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FOR GOA CLASS 9 PREPARATION
Goa Board Class 9
Sample Paper 2027
Mathematics
EXAM YEAR TYPE SUBJECT
Goa Class 9 2027 Sample Paper Maths
Notes · Sample Papers · Previous Year Papers · Mock Tests
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GOA BOARD OF SECONDARY AND HIGHER SECONDARY EDUCATION
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ALTO-BETIM GOA 403521
Grade 9 Subject: MATHEMATICS (E) ( 2026 – 2027 )
SEMESTER - I
PORTION AND MARKS DISTRIBUTION (2026-2027)
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MONTH Topic Marks Hours
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Chapter
No.
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1. c s e
April
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8
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JUNE
5 Introduction to Euclid’s Geometry
3 2
JULY 6 Lines and Angles 14 10
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7 Triangles 15 9
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PDF
Trigonometry
l as 8 8
AUGUST
8 ag
Quadrilaterals
10 8
Quadrilaterals contd….. 2
SEPTEMBER Revision 8
Total 80 marks
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s em Assignment on Financial
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g laASSESSMENT
INTERNAL
Education
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Lab Activities ( Any two ) 10 marks 2
Total 100 marks 75
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GOA BOARD OF SECONDARY AND HIGHER SECONDARY EDUCATION
ALTO-BETIM GOA 403521
Grade 9 Subject: MATHEMATICS (E) ( 2026 – 2027 )
SEMESTER – II
PORTION AND MARKS DISTRIBUTION (2026-2027 )
MONTH Topic Marks Hours
Chapter
No.
OCTOBER PDF Logarithms 10 8
3 Coordinate Geometry 3 3
NOVEMBER
4 Linear Equations in 2 variables 8 9
DECEMBER 10 Circles 14 10
12 Heron’s Formula 14 10
JANUARY
14 Statistics
15 11
FEBRUARY 13 Surface Areas and Volumes 16 12
MARCH Revision 8
Total 80 marks
Assignment on Experimental 10 marks 3
verification of properties /
INTERNAL theorems on circles using
ASSESSMENT Geoboard
Lab Activities ( Any two ) 10 marks 2
Total 100 marks 75
2
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GOA BOARD OF SECONDARY AND HIGHER SECONDARY EDUCATION
ALTO-BETIM GOA 403521
Rationalised syllabus 2026 – 2027
Grade 9 Subject : Mathematics
Chapter Units Included Units Deleted
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1. Number 1.1 Introduction 1.4 Representing Real
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systems 1.2 Irrational Numbers Numbers on the Number
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1.3 Real Numbers and their Decimal Expansions Line
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2. Polynomials 2.1 Introduction
2.2 Polynomials in One Variable
2.3 Zeroes of a Polynomial
2.4 Remainder Theorem
2.5 Factorisation of Polynomials
2.6 Algebraic Identities
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3. Co - ordinate 3.1 Introduction
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geometry 3.2 Cartesian System
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3.3 Plotting a Point in the Plane if its Coordinates
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are given
4. Linear equations in 4.1 Introduction
two variables 4.2 Linear Equations
4.3 Solution of a Linear Equation
4.4 Graph of a Linear Equation in Two Variables
4.5 Equations of Lines Parallel to x-axis and y-axis
5. Introduction to 5.1 Introduction 5.3 Equivalent Versions
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Euclid's geometry 5.2 Euclid's Definitions, Axioms and Postulates of Euclid's Fifth Postulate
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6.4 Pairs of Angles
Theorem (to prove): Thm 6.1
6.5 Parallel Lines and a Transversal
6.6 Lines Parallel to the same Line
6.7 Angle Sum Property of a Triangle
Theorem (to prove): Thm 6.7
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Theorems (Motivate – without proof): Thm 6.2, Thm
6.3, Thm 6.4, Thm 6.5, Thm 6.6, Thm 6.8
7. Triangles 7.1 Introduction 7.6 Inequalities in a
7.2 Congruence of Triangles Triangle
7.3 Criteria for Congruence of Triangles
7.4 Some Properties of a Triangle
Theorems (to prove): Thm 7.2 , Thm 7.3
7.5 Some More Criteria for Congruence of Triangles
Theorems (Motivate – without proof): Thm 7.1, Thm
7.4, Thm 7.5
8. Quadrilaterals 8.1 Introduction
8.2 Angle Sum Property of a Quadrilateral
8.3 Types of Quadrilaterals
8.4 Properties of a Parallelogram
Theorem (to prove): Thm 8.1
8.5 Another Condition for a Quadrilateral to be a
Parallelogram
8.6 The Midpoint Theorem
Theorems (Motivate – without proof): Thm 8.2, Thm
8.3, Thm 8.4, Thm 8.5, Thm 8.6, Thm 8.7, Thm 8.8
9. Areas of FULL CHAPTER
Parallelograms
10. Circles 10.1 Introduction Ex 10.3
10.2 Circles and its Related Terms Ex 10.5 from sum no. 7
10.3 Angle Subtended by a Chord at a Point onwards
Theorems (to prove): Thm 10.1 , Thm 10.2
10.4 Perpendicular from the Centre to a Chord
Theorems (to prove): Thm 10.3 , Thm 10.4
10.5 Circle through three Points
10.6 Equal Chords and their Distances from the Centre
10.7 Angle Subtended by an Arc of a Circle
10.8 Cyclic Quadrilaterals
Theorems (Motivate – without proof):
Thms: 10.5, 10.6 , 10.7 , 10.8 , 10.9 , 10.10 , 10.11
11. Constructions FULL CHAPTER
12.Heron's Formula 12.1 Introduction
12.2 Area of a Triangle – by Heron's Formula
12.3 Application of Heron's Formula in finding
Areas of Quadrilaterals
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Volumes 13.3 Surface Area of a Right Circular Cylinder Cuboid and a Cube
13.4 Surface Area of a Right Circular Cone 13.6 Volume of a
13.5 Surface Area of a Sphere & Hemisphere Cuboid and a Cube
13.7 Volume of a Right Circular Cylinder
13.8 Volume of a Right Circular Cone
13.9 Volume of a Sphere & Hemisphere
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14. Statistics 14.1 Introduction 14.4 (A) Bar Graphs
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14.2 Collection of Data
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14.3 Presentation of Data
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14.5 Measures of Central Tendency
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15. Probability FULL CHAPTER
* Trigonometry (PDF) Full PDF
* Logarithms (PDF) Full PDF
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GOA BOARD OF SECONDARY AND HIGHER SECONDARY EDUCATION
ALTO-BETIM GOA 403521
Mapping Syllabus with Curricular Goals and Competencies
2026 – 2027
Grade 9 Sub: Mathematics (E)
Sr. Chapter Curricular Competencies
No Goals
1. Number Systems CG-1 C-1.1
CG-2 C-2.1
2. Polynomials CG-3 C-3.1
C-3.2
3. Introduction to Euclid’s CG-4 C-4.1
Geometry CG-7 C-7.1
CG-10 C-10.1
C-10.2
4. Lines and Angles CG-4 C-4.1
C-4.2
C-7.3
5. Triangles CG-4 C-4.1
C-4.2
CG-7 C-7.3
6. Quadrilaterals CG-4 C-4.1
C-4.2
CG-7 C-7.3
7. Trigonometry CG-4 C-4.6
8. Logarithms CG-9 C-9.1
C-9.3
9. Coordinate Geometry CG-4 C-4.5
CG-10 C-10.1
10. Linear Equations in two CG-3 C-3.2
variables CG-8 C-8.1
11. Circles CG-4 C-4.1
C-4.3
12. Heron’s Formula CG-5 C-5.1
CG-10 C-10.1
13. Surface Areas and Volumes CG-5 C-5.2
CG-8 C-8.2
C-8.3
14. Statistics CG-6 C-6.1
CG-8 C-8.1
CG-11 C-11.1
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Competency Based Learning Outcomes
Grade 9 Sub: Mathematics (E)
Chapter Name Learning Outcomes
and
Serial No.
1. Number The learner
Systems • Applies logical reasoning in classifying real numbers,
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proving their properties and using them in different
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decimal representation.
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Understands the operations on irrational numbers and
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applies to solve the numericals.
Represents real numbers on the number line.
• Rationalises the denominator of real numbers.
• Extends the understanding of powers(radical powers)
and exponents to real numbers.
• Applies the extended laws of exponents to simplify
expressions.
2. Polynomials The learner
•
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Identifies/Classifies polynomials among algebraic
expressions .
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Understands the concept of degree of polynomials.
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Understands the concept of zeros of a polynomial and
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applies it to find zeros of any given polynomial.
• Applies the remainder theorem to find the remainder
when a polynomial is divided by a linear polynomial.
• Finds the factors of a polynomial using factor theorem.
Factorises polynomials by applying appropriate algebraic
identities.
3.Introduction to The learner
Euclid’s • Understands Euclid’s contribution in Plane Geometry.
Geometry Defines axioms , postulates theorems with reference to
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Euclidean Geometry
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4.Lines and The learner
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Angles • Develops understanding of basic terms and definitions
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problems.
States and applies angle sum property and exterior angle
property to various geometrical situations.
5.Triangles The learner
• Derives proofs of mathematical statements particularly
related to geometrical concepts , like triangles by
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applying axiomatic approach and solves problems using
them.
• Understands the criteria of congruency of triangles.
Applies various criteria of congruency of triangles to
solve related problems
6. Quadrilaterals The learner
• Identifies various types of quadrilaterals.
• Analyses and applies properties of parallelogram to prove
various relationships.
Applies midpoint theorem to solve problems.
7. Trigonometry The learner
• Demonstrates an understanding of the relationship
between the sides of a triangle and the trigonometric
ratios :sine ,cosine and tangent.
• Evaluates trigonometric expressions using values of
trigonometric ratios for standard angles.
• Derives the relationship between sin𝜃 and cos𝜃.
Applies the relationship for solving problems.
8. Logarithms The learner
• Understands the concepts of logarithm.
• Writes given number using scientific notations.
• Find characteristic of a number using scientific form.
• Finds logarithm and antilogarithm of numbers using log
tables.
• Understands and applies laws of logarithms to simplify
algebraic expressions
Applies logarithms to solve real life problems
9. Coordinate The learner
Geometry • Understands the concept of Cartesian system of
coordinates.
• Develops strategies to locate points in a Cartesian plane.
• Finds abscissa and ordinate of a point in a Cartesian
plane.
Plots the given points in a Cartesian plane
10.Linear The learner
Equations in two • Identifies and models real life situations into a linear
variables equation in two variables.
• Develops the understanding of infinitely many solutions
of a linear equation in two variables.
• Relates the algebraic and graphical representations of a
linear equation in two variables.
Represents the linear equation in one and two variables
as a straight line in the Cartesian plane.
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• Recollects the knowledge of different terms related to
circles.
• Derives proofs of theorems related to circles by applying
axiomatic approach.
Applies theorems to solve problems.
12.Heron’s The learner
Formula • Computes area of a triangle using Heron’s formula.
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• Applies The concept of Heron’s formula in real life
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13. Surface The learner
Areas and
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Derives formulae for surface areas and volumes of
Volumes
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cylinders , cones spheres and hemispheres.
Applies formulae to solve problems.
Applies the formulae to find surface areas and volumes
of the objects found in surrounding areas.
14. Statistics The learner
• Represents the data as frequency distribution table
(grouped or ungrouped) and graphically as bar graphs ,
histograms and frequency polygons.
•
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Analyses and interprets the data represented using
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various forms.
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Computes mean , median and mode for ungrouped data.
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3.6.1 Pedagogy for Mathematics a
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3.6.1.3 Integrating Mathematics with other Curricular Areas
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Revised Bloom’s Taxonomy :
The revised Bloom’s taxonomy includes the following levels:
• Remembering: Exhibit memory of previously learned material by recalling facts ,
terms , basic concepts and answers.
• Understanding: Demonstrate understanding of facts and ideas by organizing
,comparing , translating , interpreting , giving descriptions and stating main ideas.
• Applying ; Solve problems to new situations by applying acquired knowledge ,
facts , techniques and rules in a different way.
• Analysing : Examine and break information into parts by identifying motives and
causes. Make inferences and find evidence to support generalization.
• Evaluating : Present and defend opinions by making judgements about
information , validity of ideas, or quality of work based on asset of criteria.
• Creating : Compile information together in a different way by combining elements in
a new pattern or proposing alternative solutions.
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GOA BOARD OF SECONDARY AND HIGHER SECONDARY EDUCATION
ALTO-BETIM GOA 403521
Grade 9 MATHEMATICS LABORATORY ACTIVITIES ( 2026-2027 )
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ROLE OF MATHEMATICS LABORATORY IN TEACHING - LEARNING
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The Mathematics Laboratory allows and encourages the students to think, discuss with each other
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and the teacher, and assimilate the concepts in a more effective manner.
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It enables the teacher
concrete objects, models, charts, graphs, pictures etc
There is no second opinion that for effective teaching and learning. ‘Learning by Doing’ is of great
importance as the experiences gained remain permanently affixed in the mind of the child.
This PDF has 8 activities for STD IX which can be done in the class and some are selected from the
LABORATORY MANUAL IN MATHEMATICS AT SECONDARY STAGE.
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It is based on the National Education policy (NEP)2020.
Activities for the two terms are as follows:
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FIRST TERM 1, 2, 3, 4 (any two)
SECOND TERM 5, 6, 7, 8 (any two)
Students should maintain a file of the activity done.
NOTE: High-achieving students or students with keen interest in the subject can be
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motivated and encouraged to complete as many activities as per their interest with
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teacher’s guidance by referring to the laboratory manual online as follows:
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3.Laboratory Manual
4.Standardwise Maths activities
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Grade 9 : MATHEMATICS LABORATORY ACTIVITIES
Sr. No. List of Activities
1 To make a square root spiral by paper folding
2 To verify the algebraic identity:
( a + b + c )2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
3 To verify experimentally the different criteria for congruency of triangles using
triangle cut outs
4 To verify the midpoint theorem using paper cutting and pasting
5 To plot a set of points on the Cartesian plane to create an artistic picture
6 Drawing Histogram and Frequency Polygon for a real life situation (Eg. Heights of a
Group of Students )
7 Exploring Pythagoras Theorem using regular polygons and semicircle
8 Exploring Volume of an Open-Top Box Made from a Square Sheet.
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OBJECTIVE
To make a square root spiral by paper folding.
MATERIALS REQUIRED
Rectangular blank sheet of paper , geometry box , coloured pencils etc
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METHOD OF CONSTRUCTION:
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1. Take a rectangular
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2. Draw laa horizontal line OP = 1 unit using a ruler and a pencil. a
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a and press the paper along OP in such a way that the crease OP is formed.
3. Fold
4. Form a crease perpendicular to OP. Unfold and draw PA = 1 unit on the new
crease formed.
5. Form a crease joining OA so that right - angled triangle OPA is formed.
See Fig. 1 (a)
6. Form a crease perpendicular to OA , unfold and draw BA = 1 unit on the crease
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7. Join OB so that right - angled triangle OAB is formed .
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8. In the same way , unfold and draw BC = 1 unit perpendicular
a on .
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DEMONSTRATION :
In right - angled triangle OPA ,
OA2 = OP2 + PA2
𝑂𝐴 = √12 + 12
𝑂𝐴 = √2 𝑢𝑛𝑖𝑡𝑠
OBSERVATION :
1. In right - angled triangle OAB ,
𝑂𝐵 = √𝑂𝐴2 + 𝑂𝐵 2
= =
2. In right - angled triangle OBC ,
𝑂𝐶 = √𝑂𝐵 2 + 𝐵𝐶 2
= =
Continuing like this , we observe that lengths of hypotenuses OA, OB
, OC , OD ,… are
, …respectively.
APPLICATION :
The shape so formed by performing the activity is a square root spiral.
Through this activity, existence of irrational numbers can be illustrated.
Alternate method: https://youtu.be/i_MNzAJFK0c?si=8fhUGjqBtjS-6nEO
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OBJECTIVE
To verify the algebraic identity :
( a + b + c )2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
MATERIALS REQUIRED
Coloured papers , adhesive, scissors ,geometry box etc.
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METHOD OF CONSTRUCTION
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1. Cut out a square ofm
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2. Cut out a square of
3. Cut out a a
square of side c units from a coloured paper ( see Fig. 3 )
4. Cut out two rectangles of dimensions a × b , two rectangles of dimensions b × c and
two rectangles of dimensions c × a square units from a coloured paper ( see Fig. 4 )
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Page 17
DEMONSTRATION
From the arrangement of squares and rectangles in Fig. 5 , a square ABCD is
obtained whose side is ( a + b + c ) units.
Area of square ABCD = ( a + b + c ) 2
Therefore , ( a + b + c ) 2 = sum of the areas of all the squares and rectangles shown
in Fig. 1 to Fig. 4
= a2 + ab + ac + ab + b2 + bc + ac + bc + c2
= a2 + b2 + c2 + 2ab + 2bc + 2ca
Here , area is in square units.
On actual measurement :
a = …………….., b = ………………, c = ................. ,
So , a2 = ………………, b2 = …………….., c2 =................ ,
ab = ……………., bc = …………….., ca = ................ ,
2ab = …………….., 2bc = ……………., 2ca = ……………., a+b+c =
…………….., ( a + b + c )2 =................. ,
Therefore , ( a + b + c )2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
APPLICATION: The identity may be used for
1. simplification/factorisation of algebraic expressions
2. calculating the square of a number expressed as a sum of three convenient numbers.
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a Alternate method - paper folding activity ag
(by Prof. V.S.S.Sastry Kolar)
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ACTIVITY 3
OBJECTIVE
To verify experimentally the different criteria for congruency of triangles
using triangle cut-outs
MATERIALS REQUIRED
Chart paper , scissors , cutter , geometry box , pencil / sketch pens , coloured glazed
papers etc
METHOD OF CONSTRUCTION
Take a chart paper of a convenient size.
1. Make a pair of triangles ABC and DEF in which AB = DE,BC = EF, AC =DF on a glazed paper
and cut them out . ( see Fig. 1 )
2. Make a pair of triangles GHI and JKL in which GH =JK , GI = JL,
∠𝐺 = ∠ J on a glazed paper and cut them out . ( see Fig.2)
3. Make a pair of triangles PQR and STU in which QR = TU , ∠Q = ∠T , ∠R = ∠U on a
glazed paper and cut them out. ( see Fig. 3 )
4.Make two right triangles XYZ and LMN in which hypotenuse YZ= hypotenuse MN
and XZ = LN on a glazed paper and cut them out . ( see Fig. 4)
A D
B C E F
Fig.1
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Fig. 4
DEMONSTRATION
1. Superimpose ∆ABC on ∆DEF and see whether one triangle covers the other triangle or
not by suitable arrangement . See that ∆ABC covers ∆DEF completely only under the
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correspondence A ↔ D , B ↔ E , C ↔ F.
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So , ∆ABC ≅ ∆DEF , if AB = DE , BC= EF and AC = DF.
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Similarly , establish ∆GHI ≅ ∆JKL , if GH =JK , ∠𝐺 = ∠ J and =g
GIa
g
JL . This is SAS
a for congruency.
3. Establish ∆PQR ≅ ∆STU , if QR = TU , ∠Q = ∠T and ∠R = ∠U. This is ASA
criterion for congruency.
4. In the same way , ∆XYZ ≅ ∆LMN , if hypotenuse YZ = hypotenuse MN and XZ = LN. This
is RHS criterion for right triangles.
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OBSERVATION
1. In ∆ABC and ∆DEF
AB = DE = ……, BC = EF =………, AC = DF = ………,
On actual measurement
∠A = …………………., ∠D =......................,
∠B = …………………., ∠E =...................... ,
∠C = …………………., ∠F =......................,
Therefore , ∆ABC ≅ ∆DEF
2. In ∆GHI and ∆JKL
GH = JK = ……..,GI = JL = ……,∠G = ∠J = ............ ,
On actual measurement
HI = …………………, KL =....................... ,
∠I = ……………………., ∠L =..................... ,
∠H = …………………., ∠K =..................... ,
Therefore , ∆GHI ≅ ∆JKL
3. In ∆PQR and ∆STU
QR = TU = ………, ∠Q = ∠T = ………,∠R = ∠U = ...................... ,
On actual measurement
PQ = ……,ST = ………., PR = .. .……, SU =...........,
∠P =……….., ∠S = ........... ,
Therefore , ∆PQR ≅ ∆STU
4. In ∆XYZ and ∆LMN , ∠X = ∠L = 900
hypotenuse YZ = hypotenuse MN = ………, XZ = LN = ............... ,
On actual measurement
LM = …………, XY = …………, ∠Y=…………,∠M =............. ,
∠N = ……………, ∠Z = ..................... ,
Therefore , ∆XYZ ≅ ∆LMN.
Note: Students should find out why the SSA congruence rule is not possible, as the sides can be
located in two different parts of the triangles and not corresponding sides of the two triangles.
APPLICATION
These criteria are useful in solving a number of problems in geometry.
These criteria are also useful in solving some practical problems such as finding
width of a river without crossing it .
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OBJECTIVE
To verify the mid-point theorem for a triangle using paper cutting and pasting
Midpoint theorem
A straight line joining the mid-points of any two sides of a triangle is parallel to the
third side and is equal to half of it.
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MATERIALS REQUIRED
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Coloured sheet , tracing paper, geometry box, a pair of scissors, adhesive or fevicol etc.
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e of paper and obtain the mid-points P , Q and R of sides AB , AC gl as
s
METHOD OF CONSTRUCTION
1. Draw ∆ABC on a asheet
l by paper folding a
a g
and BC respectively
2. Join P and Q by folding and making a crease PQ ( see Fig. 1 )
3. Make a replica of ∆APQ and cut it out.
DEMONSTRATION
Superimpose AQ over QC , so that QP falls along CB ( see Fig. 2 )
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A A
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P Q
agP Q(A)
C
R B R C
Fig. 1 Fig. 2
OBSERVATION
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c. o2.1. They exactly .
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form angles on PQ and BC , AC being a transversal.
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is parallel to BC.
ag 4. Also , P coincides with R.
= BC
APPLICATION
Mid-point theorem is verified and it is useful in solving a number of geometrical
problems.
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Page 23
ACTIVITY 5
OBJECTIVE
To create a hidden picture by plotting and joining points with given coordinates on the Cartesian plane.
MATERIALS REQUIRED
• Cardboard, White paper, scissor, Pencil, Adhesive, Graph paper (squared paper), Geometry box
METHOD OF CONSTRUCTION
1. Take a cardboard of a suitable size and paste a white sheet on it.
2. Paste a graph paper neatly on the white sheet.
3. Draw two perpendicular axes, X’OX (horizontal) and Y’OY (vertical), representing the Cartesian
plane.
4. Plot the given points A, B, C, ... with coordinates such as (a, b), (c, d), (e, f), etc.
5. Join the points in the specified order: A → B → C → D → ... → A, to form a closed figure.
6. The figure will reveal a hidden image.
DEMONSTRATION
By plotting and joining the points as instructed, a hidden image of a ‘ ’ (e.g., kite, house,
tree) appears on the graph.
OBSERVATION
• Coordinates of the points:
A=( , ), B = ( , ), C = ( , ),= ( , ), ...
• Hidden picture formed:
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APPLICATION
This activity enhances understanding of:
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• Cartesian coordinates and plotting of points
• Shapes formed by connecting coordinates
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• Practical uses such as road maps, classroom layouts, and blueprint design.
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N.B : Teachers are requested to provide coordinates for hidden pictures, or students may create their own
sets of coordinates that form a picture (e.g., a house, bird, animal, fish, vase, etc.) when joined.
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Page 25
ACTIVITY 6
OBJECTIVE
To draw a Histogram and Frequency Polygon for the heights of a group of students.
MATERIALS REQUIRED
Graph paper, pencil, ruler, eraser, notebook.
METHOD OF CONSTRUCTION
1. Data Collection:
- Measure and record the heights of 30 students in your class (in cm).
2. Organize Data into Class Intervals:
- Form suitable class intervals, e.g., 140–145 cm, 145–150 cm, etc.
3. Prepare a Frequency Table:
- Count how many students fall into each height group.
4. Draw the Histogram:
- Draw class intervals on the x-axis and frequencies on the y-axis.
- Draw rectangles (bars) without gaps. The height of each bar should represent the frequency of the
corresponding class interval.
5. Draw the Frequency Polygon:
- Find the midpoints of each class interval.
- Plot points as (midpoint, frequency).
- Connect the points using straight lines.
- Extend the polygon by joining the first and last points to the x-axis at height 0.
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Class Interval (Height in cm) Frequency (No. of Students)
140 – 145 3
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145 – 150 6
150o–m .
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l as 160 – 165 7
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4
Graph Work:
1. Histogram:
• Draw bars for each class interval with heights equal to their frequencies.
• Note: There should be no gaps between the bars.
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2. Frequency Polygon:
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• Midpoints: 142.5, 147.5, 152.5, 157.5, 162.5
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• Plot the points: (142.5, 3), (147.5, 6), (152.5, 10), (157.5, 7), (162.5, 4)
• Connect the points with straight lines.
• Join the first and last points to the x-axis at height 0.
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N.B : The above activity is just an example using mock data. Teachers are requested to help students
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use real data such as their weights, heights, marks in Semester -1 Mathematics, etc. for statistics
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activities.
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Page 27
ACTIVITY 7
OBJECTIVE
To explore the Pythagoras Theorem using areas of regular polygons (such as equilateral triangles,
squares, hexagons) and semicircles constructed on the sides of a right-angled triangle.
MATERIALS REQUIRED
• Cardboard, White paper, Coloured paper Compass, Protractor, Ruler, Pencil, Scissors, Glue
METHOD OF CONSTRUCTION
1. Draw a right-angled triangle ABC (right-angled at B) on cardboard.
2. Construct regular shapes (square, equilateral triangle, hexagon, or semicircle) on each side AB,
BC, and AC.
3. Ensure the shapes are constructed such that each shares a side with the triangle.
4. Calculate or cut and paste shapes on each side showing the area.
5. Demonstrate that:
Area on AB + Area on BC = Area on AC
(i.e., sum of areas on the legs = area on the hypotenuse).
6. Repeat for different regular polygons and semicircles.
DEMONSTRATION
By constructing the same regular polygon (e.g., squares or semicircles) on each side of a right triangle,
it can be visually shown that the area on the hypotenuse equals the sum of areas on the other two
sides—thus proving the Pythagoras Theorem in a geometric and visual way.
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After constructing the regular polygons (e.g., squares, equilateral triangles, hexagons, and semicircles)
on each side of the right-angled triangle, the following observations were made:
• The combined area of the shapes on the two shorter sides (legs) is equal to the area of the shape
on the hypotenuse, regardless of the type of regular polygon or semicircle used.
• This visual and area-based approach confirms the Pythagoras Theorem:
(Area on side AB) + (Area on side BC) = (Area on side AC)
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• The result holds true consistently across different shapes, reinforcing the geometric truth of the
theorem.
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APPLICATION
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• Enhancesgvisual
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• Helps understand the concept of area in regular polygons.
• Useful in architectural design, geometry-based problem solving, and spatial understanding.
• Encourages creativity and application of mathematics in real-world geometry.
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Page 29
ACTIVITY 8
OBJECTIVE:
To explore how the volume of an open-top box changes when squares of different sizes are cut from each
corner of a square sheet and the sides are folded up to form the box.
MATERIALS REQUIRED:
• Square sheets of paper or card (12 inches × 12 inches)
• Ruler, Pencil, Scissors
METHOD OF CONSTRUCTION:
6. Take a square sheet of size 12 inches × 12 inches.
7. Cut equal squares from each corner. Try cutting squares of side 1 inch, 2 inches, 3 inches, etc.
8. Fold up the flaps formed by the remaining edges to form an open-top box.
9. The height of the box will be equal to the side of the square cut from each corner.
10. Use the formula to calculate the volume of the box:
Volume = length × breadth × height
where,
- height = 𝑥 (cut size)
- length = 12 − 2 𝑥
- breadth = 12 − 2 𝑥
DEMONSTRATION:
Construct several boxes by cutting squares of side:
- 1 inch
- 2 inches
- 3 inches
- 4 inches
- …
Calculate volume for each case using the formula above.
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Cut Size Length Breadth Height Volume
(inches) (in) (in) (in) (cubic in)
1
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2
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3
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4
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APPLICATION:
This activity demonstrates a practical optimization problem. It shows how changing one dimension affects
the others and the overall volume. This concept is useful in packaging design, waste reduction and
engineering solutions where material usage and space optimization are important.
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Conclusion: ( To be written by students ) :
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Through this activity, I observed that ….. ag
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Page 31
GOA BOARD OF SECONDARY AND HIGHER SECONDARY EDUCATION
ALTO- BETIM , GOA 403521
Grade 9 Subject: MATHEMATICS Yr: 2026 - 2027
SEMESTER I : ASSIGNMENT ( FINANCIAL EDUCATION ) Max.Marks: 10
Topic: BANKING
INSTRUCTIONS:
1) Prepare a portfolio with the help of the guidelines given below.
2) Visit a Bank and obtain the following information required for the assignment.
Sr. No. Banking Marks
1. Cover page design of the LOGO and SLOGAN of the Bank visited. 1
2. Index ½
3. Functions of a Bank and Importance of Saving. ½
4. Types of Bank accounts and their advantages. 1
Type of Bank Loans.
5. Find the eligibility criteria and documents required for taking an 1
educational loan.
6. Documents required for opening a Bank Account. ½
Calculation of maturity amount on a Recurring Deposit.
For eg: You deposited ₹200 per month in Bank A for 2 years under the
7. Recurring Deposit Scheme. ½
Find the maturity value at the end of 2 years. (Write
the formula and show the calculations)
Calculation of maturity amount on a Fixed Deposit.
For eg: You deposited ₹ 5000 in Bank A for 2 years under the fixed deposit scheme.
8.
Find the Maturity value at the end of 2 years. 1½
(Write the formula and show the calculations).
9. Fill up a withdrawal slip, deposit slip and a xerox of a cheque. 1½
10. Acknowledgement. ½
11. Bibliography. ½
TOTAL 10
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GOA BOARD OF SECONDARY AND HIGHER SECONDARY
ALTO- BETIM , GOA 403521
Grade 9 Subject: MATHEMATICS Yr : 2026 - 2027
SEMESTER II : ASSIGNMENT ( GEOBOARD ) Max.Marks: 10
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Topic : Exploring circle theorems using Geoboard
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Objective:
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- To explore and illustrate basic circle theorems using a self-made circular Geoboard.
- To develop conceptual understanding through hands-on activity.
Materials Required:
• Wooden board/cardboard (20cm×20cm or 25cm×25cm)
• Small nails or push pins
•
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Protractor, ruler, compass, pencil/Markers
• Rubber bands or coloured threads
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• Chart/notebook for observations
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Steps to Make the Geoboard:
i. Find a central point on the board and using a compass draw a circle with centre O .
ii. Mark evenly spaced points around the circle’s circumference .
( e.g. every 15° for 24 points)
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iii. Insert small nails or push pins at each marked point.
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iv. Use rubber bands or coloured threads to create chords and other shapes to
demonstrate circle properties.
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e Concepts & Theorems to Demonstrate/Investigate/Explain Using Geoboard:
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ag 1. Equal chords of a circle are equidistant from the centre
• Make two chords AB and CD of equal length.
• Verify that perpendiculars from the centre of the circle to both the chords are equal.
2. The perpendicular from the centre of a circle to a chord bisects the chord.
• Make a chord XY.
•
c
Verify that the perpendicular from the centre of the circle bisects the chord.
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3.1 Alternate segment Theorem (Inscribed Angle Theorem )
• Make an arc PB subtending ∠POB at the centre O and ∠PQB at point Q on
the remaining part of the circle.
• Measure inscribed ∠PQB and central ∠POB
• Verify that the inscribed angle is half of the central angle .
3.2. Angle in a Semicircle theorem
• Make a diameter EF.
• Choose a point D on the circle and measure ∠EDF
• Verify that ∠EDF = 90°
4. Angles in the same segment are equal.
• Make a chord MN .
• Choose two more points S and T on the circle.
• Measure ∠MSN and ∠MTN .
• Check that both angles are equal.
5. Opposite angles of a cyclic quadrilateral sum to 180°.
• Take four points A , B , C and D on the circle .
• Connect them in order : A-B , B-C , C-D , D-A to form a quadrilateral.
• Find the measure of each pair of opposite angles .
• Verify that ; ∠ABC + ∠CDA = 180° and ∠BCD + ∠DAB= 180°
Conclusion: (to be written by the student): …………
*******************************************************
NOTE:
❖ Use the Geoboard to illustrate each theorem with rubber bands/ coloured threads and
measure/observe relationships using a scale.
❖ Draw diagrams of each, showing the measured data and label them neatly.
❖ # Teachers can guide students to measure angles using paper folding techniques and record their
findings in a tabular form.
INSTRUCTIONS:
1) Prepare a Geoboard with the help of the guidelines given above .
2) Explain the Concepts & Theorems Using Geoboard.
Sr. No. Criteria Marks
1. Geoboard Construction 5
2. Presentation / Explanation of concepts on circles using Geoboard
5
Total
10
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Page 34
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GOA BOARD OF SECONDARY AND HIGHER SECONDARY
ALTO-BETIM GOA 403521
DESIGN OF THE QUESTION PAPER (2026-2027)
SEMESTER-I
Subject : MATHEMATICS (E)
Time : 3 hrs Grade : 9
o
Max. Marks : 80 m
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The weightage orem a
s the distribution of marks over different dimensions of the
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question paper
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a to the Learning objectives :
1. Weightage
Sr. No. Learning Objectives Marks Percentage of Marks
1. Remembering and 50 62.5%
Understanding
2. Applying 20 25%
3. Analysing , Evaluating 10
m 12.5%
and Creating
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Total
80 100%
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ag of Content :
2. Weightage to the different areas
Chapter No. Topic Marks
1 Number systems 12
2 Polynomials 17
5 Introduction to Euclid’s Geometry 03
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6 Lines and Angles
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Triangles
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a Total 80
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3. Weightage to different form/type of Questions :
Sr. No. Form of Questions Marks for Number of Total
each question questions Marks
1. Very Short Answer Type (VSA) 1 20 20
2. Short Answer Type I (SA-I) 2 11 22
3. Short Answer Type II (SA-II) 3 10 30
4. Long Answer Type (LA) 4 2 08
Total 43 80
4. The expected time for different type of questions would be as fo follows:
Sr. No. Form of Questions Approx. time Number Approx. time
for each of for each form
question in questions of questions in
mins (t) (n) mins (t) x (n)
1. Very Short Answer Type (VSA) 2 20 40
2. Short Answer Type I (SA-I) 3 11 33
3. Short Answer Type II (SA-II) 8.5 10 85
4. Long Answer Type(LA) 11 02 22
Total 43 180
4. Weightage to difficulty level of questions:
Sr. No. Estimated difficulty level of questions Percentage
1. Easy 20%
2. Average 60%
3. Difficult 20%
Total 100%
5. Number of Questions:
There will be 43 questions
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BLUE PRINT OF SEMESTER-I EXAM MATH QUESTION PAPER ; 2026-2027
Grade 9
Objectives
Sr.
No. Topic Remembering & Understanding Applying Analysing , Evaluating & Creating Total
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VSA SAI SAII LA VSA SAI SAII LA VSA SAI SAII LA
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1mk 2mk 3mk 4mk 1mk 2mk 3mk 4mk 1mk 2mk 3mk 4mk
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1 Number 1(1) 22(2) 32(3) 12(1) 21(2) 7(12)
systems 2(1) 24(2)
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2 Polynomials 3(1)
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*23(2) 33(3) 13(1) 19(1)
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42(4) 9(17)
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*27(2)
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5
to Euclid’s a
Introduction
g 5(1) 28(2) 2(3)
Geometry
6 Lines and 6(1) 26(2) *34(3) 14(1) 39(3) 31(2) 8(14)
Angles 7(1) 15(1)
7 Triangles 8(1) 35(3) 40(3) 43(4) 20(1) 6(15)
*36(3)
8 Quadrilaterals 9(1) 29 (2) 37(3) 16(1) 41(3) 5(10)
PDF Trigonometry 10(1) 30(2) 38(3) 17(1) 6(9)
11(1) 18(1)
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Total 11(11) 9(18) 7(21) 0(0) 7(7) 0(0) 3(9) 1(4) 2(2) 2(4) 0(0) 1(4)
em
27(50) 11(20) 5(10) 43(80)
s
la indicate the question number and
figures within the bracket a
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NOTE: Figures outside the bracket
indicate marks .
*Indicates internal choice to be provided.
This is a model Blueprint, paper setter may make
changes in the objectives chapter wise.
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GOA BOARD OF SECONDARY AND HIGHER SECONDARY EDUCATION
ALTO – BETIM GOA 403521
MODEL QUESTION PAPER ( 2026-2027)
SEMESTER I
SUBJECT: MATHEMATICS (E)
TIME : 3 Hrs GRADE 9 MAX. MARKS : 80
INSTRUCTIONS:
i. This question paper consists of 43 questions. All questions are
compulsory.
ii. This question paper is divided into four Sections.- A , B , C and D.
iii. In Section A , question numbers 1 to 20 are multiple choice
questions (MCQs) and question numbers 19 and 20 are
Assertion – Reason based questions of 1 mark each.
iv. In Section B , question numbers 21 to 31 are short answer type I
(SA-I) questions carrying 2 marks each.
v. In Section C , question numbers 32 to 41 are short answer type II
(SA-II) questions carrying 3 marks each.
vi. In Section D , question numbers 42 and 43 are long answer (LA)
questions carrying 4 marks each.
vii. There is no overall choice . However , an internal choice has been
provided in two questions of 2 marks each in Section B and two
questions of 3 marks each in Section C.
viii. In the question on construction, the drawing should be clear and
exactly as per given measurement. The construction lines and arcs
should also be maintained.
ix. Use of calculator is NOT permitted.
Section A (1 mark each)
Select and write the correct alternative from those given below each
statement for question 1 to 20:
1. The decimal representation of a rational number is :
• always terminating
• either terminating or repeating
• either terminating or nonrepeating
• neither terminating nor repeating
2. Which of the following is an irrational number
•
√24 • √𝟓 × √𝟓
√6
• √𝟓 × √3
4
• √
9
3. The degree of the polynomial 5𝑥 3 − 7𝑥 2 + 9 is :
• 0 • 1 • 2 • 3
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se a
l:
When 𝑥 − 5𝑥 + 4 is divided by 𝑥 + 1 the remaindergis
3
• 0 • 8 • 9a • 10
5. How many dimensions does a plane surface have ?
• 0 • 1 • 2 • 3
6. The sum of the angles formed on the same of a straight line at a point is :
• 90° • 180° • 270° • 360°
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7. Which of the following statements is true ?
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• all adjacent angles are supplementary.
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• vertically opposite angles are always supplementary.
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• if two lines intersect , adjacent angles are always equal.
• vertically opposite angles are always equal. ag
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8. In ∆PQR ,if QP = QR , S is the midpoint of PR and ∠PRQ = 35°, then ∠PQS is :
• 35° • 55° • 70° • 110°
9. If the diagonals of a quadrilateral bisect at right angles , the figure is a :
• trapezium • rectangle
• parallelogram • rhombus
10. The value of tan 30° is :
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• 0 •
1
c. o • 1 • √3
√3
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11. In the figure , the value of cos𝜃 is :
las √5
•
2
3 ag •
√5 𝜃
2
2 3
3
• √5
2 •
3
12. The real number that lies between 2 and 3 on the number line is :
• √3 • √4 • √7 • √10
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13. . If 𝑥+y =5 and 𝑥 +𝑦 =111 then the value of 𝑥 +𝑦 is : e
s
2 2 3 3
s em • 115 • 220 • 555
g l a • 770
g la 14. If the difference between two supplementary angles is 60°
a , then the smaller
a angle is :
• 30° • 60° • 90° • 110°
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15. If two exterior angles of a triangle are 110° and 120° , then the measure of
the third exterior angle is :
• 110° • 120° • 130° • 230°
3
16. One side of the parallelogram is 2.4cm and the other side is times of the
2
first side , then the perimeter of the parallelogram is :
• 7.8 cm • 10.8 cm • 12 cm • 14.4 cm
17. If A is an acute angle and 𝑠𝑖𝑛2 A + 𝑠𝑖𝑛2 65° = 1 , then the value of A is :
• 0 • 25 • 65 • 1
1−𝑡𝑎𝑛2 45°
18. The value of is same as the value of :
1+𝑡𝑎𝑛2 45°
• sin 0° • cos 0° • tan 45° • tan 90°
Directions :
In Q. No. 19 and 20, a statement of Assertion (As) is followed by a statement of
Reason (R). Select the correct option from the following :
• Both, Assertion (As) and Reason (R) are true. Reason (R) explains
Assertion (As) completely.
• Both , Assertion (As) and Reason (R) are true . Reason (R) does not
explain Assertion (As).
• Assertion (As) is true but Reason (R) is false.
• Assertion (As) is false but Reason (R) is true.
19. Assertion (As) : The remainder when p(𝑥) = 𝑥 3 − 2𝑥 2 + 3𝑥 is divided by
9
by 2𝑥+1 is 8 .
Reason (R) : If a polynomial p(𝑥) is divided by a𝑥 − b , the remainder is
b
the value of p(𝑥) at 𝑥 = a
20. Assertion (As): In ∆ABC and ∆PQR , If AB = PQ , AC = PR and ∠ BAC = ∠PQR
then , ∆ABC ≅ ∆PQR
Reason (R) : Both triangles are congruent by SSS congruence rule
Section B ( 2 marks each )
21. Represent √7.3 on the number line.
22. ̅̅̅ in the form 𝑝 , where p and q are integers and q≠ 0.
Express 0. ̅54 𝑞
23. Factorise the following quadratic polynomial by splitting the middle term .
4𝑥 2 − 11𝑥 + 6
OR
2
6𝑥 + 7𝑥 − 5
38
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Page 40
m
m .co
m .co s e m
se 3 −1 3
g l a
24. Simplify : 54 × 25 2 ÷ 1254
a
25. Find the value of k , if 𝑥 + √2 is a factor of p(𝑥) = 3√2𝑥 2 +5𝑥+√2
D X E
4 5
26. Given : In ∆XYZ , a line DE is drawn through the point X 1
and parallel to side YZ to form the angles
m
.co
∠ 4 and ∠ 5 as shown in the figure.
Prove that :
m
∠ 1 + ∠ 2 + ∠3 = 180°
o
2 3
m
27. Expand using m . c Y Z
s e
a suitable identity : ( 5a − 7b + 3c )
a
2
s e l
g l a OR ag
a
27. Evaluate using a suitable identity : 103 × 105
C
28. Given : In the adjoining figure ,
X Y
X and Y are the midpoints of AC and BC respectively Type equation here.
and AX = CY.
Prove that : AC = BC A B
m
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29. Given : In the adjoining figure ,
s em S R
la
PR is a diagonal of parallelogram PQRS.
Prove that : ∆PQR ≅ ∆RSP
ag
P Q
30. Evaluate the following trigonometric expression using known numerical values
of trigonometric ratios :
7𝑠𝑖𝑛2 45° + 2𝑐𝑜𝑠 2 60°
m
m : In the adjoining figure ,
oGiven c. o 𝑡
31. c. Line e m
em t is a transversal of lines l and m.
l as 𝑙
las Find the value of y for which lines l and m
ag
ag will be parallel to each other.
𝑚
Section C ( 3 marks each)
32. Simplify :
4 + √13 4 − √13 39
+
m .
.co m
4 − √13 4 + √13
s e
s em l a
g la ag
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Page 41
33. Divide the polynomial p(𝑥) = 𝑥 3 + 7𝑥 − 12 by the polynomial g(𝑥) = 𝑥 − 1
and find the quotient and remainder.
34. Given : In the adjoining figure ,
A C E
AG ∥ CH ∥ EF, ∠ EAB = 90° and ∠ BEF = 65°.
Find : 65°
i) ∠ CED D
B
ii) ∠ EDC
iii) ∠ DBG G H F
OR
34. Given : In the adjoining figure , Y X
XY ∥ ZW , ∠ ZXY = 90°, ∠ YZW = 35° and ∠ WYZ = 50°
Find : 50°
i) ∠ XZY
ii) ∠ XYZ
iii) ∠ YWU 35°
W Z
U
35. Given : ∆ PQR is an isosceles triangle such that PQ = PR and ray PS is the
bisector of ∠ QPR. P
Prove that : ∠ Q = ∠ R
Q R
S
A
36. Given : In the adjoining figure , BA ⊥ AC and ED ⊥ DF
such that AB = DE and BF = EC
Prove that : DF = AC
E C
F B
D
OR
36. Given : In the adjoining figure ,
A B
∠ BCD = ∠ ADC and ∠ ACB = ∠ BDA
Prove that : AD = BC
C D
40
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37. Given : ABCD is a quadrilateral in which P , Q , R and S are the midpoints
of the sides AB , BC , CD and DA respectively.
D
AC is a diagonal. R
C
If SR =5.2cm and QR = 6.4 cm,
S
then find the lengths of AC , PQ and PS.
A Q
m
om
P
B . co
. c em
m
38. In ∆ LMN , ∠ M = 90° , LM = 8cm and MN =15cm. L
e l as
Find :
l as ag
i)
ii) ag
length of LN
value of sin N
iii) value of tan L M N
A
39. Given : In the adjoining figure ,
p the sides AB and AC of ∆ABC are produced
to points P and Q respectively.
If bisectors BO and CO 𝑥 y
of ∠CBP and ∠BCQ respectively, meet at O , then m
c. o
B C
1
Prove that : ∠BOC = (𝑥 + y)
2
e m
l as P Q
40. Given : In the adjoining figure ,
ag O
p ∠ 𝑥 = ∠ 𝑦 and AB = CB. D
Prove that : AE = CD 𝑥
B
𝑦
E
C
m
41.
m
In the figure given below,
.co
.co m
AD and BE are the medians of ∆ABC and DF ∥ BE.
m
1
s e
e la
Prove that : CF = AC.
las 4
ag
ag
m . c
c. o 41
s e m
s em
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Page 43
Section D (4 marks each)
42. Factorise the polynomial : 𝑎3 + 13𝑎2 + 32a + 20
43. Given : In the adjoining figure ,
In ∆ ABC , D is a point on side AC such
DE = DF , AD = CD ,
DE⊥AB at E and DF⊥CB at F.
Prove that : AB = BC
*********************************
42
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Page 44
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GOA BOARD OF SECONDARY AND HIGHER SECONDARY EDUCATION
ALTO-BETIM GOA 403521
DESIGN OF THE QUESTION PAPER (2026-2027)
SEMESTER II
Subject : MATHEMATICS (E)
m
om . co
c m
Time : 3 hrs Grade 9 Max. Marks :80
m . s e
ethe distribution of marks over different dimensions of the gl a
***********************************************************************************
s
The weightageaor a
g l shall be as follows:
a
question paper
1. Weightage to the Learning objectives :
Sr. No. Learning Objectives Marks Percentage of Marks
1. Remembering and 50 62.5%
Understanding
2. Applying 18
m 22.5%
3. Analysing , Evaluating c. o
12 15%
and Creating
s em
Total
l a 80 100%
ag
2. Weightage to the different areas of Content :
Chapter No. Topic Marks
PDF Logarithms 10
3 Coordinate Geometry 03
4 Linear Equations in Two Variables
o m08
m 10 .c 14
.co m
Circles
s e
em la
12 Heron’s Formula 14
las 13 Surface Areas and Volumes
ag 16
ag 14 Statistics 15
Total 80
m . c
c. o 43
s e m
s em
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Page 45
3. Weightage to different form/type of Questions :
Sr. No. Form of Questions Marks for Number of Total
each question questions Marks
1. Very Short Answer Type (VSA) 1 20 20
2. Short Answer Type I (SA-I) 2 11 22
3. Short Answer Type II (SA-II) 3 10 30
4. Long Answer Type (LA) 4 2 08
Total 43 80
4. The expected time for different type of questions would be as
follows:
Sr. No. Form of Questions Approx. time Number Approx. time
for each of for each form
question in questions of questions in
mins (t) (n) mins (t) x (n)
1. Very Short Answer Type (VSA) 2 20 40
2. Short Answer Type I (SA-I) 3 11 33
3. Short Answer Type II (SA-II) 8.5 10 85
4. Long Answer Type(LA) 11 02 22
Total 43 180
5. Weightage to difficulty level of questions:
Sr. No. Estimated difficulty level of questions Percentage
1. Easy 20%
2. Average 60%
3. Difficult 20%
Total 100%
6. Number of Questions:
There will be 43 questions
44
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Page 46
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BLUE PRINT OF SEMESTER II EXAM MATH QUESTION PAPER ; 2026-2027
GRADE 9
Objectives
Chp.
m
No. Topic Remembering & Understanding Applying Analysing , Evaluating & Total
o mSAII
Creating
. co
VSA SAI
c
. 3mk
LA VSA SAI SAII LA VSA SAI SAII LA
e m
1mk
e m
2mk 4mk 1mk 2mk 3mk 4m 1mk 2mk 3mk 4mk
l as
PDF Logarithms
l as
1(1) 25(2) 39(3)
k
ag 6(10)
ag 2(1)
3(1)
26(2)
3 Coordinate 4(1) 24(2) 2(3)
Geometry
4 Linear 5(1) 28(2) 14(1) 32(3) 5(8)
Equations 6(1)
in two
variables
10 Circles 7(1) 21(2) *33(3) 15(1) 40(3) 19(1) 8(14)
m
8(1) 27(2)
.co
12 Heron’s 9(1) 29(2) 34(3) 16(1) 43(4) 20(1) 7(14)
m
Formula *31(2)
13 Surface 10(1) 22 (2) *35(3)
s e
17(1) 41(3) 36(3) 8(16)
areas and *23(2)
l a 18(1)
14
Volumes
Statistics 11(1) 30(2) 37(3) ag 42(4) 7(15)
12(1) 38(3)
13(1)
Total 13(13) 11(22) 5(15) 0(0) 5(5) 0(0) 3(9) 1(4) 2(2) 0(0) 2(6) 1(4)
29(50) 9(18) 5(12) 43(80)
NOTE: Figures outside the bracket indicate the question number and figures within the bracket
indicate marks .
m
o m
*Indicates internal choice to be provided.
c m .co
. e
is a model Blueprint, paper setter may make changes insthe
s emobjectives chapter wise.
This
g l a
la a
ag
*********************************
m . c
c. o 45
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s em
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Page 47
GOA BOARD OF SECONDARY AND HIGHER SECONDARY EDUCATION
ALTO – BETIM GOA 403521
MODEL QUESTION PAPER ( 2026-2027 )
SEMESTER II
SUBJECT: MATHEMATICS (E)
TIME : 3 Hrs GRADE 9 MAX. MARKS : 80
INSTRUCTIONS:
i. This question paper consists of 43 questions. All questions are compulsory.
ii. This question paper is divided into four Sections.- A , B , C and D.
iii. In Section A , question numbers 1 to 20 are multiple choice questions (MCQs)
and question numbers 19 and 20 are Assertion – Reason based
questions of 1 mark each.
iv. In Section B , question numbers 21 to 31 are short answer type I (SA-I) questions
carrying 2 marks each.
v. In Section C , question numbers 32 to 41 are short answer type II
(SA-II) questions carrying 3 marks each.
vi. In Section D , question numbers 42 and 43 are long answer (LA) questions
carrying 4 marks each.
vii. There is no overall choice . However , an internal choice has been provided in two
questions of 2 marks each in Section B and two questions of 3 marks each in
Section C.
viii. Graph paper will be supplied on request.
ix. Logarithm and Antilogarithm tables are printed on the last pages of the question
paper.
x. Use of calculator is NOT permitted.
Section A (1 mark each)
Select and write the correct alternative from those given below each statement for question 1
to 20:
1. If 𝑎𝑥 = 𝑛, then :
• 𝑎 = 𝑙𝑜𝑔𝑥 𝑛 • n = 𝑙𝑜𝑔𝑎 𝑥
• 𝑥 = log𝑛 𝑎 • 𝑥 = 𝑙𝑜𝑔𝑎 n
2. The value of l𝑜𝑔3 81 𝑖𝑠 :
• 9 • 18
• 4 • 27
3. The value of log222 is :
• 1 • 4
• 2 • 8
46
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4. If y-coordinate of a point is zero, then this point always lies :
• in 1st quadrant • on the 𝑥 - axis
• at the origin • on the 𝑦 - axis
5. Which of the following equations represent a linear equation in two variables?
• 𝑥² + y = 5 • 𝑥 + 2y = 5
• 𝑥 + y² = 5 • 𝑥y = 5 m
om . co
. c e m
m
6. The value of k , if 𝑥 = 2 and y = −1 is a solution of the equation 2𝑥 – y = k is :
e l as
• 1
l as • –2
ag
• 3
ag • 5
7. If two chords AB and CD are equidistant from the centre then :
• AB < CD • AB = CD
• AB > CD • AB = ½ CD
8. In the figure , O is the centre of the circle. If ∠ ABC = 20° , then the measure of
∠ AOC is :
• 10° • 40°
m
• 20° • 60°
.co O
em
B
l as A
20°
ag C
9. The semi-perimeter of a triangle with sides of length 20 cm, 15cm, and 9 cm is :
• 88cm • 22cm
• 44 cm • 15 cm
10. In a right circular cylinder , if the radius is doubled and the height is halved , then
the curved surface area will be :
m
• halved
m • same
.co
m .co
• doubled • 4 times
s e m
s e
11. The mean of first five natural numbers is :
g la
g la • 1 • 5 a
a • 3 • 15
12. The class mark of the class 90 − 120 :
• 90 • 105
• 100 • 115
m . c
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13. The range of the data 18 , 17 , 20 , 29 , 6 , 12 , 35 is :
• 20 • 29 • 35 • 41
14. The entry fee to a historical monument is ₹30 for adults and children are
charged half the entry fee. If on a particular day 20 adults visited the
monument and the total revenue generated was ₹720, then the number of
children who visited the monument on that day is :
• 6 • 10
• 8 • 12
15. In ∆ABC , ∠B is a right angle , AC = 13cm and AB = 5cm . A circle is drawn with
A as centre and AC as radius. The length of the chord of this circle passing
through C and B is :
• 5cm • 13cm
• 12cm • 24cm
16. An isosceles right triangle has an area of 8 cm2. The length of its hypotenuse
is:
• 2√6 cm • 4√2 cm
• 4cm • 4√3cm
17. If the volume and the base area of a right circular cone are 48 cm3 and 12cm2
respectively , then the height of the cone is :
• 3cm • 12cm
• 6cm • 9cm
18. If radii of the two spheres are in the ratio 4:3 and the sum of their radii is 7 then
the difference of their surface areas is :
• 88cm2 • 22cm2
• 44cm2 • 28cm2
Directions :
In Q. No. 19 and 20, a statement of Assertion (As) is followed by a statement of
Reason (R). Select the correct option from the following :
• Both, Assertion (As) and Reason (R) are true. Reason (R) explains
Assertion (As) completely.
• Both , Assertion (As) and Reason (R) are true . Reason (R) does not
explain Assertion (As).
• Assertion (As) is true but Reason (R) is false.
• Assertion (As) is false but Reason (R) is true.
48
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19. Assertion (As) : Two diameters of a circle intersect each other at right angles . Then the
quadrilateral formed by joining their end-points is a square.
Reason (R) : Equal chords subtend equal angles at the centre.
20. Assertion (As): The side of an equilateral triangle is 6 cm , then the height of the
triangle is 9cm.
m
om
√3
. co
. c
Reason (R) : The height of an equilateral triangle is 2 × side.
e m
e m l as
as
l Section B ( 2 marks each ) Q a
g
ag
21. Given : PQ and RS are equal chords of a circle with centre O.
S
Prove that : ∠POQ = ∠ROS P O
R
22. A cylindrical tube, open at both ends is made of metal. The internal diameter of the tube is
m
10.4 cm and its length is 25 cm. The thickness of the tube is 8 mm. Find the volume of
.co
the metal used in making the tube.
e m
l as
23. Find the volume of a sphere whose surface area is 154cm2.
ag OR
2
The total surface area of a solid hemisphere is 5940 cm . Find the diameter of the
hemisphere .
24. In the adjoining figure , ∆ABC is an isosceles triangle. Find the
coordinates of its vertices and the distance between points B
and C.
m
o m .co
25. If log. 49.83 = 1.6975 and antilog 2.6528 = 449.5, then find the value of: em
c
m
i)seantilog 3. 6975 l as
l a
ii) log 0.4495
ag
g
a26. Using the logarithmic table find the value of :
i) log 3.258 ii) antilog 2.2792
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Page 51
27. In the adjoining figure , points E , F , G and H lie on the circle with centre O.
If EH is a diameter and ∆ OEF is an equilateral triangle then find the values of 𝑥 and y
. H
O 𝑥
𝑦
E
F
28. The cost of 3 pens and 2 pencils together is ₹76.
Answer the following questions based on the above situation.
i. Represent this situation as a linear equation in two variables, where 𝑥 is the cost of
a pen and y is the cost of a pencil.
ii. If the cost of a pen is ₹20, find the cost of a pencil.
29. A table runner is made by stitching 18 congruent triangular pieces of cloth of two
different colours, each piece measuring 10cm , 25cm and 25cm. How much cloth of each
colour is required for the table runner?
30. The following observations are arranged in ascending order :
6 , 8 ,9 , 15 , 𝑥 , 𝑥+2 , 𝑥+6, 22 , 25 , 29 .
If the median is 17 , find the value of 𝑥.
31. Find the cost of levelling the ground which is in the form of a triangle having sides 51m ,
37m and 20m at the rate of ₹10 per m2 .
OR
Find the cost of painting a triangular sheet having sides 12cm ,16cm and 20cm at the
rate of ` ₹1.5 per cm2 .
Section C ( 3 marks each )
32. Draw the graph of the linear equation 3𝑥 – y = 5
Rewrite and complete the following table.
( Plot at least 3 points for this line on a graph paper )
3𝑥 – y = 5
𝑥
y
33. In the adjoining figure , points X , Y , Z and W lie on the circle with centre O.
If XZ is a diameter and ∠ ZYW = 50° then , Y
Find : i) ∠WXZ
i) ∠XWZ 50°
ii) ∠XZW O
X
50
W
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Page 52
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OR
R
In the adjoining figure , points P , R , Q and T lie on the circle.
O is the centre of the circle and PQ is a diameter. O 60°
P T
If ∠PQR = 60° and ∠ PQT = 40° then , 40°
Find : i) ∠ PRQ
ii) ∠ QPR
m
co
iii) ∠ 𝑃𝑅𝑇 Q
. c om e
34.The perimeter of an isosceles triangle is 32 cm. The ratio of equal side to the base is 3: 2 .
m .
m
Using Heron’s formula, find the area of the triangle.
eis 16cm and its base radius is 12cm . Find the curved surface area
l as
as
l area of the cone (take 𝜋 = 3.14)
35.The height of a cone a g
a g
and the total surface
OR
How many litres of milk can a hemispherical bowl of diameter 10.5cm hold ?
36. A corn cob shaped some what like a cone , has the radius of its broadest end as 3.5 cm
and length ( height ) as 24cm . If each 1cm2 of the surface of the cob carries an average of
3 grains, find the number of grains you would find on the entire cob.
m
.co
37.The weekly savings (in rupees) of 30 students of class IX are as follows:
38 , 42 , 40 , 35 , 72 ,32 , 57 , 62 ,59 , 80 , 84 , 73 , 65 , 40 , 76 ,
e m
s
40 , 38 , 60 , 58 , 38 , 54 ,39 ,50 , 44 , 71 , 83 , 45 , 38 , 80 , 77.
l a
Represent the data given above using tally marks in a grouped frequency distribution table
taking class intervals as 30-40 , 40-50 …
ag
38. The following table shows the ages of the patients admitted in a hospital
during the year 2024.
Rewrite and complete the table given below and find the mean age of the patients.
Age in years Number of patients 𝑓𝑖𝑥𝑖
𝑥𝑖 𝑓𝑖
10 06
m
.co
20 11
m
.co
30 21
m
40 23
s em
e la
50 14
las 60 05
g
a ∑𝑓 𝑥 =
ag ∑𝑓𝑖 = 𝑖 𝑖
39. Evaluate the following expression by using the logarithm method.
256.7 × 0.5091
40. Two chords of lengths 6cm and 8cm of a circle are parallel to each other and are on the
same side of its centre . If the distance between the chords is 1cm , find the radius of
the circle.
m . c
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41. A cone with a radius of 5cm is completely filled with water. If this water is poured into a
cylindrical container of radius 10cm , the water level in the cylinder rises by 2cm. Find
the height of the cone.
Section D ( 4 marks each )
42. The following table gives the monthly consumption of electricity of 50 consumers
of a locality.
Draw a histogram and a frequency polygon to represent the given data.
Monthly consumption No of consumers
(in units) fi
150- 160 10
160-170 16
170-180 12
180-190 8
190-200 4
43. The sides of a triangular park are 18 m, 24 m, and 30 m. Inside the park, a triangular
flower bed is constructed such that its sides are half the length of the park’s
sides.
Calculate:
(i) The area of the park using Heron’s formula.
(ii) The area of the flower bed.
(iii) Find the ratio between the two areas.
*********************************************************************
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m
om . co
. c e m
em l as
l as ag
ag
m
m .co
s e
l a
ag
m
m .co
m .co s e m
s e g la
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a
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