Rajasthan Board 10th Model Paper 2024 Maths

CLASS 10
Rajasthan Board

MODEL
PAPER

ek/;fed ijh{kk] 2024
Secondary Examination, 2024
uewuk iz'u&i=
Model Paper
d{kk & 10oha
Class - 10th
fo"k; & xf.kr
Sub : Maths

le; % 03 ?k.Vs 15 feuV iw.kkZad % 80

ijh{kkfFkZ;ksa ds fy;s lkekU; funsZ'k %&
1- ijh{kkFkhZ loZizFke vius iz'u i= ij ukekad vfuok;Zr% fy[kasA

2- lHkh iz'u gy djuk vfuok;Z gSaA

3- izR;sd iz'u dk mÙkj nh xbZ mÙkj iqfLrdk esa gh fy[ksaA

4- ftu iz'uksa esa vkUrfjd [k.M gSa] mu lHkh ds mÙkj ,d lkFk gh fy[ksAa

5- iz'u dk mÙkj fy[kus ls iwoZ iz'u dk Øekad vo'; fy[kasA

[kaM & v
Section – A

cgqfodYih; iz”u %
Multiple Choice Questions :

1- fuEu oLrqfu"B iz'uksa ds mRrj dk lgh fodYi p;u dj mRrj iqfLrdk esa fyf[k, &
Choose the correct option to answer the following objective questions in the answer
sheet-

i. la[;kvksa 96 vkSj 404 dk e-l- gksxk &

¼v½ 16 ¼c½ 12 ¼l½ 8 ¼n½ 4

HCF of numbers 96 and 404 will be -

(a) 16 (b) 12 (c) 8 (d) 4 [1]

ii. ;fn cgqinp (x) = x2 – 2x - 15 ds 'kwU;kad a o b gks rks ab dk eku gksxk &
¼v½ 15 ¼c½ &15 ¼l½ 5 ¼n½ 2

If the zeros of the polynomial p (x) = x2 – 2x - 15 are a and b, then the
value of ab will be –
(a) 15 (b) -15 (c) 5 (d) 2 [1]

iii. 2] 3] 4] 5] 6 dk vkSlr ¼ek/;½ gksxk &
¼v½ 2 ¼c½ 3 ¼l½ 4 ¼n½ 5

The average (mean) of 2, 3, 4, 5, 6 will be –

(a) 2 (b) 3 (c) 4 (d) 5 [1]

iv. ;fn 2x + y = 6 gks rks bls lUrq"V djus okyk ;qXe gksxk&

¼v½ ¼1] 2½ ¼c½ ¼2] 1½ ¼l½ ¼2] 2½ ¼n½ ¼1] 1½

If 2x+ y = 6 then the pair to satisfy this, will be- -

(a) (1,2) (b) (2,1) (c) (2,2) (d) (1,1) [1]

v. ;fn AP dk izFke in 6 vkSj lkoZ varj 3 gks rks AP gksxh &
¼v½ 6, 9, 12, 15, ---------- ¼c½–6, –9,–12, –15----------
¼l½3, 6, 9, ---------- ¼n½–4, –6, –9,----------
If the first term of AP is 6 and common difference is 3 then AP will be –

(a) 6, 9, 12, 15, ---------- (b) –6, –9, –12, –15 ----------

(c) 3, 6, 9, ------------ (d) -4, -6, -9 ------------ [1]

vi. fuEu esa ls dkSulh le:irk dh dlkSVh ugha gS &
¼v½ dks.k&dks.k&dks.k ¼c½ Hkqtk&dks.k&Hkqtk
¼l½ Hkqtk&Hkqtk&Hkqtk ¼n½ dks.k&Hkqtk&Hkqtk

Which of the following is not a criterion of symmetry?

(a) angle-angle-angle (b) side - angle-side
(c) arm - arm – arm (d) angle - side – side [1]

vii. fcUnq A (4, 0) rFkk B (0, 4)gks rks AB dk e/; fcUnq gksxk &
¼v½ ¼0] 2½ ¼c½ ¼2] 0½ ¼l½ ¼2] 2½ ¼n½ ¼&2]&2½
If A (4,0) and B (0, 4) are points, then the midpoint of AB will be –
(a) (0,2) (b) (2,0) (c) (2, 2) (d)(-2,-2) [1]

viii. ∆𝐴𝐵𝐶esa 𝐵 ledks.k gS rFkk CosA = 35 gks rks Sin A dk eku gksxk&

¼v½ ¼c½ ¼l½ ¼n½
3
In ∆𝐴𝐵𝐶, 𝐵 is a right angle and CosA = 5 then the value of Sin A will be –

(a) (b) (c) (d) [1]

ix. fdlh ehukj dh Nk;k bldh Å¡pkbZ ds cjkcj gks rks lw;Z dk mUu;u dks.k gksxk&
¼v½ 30o ¼c½ 60o ¼l½ 45o ¼n½ 90o

If the shadow of a tower is equal to its height, then the angle of elevation of
the Sun will be-
(a) 30o (b) 60o (c) 45o (d) 90o [1]

x. oxZ vUrjky 10&25 dk oxZ fpUg gS &
¼v½ 10 ¼c½ 15 ¼l½ 17-5 ¼n½ 25

The class symbol of class interval 10-25 is -
(a) 10 (b) 15 (c) 17.5 (d) 25 [1]

xi. fdlh o`Ùk ds O;kl ds fljksa ij [khaph xbZ Li'kZ js[kk,¡a vkil esa gksrh gSa &
¼v½ yEc ¼c½ lekUrj ¼l½ izfrPNsnh ¼n½ Nsnd

The tangent lines drawn at the ends of the diameter of a circle are -
(a) perpendicular (b) parallel (c) Intersecting (d) borer [1]

xii. Hkqtk 7 lseh- okys ,d ?kukdkj CykWd ds Åij ,d v}Zxksyk j[kk gqvk gSA v}Zxksys dk
vf/kdre O;kl gks ldrk gS &
¼v½ 7 lseh- ¼c½ 14 lseh- ¼l½ 21 lseh- ¼n½ 28 lseh

Side 7 cm. A hemisphere is placed on top of a cube-shaped block. The
maximum diameter of a hemisphere can be -
(a) 7 cm. (b) 14 cm. (c) 21 cm (d) 28 cm [1]

xiii. ,d o`Ùk ds izR;sd prqFkkaZ'k ds dks.k dk eku gksrk gS &
¼v½ 30° ¼c½ 45° ¼l½ 60° ¼n½ 90°

The value of the angle of each quadrant of a circle is-
(a) 30° (b) 45° (c) 60° (d) 90° [1]

xiv. ,d ikls dks mNkys tkus ij 6 ls cM+k vad vkus dh izkf;drk gS &
¼v½ 0 ¼c½ 1@4 ¼l½ 1@2 ¼n½ 1

The probability of getting a number greater than 6 when a die is thrown is - [1]
(a) 0 (b) ¼ (c) ½ (d) 1

xv. lekUrj Js.kh −3, − , 2, − − −dk 11 oka in gSA

¼v½22 ¼c½30 ¼l½25 ¼n½32

Arithmetic series is −3, − , 2, − − − - the 11th term of this A.P is -
(a) 22 (b) 30 (c) 25 (d) 32 [1]

2. fuEufyf[kr iz'uksa esa fjDr LFkkuksa dh iwfrZ djrs gq;s mRrj iqfLrdk esa fyf[k;s &

Fill in the blank spaces in the following questions and write in your answer sheet -

i. A.P.: 3, 1, –1, –3 dk izFke in----------------,oa lkoZ varj---------------- gSA

A.P. The first term of 3, 1, −1, −3 is…..and the common difference is … [1]

ii. Cos260o + Sin260odk gy ----------------- gSA
[1]
the solution of Cos² 60° + Sin² 60° is ………

iii. ,d 'kadq dh f=T;k 6 lseh- o ÅapkbZ 8 lseh- gSA 'kadq dh fr;Zd ÅapkbZ-------------gSA
The radius of a cone is 6 cm. And height is 8 cm. The slant height of the cone is….. [1]

iv. oxhZd`r vkadM+kas dk ek/;d Kkr djus dk lw= -------------------- gSA
[1]
The formula to find the median of grouped data is ………….

v. ml iz{s k.k dk eku ftldh ckjackjrk lcls vf/kd gksrh gS--------------------dgykrk gSA
[1]
The value of the observation that has the highest frequency is called… ...

vi. ?kM+h dh feuV dh lqbZ }kjk 1 feuV esa jfpr dks.k dk eku ----------------- gksrk gSA
The value of the angle subtended by the minute hand of a clock in 1 minute
is,………………………….. [1]

vii. ,d vlaHko ?kVuk dh izkf;drk ------------------------ gksrh gSA
There is a probability of an impossible event. [1]

3. vfr y?kqRrjkRed iz”u %

Very short answer question:

i. 1260 ds vHkkT; xq.ku[k.Mkas dks ?kkrkad ds :i esa fyf[k, A
[1]
Write the prime factors of 1260 as exponents.

ii. ;fn cgqin2𝑥 + 𝑥 + 𝑘 dk ,d 'kwU;d 3 gS rks 𝑘 dk eku Kkr dhft;sA

If one zero of the polynomial 2𝑥 + 𝑥 + 𝑘 is 3, then find the value of k. [1]

iii. 9 isafly rFkk 8 isu dk ewY; 54 #- gSA bls chtxf.krh; lehdj.k ds :i esa fyf[k,A
The cost of 9 pencils and 8 pens is Rs 54. Write this as an algebraic [1]
equation.

iv. fp= esa DEAA BC gS ;fn = rFkk

AD =2.7cmgS rks DBdh yEckbZ Kkr dhft, \

AE
In the picture DE || BC is if = and
EC [1]
AD = 2.7cm then find the length of DB?

v. fcUnq P¼3] 4½ dh X– v{k ls nwjh fyf[k;sA
[1]
Write the distance of point P (3, 4) from the X-axis.

vi. 14 lseh f=T;k ds xksys dk lEiw.kZ i`"Bh; {ks=Qy Kkr dhft,A
[1]
Find the total surface area of a sphere of radius 14 cm.

vii. ,d csyu dh Å¡pkbZ 11 lseh ,oa mldk oØi`"Bh; {ks=Qy 968 oxZ lseh gS rks csyu ds
vk/kkj dh f=T;k Kkr dhft,A
If the height of a cylinder is 11 cm and its curved surface area is 968 square cm,
[1]
then find the radius of the base of the cylinder.

viii. f=T;k 14 lseh- okys ,d o`r dk ,d pki dsUnz ij 60°dk dks.k vUrfjr djrk gSA
pki dh yEckbZ Kkr dhft,A
An arc of a circle of radius 14 cm subtends an angle of 6
60°
0° at the centre. Find the [1]
length of the arc.

ix. 6 ehVj ÅWps ,d [kEHks dh Nk;k 2√3 ehVj yEch gks rks lw;Z dk mUurka'k
'k dks.k Kkr
dhft;sA
If the shadow of a 6 meter high pillar is 2√3 meter long, then find the angle of [1]
elevation of the Sun.

x. 20 ehVj ÅWps unh ds iqy ls ,d uko dk voueu dks.k 300 gS uko dks iqy rd igqp
a us esa
fdruh nwjh r; djuh gksxh \
The angle of depression of a boat from a 20 meter high river bridge is 30°. What [1]
distance must the boat cover to reach the bridge ?

Section - B

y?kqRrjkRed iz”u &
Short Answer Type Questions :

4- fl) dhft, fd √2 ,d vifjes; la[;k gSA [2]
Prove that √2 is an irrational number.

5- ;fn cgqin 6x2–3 – 7x ds 'kwU;kad , − gS] rks 'kwU;kadksa ,oa xq.kkadks ds lac/a k dh lR;rk
dh tkWap dhft;sA
If the zeroes of a polynomial 6x2–3 – 7x is , − , then check the truth of the relation [ 2 ]
between zeroes and coefficients .

6- lehdj.k fudk; x–y + 1 = 0vkSj 3x + 2y– 12 = 0dks gy dhft,A
[2]
Solve the group of equations x-y+1= 0 and 3x + 2y – 12 = 0.

7- 𝐴𝐵𝐶𝐷 ,d leyac gS ftlesa 𝐴𝐵 ∥ 𝐶𝐷 gS rFkk blds fod.kZ ijLij fcanq 𝑜 ij izfrPNsn
djrs gSa rks n'kkZb, fd =
ABCD is a trapezium in which AB || CD is and its diagonals intersect at point
[2]
𝑜 then show that =

8- X– v{k ij og fcUnq Kkr dhft, tks fcUnqvksa A¼6] 5½ vkSj B(–4, 5) ls lenwjLFk gS A
[2]
Find the point on the X-axis which is equidistant from the points A(6,5) and B(-4,5).

9- fdlh f=Hkqt ABC esa AB=24 lseh BC = 7 lseh rFkkB = 90o gS rks Sin A o Sin C dk eku
Kkr dhft,A
In a triangle ABC, AB = 24 cm, BC = 7 cm andB = 90o then find the value of Sin A [2]
and Sin C.

10- ,d lery tehu ij [kM+h ehukj dh Nk;k 40 ehVj vf/kd yEch gks tkrh gS tc lw;Z dk
mUurka'k dks.k 600 ls ?kVdj 300 gks tkrk gS] ehukj dh ÅWpkbZ Kkr dhft,A
The shadow of a tower standing on a level ground becomes 40 meters longer when
the angle of elevation of the Sun decreases from 60° to 30°, find the height of the [2]
tower.

11- fl} dhft;s fd fdlh o`Rr ds O;kl ds fljksa ij [khaph xbZ Li'kZ js[kk,a lekUrj gksrh gSA
Prove that the tangents drawn at the ends of the diameter of a circle are parallel. [2]

12- 12 lseh- f=T;k okys ,d o`r dh thok dsna z ij 60°dk dks.k vUrfjr djrh gSA laxr y?kq
o nh?kZ o`r[kaMks ds {ks=Qy Kkr dhft,A
12 cm. A chord of a circle of radius subtends an angle of 60° at the centre. Find the
areas of the corresponding minor and major circle segments. [2]

13- ,d nhokj dh yEckbZ 5 ehVj pkSMkbZ 30 lseh Å¡pkbZ 3 ehVj gSA nhokj cukus esa 20 lseh x
10 lseh x 7-5 lseh eki dh fdruh bZaVksa dh vko';drk gksxh \
The length of a wall is 5 meters, width is 30 cm and height is 3 meters. How many
bricks measuring 20 cm x 10 cm x 7.5 cm will be required to build a wall? [2]

14- fuEufyf[kr vkadM+kas dk ek/;d Kkr dhft;s &

x 20 25 28 29 33 38 42 43
ckjEckjrk 6 20 24 28 15 4 2 1

Find the median of the following data –

x 20 25 28 29 33 38 42 43
frequency 6 20 24 28 15 4 2 1 [2]

15- nks iklksa dks ,d lkFk Qsd
a k tkrk gSA bldh D;k izkf;drk gS fd &
i. nksuks iklksa esa leku vad izkIr gksaxs A

ii. nksuks iklksa ds vadks dk ;ksx 7 izkIr gksxk A
Two dice are thrown simultaneously. What is the probability that -
i. Equal marks will be obtained in both the dice.
[2]
ii. The sum of the numbers of both the dice will be 7.

Section – C

nh?kZmRrjh; iz'u %
Long Answer Type Questions :

16- fuEufyf[kr caVu dk lekUrj ek/; dfYir ek/; fof/k ls Kkr dhft, &

oxZ 10&25 25&40 40&55 55&70 70&85 85&100
vUrjky
ckjEckjrk 2 3 7 6 6 6

Find the arithmetic mean of the following distribution by assumed mean method –

Social 10&25 25&40 40&55 55&70 70&85 85&100
class

interval

frequency 2 3 7 6 6 6 [3]

uhps fn;k gqvk caVu ,d d{kk ds 40 fo|kfFkZ;ksa ds Hkkj n'kkZ jgk gSA

Hkkj fdxzk esa 40&45 45&50 50&55 55&60 60&65 65&70 70&75
fo|kfFkZ;ksa dh 3 5 10 8 7 4 3
la[;k
fo|kfFkZ;ksa dk ek/;d Hkkj Kkr dhft,A

The distribution given below shows the weights of 40 students in a class.

weight in kg 40&45 45&50 50&55 55&60 60&65 65&70 70&75
number of 3 5 10 8 7 4 3
students

Calculate the median weight of students.

17- izFke 100 izkd`r la[;kvksa dk ;ksx Kkr dhft,A
Find the sum of the first 100 natural numbers.

A.P.dk izFke in ,oa vafre in Øe'k% 1 rFkk 11 gS ;fn blds inksa dk ;ksxQy 36 gS rks
inks dh la[;k Kkr djksA
The first term and last term of A.P. is 1 and 11 respectively. If the sum of its terms
is 36 then find the number of terms. [3]

18. fcUnqvksa P (-3, 4) vkSj Q (4, 5) dks tksMu+ s okys js[kk[k.M dks lef=Hkkftr djus okys fcUnqvksa
ds funsZ”kkad Kkr dhft,A

Find the coordinates of the points trisecting the line segment joining the points P
(3,4) and Q (4,5).

og vuqikr Kkr dhft, tcfd fcUnq (–3, P) fcUnqvksa (–5, –4)vkSj (–2, 3)dks vUr% foHkkftr
djrk gSA P dk eku Hkh Kkr dhft, \
Find the ratio in which the point (-3, P) divides the points (-5, -4) and (-2. 3). Also
[3]
find the value of P?

19- fl} dhft;s fd fdlh o`Rr ds ifjxr lekarj prqHkqZt] leprqHkZat gksrk gSA
Prove that a parallelogram circumscribing a circle is a rhombus.

fl} dhft;s fd o`Rr ds ifjxr cus prqHkqZt dh vkeus & lkeus dh Hkqtk;sa dsna z ij laiwjd
dks.k varfjr djrh gSA
Prove that the opposite of a quadrilateral circumscribed about a circle sides
[3]
subtend angles Complement on center front arms .

Section – D

Essay Type Questions:
20- fuEufyf[kr vk¡dM+s 225 fctyh midj.kks ds izfs {kr thou dky ¼?k.Vksa esa ½ dh lwpuk nsrs
gS&&

thou dky 0&20 20&40 40&60 60&80 80&100 100&120
¼?k.Vksa esa½
ckjEckjrk 10 35 52 61 38 29
midj.kksa dk cgqyd thou dky Kkr dhft,A
The following data shows the observed life span (In hours) of 225 electrical appliances:
Life span 0&20 20&40 40&60 60&80 80&100 100&120
(in hours)
frequency 10 35 52 61 38 29
Find the mode life span of the appliances.

fuEufyf[kr caVu ,d eksgYys ds cPpksa ds nSfud tsc [kpZ n'kkZrk gSA ek/;] tsc [kpZ 18 :
gSA YkqIr ckjEckjrk f Kkr dhft,A

nSfud tsc [kpZ 11&13 13&15 15&17 17&19 19&21 21&23 23&25
¼: es½a
cPpksa dh la[;k 7 6 9 13 f 5 4

The following distribution shows the daily pocket money of children in a locality.
Mean, pocket money is Rs 18. Find the missing frequency. [4]

Daily pocket 11&13 13&15 15&17 17&19 19&21 21&23 23&25
money (in
Rs)

number of 7 6 9 13 f 5 4
children

21- nks Øekxr /kukRed iw.kkZad Kkr dhft, ftuds oxkZas dk ;ksx 365 gksA
Find two consecutive positive integers whose sum of squares is 365.

D;k ,d ,slh vke dh cfx;k cukuk lEHko gS ftldh yEckbZ] pkSMk+ bZ ls nqxquh gks vkSj
mldk {ks=Qy 800 m2 gks\ ;fn gka] rks mldh yEckbZ vkSj pkSM+kbZ Kkr dhft,A
Is it possible to make a mango orchard whose length is twice the width and its area is
800 square meters? It yes, find its length and width. [4]

22- fl) dhft;s & = tan A

Prove that - = tan A

fl) dhft;s & + = 2 𝑆𝑒𝑐 𝐴

[4]
Prove that - + = 2 𝑆𝑒𝑐 𝐴

iz’u&i= dh ;kstuk 2023&24

d{kk & 10oha
fo"k; & xf.kr
vof/k & 3 ?k.Vs 15 feuV iw.kkZd
a & 80
1- mn~ns'; gsrq vadHkkj &
Ø-l-a mn~n's ; vadHkkj izfr'kr
1- Kku 20 25%
2- vocks/k 21 26.25%
3- Kkuksi;ksx@vfHkO;fDr 19 23.75%
4- dkS'ky@ekSfydrk 20 25%
;ksx 80 100

2- iz'uksa ds izdkjokj vadHkkj &
Ø- iz'uksa dk izdkj iz'uksa dh vad dqy vad izfr'kr izfr'kr laHkkfor
la- la[;k izfr iz'u ¼vadks dk½ ¼iz'uksa dk½ le;
1- oLrqfu"B 15 1 15 18.75 29.41 30
2- fjDr LFkku 7 1 7 8.75 13.72 15
3- vfry?kqÙkjkRed 10 1 10 12.50 .19.61 35
4- y?kqÙkjkRed 12 2 24 30.00 23.53 45
5- nh?kZmÙkjh; 4 3 12 15.00 7-84 35
6- fuca/kkRed 3 4 12 15.00 5-89 35
;ksx 51 80 100 100 195 feuV

fodYi ;kstuk % [k.M ^l* ,oa ^n* esa gSa

3- fo"k; oLrq dk vadHkkj &
Ø-l-a fo"k; oLrq vadHkj izfr'kr
1 okLrfod la[;k, 4 5%
2 cgqin 4 5%
3 nks pj okys jSf[kd lehdj.k ;qXe 4 5%
4 f}?kkr lehdj.k 4 5%
5 lekUrj Jsf.k;k 6 7.5%
6 f=Hkqt 4 5%
7 funs'kkda T;kfefr 7 8.75%
8 f=dks.kfefr dk ifjp; 8 10%
9 f=dks.kfefr ds vuqiz;ksx 5 6.25%
10 o`Ùk 6 7.5%
11 o`Ùkks ls lEcfU/kr {ks=Qy 5 6.25%
12 i`"Bh; {ks=Qy vkSj vk;ru 6 7-5%
13 lkaf[;dh 13 16.25%
14 izkf;drk 4 5%

iz'u&i= CY;w fizUV 2023&24
d{kk & 10oha fo"k; %& xf.kr iw.kkZad & 80
Ø-la- mÌs'; bdkbZ@mi bdkbZ Kku vocks/k Kkuksi;ksx@vfHkO;fDr dkS'ky@ekSfydrk ;ksx

vfry?kqÙkjkRed

vfry?kqÙkjkRed

vfry?kqÙkjkRed

vfry?kqÙkjkRed
nh?kZmÙkjkRed

nh?kZmÙkjkRed

nh?kZmÙkjkRed

nh?kZmÙkjkRed
y?kqÙkjkRed

y?kqÙkjkRed

y?kqÙkjkRed

y?kqÙkjkRed
fjDr LFkku

fjDr LFkku

fjDr LFkku

fjDr LFkku
fucU/kkRed

fucU/kkRed

fucU/kkRed

fucU/kkRed
oLrqfu"B

oLrqfu"B

oLrqfu"B

oLrqfu"B
1 okLrfod la[;k, 1(1) 1(1) 2(1) 4(3)

2 cgqin 1(1)
1(1)
2(1) 4(3)

3 nks pj okys jSf[kd lehdj.k ;qe 1(1) 1(1) 2(1) 4(3)

4 f}?kkr lehdj.k 4(1) 4(1)

5 lekUrj Jsf<+;k¡ 1(2) 1(1) 3(1) 6(4)

6 f=Hkqt 1(1) 1(1) 2(1) 4(3)

7 funs'kkda T;kfefr 1(1)
1(1)
2(1) 3(1) 7(4)

8 f=dks.kfefr dk ifjp; 1(1) 1(1) 2(1) 4(1) 8(4)

9 f=dks.kfefr ds vuqiz;ksx 1(1) 1(2) 2(1) 5(4)

10 o`Ùk 1(1) 2(1) 3(1) 6(3)

11 o`Ùkks ls lEcfU/kr {ks=Qy 1(1)
1(1)
1(1) 2(1) 5(4)

12 i`"Bh; {ks=Qy vkSj vk;ru 1(1)
1(1)
1(2) 2(1) 6(5)

13 lkaf[;dh 1(2)
1(2)
2(1) 3(1) 4(1) 13(7)

14 izkf;drk

1(1) 1(1) 2(1) 4(3)

;ksx 4(4) 1(1) 3(3) 8(4) 4(1) 4(4) 2(2) 1(1) 4(2) 6(2) 4(1) 3(3) 3(3) 2(2) 4(2) 3(1) 4(1) 4(4) 1(1) 4(4) 8(4) 3(1) 80(51)

fodYiksa dh ;kstuk %& [k.M ^l* ,oa ^n* esa izR;sd esa ,d vkarfjd fodYi gS uksV%& dks"Bd ds ckgj dh la[;k ^vadks*a dh rFkk vanj dh la[;k ^iz'uksa* ds |ksrd gSA

gLrk{kj
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