appeared as

(A) blue

(B) violet

(C) black

(D) red

4. Resistors of resistance 100 Ω each are connected in parallel in

an electric circuit. Then the number of resistors have to be

connected to obtain 25 Ω as equivalent resistance is

(A) 10

(B) 5

(C) 40

(D) 4

[ Turn over

83-E 4 CCE RF

II. Answer the following questions : 2×1=2

5. Is it possible to connect a refrigerator rated 1320W to a domestic

circuit of 220 V with an electric fuse rated 5 A ? Clarify the

reason for your answer.

6. What is the function of the mirror used in solar cooker ?

III. Answer the following questions : 2×2=4

7. Draw the diagram of a simple electric motor and label ‘Split

rings’.

8. Bio-gas is an excellent fuel. How ?

OR

Mention the advantages and the limitations of wind energy.

IV. Answer the following questions : 3×3=9

9. ‘Earthing of the electric instruments having metallic surface is

must.’ How is this measure be justified ?

OR

Which measures have to be taken to avoid the overload in

domestic electric circuits ?

83-E 5 CCE RF

10. Draw the ray diagram for the image formation in a convex lens

when the object is placed between F 1 and 2 F 1 . Mention the

position and the nature of the image formed with the help of ray

diagram.

( F 1 : Principal focus of the lens )

11. Explain the following natural phenomena :

i) Twinkling of stars

ii) Rainbow formation.

OR

a) How does the eye lens accommodate to see the nearby

objects and distant objects ? Explain.

b) The overhead sun at noon appears as white. What is the

reason for this ?

[ Turn over

83-E 6 CCE RF

V. Answer the following question : 1×4=4

12. a) What is reflection of light ? State the two laws of reflection.

b) Define the following terms related to the spherical

mirrors :

i) Aperture

ii) Pole of the mirror

VI. Answer the following question : 1×5=5

13. a) State Joule’s law of heating. How does a bulb work based

on this law ? Explain.

b) What is electric potential difference ? Name the instrument

used to measure the potential difference. How is this

instrument be connected in an electric circuit ?

83-E 7 CCE RF

PART – B

( CHEMISTRY )

VII. Four alternatives are given for each of the following questions /
incomplete statements. Choose the correct alternative and write
the complete answer along with its letter of alphabet. 2×1=2

14. A type of chemical reaction in which a single product is formed

by two or more reactants is

(A) chemical decomposition

(B) chemical combination

(C) chemical displacement

(D) chemical double displacement

15. Atomic number of chlorine is 17. The period of this element in

the modern periodic table is

(A) 1 st period (B) 2 nd period

(C) 3 rd period (D) 4 th period

[ Turn over

83-E 8 CCE RF

VIII. Answer the following questions : 4×1=4

16. What is dilution of acids ?

17. What could be the pH value of a salt that is commonly used to

remove strong oil stains in any source ? Why ?

18. What is the reason for the formation of water when moderately

reactive metals react with nitric acid ?

19. Though concentrated sulphuric acid is not a reactant during the

conversion of ethanol to ethene, its presence is necessary. Why ?

IX. Answer the following questions : 3×2=6

20. Name the carbon compounds having the following structures.

i)

ii)

iii)

iv)

83-E 9 CCE RF

21. “Thermite process is useful to join railway tracks.” Why ?

Substantiate this statement with suitable explanation.

OR

Can zinc carbonate and cinnabar ores be converted into their

oxides by roasting ? Justify your answer with reason.

22. Observe the table given below. Answer the given questions :

Element B O C Li K

Atomic Number 5 8 6 3 19

i) Choose the elements that have the smallest and the largest

atoms.

ii) Predict the formula of potassium oxide with reason.

X. Answer the following questions : 3×3=9

23. a) What are saturated carbon compounds ?

b) Define the following :

i) Homologous series

ii) Esters.

OR

[ Turn over

83-E 10 CCE RF

a) What are micelles ?

b) What is covalent bond ? Write any two properties of

covalent compounds.

24. Draw the diagram of the arrangement of apparatus to show the

action of steam on a metal. Label the following parts :

i) Metal sample

ii) Hydrogen gas.

25. In which of the following chemical reactions water insoluble

precipitate will be formed ? Explain. Which water soluble

products are formed in both of the reactions ?

i) Barium chloride reacted with sodium sulphate.

ii) Zinc reacted with hydrochloric acid.

83-E 11 CCE RF

XI. Answer the following question : 1×4=4

26. a) Observe the following chemical equations and answer the

question given :

CuO + 2HCl → CuCl 2 + H 2 O

CO 2 + Ca(OH) 2 → CaCO 3 + H 2 O

Which property of metallic oxide and non-metallic oxide is

expressed here ? Explain.

b) How sodium carbonate is prepared ? Explain with suitable

chemical equations. Mention any two uses of this salt.

PART – C

( BIOLOGY )

XII. Four alternatives are given for each of the following questions /

incomplete statements. Choose the correct alternative and write

the complete answer along with its letter of alphabet. 2×1=2

27. The process that occurs in the production of new individuals of

planaria is

(A) binary fission

(B) regeneration

(C) budding

(D) fragmentation

[ Turn over

83-E 12 CCE RF

28. A phenomenon that does not direct the speciation is

(A) Geographical isolation

(B) Genetic drift

(C) Natural selection

(D) DNA replication

XIII. Answer the following questions : 2×1=2

29. Which tropisms are necessary to bring the growth in the shoots

and roots of plants ?

30. What type of pollination occurs in the given below type of

flower ? Why ?

83-E 13 CCE RF

XIV. Answer the following questions : 3×2=6

31. What are fossils ? What are the methods of estimating the age of

fossils ?

32. Classify the following into natural and artificial ecosystems :

Rainforest, Crop field, Lake, Pond

33. Existing in enormous number and the tiny structures of both

‘alveoli’ and ‘nephrons’ are complementary to their work

efficiency. How ?

XV. Answer the following questions : 3×3=9

34. a) What are the problems caused by the construction of large

dams ?

b) Who are the stakeholders of forests ?

35. a) Sexual reproduction in higher organisms brings the

genetic stability among the population of species. How is it

possible ?

b) Surgical method of contraception is better than

mechanical method of contraception. Why ?

[ Turn over

83-E 14 CCE RF

36. a) How homologous organs are differ from analogous

organs ?

b) “An individual cannot pass its lifetime experiences to its

progeny.” Explain with an illustration.

OR

Round, yellow seed producing ( RRYY ) pea plant is crossed with

wrinkled, green seed producing ( rryy ) pea plant. Show the
results obtained in F 2 generation with the help of checker board

and mention the ratio of the plant types produced.

XVI. Answer the following questions : 2×4=8

37. a) Which are the events that occur during photosynthesis ?

b) What is the importance of transpiration in the

transportation of salts ? Mention the different strategies

found in plants during the excretion of wastes.

OR

a) What is the function of buccal cavity and stomach in the

digestion of food in our body ?

b) Mention the role of arteries and capillaries in the

transportation of materials in our body.

83-E 15 CCE RF

38. Draw the diagram showing the structure of human brain. Label

the following parts :

i) Cerebellum

ii) Hypothalamus.

[ Turn over

83-E 16 CCE RF

PÜ®ÝìoPÜ ÍÝÇÝ ±ÜÄàûæ ÊÜáñÜᤠÊÜåèƯ|ì¿á ÊÜáívÜÈ
ÊÜáÇæÉàÍÜÌÃÜí, ¸æíWÜÙÜãÃÜá & 560 003
KARNATAKA SCHOOL EXAMINATION AND ASSESSMENT BOARD
Malleshwaram, Bengaluru – 560 003

2023-24 ÃÜ GÓ….GÓ….GÇ….Ô. ÊÜÞ¨ÜÄ ±ÜÅÍ氱ܣÅPæ
S.S.L.C. MODEL QUESTION PAPER – 2023-24
ËÐÜ¿á : ËþÝ®Ü
Subject : SCIENCE
»èñÜ ËþÝ®Ü, ÃÜÓÝ¿á®Ü ËþÝ®Ü ÊÜáñÜᤠiàÊÜ ËþÝ®Ü / Physics, Chemistry & Biology
PܮܰvÜ ÊÜÞ«ÜÂÊÜá / Kannada Medium
ÓÜÊÜá¿á 3 WÜípæ 15 ¯ËáÐÜWÜÙÜá ] ËÐÜ¿á ÓÜíPæàñÜ : 83-K
WÜÄÐÜu AíPÜWÜÙÜá 80 ] Subject Code : 83-K
CCE-RF : ÍÝÇÝ Ë¨Ý¦ìWÜÙÜá / Regular Fresh

±ÜÄàûݦìWÝX ÓÝÊÜޮܠÓÜãaÜ®æWÜÙÜá
1. D ±ÜÅÍ氱ܣÅPæ¿áÈÉ »ÝWÜ&A : »èñÜ ËþÝ®Ü, »ÝWÜ&B : ÃÜÓÝ¿á®Ü ËþÝ®Ü,
»ÝWÜ&C : iàÊÜ ËþÝ®Ü GíŸ ÊÜáãÃÜá »ÝWÜWÜÚÊæ.
2. D ±ÜÅÍ氱ܣÅPæ¿áá Joár 38 ±ÜÅÍæ°WÜÙÜ®Üá° Öæãí©¨æ.
3. ±ÜÅÍ氱ܣÅPæ¿á®Üá° ×ÊÜáá¾S hÝPæp… ÊÜáãÆPÜ ÊæãÖÜÃÜá ÔàÇ… ÊÜÞvÜÇÝX¨æ. ±ÜÄàûæ
±ÝÅÃÜí»ÜÊÝWÜáÊÜ ÓÜÊÜá¿áPæR ¯ÊÜá¾ ±ÜÅÍ氱ܣÅPæ¿á ŸÆŸ© ±ÝÍÜÌìÊÜ®Üá° PÜñܤÄÔ,
±ÜÅÍ氱ܣÅPæ¿áÈÉ GÇÝÉ ±ÜâoWÜÙÜá CÊæÁáà Gí¨Üá ±ÜÄàüÔPæãÚÛ.
4. ±ÜÅÍæ°WÜÚWæ PæãqrÃÜáÊÜ ÓÜãaÜ®æWÜÙÜ®Üá° ±ÝÈÔ.
5. ŸÆ »ÝWܨÜÈÉ PæãqrÃÜáÊÜ AíQWÜÙÜá ±ÜÅÍæ°WÜÚXÃÜáÊÜ ±Üä|ì AíPÜWÜÙÜ®Üá° ñæãàÄÓÜáñܤÊæ.
6. ±ÜÅÍ氱ܣÅPæ¿á®Üá° K©PæãÙÜÛÆá 15 ¯ËáÐÜWÜÙÜ PÝÇÝÊÜPÝÍÜÊÜâ ÓæàĨÜíñæ, EñܤÄÓÜÆá
¯WÜ©±ÜwÓÜÇÝ¨Ü ÓÜÊÜá¿áÊÜ®Üá° ±ÜÅÍ氱ܣÅPæ¿á ÊæáàÇݽWܨÜÈÉ ¯àvÜÇÝX¨æ.

[ Turn over

83-K 2 CCE RF

»ÝWÜ & A
( »èñÜ ËþÝ®Ü )
I. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ A¥ÜÊÝ A±Üä|ì ÖæàÚPæWÜÚWæ ®ÝÆáR ±Ü¿Þì¿á EñܤÃÜWÜÙÜ®Üá°
¯àvÜÇÝX¨æ. AÊÜâWÜÙÜÈÉ ÓÜãPܤÊÝ¨Ü Jí¨Üá EñܤÃÜÊÜ®Üá° BÄÔ, A¨ÜÃÜ PÜÅÊÜÞûÜÃܨæãvÜ®æ
±Üä|ì EñܤÃÜÊÜ®Üá° ŸÃæÀáÄ 4×1=4

1. ÓÜËáà±Ü ¨ÜêÑr ÊÜáÁãà²¿Þ ¿á®Üá° ÓÜıÜwÓÜÆá ŸÙÜÓÜáÊÜ ÊÜáÓÜãÃÜ¨Ü Ë«Ü

(A) ²à®Ü ÊÜáÓÜãÃÜ

(B) ¯ÊÜá° ÊÜáÓÜãÃÜ

(C) ©ÌÓÜíWÜÊÜá ÊÜáÓÜãÃÜ

(D) ¯ÊÜá° ²à®Ü ÊÜáÓÜãÃÜ

2. ˨ÜáÂñ… ±ÜÅÊÜ×ÓÜᣤÃÜáÊÜ ®æàÃÜ ÊÝÖÜPÜ¨Ü ÓÜáñܤÆã CÃÜáÊÜ PÝíñÜûæàñÜÅ¨Ü ©PÜR®Üá°
¯«ÜìÄÓÜÆá ÓÜÖÝ¿áPÜÊÝWÜáÊÜ ¯¿áÊÜá

(A) ŸÆWæç Öæ¸æºÃÜÙÜ ¯¿áÊÜá

(B) ¶æÉËáíW…®Ü ŸÆWæç ¯¿áÊÜá

(C) PÝíñÜ«ÜáÅÊÜWÜÙÜ ¯¿áÊÜá

(D) ¶æÉËáíW…®Ü GvÜWæç ¯¿áÊÜá

83-K 3 CCE RF
3. aÜí¨ÜÅ®Ü ÊæáàÇ澄¯í¨Ü WæãàaÜÄÓÜáÊÜ BPÝÍÜ¨Ü Ÿ|¡ÊÜâ

(A) ¯àÈ

(B) ®æàÃÜÙæ

(C) PܱÜâ³

(D) Pæí±Üâ

4. ±ÜÅ£Áãí¨ÜÃÜ Ãæãà«ÜÊÜâ 100 ®ÜÐÜár CÃÜáÊÜ Ãæãà«ÜPÜWÜÙÜ®Üᰠ˨ÜáÂñ…ÊÜáívÜƨÜÈÉ

ÓÜÊÜÞíñÜÃÜÊÝX hæãàwÔ¨æ. BWÜ 25 ®ÜÐÜár ÓÜÊÜÞ®ÜÃæãà«ÜÊÜ®Üá° ±Üvæ¿áÆá

hæãàwÓܸæàPÝ¨Ü Ãæãà«ÜPÜWÜÙÜ ÓÜíTæÂ

(A) 10

(B) 5

(C) 40

(D) 4

[ Turn over

83-K 4 CCE RF
II. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ 2×1=2

5. 220 V Ë»ÜÊÝíñÜÃÜËÃÜáÊÜ WÜêÖÜŸÙÜPæ¿á ˨ÜáÂñ…ÊÜáívÜƨÜÈÉ 1320 W

ÓÝÊÜá¥ÜÂìËÃÜáÊÜ ÃæµÅgÃæàoÃ…®Üá° 5 A ¨ÜÃÜ¨Ü ¶ÜäÂÓ…Wæ ÓÜí±ÜQìÓÜÆá ÓÝ«ÜÂÊæà ¯ÊÜá¾
EñܤÃÜPæR PÝÃÜ|ÊÜ®Üá° ÓܳÐÜr±ÜwÔ.

6. ÓèÃÜPÜáPÜRÃ…®ÜÈÉ ŸÙÜÓÜáÊÜ Pܮܰw¿á PÝ¿áìÊæà®Üá

III. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ 2×2=4

7. Jí¨Üá ÓÜÃÜÙÜ Ë¨ÜáÂñ… ÊæãàpÝÃ…®Ü bñÜÅÊÜ®Üá° ŸÃæ¨Üá, JvÜPÜá EíWÜáÃÜ WÜÙÜ®Üá°
WÜáÃÜá£Ô.

8. hæçËPÜ A¯ÆÊÜâ AñÜáÂñܤÊÜá Cí«Ü®ÜÊÝX¨æ. ÖæàWæ

A¥ÜÊÝ
±ÜÊÜ®ÜÍÜQ¤¿á A®ÜáPÜãÆWÜÙÜá ÊÜáñÜᤠËá£WÜÙÜ®Üá° £ÚÔ.

IV. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ 3×3=9

9. ÇæãàÖÜ¨Ü ÊæáàÇ澄 Öæãí©ÃÜáÊÜ Ë¨ÜáÂñ… E±ÜPÜÃÜ|WÜÙÜ®Üá° »ÜãÓÜí±ÜPÜìWæãÚÓܸæàPÜá.
D PÜÅÊÜáÊÜ®Üá° ÖæàWæ ÓÜÊÜá¦ìÓÜáËÄ

A¥ÜÊÝ

WÜêÖÜŸÙÜPæ¿á ˨ÜáÂñ…ÊÜáívÜÆWÜÙÜÈÉ KÊÜÃ…Çæãàv… A®Üá° ñܲ³ÓÜÆá ¿ÞÊÜ

PÜÅÊÜáWÜÙÜ®Üá° PæçWæãÙÜÛ¸æàPÜá

83-K 5 CCE RF
10. ²à®Ü ÊÜáÓÜãÃÜ¨Ü ÊÜááí¨æ ÊÜÓÜá¤ÊÜ®Üá° F 1 ÊÜáñÜᤠ2 F1 WÜÙÜ ®ÜvÜáÊæ CÄÔ¨ÝWÜ

EípÝWÜáÊÜ ±ÜÅ£¹íŸ¨Ü ÃæàTÝbñÜÅÊÜ®Üá° ŸÃæÀáÄ. ÃæàTÝbñÜÅ¨Ü ÓÜÖÝ¿á©í¨Ü

±ÜÅ£¹íŸ¨Ü Óݧ®Ü ÊÜáñÜᤠÓÜÌ»ÝÊÜWÜÙÜ®Üá° £ÚÔ.

[ F 1 ÊÜáÓÜãÃÜ¨Ü ±ÜÅ«Ý®Ü ÓÜíWÜÊÜá ]

11. D PæÙÜX®Ü ®æçÓÜXìPÜ Ë¨ÜÂÊÜÞ®ÜWÜÙÜ®Üá° ËÊÜÄÔ

i) ®ÜûÜñÜÅWÜÙÜ Ëá®ÜáWÜáËPæ

ii) PÝÊÜá®Ü¹ÆáÉ EípÝWÜáËPæ

A¥ÜÊÝ

a) PÜ|á¡ ñܮܰ ÓÜËáà±Ü¨Ü ÊÜÓÜá¤WÜÙÜá ÊÜáñÜᤠ¨ÜãÃܨÜÈÉÃÜáÊÜ ÊÜÓÜá¤WÜÙÜ®Üá° ®æãàvÜÆá

ÖæàWæ Öæãí¨Ý~Pæ ÊÜÞwPæãÙÜáÛñܤ¨æ ËÊÜÄÔ.

b) ÊÜá«ÝÂÖÜ°¨ÜÈÉ ®æ£¤¿á Êæáà騆 ÓÜã¿áì®Üá ¸æÙÜÛWæ PÝ|áñݤ®æ. C¨ÜPæR

PÝÃÜ|Êæà®Üá

[ Turn over

83-K 6 CCE RF
V. PæÙÜX®Ü ±ÜÅÍæ°Wæ EñܤÄÔ 1×4=4

12. a) ¸æÙÜQ®Ü ±ÜÅ£¶ÜÆ®Ü Gí¨ÜÃæà®Üá ±ÜÅ£¶ÜÆ®Ü¨Ü GÃÜvÜá ¯¿áÊÜáWÜÙÜ®Üá°

¯ÃÜã²Ô.

b) WæãàÚà¿á ¨Ü±Üì|WÜÚWæ ÓÜíŸí˜Ô¨Üíñæ PæÙÜX®Ü ±Ü¨ÜWÜÙÜ®Üá° ÊÝÂTݯÔ

i) ¨Üá£ÃÜí«ÜÅ

ii) ¨Ü±Üì| «ÜáÅÊÜ

VI. PæÙÜX®Ü ±ÜÅÍæ°Wæ EñܤÄÔ 1×5=5

13. a) hèÇ…®Ü EÐæã¡àñݳ¨Ü®Ý ¯¿áÊÜáÊÜ®Üá° ¯ÃÜã²Ô. D ¯¿áÊÜá¨Ü B«ÝÃܨÜ

ÊæáàÇæ ŸÇ…º ÖæàWæ PÝ¿áì¯ÊÜì×ÓÜáñܤ¨æ ËÊÜÄÔ.

b) ˨ÜáÂñ… Ë»ÜÊÝíñÜÃÜ Gí¨ÜÃæà®Üá Ë»ÜÊÝíñÜÃÜÊÜ®Üá° AÙæ¿áÆá ŸÙÜÓÜáÊÜ

E±ÜPÜÃÜ|ÊÜ®Üá° ÖæÓÜÄÔ. D E±ÜPÜÃÜ|ÊÜ®Üᰠ˨ÜáÂñ…ÊÜáívÜƨÜÈÉ ÖæàWæ

ÓÜí±ÜQìÓܸæàPÜá

83-K 7 CCE RF

»ÝWÜ & B
( ÃÜÓÝ¿á®Ü ËþÝ®Ü )
VII. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ A¥ÜÊÝ A±Üä|ì ÖæàÚPæWÜÚWæ ®ÝÆáR ±Ü¿Þì¿á EñܤÃÜWÜÙÜ®Üá°
¯àvÜÇÝX¨æ. AÊÜâWÜÙÜÈÉ ÓÜãPܤÊÝ¨Ü Jí¨Üá EñܤÃÜÊÜ®Üá° BÄÔ, A¨ÜÃÜ PÜÅÊÜÞûÜÃܨæãvÜ®æ
±Üä|ì EñܤÃÜÊÜ®Üá° ŸÃæÀáÄ 2×1=2

14. GÃÜvÜá A¥ÜÊÝ ÖæaÜác ±ÜÅ£ÊÜñÜìPÜWÜÚí¨Ü Jí¨æà Eñܳ®Ü° EípÝWÜáÊÜ ÃÝÓÝ¿á¯PÜ
QÅÁá¿á Ë«ÜÊæí¨ÜÃæ

(A) ÃÝÓÝ¿á¯PÜ Ë»Üg®æ

(B) ÃÝÓÝ¿á¯PÜ ÓÜíÁãàWÜ

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