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STSE 2015 Question Paper Class 10 SAT

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Page 1

SAT-3 Code : S STSE/15
Booklet Number {…÷Œ∫i…EÚ… ∫…ΔJ™……

Æ˙…V™… |… i…¶…… J……‰V… {…Æ˙“I…… 2015
STATE TALENT SEARCH EXAMINATION 2015
Roll No. Æ˙…‰±… x…®§…Æ˙
EÚI……-X E‰Ú ¥…t…Ãl…™……Â E‰Ú ±…B
FOR STUDENTS OF CLASS X

SCHOLASTIC APTITUDE TEST ∂…Ë I…EÚ ™……‰M™…i…… {…Æ˙“I……
( For Students of Class X ) ( EÚI…… X E‰Ú ¥…t…Ãl…™……Â E‰Ú ±…B )
Time : 90 Minutes Max. Marks : 90 ∫…®…™… : 90 ®…x…]ı {…⁄h……»EÚ : 90
( For Blind Candidates Time : 2 Hours ) ( o˘Œπ]ıΩ˛“x… +¶™…Ãl…™…… E‰Ú ±…B ∫…®…™… : 2 P…Δ]‰ı )
INSTRUCTIONS TO CANDIDATES {…Æ˙“I……Ãl…™…… E‰Ú ±…B x…nÊ˘∂…
Read the following instructions carefully |…∂x… {…÷Œ∫i…EÚ… J……‰±…x…‰ ∫…‰ {…Ω˛±…‰ x…®x… x…nÊ˘∂…… EÚ…‰ v™……x… ∫…‰
before you open the question booklet.
1. Answers are to be given on a separate
{… g¯B*
answer sheet (OMR sheet). 1. =k…Æ˙ BEÚ +±…M… =k…Æ˙-{…j…EÚ (+…‰0 B®…0 +…Æ˙0 ∂…“]ı)
2. Please write your Roll Number as allotted to ®… n‰˘x…‰ ΩÈ˛*
you in the admission card very clearly on 2. EfiÚ{…™…… +{…x…… Æ˙…‰±… x…®§…Æ˙ V…Ë∫…… EÚ +…{…E‰Ú |…¥…‰∂… {…j… {…Æ˙
the test-booklet and darken the n˘™…… M…™…… Ω˲, x…nÊ˘∂……x…÷∫……Æ˙ ]‰ı∫]ı {…÷Œ∫i…EÚ… {…Æ˙ §…Ω÷˛i… ∫{…π]ı
appropriate circles on the answer sheet as
per instructions given.
±… J…™…‰ +…ËÆ˙ =k…Æ˙-{…j…EÚ {…Æ˙˙ n˘™…‰ M…™…‰ M……‰±…… EÚ…‰ EÚ…±……
3. There are 90 questions in this test. All are EÚÆÂ˙*
compulsory. The question numbers 1 to 3. <∫… {…Æ˙“I…… ®… 90 |…∂x… ΩÈ˛* ∫…¶…“ |…∂x… + x…¥……™…« ΩÈ˛* |…∂x…
25 belong to Physics. 26 to 50 to Chemistry, ∫…ΔJ™…… 1 ∫…‰ 25 ¶……Ë i…EÚ ¥…Y……x…, 26 ∫…‰ 50 Æ˙∫……™…x… ¥…Y……x…,
51 to 70 to Biology and 71 to 90 are on 51 ∫…‰ 70 V…“¥… ¥…Y……x… +…ËÆ˙ 71 ∫…‰ 90 M… h…i… ¥…π…™……Â {…Æ˙
Math subjects. +…v…… Æ˙i… ΩÈ˛*
4. Please follow the instructions given on the
answer sheet for marking the answers. 4. EfiÚ{…™…… =k…Æ˙ S…Ì»i… EÚÆ˙x…‰ E‰Ú ±…B =k…Æ˙-{…j…EÚ {…Æ˙ n˘™…‰ M…™…‰
5. If you do not know the answer to any x…nÊ˘∂…… EÚ…‰ v™……x… ∫…‰ ∫…®…Z… EÚÆ˙ =x…EÚ“ +x…÷{……±…x…… EÚ“ V…B*
question, do not waste time on it and pass 5. ™… n˘ +…{… EÚ∫…“ |…∂x… EÚ… =k…Æ˙ x…Ω˛” V……x…i…‰ ΩÈ˛ i……‰ =∫… {…Æ˙
on to the next one. Time permitting, you can §…Ω÷˛i… ∫…®…™… x… M…Δ¥……<™…‰ +…ËÆ˙ +M…±…‰ |…∂x… {…Æ˙ §…g¯ V……<™…‰*
come back to the questions, which you have ™… n˘ §……n˘ ®… ∫…®…™… ®…±…‰ i……‰ V…x… |…∂x…… EÚ…‰ +…{…x…‰ {…Ω˛±…‰
left in the first instance and attempt them.
6. Since the time allotted for this question UÙ…‰c˜ n˘™…… l……, =x… {…Æ˙ ¥……{…∫… +…EÚÆ˙ =x…E‰Ú =k…Æ˙ n˘“ V…B*
paper is very limited, you should make the 6. C™…… EÚ <∫… |…∂x… {…j… E‰Ú ±…B x…v……« Æ˙i… ∫…®…™… §…Ω÷˛i… ∫…“ ®…i…
best use of it by not spending too much time Ω˲, <∫… ±…B <∫…EÚ… + v…EÚi…®… ={…™……‰M… EÚ“ V…™…‰ +…ËÆ˙ EÚ∫…“
on any one question. |…∂x… {…Æ˙ §…Ω÷˛i… ∫…®…™… x… ±…M……<™…‰*
7. Rough work can be done on the given 7. Æ˙°Ú EÚ…™…« {…÷Œ∫i…EÚ… E‰Ú +Δi… ®… n˘B M…B Æ˙HÚ {…fiπ`ˆ… {…Æ˙
Blank Pages at the end of the booklet but
not on the answer sheet/loose paper. EÚ™…… V…… ∫…EÚi…… Ω˲ EÚxi…÷ =k…Æ˙-{…j…EÚ/+±…M… EÚ…M…V…
8. Every correct answer will be awarded one {…Æ˙ x…Ω˛”*
mark. There will be no negative marking. 8. |…i™…‰EÚ ∫…Ω˛“ =k…Æ˙ EÚ… BEÚ +ΔEÚ |…n˘…x… EÚ™…… V……BM……* <∫…®…Â
9. Please return the Answer sheet (OMR @Òh……i®…EÚ +ΔEÚx… x…Ω˛” Ω˛…‰M……*
Sheet) only to the invigilator after the 9. EfiÚ{…™…… {…Æ˙“I…… E‰Ú §……n˘ E‰Ú¥…±… =k…Æ˙-{…j…EÚ (+…‰0 B®…0
test.
10. Hindi version of the question paper will be +…Æ˙0 ∂…“]ı) Ω˛“ x…Æ˙“I…EÚ EÚ…‰ ±……Ë]ı…<B*
considered as final in case of any dispute 10. +x…÷¥…… n˘i… ¥…¥…Æ˙h… ®… +xi…Æ˙ ∫…‰ =`‰ˆ EÚ∫…“ ¶…“ ¥…¥……n˘ EÚ“
arising out of variation in translated version. Œ∫l… i… ®… |…∂x…-{…j… E‰Ú Ω˛xn˘“ ¥…¥…Æ˙h… EÚ…‰ x…h……«™…EÚ ®……x……
PLEASE TURN OVER THE PAGE AND START V……BM……*
YOUR WORK. EfiÚ{…™…… {…fiπ`ˆ {…±… ]ı™…‰ +…ËÆ˙ +{…x…… EÚ…™…« +…Æ˙®¶… EÚ“ V…B*
BSER 2015
The copyright of the contents of this booklet rests with the BSER and no part of it should be used by
anybody in any manner whatsoever without the prior permission of the BSER. The items are prepared
on best effort basis. In case of any dispute the opinion of the experts appointed by BSER will be final.

STSE/15 – SAT–1007 1007

Page 2

SAT-3 (2)

STSE/15 – SAT–1007 1007

Page 3

(3) SAT-3

∂…Ë I…EÚ ™……‰M™…i…… {…Æ˙“I……
SCHOLASTIC APTITUDE TEST
<∫… |…∂x…-{…j… ®… E÷Ú±… 90 |…∂x… ΩÈ˛* |…i™…‰EÚ |…∂x… BEÚ +ΔEÚ EÚ… Ω˲*
THERE ARE 90 QUESTIONS IN THIS PAPER.
EACH QUESTION CARRIES ONE MARK.

1. BEÚ ¥…∫i…÷ u˘…Æ˙… i…™… EÚ“ M…<« n⁄˘Æ˙“, ∫…®…™… E‰Ú ∫…®……x…÷{……i…“ Ω˲ * =∫…EÚ“ S……±…
(1) §…g‰¯M…“ (2) P…]‰ıM…“
(3) ∂…⁄x™… Ω˛…‰M…“ (4) ∫l…Æ˙ Æ˙Ω‰˛M…“ *
The distance travelled by a body is proportional to time. Its speed
(1) increases (2) decreases
(3) becomes zero (4) remains constant.
2. EÚ∫…“ EÚ…Æ˙ EÚ… S……±…-∫…®…™… O……°Ú S…j… ®… |…n˘ ∂…«i… ΩÈ˛ * {…Ω˛±…‰ 6 ∫…‰EÚhb˜ ®… EÚ…Æ˙ EÚi…x…“ n⁄˘Æ˙“ i…™…
EÚÆ˙i…“ ΩË ?

(1) 27 m (2) 54 m
(3) 6m (4) 9 m.
The speed-time graph for a car is shown in figure. How far does the car travel in
the first 6 seconds ?

(1) 27 m (2) 54 m
(3) 6m (4) 9 m.

STSE/15 – SAT-1007 1007 [ P.T.O.

Page 4

SAT-3 (4)

3. ¶……Ë i…EÚ Æ˙… ∂… V…∫…EÚ… ®……j…EÚ x™…⁄]ıx… / EÚO…… ΩË, Ω˲
(1) §…±… (2) ∫…Δ¥…‰M…
(3) i¥…Æ˙h… (4) >V……« *
The physical quantity which has unit newton/kg is

(1) force (2) momentum
(3) acceleration (4) energy.
4. 100 g +…ËÆ˙ 200 g p˘¥™…®……x… EÚ“ n˘…‰ ¥…∫i…÷Bƒ BEÚ Ω˛“ Ɖ˙J…… E‰Ú +x…÷ n˘∂… BEÚ Ω˛“ n˘∂…… ®… GÚ®…∂…:
2 ms – 1 +…ËÆ˙ 1 ms – 1 E‰Ú ¥…‰M… ∫…‰ M… i… EÚÆ˙ Æ˙Ω˛“ ΩÈ˛ * =x…E‰Ú ∫…Δ¥…‰M…… EÚ… +x…÷{……i… Ω˛…‰M……

(1) 4:1 (2) 1:1

(3) 2:1 (4) 1 : 2.

Two objects of masses 100 g and 200 g are moving along the same line and

direction with velocities of 2 ms – 1 and 1 ms – 1 respectively. Ratio of their

momenta is

(1) 4:1 (2) 1:1

(3) 2:1 (4) 1 : 2.
5. ®…÷HÚ {…i…x… ¥……±…“ ∫…¶…“ ¥…∫i…÷+…Â EÚ… i¥…Æ˙h…
(1) ∫…®…™… E‰Ú ∫……l… §…g¯i…… ΩË (2) ∫…®…™… E‰Ú ∫……l… P…]ıi…… ΩË
(3) x…™…i… Ω˛…‰i…… Ω˲ (4) ∂…⁄x™… Æ˙Ω˛i…… ΩÈ˛ *
Acceleration of all freely falling bodies

(1) increases with time (2) decreases with time

(3) remains constant (4) remains zero.
6. BEÚ {…il…Æ˙ EÚ…‰ >v¥……«v…Æ˙ >{…Æ˙ EÚ“ +…‰Æ˙ 9·8 ms – 1 E‰Ú ¥…‰M… ∫…‰ °ÂÚEÚ… V……i…… Ω˲ * {…il…Æ˙ u˘…Æ˙… |……{i… EÚ“
M…™…“ + v…EÚi…®… >ƒS……<« Ω˛…‰M…“
(1) 19·6 m (2) 9·8 m

(3) 49 m (4) 4·9 m.
A stone is thrown vertically upward with a velocity of 9·8 ms – 1 . The maximum

height attained by the stone is

(1) 19·6 m (2) 9·8 m

(3) 49 m (4) 4·9 m.

STSE/15 – SAT-1007 1007

Page 5

(5) SAT-3

7. V…§… Ω˛®… ±……‰Ω‰˛ EÚ“ EÚ“±… EÚ…‰ {……x…“ EÚ“ ∫…i…Ω˛ {…Æ˙ Æ˙J…i…‰ ΩÈ˛ i……‰ ¥…Ω˛ b⁄˜§… V……i…“ Ω˲, <∫…EÚ… +…∂…™… Ω˲ EÚ
(1) ±……‰Ω‰˛ EÚ“ EÚ“±… {…Æ˙ =i{±……¥…x… §…±… =∫…E‰Ú ¶……Æ˙ ∫…‰ V™……n˘… Ω˲ *
(2) ±……‰Ω‰˛ EÚ“ EÚ“±… {…Æ˙ =i{±……¥…x… §…±… =∫…E‰Ú ¶……Æ˙ ∫…‰ EÚ®… Ω˲ *
(3) ±……‰Ω‰˛ EÚ“ EÚ“±… {…Æ˙ =i{±……¥…x… §…±… =∫…E‰Ú ¶……Æ˙ E‰Ú §…Æ˙…§…Æ˙ Ω˲ *
(4) ±……‰Ω‰˛ EÚ“ EÚ“±… EÚ… tx…i¥… {……x…“ E‰Ú tx…i¥… ∫…‰ EÚ®… ΩÈ˛ *
When we place an iron nail on the surface of water the nail sinks. This means
that
(1) upthrust on iron nail is more than its weight
(2) upthrust on iron nail is less than its weight
(3) upthrust on iron nail is same as its weight
(4) density of iron nail is less than that of water.
8. +…{…‰ I…EÚ P…x…i¥… EÚ… S.I. ®……j…EÚ Ω˲
(1) kg m – 3 (2) gm cm – 3

(3) kg m – 2 (4) no unit.

The S.I. unit of relative density is

(1) kg m – 3 (2) gm cm – 3

(3) kg m – 2 (4) no unit.
9. x…M…h™… ¥……™…÷ |… i…Æ˙…‰v… EÚ“ ∫l… i… ®… V…§… BEÚ M…Ân˘ EÚ…‰ >{…Æ˙ EÚ“ +…‰Æ˙ °ÂÚEÚ… V……i…… Ω˲, i……‰ =∫…EÚ“ E÷Ú±…
>V……«
(1) §…g¯i…“ Ω˲
(2) P…]ıi…“ Ω˲
(3) x…™…i… Æ˙Ω˛i…“ Ω˲
(4) <∫…EÚ“ ™……j…… E‰Ú =SS…i…®… §…xn÷˘ {…Æ˙ ∂…⁄x™… Ω˛…‰ V……i…“ Ω˲ *
When a ball is thrown upward in the condition of negligible air resistance then
its total energy
(1) increases

(2) decreases

(3) remains constant

(4) becomes zero at the highest point of its journey.

STSE/15 – SAT-1007 1007 [ P.T.O.

Page 6

SAT-3 (6)

10. 0·5 EÚO…… p˘¥™…®……x… EÚ… ¥…‰M… 20 ms – 1 ∫…‰ 10 ms – 1 i…EÚ EÚ®… EÚÆ˙x…‰ E‰Ú ±…™…‰ EÚ™…… M…™…… EÚ…™…« Ω˛…‰M……
(1) 75 J (2) 7·5 J

(3) 50 J (4) 25 J.

Work done is reducing the velocity from 20 ms – 1 to 10 ms – 1 of a mass of 0·5 kg

is

(1) 75 J (2) 7·5 J

(3) 50 J (4) 25 J.

11. EÚ±……‰¥……]ı-P…Δ]ı… ®……j…EÚ Ω˲
(1) >V……« × ∫…®…™… EÚ… (2) ∂… HÚ / ∫…®…™… EÚ…
(3) >V……« / ∫…®…™… EÚ… (4) EÚ…™…« EÚ… *
kWh is a unit of

(1) energy × time (2) power / time

(3) energy / time (4) work.

12. x…®x… ®…Â ∫…‰ EÚ∫… {…n˘…l…« ®…Â v¥… x… EÚ“ S……±… + v…EÚi…®… Ω˛…‰M…“ ?
(1) B‰±…÷ ®… x…™…®… ®… (2) EÚ…ƒS… ®…Â
(3) {……x…“ ®…Â (4) ¥……™…÷ ®…Â *
In which of the following materials speed of sound is maximum ?

(1) Aluminium (2) Glass

(3) Water (4) Air.
13. ∫{…π]ı |… i…v¥… x… ∫…÷x…x…‰ E‰Ú ±…B +¥…Æ˙…‰v…EÚ EÚ“ v¥… x… ª……‰i… ∫…‰ x™…⁄x…i…®… n⁄˘Æ˙“ Ω˛…‰x…“ S…… Ω˛™…‰
(1) 34·4 m (2) 17·2 m

(3) 3·44 m (4) 1·72 m.

For hearing distinct echoes the minimum distance of the obstacle from the
source of sound must be

(1) 34·4 m (2) 17·2 m

(3) 3·44 m (4) 1·72 m.

STSE/15 – SAT-1007 1007

Page 7

(7) SAT-3

14. EÚ∫…“ ™…÷¥…… ¥™… HÚ EÚ… æ˛n˘™… 1 ®…x…]ı ®… 80 §……Æ˙ v…c˜EÚi…… Ω˲ * =∫…E‰Ú æ˛n˘™… E‰Ú v…c˜EÚx…‰ EÚ“ +…¥…fi k…
C™…… Ω˛…‰M…“ ?
(1) 13·3 Hz (2) 80 Hz

(3) 1·33 Hz (4) 60 Hz.

Heart of a young man beats 80 times in 1 minute. What will be the frequency of
his heartbeat ?

(1) 13·3 Hz (2) 80 Hz

(3) 1·33 Hz (4) 60 Hz.

15. ™… n˘ EÚ…‰<« =k…±… ±…Â∫… §…®§… E‰Ú ∫…®……x… +…EÚ…Æ˙ EÚ… |… i… §…®§… §…x……i…… Ω˲, i……‰ §…®§… EÚ“ ±…Â∫… ∫…‰ n⁄˘Æ˙“ ΩÈ˛
(1) F ¥… 2 F E‰Ú ®…v™… (2) 2 F ∫…‰ V™……n˘…

(3) F ∫…‰ EÚ®… (4) 2 F.

If convex lens forms an image equal in size to that of the object the object is

placed at a distance

(1) between F and 2 F (2) greater than 2 F

(3) less than F (4) 2 F.
16. =k…±… ±…Â∫… EÚ“ °Ú…‰EÚ∫… n⁄˘Æ˙“ C™…… Ω˛…‰M…“ V…∫…EÚ“ ∂… HÚ 1·5 D ΩË ?
(1) + 1·5 m (2) + 66·6 cm

(3) – 66·6 cm (4) – 1·5 m.

What will be the focal length of a convex lens whose power is 1·5 D ?

(1) + 1·5 m (2) + 66·6 cm

(3) – 66·6 cm (4) – 1·5 m.

17. x…‰j… ®… |…¥…‰∂… EÚÆ˙x…‰ ¥……±…‰ |…EÚ…∂… EÚ“ ®……j…… EÚ…‰ x…™…Δ j…i… EÚÆ˙i…… Ω˲
(1) x…‰j… ±…Â∫… (2) {…÷i…±…“
(3) EÚ…ÏÃx…™…… (4) o˘Œπ]ı {…]ı±… *
The amount of light entering the eye is controlled by

(1) eye lens (2) pupil

(3) cornea (4) retina.

STSE/15 – SAT-1007 1007 [ P.T.O.

Page 8

SAT-3 (8)

18. EÚ∫…“ S……±…EÚ ®… S…Æ˙ ∫…®®…i… v……Æ˙… EÚ“ n˘∂…… EÚ∫…E‰Ú |…¥……Ω˛ EÚ“ n˘∂…… ®… ®……x…“ V……i…“ Ω˲ ?
(1) <±…‰C]≈ı…Ïx……Â E‰Ú (2) {…Æ˙®……h…÷+…Â E‰Ú
(3) v…x……¥…‰∂…… E‰Ú (4) @Òh……™…x…… E‰Ú *
The direction of conventional current in a conductor is assumed in the direction

of flow of

(1) electrons (2) atoms

(3) positive charges (4) negative ions.
19. x…®x… ¥…t÷i… {… Æ˙{…l… ®…Â R EÚ… ®……x… C™…… Ω˛…‰M…… ?

(1) 6Ω (2) 4Ω
(3) 8Ω (4) 2 Ω.

What will be the value of R in the following electric circuit ?

(1) 6Ω (2) 4Ω

(3) 8Ω (4) 2 Ω.
20. EÚ∫…“ ¥…Ët÷i… ™…÷ HÚ EÚ“ ¥…Ët÷i… ∂… HÚ n˘“ V……i…“ Ω˲
(1) I 2V (2) IV

(3) IR 2 (4) V 2R .

The electric power of an electric appliance is given by

(1) I 2V (2) IV

(3) IR 2 (4) V 2R .

STSE/15 – SAT-1007 1007

Page 9

(9) SAT-3

21. EÚ∫…“ v……Æ˙…¥……Ω˛“ E÷Úhb˜±…“ ®… °‰ÚÆ˙… EÚ“ ∫…ΔJ™…… §…g¯…x…‰ {…Æ˙ <∫…E‰Ú u˘…Æ˙… =i{…z… S…÷®§…EÚ“™… I…‰j… EÚ“ i…“μ…i……
(1) P…]ıi…“ Ω˲ (2) §…g¯i…“ Ω˲
(3) {…Ω˛±…‰ P…]ıi…“ Ω˲ °ÚÆ˙ §…g¯i…“ Ω˲ (4) +|…¶…… ¥…i… Æ˙Ω˛i…“ ΩË *
By increasing the number of turns in a current carrying coil the intensity of the

magnetic field produced by it
(1) decreases (2) increases

(3) first decreases then increases (4) remains unchanged.
22. BEÚ i……Æ˙ V…∫…®… <±…‰C]≈ı…Ïx… {…⁄¥…« n˘∂…… EÚ“ +…‰Æ˙ M… i… EÚÆ˙ Æ˙Ω‰˛ ΩÈ˛ =∫…E‰Ú `ˆ“EÚ ={…Æ˙ Æ˙J…“ n˘EÚ¬ ∫…⁄S…“ <Δ M…i…
EÚÆ‰˙M…“
(1) n˘ I…h… ®…Â (2) {…⁄¥…« ®…Â
(3) =k…Æ˙ ®… (4) {…Œ∂S…®… ®… *
A compass needle just above a wire in which electrons are moving towards east

will point

(1) South (2) East

(3) North (4) West.
23. i……Δ§…‰ E‰Ú i……Æ˙ EÚ“ BEÚ +…™…i……EÚ…Æ˙ E÷Úhb˜±…“ S…÷®§…EÚ“™… I…‰j… E‰Ú ±…®§…¥…i… i…±… ®… P…⁄h…«x… EÚÆ˙i…“ ΩË * i…§…
=∫…®… |…‰ Æ˙i… v……Æ˙… EÚ“ n˘∂…… =iGÚ ®…i… Ω˛…‰i…“ Ω˲ |…i™…‰EÚ
(1) n˘…‰ P…⁄h…«x… {…Æ˙ (2) BEÚ P…⁄h…«x… {…Æ˙
(3) BEÚ S……Ël……<« P…⁄h…«x… {…Æ˙ (4) +v…« P…⁄h…«x… {…Æ˙ *
A rectangular coil of copper wire is rotated in a plane perpendicular to the

magnetic field. The direction of induced current reverses once in each

(1) two rotations (2) one rotation

(3) one fourth rotations (4) half rotation.
24. {…¥…x… >V……« E‰Ú ¥™……¥…Ω˛… Æ˙EÚ ={…™……‰M… Ω‰˛i…÷ {…¥…x… EÚ“ x™…⁄x…i…®… S……±… Ω˛…‰x…“ S…… Ω˛™…‰
(1) 2 kmh – 1 (2) 5 kmh – 1

(3) 10 kmh – 1 (4) 15 kmh – 1 .
To make practical use of wind energy the minimum wind speed should be

(1) 2 kmh – 1 (2) 5 kmh – 1

(3) 10 kmh – 1 (4) 15 kmh – 1 .

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25. ∫……M…Æ˙“™… i……{…“™… >V……« ∞¸{……xi…Æ˙h… ∫…Δ™…Δj… E‰Ú |…S……±…x… E‰Ú ±…™…‰ ®…Ω˛…∫……M…Æ˙ E‰Ú {…fiπ`ˆ {…Æ˙ V…±… E‰Ú i……{… i…l……
2 km i…EÚ EÚ“ M…Ω˛Æ˙…<« E‰Ú V…±… E‰Ú i……{… ®… x™…⁄x…i…®… +xi…Æ˙ Ω˛…‰x…… S…… Ω˛B

(1) 20°C (2) 15°C

(3) 10°C (4) 5°C.

For operation of ocean thermal energy conversion plants the minimum
temperature difference between the water at the surface and water at the depths

up to 2 km should be

(1) 20°C (2) 15°C

(3) 10°C (4) 5°C.

26. {…Æ˙®……h…÷ EÚ… p˘¥™…®……x… C™…… Ω˛…‰i…… Ω˲ ?
(1) <±…‰C]≈ı…Ïx… ¥… x™…⁄]≈ı…Ïx… E‰Ú p˘¥™…®……x… EÚ… ™……‰M…
(2) <±…‰C]≈ı…Ïx… ¥… |……‰]ı…Ïx… E‰Ú p˘¥™…®……x… EÚ… ™……‰M…
(3) |……‰]ı…Ïx… ¥… x™…⁄]≈ı…Ïx… E‰Ú p˘¥™…®……x… EÚ… ™……‰M…
(4) <±…‰C]≈ı…Ïx…, |……‰]ı…Ïx… ¥… x™…⁄]≈ı…Ïx… E‰Ú p˘¥™…®……x… EÚ… ™……‰M… *
What is the mass of an atom ?

(1) Sum of the masses of electron and neutron

(2) Sum of the masses of electron and proton

(3) Sum of the masses of proton and neutron

(4) Sum of the masses of electron, proton and neutron.

27. ∫…ΔI……Æ˙h… EÚ∫… |…EÚ…Æ˙ EÚ“ + ¶… GÚ™…… Ω˲ ?
(1) +{…S…™…x… (2) +…C∫…“EÚÆ˙h…
(3) u˘ ¥…∫l……{…x… (4) ¥…™……‰V…x… *
Corrosion is which type of reaction ?

(1) Reduction (2) Oxidation

(3) Double Displacement (4) Decomposition.

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28. ®……x…¥… ∂…Æ˙“Æ˙ EÚ∫… pH {…Æ˙…∫… E‰Ú ®…v™… EÚ…™…« EÚÆ˙i…… Ω˲ ?
(1) 4·8 — 5·6 (2) 8·1 — 9·2
(3) 5·9 — 7·0 (4) 7·0 — 7·8.

Human body works within which pH range ?

(1) 4·8 — 5·6 (2) 8·1 — 9·2
(3) 5·9 — 7·0 (4) 7·0 — 7·8.
29. ¥…ÆΔ˙V…EÚ S…⁄h…« §…x……x…‰ ¥……±…“ + ¶… GÚ™…… Ω˲
(1) Na 2 CO 3 + 10 H 2 O → (2) CaCO 3 + 3 H 2 O →

(3) NaOH + Cl 2 → (4) Ca (OH) 2 + Cl 2 →

Which reaction produces bleaching power ?
(1) Na 2 CO 3 + 10 H 2 O → (2) CaCO 3 + 3 H 2 O →

(3) NaOH + Cl 2 → (4) Ca (OH) 2 + Cl 2 →

30. +…ÏC∫…‰ ±…EÚ +®±… EÚ… |……EfiÚ i…EÚ ª……‰i… EÚ…Ëx…-∫…… Ω˲ ?
(1) x…”§…⁄ (2) ∫…Δi…Æ˙…
(3) <®…±…“ (4) ]ı®……]ıÆ˙ *
Which one is natural source of oxalic acid ?

(1) Lemon (2) Orange

(3) Tamarind (4) Tomato.
31. B‰C¥…… Ɖ˙ V…™…… Ω˲
(1) ∫……xp˘ ∫…±}™…⁄ Æ˙EÚ +®±… ¥… x……< ]≈ıEÚ +®±… EÚ… ®…∏…h…
(2) 2 : 1 ®… x……< ]≈ıEÚ +®±… ¥… Ω˛…<b≈˜…‰C±……‰ Æ˙EÚ +®±… EÚ… ®…∏…h…

(3) 3 : 1 ®… ∫……xp˘ Ω˛…<b≈˜…‰C±……‰ Æ˙EÚ +®±… ¥… ∫……xp˘ x……< ]≈ıEÚ +®±… EÚ… i……V…… ®…∏…h…

(4) Ɖ˙ V…™…… x……®…EÚ {……Ëv…‰ EÚ… V…±…“™… ∫…i… *
What is Aqua regia ?
(1) Mixture of concentrated sulphuric acid and nitric acid
(2) 2 : 1 mixture of nitric acid and hydrochloric acid
(3) Fresh mixture of concentrated hydrochloric acid and concentrated nitric
acid in 3 : 1 ratio
(4) Water extract of a plant namely Regia.

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32. EÚ∫… |…EÚ…Æ˙ EÚ“ +…Ëπ… v… +{…S… E‰Ú ={…S……Æ˙ ®… |…™…÷HÚ Ω˛…‰i…“ Ω˲ ?
(1) Bx]ı“∫…‰ {]ıEÚ (2) B‰x]Ëı ∫…b˜
(3) B‰x]ı“ Ω˛∫]ı… ®… x…EÚ (4) Bx]ı“∫……<EÚ…‰ ]ıEÚ *
Which type of medicine is used for the treatment of indigestion ?

(1) Antiseptic (2) Antacid

(3) Anti-histaminic (4) Anti-psychotic.

33. EÚ…§…«x… E‰Ú +{…Æ˙∞¸{… EÚ…Ëx…-∫…‰ ΩÈ˛ ?
(1) Ω˛“Æ˙… (2) °÷Ú±…Æ˙“x…
(3) n˘…‰x……Â Ω˛“ (4) n˘…‰x…… ®… ∫…‰ EÚ…‰<« x…Ω˛” *
Which is / are allotrope(s) of carbon ?

(1) Diamond (2) Fullerene

(3) Both (4) None of these.

34. EÚ“]ı…‰x… |…EÚ…™……«i®…EÚ ∫…®…⁄Ω˛ EÚ… ∫…Ω˛“ °Ú…®…⁄«±…… EÚ…Ëx…-∫…… Ω˲ ?
(1) —C=O (2)

(3) — CHO (4) — COOH.

Which one is the correct formula for ketone functional group ?
(1) —C=O (2)

(3) — CHO (4) — COOH.

35. |……‰{…‰x…˱… EÚ… ∫…⁄j… EÚ…Ëx…-∫…… Ω˲ ?
(1) C3H6 (2) C3H8

(3) C3H6O (4) C 3 H 8 O.

Which is the formula of Propanal ?
(1) C3H6 (2) C3H8

(3) C3H6O (4) C 3 H 8 O.

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36. ¥…π…˱…“ ∂…Æ˙…§… ®… EÚ…Ëx…-∫…… {…n˘…l…« {……™…… V……i…… Ω˲ ?
(1) B‰l…‰x……ϱ… (2) ®…‰l…‰x……ϱ…
(3) |……‰{…‰x……ϱ… (4) §™…⁄]‰ıx……ϱ… *
Poisonous liqueur contains which substance ?

(1) Ethanol (2) Methanol

(3) Propanol (4) Butanol.

37. +…v…÷ x…EÚ +…¥…i…« ∫……Æ˙h…“ ®… i…i¥…… EÚ…‰ EÚ∫… M…÷h… E‰Ú +…v……Æ˙ {…Æ˙ ¥™…¥…Œ∫l…i… EÚ™…… M…™…… Ω˲ ?
(1) {…Æ˙®……h…÷ j…V™…… (2) +…™…x…x… ¥…¶…¥…
(3) {…Æ˙®……h…÷ ∫…ΔJ™…… (4) {…Æ˙®……h…÷ ¶……Æ˙ *
On the basis of which property, elements are arranged in modern periodic table.

(1) Atomic radii (2) Ionisation potential

(3) Atomic number (4) Atomic weight.
38. {…Æ˙®……h…÷ GÚ®……ΔEÚ 79 ¥……±…… i…i¥… +…v…÷ x…EÚ +…¥…i…« ∫……Æ˙h…“ E‰Ú EÚ…Ëx…-∫…‰ +…¥…i…« ¥… ¥…M…« ®… ={…Œ∫l…i…
Ω˛…‰M…… ?
(1) 6 ¥……Δ +…¥…«i…, 11 ¥……Δ ¥…M…« (2) 5 ¥……Δ +…¥…«i…, 10 ¥……Δ ¥…M…«

(3) 6 ¥……Δ +…¥…«i…, 12 ¥……Δ ¥…M…« (4) 7 ¥……Δ +…¥…«i…n˘, 11 ¥……Δ ¥…M…« *

The element with atomic number 79 stands in which period and group of the
modern periodic table ?

(1) 6th period, 11th group (2) 5th period, 10th group
(3) 6th period, 12th group (4) 7th period, 11th group.

39. ¥…t÷i… @Òh…“ i…i¥… +…v…÷ x…EÚ +…¥…i…« ∫……Æ˙h…“ ®… EÚ∫… +…‰Æ˙ {……™…‰ V……i…‰ ΩÈ˛ ?
(1) §……<» +…‰Æ˙ (2) n˘…<» +…‰Æ˙
(3) ®…v™… ®… (4) EÚΩ˛” {…Æ˙ ¶…“ x…Ω˛” *
Electronegative elements are found on which side of modern periodic table ?

(1) Left side (2) Right side
(3) Middle (4) Nowhere.

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40. UÙ`‰ˆ +…¥…i…« ®… EÚi…x…‰ i…i¥… ΩÈ˛ ?
(1) 31 (2) 18

(3) 32 (4) 28.

How many elements are there in 6th period ?

(1) 31 (2) 18

(3) 32 (4) 28.

41. =n˘…∫…“x…“EÚÆ˙h… + ¶… GÚ™…… Ω˲
(1) +®±… ¥… ±…¥…h… E‰Ú ®…v™… (2) ±…¥…h… ¥… I……Æ˙ E‰Ú ®…v™…
(3) +®±… ¥… I……Æ˙ E‰Ú ®…v™… (4) +®±… ¥… V…±… E‰Ú ®…v™… *
Neutralisation reaction is

(1) between acid and salt (2) between salt and base

(3) between acid and base (4) between acid and water.
42. i…“x… R EÚ∫…‰ §…i……i…… Ω˲ ?
(1) EÚ®… ={…™……‰M…, {…÷x…:S…GÚh…, {…÷x…:={…™……‰M…
(2) ®…x…… EÚÆ˙x……, ∫…Ω˛“ EÚÆ˙x……, Æ˙…‰V… EÚÆ˙x……
(3) n˘…‰x……Â Ω˛“
(4) <x…®… ∫…‰ EÚ…‰<« ¶…“ x…Ω˛” *
Three R stands for

(1) Reduce, Recycle, Reuse (2) Refuse, Right, Routine

(3) Both (4) None of these.
43. +®…fii…… n‰˘¥…“ ¥…∂x……‰<« |… ∫…r˘ ΩÈ˛
(1) °Ú±®…“ Ω˛“Æ˙…‰<x… E‰Ú ∞¸{… ®… (2) J…‰V…Æ˙“ ¥…fiI…… E‰Ú ∫…ΔÆ˙I…EÚ E‰Ú ±…™…‰
(3) b˜EËÚi…“ E‰Ú ±…™…‰ (4) x…fii™……ΔM…x…… Ω˛…‰x…‰ E‰Ú EÚ…Æ˙h… *
Amrita Devi Vishnoi is famous as a

(1) film actress (2) conservator of Khejri trees

(3) dacoit (4) dancer.

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44. O…“x… Ω˛…>∫… M…Ë∫… Ω˲
(1) C2H2 (2) CO 2

(3) SO 3 (4) N2O5.

Which is Greenhouse gas ?
(1) C2H2 (2) CO 2

(3) SO 3 (4) N2O5.

45. +®…±…M…®… EÚ∫…E‰Ú ∫……l… ®…∏… v……i…÷ Ω˲ ?
(1) i……Δ§…… (2) ]ıx…
(3) {……Æ˙… (4) V…∫i…… *
Amalgam is an alloy with

(1) Copper (2) Tin

(3) Mercury (4) Zinc.

46. ∫… GÚ™…i…… ∏…‰h…“ ®… ∫…§…∫…‰ x…“S…‰ +…x…‰ ¥……±…“ v……i…÷™… {……<« V……i…“ ΩÈ˛
(1) ∫¥…i…xj… +¥…∫l…… ®… (2) ∫…±°Ú…<b˜ı +™…∫EÚ E‰Ú ∞¸{… ®…Â
(3) EÚ…§……«‰x…‰]ı E‰Ú ∞¸{… ®… (4) +…ÏC∫……<b˜ E‰Ú ∞¸{… ®… *
Metals at the bottom of activity series are found as

(1) free state (2) sulphide ore

(3) carbonate (4) oxide.

47. ∫……‰ b˜™…®… Ω˛…<b≈˜…C∫……<b˜ ¥… V…ΔEÚ EÚ…‰ M…®…« EÚÆ˙x…‰ {…Æ˙ |……{i… Ω˛…‰i…… ΩË
(1) ∫……‰ b˜™…®… v……i…÷ (2) V…ΔEÚ +…ÏC∫……<b˜
(3) ∫……‰ b˜™…®… V…ΔE‰Ú]ı (4) EÚ…‰<« + ¶… GÚ™…… x…Ω˛” Ω˛…‰i…“ *
What will produce when NaOH ( sodium hydroxide ) is heated with zinc ?

(1) Sodium metal (2) Zinc oxide

(3) Sodium zincate (4) No reaction occurs.

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48. EÚ∫… ¥…±…™…x… ∫…‰ ¥…t÷i… v……Æ˙… EÚ… S……±…x… Ω˛…‰M…… ?
(1) M±…⁄EÚ…‰∫… ¥…±…™…x… (2) ∫…±}™…⁄ Æ˙EÚ +®±… ¥…±…™…x…
(3) B‰±EÚ…‰Ω˛±… ¥…±…™…x… (4) <x…®… ∫…‰ EÚ…‰<« ¶…“ x…Ω˛” *
Which solution will conduct electric current ?

(1) Glucose solution (2) Sulphuric acid solution

(3) Alcohol solution (4) None of these.

49. +…™… x…EÚ ™……Ë M…EÚ ∫……®……x™…i…: n˘∂……«i…‰ ΩÈ˛
(1) EÚ`ˆ…‰Æ˙i…… (2) =SS… M…±…x……ΔEÚ ¥… C¥…l…x……ΔEÚ
(3) V…±… ®… ¥…±…‰™…i…… (4) <x…®… ∫…‰ ∫…¶…“ *
Ionic compounds generally show

(1) hardness (2) high melting and boiling points

(3) water solubility (4) all of these.

50. EÚ…‰§……±]ı EÚ… {…Æ˙®……h…÷ GÚ®……ΔEÚ EÚi…x…… ΩË ?
(1) 24 (2) 27

(3) 28 (4) 26.

What is the atomic number of Cobalt ?

(1) 24 (2) 27

(3) 28 (4) 26.
51. ¥…∫…… E‰Ú {……S…x… ∫…‰ ∫…Δ§…Δ v…i… BxV……<®… Ω˲
(1) B®……<±…‰V… (2) ±……<{…‰V…
(3) {…‰Œ{∫…x… (4) ]≈ıŒ{∫…x… *
The enzyme related with digestion of fat is

(1) amylase (2) lipase

(3) pepsin (4) trypsin.

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52. UÙ: EÚ…§…«x…™…÷HÚ M±…⁄EÚ…‰V… E‰Ú BEÚ +h…÷ EÚ“ i…“x… EÚ…§…«x…™…÷HÚ {……<Ø˚¥…‰]ı E‰Ú n˘…‰ +h…÷+…Â ®…Â ¥…J…hbx…˜ EÚ“
GÚ™…… EÚΩ˛±……i…“ Ω˲
(1) E‰Ú ±¥…x… S…GÚ (2) M±……<EÚ…‰±……< ∫…∫…
(3) G‰Ú§∫… S…GÚ (4) M±……<EÚ…‰ V…x……‰±……< ∫…∫… *
The breakdown of glucose, a 6-carbon molecule into two, 3-carbon molecule

pyruvate is called

(1) Calvin cycle (2) Glycolysis

(3) Krebs’ cycle (4) Glycogenolysis.

53. |…Æ˙…‰Ω˛ E‰Ú +O… ¶……M… ®…Â ∫…Δ∂±…‰ π…i… Ω˛…‰x…‰ ¥……±…… Ω˛…Æ˙®……‰x… V……‰ EÚ |…Æ˙…‰Ω˛ E‰Ú UÙ…™…… ¥……±…‰ ¶……M… ®…Â ¥…∫… Æ˙i…
Ω˛…‰i…… Ω˲ +…ËÆ˙ ¥…GÚi…… ±……i…… Ω˲, EÚΩ˛±……i…… Ω˲
(1) +…ÏŒC∫…x… (2) ∫……<]ı…‰EÚ…< x…x…
(3) V…§§…‰Æ‰˙ ±…x… (4) B §∫… ∫…EÚ +®±… *
A hormone which is synthesised at the shoot tip and then diffuses towards the

shady side of the shoot and causes curvature is called

(1) Auxin (2) Cytokinin

(3) Gibberellin (4) Abscisic acid.

54. •……™……‰ °Ú±…®… {……n˘{… ®… EÚ… ™…EÚ |…¥…v…«x… EÚ… ®……v™…®… Ω˲
(1) EÚI…∫l… EÚ ±…EÚ… (2) ∂…“π…«∫l… EÚ ±…EÚ…
(3) {…÷π{… EÚ ±…EÚ… (4) {…h…« EÚ ±…EÚ… *
The means of vegetative propagation in Bryophyllum plant is

(1) Auxillary bud (2) Apical bud

(3) Flower bud (4) Leaf bud.

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55. x…®x… ®… ∫…‰ EÚ…Ëx…-∫…… ™……Ëx… ∫…ΔS… Æ˙i… Æ˙…‰M… EÚ… =n˘…Ω˛Æ˙h… x…Ω˛” Ω˲ ?
(1) M……‰x…‰ Æ˙™…… (2) ∫…°Ú ±…∫…
(3) Bb˜¬∫… (4) Ω˛{…‘W… *
Which is not an example of sexually transmitted disease ?

(1) Gonorrhoea (2) Syphilis
(3) AIDS (4) Herpes.

56. +…‰V……‰x… {…Æ˙i… EÚ…‰ x…÷EÚ∫……x… {…Ω÷ƒ˛S……x…‰ ¥……±…… |…®…÷J… EÚ…Æ˙EÚ Ω˲
(1) EÚ…§…«x… b˜…<+…ÏC∫……<b˜ (2) EÚ…§…«x… ®……‰x……‰C∫……<b˜
(3) Ω˛…<b≈˜…‰EÚ…§…«x∫… (4) C±……‰Æ˙…‰}±…÷+…‰Æ˙…‰ EÚ…§…«x… *
The main factor responsible for the damage of ozone layer is

(1) Carbon dioxide (2) Carbon monoxide

(3) Hydrocarbons (4) Chlorofluorocarbon.

57. Æ˙…V…∫l……x… ®… V…±… ∫…ΔO…Ω˛h… Ω‰˛i…÷ ={…™……‰M… ±…“ V……x…‰ ¥……±…“ ∫…ΔÆ˙S…x…… Ω˲
(1) J…… n˘x… (2) i……±…
(3) E÷Ú±Ω˛ (4) §…Δ v…∫… *
The water harvesting structure found in Rajasthan is

(1) Khadins (2) Tal

(3) Kulhas (4) Bundhis.

58. EÚ…‰ ∂…EÚ… ®… §…x…‰ {…n˘…l……Á EÚ… ∫…ΔS…™…x…, ∞¸{……xi…Æ˙h… i…l…… §…xn˘ EÚÆ˙x…‰ ¥……±…… EÚ…‰ ∂…EÚ…ΔM… Ω˲
(1) ®……<]ı…‰EÚ…Ï xb≈˜™…… (2) M……ϱV…“ ={…EÚÆ˙h…
(3) +Δi…p«˘¥™…“ V…… ±…EÚ… (4) ±……<∫……‰∫……‰®… *
Cell organelle which functions in the storage, modification and packaging of

substances manufactured in the cell is

(1) Mitochondria (2) Golgi apparatus

(3) Endoplasmic reticulum (4) Lysosome.

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59. EÚ∫…E‰Ú ¶…“i…Æ˙“ +∫i…Æ˙ ®… {…I®……¶…“ ∫i…®¶……EÚ…Æ˙ B{…“l…“ ±…™…®… {……<« V……i…“ Ω˲ ?
(1) ¥…fiCEÚ“™… x…±…“ (2) ±……Æ˙ O…Δ l… EÚ“ x…±…“
(3) ∑……∫… x…±…“ (4) Æ˙HÚ x… ±…EÚ… *
Ciliated columnar epithelium is present in the inner lining of

(1) kidney tubules (2) ducts of salivary glands

(3) respiratory tract (4) blood vessels.

60. V…±… ¥… J… x…V… ±…¥…h…… E‰Ú ∫…Δ¥…Ω˛x… Ω‰˛i…÷ ¥… ∂…π]ı >i…EÚ EÚ“ +x…÷ {…Œ∫l… i… |…®…÷J… ±…I…h… Ω˲
(1) B xV…™……‰∫{…®…« EÚ… (2) •……™……‰°Ú…<]ı… EÚ…
(3) ]‰ı Æ˙b˜…‰°Ú…<]ı… EÚ… (4) V…®x……‰∫{…®…« EÚ… *
The absence of specialised tissue for conduction of water and minerals is the

main characteristic feature of

(1) Angiosperms (2) Bryophyta

(3) Pteridophyta (4) Gymnosperms.

61. EÚ…±……W……Æ˙ ¥™…… v… EÚ… EÚ…Æ˙EÚ Ω˲
(1) ]≈ı{x……‰∫……‰®…… (2) ±…‰∂®…… x…™……
(3) ∫]‰ı°Ú…<±……‰EÚ…‰EÚ…<« (4) {±……V®……‰ b˜™…®… *
Which of the following is the cause of Kala-azar disease ?

(1) Trypanosoma (2) Leishmania

(3) Staphylococci (4) Plasmodium.

62. EÚ±…“n˘…Æ˙ {……n˘{…… EÚ“ ®…⁄±… O…Δ l…EÚ…+… ®… {……™…… V……x…‰ ¥……±…… x……<]≈ı…‰V…x… ∫l…Æ˙“EÚ…Æ˙“ V…“¥……h…÷ Ω˲
(1) C±……‰∫]≈ı“ b˜™…®… (2) B‰V…‰]ı…‰§…‰C]ıÆ˙
(3) ∫……<x……‰§…ËC]ı“ Æ˙™…… (4) Æ˙…<V……‰ §…™…®… *
The nitrogen fixing bacteria found in the root nodules of leguminous plants is

(1) Clostridium (2) Azotobacter

(3) Cyanobacteria (4) Rhizobium.

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63. ∑…‰i… GÚ…Œxi… ∫…®§…Œxv…i… Ω˲
(1) ®…i∫™… ∫…‰ (2) Ɖ˙∂…®… ∫…‰
(3) n÷˘Mv… ∫…‰ (4) +x……V… ∫…‰ *
White revolution is related with

(1) Fish (2) Silk

(3) Milk (4) Cereals.

64. {……n˘{…… ®… {…h…«Ω˛ Æ˙i… E‰Ú x…®……«h… Ω‰˛i…÷ +…¥…∂™…EÚ i…i¥… Ω˲
(1) ®…ÈM…x…“V… (2) x……<]≈ı…‰V…x…
(3) ®…ËMx…“ ∂…™…®… (4) °Ú…∫°Ú…‰Æ˙∫… *
The essential element for the formation of chlorophyll in plants is

(1) Manganese (2) Nitrogen

(3) Magnesium (4) Phosphorus.

65. °Ú∫…±…“ {……n˘{… EÚ… =n˘…Ω˛Æ˙h… Ω˲
(1) V…È l…™…®… (2) ]≈ı]ı“EÚ®…
(3) {……Æ˙l…‰ x…™…®… (4) ∫……< |…x…∫… *
An example of cereal plant is

(1) Xanthium (2) Triticum

(3) Parthenium (4) Cyprinus.

66. x…®x… ®… ∫…‰ @Òi…÷ª……¥… EÚ…‰ x…™…Δ j…i… EÚÆ˙x…‰ ¥……±…… Ω˛…Æ˙®……‰x… Ω˲
(1) Æ˙±…‰ŒC∫…x… (2) |……‰V…‰∫]≈ı…Ïx…
(3) |……‰±…‰ŒC]ıx… (4) +…ÏC∫…“]ı…‰ ∫…x… *
Which of the following hormones regulates the menstruation ?

(1) Relaxin (2) Progesterone

(3) Prolactin (4) Oxytocin.

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67. C™…… Ω˛…‰M…… ™… n˘ EÚ∫…“ ∫j…“ ®… M…¶……«∂…™… E‰Ú ∫l……x… {…Æ˙ BEÚ {±……Œ∫]ıEÚ EÚ“ l…˱…“ |… i…∫l…… {…i… EÚÆ˙ n˘“
V……B ?
(1) ß…⁄h… {… Æ˙¥…v…«x… x…Ω˛” Ω˛…‰M…… (2) ®……n˘… ™…÷M®…EÚ EÚ… x…®……«h… x…Ω˛” Ω˛…‰M……
(3) @Òi…÷ª……¥… x…Ω˛” Ω˛…‰M…… (4) +hb˜…∂…™… ∫…‰ +hb˜®……‰S…x… x…Ω˛” Ω˛…‰M…… *
What will happen if the uterus is replaced by a plastic pouch in a woman ?

(1) Embryo development will not take place

(2) Female gamete will not be formed

(3) Menstruation will not take place

(4) Ovary will not release egg.

68. ∫…®…∞¸{… +ΔM…… EÚ… ∫…Ω˛“ ™…÷M®… Ω˲
(1) Ω˛®……Æ˙… Ω˛…l… B¥…Δ E÷Úk…‰ EÚ… +O…{……n˘ (2) {…I…“ E‰Ú {…ΔJ… B¥…Δ i…i…±…“ E‰Ú {…ΔJ…
(3) Ω˛®……Ɖ˙ n˘…ƒi… B¥…Δ Ω˛…l…“ E‰Ú n˘…ƒi… (4) i……‰i…‰ E‰Ú {…ΔJ… B¥…Δ S…“±… E‰Ú {…ΔJ… *
The correct pair of Analogous organs is

(1) our arm and dog’s fore-leg

(2) wings of bird and wings of butterfly
(3) our teeth and elephant’s tusk

(4) wings of parrot and wings of eagle.

69. ¥……∫i… ¥…EÚ n‰˘Ω˛M…÷Ω˛… ™…÷HÚ V…xi…÷+… EÚ… ∫…®…⁄Ω˛ Ω˲
(1) {±…‰]ı“Ω‰˛ ±®…xl…“V… (2) x…®…‰]ı…‰b˜…
(3) ∫…“±…‰x]≈‰ı]ı… (4) Bx…‰ ±…b˜… *
The phylum which has true Coelom ( body cavity ) is

(1) Platyhelminthes (2) Nematoda

(3) Coelenterata (4) Annelida.

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70. Ω˛Æ˙… {……n˘{… → ]ıd˜… → S…⁄Ω˛… → ∫…{…« → §……V… – <∫… J……t ÈF_kJ…±…… ®… ∫…¥……« v…EÚ >V……« EÚ…Ëx…∫…‰ V…xi…÷ EÚ…‰
|……{i… Ω˛…‰M…“ ?
(1) S…⁄Ω˛… (2) ]ıb˜¬b˜…
(3) ∫…{…« (4) §……V… *
Green plant → Grasshopper → Rat → Snake → Eagle –

In this food chain which animal will receive maximum energy ?

(1) Rat (2) Grasshopper
(3) Snake (4) Eagle.
p
71. 1⋅ 27 EÚ… ∞¸{… Ω˲
q
12 13
(1) (2)
11 11
14 15
(3) (4) .
11 11
p
The form of number 1⋅ 27 is
q
12 13
(1) (2)
11 11
14 15
(3) (4) .
11 11
72. 22 / 3. 21/ 3 EÚ… ®……x… Ω˛…‰M……

(1) 22 / 9 (2) 22

(3) 2 (4) 21/ 3 .
The value of 22 / 3. 21/ 3 is

(1) 22 / 9 (2) 22

(3) 2 (4) 21/ 3 .
73. x 3 – 2x 2 – x + 2 EÚ… BEÚ M…÷h…x…J…hb˜ ( x + 1 ) Ω˛…‰, i……‰ n⁄∫…Æ˙… M…÷h…x…J…hb˜ Ω˛…‰M……

(1) x 2 – 3x + 2 (2) x 2 + 3x – 2

(3) x 2 – 3x – 2 (4) x 2 + 3x + 2 .

If one of the factors of x 3 – 2x 2 – x + 2 is ( x + 1 ), then another factor will be

(1) x 2 – 3x + 2 (2) x 2 + 3x – 2

(3) x 2 – 3x – 2 (4) x 2 + 3x + 2 .

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74. ™… n˘ Ω˛®… +Δ∂… ®… 1 V……‰c˜ n¢ i…l…… Ω˛Æ˙ ®… 1 P…]ı… n¢ i……‰ ¶…z… 1 ®… §…n˘±… V……i…“ ΩË * ™… n˘ Ω˛Æ˙ ®… 1 V……‰c˜ n¢,
i……‰ ™…Ω 12 Ω˛…‰ V……i…“ Ω˲ * ¥…Ω˛ ¶…z… C™…… Ω˲ ?
2 3
(1) (2)
5 5
4 2
(3) (4) .
5 3
If we add 1 to the numerator and subtract 1 from the denominator, a fraction
reduces to 1. It becomes 1 , if we only add 1 to denominator. What is the
2
fraction ?
2 3
(1) (2)
5 5
4 2
(3) (4) .
5 3
75. ™… n˘ 9x 2 – 15x + 6 = 0 i…l…… ( 3x – 52 ) 2 = k BEÚ ∫…®……x… Ω˛…‰, i……‰ k EÚ… ®……x… Ω˛…‰M……
1
(1) (2) 4
4
1
(3) 9 (4) .
9
If 9x 2 – 15x + 6 = 0 and 3x – 52 ( ) = k are identical, then the value of k is
2

1
(1) (2) 4
4
1
(3) 9 (4) .
9
76. °⁄Ú±…… EÚ“ BEÚ C™……Æ˙“ EÚ“ {…Ω˛±…“ {…Δ HÚ ®… 23 M…÷±……§… E‰Ú {……Ëv…‰ ΩÈ˛, n⁄˘∫…Æ˙“ {…Δ HÚ ®… 21 M…÷±……§… E‰Ú {……Ëv…‰ ΩÈ˛,
i…“∫…Æ˙“ {…Δ HÚ ®… 19 M…÷±……§… E‰Ú {……Ëv…‰ ΩÈ˛ * <∫…“ GÚ®… ®… ™… n˘ + xi…®… {…Δ HÚ ®… 5 M…÷±……§… E‰Ú {……Ëv…‰ Ω˛…Â, i……‰
<∫… C™……Æ˙“ ®… E÷Ú±… EÚi…x…“ {…Δ HÚ™……ƒ ΩÈ˛ ?
(1) 20 (2) 15
(3) 10 (4) 5.
In the flower bed, there are 23 rose plants in the first row, 21 in the second,
19 in the third and so on. If there are 5 rose plants in the last row, then how
many rows are there in the flower bed ?
(1) 20 (2) 15
(3) 10 (4) 5.
77. ™… n˘ sin 3A = cos ( A – 26° ) Ω˛…‰, V…Ω˛…ƒ 3A BEÚ x™…⁄x… EÚ…‰h… Ω˛…‰, i……‰ A EÚ… ®……x… C™…… Ω˛…‰M…… ?
(1) A = 16° (2) A = 29°
(3) A = 58° (4) A = 30°.
If sin 3A = cos ( A – 26° ), where 3A is an acute angle then the value of A is
(1) A = 16° (2) A = 29°
(3) A = 58° (4) A = 30°.

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1 + tan 2 θ
78. EÚ… ®……x… Ω˲
1 + cot 2 θ
(1) sec 2 θ (2) –1
2
(3) cot θ (4) tan 2 θ.
1 + tan 2 θ
is equal to
1 + cot 2 θ
(1) sec 2 θ (2) –1
2
(3) cot θ (4) tan 2 θ.
79. BEÚ x…n˘“ {…Æ˙ §…x…‰ {…÷±… EÚ“ x…n˘“ E‰Ú EÚx……Æ˙… ∫…‰ >ƒS……<« 3 ®…“]ıÆ˙ Ω˲ * {…÷±… {…Æ˙ Œ∫l…i… EÚ∫…“ §…xn÷˘ ∫…‰ x…n˘“
E‰Ú ∫…®®…÷J… EÚx……Æ˙… E‰Ú +¥…x…®…x… EÚ…‰h… GÚ®…∂…: 30° Ú∫…‰ 45° ÚΩ˛…‰, i……‰ x…n˘“ EÚ“ S……Ëc˜…<« Ω˛…‰M…“
(1) 6 ®…“]ıÆ˙ (2) 3 ( 3 + 1 ) ®…“]ıÆ˙
(3) 2 ( 3 + 1 ) ®…“]ıÆ˙ (4) ( 3 + 1 ) ®…“]ıÆ˙ *
From a point on a bridge across a river, the angles of depression of the bank on
opposite sides of the river are 30° & 45° respectively. If the bridge is at a height of
3 m from the bank, the width of the river is
(1) 6m (2) 3( 3 +1) m
(3) 2( 3 + 1 ) m (4) ( 3 + 1 ) m.
80. n˘“ M…<« +…EfiÚ i… ®… ™… n˘ PQ || ST, ∠ PQR = 110° +…ËÆ˙ ∠ RST = 130° Ω˛…‰, i……‰ ∠ QRS EÚ…
®……x… Ω˛…‰M……

(1) 60° (2) 70°
(3) 80° (4) 90°.
In the given figure, if PQ || ST, ∠ PQR = 110° and ∠ RST = 130°. Then the value
of ∠ QRS is

(1) 60° (2) 70°
(3) 80° (4) 90°.

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81. ™… n˘ S…i…÷¶…÷«V… ABCD EÚ“ ∫…§…∫…‰ UÙ…‰]ı“ +…ËÆ˙ ∫…§…∫…‰ §…c˜“ ¶…÷V……Bƒ GÚ®…∂…: AB +…ËÆ˙ CD ΩÈ˛, i……‰ x…®x… ®… ∫…‰
EÚ…Ëx…-∫…… EÚl…x… ∫…i™… Ω˲ ?

(1) ∠ A > ∠ C >∠ D >∠ B (2) ∠ C > ∠ B >∠ D >∠ A

(3) ∠ B > ∠ C >∠ D >∠ A (4) ∠ A > ∠ C >∠ B >∠ D.
In the given figure, if AB and CD are respectively the smallest and longest sides
of a quadrilateral ABCD, then which statement is true ?

(1) ∠ A > ∠ C >∠ D >∠ B (2) ∠ C > ∠ B >∠ D >∠ A

(3) ∠ B > ∠ C >∠ D >∠ A (4) ∠ A > ∠ C >∠ B >∠ D.

82. x…®x… +…EfiÚ i… ®…Â Δ ABC EÚ“ ¶…÷V…… AC E‰Ú ∫…®……xi…Æ˙ Ɖ˙J…… J…hb˜ XY Ω˲ i…l…… ™…Ω˛ Δ ABC EÚ…‰ n˘…‰
§…Æ˙…§…Æ˙ I…‰j…°Ú±… ¥……±…‰ ¶……M…… ®… ¥…¶…… V…i… EÚÆ˙i…… Ω˲, i……‰ XB +…ËÆ˙ AB EÚ… +x…÷{……i… Ω˛…‰M……

(1) 2 :1 (2) 1: 2

(3) 1:( 2 –1) (4) ( 2 – 1 ) : 1.

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In the given figure, the line segment XY is parallel to side AC of Δ ABC and it
divides the triangle into two parts of equal area. The ratio of XB and AB is

(1) 2 :1 (2) 1: 2
(3) 1:( 2 –1) (4) ( 2 – 1 ) : 1.
83. x…®x… +…EfiÚ i… E‰Ú +x…÷∫……Æ˙ n˘…‰ ¥…fik… BEÚ n⁄˘∫…Ɖ˙ EÚ…‰ B ¥… C {…Æ˙ |… i…SU‰Ùn˘ EÚÆ˙i…‰ ΩÈ˛ * B §…xn÷˘ ∫…‰ M…÷V…Æ˙x…‰
¥……±…‰ Ɖ˙J…… J…hb ABD +…ËÆ˙ PBQ ¥…fik……‰Δ EÚ…‰ GÚ®…∂…: A, D ¥… P, Q {…Æ˙ |… i…SU‰Ùn˘ EÚÆ˙i…‰ ΩÈ˛ * ™… n˘
∠ ABP = 25° +…ËÆ˙ ∠ CAB = 50° Ω˛…‰, i……‰∠ DCQ EÚ… ®……x… Ω˛…‰M……

(1) 25° (2) 50°
(3) 30° (4) 90°.
In the given figure, two circles intersect in two points B and C. Through B, two
line segments ABD and PBQ are drawn intersecting the circles in A, D and P, Q
respectively. If ∠ ABP = 25° and ∠ CAB = 50° then the value of ∠ DCQ is

(1) 25° (2) 50°
(3) 30° (4) 90°.
84. BEÚ ∫…®…S…i…÷¶…÷«V… E‰Ú ∂…“π…« GÚ®…∂…: ( 3, 0 ), ( x, y ), ( – 1, 4 ) +…ËÆ˙ ( – 2, – 1 ) Ω˲, i……‰ ∫…®…S…i…÷¶…÷«V…
EÚ… ∂…“π…« ( x, y ) Ω˛…‰M……
(1) ( – 2, – 3 ) (2) ( 0, 3 )
(3) ( 4, 5 ) (4) ( – 4, 5 ).
If ( 3, 0 ), ( x, y ), ( – 1, 4 ) and ( – 2, – 1 ) are vertices of a rhombus taken in
order, then vertex ( x, y ) is
(1) ( – 2, – 3 ) (2) ( 0, 3 )
(3) ( 4, 5 ) (4) ( – 4, 5 ).
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85. n˘“ M…<« +…EfiÚ i… ®… n˘…‰ ∫…ΔE‰Úxp˘“™… O E‰Úxp˘¥……±…‰ ¥…fik…… EÚ“ j…V™……Bƒ GÚ®…∂…: 7 ∫…‰®…“ +…ËÆ˙ 14 ∫…‰®…“ ΩËΔ * V…Ω˛…ƒ
O ¥…fik…… EÚ… E‰Úxp˘ ΩË * ™… n˘˘ ∠ AOC = 40°, i……‰ UÙ…™……Δ EÚi… ¶……M… EÚ… I…‰j…°Ú±… Ω˛…‰M……

49 π 21π 28 π 35 π
(1) (2) (3) (4) .
3 3 3 3
According to figure, the radii of two concentric circles with centre O are 7 cm &
14 cm respectively. If ∠ AOC = 40°, then the area of shaded region is

49 π 21π 28 π 35 π
(1) (2) (3) (4) .
3 3 3 3
86. ™… n˘ BEÚ M……‰±…‰ E‰Ú ¥™……∫… ®… 25% EÚ“ EÚ®…“ EÚ“ V……i…“ Ω˲, i……‰ =∫…EÚ… {…fiπ`ˆ“™… I…‰j…°Ú±… EÚi…x…‰ |… i…∂…i…
EÚ®… Ω˛…‰M…… ?
(1) 56·25% (2) 55%
(3) 40% (4) 43·75%.
The diameter of a sphere is decreased by 25%. Its surface area will be decreased
by
(1) 56·25% (2) 55%
(3) 40% (4) 43·75%.
87. BEÚ ∂…ΔE÷Ú EÚ… UÙz…EÚ, V……‰ 45 ∫…‰®…“ >ƒS…… Ω˲, E‰Ú ∫…Æ˙… EÚ“ j…V™……Bƒ 28 ∫…‰®…“ +…ËÆ˙ 7 ∫…‰®…“ ΩÈ˛, i……‰
UÙz…EÚ EÚ… +…™…i…x… Ω˛…‰M……
(1) 8079·5 ∫…‰®…“ 3 (2) 6620 ∫…‰®…“ 3

(3) 48510 ∫…‰®…“ 3 (4) 5461·5 ∫…‰®…“ 3 .
The radii of the ends of frustum of a cone of height 45 cm are 28 cm and 7 cm.
The volume of frustum of cone is
(1) 8079·5 cm 3 (2) 6620 cm 3
(3) 48510 cm 3 (4) 5461·5 cm 3 .

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88. ™… n˘ x…®x… ±… J…i… §…Δ]ıx… EÚ… ®……v™… 6 Ω˲, i……‰ f EÚ… ®……x… Ω˛…‰M……
¥…M…« +xi…Æ˙…±… : 0-2 2-4 4-6 6-8 8 - 10
§……Æ˙®§……Æ˙i…… : 1 2 5 f 3
(1) 6 (2) 7
(3) 5 (4) 3.
If the mean of the following distribution is 6, the value of f is
Class-interval : 0-2 2-4 4-6 6-8 8 - 10
Frequency : 1 2 5 f 3
(1) 6 (2) 7
(3) 5 (4) 3.
89. EÚ∫…“ M…Ân˘§……V… u˘…Æ˙… 10 GÚE‰Ú]ı ®…ËS…… ®… ±…B M…™…‰ ¥… EÚ]ı… EÚ“ ∫…ΔJ™……B x…®x… ΩÈ˛ :
2, 6, 4, 5, 0, 2, 1, 3, 2, 3
<x… +…ƒEÚc˜… EÚ… §…Ω÷˛±…EÚ Ω˲
(1) 6 (2) 5
(3) 3 (4) 2.
The wickets taken by a bowler in 10 cricket matches are as follows :
2, 6, 4, 5, 0, 2, 1, 3, 2, 3
The mode of the data is
(1) 6 (2) 5
(3) 3 (4) 2.
90. BEÚ {……∫…‰ EÚ…‰ BEÚ Ω˛V……Æ˙ §……Æ˙ °ÂÚEÚx…‰ {…Æ˙ |……{i… {… Æ˙h……®……Â 1, 2, 3, 4, 5 +…ËÆ˙ 6 EÚ“ §……Æ˙®§……Æ˙i……Bƒ x…®x…
∫……Æ˙h…“ ®… n˘“ M…<« ΩÈ˛ :
{… Æ˙h……®… : 1 2 3 4 5 6
§……Æ˙®§……Æ˙i…… : 179 150 157 149 175 190
{… Æ˙h……®… 5 E‰Ú +…x…‰ EÚ“ |…… ™…EÚi…… Ω˲
(1) 0·150 (2) 0·175
(3) 0·149 (4) 0·157.
A die is thrown 1000 times with the frequencies for the outcomes 1, 2, 3, 4, 5
and 6 are given in the following table :
Outcome : 1 2 3 4 5 6
Frequency : 179 150 157 149 175 190
Probability of the outcome 5 is
(1) 0·150 (2) 0·175
(3) 0·149 (4) 0·157.

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SPACE FOR ROUGH WORK / Æ˙°Ú EÚ…™…« E‰Ú ±…B V…M…Ω˛

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SPACE FOR ROUGH WORK / Æ˙°Ú EÚ…™…« E‰Ú ±…B V…M…Ω˛

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SPACE FOR ROUGH WORK / Æ˙°Ú EÚ…™…« E‰Ú ±…B V…M…Ω˛

STSE/15 – SAT-1007 1007 [ P.T.O.

Document Details

Board / OrgRajasthan Board
ExamSTSE
TypeQuestion Paper
Pages31
Updated09 Jun 2026