Karnataka SSLC Mid Term Question Paper 2025 Science

Government of Karnataka
Karnataka Secondary Education Examination Board

Question Papers
Mid Term

PÜ®ÝìoPÜ ÍÝÇÝ ±ÜÄàûæ ÊÜáñÜᤠÊÜåèƯ|ì¿á ÊÜáívÜÈ
6 ®æà AvÜxÃÜÓæ¤, ÊÜáÇæÉàÍÜÌÃÜí, ¸æíWÜÙÜãÃÜá & 560 003

KARNATAKA SCHOOL EXAMINATION AND ASSESSMENT BOARD
6th Cross, Malleshwaram, Bengaluru – 560 003

2025-26 ®æà ÓÝ騆 GÓ….GÓ….GÇ….Ô. A«ÜìÊÝÑìPÜ ±ÜÄàûæ
S.S.L.C. MID-TERM EXAMINATION
FOR THE YEAR – 2025-26
…Œ⁄æ⁄fl : …e¤k´⁄
Subject : SCIENCE
(»èñÜ ËþÝ®Ü, ÃÜÓÝ¿á®Ü ËþÝ®Ü ÊÜáñÜᤠiàÊÜ ËþÝ®Ü / Physics, Chemistry & Biology )
( BMW«ŒÈ »⁄·¤®⁄¥¿»⁄fl / English Medium )
ËÐÜ¿á ÓÜíPæàñÜ : 83-E Subject Code : 83-E

©®ÝíPÜ : 13. 09. 2025 ] [ Date : 13. 09. 2025
ÓÜÊÜá¿á : ¸æÙÜWæY 10-30 Äí¨Ü ÊÜá«ÝÂÖÜ° 1-45 ÃÜÊÜÃæWæ ] [ Time : 10-30 A.M. to 1-45 P.M.
WÜÄÐÜu AíPÜWÜÙÜá : 80 ] [ Max. Marks : 80

General Instructions to the Candidate :
1. There are three parts in the question paper :
Part A : Physics, Part B : Chemistry, Part C : Biology.
2. This question paper consists of 38 questions.
3. Follow the instructions given against the questions.
4. Figures in the right hand margin indicate maximum marks for the questions.
5. The maximum time to answer the paper is given at the top of the question paper.
It includes 15 minutes for reading the question paper.
PART – A
( PHYSICS )

I. Four alternatives are given for each of the following questions / incomplete
statements. Choose the correct alternative and write the complete answer
along with its letter of alphabet. 2×1=2

1. The field lines inside a current carrying solenoid are parallel. Hence the
magnetic field inside the solenoid is

(A) very high (B) equal

(C) zero (D) very low
MID/T-25-26/11 [ Turn over

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2. An electric current flowing through a conductor for 2 seconds generates ‘J’
joules of heat. If the current flowing through the same conductor is doubled
1
and passed for a second, then the amount of heat generated is
2
J
(A) (B) J
2

(C) 2J (D) 4J

II. Answer the following questions : 3×1=3

3. Name the device used to vary resistance in an electric circuit.

4. Why does a magnetic needle brought near a bar magnet deflect ?

5. A part of a diagram showing the flow of current in a circuit is given :

If I 1 > I 2 , I 4 > I 3 and I 2 = 2 I 4 then the resistance of which resistor is

more ?

III. Answer the following questions : 2×2=4

6. Observe the figure of a bar magnet given below. Between the points A and
B, in which of the points is the magnitude of the magnetic field lesser ?
Mention the reason.

7. State Joule’s law of heating. Write the mathematical form of this law.

OR

State Ohm’s law. Define 1 ‘ohm’.

IV. Answer the following questions : 3×3=9

8. Draw the schematic diagram of an electric circuit comprising of resistors
R 1 , R 2 and R 3 connected in series, a battery, a switch and the devices

used to measure the potential difference of the total resistance and electric
current.
MID/T-25-26/11

3 83-E

9. State Right hand thumb rule. Write four characteristics of magnetic field

lines.

OR

State Fleming’s left hand rule. Write the characteristics of magnetic field

lines formed around a current carrying circular loop.

10. a) Find the amount of charges flowing in a circuit if 1A of current flows

for 5 minutes in the circuit.

b) If 2 joules of work is done in bringing 1 coulomb of charge from one

point to another, then what is the potential difference between those

two points ?

OR

a) Find the work done if 9 C of charge moves between two points having

a potential difference of 9 V.

b) What is the electric current if 3 C of charge flows through a point in

3 sec in an electric circuit ?

V. Answer the following question : 1×4=4

11. a) What is overload ? What are the causes for overloading in domestic

electric circuit ?

b) What is the function of an earth wire ?

VI. Answer the following question : 1×5=5

12. a) What is electric power ? Which is the SI unit of electric power ? Write

the three formulae used to calculate electric power.

b) What is the function of a fuse ? What is the difference between the

wire used in the filaments of bulbs and the wire used in the fuses with

respect to their melting points ?

MID/T-25-26/11 [ Turn over

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PART – B

( CHEMISTRY )
VII. Four alternatives are given for each of the following questions / incomplete
statements. Choose the correct alternative and write the complete answer
along with its letter of alphabet. 3×1=3

13. Among the following reactions, a chemical reaction that resembles the
reaction in which a reddish brown coat is formed on the shining surface of
iron articles is

(A) Coating of chromium on iron articles

(B) Formation of silver sulphide on silver articles by oxidation

(C) Obtaining copper coat on iron nail by electrolysis

(D) Formation of grey coloured silver by the decomposition of silver
chloride

14. The pH value of a solution is 7. The pH value of this solution can be
increased by adding

(A) a small amount of an acid

(B) 5 gm of common salt

(C) a small amount of sodium hydroxide

(D) carbon dioxide through a delivery tube

15. An acid present in the stinging hairs of nettle leaves is

(A) Methanoic acid (B) Oxalic acid

(C) Citric acid (D) Lactic acid

VIII. Answer the following questions : 3×1=3

16. Suggest any two methods to prevent rancidity.

17. When sodium sulphate solution is added to barium chloride solution, a
white precipitate will be formed. Which are the ions responsible for this
precipitate formation ?

MID/T-25-26/11

5 83-E

18. Observe the below depicted experiments. Predict the nature of the salts
that form in beaker A and beaker B.

IX. Answer the following questions : 3×2=6

19. List the observations that help us to determine that a chemical reaction
has been taken place.

20. Draw a diagram of the apparatus used in the electrolysis of water and label
the following parts :

i) Graphite rod

ii) Oxygen

21. Draw the diagram of the arrangement of the apparatus used to show the
reaction of zinc granules with dilute sulphuric acid.

X. Answer the following questions : 3×3=9

22. Read the data given. Analyse and answer the questions given below :

Water is added to a beaker containing calcium oxide.

When ferrous sulphate crystals are heated, the green colour of these crystals

disappears.

i) Identify the exothermic and the endothermic reactions among these

reactions.

ii) What is the reason for the disappearance of green colour of ferrous sulphate

crystals ? Determine the type of this reaction.

OR

MID/T-25-26/11 [ Turn over

83-E 6

Analyse the following situations A and B. Answer the questions given :

A: Copper powder turns black when it is heated.

B: If hydrogen gas is passed over the heated black copper powder then copper

will be formed with water vapours.

i) Write the balanced chemical equations for the above situations.

ii) How can hydrogen be considered as a reactive element here ?

23. Write the molecular formula and any one use of each of the following salt :

i) Bleaching powder

ii) Plaster of Paris

iii) Sodium carbonate.

24. What is a strong acid ? How is tooth decay caused ? Mention a measure
that is followed to prevent tooth decay.

XI. Answer the following question : 1×4=4

25. a) What is the difference between concentrated and dilute acids ? How
do you detect the acids and bases using litmus papers ?

b) While diluting an acid, the acid should be added to water. Explain the
reason.

OR

a) Write any two differences between acids and bases. How do you detect
a solution as basic solution by using blue litmus paper ?

b) Name any two products that are formed in chlor-alkali process.

PART – C

( BIOLOGY )
XII. Four alternatives are given for each of the following questions / incomplete
statements. Choose the correct alternative and write the complete answer
along with its letter of alphabet. 3×1=3

26. Carbohydrates in the plants are stored in the form of

(A) Glycogen (B) Starch

(C) Glucose (D) Maltose
MID/T-25-26/11

7 83-E

27. Structures that perform exchange of oxygen and carbon dioxide are

(A) Villi (B) Skin pores

(C) Alveoli (D) Nephrons

28. Important role of synapses in neural communication is

(A) Transmitting electrical impulses

(B) Maintaining the structure of neurons

(C) Storing memories

(D) Facilitating communication between neurons.

XIII. Answer the following questions : 2×1=2

29. What is double circulation ?

30. The folding of leaves in sensitive plant ( touch-me-not plant ) for a touch is
not a tropism. Clarify the reason.

XIV. Answer the following questions : 3×2=6

31. Name the following :

a) The mineral essential for the production of thyroxine hormone.

b) The gland that secretes insulin hormone.

OR

Name the following :

a) Hormone that stimulates the growth of plant stems towards light.

b) Tropism in which plant root grows towards the soil.

32. Draw the diagram to show the structure of nephron and label the part
‘glomerulus’.

33. ‘Functioning of reflex arc is more effective than thinking process of the
brain. Clarify this statement with an illustration.

XV. Answer the following questions : 3×3=9

34. Draw the diagram showing the sectional view of the human brain. Label the
following parts.

i) Cerebrum

ii) Medulla.

MID/T-25-26/11 [ Turn over

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35. List the different methods of excretion that are found in plants.

36. Justify the following statements :

a) ‘The function of xylem tissue and the process of transpiration in
plants are correlated.’

b) ‘The amount of haemoglobin pigments determine the amount of
energy that is produced in our body.’

OR

Frog, peacock and fish : Arrange these animals on the basis of the
increasing order of the amount of energy generation in their body. Clarify
the reasons for your answer.

XVI. Answer the following questions : 2×4=8
37. a) Mention the function of ‘gastric juice’ and ‘intestinal juice’ in the
human digestive system.

b) List any two differences between aerobic respiration and anaerobic
respiration.

38. a) How does our body respond when adrenaline hormone is secreted into
the blood ? Explain.

b) Mention the components and the major role of human peripheral
nervous system.

MID/T-25-26/11

PÜ®ÝìoPÜ ÍÝÇÝ ±ÜÄàûæ ÊÜáñÜᤠÊÜåèƯ|ì¿á ÊÜáívÜÈ
6 ®æà AvÜxÃÜÓæ¤, ÊÜáÇæÉàÍÜÌÃÜí, ¸æíWÜÙÜãÃÜá & 560 003

KARNATAKA SCHOOL EXAMINATION AND ASSESSMENT BOARD
6th Cross, Malleshwaram, Bengaluru – 560 003
2025-26 ®æà ÓÝ騆 GÓ….GÓ….GÇ….Ô. A«ÜìÊÝÑìPÜ ±ÜÄàûæ
S.S.L.C. MID-TERM EXAMINATION FOR THE YEAR – 2025-26
ËÐÜ¿á : ËþÝ®Ü
Subject : SCIENCE
»èñÜ ËþÝ®Ü, ÃÜÓÝ¿á®Ü ËþÝ®Ü ÊÜáñÜᤠiàÊÜ ËþÝ®Ü / Physics, Chemistry & Biology
PܮܰvÜ ÊÜÞ«ÜÂÊÜá / Kannada Medium
ËÐÜ¿á ÓÜíPæàñÜ : 83-K Subject Code : 83-K
©®ÝíPÜ : 13. 09. 2025 ] [ Date : 13. 09. 2025
ÓÜÊÜá¿á ¸æÙÜWæY 10-30 Äí¨Ü ÊÜá«ÝÂÖÜ° 1-45 ÃÜÊÜÃæWæ ] [ Time : 10-30 A.M. to 1-45 P.M.
WÜÄÐÜu AíPÜWÜÙÜá 80 ] [ Max. Marks : 80

±ÜÄàûݦìWÝX ÓÝÊÜޮܠÓÜãaÜ®æWÜÙÜá
1. D ±ÜÅÍ氱ܣÅPæ¿áÈÉ »ÝWÜ&A : »èñÜ ËþÝ®Ü, »ÝWÜ&B : ÃÜÓÝ¿á®Ü ËþÝ®Ü, »ÝWÜ&C : iàÊÜ ËþÝ®Ü GíŸ
ÊÜáãÃÜá »ÝWÜWÜÚÊæ.
2. D ±ÜÅÍ氱ܣÅPæ¿áá Joár 38 ±ÜÅÍæ°WÜÙÜ®Üá° Öæãí©¨æ.
3. ±ÜÅÍæ°WÜÚWæ PæãqrÃÜáÊÜ ÓÜãaÜ®æWÜÙÜ®Üá° ±ÝÈÔ.
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5. ±ÜÅÍ氱ܣÅPæ¿á®Üá° K©PæãÙÜÛÆá 15 ¯ËáÐÜWÜÙÜ PÝÇÝÊÜPÝÍÜÊÜâ ÓæàĨÜíñæ, EñܤÄÓÜÆá ¯WÜ©±ÜwÓÜÇݨÜ
ÓÜÊÜá¿áÊÜ®Üá° ±ÜÅÍ氱ܣÅPæ¿á ÊæáàÇݽWܨÜÈÉ ¯àvÜÇÝX¨æ.
»ÝWÜ & A
( »èñÜ ËþÝ®Ü )
I. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ A¥ÜÊÝ A±Üä|ì ÖæàÚPæWÜÚWæ ®ÝÆáR ±Ü¿Þì¿á EñܤÃÜWÜÙÜ®Üá° ¯àvÜÇÝX¨æ. AÊÜâWÜÙÜÈÉ
ÓÜãPܤÊÝ¨Ü Jí¨Üá EñܤÃÜÊÜ®Üá° BÄÔ, A¨ÜÃÜ PÜÅÊÜÞûÜÃܨæãvÜ®æ ±Üä|ì EñܤÃÜÊÜ®Üá° ŸÃæÀáÄ 2×1=2

1. ˨ÜáÂñ…±ÜÅÊÝÖÜËÃÜáÊÜ ÓæãÇæ®Ý¿å…x®Ü JÙÜWæ PÝí£à¿á ŸÆÃæàTæWÜÙÜá ÓÜÊÜÞíñÜÃÜ
ÓÜÃÜÙÜÃæàTæWÜÙÝXÃÜáñܤÊæ. B¨ÜªÄí¨Ü ÓæãÇæ®Ý¿å…x®Ü JÙÜX®Ü PÝíñÜûæàñÜÅÊÜâ
(A) ñÜáí¸Ý ÖæaÝcXÃÜáñܤ¨æ (B) Jí¨æà ÓÜÊÜá®ÝXÃÜáñܤ¨æ
(C) ÍÜã®ÜÂÊÝXÃÜáñܤ¨æ (D) ñÜáí¸Ý PÜwÊæá CÃÜáñܤ¨æ

MID/T-25-26/10 [ Turn over

83-K 2
2. Jí¨Üá ÊÝÖÜPÜ¨Ü ÊÜáãÆPÜ 2 ÓæPæívÜáWÜÙÜ PÝÆ ÖÜÄ¿ááÊÜ Ë¨ÜáÂñ…±ÜÅÊÝÖÜÊÜâ ‘J’ hèÇ…®ÜÐÜár EÐÜ¡ÊÜ®Üá°
Eñݳ©ÓÜáñܤ¨æ. A¨æà ÊÝÖÜPÜ¨Ü ÊÜáãÆPÜ ÖÜÄ¿ááÊÜ Ë¨ÜáÂñ…±ÜÅÊÝÖÜÊÜâ ©ÌWÜá|WæãívÜÃæ 12 ÓæPæív…®ÜÈÉ
Eñܳ£¤¿ÞWÜáÊÜ EÐÜ¡¨Ü ±ÜÅÊÜÞ|ÊÜâ

(A) J (B) J
2

(C) 2J (D) 4J

II. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ 3×1=3

3. ˨ÜáÂñ…ÊÜáívÜƨÜÈÉ Ãæãà«ÜÊÜ®Üá° Ÿ¨ÜÇÝÀáÓÜÆá E±ÜÁãàXÓÜáÊÜ ÓÝ«Ü®ÜÊÜ®Üá° ÖæÓÜÄÔ.

4. ¨ÜívÜPÝíñÜ¨Ü ŸÚ ñÜí¨Ü ©PÜãÕb¿áá HPæ ËaÜÆ®æ Öæãí¨Üáñܤ¨æ

5. Jí¨Üá ÊÜáívÜƨÜÈÉ ÖÜÄ¿áᣤÃÜáÊÜ Ë¨ÜáÂñ…±ÜÅÊÝÖÜÊÜ®Üá° ñæãàÄÓÜᣤÃÜáÊÜ bñÜÅ¨Ü »ÝWÜÊæäí¨Ü®Üá°
¯àvÜÇÝX¨æ.

Jí¨Üá ÊæàÙæ I 1 > I 2, I 4 > I 3, I 2 = 2I 4 B¨ÜÃæ ¿ÞÊÜ Ãæãà«ÜPÜ¨Ü Ãæãà«ÜÊÜâ ÖæaÝcX¨æ

III. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ 2×2=4

6. PæÙÜWæ PæãqrÃÜáÊÜ ¨ÜívÜPÝíñÜ¨Ü bñÜÅÊÜ®Üá° WÜÊÜá¯Ô A ÊÜáñÜᤠB ¹í¨ÜáWÜÙÜÈÉ ¿ÞÊÜ ¹í¨ÜáË®ÜÈÉ
PÝíñÜûæàñÜÅ¨Ü ±ÜÅÊÜÞ|ÊÜâ PÜwÊæá CÃÜáñܤ¨æ PÝÃÜ| £ÚÔ.

7. hèÇ…®Ü EÐæã¡àñݳ¨Ü®Ý ¯¿áÊÜáÊÜ®Üá° ¯ÃÜã²Ô. D ¯¿áÊÜá¨Ü WÜ~£à¿á ÃÜã±ÜÊÜ®Üá° ŸÃæÀáÄ.

A¥ÜÊÝ

KÊÜå…®Ü ¯¿áÊÜáÊÜ®Üá° ¯ÃÜã²Ô. 1 KÊÜå… A®Üá° ÊÝÂTݯÔ.

MID/T-25-26/10

3 83-K
IV. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ 3×3=9

8. ÓÜÃÜ~PÜÅÊÜá¨ÜÈÉ hæãàwÔÃÜáÊÜ R 1, R 2 ÊÜáñÜᤠR 3 Ãæãà«ÜPÜWÜÙÜá, ¸ÝÂoÄ, ÔÌa… ÖÝWÜã ÊÜáívÜƨÜÈÉ®Ü
Joár Ãæãà«Ü¨Ü Ë»ÜÊÝíñÜÃÜ ÊÜáñÜᤠ˨ÜáÂñ…±ÜÅÊÝÖÜÊÜ®Üá° AÙæ¿áÆá E±ÜÁãàXÓÜáÊÜ E±ÜPÜÃÜ|WÜÙÜ®Üá°
JÙÜWæãíwÃÜáÊÜ Ë¨ÜáÂñ…ÊÜáívÜÆ¨Ü ÃæàTÝbñÜÅÊÜ®Üá° ŸÃæÀáÄ.

9. ŸÆWæç Öæ¸æºÃÜÙÜ ¯¿áÊÜáÊÜ®Üá° ¯ÃÜã²Ô. PÝí£à¿á ŸÆÃæàTæWÜÙÜ ®ÝÆáR WÜá|ÆûÜ|WÜÙÜ®Üá° ŸÃæÀáÄ.

A¥ÜÊÝ

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˨Üá¨ÝÊæàÍÜWÜÙÜ ±ÜÅÊÜÞ|ÊÜ®Üá° PÜívÜá×wÀáÄ.

b) 1 PÜãÆÊÜå… BÊæàÍÜÊÜ®Üá° Jí¨Üá ¹í¨Üá˯í¨Ü C®æã°í¨Üá ¹í¨ÜáËWæ ñÜÃÜáÊÜÈÉ 2 hèÇ… PæÆÓÜÊÜâ
®Üvæ¨ÜÃæ B GÃÜvÜá ¹í¨ÜáWÜÙÜ ®ÜvÜáÊÜ| Ë»ÜÊÝíñÜÃÜ GÐÜár

A¥ÜÊÝ

a) 9V Ë»ÜÊÝíñÜÃÜ Öæãí©ÃÜáÊÜ GÃÜvÜá ¹í¨ÜáWÜÙÜ ®ÜvÜáÊæ 9C BÊæàÍÜWÜÙÜá aÜÈÔ¨ÝWÜ ®Üvæ¨Ü
PæÆÓÜÊÜ®Üá° PÜívÜá×wÀáÄ.

b) Jí¨Üá ˨ÜáÂñ…ÊÜáívÜƨÜÈÉ 3 PÜãÆÊÜå… BÊæàÍÜWÜÙÜá Jí¨Üá ¹í¨Üá訆 ÊÜáãÆPÜ 3 ÓæPæív…®ÜÈÉ
ÖÜĨÝWÜ ±ÜÅÊÜ×ÓÜáÊÜ Ë¨ÜáÂñ…±ÜÅÊÝÖÜ GÐÜár

V. PæÙÜX®Ü ±ÜÅÍæ°Wæ EñܤÄÔ 1×4=4

11. a) KÊÜÃ…Çæãàv… Gí¨ÜÃæà®Üá WÜêÖÜ Ë¨ÜáÂñ…ÊÜáívÜƨÜÈÉ KÊÜÃ…Çæãàv… EípÝWÜÆá
PÝÃÜ|WÜÙæà®Üá

b) »Üã ÓÜí±ÜPÜì ñÜí£¿á PÝ¿áìÊæà®Üá

VI. PæÙÜX®Ü ±ÜÅÍæ°Wæ EñܤÄÔ 1×5=5

12. a) ˨ÜáÂñ… ÓÝÊÜá¥ÜÂì Gí¨ÜÃæà®Üá ˨ÜáÂñ… ÓÝÊÜá¥ÜÂì¨Ü SI HPÜÊÜÞ®Ü ¿ÞÊÜâ¨Üá ˨ÜáÂñ…
ÓÝÊÜá¥ÜÂìÊÜ®Üá° PÜívÜá×w¿áÆá ŸÙÜÓÜáÊÜ ÊÜáãÃÜá ÓÜãñÜÅWÜÙÜ®Üá° ŸÃæ¿áÄ.

b) ¶ÜäÂÓ…®Ü PÝ¿áìÊæà®Üá PÜÃÜWÜáÊÜ ¹í¨ÜáWÜÚWæ ÓÜíŸí˜Ô¨Üíñæ ŸÇ…ºWÜÙÜÈÉ µÆÊæáíp…WÜÙÝX
ŸÙÜÓÜáÊÜ ñÜí£WÜã ÊÜáñÜᤠ¶ÜäÂÓ…WÜÙÜÈÉ ŸÙÜÓÜáÊÜ ñÜí£WÜã CÃÜáÊÜ ÊÜÂñÝÂÓÜÊæà®Üá

MID/T-25-26/10 [ Turn over

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»ÝWÜ & B
( ÃÜÓÝ¿á®Ü ËþÝ®Ü )
VII. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ A¥ÜÊÝ A±Üä|ì ÖæàÚPæWÜÚWæ ®ÝÆáR ±Ü¿Þì¿á EñܤÃÜWÜÙÜ®Üá° ¯àvÜÇÝX¨æ. AÊÜâWÜÙÜÈÉ
ÓÜãPܤÊÝ¨Ü Jí¨Üá EñܤÃÜÊÜ®Üá° BÄÔ, A¨ÜÃÜ PÜÅÊÜÞûÜÃܨæãvÜ®æ ±Üä|ì EñܤÃÜÊÜ®Üá° ŸÃæÀáÄ 3×1=3

13. PæÙÜX®Ü QÅÁáWÜÙÜÈÉ Pܹº|¨Ü ÊÜÓÜá¤WÜÙÜ ÊæáàÇæ Pæí±Üâ ËáÎÅñÜ PÜí¨Üá Ÿ|¡¨Ü Çæà±Ü®ÜÊÜâ EípÝWÜáÊÜ
QÅÁá¿á®Üá° ÖæãàÆáÊÜ Jí¨Üá ÃÝÓÝ¿á¯PÜ QÅÁá

(A) Pܹº|¨Ü ÊÜÓÜá¤WÜÙÜ ÊæáàÇæ PæãÅàËá¿áí A®Üá° Çæà²ÓÜáÊÜâ¨Üá

(B) EñÜRÐÜìOæÀáí¨Ü ¸æÚÛ ±Ü¨Ý¥ÜìWÜÙÜ ÊæáàÇæ ¸æÚÛ¿á ÓÜÇæ#„v… EpÝWÜáÊÜâ¨Üá

(C) ˨Üá©̻Üg®æÀáí¨Ü Pܹº|¨Ü ÊæãÙæ¿á ÊæáàÇæ ñÝÊÜáÅ¨Ü ±Ü¨ÜÃÜ®Üá° ±Üvæ¿ááÊÜâ¨Üá

(D) ¸æÚÛ¿á PæãÉàÃæçv… Ë»Üg®æÀáí¨Ü Ÿã¨Üá Ÿ|¡¨Ü ¸æÚÛ¿áá EípÝWÜáÊÜâ¨Üá

14. Jí¨Üá ¨ÝÅÊÜ|¨Ü pH ÊÜåèÆÂÊÜâ 7 BX¨æ. D ¨ÝÅÊÜ|¨Ü pH ÊÜåèÆÂÊÜ®Üá° ×àWæ ÖæbcÓÜŸÖÜá¨Üá. D
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(B) 5 WÝÅí ÓÝÊÜޮܠE±Ü³®Üá° ÓæàÄÔ

(C) ÓÜÌƳ ±ÜÅÊÜÞ|¨ÜÈÉ Óæãàw¿áí ÖæçvÝÅPæÕ„v… A®Üá° ÓæàÄÓÜáÊÜâ¨ÜÄí¨Ü

(D) ËñÜÃÜOÝ ®ÜÚPæ ÊÜáãÆPÜ PÝŸì®… væçBPæÕ„v… ÓæàÄÔ

15. ñÜáÄPæ XvÜ¨Ü GÇæWÜÙÜ aÜáaÜácÊÜ PÜã¨ÜÆáWÜÙÜÈÉ CÃÜáÊÜ Jí¨Üá BÊÜáÉ

(A) Êæá¥æ®æãàÀáP… BÊÜáÉ (B) BPÝÕÈP… BÊÜáÉ

(C) ÔqÅP… BÊÜáÉ (D) ÇÝÂQrP… BÊÜáÉ

VIII. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ 3×1=3

16. PÜÊÜáoáËPæ¿á®Üá° ¯¿áí£ÅÓÜÆá ¿ÞÊÜâ¨Ý¨ÜÃÜã GÃÜvÜá Ë«Ý®ÜWÜÙÜ®Üá° ÓÜãbÔ.

17. Óæãàw¿áí ÓÜÇæ#àp… ¨ÝÅÊÜ|ÊÜ®Üá° ¸æàÄ¿áí PæãÉàÃæçv… ¨ÝÅÊÜ|PæR ÓæàÄÔ¨ÝWÜ, Jí¨Üá ¹Ú¿á ±ÜÅûæà±ÜÊÜâ
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18. PæÙÜWæ ÊÜÂPܤ±ÜwÓÜÇÝ¨Ü ±ÜÅÁãàWÜWÜÙÜ®Üá° ËàüÔ. ¹àPÜÃ… A ÊÜáñÜᤠ¹àPÜÃ… B ®ÜÈÉ EípÝWÜáÊÜ ÆÊÜ|WÜÙÜ
ÓÜÌ»ÝÊÜÊÜ®Üá° F×Ô

IX. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ 3×2=6

19. Jí¨Üá ÃÝÓÝ¿á¯PÜ QÅÁá¿áá gÃÜáX¨æ Gí¨Üá ¯«ÜìÄÓÜÆá ÓÜÖÝ¿áPÜÊÝWÜáÊÜ ËàûÜOæWÜÙÜ®Üá° ±Üqr
ÊÜÞw.

20. ¯àÄ®Ü Ë¨Üá©̻Üg®æ¿áÈÉ E±ÜÁãàXÓÜáÊÜ E±ÜPÜÃÜ|¨Ü bñÜÅÊÜ®Üá° ŸÃæÀáÄ ÊÜáñÜᤠPæÙÜX®Ü »ÝWÜWÜÙÜ®Üá°
WÜáÃÜá£Ô

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ii) BQÕg®…

21. ÓÝÃÜÄPܤ ÓÜÆã#éÄP… BÊÜáÉ¨Ü hæãñæ ÓÜñÜá訆 aÜãÃÜáWÜÙÜ ÊÜñÜì®æ¿á®Üá° ñæãàÄÓÜÆá E±ÜÁãàXÓÜáÊÜ
E±ÜPÜÃÜ|WÜÙÜ hæãàvÜOæ¿á bñÜÅÊÜ®Üá° ŸÃæÀáÄ.

X. D PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ 3×3=9

22. PæãqrÃÜáÊÜ ¨ÜñݤíÍÜÊÜ®Üá° K©, ËÍæÉàÑÔ. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ

 PÝÂÈÕ¿áí BPæÕ„v… A®Üá° Öæãí©ÃÜáÊÜ Jí¨Üá ¹àPÜÃ…Wæ ¯àÃÜ®Üá° ÓæàÄÓÜÇÝX¨æ.

 ¶æÃÜÓ… ÓÜÇæ#àp… ÖÜÃÜÙÜáWÜÙÜ®Üá° PÝÔ¨ÝWÜ, D ÖÜÃÜÙÜáWÜÙÜ ÖÜÔÃÜá Ÿ|¡ÊÜâ PÝOæ¿ÞWÜáÊÜâ¨Üá.

i) D QÅÁáWÜÙÜÈÉ Ÿ×ÃÜáÐÜ¡PÜ ÊÜáñÜᤠAíñÜÃÜáÐÜ¡PÜ QÅÁáWÜÙÜ®Üá° WÜáÃÜá£Ô.

ii) ¶æÃÜÓ… ÓÜÇæ³àp…®Ü ÖÜÔÃÜá Ÿ|¡ÊÜâ PÝ~ÓܨÜíñÝWÜÆá PÝÃÜ|Êæà®Üá D QÅÁá¿á Ë«ÜÊÜ®Üá°
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MID/T-25-26/10 [ Turn over

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PæÙÜX®Ü A ÊÜáñÜᤠB ÓÜí¨Ü»ÜìWÜÙÜ®Üá° ËÍæÉàÑÔ PæãqrÃÜáÊÜ ±ÜÅÍæ°WÜÚWæ EñܤÄÔ
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B: ¹Ô¿Þ¨Ü Pܱݳ¨Ü ñÝÊÜáÅ¨Ü ±Üâw¿á ÊæáàÇæ ÖæçvæãÅàg®… A¯ÆÊÜ®Üá° ÖÝÀáÔ¨ÝWÜ
¯àÃÝËÁãí©Wæ ñÝÊÜáÅÊÜâ EípÝWÜáÊÜâ¨Üá.
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ii) CÈÉ ÖæçvæãÅàg®… A®Üá° QÅ¿ÞÎàÆ «ÝñÜáÊæí¨Üá ÖæàWæ ±ÜÄWÜ~ÓÜŸÖÜá¨Üá
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A®ÜáÓÜÄÓÜáÊÜ Jí¨Üá PÜÅÊÜáÊÜ®Üá° £ÚÔ.
XI. PæÙÜX®Ü ±ÜÅÍæ°Wæ EñܤÄÔ 1×4=4

25. a) ÓÝÄàPÜêñÜ ÊÜáñÜᤠÓÝÃÜÄPܤ BÊÜáÉWÜÙÜ ®ÜvÜáÊÜ| ÊÜÂñÝÂÓÜÊæà®Üá Èo¾Ó… PÝWܨÜWÜÙÜ®Üá° ŸÙÜÔ
BÊÜáÉWÜÙÜ®Üá° ÊÜáñÜᤠ±ÜÅñÝÂÊÜáÉWÜÙÜ®Üá° ÖæàWæ ±Üñæ¤ ÖÜaÜácËÄ
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XII. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ A¥ÜÊÝ A±Üä|ì ÖæàÚPæWÜÚWæ ®ÝÆáR ±Ü¿Þì¿á EñܤÃÜWÜÙÜ®Üá° ¯àvÜÇÝX¨æ. AÊÜâWÜÙÜÈÉ
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26. ÓÜÓÜÂWÜÙÜÈÉ PݸæãàìÖæçvæÅàp…WÜÙÜá ÓÜíWÜÅÖÜÊÝXÃÜáÊÜâ¨Üá
(A) WæÉ„Pæãàg®… ÃÜã±Ü¨ÜÈÉ (B) ²ÐÜr¨Ü ÃÜã±Ü¨ÜÈÉ
(C) WÜáÉPæãàÓ… ÃÜã±Ü¨ÜÈÉ (D) ÊÜÞÇæãràÓ… ÃÜã±Ü¨ÜÈÉ

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27. BQÕg®… ÊÜáñÜᤠPÝŸì®… væç BPæÕ„v… A¯ÆWÜÙÜ Ë¯ÊÜá¿áÊÜ®Üá° ¯ÊÜì×ÓÜáÊÜ ÃÜaÜ®æWÜÙÜá

(A) ËÇæÉ„ (B) aÜÊÜáìÃÜí«ÜÅWÜÙÜá

(C) BÈÌÁãàÇæç (D) ®æ¶ÝÅ®…WÜÙÜá

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(A) ˨ÜáÂñ… BÊæàWÜWÜÙÜ®Üá° ÊÜWÝìÀáÓÜáÊÜâ¨Üá

(B) ®ÜÃÜPæãàÍÜWÜÙÜ ÃÜaÜ®æ¿á®Üá° ¯ÊÜì×ÓÜáÊÜâ¨Üá

(C) ®æ®Ü±ÜâWÜÙÜ®Üá° ÓÜíWÜÅ×ÓÜáÊÜâ¨Üá

(D) ®ÜÃÜPæãàÍÜWÜÙÜ ÊÜá«æ ÓÜíÊÜÖÜ®ÜÊÜ®Üá° A®ÜáPÜãÈÓÜáÊÜâ¨Üá

XIII. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ 2×1=2

29. CÊÜá¾w ±ÜÄaÜÆ®æ Gí¨ÜÃæà®Üá

30. ÓܳÍÜìPæR ®ÝbPæ XvÜ¨Ü ÊÜááqr¨ÜÃæ ÊÜáᯠÓÜÓÜ GÇæWÜÙÜá ÊÜáá¨ÜáwPæãÙÜáÛÊÜâ¨Üá Jí¨Üá A®ÜáÊÜñÜì®æ¿áÆÉ.
PÝÃÜ|ÊÜ®Üá° ÓܳÐÜr±ÜwÔ.

XIV. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ 3×2=6

31. PæÙÜX®ÜÊÜâWÜÙÜ®Üá° ÖæÓÜÄÔ

a) ¥æçÃÝQÕ®… ÖÝÊæãàì®…®Ü Eñݳ¨Ü®æWæ AWÜñÜÂÊÝ¨Ü S¯g.

b) C®ÜáÕÈ®… ÖÝÊæãàì®… A®Üá° ÓÜÅËÓÜáÊÜ WÜÅí¦.

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b) ÓÜÓÜ嬆 ¸æàÃÜáWÜÙÜ ÊÜá~¡®Ü PÜvæWæ ¸æÙæ¿ááÊÜ A®ÜáÊÜñÜì®æ.

32. ®æ¶ÝÅ®…®Ü ÃÜaÜ®æ¿á®Üá° ñæãàÄÓÜáÊÜ bñÜÅÊÜ®Üá° ŸÃæÀáÄ ÊÜáñÜᤠWÝÉÊÜáÃÜáÆÓ… »ÝWÜÊÜ®Üá° WÜáÃÜá£Ô.

33. Ëá¨ÜáÚ®Ü BÇæãàaÜ®Ý ±ÜÅQÅÁáXíñÜÆã ±ÜÃÝÊÜ£ìñÜ aÝ±Ü¨Ü PÝ¿áìË«Ý®ÜÊÜâ
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MID/T-25-26/10 [ Turn over

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XV. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ 3×3=9

34. ÊÜÞ®ÜÊÜ®Ü Ëá¨ÜáÚ®Ü dæà¨Ü ®æãào¨Ü ÃÜaÜ®æ¿á®Üá° ñæãàÄÓÜáÊÜ bñÜÅÊÜ®Üá° ŸÃæÀáÄ. PæÙÜX®Ü »ÝWÜWÜÙÜ®Üá°
WÜáÃÜá£Ô

i) ÊÜáÖÝÊÜáÔ¤ÐÜR

ii) ÊæávÜáÇÝÉ

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36. PæÙÜX®Ü ÖæàÚPæWÜÙÜ®Üá° ÓÜÊÜá¦ìÔ

a) ÓÜÓÜÂWÜÙÜÈÉ PæÕ„Æí AíWÝíÍÜ¨Ü PÝ¿áì ÊÜáñÜᤠ¸ÝÐܳËÓÜgì®æ ±ÜÅQÅÁáWÜÙÜá ±ÜÃÜÓܳÃÜ ÓÜíŸí˜ÔÊæ.

b) ®ÜÊÜá¾ ¨æàÖܨÜÈÉ ×àÊæãàWæãÉ๮… ÊÜ|ìPÜWÜÙÜ ±ÜÅÊÜÞ|ÊÜâ Eñܳ£¤¿ÞWÜáÊÜ ÍÜQ¤ ±ÜÅÊÜÞ|ÊÜ®Üá°
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XVI. D PæÙÜX®Ü ±ÜÅÍæ°Wæ EñܤÄÔ 2×4=8

37. a) ÊÜÞ®ÜÊÜ®Ü iàOÝìíWÜÊÜäÂÖܨÜÈÉ gsÜÃÜ ÃÜÓÜ ÊÜáñÜᤠPÜÃÜáÚ®Ü ÃÜÓÜ WÜÙÜ PÝ¿áìÊÜ®Üá° £ÚÔ.

b) ÊÝ¿ááËPÜ EÔÃÝo ÊÜáñÜᤠAÊÝ¿ááËPÜ EÔÃÝoWÜÙÜ ®ÜvÜáÊÜ| ¿ÞÊÜâ¨Ý¨ÜÃÜã GÃÜvÜá
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b) ÊÜÞ®ÜÊÜ®Ü ±ÜĘ ®ÜÃÜÊÜäÂÖÜ¨Ü ZoPÜWÜÙÜ®Üá° ÊÜáñÜᤠ±ÜÅÊÜááS ±ÝñÜÅÊÜ®Üá° £ÚÔ.

MID/T-25-26/10

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