Karnataka SSLC Question Paper 2023 Science

Karnataka Board
Question Paper

SSLC
Question Paper

B∆«M•⁄ O⁄}⁄¬° “
5 RF(A)/100/3330

A

Question Paper Serial No.
Jlflo »⁄flfl¶√}⁄ Æ⁄‚¥lV⁄◊⁄ —⁄MSÊ¿ : 16 ]
Total No. of Printed Pages : 16 ]

Jlflo Æ⁄√ÀÊ-V⁄◊⁄ —⁄MSÊ¿ : 38 ]
Total No. of Questions : 38 ]
CCE RF
UNREVISED
—⁄MOÊfi}⁄ —⁄MSÊ¿ : 83-E

100
FULL SYLLABUS
Code No. : 83-E
…Œ⁄æ⁄fl : …e¤k´⁄

TEAR HERE TO OPEN THE QUESTION PAPER
Subject : SCIENCE
(»èñÜ ËþÝ®Ü, ÃÜÓÝ¿á®Ü ËþÝ®Ü ÊÜáñÜᤠiàÊÜ ËþÝ®Ü / Physics, Chemistry & Biology )

Æ⁄√ÀÊ-Æ⁄~√OÊæ⁄fl´⁄fl-}Ê¡Êæ⁄flƒfl B∆« O⁄}⁄°¬“
( BMW«ŒÈ »⁄·¤®⁄¥¿»⁄fl / English Medium )
( À¤≈¤ @∫⁄¥¿£% / Regular Fresh )

¶´¤MO⁄ : 10. 04. 2023 ] [ Date : 10. 04. 2023
—⁄»⁄flæ⁄fl : ∑Ê◊⁄VÊX 10-30 ¬M•⁄ »⁄fl®¤¿‘⁄-1-45 ¡⁄»⁄¡ÊVÊ ]
[ Time : 10-30 A.M. to 1-45 P.M.
V⁄¬Œ⁄r @MO⁄V⁄◊⁄fl : 80 ] [ Max. Marks : 80
General Instructions to the Candidate :
1. There are three parts in the question paper :
Part A : Physics, Part B : Chemistry, Part C : Biology.
2. This question paper consists of objective and subjective types of
38 questions.
3. This question paper has been sealed by reverse jacket. You have to
cut on the right side to open the paper at the time of commencement
of the examination. Check whether all the pages of the question
paper are intact.
4. Follow the instructions given against both the objective and
subjective types of questions.
5. Figures in the right hand margin indicate maximum marks for the
questions.
6. The maximum time to answer the paper is given at the top of the
Tear here

question paper. It includes 15 minutes for reading the question paper.

[ Turn over

5 RF(A)/100/3330 2 CCE RF 83-E

PART – A

( PHYSICS )

I. Four alternatives are given for each of the following questions /

incomplete statements. Choose the correct alternative and write

the complete answer along with its letter of alphabet. 4×1=4

1. The device used to measure the rate of current in a circuit is

(A) Ammeter (B) Voltmeter

(C) Galvanometer (D) Battery

2. Observe the given figure. Identify the eye defect indicated in this
figure.

(A) Presbyopia (B) Hypermetropia

(C) Myopia (D) Cataract

3. A light ray enters to rarer medium from a denser medium. Then
the speed of that light ray

(A) decreases and bends towards the normal

(B) increases and bends away from the normal

(C) decreases and bends away from the normal

(D) increases and bends towards the normal

5 RF(A)/100/3330 3 CCE RF 83-E

4. The inner wall of the solar cooker is painted black. Because

black colour

(A) reflects light

(B) converges solar rays

(C) prevents from rusting

(D) absorbs more heat

II. Answer the following questions : 2×1=2

5. Write the symbols of the following components used in an

electric circuit.

i) Rheostat

ii) Wires crossing without joining

6. What does the thumb indicate in the right hand thumb rule ?

III. Answer the following questions : 2×2=4

7. Light enters from air to benzene having refractive index 1·50.

Calculate the speed of light in benzene.

( Speed of light in air : 3 × 10 8 ms − 1 )

OR

A concave lens has focal length of 12 cm. At what distance

should the object from the lens be placed so that it forms an

image at 9 cm from the lens ?

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5 RF(A)/100/3330 4 CCE RF 83-E

8. Name the major constituent of biogas and write the properties of

biogas.

OR

List the hazards of nuclear power generation.

IV. Answer the following questions : 3×3=9

9. State Ohm’s law. On which factors does the resistance of a

conductor depend ? Mention the SI unit of electric power.

OR

State Joule’s law of heating. How is fuse connected in the

circuits ? Name the metal used in the filament and the gas filled

in electric bulb.

10. The resistors R 1 , R 2 and R 3 have the values 10 Ω, 20 Ω and

60 Ω respectively, which have been parallelly connected to a

battery of 24 V in an electric circuit. Then calculate the

following :

i) The current flowing through each resistor

ii) The total current in the circuit

iii) The total resistance of the circuit.

5 RF(A)/100/3330 5 CCE RF 83-E

11. Draw the ray diagram for the image formation in a convex lens

when the object is placed beyond 2 F 1 . Mention the position and

nature of the image formed.

[ F 1 : Principal focus of the lens ]

V. Answer the following question : 1×4=4

12. a) What is solenoid ? Write the properties of the magnetic

field lines formed around a current carrying solenoid.

b) What is alternating current ? Electric appliances having

metallic body are connected to earth wire, why ?

VI. Answer the following question : 1×5=5

13. a) How does rainbow form in the nature ? Explain. Mention

the colour of the light that bends the most and that bends

the least.

b) How does the eye lens accommodate to see the distant

objects and nearby objects ? Explain.

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5 RF(A)/100/3330 6 CCE RF 83-E

PART – B

( CHEMISTRY )

VII. Four alternatives are given for each of the following questions /

incomplete statements. Choose the correct alternative and write

the complete answer along with its letter of alphabet. 2×1=2

14. The reactants that exchange ions by reacting with each other

and form a precipitate among the following are

(A) BaCl 2 and Na 2 SO 4

(B) Al 2 O 3 and HCl

(C) NaOH and H 2 SO 4

(D) Na 2 O and CO 2

15. Among 2
X 4 , 8Y 16 , 10 Z 20 the elements having zero valency

are

[ 2, 8, 10 are atomic numbers of elements ]

(A) 2
X 4 and 8Y 16

(B) 8
Y 16 and 10 Z 20

(C) 2
X 4 and 10 Z 20

(D) 2
X 4 , 8Y 16 and 10 Z 20

5 RF(A)/100/3330 7 CCE RF 83-E

VIII. Answer the following questions : 4×1=4

16. The general formula of cycloalkanes is Cn H2n and its first
member is cyclopropane ( C3H6 ). Write the molecular formula

and structural arrangement of the fourth member of this
homologous series.

17. Packets of chips are flushed with nitrogen gas. Why ?

18. An iron nail is dropped into a test tube having copper sulphate
solution. The iron nail gradually turns to brownish colour.
Why ?

19. What is hydrogenation ?

IX. Answer the following questions : 3×2=6

20. Draw the diagram of arrangement of apparatus to show that

acid solution in water conducts electricity and label dilute HCl
solution.

21. “Calcium oxide and carbon dioxide are produced on heating

calcium carbonate.” Write the balanced chemical equation for
this reaction. Mention the type of this chemical reaction.

22. Draw the diagram of arrangement of apparatus to show the

action of steam on a metal.

X. Answer the following questions : 3×3=9

23. a) Depict the formation of magnesium chloride with the help

of electron dot structure.

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5 RF(A)/100/3330 8 CCE RF 83-E

b) Hydrogen gas is not liberated when a metal like zinc reacts

with nitric acid. Why ?

OR

How are metals in the middle of the reactivity series extracted

from their ores ? Explain.

24. a) Observe the given part of the modern periodic table and

answer the following questions :

Groups →
1 2 13 17
Periods ↓

2 — Be — —

3 Na Mg Al Cl

4 — Ca — —

i) Which element is more electropositive ? Why ?

ii) Atoms of which element have minimum atomic

radius ? Why ?

b) Mention the period and group number of the element that

has atomic number 19.

5 RF(A)/100/3330 9 CCE RF 83-E

25. Name the salts used in the following situations and write their

molecular formula :

a) To remove permanent hardness of water.

b) To make drinking water free from germs.

c) To support fractured bones in their right position.

OR

a) The pH values of four solutions are given in the below

table. Classify these into acidic and basic solutions :

Solution pH Value

e 5

f 13

g 9

h 2

b) Name the antacid used to neutralise excess of acid in the

stomach.

XI. Answer the following question : 1×4=4

26. a) How will ethanol be oxidised ?

b) Explain the cleaning action of soaps.

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5 RF(A)/100/3330 10 CCE RF 83-E

PART – C

( BIOLOGY )

XII. Four alternatives are given for each of the following questions /

incomplete statements. Choose the correct alternative and write

the complete answer along with its letter of alphabet. 2×1=2

27. “A person immediately starts running soon after observing a

snake.” The correct transmission path of reflex impulse in this

situation is

(A) Receptor → Sensory neuron → Brain → Relay neuron →

Motor neuron → Effector

(B) Receptor → Sensory neuron → Spinal cord → Relay

neuron → Motor neuron → Effector

(C) Effector → Spinal cord → Sensory neuron → Relay

neuron → Motor neuron → Receptor

(D) Effector → Motor neuron → Relay neuron → Brain →

Sensory neuron → Receptor

5 RF(A)/100/3330 11 CCE RF 83-E

28. In humans, the testes are located outside the lower abdomen in

the scrotum because

(A) to protect testes from mechanical shocks

(B) to increase the production of sperms

(C) to maintain the secretion of testosterone hormone

(D) to maintain the temperature required for sperm

production.

XIII. Answer the following questions : 2×1=2

29. What is the role of abscisic acid in plants ?

30. Write two examples for the organisms that reproduce by binary

fission.

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5 RF(A)/100/3330 12 CCE RF 83-E

XIV. Answer the following questions : 3×2=6

31. Mention the tools used for tracing the evolutionary relationships

between the organisms.

32. Observe the given below figures :

Fig. (i) Fig. (ii)

a) Which figure indicates the massive amount of exchange of

gases ? Why ?

b) Name the parts X and Y. What is the function of the

part X ?

33. Give an example for a food chain of grassland ecosystem. If there

is an increase in the number of organisms in the second trophic

level, how does this affect on that food chain ?

5 RF(A)/100/3330 13 CCE RF 83-E

XV. Answer the following questions : 3×3=9

34. What is pollination ? What are the changes that occur in the

flower after pollination ?

35. Coal and petroleum products should be used judiciously. Why ?

36. Tall pea plant producing red flowers ( TT RR ) is crossed with

short pea plant producing white flowers ( tt rr ).

i) Mention the type of plants produced from these plants in

the F 1 generation.

ii) Write the ratio of plants obtained in the F 2 generation by

crossing the plants of F 1 generation and name the

varieties of plants obtained.

OR

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5 RF(A)/100/3330 14 CCE RF 83-E

Analyse the situations given below. Answer the questions

given :

Situation 1 : The number of green grasshoppers in a green zone

has been increasing from one generation to another

generation.

Situation 2 : The number of brown grasshoppers in the same

green zone has been reducing.

Here,

a) Where could genetic drift be happened more ? Why ?

b) How can natural selection be considered as an important

factor in organic evolution ?

XVI. Answer the following questions : 2×4=8

37. Draw the diagram showing the structure of human brain. Label

the following parts :

i) Hypothalamus

ii) Pons.

5 RF(A)/100/3330 15 CCE RF 83-E

38. Explain the digestion of food materials in stomach and small

intestine.

OR

Explain the role of xylem and phloem tissues in the

transportation of materials in plants.

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5 RF(A)/100/3330 16 CCE RF 83-E

5
A
RF(A)/100/3329

Question Paper Serial No.
Joár ÊÜáá©ÅñÜ ±ÜâoWÜÙÜ ÓÜíTæ : 16 ]
Total No. of Printed Pages : 16 ]

CÈÉí¨Ü PÜñܤÄÔ
Joár ±ÜÅÍæ°WÜÙÜ ÓÜíTæ : 38 ] CCE RF
Total No. of Questions : 38 ]
UNREVISED
ÓÜíPæàñÜ ÓÜíTæ : 83-K FULL SYLLABUS

100
Code No. : 83-K
ËÐÜ¿á : ËþÝ®Ü
Subject : SCIENCE
(»èñÜ ËþÝ®Ü, ÃÜÓÝ¿á®Ü ËþÝ®Ü ÊÜáñÜᤠiàÊÜ ËþÝ®Ü / Physics, Chemistry & Biology)

TEAR HERE TO OPEN THE QUESTION PAPER
(PܮܰvÜ ÊÜÞ«ÜÂÊÜá / Kannada Medium)
(ÍÝÇÝ A»Ü¦ì / Regular Fresh)

±ÜÅÍ氱ܣÅPæ¿á®Üá° ñæÃæ¿áÆá CÈÉ PÜñܤÄÔ
©®ÝíPÜ : 10. 04. 2023 ] [ Date : 10. 04. 2023
ÓÜÊÜá¿á : ¸æÙÜWæY 10-30 Äí¨Ü ÊÜá«ÝÂÖÜ° 1-45 ÃÜÊÜÃæWæ ] [ Time : 10-30 A.M. to 1-45 P.M.
WÜÄÐÜu AíPÜWÜÙÜá : 80 ] [ Max. Marks : 80
±ÜÄàûݦìWÝX ÓÝÊÜޮܠÓÜãaÜ®æWÜÙÜá :
1. D ±ÜÅÍ氱ܣÅPæ¿áÈÉ »ÝWÜ&A : »èñÜ ËþÝ®Ü, »ÝWÜ&B : ÃÜÓÝ¿á®Ü ËþÝ®Ü,
»ÝWÜ&C : iàÊÜ ËþÝ®Ü GíŸ ÊÜáãÃÜá »ÝWÜWÜÚÊæ.
2. D ±ÜÅÍ氱ܣÅPæ¿áá ÊÜÓÜ᤯ÐÜu ÊÜáñÜᤠËÐÜ¿á¯ÐÜu ÊÜÞ¨ÜÄ¿á Joár 38 ±ÜÅÍæ°WÜÙÜ®Üá°
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Tear here

6.
¯WÜ©±ÜwÓÜÇÝ¨Ü ÓÜÊÜá¿áÊÜ®Üá° ±ÜÅÍ氱ܣÅPæ¿á ÊæáàÇݽWܨÜÈÉ ¯àvÜÇÝX¨æ.

3 [ Turn over

5 RF(A)/100/3329 2 CCE RF 83-K

»ÝWÜ & A
( »èñÜ ËþÝ®Ü )
I. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ A¥ÜÊÝ A±Üä|ì ÖæàÚPæWÜÚWæ ®ÝÆáR ±Ü¿Þì¿á EñܤÃÜWÜÙÜ®Üá°
¯àvÜÇÝX¨æ. AÊÜâWÜÙÜÈÉ ÓÜãPܤÊÝ¨Ü Jí¨Üá EñܤÃÜÊÜ®Üá° BÄÔ, A¨ÜÃÜ PÜÅÊÜÞûÜÃܨæãvÜ®æ
±Üä|ì EñܤÃÜÊÜ®Üá° ŸÃæÀáÄ : 4×1=4

1. ÊÜáívÜƨÜÈÉ®Ü Ë¨ÜáÂñ…±ÜÅÊÝÖÜ¨Ü ¨ÜÃÜÊÜ®Üá° AÙæ¿áÆá ŸÙÜÓÜáÊÜ ÓÝ«Ü®Ü

(A) BËá¾àoÃ…

(B) ÊæäàÇ…rËáàoÃ…

(C) WÝÂÆÌ®æãàËáàoÃ…

(D) ¸ÝÂoÄ

2. PæãqrÃÜáÊÜ bñÜÅÊÜ®Üá° WÜÊÜá¯Ô D bñÜÅÊÜâ ÓÜãbÓÜáÊÜ ¨ÜêÑr¨æãàÐÜÊÜ®Üá° WÜáÃÜá£Ô

(A) ²ÅÓ…ŸÁãಿá

(B) ¨ÜãÃܨÜêÑr (Öæç±ÜÃ… ÊæápæãÅಿá)

(C) ÓÜËáà±Ü¨ÜêÑr (ÊÜáÁãಿá)

(D) PÜ~¡®Ü ±æäÃæ

3

5 RF(A)/100/3329 3 CCE RF 83-K
3. ¸æÙÜQ®Ü QÃÜ|ÊÜâ ËÃÜÙÜ ÊÜÞ«ÜÂÊÜáPæR ÓÝí¨ÜÅ ÊÜÞ«ÜÂÊÜá©í¨Ü ±ÜÅÊæàÎÔ¨æ. BWÜ B
¸æÙÜQ®Ü QÃÜ|¨Ü ÊæàWÜÊÜâ

(A) PÜwÊæá¿ÞWÜáñܤ¨æ ÖÝWÜã ÆíŸ¨Ü PÜvæWæ ¸ÝWÜáñܤ¨æ

(B) ÖæaÝcWÜáñܤ¨æ ÖÝWÜã Æퟩí¨Ü ¨ÜãÃÜPæR ¸ÝWÜáñܤ¨æ

(C) PÜwÊæá¿ÞWÜáñܤ¨æ ÖÝWÜã Æퟩí¨Ü ¨ÜãÃÜPæR ¸ÝWÜáñܤ¨æ

(D) ÖæaÝcWÜáñܤ¨æ ÖÝWÜã ÆíŸ¨Ü PÜvæWæ ¸ÝWÜáñܤ¨æ

4. ÓèÃÜPÜáPÜRÃ…®Ü JÙÜ»ÝWÜPæR PܱÜâ³ Ÿ|¡ÊÜ®Üá° ŸÚ©ÃÜáñݤÃæ. HPæí¨ÜÃæ PܱÜâ³ Ÿ|¡ÊÜâ

(A) ¸æÙÜPÜ®Üá° ±ÜÅ£¶ÜÈÓÜáñܤ¨æ

(B) ÓèÃÜQÃÜ|WÜÙÜ®Üá° Pæàí©ÅàPÜÄÓÜáñܤ¨æ

(C) ñÜáPÜáR ×w¿ááÊÜâ¨Ü®Üá° ñÜvæWÜoárñܤ¨æ

(D) ÖæaÜác ÍÝSÊÜ®Üá° ×àÄPæãÙÜáÛñܤ¨æ

II. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ : 2×1=2

5. Jí¨Üá ˨ÜáÂñ… ÊÜáívÜƨÜÈÉ E±ÜÁãàXÓÜáÊÜ PæÙÜX®Ü ZoPÜWÜÙÜ bÖæ°WÜÙÜ®Üá° ŸÃæÀáÄ.

i) ÄÁãàÓÝrp…

ii) Óæà±ÜìvæÀáÆÉ¨æ ¨Ýq¨Ü ñÜí£WÜÙÜá

6. ŸÆWæç Öæ¸æºÃÜÙÜ ¯¿áÊÜá¨ÜÈÉ Öæ¸æºÃÜÙÜá H®Ü®Üá° ÓÜãbÓÜáñܤ¨æ ?

3 [ Turn over

5 RF(A)/100/3329 4 CCE RF 83-K
III. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ : 2×2=4

7. ¸æÙÜPÜá WÝÚÀáí¨Ü 1·50 ÊÜQÅà»ÜÊÜ®Ü ÓÜãaÜÂíPÜÊÜ®Üá° Öæãí©ÃÜáÊÜ ¸æíià®…®Ü®Üá°
±ÜÅÊæàÎÓÜᣤ¨æ. ¸æíià®…®ÜÈÉ ¸æÙÜQ®Ü ÊæàWÜÊÜ®Üá° ÇæPÜRaÝÃÜ ÊÜÞw.

(WÝÚ¿áÈÉ ¸æÙÜQ®Ü ÊæàWÜ : 3 × 10 8 ms − 1 )

A¥ÜÊÝ

Jí¨Üá ¯ÊÜá° ÊÜáÓÜãÃÜ¨Ü ÓÜíWÜÊÜá¨ÜãÃÜÊÜâ 12 cm C¨æ. ÊÜáÓÜãÃÜ©í¨Ü ±ÜÅ£¹íŸÊÜâ
9 cm ¨ÜãÃܨÜÈÉ EípÝWÜÆá ÊÜÓÜá¤ÊÜ®Üá° ÊÜáÓÜãÃÜ©í¨Ü GÐÜár ¨ÜãÃܨÜÈÉ
CvܸæàPÜá ?

8. hæçËPÜ A¯Æ¨Ü ±ÜÅ«Ý®Ü ZoPÜÊÜ®Üá° ÖæÓÜÄÔ ÊÜáñÜᤠhæçËPÜ A¯Æ¨Ü WÜá|ÆûÜ|WÜÙÜ®Üá°
ŸÃæÀáÄ.

A¥ÜÊÝ

±ÜÃÜÊÜÞ|á ˨ÜáÂñ… Eñݳ¨Ü®æ¿á A±Ý¿áWÜÙÜ®Üá° ±ÜqrÊÜÞw.

IV. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ : 3×3=9

9. KÊÜå…®Ü ¯¿áÊÜáÊÜ®Üá° ¯ÃÜã²Ô. Jí¨Üá ÊÝÖÜPÜ¨Ü Ãæãà«ÜÊÜâ ¿ÞÊÜ AíÍÜWÜÙÜ ÊæáàÇæ
AÊÜÆí¹ñÜÊÝX¨æ ? ˨ÜáÂñ… ÓÝÊÜá¥ÜÂì¨Ü SI HPÜÊÜÞ®Ü £ÚÔ.

A¥ÜÊÝ

3

5 RF(A)/100/3329 5 CCE RF 83-K
hèÇ…®Ü EÐæã¡àñݳ¨Ü®Ý ¯¿áÊÜáÊÜ®Üá° ¯ÃÜã²Ô. ¶ÜäÂÓ…®Üᰠ˨ÜáÂñ…

ÊÜáívÜÆWÜÙÜÈÉ ÖæàWæ hæãàwÔÃÜáñݤÃæ ? ˨ÜáÂñ… ŸÇ…º®Ü ñÜíñÜáWÜÙÜÈÉ ŸÙÜÓÜáÊÜ

ÇæãàÖÜ ÊÜáñÜᤠA¨ÜÃÜÈÉ ñÜáíŸáÊÜ A¯ÆÊÜ®Üá° ÖæÓÜÄÔ.

10. Ãæãà«ÜPÜWÜÙÝ¨Ü R 1 , R 2 ÊÜáñÜᤠR 3 WÜÙÜ ¸æÇæWÜÙÜá PÜÅÊÜáÊÝX 10 Ω, 20 Ω ÊÜáñÜá¤

60 Ω WÜÙÝX¨Ü᪠AÊÜâWÜÙÜ®Üá° 24 V Ë»ÜÊÝíñÜÃÜËÃÜáÊÜ Jí¨Üá ¸ÝÂoÄWæ

ÓÜÊÜÞíñÜÃÜÊÝX ˨ÜáÂñ…ÊÜáívÜƨÜÈÉ hæãàwÔ¨æ. ÖÝWݨÜÃæ PæÙÜX®ÜÊÜâWÜÙÜ®Üá°

ÇæPÝRaÝÃÜ ÊÜÞw.

i) ±ÜÅ£Áãí¨Üá Ãæãà«ÜPÜ¨Ü ÊÜáãÆPÜ ±ÜÅÊÜ×ÓÜᣤÃÜáÊÜ Ë¨ÜáÂñ…±ÜÅÊÝÖÜ

ii) ÊÜáívÜƨÜÈÉÃÜáÊÜ Joár ˨ÜáÂñ…±ÜÅÊÝÖÜ

iii) ÊÜáívÜÆ¨Ü Joár Ãæãà«Ü

11. Jí¨Üá ÊÜÓÜá¤ÊÜ®Üá° ²à®ÜÊÜáÓÜãÃÜ¨Ü 2 F 1 XíñÜ ¨ÜãÃܨÜÈÉ CpÝrWÜ EípÝWÜáÊÜ

±ÜÅ£¹íŸ EípÝWÜáËPæ¿á ÃæàTÝbñÜÅÊÜ®Üá° ŸÃæÀáÄ. EípÝ¨Ü ±ÜÅ£¹íŸ¨Ü

Óݧ®Ü ÊÜáñÜᤠÓÜÌ»ÝÊÜWÜÙÜ®Üá° £ÚÔ.

[ F 1 : ÊÜáÓÜãÃÜ¨Ü ±ÜÅ«Ý®Ü ÓÜíWÜÊÜá ]

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V. PæÙÜX®Ü ±ÜÅÍæ°Wæ EñܤÄÔ : 1×4=4

12. a) ÓæãÇæ®Ý¿å…x Gí¨ÜÃæà®Üá ? ˨ÜáÂñ…±ÜÅÊÜ×ÓÜᣤÃÜáÊÜ ÓæãÇæ®Ý¿å…x®Ü ÓÜáñܤÆã

EípÝWÜáÊÜ PÝí£à¿á ŸÆÃæàTæWÜÙÜ WÜá|ÆûÜ|WÜÙÜ®Üá° ŸÃæÀáÄ.

b) ±Ü¿Þì¿á ˨ÜáÂñ…±ÜÅÊÝÖÜ Gí¨ÜÃæà®Üá ? ÇæãàÖÜ¨Ü ÊæáàÇ澄 Öæãí©ÃÜáÊÜ

˨ÜáÂñ… E±ÜPÜÃÜ|WÜÙÜ®Üá° »ÜãÓÜí±ÜPÜì ñÜí£Wæ hæãàwÓÜÇÝWÜáñܤ¨æ. HPæ ?

VI. PæÙÜX®Ü ±ÜÅÍæ°Wæ EñܤÄÔ : 1×5=5

13. a) ¯ÓÜWÜì¨ÜÈÉ PÝÊÜá®Ü¹ÆáÉ ÖæàWæ EípÝWÜáñܤ¨æ ? ËÊÜÄÔ. A£ ÖæaÜác

¸ÝWÜáÊÜ ÊÜáñÜᤠA£ PÜwÊæá ¸ÝWÜáÊÜ ¸æÙÜQ®Ü Ÿ|¡ÊÜ®Üá° £ÚÔ.

b) ¨ÜãÃÜ¨Ü ÊÜáñÜᤠÖÜ£¤ÃÜ¨Ü ÊÜÓÜá¤WÜÙÜ®Üá° ®æãàvÜÆá PÜ~¡®Ü ÊÜáÓÜãÃÜÊÜâ ÖæàWæ

Öæãí¨Ý~Pæ ÊÜÞwPæãÙÜáÛñܤ¨æ ? ËÊÜÄÔ.

3

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»ÝWÜ & B
( ÃÜÓÝ¿á®Ü ËþÝ®Ü )
VII. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ A¥ÜÊÝ A±Üä|ì ÖæàÚPæWÜÚWæ ®ÝÆáR ±Ü¿Þì¿á EñܤÃÜWÜÙÜ®Üá°
¯àvÜÇÝX¨æ. AÊÜâWÜÙÜÈÉ ÓÜãPܤÊÝ¨Ü Jí¨Üá EñܤÃÜÊÜ®Üá° BÄÔ, A¨ÜÃÜ PÜÅÊÜÞûÜÃܨæãvÜ®æ
±Üä|ì EñܤÃÜÊÜ®Üá° ŸÃæÀáÄ : 2×1=2

14. PæÙÜX®ÜÊÜâWÜÙÜÈÉ ±ÜÃÜÓܳÃÜ ÊÜ£ìÔ A¿Þ®…WÜÙÜ®Üᰠ˯ÊÜá¿á ÊÜÞwPæãÙÜáÛÊÜ
±ÜÅ£ÊÜñÜìPÜWÜÙÜá

(A) BaCl 2 ÊÜáñÜᤠNa 2 SO 4

(B) Al 2 O 3 ÊÜáñÜᤠHCl

(C) NaOH ÊÜáñÜᤠH 2 SO 4

(D) Na 2 O ÊÜáñÜᤠCO 2

4
15. 2X
, 8 Y16 , 10 Z 20 CÊÜâWÜÙÜÈÉ ; Óæã®æ° ÊæàÇæ¯Õ¿á®Üá° Öæãí©ÃÜáÊÜ «ÝñÜáWÜÙÜá

(2, 8, 10 CÊÜâWÜÙÜá «ÝñÜáWÜÙÜ ±ÜÃÜÊÜÞ|á ÓÜíTæÂWÜÙÝXÊæ)
4
(A) 2X
ÊÜáñÜᤠ8 Y16

16
(B) 8Y
ÊÜáñÜᤠ10 Z 20

4
(C) 2X
ÊÜáñÜᤠ10 Z 20

4
(D) 2X
, 8 Y16 ÊÜáñÜᤠ10 Z 20

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VIII. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ : 4×1=4

16. ÓæçPæãÉàBÇæRà®…WÜÙÜ ÓÝÊÜޮܠÓÜãñÜÅÊÜâ C nH 2n ÊÜáñÜᤠC¨ÜÃÜ Êæã¨ÜÆ ÓܨÜÓÜÂ
ÓæçPæãÉà±æäÅà±æà®… ( C3H6 ) BX¨æ. D A®ÜáÃÜã±Ü ÍæÅà~¿áÈÉÃÜáÊÜ ®ÝÆR®æà
ÓܨÜÓÜ娆 A|áÓÜãñÜÅ ÊÜáñÜᤠÃÜaÜ®Ý Ë®ÝÂÓÜÊÜ®Üá° ŸÃæÀáÄ.

17. b±…Õ ±æäor|WÜÙÜÈÉ ®æçpæãÅàg®… A¯ÆÊÜ®Üá° ÖÝÀáÓÜáñݤÃæ. HPæ ?

18. ñÝÊÜáÅ¨Ü ÓÜÇæ#àp… ¨ÝÅÊÜ|ÊÜ®Üá° Öæãí©ÃÜáÊÜ Jí¨Üá ±ÜÅ®ÝÙÜPæR Pܹº|¨Ü
ÊæãÙæÁãí¨Ü®Üá° ÖÝPÜÇÝX¨æ. Pܹº|¨Ü ÊæãÙæ¿áá PÜÅÊæáà|ÊÝX PÜí¨Üá Ÿ|¡PæR
£ÃÜáWÜáñܤ¨æ. HPæ ?

19. ÖæçvæãÅàg¯àPÜÃÜ| Gí¨ÜÃæà®Üá ?

IX. D PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ : 3×2=6

20. ¯àÄ®ÜÈÉ BËáÉà¿á ¨ÝÅÊÜ|ÊÜâ ˨ÜáÂñ…±ÜÅÊÜ×ÓÜáÊÜâ¨Ü®Üá° ñæãàÄÓÜáÊÜ E±ÜPÜÃÜ|WÜÙÜ
hæãàvÜOæ¿á bñÜÅÊÜ®Üá° ŸÃæ¨Üá, ÓÝÃÜÄPܤ HCl ¨ÝÅÊÜ|ÊÜ®Üá° WÜáÃÜá£Ô.

21. ""PÝÂÈÕ¿áí Pݸæãàì®æàp…A®Üá° PÝÔ¨ÝWÜ PÝÂÈÕ¿áí BPæÕ„v… ÊÜáñÜá¤
PÝŸì®…væçBPæÕ„v… Eñܳ£¤¿ÞWÜáñܤ¨æ.'' D QÅÁáWæ ÓÜĨÜãXst ÃÝÓÝ¿á¯PÜ
ÓÜËáàPÜÃÜ|ÊÜ®Üá° ŸÃæÀáÄ. D ÃÝÓÝ¿á¯PÜ QÅÁá¿á Ë«ÜÊÜ®Üá° £ÚÔ.

22. ÇæãàÖÜ¨Ü ÊæáàÇæ Öܸæ¿á ÊÜñÜì®æ¿á®Üá° ñæãàÄÓÜáÊÜ E±ÜPÜÃÜ|WÜÙÜ hæãàvÜOæ¿á
bñÜÅÊÜ®Üá° ŸÃæÀáÄ.

3

5 RF(A)/100/3329 9 CCE RF 83-K
X. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ : 3×3=9

23. a) CÇæPÝó®… aÜáQR Ë®ÝÂÓÜ¨Ü ÓÜÖÝ¿á©í¨Ü ÊæáX°àÑ¿áí PæãÉàÃæçv…
EípÝWÜáËPæ¿á®Üá° ÊÜÂPܤ±ÜwÔ.

b) ÓÜñÜáË®ÜíñÜÖÜ ÇæãàÖÜÊÜâ ®æçqÅP… BÊÜáɨæãí©Wæ ÊÜ£ìÔ¨ÝWÜ ÖæçvæãÅàg®…
A¯ÆÊÜâ ¹vÜáWÜvæ¿ÞWÜáÊÜâ©ÆÉ. HPæ ?

A¥ÜÊÝ

QÅ¿ÞÎàÆñæ¿á ÓÜÃÜ~¿áÈÉ®Ü ÊÜá«Ü嬆 CÃÜáÊÜ ÇæãàÖÜWÜÙÜ®Üá° AÊÜâWÜÙÜ
A¨ÜáÃÜáWÜÚí¨Ü ÖæàWæ E¨ÜœÄÓÜáñݤÃæ ? ËÊÜÄÔ.

24. a) PæãqrÃÜáÊÜ B«Üá¯PÜ BÊÜñÜìPÜ PæãàÐÜrPÜ¨Ü »ÝWÜÊÜ®Üá° WÜÊÜá¯Ô ÊÜáñÜᤠPæÙÜX®Ü
±ÜÅÍæ°WÜÚWæ EñܤÄÔ :

i) ¿ÞÊÜ «ÝñÜáÊÜâ ÖæaÜác ˨Üá¨ܜ¯à¿áÊÝX¨æ ? HPæ ?

ii) ¿ÞÊÜ «ÝñÜá訆 ±ÜÃÜÊÜÞ|áWÜÙÜá PܯÐÜu ±ÜÃÜÊÜÞ|á £ÅgÂÊÜ®Üá°
Öæãí©Êæ ? HPæ ?

b) ±ÜÃÜÊÜÞ|á ÓÜíTæ 19 A®Üá° Öæãí©ÃÜáÊÜ «ÝñÜá訆 BÊÜñÜì ÊÜáñÜᤠWÜáí²®Ü
ÓÜíTæ¿á®Üá° £ÚÔ.

3 [ Turn over

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25. PæÙÜX®Ü ÓÜí¨Ü»ÜìWÜÙÜÈÉ ŸÙÜÓÜáÊÜ ÆÊÜ|WÜÙÜ®Üá° ÖæÓÜÄÔ ÊÜáñÜᤠAÊÜâWÜÙÜ A|áÓÜãñÜÅÊÜ®Üá°
ŸÃæÀáÄ :

a) ¯àÄ®Ü ÍÝÍÜÌñÜ WÜvÜÓÜáñÜ®ÜÊÜ®Üá° ¯ÊÝÄÓÜÆá

b) PÜáw¿ááÊÜ ¯àÃÜ®Üá° QÅËáÊÜááPܤWæãÚÓÜÆá

c) ÊÜááÄ¨Ü ÊÜáãÙæWÜÚWæ ÓÜÄ¿Þ¨Ü ÓܧÙܨÜÈÉ B«ÝÃÜ ¯àvÜÆá

A¥ÜÊÝ

a) PæÙÜX®Ü PæãàÐÜrPܨÜÈÉ ®ÝÆáR ¨ÝÅÊÜ|WÜÙÜ pH ÊÜåèÆÂWÜÙÜ®Üá° Pæãqr¨æ.
CÊÜâWÜÙÜ®Üá° BËáÉà¿á ÊÜáñÜᤠ±ÜÅñÝÂËáÉà¿á ¨ÝÅÊÜ|WÜÙܮݰX ËíWÜwÔ :

¨ÝÅÊÜ| pH ÊÜåèÆÂ

e 5

f 13

g 9

h 2

b) gsÜÃܨÜÈÉ®Ü ÖæaÜácÊÜÄ BÊÜáÉÊÜ®Üá° ñÜoÓܧWæãÚÓÜÆá ŸÙÜÓÜáÊÜ BÊÜáÉÍÝÊÜáPÜÊÜ®Üá°
ÖæÓÜÄÔ.

XI. D PæÙÜX®Ü ±ÜÅÍæ°Wæ EñܤÄÔ : 1×4=4

26. a) G¥Ü®ÝÇ…A®Üá° ÖæàWæ EñÜRÑìÓÜÇÝWÜáñܤ¨æ ?

b) ÓÝŸã®ÜáWÜÙÜá ÓÜÌaÜfWæãÚÓÜáÊÜ ±ÜÅQÅÁá¿á®Üá° ËÊÜÄÔ.

3

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»ÝWÜ & C
( iàÊÜ ËþÝ®Ü )
XII. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ A¥ÜÊÝ A±Üä|ì ÖæàÚPæWÜÚWæ ®ÝÆáR ±Ü¿Þì¿á EñܤÃÜWÜÙÜ®Üá°
¯àvÜÇÝX¨æ. AÊÜâWÜÙÜÈÉ ÓÜãPܤÊÝ¨Ü Jí¨Üá EñܤÃÜÊÜ®Üá° BÄÔ, A¨ÜÃÜ PÜÅÊÜÞûÜÃܨæãvÜ®æ
±Üä|ì EñܤÃÜÊÜ®Üá° ŸÃæÀáÄ : 2×1=2

27. ""JŸº ÊÜÂQ¤¿áá ÖÝÊÜ®Üá° ®æãàw¨Ü PÜãvÜÇæà KvÜÆá ±ÝÅÃÜí¼ÓÜáñݤ®æ.'' D
ÓÜí¨Ü»Üì¨ÜÈÉ ±ÜÃÝÊÜ£ìñÜ BÊæàWÜÊÜâ ÓÝWÜáÊÜ ÓÜÄ¿Þ¨Ü ±Ü¥Ü

(A) WÝÅÖÜPÜ → þÝ®ÜÊÝ× ®ÜÃÜPæãàÍÜ → Ëá¨ÜáÙÜá → ÓÜíŸí«Ü PÜȳÓÜáÊÜ

®ÜÃÜPæãàÍÜ → QÅ¿ÞÊÝ× ®ÜÃÜPæãàÍÜ → PÝ¿áì ¯ÊÝìÖÜPÜ

(B) WÝÅÖÜPÜ → þÝ®ÜÊÝ× ®ÜÃÜPæãàÍÜ → Ëá¨ÜáÙÜá ŸÚÛ → ÓÜíŸí«Ü PÜȳÓÜáÊÜ

®ÜÃÜPæãàÍÜ → QÅ¿ÞÊÝ× ®ÜÃÜPæãàÍÜ → PÝ¿áì ¯ÊÝìÖÜPÜ

(C) PÝ¿áì ¯ÊÝìÖÜPÜ → Ëá¨ÜáÙÜá ŸÚÛ → þÝ®ÜÊÝ× ®ÜÃÜPæãàÍÜ → ÓÜíŸí«Ü

PÜȳÓÜáÊÜ ®ÜÃÜPæãàÍÜ → QÅ¿ÞÊÝ× ®ÜÃÜPæãàÍÜ → WÝÅÖÜPÜ

(D) PÝ¿áì ¯ÊÝìÖÜPÜ → QÅ¿ÞÊÝ× ®ÜÃÜPæãàÍÜ → ÓÜíŸí«Ü PÜȳÓÜáÊÜ

®ÜÃÜPæãàÍÜ → Ëá¨ÜáÙÜá → þÝ®ÜÊÝ× ®ÜÃÜPæãàÍÜ → WÝÅÖÜPÜ

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28. ÊÜÞ®ÜÊÜÃÜÈÉ, ÊÜêÐÜ|WÜÙÜá Q¸æãºpær¿á ÖæãÃÜWæ ÊÜêÐÜ|bàƨÜÈÉÃÜáñܤÊæ, HPæí¨ÜÃæ

(A) ÊÜêÐÜ|WÜÙÜ®Üá° ¿Þí£ÅPÜ B[ÝñÜWÜÚí¨Ü ÃÜüÓÜÆá

(B) Ëà¿Þì|áWÜÙÜ Eñݳ¨Ü®æ¿á®Üá° ÖæbcÓÜÆá

(C) pæÓæãràÔràÃÝ®… ÖÝÊæãàì®…®Ü ÓÜÅËPæ¿á®Üá° ¯ÊÜì×ÓÜÆá

(D) Ëà¿Þì|áWÜÙÜ Eñݳ¨Ü®æWæ AWÜñÜÂËÃÜáÊÜ EÐÜ¡ñæ¿á®Üá° ¯ÊÜì×ÓÜÆá

XIII. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ : 2×1=2

29. ÓÜÓÜÂWÜÙÜÈÉ B¹ÕÔP… BÊÜáÉ¨Ü ±ÝñÜÅÊæà®Üá ?

30. ©Ì˨ÜÙܮܩí¨Ü ÓÜíñÝ®æãàñܳ£¤ ÊÜÞvÜáÊÜ iàËWÜÚWæ GÃÜvÜá E¨ÝÖÜÃÜOæWÜÙÜ®Üá°

ŸÃæÀáÄ.

XIV. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ : 3×2=6

31. iàËWÜÙÜ ®ÜvÜáÊæ iàÊÜËPÝÔà¿á ÓÜíŸí«ÜWÜÙÜ®Üá° ±Üñæ¤ ÊÜÞvÜÆá ŸÙÜÓÜáÊÜ
ÓÝ«Ü®ÜWÜÙÜ®Üá° £ÚÔ.

3

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32. PæÙÜWæ PæãqrÃÜáÊÜ bñÜÅWÜÙÜ®Üá° WÜÊÜá¯Ô :

bñÜÅ (i) bñÜÅ (ii)

a) ¿ÞÊÜ bñÜÅÊÜâ A◊PÜ ±ÜÅÊÜÞ|¨ÜÈÉ A¯ÆWÜÙÜ Ë¯ÊÜá¿áÊÝWÜáÊÜâ¨Ü®Üá°

ÓÜãbÓÜáñܤ¨æ ? HPæ ?

b) X ÊÜáñÜᤠY »ÝWÜWÜÙÜ®Üá° ÖæÓÜÄÔ ÊÜáñÜᤠX »ÝWÜ¨Ü PÝ¿áìÊæà®Üá ?

33. ÖÜáÆáÉWÝÊÜÆá ±ÜÄÓÜÃÜ ÊÜÂÊÜÓ槿áÈÉ®Ü BÖÝÃÜ ÓÜÃܱÜÚWæ Jí¨Üá E¨ÝÖÜÃÜOæ¿á®Üá°

Pæãw. GÃÜvÜ®æà ±æäàÐÜOÝÓܤÃܨÜÈÉÃÜáÊÜ iàËWÜÙÜ ÓÜíTæ¿áá ÖæaÝc¨ÜÃæ C¨Üá B

BÖÝÃÜ ÓÜÃܱÜÚ¿á ÊæáàÇæ ÖæàWæ ±ÜÄOÝÊÜáÊÜ®Üá° ¹àÃÜáñܤ¨æ ?

XV. PæÙÜX®Ü ±ÜÅÍæ°WÜÚWæ EñܤÄÔ : 3×3=9

34. ±ÜÃÝWÜÓܳÍÜì Gí¨ÜÃæà®Üá ? ±ÜÃÝWÜÓܳÍÜì¨Ü ®ÜíñÜÃÜ ÖÜãË®ÜÈÉ EípÝWÜáÊÜ
Ÿ¨ÜÇÝÊÜOæWÜÙÜá ¿ÞÊÜâÊÜâ ?

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35. PÜÈɨܪÆá ÊÜáñÜᤠ±æpæãÅàÈ¿áí Eñܳ®Ü°WÜÙÜ®Üá° ËÊæàaÜ®æÀáí¨Ü ŸÙÜÓܸæàPÜá. HPæ ?

36. Pæí±Üâ ÖÜã ¹vÜáÊÜ GñܤÃÜ¨Ü ŸpÝ~ ÓÜÓÜ ( TT RR ) ÊÜ®Üá° ¹Ú ÖÜã ¹vÜáÊÜ
XvÜx®æ¿á ŸpÝ~ ÓÜÓÜ ( tt rr ) ¨æãí©Wæ ÓÜíPÜÃÜWæãÚÔ¨æ. CÊÜâWÜÚí¨Ü

i) F 1 ²àÚWæ¿áÈÉ ±Üvæ¿ááÊÜ ÓÜÓÜÂWÜÙÜ Ë«ÜWÜÙÜ®Üá° £ÚÔ.

ii) F1 ²àÚWæ¿áÈÉ ±Üvæ¨Ü ÓÜÓÜÂWÜÙÜ®Üá° ÓÜíPÜÃÜWæãÚÔ¨ÝWÜ F 2 ²àÚWæ¿áÈÉ
¨æãÃæ¿ááÊÜ ÓÜÓÜÂWÜÙÜ A®Üá±ÝñÜÊÜ®Üá° ŸÃæÀáÄ ÊÜáñÜᤠÓÜÓÜÂWÜÙÜ Ë«ÜWÜÙÜ®Üá°
ÖæÓÜÄÔ.

A¥ÜÊÝ

PæÙÜWæ PæãqrÃÜáÊÜ Óܯ°ÊæàÍÜWÜÙÜ®Üá° ËÍæÉàÑÔ. ¯àwÃÜáÊÜ ±ÜÅÍæ°WÜÚWæ EñܤÄÔ :

Óܯ°ÊæàÍÜ (1) : Jí¨Üá ÖÜÔÃÜá ÊÜÆ¿á¨ÜÈÉÃÜáÊÜ ÖÜÔÃÜá ËávÜñæWÜÙÜ ÓÜíTæ¿áá
Jí¨Üá ²àÚWæÀáí¨Ü ÊÜáñæã¤í¨Üá ²àÚWæWæ ÖæaÝcWÜᣤ¨æ.

Óܯ°ÊæàÍÜ (2) : A¨æà ÖÜÔÃÜáÊÜÆ¿á¨ÜÈÉÃÜáÊÜ PÜí¨Üá ËávÜñæWÜÙÜ ÓÜíTæ¿áá
üà~ÓÜᣤ¨æ.

CÈÉ,

a) B®ÜáÊÜíÎà¿á ©PÜác飿áá ÖæaÝcX GÈÉ ÓÜí»ÜËÓÜŸÖÜá¨ÝX¨æ ? HPæ ?

b) iàÊÜËPÝÓܨÜÈÉ ®æçÓÜXìPÜ BÁáR¿áá Jí¨Üá ±ÜÅÊÜááS AíÍÜÊÝX¨æ Gí¨Üá
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