aglasem.com
Schools Admission Mock Test Playground
ClassChoose class
StateSelect state

Rajasthan Board 10th Model Paper 2022 Maths

Download the Rajasthan Board 10th Model Paper 2022 Maths PDF for free at AglaSem. Designed as per the latest Rajasthan Class 10 exam pattern and marking scheme, this sample paper lets you practise likely questions, manage time and self-assess before the exam. More Detail
Rajasthan Board 10th Model Paper 2022 Maths - Page 1 of 11

Finished viewing? Save it for later —

Download Rajasthan Board 10th Model Paper 2022 Maths (PDF · 11 pages)
Downloaded 28 times

About Rajasthan Board 10th Model Paper 2022 Maths

Rajasthan Board 10th Model Paper 2022 Maths is available here for free download. Published by Rajasthan Board for Class 10, this sample paper can be viewed online or downloaded as a PDF (11 pages). Candidates preparing for Class 10 can use Rajasthan Board 10th Model Paper 2022 Maths to understand the exam pattern, the type of questions asked, and the overall difficulty level.

Frequently Asked Questions

How can I download Rajasthan Board 10th Model Paper 2022 Maths?

Open this page and click the Download button to save Rajasthan Board 10th Model Paper 2022 Maths as a PDF. It is completely free on AglaSem Docs.

Is Rajasthan Board 10th Model Paper 2022 Maths free to download?

Yes. Rajasthan Board 10th Model Paper 2022 Maths can be viewed online and downloaded as a PDF free of cost on AglaSem Docs.

How many pages does Rajasthan Board 10th Model Paper 2022 Maths have?

Rajasthan Board 10th Model Paper 2022 Maths contains 11 pages, which you can read online or download together as a single PDF.

Where can I find more Class 10 study material?

You can find more Class 10 question papers, sample papers, syllabus, and answer keys on AglaSem Docs.

Rajasthan Board 10th Model Paper 2022 Maths – Text

Read the full text of this sample paper below — useful to quickly search, copy and reference the content online without downloading the PDF.

📄 View text version (11 pages)

Page 1

iz’u&i= dh ;kstuk

d{kk & 10th
fo"k; &xf.kr
vof/k & 2 ?k.Vs 45 feuV iw.kkZad & 80
1- mn~ns'; gsrq vadHkkj &
Ø-l-a mn~ns'; vadHkkj izfr'kr
1- Kku 25 31.25
2- vocks/k 30 37-50
3- vfHkO;fDr 15 18-75
4- ekSfydrk 10 12-50
;ksx 80 100%

2- iz'uksa ds izdkjokj vadHkkj &
Ø- iz'uksa dk izdkj iz'uksa dh vad izfr dqy vad izfr'kr izfr'kr laHkkfor
la- la[;k iz'u iz'uksa dk le;
1- oLrqfu"B 18 1 18 (22.50%) 36 35
2- vfry?kwÙkjkRed 12 1 12 (15%) 24 25
3- y?kwÙkjkRed& I 13 2 26 (32.5%) 26 45
4- y?kwÙkjkRed & II 4 3 12 (15%) 08 30
5- fuca/kkRed 3 4 12 (15%) 06 30
;ksx 50 80 (100%) 100 165

fodYi ;kstuk % vkUrfjd
3- fo"k; oLrq dk vadHkkj &
Ø-l-a fo"k; oLrq vadHkkj izfr'kr
1 ¼1½ okLrfod la[;k,a 04 5%
2 ¼2½ cgqin 05 6.25%
3 ¼3½ nks pjks okys jSf[kd lehdj.k ;qXe 09 11.25%
4 ¼4½ f}?kkr lehdj.k 05 6.25%
5 ¼5½ lekUrj Js.kh 09 11.25%
6 ¼11½ jpuk,¡ 11 13.75%
7 ¼7½ funsZ’kkad T;kfefr 06 7.5%
8 ¼8½ f=dks.kfefr ifjp; 12 15%
9 ¼14½ lkaf[;dh 15 18.75%
10 ¼15½ izkfidrk 04 5%
;ksx %& 80 100%

Page 2

CY;w fizUV
d{kk & X fo"k; %& xf.kr iw.kkZad & 80
Ø- mÌs'; bdkbZ@mi Kku vocks/k Kkuksi;ksx@vfHkO;fDr dkS'ky@ekSfydrk ;ksx
la- bdkbZ

y?kq mRrjkRed

y?kq mRrjkRed

y?kq mRrjkRed

y?kq mRrjkRed
nh?kZmRrjh;
nh?kZmRrjh;

nh?kZmRrjh;

nh?kZmRrjh;
fucU/kRed

fucU/kRed

fucU/kRed

fucU/kRed
oLrqfu"B

vfr-y?kq

vfr-y?kq

vfr-y?kq

vfr-y?kw
oLrqf"B

oLrqf"B

oLrqf"B
1 okLrfod
1¼1½ & & & & & & 2¼1½ & & & & & & & & 1¼1½ & & & 4¼3½
la[;k,a
2 cgqin & 1¼1½ & & & 1¼1½ & & & & & 1¼1½ 2¼1½ & & & & & & & 5¼4½
3 nks pjks okys
jSf[kd
1¼1½ & & & & & & & & & 1¼1½ & & & & & 1¼1½ 2¼1½ & 4¼1½ 9¼5½
lehdj.k
;qXe
4 f}?kkr & 1¼1½ 2¼1½ & & 1¼1½ & & & & & 1¼1½ & & & & & & & & 5¼4½
lehdj.k
5 lekUrj Js.kh 1¼1½ & & & & & & 2¼1½ & & & & 2¼1½ & & 1¼1½ & & 3¼1½ & 9¼5½
6 jpuk,¡ & & & & & 1¼1½ & & & & 1¼1½ & 2¼1½ & & & 1¼1½ 2¼1½ & 4¼1½ 11¼6½
7 funsZ’kkad
1¼1½ 1¼1½ & & & & & & & & & & & 3¼1½ & 1¼1½ & & & & 6¼4½
T;kfefr
8 f=dks.kfefr & & 2¼1½ 3¼1½ & 1¼1½ 1¼1½ 2¼1½ & & 1¼1½ 1¼1½ & & & 1¼1½ & & & & 12¼8½
ifjp;
9 lkaf[;dh 1¼1½ & & & & & & & 3¼1½ & 1¼1½ & 2¼1½ & 4¼1½ 1¼1½ 1¼1½ 2¼1½ & &15¼8½
10 izkfidrk & & 2¼1½ & & 1¼1½ 1¼1½ & & & & & & & & & & & & 14¼3½
;ksx %& 5¼5½ 3¼3½ 6¼3½ 3¼1½ & 5¼5½ 2¼2½ 6¼3½ 3¼1½ & 4¼4½ 3¼3½ 8¼4½ 3¼1½ 4¼1½ 4¼4½ 4¼4½ 6¼3½ 3¼1½ 8¼2½ 80¼50½
fodYiksa dh ;kstuk %& iz-la- 17 ls 23 esa ,dkfUrd vkarfjd fodYi gS uksV%& dks"Bd esa ckgj dh la[;k vadksa dh rFkk Hkhrj iz'uksa dh |ksrd gSA

gLrk{kj

Page 3

ek/;fed f'k{kk cksMZ jktLFkku]vtesj
ekWMy iz’u i= ek/;fed ijh{kk 2022
fo"k;& xf.kr
d{kk&10
le;% 2 ?k.Vs 45 feuV iw.kkZad%80

ijh{kkfFkZ;ksa ds fy, lkekU; funZs'k %&

GENERAL INSTRUCTION TO THE EXAMINEES:

1- ijh{kkFkhZ loZizFke vius iz'u i= ij ukekad vfuok;Zr% fy[ksaA

Candidate must write first his/her Roll No. on the question paper
compulsorily.
2- lHkh iz'u djus vfuok;Z gSA

All the questions are compulasory.
3- izR;sd iz'u dk mÙkj nh xbZ mÙkj iqfLrdk esa gh fy[ksaA
Write the answer to each question in the given answer book only.
4- ftu iz'uksa esa vkUrfjd [k.M gS mu lHkh ds mÙkj ,d lkFk gh fy[ksaA
For questions having more than one part the answers to those parts are to be
written together in continuity.
5- iz'u i= ds fgUnh ij vaxzsth :ikUrj.k esa fdlh izdkj dh =qfV@ vUrj@fojks/kkHkkl gksus ij
fgUnh Hkk"kk ds iz'u dks lgh ekusAa

If there is any error/difference/contradiction in Hindi & English version of the
question paper, the question of the Hindi version should be treated valid.

Page 4

¼[k.M v½
oLrqfu"B iz'u
iz'u&01 fuEu iz'uksa ds mRrj dk lgh fodYi p;u dj mRrj iqfLrdk esa fyf[k, %&
(i) ifjes; la[;k 129 dk n’keyo izlkj gS& 1
25 X 5 7 X 57

¼v½ lkar ¼c½ vlkar ¼l½ vlkar vko`fÙk ¼n½ vlkar vuko`fÙk

Decimal Expansion of Rational Number 129
2 X 57 X 57
5

(A) Terminating (B) Non Terminating
(C) Non Terminating Repeating (D) Non Terminating Non Repeating

(ii) fuEu esa ls ,d f}?kkr cgqin ugha gS& 1
¼v½ X2 ¼c½ X2- 4 ¼l½ X – 4X+4
2
¼n½ X –3X +3X -1
3 2

One of these is not a quadratic polynomial.
¼A½ X2 ¼B½ X2- 4 ¼C½ X2 – 4X+4 ¼D½ X3–3X2 +3X -1

(iii) fuEu jSf[kd lehdj.k ;qXe ds gy gS X+Y = 4, X-Y = 2 1
¼v½ X=3 Y=1 ¼c½ X=1 Y=3 ¼l½ X=Y =2 ¼n½ X=4 Y=0

Which is the solution of linear pair equation X+Y = 4, X-Y = 2
¼A½ X=3 Y=1 ¼B½ X=1 Y=3 ¼C½ X=Y =2 ¼D½ X=4 Y=0

(iv) fuEufyf[kr esa ls dkSu f}?kkr lehdj.k dks gy djus dh ,d fof/k gS& 1
¼v½ xq.ku[k.M fof/k ¼c½ iw.kZ oxZ fof/k ¼l½ f}?kkr lw= ¼n½ mijksDr lHkh

Which one of method use to solve quadratic equation -
¼A½ Factorisation ¼B½ Perfect Square ¼C½ Quadratic formula ¼D½ All Above

(v) lekUrj Js.kh 4]10]16] 22-------------------- dk izFke in vkSj lkoZvUrj D;k gksxk& 1
¼v½ ¼10] 5½ ¼c½ ¼4] 6½ ¼l½ ¼4] 10½ ¼n½ ¼6] 10½

Which is the first term and common difference for AI 4, 10, 16, 22.................
¼A½ (10, 5) ¼B½ (4, 6) ¼C½ (4, 10) ¼D½ (6, 10)

(vi) 3-5 lseh f=T;k okys o`Ùk dk O;kl gksxk& 1
¼v½ 6 lseh ¼c½ 7 lseh ¼l½ 8-5 lseh ¼n½ buesa ls dksbZ ugha

Radius of a circle is 3.5 cm then Dimeter of circle is -
¼A½ 6 cm ¼B½ 7 cm ¼C½ 8.5 cm ¼D½ none of these
(vii) fcUnq ¼&3] 5½ dkSu ls prqZFkka’k esa gksxk& 1
¼v½ izFke ¼c½ f}rh; ¼l½ r`rh; ¼n½ prqFkZ

Page 5

Point (-3, 5) belongs to in which quadrant -
¼A½ First ¼B½ Second ¼C½ Third ¼D½ Fourth

(viii) tan 450 + cot 450 dk eku gksxk & 1
¼v½ 1 ¼c½ 2 ¼l½ 3 ¼n½ 0

Value of tan tan 450 + cot 450 is -
¼A½ 1 ¼B½ 2 ¼C½ 3 ¼D½ 0

(ix) cos (900-480) dk eku gksxk & 1
¼v½ sec 480 ¼c½ tan 480 ¼l½ sin 48 0
¼n½ cot 48 0

Value of cos (900-480) is -
¼A½ sec 480 ¼B½ tan 480 ¼C½ sin 480 ¼D½ cot 480

(x) fuEu esa ls ,d ek/; Kkr djus dk lw= ugha gS & 1

(v) ∑x ¼c½ ∑x + ah ¼l½ ∑fx ¼n½ ∑fd
n n N N

(x) One of these is not a formula to find mean -
(A) ∑x (B) ∑x + ah (C) ∑fx (D) ∑fd
n n N N

(xi) fuEu dk cgqyd Kkr djks & 1

x 5 7 9 11
f 4 8 6 2

¼v½ 9 ¼c½ 5 ¼l½ 7 ¼n½ 11

(xi) Find the Mode of data-
x 5 7 9 11
f 4 8 6 2

¼A½ 9 ¼B½ 5 ¼C½ 7 ¼D½ 11

(xii) fuEufyf[kr esa ls dkSulh la[;k fdlh ?kVuk dh izkf;drk ugha gks ldrh & 1
¼v½ 2/3 ¼c½ -1.5 ¼l½ 15% ¼n½ 0.7

Which of the following can not be the probability of an event -
¼A½ 2/3 ¼B½ -1.5 ¼C½ 15% ¼D½ 0.7

Q-2 Fill in the Blanks :-

fuEufyf[kr iz'uksa esa fjDr LFkkuksa dh iwfÙkZ djrs gq, mRrj iqfLrdk esa fyf[k,&

Page 6

(i) ;fn gks rks lehdj.k fudk; dk gy ------------------ gksrk gS & 1

If , then solution of linear pair of equation is ..................

(ii) l-Js- 10] 8] 6] 4 -------------------------------- dk 7ok¡ in ------------------------------ gSA 1

7th Term of AP 10, 8, 6, 4.................................... is ...................................

(iii) fdlh ckgjh fcUnq ls o`Ùk ij ------------------------------- Li’kZ js[kk,a [khaph tk ldrh gSA 1

How many tangent drawn circle from point of out site the circle ...................................

(iv) funsZ’kkad T;kfefr esa nks fcUnqvksa ds chp dh nwjh Kkr djus dk lw=----------------------- gS A 1

Find Formula for Distance between two points in a co-ordinate geometry is.................

(v) sin (900 - ) = ................................ 1

sin (900 - ) = ................................

(vi) caVu 7]4]6]3]8]5]9 dh ekf/;dk ---------------------------------------------- gksxhA 1

Median of distribution 7,4,6,3,8,5,9 is ..................................

Hkkx & v
PART – A
iz'u la- 03 vfry?kqrjkRed iz'u ¼Very Short answer type of questions½
(i) nks la[;kvksa dk xq.kuQy 180 gS rFkk egRre lekiorZd 3 gS rks y?kqRre lekiorZd Kkr
djks \ 1

If Product of two numbers is 180 and HCF is 3 then find their LCM .

(ii) X2 +3X+1 dks X-2 ls Hkkx nsus ij 'ks"kQy Kkr dhft, \ 1

Find the reminder if X2 +3X+1 divided by X-2

(iii) cgqin X2 -6X+7 esa 'kwU;kadksa dk ;ksx vkSj xq.kuQy fyf[k, \ 1

Write the sum and product of zeroes of polynomial X2 -6X+7

(iv) nks pj okys lehdj.k fudk; dk gy vf}rh; gksus dh 'krZ fyf[k, \ 1

Page 7

Find the condition of unique solution for pair if linear equation in two variables.

(v) f}?kkr lehsdj.k 2X2 + 3X+4 =0 esa ewyksa dk ;ksx Kkr dhft, \ 1

Find the sum of roots of quadratic equation 2X2 + 3X+4 =0

(vi) f}?kkr lehsdj.k ds ewy Kkr djus ds fy;s Jh /kjkpk;Z lw= fyf[k, \ 1

Write SHREE DHARACHARYA Formula for finding roots of quadratic equation.

(vii) fdlh o`Ùk dh f=T;k vkSj ml ij [khaph xbZ Li’kZ js[kk ds e/; fdrus fMxzh dk dks.k
gksrk gS \ 1

Find the triangle between radius of a circle and tangent of circle .

(viii) funsZ’kkad ¼4] 3½ esa Hkqt vkSj dksVh Kkr dhft, \ 1

Find the abscissa and ordinate in co-ordinate (4, 3)

(ix) eku Kkr dhft, cos 300 – sin 600 1

Find the value cos 300 – sin 600

(x) ;fn sin 3x=1 rks X dk eku Kkr dhft, \ 1

If sin 3x=1 then find the value of X

(xi) caVu 10] 12] 8] 7] 13 dk ek/; Kkr djks \ 1

Find the mean of distribution 10, 12, 8, 7, 13

(xii) ;fn ,d flDds dks ,d ckj mNkyk tkrk gS rks fpr vkSj iV vkus dh laHkkouk
D;k gksxh \ 1
Find the probability of getting a head and a tail when a coin is tossed once.

Hkkx & c
PART – B
Q-4. ;wfDyM foHkktu fof/k }kjk 90 vkSj 144 dk egÙke lekiorZd Kkr dhft,A 2

Find the HCF of 90 and 144 by using EUCLID’S division method.

Q-5. f}?kkr cgqin X2 -2x-15 ds 'kwU;d Kkr dhft,A 2

Find the Zero of a quadratic polynomial X2 -2x-15 .

Page 8

Q-6. fuEu jSf[kd lehdj.k ;qXe dks foyksiu fof/k ls gy dhft,A 2
2x+y = 6, 2x-y = 2

Solve the following pair of linear equations by elimination method.
2x+y = 6, 2x-y = 2

Q-7. xq.ku[k.M fof/k ls fuEu f}?kkr lehdj.k ds ewy Kkr dhft,A 2
2
2X + X– 6 = 0
Find the roots of the following quadratic equations by factorisation.
2X2 + X– 6 = 0
Q-8. fuEufyf[kr lekarj Js.kh esa ls fdrus in gSA 2
7, 13, 19, ............................. 205

Find the number of terms of the following APs .
7, 13, 19, ............................. 205

Q-9. rhu vadksa okyh fdruh la[;k,a 7 ls foHkkT; gS \ 2

How many Three Digit numbers are divisible by 7 ?

Q-10. 5 lseh yEck ,d js[kk[k.M [khafp, vkSj bls 2 % 3 vuqikr esa foHkkftr
dhft, \ 2

Draw a line segment of length 5 cm and divide in the ration 2:3 .
0
Q-11. 5 lseh f=T;k ds ,d o`Ùk ij nks Li’kZ js[kk,a [khafp,a] tks ijLij 60 ds dks.k
ij >qdh gksAa 2

Draw a pair of tangents to a circle of radius 5 cm which are inclined to each other at an
0
angle 60

Q-12. ;fn rks cos A vkSj tan A dk eku ifjdfyr dhft,A 2

If calculate cos A and tan A .

Q-13. fuEufyf[kr dk eku fudkfy,A 2
2 tan2 450 + cos2 300 – sin2 600

If Evaluate the following -
2 tan2 450 + cos2 300 – sin2 600

Q-14. fuEu caVu dk ek/; Kkr dhft,A 2

izkIrkad 25 35 45 55 65
Nk=ksa dh 4 28 42 20 6
la[;k

Page 9

Find the mean of the following frequency –

Score 25 35 45 55 65
No. Of 4 28 42 20 6
Students

Q-15. fuEu caVu dk cgqyd Kkr dhft,A 2

oxZ 0&20 20&40 40&60 60&80 80&100 100&120
varjky
ckjackjrk 10 35 52 61 38 20

Find the mean of the following frequency –

Class 0&20 20&40 40&60 60&80 80&100 100&120
Interval
Frequency 10 35 52 61 38 20

Q-16. ,d FkSys esa 5 lQsn o 2 yky xsn
a s gSA bl FkSys esa ls ,d xsna ;knqPN;k fudkyh tkrh gSA
bldh D;k izkfidrk gS fd fudkyh xbZ xsna ----------------------------------- gksxh \ 2

¼A½ lQsn ¼AA½ yky

A bag contains 5 white and 2 red balls. From this bag one ball is drawn randomly. What
is the probability that drawn ball is ...............................

(i) White (ii) Red

[k.M& l
PART – C
Q-17. ;fn fdlh lekarj Js.kh ds nwljs vkSj rhljs in Øe’k% 24 rFkk 28 gks rks] Js.kh 3
ds igys 61 inksa dk ;ksxQy Kkr dhft,A
If Second and third terms of an A.P. are 24 and 28 respectively, then find the sum of first
61 terms.
vFkok @ OR
2 vkSj 101 ds e/; 5 ls foHkkftr ¼HkkT;½ gksus okyh lHkh izkd`r la[;kvksa dk 3
;ksxQy Kkr dhft,A
Find the sum of all natural numbers divisible by 5 between 2 and 101 .

Q-18. X &v{k ij og fcUnq Kkr dhft, tks fcUnqvksa ¼&2] 3½ vkSj ¼&3] 4½ ls leku nwjh 3
ij fLFkr gSA
Find the point on X-Axis which is equidistant from the point (-2, 3) and (-3, 4)

vFkok @ OR

fcUnqvksa ¼11] 8½ vkSj ¼1] 3½ dks feykus okyh js[kk dks fcUnq ¼7] 6½ fdl vuqikr esa 3

Page 10

foHkkftr djrk gSA
In which ratio, point (7, 6) divides the line joining the points (11, 8) and (1, 3) .

Q-19.
Sin 170 Cos 670 Sin 150
5 + 2 - 6 dk eku Kkr dhft,A 3
5 Cos 730 Sin 230 Cos 750
5

Sin 170 Cos 670 Sin 150
Find the value of 5 + 2 - 6
0 0
5 Cos 73 Sin 23 Cos 750
5
vFkok @ OR

fl) dhft, & cos4 + sin4 = 1-2 cos2 sin2 3
4 4 2
Prove that - cos + sin = 1-2 cos sin2

Q-20. fuEu ckjEckjrk caVu dk ek/; Kkr dhft,A 3

oxZ 0&10 10&20 20&30 30&40 40&50
fi 6 10 13 7 4

Find the mean of the following frequency distribution –

Class 0&10 10&20 20&30 30&40 40&50
fi 6 10 13 7 4

vFkok @ OR

fuEu ckjEckjrk caVu dk cgqyd Kkr dhft,A 3

oxZ 10&25 25&40 40&55 55&70 70&85 85&100
fi 6 20 44 26 3 1

Find the Mode of the following frequency distribution –

Class 10&25 25&40 40&55 55&70 70&85 85&100
fi 6 20 44 26 3 1

[k.M& n
PART – D
Q-21. fuEu jSf[kd lehdj.k ;qXe dks vkys[kh; fof/k }kjk gy dhft,A 4
3 x – 5y = 1
2x–y =3

Page 11

Solve the following pair of linear equation by graphical method .
3 x – 5y = 1
2x–y =3
vFkok @ OR

fuEu jSf[kd lehdj.k ;qXe dks vkys[kh; fof/k }kjk gy dhft,A 4
4 x – 5y = 20
3 x + 5y = 15
Solve the following pair of linear equation by graphical method .
4 x – 5y = 20
3 x + 5y = 15

Q-22. ,d 10 lseh yEckbZ dk js[kk[k.M [khapdj mldk 2 % 3 esa foHkktu dhft,A 4

Draw a line segment at length 10 cm and divide into 2 : 3

vFkok @ OR

AB = 5 lseh yEckbZ dk ,d js[kk[k.M [khafp,A fcUnq B dks dsUnz ekudj 2-2 lseh 4
f=T;k dk o`Ùk cukb, rFkk bl o`Ùk ij fcUnq A ls Li’kZ js[kk,¡ [khafp,A
Draw a line segment AB of length 5 cm. Taking B as the centre, draw a circle of radius 2.2 cm
and draw tangents to the circle from point A.

Q-23. fuEu ckjEckjrk caVu dk ek/;d Kkr dhft,A 4

oxZ 10&25 25&40 40&55 55&70 70&85 85&100
fi 6 20 44 26 3 1

Find the medianof the following frequency distribution –

Class 10&25 25&40 40&55 55&70 70&85 85&100
fi 6 20 44 26 3 1

vFkok @ OR

fuEu ckjEckjrk caVu dk cgqyd Kkr dhft,A 4

izkIrkad 0&20 20&40 40&60 60&80 80&100
Nk=ksa dh 5 10 12 6 3
la[;k

Find the Mode of the following frequency distribution –

Score 0&20 20&40 40&60 60&80 80&100
No. of 5 10 12 6 3
Students

Document Details

Board / OrgRajasthan Board
ExamClass 10
TypeSample Paper
Pages11
Languagehindi
Updated22 Jul 2026