HBSE Class 11 Sample Paper 2024 Biology

HBSE
MODEL PAPER
2024
Practice Papers
MODEL PAPERS
Marking Scheme
ANSWER KEY

Class 11th

Subject- Biology

Maximum marks 70 Time allowed 3hrs

General instructions

All questions are compulsory

The question paper has five sections and 35 questions .

All questions are compulsory

Section A has 18 questions of one mark each

Section B has 7 questions of 2 marks each

Section C has 5 questions of 3 marks each

Section D has two case study based questions of 4 marks

Section E has three questions of 5 marks each

There is no over all choice however internal choice have been provided in some
questions student has to attempt only one of the alternative questions

Wherever necessary draw properly labelled diagrams

Section A

1 Solanum , Petunia and Datura are placed in the family:

a) Solanaceae

b)Fabaceae

1

c)Liliaceae

d)Cruciferae

2. The order of Homo sapien is

a) Carnivora

b)Diptera

c) Poales

d)Primata

3 .The five kingdom classification was given in the year

a)1979

b)1971

c)1969

d)1970

4. The first colonizers on rocks are

a) Mosses

b)Lichens

c) both a&b

d) Sphagnum

5). Water vascular system is the characteristic of

a) Echinoderms

b)Porifers

c)Mollusca

2

d)Coelentrata

6. Nereis is :

(a) Aquatic

(b) Monoecious

c) Dioecious

d) both a&c 1

7. Alternate type of Phyllotaxy where a single leave arise at each node in alternate
manner is found in

a) China rose plant

b) Mustard plant

c) Sunflower plant

d) all the above

8) The living component in xylem tissue is

a) Trachieds

b) Vessels

c) Fibres

d) Parenchyma

9) Stele includes

a) Pericycle

b) Vascular bundle

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c) Pith

d) All of the above

10. Inclusion is a unique feature of :

(a) Bacteria

(b) Virus

c) PPLO

(d) All of the above

11. Endomembrane system includes

a) lysosomes

b) Mitochondria

c) Chloroplast

d) Ribosomes

12.Protein is a

a)Homopolymer

b) Hetero polymer

c) Mixed polymer

d) both a and b

13 Rhizopus belongs to

a) Phycomycetes

b)Zygomycetes

c) Deutromycetes

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d) Ascomycetes

14 Equisetum is :

a)Bryophyte

b) Pteridophyte

c)Angiosperm

d)Gymnosperm

Assertion reason type questions

These questions consists of two statements each printed as assertion and reason
while answering these questions you are required to choose any one of the
following four responses

A. If both assertion and reason are true and reason is correct explanation of
assertion

B. If both assertion and reason are true but reason is not correct explaination of
assertion

C if assertion is true but reason is false

D both assertion and reason are false

15 Assertion: Glycolysis takes place in cytoplasm and produce only 2ATPand
2NADH

Reason: Glycolysis is anaerobic process and cannot oxidize the substrate fully

16 Assertion: Hemoglobin is an oxygen career

Reason: oxygen binds as O2 to Fe of hemoglobin

5

17Assertion: RBC production is regulated by kidney

Reason: erythropoietin reaches red bone marrow

18Assertion: tubular secretion is important in marine fishes and desert
amphibians

Reason: in marine fishes and desert amphibians nephrons are a glomerular

Section -B

19 Describe the different modes of respiration in frog.

OR

Make labelled diagram of urinogenital system of frog 2

20 Why abscisic acid is called stress hormone? 2

21 Distinguish between vital capacity and total lung capacity 2

22 Compare resting potential and action potential 2

23 Pallavi has cut a transverse section of young stem of a plant from her school
and observed it under microscope.How she can ascertain whether it is
monocotstem or dicot stem

OR

Write features of any two types of simple tissues. 2

24. How fungi reproduce sexually,Explain it 2

6

25. Mention the ploidy of the following : Protonemal cell of a moss, ,leaf cell of
a moss, Prothallus cell of a fern, Gemma cell in Marchantia.

Section-C

26 Write the unique features of Arthropods . 3

27 How infloresence is different from flower ?Write difference between
racemose and cymose infloresence?

Or

Explain hypogynous,epigynous and perigynous types of flowers 3

28 Graphically show the effect of change PH,Temperature and concentration on
activity of enzyme. 3

29 . With the help of diagram describe structure of skeletal muscle 3

30 List the hormones released by Pancreas,Thyroid,Ovary 3

OR

Diagrammatically represent the mechanism of action of the mechanism of
steroid hormone.

SECTION D

The following questions are case based questions.Read the cases carefully and
answer the questions that follow

31 Cells that have membrane bound nuclei are called eukaryotic whereas cells
that lack a membrane bound nucleus are prokaryotic. In both prokaryotic and
eukaryotic cells, a semi-fluid matrix called cytoplasm occupies the volume of the
cell. The cytoplasm is the main arena of cellular activities in both the plant and
animal cells. Various chemical reactions occur in it to keep the cell in the „living
state‟. Besides the nucleus, the eukaryotic cells have other membrane bound
distinct structures called organelles like the endoplasmic reticulum (ER), the golgi

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complex, lysosomes, mitochondria, microbodies and vacuoles. The prokaryotic
cells lack such membrane bound organelles.

1. Write two differences between prokaryotic and eukaryotic cells. 1

2. Mention the location for various metabolic activities. 1

3.(a) State whether bacterial cell is prokaryotic or eukaryotic justify

OR

(b) Name four membrane bound organelles 2

32 "The TCA cycle starts with the condensation of acetyl group with oxaloacetic
acid (OAA) and water to yield citric acid.Before participating in the TCA cycle
pyruvic acid enters the mitochondrion. Here it is decarboxylated and the
remaining 2-carbon fragment is combined with a molecule of coenzyme A to form
acetyl-CoA. This reaction is an oxidative decarboxylation process and produces H+
ions and electrons along with carbon dioxide. The reaction is catalysed by the
enzyme citrate synthase and a molecule of CoA is released. Citrate is then
isomerised to isocitrate. It is followed by two successive steps of decarboxylation,
leading to the formation of α-ketoglutaric acidand then succinyl-CoA. In the
remaining steps of citric acid cycle, succinyl-CoA is oxidised to OAA allowing the
cycle to continue. During the conversion of succinyl-CoA to succinic acid a
molecule of GTP is synthesised. This is a substrate level phosphorylation. In a
coupled reaction GTP is converted to GDP with the simultaneous synthesis of ATP
from ADP. Also there are three points in the cycle where NAD+ is reduced to
NADH + H+ and one point where FAD+ is reduced to FADH2. The continued
oxidation of acetyl CoA via the TCA cycle requires the continued replenishment of
oxaloacetic acid, the first member of the cycle. In addition it also requires
regeneration of NAD+ and FAD+ from NADH and FADH2 respectively.

1.What is oxidative decarboxylation give example 1

2.How many any NADH2 and FADH2 formed in this cycle 1

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3.How many carbons are there in Pyruvic acid and OAA

OR

Name any two types of reaction occurring in the above process 2

SECTION E

33 What is light reaction explain the different modes of light reaction in plants

OR

Write five differences between C3 and C4 plants. 5

34 . With the help of labelled diagram of human explain the cardiac cycle

OR

Explain special connective tissue consisting of fluid Matrix, plasma and formed
elements 5

35List five differences between mitosis and meiosis 5

OR

Explain the process of prophase 1 in meiosis 1 with special reference to
crossing over

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Q EXPECTED ANSWERS/ VALUE POINTS MARKS
N
O
SECTION – A
1 (a) Solanaceae 1
2 (d) All the above 1
3 (c) 1969 1
4 (b)lichens 1
5 (a) Echinoderms 1
6 (d)Aquatic and dioecious 1
7 (d) All the above 1
8 (d) Parenchyma 1
9 (d) All the above 1
10 (d) All the above 1
11 (a)Lysosomes 1
12 (b) Heteropolymer 1
13
14
15 A 1
16 C 1
17 A 1
18 A 1
17 SECTION B 1 +1
Cutaneous respiration in water
Pulmonary respiration on land
18 Inhibits plant growth,inhibitor of plant metabolism,inhibits 1+1
8 seed germination,stimulates stomata closure,increases
tolerance of of plants to various kinds of stresses(ANY TWO
CAN BE CONSISDERED)
19 Vital Capacity=ERV+TV+IRV 1+1
Total lung capacity=RV+Vital capacity
20 Resting Potential=Potential difference across the resting 1+1
membrane

10

Action Potential =Potential difference across the membrane
on generation of impulse
21 By observing the vascular bundles 1+1\2+1\2=
Scattered in monocot stem 2
Arranged in ring in dicot stem
OR
Parenchyma:thin walled isodiametric,closely packed or very
less intercellular space,Collenchyma or Sclerenchyma with
features

22 SECTION C 1+1+1=3
Plasmogamy
Karyogamy
Meiosis in zygote
23 Protonemal cell of moss: n,PEN :3n,leaf of moss : n,prothallus
of fern :n,gemma cell of marcantia :n,meristem cell of monocot
:2n

24 Chitinous exoskeleton,variety of respiratory organs and variety 1+1+1=3
in excretory organs
25 Inflorescence is group of flowers like sunflower,marigold 1+2=3
Racemose inflorescence : Unlimited growth of shoot
apex,acropetal arrangement of flowers
Cymose inflorescence :Shoot tip terminates into flower,limited

growth of shoot apex,basipetal arrangement of flowers
26 1+1+1=3

Figure 9.7 from NCERT Book

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27 Fig 20.2 (a) 1
Fig 20.2 (b) 2

12

28 Pancreas :insulin,glucagaon 1+1+1=3
Thyriod:T3,T4
Ovary:estrogen,progesterone
OR
Figure 22.5 (b)
29 Any two difference between prokaryotic and eukaryotic cell 1
Cytoplasm 1
Prokaryotic cell and any one feature of prokaryotic cell 2
OR
Nucleus,ER,Lysosomes,Vacoule etc

30 Removal of carbon along with oxidation i.e formation of acetyl 1
coenzyme A from pyruvic acid
3 NADH2and 1FADH2 1
(a) 3 and 4 carbon atoms respectively 2

13

Or
(b) Decarboxylation,Regeneration,isomerisation 2
31 Light dependent synthesis of ATP and NADPH 1
Cyclic and acyclic photophosphorylation 1 2+2

1+1+1+1+1
=5

2

2
OR
Any five differences between C3 and C4 Plants

14

32

4 steps of
one mark
each and
one mark
for
diagramma
Cardiac cycle consists of
tic
Joint diastole of atria and ventricles
representat
Atrial systole
ion
Ventricular systole with atrial diastole
Ventricular diastole
Total time of cycle is 0.8
OR
OR
1+1+3
Plasma:90-92 water and protein
RBC:Without nucleus,avwrage life span 120
days
WBC:Granulocytes and Agranulocyte (with
details)
33 Mitosis :Occurs in somatic cells,daughter cells are identical,no 1+1+1+1+1
crossing over,short process from oneparent cell two daughter =5
cells are produced
Meiosis :occur in germinal cells,variation in daughter
cells,crossing over is there ,long process, from one daughter
ceii four daughter cells are produced
OR
Leptotene
Zygotene
pachytene
Deplotene
diakinesis

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