Class 9 Sample Paper 2022 Solution Maths Term 1

Marking Scheme of Practice Paper – I
Class – IX
Mathematics (Code: 041)
Maximum Marks: 40 Time Duration: 90 minutes

Q. No. Correct option Hint/ Solution
1. (c) A reflex angle is more than 180° and less than 3600.
2. (c) Let sides of triangle be 2x, x and 3x.
∴ 2x + x + 3x = 24
⇒x=4
So, the length of longest side of triangle is 12 cm.
3. (d) The product of a rational and an irrational number is sometimes rational and
sometimes irrational.
4. (a) Let angles be 10x and 8x.
10x + 8x = 900
x = 50
so, angles are 500 and 400.
5. (c) √5 is an irrational number.
6. (c) SSA is not a criterion for congruence of triangles.
7. (b) Third side = 42 – 18 – 10 = 14 cm
S = 21 cm
A= 21 (21 − 18)(21 − 10)(21 − 14)
= 21√11 cm2
8. (a) AB = AC ⇒ ∠C = ∠ B
But ∠C = ∠P and ∠B = ∠Q (Given)
∴ ∠P = ∠Q
⇒ QR = PR
∴ PQR is isosceles triangle.
9. (a) Let x = 0⋅35
100 x = 35⋅35
∴ 99 x = 35
So, x =
10. (c) 91 – 6 = 85
11. (c) y=5
∴y–5=0
12. (b) k(3) – 3(-2) = 12
k=2
13. (a) Class size is 20 – 15 = 5

∴ class corresponding to the class mark 15 is 12.5 – 17.5.
14. (c) BC = AB ⇒ ∠A = ∠C
2∠A + 800 = 1800
∠A = 500

15. (c) If two parallel lines are intersected by a transversal, then the sum of the
interior angles on the same side of the transversal is 1800.
16. (b) 2x + 5(0) = 6 ⇒ x = 3
∴ required point is (3, 0).
17. (b) AB↔FD and ∠C↔∠E
18. (c) = 140
19. (b) LHS = 4 – 2 (0) = 4 = RHS
∴ (4, 0) is the solution of given equation.
20. (a) ∠3 and ∠6 represent interior alternate angle.
21. (a) 30 + x = 180 – 40
∴ x = 110
22. (c) ∠A = ∠B + 420
∠C = ∠B – 210
∠B + 420 + ∠B + ∠B – 210 = 1800
∠B = 530
23. (d) (3a4 b3 ) X (18 a3 b5 ) = 54 a7 b8
24. (b) 10 – 3 = 7
25. (b) Let vertex angle and one of base angles be x and y respectively.
x + y + y = 1800 & x = 2(y+ y)
∴ x = 1200
26. (c) √2 = ((2 ) ) = 2
27. (a) x + 500 = 1230
∴ x = 730
28. (a) If x and y are both positive solutions of equation ax + by + c = 0, always lie in
first quadrant.
29. (d) (√2 – 1) + (√3 - √2) + (√4 - √3) + …… + (√9 - √8) = √9 – 1 = 2
30. (b) ΔABC ≅ ΔA’B’C’
∠BAC = ∠B’A’C’
3x = 2x + 200
x = 200
∴ ∠B’A’C’ = 2 X 200 + 200 = 600
31. (d) 1200 + x + x + 100 = 3600 (Complete angle)
x = 1150
32. (a) The number in the interval 20-30 is 4 (25, 20, 22 and 20).
33. (a) After rationalizing
2 - √3 = a – b√3
∴ a = 2 and b = 1
So, a + b = 2 + 1 = 3

34. (b) x + y = 0 has solutions (–3, 3), (0, 0) and (3, –3).
35. (d) Upper limit = 15 + (15 – 13) = 17
36. (a) It is example of Primary data & Secondary data respectively.
37. (d) The graph of x = y is a straight line passing through the origin.
38. (c) 8y – 6x = 4 has solutions (2, 2) and (-2, -1).

39. (b) = √5 – 2
∴ x – = (√5 + 2) – (√5 – 2) = 4
40. (c) a + b + 900 = 1800 (Straight angle)
∴ a + b = 900
41. (a) (1, 2) is the coordinates of A.
42. (c) (5, 0) is the coordinates of D.
43. (b) (8, 3) is the coordinates of F.
44. (b) ½ X 2 X 2 = 2 square units
45. (c) 3 X 3 = 9 square units
46. (b) = 125 m
47. (a) 50 + 80 + 120 = 250 m
48. (d) 250 – 3 = 247 m
49. (c) 247 X 20 = ₹ 4940
50. (b) A = 125 (125 − 50)(125 − 80)(125 − 120) = 375√15 m2