HBSE Class 11 Question Paper 2019 Physics

Code No. 1028
CLASS : 11th (Eleventh) Series : 11-M/2019
Roll No.











HkkSfrd foKku
PHYSICS
[ fgUnh ,oa vaxzsth ek/;e ]
[ Hindi and English Medium ]
(Only for Fresh/School Candidates)

le; : 3 ?k.Vs ] [ iw.kk±d : 70
Time allowed : 3 hours ] [ Maximum Marks : 70

• Ñi;k tk¡p dj ysa fd bl iz'u-i= esa eqfnzr i`"B 16 rFkk iz'u
21 gSaA

Please make sure that the printed pages in this
question paper are 16 in number and it contains
21 questions.

• iz'u-i= esa lcls Åij fn;s x;s dksM uEcj dks Nk= mÙkj-iqfLrdk
ds eq[;-i`"B ij fy[ksaA
The Code No. on the top of the question paper
should be written by the candidate on the front
page of the answer-book.

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(2) 1028
• Ñi;k iz'u dk mÙkj fy[kuk 'kq: djus ls igys] iz'u dk Øekad
vo'; fy[ksaA
Before beginning to answer a question, its Serial
Number must be written.

• mÙkj-iqfLrdk ds chp esa [kkyh iUuk / iUus u NksMsa+A
Don’t leave blank page/pages in your answer-book.
• mÙkj-iqfLrdk ds vfrfjDr dksbZ vU; 'khV ugha feysxhA vr%
vko';drkuqlkj gh fy[ksa vkSj fy[kk mÙkj u dkVsaA
Except answer-book, no extra sheet will be given.
Write to the point and do not strike the written
answer.

• ijh{kkFkhZ viuk jksy ua0 iz'u&i= ij vo'; fy[ksaA
Candidates must write their Roll Number on the
question paper.
• d`i;k iz'uksa dk mÙkj nsus lss iwoZ ;g lqfuf'pr dj ysa fd iz'u-i=
iw.kZ o lgh gS] ijh{kk ds mijkUr bl lEcU/k esa dksbZ Hkh nkok
Lohdkj ugha fd;k tk;sxkA
Before answering the question, ensure that you
have been supplied the correct and complete
question paper, no claim in this regard, will be
entertained after examination.

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(3) 1028
lkekU; funsZ'k %
(i) lHkh iz'u vfuok;Z gSaA
(ii) iz'ui= esa dqy 21 iz'u gSaA
(iii) iz'u la[;k 1 esa 1-1 vadksa ds pkSng (i-xiv) oLrqfu"B
iz'u lfEefyr gSaA
(iv) iz'u la[;k 2 ls 11 rd vfr-y?kwÙkjkRed iz'u gSa rFkk
izR;sd iz'u 2 vadksa dk gSA
(v) iz'u la[;k 12 ls 18 rd y?kq mÙkjh; iz'u gSa rFkk
izR;sd iz'u 3 vadksa dk gSA
(vi) iz'u la[;k 19 ls 21 rd nh?kZ mÙkjh; iz'u gSa rFkk
izR;sd iz'u 5 vadksa dk gSA
(vii) iz'ui= esa lexz :i ls dksbZ fodYi ugha gSA rFkkfi 5
vadksa okys lHkh rhuksa iz'uksa esa vkarfjd p;u iznku fd;k
x;k gSA ,sls iz'uksa esa ls vkidks dsoy ,d gh iz'u djuk
gSA
(viii)dSYD;qysVj ds mi;ksx dh vuqefr ugha gSA vko';d gksus
ij] y?kqx.kdh; lkjf.k;ksa dk iz;ksx fd;k tk ldrk gSA
General Instructions :
(i) All questions are compulsory.
(ii) There are 21 questions in all.
(iii) Question No. 1 is objective type questions.
It consists of fourteen (i-xiv) questions of 1
mark each.

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(iv) Question numbers 2 to 11 are Very Short
Answer Type Questions and carry 2 marks
each.
(v) Question numbers 12 to 18 are Short
Answer Type Questions and carry 3 marks
each.
(vi) Question numbers 19 to 21 are Long
Answer Type Questions and carry 5 marks
each.
(vii) There is no overall choice. However,
internal choice is given in all three long
answer type questions and carry 5 marks
each. You have to attempt only one of the
given choice is such questions.
(viii) Use of calculators is not permitted. If
required, you may use logarithmic tables.

1. (i) ,d fcUnq ij nks cy çR;sd 5 U;wVu ds ijLij 120°
ij gSaA bu cyksa ds lfn'k ;ksx dk ifj.kke gS % 1

(a) 'kwU; (b) 5 U;wVu
(c) 5 3 U;wVu (d) 10 U;wVu

Two forces of 5 Newton each act at a point
inclined at 120° with each other. The
magnitude of vector addition of these forces
is :
(a) Zero (b) 5 Newton
(c) 5 3 Newton (d) 10 Newton

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(ii) [kqjnjs i`"B ij j[ks 20 fdxzk ds xqVds dks Bhd pykus ds
fy, 98 U;wVu ds cy dh vko';drk iM+rh gS ?k"kZ.k
xq.kkad gksxk ¼g = 9.8 eh0/ls02½ % 1

(a) .4 (b) .5

(c) .6 (d) 'kwU;
A force of 98 N is just able to move a block
of mass 20 kg on a rough horizontal
surface. Coefficient of friction is (g = 9.8
m/sec2) :

(a) .4 (b) .5

(c) .6 (d) Zero
(iii) ;fn fdlh fi.M dk laosx rhu xquk dj fn;k tk;s] rks
mldh xfrt ÅtkZ gks tk;sxh % 1
(a) nks xquh (b) vk/kh
(c) pkj xquh (d) ukS xquh

When the momentum of body is increased
by three times, its K.E. becomes :
(a) Twice (b) Half
(c) Four times (d) Nine times

(iv) S. I. i)fr esa tM+Ro-vk?kw.kZ dk ek=d gS % 1
(a) fdxzk/ehVj2 (b) fdxzk-ehVj2
(c) fdxzk-ehVj (d) fdxzk-ehVj/ls02

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Unit of Moment of Inertia in S. I. system is :
(a) kg/meter2 (b) kg-meter2
(c) kg-meter (d) kg-meter/sec2
(v) lapkj mixzg INSAT-11B dk i`Foh ds ifjr% ifjØe.k
dky gS % 1
(a) 12 ?k.Vs (b) 24 ?k.Vs
(c) 48 ?k.Vs (d) 30 fnu

The time of revolution around the earth of
Communication Satellite INSAT-11B is :
(a) 12 hours (b) 24 hours
(c) 48 hours (d) 30 days

(vi) fdlh O;fDr }kjk fdlh dq,¡ esa ls jLlh ls ca/kh ckYVh dks
jLlh }kjk ckgj fudkyus esa fd;k x;k dk;Z /kukRed gS
;k _.kkRed \ 1
Work done by a person in lifting a bucket
out of a well by means of a rope tied to the
bucket is positive or negative ?

(vii) fdlh yksyd ds xksyd A dks] tks Å/okZ/kj ls 30° dk
dks.k cukrk gS] NksM+s tkus ij est ij fojkekoLFkk esa nwljs
xksyd B ls Vdjkrk gS tSlk fd layXu fp= esa çnf'kZr
gSA Kkr dhft, fd la?kV~V ds i'pkr~ xksyd A fdruk
Å¡pk mBrk gS \ xksydksa ds vkdkjksa dh mis{kk dhft,
vkSj eku yhft, fd la?kV~V çR;kLFk gSA 1

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(7) 1028

30°

A
m

m

B

The bob A of a pendulum released from 30°
to the vertical hits another bob B of the
same mass at rest on a table as shown in
Fig. How high does the bob A rise after the
collision ? Neglect the size of the bobs and
assume the collision to be elastic.

30°

A
m

m

B

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(viii) dSiyj ds r`rh; fu;e dk xf.krh; :i D;k gS \ 1

What is the mathematical form of Kepler's
third law ?

(ix) i`Foh ds fudV ifjØek dj jgs fdlh mixzg dk d{kh;
osx dk eku crkb,A 1

Write the value of orbital velocity of Satellite
revolving near the surface of Earth.

(x) jcM+ dh vis{kk bLikr dk ;ax-çR;kLFkrk xq.kkad vf/kd gSA
dkj.k crkb,A 1

The Young's modulus of steel is greater
than that of rubber. Give reason.

(xi) nks /ofu òksr ds ,d lkFk ctus ij] .20 lsd.M esa 2
foLiUn mRiUu gksrs gSaA foLiUn dh vko`fÙk Kkr djsaA 1
When two sound sources are sounded
together, then 2 beats are produced in .20
Second. Find the frequency of the beats.

(xii) ije 'kwU; ij fdlh xSl dh ek/; xfrt ÅtkZ fdruh
gksxh \ 1

How much will be the Kinetic Energy of a
gas at the absolute zero ?

(xiii) vkn'kZ xSl dh vkUrfjd ÅtkZ dk xSl rki ds lkFk D;k
lEcU/k gS \ 1
What is the relation of internal energy of an
ideal gas with gas temperature ?

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(xiv) D;k jsfÝtjsVj dk dk;Z xq.kkad fu;r gS \ 1

Is coefficient of performance of a
refrigerator constant ?

2. foeh; jhfr ls lehdj.k v = u + at dk ijh{k.k dhft,A 2
tgk¡ v = vfUre osx] u = vkjfEHkd osx
a = Roj.k] t = le;
Check the equation v = u + at by the method of
dimensions.
where v = Final velocity, u = Initial velocity
a = Acceleration, t = Time

3. ,d oLrq ,d fuf'pr fn'kk esa ,d fuf'pr osx ls xfr'khy gSA
bl xfr dk le;-osx ,oa le;-foLFkkiu xzkQ cukb,A 2
An object is moving in a given direction with a
definite velocity. Draw time-velocity and time-
displacement graphs for the object.

4. fØdsV dk f[kykM+h xsan dks yidrs le; vius gkFk xsan ds lkFk
ihNs dh vksj [khaprk gSA D;ksa \ 2
A cricketer moves his hands backwards while
holding a catch. Why ?

5. dksbZ cYysckt fdlh xsan dh vkjafHkd pky tks 12 ehVj/ls0
gS] esa fcuk ifjorZu fd, ml ij cy yxkdj lh/ks xsanckt dh
fn'kk esa okil Hkst nsrk gSA ;fn xsan dh lagfr .15 kg gS] rks
xsan dks fn;k x;k vkosx Kkr dhft,A 2

¼xsan dh xfr jSf[kd ekfu,½
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( 10 ) 1028
A batsman hits back a ball straight in the
direction of the bowler without changing its
initial speed of 12 ms −1 . If the mass of the ball
is .15 kg, determine the impulse imparted to the
ball. (Assume linear motion of the ball.)

6. xq#Roh; fLFkfrt ÅtkZ dh ifjHkk"kk nhft,A 2

Define Gravitational Potential Energy.

7. i`Foh dh lrg ls d xgjkbZ ij i`Foh ds xq#Roh; Roj.k ds fy,
O;atd] i`Foh ij xq#Rph; Roj.k rFkk i`Foh dh f=T;k ds :i esa
çkIr dhft,A 2

Obtain the expression for acceleration due to
gravity at depth d below the Earth's surface, in
terms of acceleration due to gravity at Earth's
surface and the radius of Earth.

8. ljy vkorZ xfr dh lehdj.k y = 5 sin 100πt ls nksyu-
vk;ke rFkk vko`fÙk ds eku crkb,A ;gk¡ foLFkkiu ehVj esa rFkk
le; lsd.M esa O;Dr gSaA 2

Find out the amplitude and the frequency from
the equation of SHM y = 5 sin 100πt. The
displacement has been expressed in meters and
the time in seconds.

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( 11 ) 1028
9. lerkih rFkk #)ks"e çØeksa esa nks vUrj fyf[k,A 2

Write two difference between Isothermal and
Adiabatic process.

10. U;wVu ds 'khryu ds fu;e dks fyf[k,A 2

Write Newton's Law of Cooling.

11. dsf'kdkRo ls vkidk D;k rkRi;Z gS \ fdlh ds'kuyh esa ty ds
mUu;u dk lw= fyf[k,A 2

What do you understand by Capillarity ? Write
down the formula for the rise of water in a
capillary tube.

12. ljy yksyd ds ,d ç;ksx esa ,d Nk= us yksyd ds vkorZdky
ds fy, dqN çs{k.k çkIr fd,A Nk= }kjk fy;s x;s çs{k.k bl
çdkj gSa % 2.63 lsd.M] 2.56 lsd.M] 2.42 lsd.M]
2.71 lsd.M rFkk 2.80 lsd.MA bu çs{k.kksa dh lgk;rk ls
fujis{k =qfV ,oa lkis{k =qfV ifjdfyr dhft,A 3

In an experiment of simple pendulum, a student
made several observations for the period of
oscillations. His reading turned out to be :
2.63 sec, 2.56 sec, 2.42 sec, 2.71 sec and 2.80
sec. With the help of above observations
calculate absolute errors and relative error.

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( 12 ) 1028
13. vfHkdsUæ cy ls vki D;k le>rs gSa \ m æO;eku dk ,d
fi.M r f=T;k okys ,d o`Ùkh; iFk ij ,d leku pky v ls
pDdj yxk jgk gSA fi.M ij vkjksfir vfHkdsUæ cy dk lw=
rFkk fn'kk fyf[k,A 3
What do you understand by Centripetal Force ?
A particle of mass m is moving in a circular orbit
of radius r with uniform speed v. Write the
formula and direction of Centripetal Force acting
on the particle.

14. n'kkZb, fd eqDr :i ls fxjrk gqvk fi.M ;kfU=d ÅtkZ ds
laj{k.k ds fu;e dh iqf"V djrk gSA 3
Show that mechanical energy of a freely falling
body justifies the Law of Conservation of
Mechanical Energy.

15. 1 xzke] 2 xzke o 3 xzke ds rhu d.k bl çdkj ls j[ks gSa fd
muls 1 ehVj Hkqtk ds ,d leckgq f=Hkqt dh jpuk gksrh gS]
rhuksa d.kksa ds bl fudk; ds æO;eku-dsUæ dh fLFkfr Kkr
dhft,A 3
Y

3 xzke

C

(0, 0) X
1 xzke 2 xzke

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( 13 ) 1028
Locate the centre of mass of a system of three
particles of masses 1 gram, 2 gram and 3 gram
placed at the corners of an equilateral triangle of
1 meter side.
Y

3 gram

C

(0, 0) X
1 gram 2 gram

16. Å"ekxfrdh ds çFke fu;e dh lgk;rk ls es;j ds lw=
C P − CV = R dk fuxeu dhft,A 3

Establish Mayer's formula C P − CV = R from
the First Law of Thermodynamics.

17. ÅtkZ lefoHkktu dk fu;e crkb,A bl fu;e dks ç;qDr djrs
gq, fn[kkb, fd vkn'kZ xSl ds fy, r = 1 + 2 ] tgk¡ f xSl ds
f
v.kqvksa dh LokrU=; dksfV;k¡ gSaA 3

State the Law of Equipartition of Energy. Prove
2
that for an ideal gas r = 1 + ] where f is the
f
number of degree of freedom of gas molecules.

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( 14 ) 1028
18. dks.kh; laosx laj{k.k dk fu;e fyf[k,A bls fdlh ,d mnkgj.k
}kjk Li"V dhft,A 3

State the Law of Conservation of Angular
Momentum. Explain it by giving any one
example.

19. ljy yksyd ds vkorZdky ds fy, O;atd çkIr dhft,A 5

Obtain an expression for the time-period of a
simple pendulum.

vFkok
vFkok
OR

vçxkeh rjax ls D;k rkRi;Z gS \ ,d [kqyh vkxZu ikbi ds fy,
fl) dhft, fd mlesa le rFkk fo"ke nksuksa çdkj dh laukfn;k¡
mRiUu gksrh gSaA
What is meant by Stationary Wave ? Prove that
in an open organ pipe, both odd and even
harmonics are produced.

20. ,d leku Rofjr xfr dh ifjHkk"kk nsaA ,d d.k ,d leku
Roj.k a ls ljy js[kk esa pyrk gSA bldk vkjfEHkd osx u gS
foLFkkiu S o vfUre osx v gSA dyu fof/k dk mi;ksx djds
fn[kkb, fd v 2 = u 2 + 2aS gksxkA 5

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( 15 ) 1028
Define uniformly accelerated motion. A particle
is moving with uniform acceleration a in a
straight path. Its initial velocity is u,
displacement S and final velocity v. Using
calculus method show that :

v 2 = u 2 + 2aS

vFkok

OR

ç{ksI; xfr esa {kSfrt ls θ dks.k ij u osx ls i`Foh ds xq#Roh;
{ks= esa Qsadk tkrk gSA ç{ksI; ds mM+ku dky rFkk {kSfrt ijkl ds
fy, O;atd çkIr djsaA

A projectile is thrown at an angle θ from the
horizontal with velocity u under the gravitational
field of Earth. Find expression for Time of flight
and Horizontal Range.

21. ';kurk ls vki D;k le>rs gSa \ ,d ';ku æo esa fxjrh xksyh
ds fy, lhekar osx dk O;atd çkIr djsaA 5

What do you mean by Viscosity ? Obtain an
expression for terminal velocity of a ball falling
in a viscous liquid.

1028 P. T. O.

( 16 ) 1028
vFkok
OR

cjukSyh dh çes; dks fy[ksa vkSj fl) djsaA
State and prove Bernoulli's Theorem.

S

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