Tamil Nadu 12th Std Model Question Paper Statistics

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3319 (NS)
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PART - III
¦Òΰ¯À / STATISTICS
( uªÌ ©ØÖ® B[Q» ÁÈ / Tamil & English Version)

Põ» AÍÄ : 3.00 ©o ÷|µ® ] [ ö©õzu ©v¨ö£sPÒ : 70
Time Allowed : 3.00 Hours ] [Maximum Marks : 70

AÔÄøµPÒ : (1) AøÚzx ÂÚõUPЮ \›¯õP £vÁõQ EÒÍuõ GߣuøÚ
\›£õºzxU öPõÒÍÄ®. Aa_¨£vÂÀ SøÓ°¸¨¤ß AøÓU
PsPõo¨£õÍ›h® EhÚi¯õPz öu›ÂUPÄ®.
(2) }»® AÀ»x P¸¨¦ ø©°øÚ ©mk÷© GÊxÁuØS®
AiU÷PõikÁuØS® £¯ß£kzu ÷Ásk®. £h[PÒ ÁøµÁuØS
ö£ß]À £¯ß£kzuÄ®.

Instructions : (1) Check the question paper for fairness of printing. If there is any lack of
fairness, inform the Hall Supervisor immediately.
(2) Use Blue or Black ink to write and underline and pencil to draw diagrams.

£Sv & I / PART - I

SÔ¨¦ : (i) AøÚzx ÂÚõUPÐUS® Âøh¯ÎUPÄ®. 15x1=15

(ii) öPõkUP¨£mkÒÍ ©õØÖ ÂøhPÎÀ ªPÄ® Hئøh¯ Âøhø¯z
÷uº¢öukzxU SÔ±mkhß Âøh°øÚ²® ÷\ºzx GÊuÄ®.
Note : (i) Answer all the questions.
(ii) Choose the most appropriate answer from the given four alternatives and
write the option code and the corresponding answer.

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3319 (NS) 2

1. J¸ P¸- x - ÷ PõÒ ÷\õ- u - ø Ú- ° À H0 : µ 0 =45, H 1 : µ 0 < 45 Gß- £ - u ØS HØ£
|hzu¨£k® ÷\õ-uøÚ :
(A) J¸ •øÚ ÷\õ-u-øÚ (B) Chx •øÚ ÷\õ-u-øÚ
(C) Á»x •øÚ ÷\õ-u-øÚ (D) C¸ •øÚ ÷\õ-u-øÚ
The hypothesis testing problem H0 : µ0=45 against H1 : µ0 < 45 be categorized as :
(a) one-tailed (b) left-tailed
(c) right-tailed (d) two-tailed

2. Pm-ißø© TÖ-PÒ n Eøh-¯ øP&ÁºUP ÷\õ-u-øÚ-°ß ©õ-Ö-£õk :
(A) n − 2 (B) n (C) n − 1 (D) 2n
If n is the degree of freedom of Chi-square distribution, then its variance is :
(a) n−2 (b) n (c) n−1 (d) 2n

3. 16 EÖ¨-¦-PÒ öPõsh Áõ´¨¦ ©õ-v-›-°ß ©õ-Ö-£õk 196 GÛÀ vm-h¨ ¤øÇ :

14 14 7
(A) 2
(B) 16 (C) 2 (D) 7
If a random sample of 16 observations has variance 196, then standard error is :
14 14 7
(a) (b) (c) (d) 7
2 16 2

4. 5 |hzx •øÓ-P-Ю ©Ø-Ö® 4 öuõ-S-v-P-Ю öPõsh C¸ ÁÈ £õ-S-£õm-iÀ
¤øÇ-P-ÐU-PõÚ Pm-ißø© TÖ :
(A) 15 (B) 12 (C) 19 (D) 16
In two-way classification with 5 treatments and 4 blocks, the degrees of freedom due
to error is :
(a) 15 (b) 12 (c) 19 (d) 16

5. ©õ-Ö-£õmk £S¨-£õ´-ÂÀ ©õ-v-› ÂÁ-µ[-PÒ :
(A) \©-©Ø-Ó-øÁ (B) JßøÓ JßÖ \õº¢-u-øÁ
(C) \õº-£Ø-Ó-øÁ (D) \©®
In ANOVA, the sample observations are :
(a) unequal (b) dependent
(c) independent (d) equal

3 3319 (NS)

6. r=±1 GÛÀ C¢u Jm-k-Ó-øÁ¨ ¤ß-Á-¸-©õÖ TÓ-»õ® :
(A) Gvº Jm-k-Ó-Ä (B) •Êø©-¯õÚ ÷|º Jm-k-Ó-Ä
(C) •Ê-ø©-¯õÚ Gvº Jm-k-Ó-Ä (D) ÷|º Jm-k-Ó-Ä
If r=±1, then the correlation is called :
(a) negative correlation (b) perfect positive correlation
(c) perfect negative correlation (d) positive correlation

7. ©õ-Ô-PÒ x ©Ø-Ö® y &ß Jm-k-Ó-ÄU öPÊU-PÒ \©a-^º GÛÀ :
(A) γxy ≠ γyx (B) γxy=γyx (C) γxy > γyx (D) γxy < γyx
The correlation coefficient of x and y is symmetric, hence :
(a) γxy ≠ γyx (b) γxy=γyx (c) γxy > γyx (d) γxy < γyx

8. bxy > 1 GÛÀ byx Gß-£x :
(A) < 1 (B) 1 (C) 0 (D) > 1
If bxy > 1 then, byx is :
(a) < 1 (b) 1 (c) 0 (d) >1

− −
9. x =7.875, y =27.5, byx=2.098 GÛÀ x &ß «uõÚ y &ß Ehß öuõhº¦a \©ß£õk :
∧ ∧
(A) y=27.5x+10.98 (B) y=7.875x+27.5
∧ ∧
(C) y=2.098x+10.98 (D) y=2.098x+27.5
− −
If x =7.875, y =27.5, byx=2.098, then the regression equation of y on x is :
∧ ∧
(a) y=27.5x+10.98 (b) y=7.875x+27.5

∧ ∧
(c) y=2.098x+10.98 (d) y=2.098x+27.5

10. Põ-»z öuõ-hº Á›-ø\-°À SÖ-Q-¯Põ» ©õ-Ö-£õ-k öuõ-hº-¦-øh¯ ¤›-Áõ-Úx :
(A) }sh Põ» ÷£õU-S (B) _ÇÀ ©õ-Ö-£õ-k
(C) -J-Ê[-PØÓ ©õ-Ö-£õ-k (D) £¸-Á-Põ» ©õ-Ö-£õ-k
The component having primary use for short-term forecasting is :
(a) trend (b) cyclical variation
(c) irregular variation (d) seasonal variation

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3319 (NS) 4

11. Põ- » z- ö uõ- h º Á›- ø \- ° ß TÖ- P Ò T, S, C ©Ø- Ö ® I EÒÍ- h U- Q - ¯ Tmk
ÁiÁø©¨¦ :
(A) Y=T×S×C+I (B) Y=T×S×C×I
(C) Y=T+S+C+I (D) Y=T×S+C×I
An additive model of time series with components T, S, C and I is :
(a) Y=T×S×C+I (b) Y=T×S×C×I
(c) Y=T+S+C+I (d) Y=T×S+C×I

12. SÇ¢øu ö£Ø- ö Ó- k U- S ® Á¯- x - ø h- ¯ ö©õzu ö£s- P - Î ß Gs- o UøP
£¯ß-£-kz-u¨-£-k® Ch® :
(A) ©U-PÒ öuõøP Áͺa-]
(B) ö\¨-£-Û-hõ ¤Ó¨¦ ÂQ-u®
(C) ö£õx P¸-Ä-Ö-uÀ ÂQ-u®
(D) Á¯-øuU SÔzu P¸-Ä-Ö-uÀ ÂQ-u®
The total number of women at child bearing age group is used to calculate :
(a) population growth
(b) crude birth rate
(c) general fertility rate
(d) age specific fertility rate

13. ÁõÌ-{-ø»U SÔ-±-k AÍ-Â-k-Áx :
(A) ö£õ-x-ÁõÚ P¸-Ä-Ö-uÀ ÂQ-u®
(B) ¤Ó¨¦ & CÓ¨¦ ÂQ-u®
(C) ÁõÌ-{ø» {PÌ-Âß ÂQ-u®
(D) SÇ- CÓ¨¦ ÂQ-u®
Vital Index measures :
(a) general fertility rate
(b) birth-death ratio
(c) rate of vital event
(d) infant mortality rate

14. "Põ¨-¤-°ß _øÁ' Gß-£øu AÍ-Â-hU Ti-¯ AÍÄ :
(A) ÂQu AÍ-Ä (B) ö£¯-µÍÄ AÍ-Ä
(C) -Á-›-ø\¨-£-kz-x® AÍ-Ä (D) Cøh-öÁÎ AÍ-Ä
The measurement scale of taste of coffee is :
(a) ratio (b) nominal
(c) ordinal (d) interval

5 3319 (NS)

15. \õß-Óõ-uõ-µ¨ £S-v-°À Aø©¢-v-¸¨-£øÁ :
(A) ¤Ø-÷\ºU-øP-PÒ ©Ø-Ö® SÔ-±-k-PÒ
(B) AiU-S-Ô¨-¦-PÒ
(C) -¡Ø-£m-i-¯À
(D) ÷©Ø-T-Ô¯ AøÚz-x®
The reference section contains :
(a) Appendix and Index
(b) Foot-notes
(c) Bibliography
(d) All of the above

£Sv & II / PART - II
SÔ¨¦ : H÷uÝ® BÖ ÂÚõUPÐUS Âøh¯ÎUPÄ®. AvÀ 24 &Áx
ÂÚõÄUS Pmhõ¯©õP Âøh¯ÎUPÄ®. 6x2=12
Note : Answer any six of the following. Question No. 24 is compulsory.
16. ©õ-v-›¨ £s-£ÍøÁ Gß-ÓõÀ GßÚ ?
What is Statistic ?

17. Pm-ißø© TÖ-PÒ & Áøµ-¯-ÖU-P-Ä®.
Define degrees of freedom.

18. t&£µÁ¼ß ÁøÍÁøµ¯õÚx G¢u C¸ `ǼÀ C¯À{ø»ø¯ Jzv¸UPõx ?
State the two situations for the graph of t-distribution when it is not similar to normal
distribution.

19. Jm-k-ÓÄ öPÊ-Âß ©v¨¦ +1 BP C¸¨-¤ß EÚ-x ÂÍU-Pz-øuU TÖ-P.
When the correlation coefficient is +1, state your interpretation.

20. C¸ Ehß öuõ-hº¦ öPÊU-PøÍ GÊx-P.
Write the two simple linear regression coefficients.

21. Ai¨£øh Bsøh Áøµ-¯-ÖU-P-Ä®.
Define base period.

22. SÖ-Q-¯Põ» •ß Po¨¦ Gß-£x ¯õx ?
What is short-term forecast ?

23. ö£¸[-SÊ Gß-£x GßÚ ?
What is Cohort ?

24. \µõ-\› Âø» SÔ-±m-öhs-P-Îß Áµ®-¦-P-ÎÀ Cµs-øhU TÖ-P.
State two limitations of Average Price Index.

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3319 (NS) 6

£Sv & III / PART - III
SÔ¨¦ : H÷uÝ® BÖ ÂÚõUPÐUS Âøh¯ÎUPÄ®. AvÀ 33 &Áx
ÂÚõÂØS Pmhõ¯©õP Âøh¯ÎUPÄ®. 6x3=18
Note : Answer any six of the following. Question no. 33 is compulsory.
25. J¸•øÚ ÷\õ-uøÚ, C¸•øÚ ÷\õ-uøÚ Gß-£øÁ £ØÔ ÂÍU-S-P.
Explain one-tailed and two-tailed tests.

26. 2×2 Á›ø\²øh¯ ÷|ºÄ AmhÁønUPõÚ ©õv› £s£ÍøÁa
÷\õuøÚø¯z u¸-P.
Give the test statistic for 2×2 contingency tables.

27. J¸-Á-È ©Ø-Ö® C¸ÁÈ ©õ-Ö-£õm-k¨ £S¨-£õ´-ÂøÚ J¨-¤-k-P.
Compare one-way and two-way ANOVA.

∧ ∧
28. Ehß öuõ- h º¦ \- © ß- £ õ- k - P Ò X = 64 − 0.95y , Y = 7.25 − 0.95x GÛÀ
Jm-k-Ó-ÄU öPÊ PnU-Q-k-P.
∧ ∧
If the regression equations are X = 64 − 0.95y , Y = 7.25 − 0.95x , then find the
correlation coefficient.

29. Gί Âø» \õº-¦-PÎß \µõ-\› •øÓ-°À, Tmk \µõ\› ©Ø-Ö® ö£¸US
\µõ\›°-øÚ¨ £¯ß-£-kzv Âø»U SÔ-±mk Gs-PøÍU PnU-Q-k-P.
2001 &À Âø» 2002 &À Âø»
EÖ¨-¦-PÒ
(` ) (` )
A 6 10
B 2 2
C 4 6
D 10 12
E 8 12
Compute price index number by simple average of price relatives method using
arithmetic mean and geometric mean.
Item Price in 2001 (` ) Price in 2002 (` )
A 6 10
B 2 2
C 4 6
D 10 12
E 8 12

7 3319 (NS)

30. J¸ ©õ-|-P-›À J¸ SÔ¨-¤mh Põ-»z-vÀ ¤Ó¢u SÇ¢-øu-P-Îß Gs-oUøP
15,628 BS®. A®-©õ-|-P-›À AU-Põ-»z-vØ-S-›¯ ©U-PÒ öuõøP 80,00,000 BS®.
AÆ-Áõ-Óõ-°ß, A®-©õ-|-P-›ß ö\¨-£-Û-hõ ¤Ó¨¦ ÂQ-uz-øuU Ps-k-¤-iU-P-Ä®.

The number of children born in a city during a period was 15,628 and the total
population of the city in that period was 80,00,000. Find the crude birth rate of the
city.

31. J¸ ÂÚõ¨ £m-i-¯À •øÓ-°À •ß ÷\õ-uøÚ Gß-£x GßÚ ?

What is a pre-test in the questionnaire method ?

32. J¸ |õ- n - ¯ ® 1,000 •øÓ _s- k ® ÷£õx 519 •øÓ uø» ÂÊ- Q - Ó x.
AÆÁõöÓÛÀ, 5% ªøP Põs {ø»-°À A¢-|õ-n-¯® SØ-Ó-©Ø-Ó-uõ Gß-£-øuU
Põn, P¸-x-÷PõÒ ÷\õ-uøÚ ö\´-P.

A coin is tossed 1,000 times and head turned up 519 times. Test the hypothesis at 5%
level of significance, that the coin is unbiased.

33. 1600 ©õ-n-Áº-PÒ P»¢x öPõsk JEE •uß-ø©z ÷uº-ÂÀ 525 ©õ-n-Áº-PÒ
öÁØÔ ö£Ø-Ó-Úº. uÛ¨-£-°Ø] ö£ØÓ 200 ÷£›À 180 ÷£º öÁØÔ ö£Ø-Ó-Úº.
uÛ¨-£-°Ø] ©Ø-Ö® öÁØ-Ô-P-ÐU-Q-øh-÷¯-¯õÚ £s-¦- \õº öuõ-hº-¤-øÚU
PõsP.

Out of 1600 candidates who appeared for JEE main examination, 525 were successful.
200 had attended a coaching class and of these, 180 came out successful. Test for the
association of attributes attending the coaching class and success in the examination.

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3319 (NS) 8

£Sv & IV / PART - IV

SÔ¨¦ : AøÚzx ÂÚõÂØS® Âøh¯ÎUPÄ®. 5x5=25
Note : Answer all the questions.

34. (A) J¸ £¢- x - • øÚ ÷£- Ú õ- Â ß Põ- » ®, Ax öuõ- h ºa- ] - ¯ õP GÊ- x ® }Í
AÍøÁ¨ ö£õ-¸z-ux. \©-Áõ´¨¦ •øÓ-°À ©õ-v-›-¯õP GkU-P¨-£mh
A ÁøP ÷£ÚõUPÒ 80 &ß Tk-uÀ GÊ-x® vÓß 96.84 Q.«. ©Ø-öÓõ¸
©õ-v-›-¯õÚ B ÁøP ÷£-ÚõU-PÒ 75 &ß Tk-uÀ G-Ê-x®- v-Óß 93.75 Q.«.
GÊ- x ® vÓÛÀ C¸ ÁøP ÷£ÚõU- P - Î - ¾ ®, Auß vmh »U- P ®
0.15 Q.«. GÚU öPõs-hõÀ B ÁøP ÷£ÚõU-P-Îß \µõ-\› GÊ-x® vÓß,
A ÁøP ÷£-ÚõUPøÍ Âh Av-P® EÒÍx GßÓ AÝ-©õ-Úz-vß ÷£›À
E£-÷¯õ-Q¨-£õͺ B ÁøP ÷£-ÚõU-PøÍz öu›-Ä ö\´-Áõ-µõ Gß-£øu
1% ªøPPõs {ø»-°À ÷\õ-uøÚ ö\´-P.
AÀ»x
(B) £¢x •øÚ¨ ÷£ÚõU- P Ò EÒÍ 100 ö£m- i - P Ò EÒÍÚ. JÆ- ö Áõ¸
ö£m-i-°-¾® EÒÍ £Ê-u-øh¢u ÷£-ÚõU-P-Îß Gs-oU-øP-°ß £µ-ÁÀ
RÌU-Ps-h-ÁõÖ uµ¨-£m-kÒÍ-x.
x 0 1 2 3 4 5
f 61 14 10 7 5 3

öPõ-kU-P¨-£mh uµ-ÂØS £õ´-\õß £µ-ÁÀ ö£õ-¸z-x-uÀ EP¢-u-uõ Gß-£øu
5% ªøP Põs {ø»°À ÷\õ-vU-P.
(a) A machine assesses the life of a ball point pen by measuring the length of a
continuous line drawn using the pen. A random sample of 80 pens of Brand A
have a total writing length of 96.84 km. Random sample of 75 pens of Brand B
have a total writing length of 93.75 km. Assuming that the standard deviation
of the writing length of a single pen is 0.15 km for both brands, can the consumer
decide to choose Brand B pens assuming that their average writing length is
more than that of Brand A pens ? Set level of significance as 1%.
OR
(b) A packet consists of 100 ball pens. The distribution of the number of defective
ball pens in each packet is given below :
x 0 1 2 3 4 5
f 61 14 10 7 5 3
Examine whether Poisson distribution is appropriate for the above data at 5%
level of significance.

9 3319 (NS)

35. (A) £ÒÎ A ©Ø- Ö ® B &°- ¼ - ¸ ¢x Áõ´¨¦ •øÓ- ° À ö£Ó¨- £ mh
©õnÁºPÎß ©v¨-ö£s-PÒ ¤ß-Á-¸-©õÖ :
£ÒÎ A 63 72 80 60 85 83 70 72 81
£ÒÎ B 86 93 64 82 81 75 86 63 63
£ÒÎ A ©õ- n - Á º- P - Î ß ©v¨- ö £s- P - Î ß ©õ- Ö - £ õmk AÍøÁ
£ÒÎ B ©õ- n - Á º- P - Î ß ©v¨- ö £s- P - Î ß ©õÖ£õmk AÍøÁ ÂhU
SøÓÁÚuõ ? α=5% Gß-P.
AÀ»x
(B) uÛ |£º-P-Îß E¯º Cµzu AÊz-uzøuU SøÓ¨-£-uØ-Põ-P AÁº-P-ÐUS
‰ßÖ öÁÆ- ÷ ÁÖ ~m- £ [- P Ò •øÓ- ÷ ¯ ©¸¢- u - Î z- u À, EhØ- £ - ° Ø]
©Ø-Ö® ]Ó¨¦ EnÄ BQ-¯øÁ Áõ´¨¦ •øÓ-°À AÎU-P¨-£-k-Qß-Óx.
|õßS Áõ-µ[-P-ÐUS¨ ¤ß AÁº-P-Îß Cµzu AÊz-u® £›÷\õvUP¨£mk
£v-Ä ö\´-¯¨-£mk RÌU-Põ-q® Am-h-Á-øn-°À öPõ-kU-P¨-£m-kÒÍx.
‰ßÖ öÁÆ- ÷ ÁÖ ~m- £ [- P - Î - Ú õÀ uÛ |£º- P - Î ß Cµzu AÊzu
\µõ-\-›-P-ÐU-Q-øh÷¯ H÷u-Ý® SÔ¨-¤-hz-uUP Âz-v-¯õ-\® HØ-£m-kÒÍuõ
GÚ 5% ªøP Põs {ø»-°À ÷\õ-vUP :
©¸¢-u-Îz-uÀ 10 12 9 15 13
EhØ-£-°Ø] 6 8 3 0 2
]Ó¨¦ En-Ä 5 9 12 8 4
(a) The following table gives the random sample of marks scored by students in two
Schools A and B.
School A 63 72 80 60 85 83 70 72 81
School B 86 93 64 82 81 75 86 63 63
Is the variance of the marks of students in School A less than that of those in
School B ? Test at 5% level of significance.
OR
(b) Three different techniques namely medication, excercises and special diet are
randomly assigned to (individuals diagnosed with high blood pressure) lower
the blood pressure. After four weeks, the reduction in each person's blood pressure
is recorded. Test at 5% level, whether there is significant difference in mean
reduction of blood pressure among the three techniques.
Medication 10 12 9 15 13
Excercise 6 8 3 0 2
Diet 5 9 12 8 4

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3319 (NS) 10

36. (A) ¤ß-Á-¸® uµ-Ä-P-ÐUS PõºÀ ¤¯º-\õ-Ûß Jm-k-Ó-ÄU öPÊ-øÁ PnU-Qmk
ÂÍU-P® u¸-P.
x 9 8 7 6 5 4 3 2 1
y 15 16 14 13 11 12 10 8 9

AÀ»x
(B) ¦Ò-Î-°-¯-¼ß \µõ-\› ©v¨-ö£s- 80. B[-Q-»z-vß \µõ-\› ©v¨-ö£s 50.
¦Ò-Î-°-¯-¼ß vmh »UP ©v¨-ö£s 15. B[-Q-»z-vß vmh »UP
©v¨ö£s 10 ©Ø-Ö® Jm-k-Ó-ÄU öPÊ 0.4 GÚ öPõ-kU-P¨-£m-kÒÍx.
B[Q»zvÀ 60 ©v¨- ö £s ö£Ö® ©õ- n - Á ß ¦Ò- Î - ° - ¯ - ¼ À ö£Ö®
©v¨ö£sønU Põs-P.
(a) Calculate the Karl Pearson's Coefficient of correlation for the following data and
interpret.

x 9 8 7 6 5 4 3 2 1
y 15 16 14 13 11 12 10 8 9

OR
(b) Given the following data, estimate the marks in Statistics obtained by a student
who has scored 60 marks in English.
Mean of marks in Statistics is 80, Mean of marks in English is 50, S.D. of marks in
Statistics is 15, S.D. of marks in English is 10 and coefficient of correlation is 0.4.

37. (A) RÌU-Psh uµ-Ä-P-ÐUS RÌU-Psh AÍÄ SÔ-±m-öhs-PøÍU PõsP.
(i) »õì-¤-¯-›ß AÍÄ SÔ-±m-öhs
(ii) £õ-]-°ß AÍÄ SÔ-±m-öhs
(iii) ¤å-›ß AÍÄ SÔ-±m-öhs

1970 1980
ö£õ¸mPÒ
Âø» (`) ö©õzu ©v¨¦ Âø» (`) ö©õzu ©v¨¦
A 10 80 11 110
B 15 90 9 108
C 8 96 17 340

AÀ»x

11 3319 (NS)

(B) J¸ |õm-Põmi Bs-iÀ J¸ |P-µz-vÀ EÒÍ ö£s-P-Îß GsoUøP²®
¤Ó¢u SÇ¢- ø u- P - Î ß Gs- o U- ø P- ² ® £Ø- Ô ¯ £vÄ ö\´- ¯ ¨- £ mh
ÂÁ-µ® RÌU-Psh Am-h-Á-øn-°À uµ¨-£m-kÒÍx. Cz-u-P-ÁÀ-P-Î-¼-¸¢x
ö£õx P¸-Ä-Ö-uÀ ÂQ-uz-øu-²®, Á¯-x SÔzu P¸-Ä-Ö-uÀ ÂQ-u[PøͲ®
PnU-Q-kP.

Á¯x Bs-k-P-ÎÀ 15-20 20-25 25-30 30-35 35-40 40-45 45-50

ö£s-P-Îß Gs-oU-øP 1,276 3,253 5,628 7,345 6,901 4,253 3,957

¤Ó¨-¦-P-Îß Gs-oU-øP 218 361 693 1,305 1,031 634 390

(a) Compute the following quantity indices from the data given below :

(i) Laspeyre's quantity index

(ii) Paasche's quantity index

(iii) Fisher's quantity index

1970 1980
Commodity
Price (` ) Total value Price (` ) Total value
A 10 80 11 110
B 15 90 9 108
C 8 96 17 340

OR

(b) The following are the information registered about the number of live births and
the female population size in a town during a calender year :

Age group
15-20 20-25 25-30 30-35 35-40 40-45 45-50
(in years)
No. of Women 1,276 3,253 5,628 7,345 6,901 4,253 3,957
No. of Live Births 218 361 693 1,305 1,031 634 390

Calculate the general fertility rate of the town and the age specific fertility rate
for the year.

[ v¸¨¦P / Turn over

3319 (NS) 12

38. (A) C¢-v-¯õ-Âß ÷u°-ø» EØ-£zv ¤ß-Á-¸-©õÖ 4 Á¸-h |P-¸® \µõ-\-›-PøÍU
PnU-Q-k-P.

Á¸-h® 1993 1994 1995 1996 1997 1998 1999 2000 2001 2002
EØ-£zv
464 515 518 467 502 540 557 571 586 612
(hß-P-ÎÀ)

÷£õUS ©v¨-¦-PøÍ J¨-¤mk ÂÁõ-vU-P.
AÀ»x
(B) ¤ß-Á-¸®- Â-Á-µ[-P-ÐU-S «a-]Ö ÁºUP •øÓ-°À ÷£õUS ÷Põmøh
ö£õ-¸z-x-P.

Á¸-h® 1983 1984 1985 1986 1987 1988

ÂØ-£øÚ
3 8 7 9 11 14
(` C»m-\[-P-ÎÀ)

2000 &Bs-iß ÷£õU-S ©v¨-ø£U Põs-P.
(a) The production of Tea in India is given as follows. Calculate the four-yearly
moving averages.

Year 1993 1994 1995 1996 1997 1998 1999 2000 2001 2002
Production
464 515 518 467 502 540 557 571 586 612
(tonnes)

Compare the trend values and discuss.
OR
(b) Fit a straight line trend by method of least squares for the following data :

Year 1983 1984 1985 1986 1987 1988
Sales
3 8 7 9 11 14
(` in Lakhs)

Find the trend value for the year 2000.

-oOo-