TBSE Class 11 Model Question Paper for 2021 Chemistry

Model Question
Class XI : Chemistry : 70 Marks : 2020-2021

Group - A : ≤Ã!ï˛!ê˛ ≤Èϟ¿Ó˚ Ùyl 1 : 1x20=20
I) l#ˆÏã˛Ó˚ ≤ß¿à%ˆÏ°yÓ˚ §!ë˛Ü˛ í˛z_Ó˚!ê˛ !ã˛!•´ï˛ ܲÓ˚ / 1x5
1) 2Cl(g) → Cl2(g) ~•z !Ó!ܲÎ˚yÓ˚ çlƒ ∆H ~ÓÇ ∆ S ~Ó˚ !ã˛•´ !ܲÓ˚)˛õ •ˆÏÓ⁄

(a ) ∆H = + ve, (b) ∆H = − ve ( c) ∆H = + ve (d ) ∆H = − ve
∆S = − ve ∆S = − ve ∆S = + ve ∆S = + ve

2) C(s) + O2(g) → CO2(g) !ܲÎ˚yÓ˚ ˆ«˛ˆÏe ∆cH 0 = −393kJ / mol , •ˆÏ° CO2(g) ~Ó˚ àë˛l ï˛y˛õ ( ∆fH 0 ) = Ü˛ï˛ ⁄

393 393
(a ) − KJ / mol ( b) − KJ / mol
9 2

( c) − 393 KJ / mol ( d ) + 393 KJ / mol
3) H2(g) + I2(g) = 2HI(g), ~•z !Ó!ܲÎ˚yÓ˚ ˆ«˛ˆÏe
(a) Kp>Kc (b) Kp<Kc (c) Kp=Kc (d) Kp ≥ Kc
4) l#ˆÏã˛Ó˚ ˆÜ˛yl!ê˛Ó˚ x!hflÏc ˆl•z Èüû
(a) Ca2+ (b) Na2+ (c) Be2+ (d) K+
19) l#ˆÏã˛Ó˚ ˆÜ˛yl!ê˛ !lí˛z!Üœ˛Î˚ Ê˛y•z° ÈüÈ
Cl
a) H+ (b) : C c) NH2OH (d) FeCl3
Cl

II) l#ˆÏã˛Ó˚ ≤ß¿à%ˆÏ°yÓ˚ í˛z_Ó˚ òyG ~ܲ ¢ˆÏ∑‡ÓyˆÏܲƒ / 1x15
6) Ni ˛õÓ˚Ùyî%Ó˚ •zˆÏ°Ü˛ê˛∆l !Ólƒy§!ê˛ !°á–
7) Na+, Cl–, Mg2+, F–ˆÜ˛ ܲÙÓô≈Ùyl xyÎ˚l#Î˚ Óƒy§yô≈ xl%ÎyÎ˚# §yçyG–
8) O3 xl%ˆÏï˛ Ü˛Î˚!ê˛ !§àÙ‰å δ ä G ܲÎ˚!ê˛ ˛õy•z å π ä Órôl xyˆÏSÈ⁄
9) •zˆÏ°Ü˛ê˛∆l xy§!=˛ !ܲ ⁄ ~Ó˚ ~ܲܲ !°á–
. .
10) N F3 xî%ˆÏï˛ N ~Ó˚ §ÇܲÓ˚yÎ˚l xÓfiÌy !ܲÓ˚)˛õ ⁄

11) ˲ƒyl‰u˛yÓ˚GÎ˚y° ô%Óܲ ‘a’ ~Ó˚ ~ܲܲ !°á–
12) ~lê˛∆!˛õÓ˚ §ÇK˛y !°á–
. . ..
13) N H 2 − N H 2 ÈüÈ~Ó˚ xl%Órô# xƒy!§í˛ ˆÜ˛yl!ê˛⁄

14) KMnO4È~ Mn ~Ó˚ çyÓ˚î §Çáƒy Ü˛ï˛ ⁄
15) NaHÈüÈ~Ó˚ §yˆÏÌ çˆÏ°Ó˚ !Ó!ܲÎ˚yÎ˚ !ܲ àƒy§ í˛zͲõߨ •Î˚⁄
16) KO2 ˆã˛Ô¡∫ܲ ˆ«˛ˆÏe xyܲ!£Ï≈ï˛ •Î˚ ˆÏܲl⁄
17) PbI4 ˆÌˆÏܲ PbI2 ~Ó˚ fiÌy!Î˚c ˆÓ!¢ ˆÜ˛l⁄

=O
18) CH3– C = CH – C – CH2COOH ~Ó˚ IUPAC ˛õÂô!ï˛ˆÏï˛ lyÙ !°á–
CH3
19) l#ˆÏã˛Ó˚ !Ó!ܲÎ˚y í˛zͲõߨ ˛õòyÌ≈ §ly=˛ ܲÓ˚ ı
. . .
C H 3 − CH = CH 2 + HBr ˛õyÓ˚ x:y•zí˛ →
20) BHC !ܲ ⁄
Group - B : ≤Ã!ï˛!ê˛ ≤Èϟ¿Ó˚ Ùyl 2 : 2x7=14
21) (i) ˆÙy°y!Ó˚!ê˛Ó˚ §ÇK˛y !°á–
(ii) NTP-ˆï˛ 1!ê˛ í˛y•zx!:ˆÏçˆÏlÓ˚ xî% ܲï˛áy!l xyÎ˚ï˛l òᰠܲˆÏÓ˚ –
22) xyʉ˛ Óyí˛z l#!ï˛!ê˛ !°á–
(ii) Fe2+ & Fe3+ xyÎ˚Ó˚ˆÏlÓ˚ ÙˆÏôƒ ˆÜ˛yl!ê˛ ˆÓ!¢ fiÌyÎ˚# G ˆÜ˛l⁄
23)(i) Be- ~Ó˚ xyÎ˚l#˲Ól !ÓË˛Ó b xˆÏ˛õ«˛y ˆÓ!¢ ˆÜ˛l⁄
(ii) ~ܲ!ê˛ˆÏÙԈϰÓ˚ ˛õyÓ˚Ùyî!Óܲ ܲÙyAܲ =24ñ ˛õÎ≈yÎ˚ §yÓ˚î#ˆÏï˛ ~Ó˚ xÓfiÌyl !°á ~ÓÇ ~!ê˛ !ܲ çyï˛#Î˚ ˆÙÔ° ⁄
24) (i) ~ܲ!ê˛ x§ÙO§ !Ó!ܲÎ˚yÓ˚ í˛zòy•Ó˚î òyG –
(ii) x¡‘ ÙyôƒˆÏÙ H2O2(aq )+ Fe2+(aq) → Fe3+ (aq) + H2O(l) §Ù#ܲÓ˚î!ê˛Ó˚ xyÎ˚l •zˆÏ°Ü˛ê˛∆l ˛õÂô!ï˛ˆÏï˛ §Ùï˛y !Óôyl
ܲÓ˚–
25) (i) çˆÏ°Ó˚ í˛z˲ô!Ù≈ï˛y Ó˚y§yÎ˚!lܲ !Ó!ܲÎ˚yÓ˚ ÙyôƒˆÏÙ ˆòáyG–
(ii) PH5ÈüÈ~Ó˚ x!hflÏc ˆl•z ˆÜ˛l⁄
26) NaNO3 ˆÜ˛ í˛z_Æ Ü˛Ó˚ˆÏ° !ܲ âˆÏê˛ §Ù#ܲÓ˚î §• !°á–
(ii) ܲ!ë˛l xÓfiÌyÎ˚ G àƒy§#Î˚ÓfiÌyÎ˚ BaCl2 ˆÓ˚ àë˛l !°á–
27) (i) ˲yç≈ÈüÈ≤Ã!ܲÎ˚yÓ˚ ~ܲ!ê˛ í˛zòy•Ó˚î òyG–
(ii) CH3–C=CH2 3
→ A →
2 O Zn / H O 1
CCl B+C ×4
4 ∆ 2
CH3
A, B ~ÓÇ C §ly=˛ ܲÓ˚–

D xÌÓy
ê˛#ܲy !°á û (i) !Ê˛ˆÏí˛° ܲyÊ˛ê‰˛§‰ xƒy°Ü˛y•zˆÏ°¢l– (ii) ˆÜ˛y°‰ˆÏÓ !Ó!ܲÎ˚y–
Group-C : ≤Ã!ï˛!ê˛ ≤Èϟ¿Ó˚ Ùyl 3 : 3x7=21
28)(a) 9.6g §y°Ê˛yÓ˚ (S8) ~Ó˚ ÙˆÏôƒ í˛z˛õ!fiÌï˛ xî% G ˛õÓ˚Ùyî% §Çáƒy !lî≈Î˚ܲÓ˚– 2+1
(b) ˆÜ˛yl àƒyˆÏ§Ó˚ Óy‹õ âlc í˛z£÷Ïï˛y G ã˛yˆÏ˛õÓ˚ í˛z˛õÓ˚ !lË≈˛Ó˚ ܲˆÏÓ˚ ܲ#⁄ Óƒyáƒy ܲÓ˚–
29) (a) 2d ~ÓÇ 3f ܲ«˛Ü˛ §Ω˛Ó lÎ˚ ˆÏܲl⁄ 1x3
(b) 2S ~ÓÇ 3Px ܲ«˛ˆÏܲÓ˚ xyÜ,˛!ï˛ !ܲÓ˚)˛õ⁄
(c) H- ˛õÓ˚Ùyî%ˆÏï˛ ~ܲ!ê˛ •zˆÏ°Ü˛ê˛∆l 12.1ev ¢!=˛ ˆ¢y£Ïî ܲˆÏÓ˚ ˆÜ˛yl ܲˆÏ«˛ °y!Ê˛ˆÏÎ˚ í˛zë˛ˆÏÓ⁄
30) (i) N2 xl%Ó˚ xylÓ Ü˛«˛Ü˛ •zˆÏ°Ü˛ê˛∆l !Ólƒy§ !°á ~ÓÇ N2ÈüÈ~Ó˚ ˆã˛Ô¡∫ܲ ôÙ≈ñ Órôl Ü˛Ù !lî≈Î˚ ܲÓ˚–
(ii) §yôyÓ˚î í˛z£÷Ïï˛yÎ˚ H2S ~ܲ!ê˛ àƒy§ !ܲv H2O ï˛Ó˚° ˆÜ˛l⁄ 2+1
D xÌÓy
(i) CO2 xô%Ó#Î˚ ˆÜ˛l⁄ 1+1+1
(ii) BF3 ~ÓÇ SiCl4 xî%Ó˚ àë˛lyÜ,˛!ï˛ !ܲ Ó˚)˛õ ⁄
(iii) !Ó¢%Âô NaCl ï˛!í˛¸Í xÈüÈ˛õ!Ó˚Óy•# ˆÜ˛l⁄

31) (a) SI ~ܲˆÏܲ R ~Ó˚ Ùyl Ü˛ï˛ ⁄
(b) í˛y°ê˛ˆÏlÓ˚ xÇ¢ã˛y˛õ §)e!ê˛ !°á–
(c) ˆÜ˛yl í˛z£÷Ïï˛yÎ˚ 28N2 àƒyˆÏ§Ó˚ xyÎ˚ï˛l 2.46atm ã˛yˆÏ˛õ 10L •ˆÏÓ⁄
32) (a) ˆ•§‰ÈüÈ~Ó˚ ï˛y˛õ §Ù!T˛Ó˚ §)e!ê˛ !ÓÓ,ï˛ Ü˛Ó˚–
(b) !l¡¨!°!áï˛ Órôl ¢!=˛ ˆÌˆÏܲ
C2H2(g) + H2(g) → C2H4(g)
~•z !Ó!ܲÎ˚yÓ˚ ~l̃y°!˛õ !lî≈Î˚ ܲÓ˚–
C − H → 414.0 KJmol −1 , C ≡ C → 827.6 KJmol −1
C = C → 606.0 KJmol −1 , H − H → 430.5KJmol −1
33) (a) ˆÙê˛yÙy!Ó˚çÙ !ܲ ⁄ í˛zòy•Ó˚î §• Óƒyáƒy ܲÓ˚–
(ii) Cl3C – COOH, CH3COOH, ClCH2COOH, Cl2CHCOOH ˆÜ˛ ܲÙÓô≈Ùyl x!¡‘ܲï˛y xl%§yˆÏÓ˚ §yçyG–
34) (i) HC ≡ CHÈüÈ~Ó˚ x¡‘ôˆÏÙ≈Ó˚ §yˆÏ˛õˆÏ«˛ 1!ê˛ !Ó!ܲÎ˚y !°áù
(ii) ˛õ!Ó˚Óï≈˛l ܲÓ˚ / ˆÓl!çl → ly•zˆÏê˛∆yˆÏÓl!çl–
(iii) l#ˆÏã˛Ó˚ !Ó!ܲÎ˚y!ê˛ §¡õ)î≈ ܲÓ˚–
CH 2
2% °â%¢#ï˛°
→ X
CH 2 KMno4 oÓî

Group-D : ≤Ã!ï˛!ê˛ ≤Èϟ¿Ó˚ Ùyl 5 : 5x3=15
35) (a) Kp G Kc ~Ó˚ ÙˆÏôƒ ~ܲ!ê˛ §¡õÜ≈˛ ˛≤Ã!ï˛¤˛y ܲÓ˚–
(b) 3O2(g) 2O3 (g) – 34Kcal ~•z !Ó!ܲÎ˚y!ê˛Ó˚ í˛z˛õÓ˚ ã˛y˛õ G ï˛y˛õ Ó,!ÂôÓ˚ ≤Ã˲yÓ !ܲ•ˆÏÓ⁄
(c) Ca3 (PO4)2 °ÓˆÏîÓ˚ oyÓƒï˛y G oyÓƒï˛y à%îÊ˛ˆÏ°Ó˚ §¡õÜ≈˛!ê˛ !°á–
xÌÓy
(a) ÓyÊ˛yÓ˚ «˛Ùï˛y !ܲ ⁄
(b) 1 !°ê˛yÓ˚ oÓˆÏî Ü˛ï˛ @˝ÃyÙ NaOH oÓ#Ë)˛ï˛ ܲÓ˚ˆÏ° ˙ oÓˆÏîÓ˚ pH=12 •ˆÏÓ⁄
(c) 2CO(g) + O2(g) = 2CO2(g) + ï˛y˛õñ §¡ø%á !Ó!ܲÎ˚y!ê˛ˆÏܲ §¡õ)Ù≈ï˛yÓ˚ !òˆÏܲ !lˆÏÎ˚ ÎyGÎ˚yÓ˚ çlƒ ï%˛!Ù !ܲ !ܲ ÓƒÓfiÌy
ˆlˆÏÓ⁄ 1+2+2
36) (a) SiCl4 ÈüÈ~Ó˚ xyo≈ !ӈϟ’£Ïî •Î˚ !ܲv CCl4 ~Ó˚ •Î˚ ly ˆÜ˛l⁄
(b) CO32– ~ÓÇ HCO3– xyÎ˚ˆÏlÓ˚ §Çflõ®l àë˛l !°á–
(c) x˜ÏçÓ ˆÓl!çl !ܲ ⁄ 2+2+1
xÌÓy
(a) BF3 ~Ó˚ xy!¡‘ܲï˛y BCl3 xˆÏ˛õ«˛y Ü˛Ù ˆÜ˛l⁄
(b) Ga ~Ó˚ ˛õyÓ˚Ùyî!Óܲ Óƒy§yô≈ Al ˆÌˆÏܲ Ü˛Ù ˆÜ˛l⁄
(c) l#ˆÏã˛Ó˚ ≤Ã!ܲÎ˚y!ê˛ §¡õ)î≈ ܲÓ˚ /ÈüÈAl + NaOH+H2O → 2+2+1
+ + +
37)(a) (CH3)3 C ~Ó˚ fiÌy!Î˚c CH3 C H2 ~ÓÇ C H3 xˆÏ˛õ«˛y x!ôܲ ˆÜ˛l⁄
(b) CH3–CH=CH–CHO ~Ó˚ çƒy!Ù!ï˛Ü˛ §ÙÓyÎ˚Óà%!° IUPAC lyÙ§• !°á–
(c) ܲƒy!ê˛ˆÏl¢yl Ó°ˆÏï˛ !ܲ Ó%V˛⁄ 2+2+1
xÌÓy
(a) xyˆÏÓ¢ ≤Ã˲yÓ !ܲ ⁄
(b) O2NCH2CH2O– ~ÓÇ CH2CH2O– xyÎ˚l ò%!ê˛Ó˚ ˆÜ˛yl!ê˛ ˆÓ!¢ §%!fiÌï˛ ~ÓÇ ˆÜ˛l⁄
(c) C5H12 xyî!Óܲ §ÇˆÏÜ˛ï˛ !Ó!¢T˛ xƒy°ˆÏܲlà%!° !ܲ !ܲ ⁄ ~ˆÏòÓ˚ ˆÜ˛yl!ê˛ˆÏï˛ ¢%ô%Ùye 10 ~ÓÇ 40 ܲyÓ≈l ˛õÓ˚Ùyî% Óï≈˛Ùyl–
~ˆÏòÓ˚ àë˛l xÑyܲ– 1+2+2
D x!ï˛!Ó˚=˛ ≤ß¿yÓ°#–

Model Question : Class XI : Chemistry : 70 Marks : 2020-2021

Group-A : Each questions carries 1 marks : 1x20=20
I) Choose the correct answer : 1x5
1) For the reactions 2cl(g) → cl2(g), the signs for ∆H and ∆ s will be –
(b) ∆H = − ve (c) ∆H = + ve (d ) ∆H = −ve
( a ) ∆H = + ve, ∆s = − ve ∆s = − ve ∆s = + ve ∆s = + ve
2) C(s) + O2(g) → CO2(g), for the reaction, ∆cH 0 = −393kg / mol , the formation enthalpy ∆fH 0 =
will be
393 393
(a ) − Kj / mol (b) − Kj / mol (c ) − 393 Kj / mol ( d ) + 393 Kj / mol
9 2
3) H2(g) + I2 = 2HI (g), or this reaction
a) kp > Kc b) Kp < Kc (c) Kp = Kc (d) Kp ≥ Kc
4) Which one does not exist –
a) Ca2+ (b) Na2+ (c) Be2+ (d) K+
5) Which one is nucleophile
Cl
a) H+(b) : C Cl c) NH2OH (d) FeCl3

II) Answer the following in one word/sentence : 1x15
6) Write down the electronic configuration of Ni atom.
7) Na+, Cl–, Mg2+, F– Arrange them in increaing order of ionic vadins.
8) What do you mean by election affinity ? Write its unit ?
9) How many sigma ( δ ) and pi ( π ) bond are there in O3 molecule ?
. .
10) What is the hybridisation of N in N F3 molecule ?

11) Write the unit for vanderwaal’s constant ‘a’.
12) Define entropy ?
. . . .
13) What is the conjutage acid of N H 2 – N H 2 ?

14) What is the oxidation no of Mn in KMnO4
15) Which gas is trohed when NaH veacis with water ?
16) Why does Ko2 attracted by magnetic field ?
17) PbI2 is more stable than PbI4 why ?
18) Write the IUPAC name of the following compound :
=O

CH3 – C = CH – C – CH2COOH
CH3
19) find the product in the following reaction
. ..
C H 3 − CH = CH 2 + HBR
˛õyÓ˚ x:y•zí˛ →

20) What is BHC ?

Group-B : Each Question Carries 2 marks : 2x7=14
21) (i) Define Molarity ? 1+1
ii) How much volume is occupied by a single dioxygen molecule at NTP
22) i) State Af-bau-Principle. 1+1
(ii) Between Fe2+ and Fe3+ ions which one is more stable and why ?
23) (i) Be has higher ionisation potential than B. Why?
(ii) Atomic number of an element is 24, find out its position in periodic table and what type of
elements is this ? 1+1
24) (i) Give an example of disproportanation reaction. 1+1
(ii) In acidic nedium, balance the following chemical equation by ion-electron method.
H2O2(aq) +Fe2+(aq) → Fe3+(aq) + H2O (l)
25) (i) Show the anphoteric nature of water by chemical reaction. 1+1
(ii) pH5 does not exist, Why ?
26) (i) What happens when NaNO3 is heated write the equation.
(ii) Draw the structure of BeCl2 solid state and gaseous state . 1+1
27) (i) Given an example of Wurtz - reaction.
ii) Identify A, B, and C.
O Zn / H O
CH3–C=CH2 3
CCl
→ A →
2
B+C
4 ∆
CH3
* OR
Write notes on :-
(i) Friedel-Crafts alkylation.
(ii) Kolbe reaction.
Group-C : Each Question carries 3 marks : 3x7=21
28) (a) Calculate the number of molecules and atoms present in 9.6g sulphar (S).
(b) Does vapour density of a gas depends on temperature and pressure- explain. 2+1
29) (a) Why 2d and 3f Orbitals are not possible ?
(b) What are the shapes of 2S and 3Px afital ?
(c) If an electron in H atom absorbs 12.1ev energy then in which orbit it will jump ? 1x3
30) (a) Write down the MO clectronic configuration of N2 molecule and find its bond order, magnetic
property.
(b) At room temperature H2S is a gas but H2O is a liquid-why ?
OR
(a) CO2 is non polar - why ?
(b) What are the geometry of BF3 and SiCl4 mudecules ?
(c) Pure NaCl is non-conductor of electricity why ?
31) (a) What is the value of R in SI unit ?
(b) State Dalton’s law of partial pressuse.
(c) Find that temperature at which 28 g of N2 at 2.46 atm presure occupies 10L volume.
32) (a) State Hess’s law of heat summation.

(b) From the given bond-energy data, calculate the enthalpy of the following reaction :
C2H2(g) + H2(g) → C2H4(g)
Given :
C–H → 414.0 KJ mol–1 C ≡ C → 827.6KJmol–1
C=C → 606.0 KJmol–1 H–H → 430.5 KJmol–1
33) (i) What is matemerism ? Explain with example.
(ii) Cl3C – COOH, CH3COOH, ClCH2COOH, Cl2CHCOOH– arrange them in inceasing order of
acidity.
34) (i) Describe a reaction in support of acidic character of HC ≡ CH
(ii) Convert :- Benzene to Nitrobenzene.
(iii) Complete the following reaction :
CH 2
2% Cold dilute
→ X
CH 2 KMno4
solution

Group -D : Each Question Carries 5 Marks : 5 x 3 = 15
25) (a) Derive a relation between Kp and Ke.
(b) 302(g) 203(g) – 34KCal, What is the affect of pressure and temperature on this above veaction.
(c) What is the relation between soulbility and solubility product for Ca3 (PO4)2 salt. 2+2+1
OR
a) What is buffer capacity.
(b) How much NaOH in gm should be dissolved in 1 liter solution to make its pH=12
(c) 2CO(g) + O2(g) = 2CO2(g) + heat
to complete the forward reaction reaction which measures you will take ?
36) (a) SiCl4 undergoes hydrolysis but CCl4 does not - why ?
(b) Write down the resonating structures of CO32– and HCO3– ions.
(c) What is Inorganic benzene ? 2+2+1
OR
a) BF3 is less acidic than BCl3– why ?
(b) Atomic radio of Ga is smaller than Al – Why ?
(c) Complete the reaction :- Al + NaOH + H2O → 2+2+1
+ + +
37) (a) (CH3)3 C is more stable than CH2 C H2 and C H3 why ?
(b) Write down the geometrical isomers of
CH3–CH=CH–CHO and their IUPAC anme.
(c) What is catenation ? 2+2+1
OR
a) What do you mean by Induction Effect ?
(b) O2N–CH2–CH2–O– and CH3CH2–O– ions, which one is more stable and why ?
(c) How many alkanes are possible with C5H12? Among them which contains only 10 and 40c atom.
Draw structures. 1+2+2

* Additional Questions.

lÙ%ly ≤ß¿˛õe / ~ܲyò¢ ˆ◊!î / xÌ≈l#!ï˛ / 80 l¡∫Ó˚ / 2020-2021
≤ÃÌÙ Ë˛yà / xÌ≈¢yˆÏflf Ó˚y!¢!ÓK˛yl-40
!Ó˲yàÈüÈܲ / ≤Ã!ï˛!ê˛ ≤Èϟ¿Ó˚ Ùyl 1 / 1x10=10
1ä ~ܲÓã˛ˆÏl Ó˚y!¢!ÓK˛yˆÏlÓ˚ §ÇK˛y òyG–
2ä !lˆÏ¡¨ ≤Ãò_ !ÓÓ,!ï˛!ê˛ §ï˛ƒ ly !Ù̃y !°á– Ó˚y!¢!ÓK˛yl •° ~Ùl ~ܲ!ê˛ !ÓK˛yl Îy à%îàï˛ ~ÓÇ ˛õ!Ó˚Ùyîàï˛ Ó˚y!¢ï˛ˆÏ̃Ó˚
xyˆÏ°yã˛ly ܲˆÏÓ˚–
3ä Ù)° í˛zͧ ˆÌˆÏܲ ≤ÃÌÙÓyˆÏÓ˚Ó˚ ÙˆÏï˛y §Çà,•#ï˛ Ó˚y!¢ ï˛ÌƒˆÏܲ ӈϰ ÈüüüÈ
ܲä ≤ÃyÌ!Ùܲ Ó˚y!¢ï˛Ìƒ åáä xÈüÈ≤ÃyÌ!Ùܲ Ó˚y!¢ï˛Ìƒ åàä x˲ƒhs˝Ó˚#î Ó˚y!¢ï˛Ìƒ åâä ˆÜ˛ylê˛y•z lÎ˚–
4ä ã˛°ˆÏܲÓ˚ §ÇK˛y òyG–
D xÌÓy
˛õ!Ó˚§Çáƒy Ó°ˆÏï˛ !ܲ Ó%V˛⁄
5ä !lˆÏ¡¨ ≤Ãò_ !ÓÓ,!ï˛!ê˛ §ï˛ƒ ly !Ù̃y !°ˆÏáy /
~ܲ!ê˛ xhs˝Ë%≈˛=˛ §y!Ó˚ˆÏï˛ ~ܲ!ê˛ ˆ◊!î !Ó˲yçˆÏlÓ˚ í˛zôÁ≈§#Ùy •° !lˆÏ¡¨y=˛ ˆ◊!îÓ˚ !l¡¨§#Ùy–
6ä xyÎ˚ï˛ˆÏ°á ~Ó˚ ÙyôƒˆÏÙ ˆÎ ˛Ó˚y!¢ï˛Ìƒ í˛z˛õfiÌy˛õl ܲÓ˚y •Î˚ ï˛y ˆ°á!ã˛e xyܲyˆÏÓ˚ !lî≈Î˚ܲÓ˚ˆÏï˛ §y•y΃ ܲˆÏÓ˚ ÈüüüÈ
ܲä àí˛¸ åáä §Çáƒyà%Ó˚%Ùyl åàä ÙôƒÙÙyl åâä í˛z˛õˆÏÓ˚Ó˚ ˆÜ˛yl!ê˛•z lÎ˚–
7ä ˆÎÔ!àܲ àí˛¸ (A.M) ˆÌˆÏܲ n §ÇáƒÜ˛ ÙyˆÏlÓ˚ ~ܲ!ê˛ ˆ§ˆÏê˛Ó˚ !Óã%˛ƒ!ï˛Ó˚ Ó#çày!î!ï˛Ü˛ ˆÎyàÊ˛° •° ÈüüüÈÈüüüÈÈüüüÈ–
¢)lƒfiÌyl˛õ)Ó˚î ܲÓ˚–
8ä ã˛Ó˚Ù Ùyl ‡ ˛õˆÏòÓ˚ í˛z˛õ!fiÌ!ï˛ ˆÜ˛yl‰ àí˛¸ˆÏܲ ˲#£Ïî ˲yˆÏÓ ≤Ã˲y!Óï˛ Ü˛ˆÏÓ˚ ÈüüüÈ
ܲä ÙôƒÙ Ùyl åáä §Çáƒyà%Ó˚% Ùyl åàä ˆÎÔ!àܲ àí˛¸ åâä à%ˆÏîy_Ó˚ àí˛¸ å.ä !ÓÓï≈˛ˆÏÎÔ!àܲ àí˛¸–
9ä §Ùܲ ˛õyÌ≈ˆÏܲƒÓ˚ ‡xyò¢≈ !Óã%˛ƒ!ï˛Ó˚ §)e!ê˛ •° ÈüÈ
2
−
( x − x) ( x − x) (x − x x
ܲä σ = N åáä σ= åàä σ = N
åâä σ = N
N
10ä !lˆÏ¡¨ ≤Ãò_ !ÓÓ,!ï˛!ê˛ §ï˛ƒ ly !Ù̃y !°ˆÏáy ÈüüüÈ
ˆË˛òyAܲ •° !Óhfl,Ï!ï˛Ó˚ ~ܲ!ê˛ ˛õÓ˚Ù ˛õ!Ó˚Ùy˛õܲ–
!Ó˲yàÈüÈá / ≤Ã!ï˛!ê˛ ≤Èϟ¿Ó˚ Ùyl 3 / 3x2 = 6
11ä Ó˚y!¢ï˛ˆÏ̃Ó˚ ˆ◊!î !Ó˲yçˆÏl ÓƒÓ•,ï˛ Ó!•≈Ë)˛ï˛ ~ÓÇ xhs˝Ë%≈˛=˛ ˛õÂô!ï˛Ó˚ Óƒyáƒy òyG–
12ä Ü˛ÙˆÏÎÔ!àܲ ˛õ!Ó˚§Çáƒy ˆÓ˚áy Óy Gçy˲ ~Ó˚ Óî≈ly òyG–
D xÌÓy
˛õy•z !ã˛e Ó°ˆÏï˛ !ܲ ˆÓyV˛⁄ •z•yÓ˚ xAܲl ˛õÂô!ï˛ Óî≈ly ܲÓ˚–
!Ó˲yàÈüÈà / ≤Ã!ï˛!ê˛ ≤Èϟ¿Ó˚ Ùyl 4 / 4x3=12
13ä l#ˆÏã˛Ó˚ ˆÜ˛yl‰ ˛õÂô!ï˛!ê˛ Ó˚y!¢!ÓK˛yl xôƒÎ˚ˆÏl ˲yˆÏ°y Ê˛° ˆòˆÏÓ ~ÓÇ ˆÜ˛l⁄ åܲä xyòÙ¢%Ùy!Ó˚ åáä lÙ%ly
D xÌÓy
!l¡¨!°!áï˛ §Ó˚° ˛õ!Ó˚§Çáƒy §y!Ó˚ˆÏܲ Ü˛ÙˆÏÎÔ!àܲ ˛õ!Ó˚§Çáƒy §y!Ó˚ˆÏï˛ Ó˚)˛õyhs˝!Ó˚ï˛ Ü˛Ó˚ ı
ˆ◊!î!Ó˲yçl 0-10 10-20 20-30 30-40 40-50 50-60
§Ó˚° ˛õ!Ó˚§Çáƒy 7 15 20 24 16 8
14ä !l¡¨!°!áï˛ 150!ê˛ ˛õ!Ó˚ÓyˆÏÓ˚Ó˚ ˜ò!lܲ xyÎ˚ §¡õ!Ü≈˛ï˛ ï˛Ìƒ ˆÌˆÏܲ ˆÎÔ!àܲ àí˛¸ !lÙ≈Î˚ ܲÓ˚–
xyÎ˚ åê˛yܲyä 75ÈüÈÓ˚ ˆÓ!¢ 85ÈüÈÓ˚ ˆÓ!¢ 95Ó˚ ˆÓ!¢ 105 Ó˚ ˆÓ!¢ 115 Ó˚ ˆÓ!¢
˛ õ!Ó˚ÓyˆÏÓ˚Ó˚ §Çáƒy 150 140 115 95 70

125 Ó˚ ˆÓ!¢ 135-Ó˚ ˆÓ!¢ 145ÈüÈÓ˚ ˆÓ!¢
60 40 25
15ä ˆÎÔ!àܲ àí˛¸ñ ÙôƒÙ Ùyl ~ÓÇ §ÇK˛yà%Ó˚% Ùyl ~Ó˚ ÙˆÏôƒ §¡õÜ≈˛ Óî≈ly ܲÓ˚–
!Ó˲yàÈüÈâ / ≤Ã!ï˛!ê˛ ≤Èϟ¿Ó˚ Ùyl 6 / 6x2=12
16ä ˛õ!Ó˚§Çáƒy Ó•%Ë)˛ç !ܲ˲yˆÏÓ ˛õ!Ó˚§Çáƒy ˆÓ˚áy ˆÌˆÏܲ !˲ߨ⁄ ~ܲ!ê˛ Ü˛y“!lܲ Ó˚y!¢ï˛ˆÏ̃Ó˚ ˆ§ê˛ !lˆÏÎ˚ ò%!ê˛ ˆÓ˚áy !ã˛e xAܲl
ܲÓ˚–
xÌÓy
xyÎ˚ï˛ˆÏ°á ~ÓÇ ò[˛ !ã˛ˆÏeÓ˚ ÙˆÏôƒ ˛õyÌ≈ܲƒ !°á–
17ä 100 çl ˛õ!Ó˚«˛yÌ#≈Ó˚ ˛õÓ˚#«˛yÎ˚ ≤ÃyÆ l¡∫Ó˚ ˆÌˆÏܲ §Ùܲ ˛õyÌ≈ܲƒ Óy xyò¢≈ !Óã%˛ƒ!ï˛ (S.D) !lî≈Î˚ ܲÓ˚ /
≤ÃyÆ l¡∫Ó˚ 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90
˛õÓ˚#«˛yÌ#≈Ó˚ §Çáƒy 19 3 2 49 24 2 0 1

!mï˛#Î˚ ˲yà / Óƒy!T˛àï˛ xÌ≈l#!ï˛ÈüÈ40

!Ó˲yàÈüÈ. / ≤Ã!ï˛!ê˛ ≤Èϟ¿Ó˚ Ùyl 1 /1x10=10
18ä •z!ï˛Óyã˛Ü˛ xÌ≈l#!ï˛Ó˚ ~ܲ!ê˛ í˛zòy•Ó˚î !ÓÓ,ï˛ Ü˛Ó˚–
19ä !lˆÏ¡¨ ≤Ãò_ !ÓÓ,!ï˛!ê˛ §ï˛ƒ ly !Ù̃y ˆ°ˆÏáy /
ÈüüüÈ ~ܲ!ê˛ oˆÏÓƒÓ˚ òyÙ !lô≈yÓ˚î •° §Ù!T˛àï˛ xÌ≈l#!ï˛Ó˚ !Ó£ÏÎ˚–
20ä Î!ò x oˆÏÓƒÓ˚ òyÙ Ó,!ÂôÓ˚ Ê˛ˆÏ° y oˆÏÓƒÓ˚ ã˛y!•òy ܲˆÏÙñ ï˛y•ˆÏ° ï˛y•yÓ˚y ˛õÓ˚flõÓ˚ !ܲ ôÓ˚ˆÏîÓ˚ oÓƒ⁄
21ä !lˆÏ¡¨ ≤Ãò_ ˆÜ˛yl‰ ¢ï≈˛!ê˛ˆÏܲ ‘Point of Satiety Óy Saturation’ Ó°y •Î˚ ⁄
ܲä ≤Ãy!hs˝Ü˛ í˛z˛õˆÏÎyà ôlydܲ åáä ≤Ãy!hs˝Ü˛ í˛z˛õˆÏÎyà ¢)lƒ åàä ˆÙyê˛ í˛z˛õˆÏÎyà Ó,!Âô ˛õyGÎ˚y åâä ˆÙyê˛ í˛z˛õˆÏÎyà •…y§ ˛õyGÎ˚y–
22ä §¡õ)î≈ !fiÌ!ï˛fiÌy˛õܲ ã˛y!•òy Ó°ˆÏï˛ Ü˛# ˆÓyV˛⁄
23ä ≤Ãy!hs˝Ü˛ í˛zͲõyòˆÏlÓ˚ §ÇK˛y òyG–
D xÌÓy
≤Ãy!hs˝Ü˛ í˛zͲõyòܲ !ܲ ¢)lƒ Óy }îydܲ •Î˚⁄
24ä ˆÜ˛yl‰ ˛õ!Ó˚!fiÌ!ï˛ˆÏï˛ ˛õ!Ó˚Óï≈˛l¢#° ÓƒÎ˚ (VC) ¢)lƒ •Î˚⁄
25ä xyÎ˚ï˛ˆÏlÓ˚ ˛≤Ã!ï˛òyl‡ÙyeyÓ,!ÂôÓ˚ ≤Ã!ï˛òyl ܲ#⁄
26ä Îál 5 ~ܲܲ oÓƒ !Ó!ܲ •Î˚ ï˛ál ˆÙyê˛ xyÎ˚ï˛l •° 100 ê˛yܲyñ xyÓyÓ˚ Îál 6~ܲܲ oÓƒ !Ó!ܲ •Î˚ ï˛ál ≤Ãy!hs˝Ü˛ xyÎ˚
•° 8 ê˛yܲy– ï˛y•ˆÏ° ܲï˛òyˆÏÙ 6 ~ܲܲ oÓƒ !Ó!ܲ •ˆÏÎ˚!SÈ° ⁄
ܲä 28 ê˛yܲy ≤Ã!ï˛ ~ܲܲ åáä 20 ê˛yܲy ≤Ã!ï˛ ~ܲܲ åàä 18 ê˛yܲy ≤Ã!ï˛ ~ܲܲ åâä 12 ê˛yܲy ≤Ã!ï˛ ~ܲܲ–
27ä ˛õ)î≈ ≤Ã!ï˛ˆÏÎy!àï˛yÙ)°Ü˛ Ê˛yˆÏÙ≈Ó˚˛ ã˛y!•òy ˆÓ˚áy!ê˛ •Î˚ ÈüüüÈ åÜ˛ä §¡õ)î≈ x!fiÌ!ï˛fiÌy˛õܲ åáä x!fiÌ!ï˛fiÌy˛õܲ åàä
!fiÌ!ï˛fiÌy˛õܲ åâä §¡õ)î≈ !fiÌ!ï˛fiÌy˛õܲ–
!Ó˲yàÈüÈã˛ / ≤Ã!ï˛!ê˛ ≤Èϟ¿Ó˚ Ùyl 3 / 3x2=6
28ä ≤Ãy!hs˝Ü˛ í˛z˛õˆÏÎy!àï˛yÓ˚ §ÇK˛y òyG– ˆÓ˚áy!ã˛e §•Ü˛yˆÏÓ˚ ˆÙyê˛ í˛z˛õˆÏÎy!àï˛y ~ÓÇ ≤Ãy!hs˝Ü˛ í˛z˛õˆÏÎy!àï˛yÓ˚ ÙˆÏôƒ §¡õÜ≈˛ Óƒyáƒy
ܲÓ˚– 1+2
D xÌÓy
ã˛y!•òyÓ˚ §ÇK˛y òyG– ã˛y!•òy ˆÓ˚áyÓ˚ í˛yl!òˆÏܲ fiÌylyhs˝ˆÏÓ˚Ó˚ !ï˛l!ê˛ Ü˛yÓ˚î !ÓÓ,!ï˛ Ü˛Ó˚–

29) !lˆÏ¡¨Ó˚ ≤ÈÏï˛ƒÜ˛ í˛zͲõyòˆÏl ≤Ãy!hs˝Ü˛ ÓƒÎ˚ (MC) !•§yÓ Ü˛Ó˚ /
í˛zͲõyòl å~ܲܲä àí˛¸ ˛õ!Ó˚Óï≈˛l¢#° ÓƒÎ˚ (AVC) ê˛yܲy
1 13
2 11
3 10
4 10
5 11
6 12
!Ó˲yàÈüÈSÈ / ≤Ã!ï˛!ê˛ ≤Èϟ¿Ó˚ Ùyl 4 / 4x3 = 12
30ä Ú!ܲ í˛zͲõyòl ܲÓ˚y •ˆÏÓÛ §Ù§ƒy!ê˛ ~ܲ!ê˛ í˛zòy•Ó˚î ~Ó˚ §y•yˆÏ΃ Óƒyáƒy ܲÓ˚–
31ä ˆÓ˚áy!ã˛e ÓƒÓ•yÓ˚ ܲˆÏÓ˚ ˆÙyê˛ í˛zͲõyòl ˛õ!Ó˚Óï≈˛ˆÏlÓ˚ !Ó!˲ߨ ˛õÎ≈yÎ˚ Ú˛õ!Ó˚Óï˛≈l#Î˚ xl%˛õyˆÏï˛Ó˚ !Ó!ôÛÓ˚ §y•yˆÏ΃ !ÓÓ,ï˛ Ü˛Ó˚–
D xÌÓy
ÓƒÎ˚ ~Ó˚ §ÇK˛y òyG– ˆÓ˚áy!ã˛e §•Ü˛yˆÏÓ˚ ≤Ãy!hs˝Ü˛ ÓƒÎ˚ ~ÓÇ àí˛¸ ˛õ!Ó˚Óï≈˛l¢#° ÓƒˆÏÎ˚Ó˚ ÙˆÏôƒ §¡õÜ≈˛ !lî≈Î˚ ܲÓ˚–
32ä ˆÎyàyl !fiÌ!ï˛fiÌy˛õܲï˛y ܲ#⁄ ~ܲ!ê˛ oˆÏÓƒÓ˚ ˆÎyàyˆÏlÓ˚ òyÙàï˛ !fiÌ!ï˛fiÌy˛õܲï˛yÓ˚ Ùyl 2 – ≤Ã!ï˛ ~ܲܲ 8 ê˛yܲy ܲˆÏÓ˚ ~ܲ!ê˛
Ê˛yÙ≈ 200 ~ܲܲ oˆÏÓƒÓ˚ ˆÎyàyl ˆòÎ˚– ï˛y•ˆÏ° Ê˛yÙ≈!ê˛ Ü˛ï˛ òyˆÏÙ 250 ~ܲܲ oÓƒ ˆÎyàyl ˆòˆÏÓ⁄ 2+ 2
!Ó˲yà ÈüÈ ç / ≤Ã!ï˛!ê˛ ≤Èϟ¿Ó˚ Ùyl ÈüÈ6 / 6x2=12
33ä ˆË˛y=˛yÓ˚ ˲yÓ˚§yˆÏÙƒÓ˚ §ÇK˛y òyG– ~ܲçl ˆË˛y=˛y ò%!ê˛ oÓƒ ˆË˛yà ܲˆÏÓ˚– í˛z˛õˆÏÎyà ï˛ˆÏ_¥Ó˚ §y•yˆÏ΃ ˆË˛y=˛yÓ˚ ˲yÓ˚§yÙƒ Óƒyáƒy
ܲÓ˚– 2+4
xÌÓy
ˆÓ˚áy!ã˛e§•Ü˛yˆÏÓ˚ ã˛y!•òyÓ˚ ˛õ!Ó˚Óï≈˛l ~ÓÇ ã˛y!•òyÓ˚ ˛õ!Ó˚ÙyˆÏîÓ˚ ˛õ!Ó˚Óï≈˛ˆÏlÓ˚ ÙˆÏôƒ ˛õyÌ≈ܲƒ !°ˆÏáy–
34ä xfl∫y˲y!Óܲ Ù%lyÊ˛y ܲ#⁄ ˆÓ˚áy!ã˛ˆÏeÓ˚ §y•yˆÏ΃ ˛õ)î≈ ≤Ã!ï˛ˆÏÎy!àï˛yÙ)°Ü˛ ÓyçyˆÏÓ˚ fl∫“ܲy°#l ˲yÓ˚§yˆÏÙƒ xfl∫y˲y!Óܲ Ù%lyÊ˛yÓ˚
xÓfiÌy Óƒyáƒy ܲÓ˚– 2+4
D x!ï˛!Ó˚=˛ ≤ß¿yÓ°#