NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers
Download the NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers PDF for free at AglaSem. Get accurate, step-by-step solutions to every question so you can check your answers, learn the correct method and see how to score full marks.
More Detail
Latest News
Finished viewing? Save it for later —
Download NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers (PDF · 10 pages)Downloaded 73 times
About NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers
NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers is available here for free download. Published by NCERT for Class 6, this solution can be viewed online or downloaded as a PDF (10 pages). Candidates preparing for Class 6 can use NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers to understand the exam pattern, the type of questions asked, and the overall difficulty level.
Frequently Asked Questions
How can I download NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers?
Open this page and click the Download button to save NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers as a PDF. It is completely free on AglaSem Docs.
Is NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers free to download?
Yes. NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers can be viewed online and downloaded as a PDF free of cost on AglaSem Docs.
How many pages does NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers have?
NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers contains 10 pages, which you can read online or download together as a single PDF.
Where can I find more Class 6 study material?
You can find more Class 6 question papers, sample papers, syllabus, and answer keys on AglaSem Docs.
NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers – Text
Read the full text of this solution below — useful to quickly search, copy and reference the content online without downloading the PDF.
📄 View text version (10 pages)
Page 1
NCERT
SOLUTIONS
CLASS - 6TH
aglase .co
SOLUTIONS
CLASS - 6TH
aglase .co
Page 2
Book: Mathematics NCERT Solutions | Chapter - 2 Maths
Class : 6th
Subject : Maths
Chapter : 2
Chapter Name : WHOLE NUMBERS
Exercise 2.1
Q1 Write the next three natural numbers after 10999.
Answer. Next three natural numbers after 10999 are 11000, 11001,11002.
Page : 31 , Block Name : Exercise 2.1
Q2 Write the three whole numbers occurring just before 10001.
Answer. 3 whole numbers just before 10001 are 10000, 9999, 9998.
Page : 31 , Block Name : Exercise 2.1
Q3 Which is the smallest whole number?
Answer. The smallest whole number is 0.
Page : 31 , Block Name : Exercise 2.1
Q4 How many whole numbers are there between 32 and 53?
Answer. Whole numbers between 32 and 53 = 20 (53 - 32 - 1 = 20)
(33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52)
Page : 31 , Block Name : Exercise 2.1
Q5 Write the successor of :
(a) 2440701
(b) 100199
(c) 1099999
Page 1 of 9 Aglasem Schools
Class : 6th
Subject : Maths
Chapter : 2
Chapter Name : WHOLE NUMBERS
Exercise 2.1
Q1 Write the next three natural numbers after 10999.
Answer. Next three natural numbers after 10999 are 11000, 11001,11002.
Page : 31 , Block Name : Exercise 2.1
Q2 Write the three whole numbers occurring just before 10001.
Answer. 3 whole numbers just before 10001 are 10000, 9999, 9998.
Page : 31 , Block Name : Exercise 2.1
Q3 Which is the smallest whole number?
Answer. The smallest whole number is 0.
Page : 31 , Block Name : Exercise 2.1
Q4 How many whole numbers are there between 32 and 53?
Answer. Whole numbers between 32 and 53 = 20 (53 - 32 - 1 = 20)
(33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52)
Page : 31 , Block Name : Exercise 2.1
Q5 Write the successor of :
(a) 2440701
(b) 100199
(c) 1099999
Page 1 of 9 Aglasem Schools
Page 3
Book: Mathematics NCERT Solutions | Chapter - 2 Maths
(d) 2345670
Answer. (a) 2440701 + 1 = 2440702
(b) 100199 + 1 = 100200
(c) 1099999 + 1 = 1100000
(d) 2345670 + 1 = 2345671
Page : 31 , Block Name : Exercise 2.1
Q6 Write the predecessor of :
(a) 94
(b) 10000
(c) 208090
(d) 7654321
Answer. (a) 94 - 1 = 93
(b) 10000 - 1 = 9999
(c) 208090 - 1-208089
(d) 7654321 - 1 = 7654320
Page : 31 , Block Name : Exercise 2.1
Q7 In each of the following pairs of numbers, state which whole number is on the left of
the other number on the number line. Also write them with the appropriate sign (>, <)
between them.
(a) 530, 503
(b) 370, 307
(c) 98765, 56789
(d) 9830415, 10023001
Answer. (a) 530, 503
As 530 > 503,
503 is on the left side of 530 on the number line.
(b) 370, 307
As 370 > 307,
307 is on the left side of 370 on the number line.
(c) 98765, 56789
As 98765 > 56789,
56789 is on the left side of 98765 on the number line.
Page 2 of 9 Aglasem Schools
(d) 2345670
Answer. (a) 2440701 + 1 = 2440702
(b) 100199 + 1 = 100200
(c) 1099999 + 1 = 1100000
(d) 2345670 + 1 = 2345671
Page : 31 , Block Name : Exercise 2.1
Q6 Write the predecessor of :
(a) 94
(b) 10000
(c) 208090
(d) 7654321
Answer. (a) 94 - 1 = 93
(b) 10000 - 1 = 9999
(c) 208090 - 1-208089
(d) 7654321 - 1 = 7654320
Page : 31 , Block Name : Exercise 2.1
Q7 In each of the following pairs of numbers, state which whole number is on the left of
the other number on the number line. Also write them with the appropriate sign (>, <)
between them.
(a) 530, 503
(b) 370, 307
(c) 98765, 56789
(d) 9830415, 10023001
Answer. (a) 530, 503
As 530 > 503,
503 is on the left side of 530 on the number line.
(b) 370, 307
As 370 > 307,
307 is on the left side of 370 on the number line.
(c) 98765, 56789
As 98765 > 56789,
56789 is on the left side of 98765 on the number line.
Page 2 of 9 Aglasem Schools
Page 4
Book: Mathematics NCERT Solutions | Chapter - 2 Maths
(d) 9830415, 10023001
Since 98, 30, 415 (<) 1, 00, 23, 001, 98, 30, 415 is on the left side of 1,00,23,001 on the
number line.
Page : 31 , Block Name : Exercise 2.1
Q8 Which of the following statements are true (T) and which are false (F) ?
(a) Zero is the smallest natural number.
(b) 400 is the predecessor
(c) Zero is the smallest whole number.
(d) 600 is the successor of 599.
(e) All natural numbers are whole numbers.
(f ) All whole numbers are natural numbers.
(g) The predecessor of a two digit number is never a single digit number.
(h) 1 is the smallest whole number.
(i) The natural number 1 has no predecessor.
(j) The whole number 1 has no predecessor.
(k) The whole number 13 lies between 11 and 12.
(l) The whole number 0 has no predecessor.
(m) The successor of a two digit number is always a two digit number.
Answer. (a) False, 0 is not a natural number.
(b) False, as predecessor of 399 is 398 (399 - 1 = 398).
(c) True
(d) True, as 599 + 1 = 600
(e) True
(f) False, as 0 is a whole number but it is not a natural number.
(g) False, as predecessor of 10 is g.
(h) False, 0 is the smallest whole number.
(i) True, as O is the predecessor of 1 but it is not a natural number.
(j) False, as 0 is the predecessor of 1 and it is a whole number.
(k) False, 13 does not lie in between 11 and 12.
(l) True, predecessor of O is —1, which is not a whole number.
(m) False, as successor of 99 is 100.
Page : 31 , Block Name : Exercise 2.1
Exercise 2.2
Page 3 of 9 Aglasem Schools
(d) 9830415, 10023001
Since 98, 30, 415 (<) 1, 00, 23, 001, 98, 30, 415 is on the left side of 1,00,23,001 on the
number line.
Page : 31 , Block Name : Exercise 2.1
Q8 Which of the following statements are true (T) and which are false (F) ?
(a) Zero is the smallest natural number.
(b) 400 is the predecessor
(c) Zero is the smallest whole number.
(d) 600 is the successor of 599.
(e) All natural numbers are whole numbers.
(f ) All whole numbers are natural numbers.
(g) The predecessor of a two digit number is never a single digit number.
(h) 1 is the smallest whole number.
(i) The natural number 1 has no predecessor.
(j) The whole number 1 has no predecessor.
(k) The whole number 13 lies between 11 and 12.
(l) The whole number 0 has no predecessor.
(m) The successor of a two digit number is always a two digit number.
Answer. (a) False, 0 is not a natural number.
(b) False, as predecessor of 399 is 398 (399 - 1 = 398).
(c) True
(d) True, as 599 + 1 = 600
(e) True
(f) False, as 0 is a whole number but it is not a natural number.
(g) False, as predecessor of 10 is g.
(h) False, 0 is the smallest whole number.
(i) True, as O is the predecessor of 1 but it is not a natural number.
(j) False, as 0 is the predecessor of 1 and it is a whole number.
(k) False, 13 does not lie in between 11 and 12.
(l) True, predecessor of O is —1, which is not a whole number.
(m) False, as successor of 99 is 100.
Page : 31 , Block Name : Exercise 2.1
Exercise 2.2
Page 3 of 9 Aglasem Schools
Page 5
Book: Mathematics NCERT Solutions | Chapter - 2 Maths
Q1 Find the sum by suitable rearrangement:
(a) 837 + 208 + 363
(b) 1962 + 453 + 1538 + 647
Answer. (a) 837 + 208 + 363 = (837 + 363) + 208 = 1200 + 208 = 1408
(b) 1962 + 453 + 1538 + 647 = (1962 + 1538) + (453 + 647) = 3500 + 1100 = 4600
Page : 40 , Block Name : Exercise 2.2
Q2 Find the product by suitable rearrangement:
(a) 2 × 1768 × 50
(b) 4 × 166 × 25
(c) 8 × 291 × 125
(d) 625 × 279 × 16
(e) 285 × 5 × 60
(f) 125 × 40 × 8 × 25
Answer. (a) 2 x 1768 x 50 = 2 x 50 x 1768 = 100 x 1768 = 176800
(b) 4 x 166 x 25 = 4 x 25 x 166 = 100 x 166 = 16600
(c) 8 x 291 x 125 = 8 x 125 x 291 = 1000 x 291 = 291000
(d) 625 x 279 x 16 = 625 x 16 x 279 = 10000 x 279 = 2790000
(e) 285 5 = 285 x 300 = 85500
(f) 125 x 40 x 8 x 25 = 125 x 8 40 x 25 = 1000 x 1000 = 1000000
Page : 40 , Block Name : Exercise 2.2
Q3 Find the value of the following:
(a) 297 × 17 + 297 × 3
(b) 54279 × 92 + 8 × 54279
(c) 81265 × 169 – 81265 × 69
(d) 3845 × 5 × 782 + 769 × 25 × 218
Answer. (a) 297 x 17 + 297 x 3 = 297 x (17+3) = 297 x 20 = 5940
(b) 54279 x 92 +8 x 54279 = 54279 x 92 + 54279 x 8
= 54279 x (92 + 8)
= 54279 x 100 = 5427900
(c) 81265 x 169 - 81265 x 69 = 81265 x (169 - 69) = 81265 x 100 = 8126500
Page 4 of 9 Aglasem Schools
Q1 Find the sum by suitable rearrangement:
(a) 837 + 208 + 363
(b) 1962 + 453 + 1538 + 647
Answer. (a) 837 + 208 + 363 = (837 + 363) + 208 = 1200 + 208 = 1408
(b) 1962 + 453 + 1538 + 647 = (1962 + 1538) + (453 + 647) = 3500 + 1100 = 4600
Page : 40 , Block Name : Exercise 2.2
Q2 Find the product by suitable rearrangement:
(a) 2 × 1768 × 50
(b) 4 × 166 × 25
(c) 8 × 291 × 125
(d) 625 × 279 × 16
(e) 285 × 5 × 60
(f) 125 × 40 × 8 × 25
Answer. (a) 2 x 1768 x 50 = 2 x 50 x 1768 = 100 x 1768 = 176800
(b) 4 x 166 x 25 = 4 x 25 x 166 = 100 x 166 = 16600
(c) 8 x 291 x 125 = 8 x 125 x 291 = 1000 x 291 = 291000
(d) 625 x 279 x 16 = 625 x 16 x 279 = 10000 x 279 = 2790000
(e) 285 5 = 285 x 300 = 85500
(f) 125 x 40 x 8 x 25 = 125 x 8 40 x 25 = 1000 x 1000 = 1000000
Page : 40 , Block Name : Exercise 2.2
Q3 Find the value of the following:
(a) 297 × 17 + 297 × 3
(b) 54279 × 92 + 8 × 54279
(c) 81265 × 169 – 81265 × 69
(d) 3845 × 5 × 782 + 769 × 25 × 218
Answer. (a) 297 x 17 + 297 x 3 = 297 x (17+3) = 297 x 20 = 5940
(b) 54279 x 92 +8 x 54279 = 54279 x 92 + 54279 x 8
= 54279 x (92 + 8)
= 54279 x 100 = 5427900
(c) 81265 x 169 - 81265 x 69 = 81265 x (169 - 69) = 81265 x 100 = 8126500
Page 4 of 9 Aglasem Schools
Page 6
Book: Mathematics NCERT Solutions | Chapter - 2 Maths
(d) 3845 x 782 + 769 x 25 x 218
= 3845 x 5 x 782 + 769 x 5 x 5 x 218
= 3845 x 5 x 782 + 3845 x 5 x 218
= 3845 x 5 x (782 + 218)
= 19225 x 1000 = 19225000
Page : 40 , Block Name : Exercise 2.2
Q4 Find the product using suitable properties.
(a) 738 × 103
(b) 854 × 102
(c) 258 × 1008
(d) 1005 × 168
Answer. (a) 738 x 103 = 738 x (100 + 3)
= 738 x 100 + 738 x 3 (Distributive property)
= 73800 + 2214
= 76014
(b) 854 x 102 = 854 x (100+2)
= 854 x 100 + 854 x 2 (Distributive property)
= 85400 + 1708 87108
(c) 258 x 1008 = 258 x (1000 + 8)
= 258 x 1000 + 258 x 8 (Distributive property)
= 258000 + 2064 = 260064
(d) 1005 x 168 = (1000 + 5) x 168
= 1000 x 168 + 5 x 168 (Distributive property)
= 168000 + 840 = 168840
Page : 40 , Block Name : Exercise 2.2
Q5 A taxi driver �lled his car petrol tank with 40 litres of petrol on Monday. The next
day, he �lled the tank with 50 litres of petrol. If the petrol costs 44 per litre, how much
did he spend in all on petrol?
Answer. Quantity of petrol �lled on Monday = 40 l
Quantity of petrol �lled on Tuesday = 50 l
Total quantity �lled = (40 + 50) l
Page 5 of 9 Aglasem Schools
(d) 3845 x 782 + 769 x 25 x 218
= 3845 x 5 x 782 + 769 x 5 x 5 x 218
= 3845 x 5 x 782 + 3845 x 5 x 218
= 3845 x 5 x (782 + 218)
= 19225 x 1000 = 19225000
Page : 40 , Block Name : Exercise 2.2
Q4 Find the product using suitable properties.
(a) 738 × 103
(b) 854 × 102
(c) 258 × 1008
(d) 1005 × 168
Answer. (a) 738 x 103 = 738 x (100 + 3)
= 738 x 100 + 738 x 3 (Distributive property)
= 73800 + 2214
= 76014
(b) 854 x 102 = 854 x (100+2)
= 854 x 100 + 854 x 2 (Distributive property)
= 85400 + 1708 87108
(c) 258 x 1008 = 258 x (1000 + 8)
= 258 x 1000 + 258 x 8 (Distributive property)
= 258000 + 2064 = 260064
(d) 1005 x 168 = (1000 + 5) x 168
= 1000 x 168 + 5 x 168 (Distributive property)
= 168000 + 840 = 168840
Page : 40 , Block Name : Exercise 2.2
Q5 A taxi driver �lled his car petrol tank with 40 litres of petrol on Monday. The next
day, he �lled the tank with 50 litres of petrol. If the petrol costs 44 per litre, how much
did he spend in all on petrol?
Answer. Quantity of petrol �lled on Monday = 40 l
Quantity of petrol �lled on Tuesday = 50 l
Total quantity �lled = (40 + 50) l
Page 5 of 9 Aglasem Schools
Page 7
Book: Mathematics NCERT Solutions | Chapter - 2 Maths
Cost of petrol (per l) = Rs 44
Total money spent = 44 x (40 + 50) = 44 x 90 = Rs 3960
Page : 40 , Block Name : Exercise 2.2
Q6 A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in
the evening. If the milk costs 45 per litre, how much money is due to the vendor per day?
Answer. Quantity of milk supplied in the morning = 32 l
Quantity of milk supplied in the evening = 68 l
Total of milk per litre = (32 + 68) l
Cost of milk per litre = Rs 15
Total cost per day = 15 x (32 + 68)
= 15 x 100 = Rs 1500
Page : 41 , Block Name : Exercise 2.2
Q7 Match the following:
Answer. (i) 425 x 136 = 425 x (6 + 30 + 100) [Distributivity of multiplication over addition]
Hence, (c)
(ii) 2 x 49 x 50 = 2 x 50 x 49 [Commutative under multiplication]
Hence, (a)
(iii) 80 + 2005 + 20 = 80 + 20 + 2005 [Commutative under addition]
Hence, (b)
Page : 41 , Block Name : Exercise 2.2
Exercise 2.3
Q1 Which of the following will not represent zero:
(a) 1 + 0
Page 6 of 9 Aglasem Schools
Cost of petrol (per l) = Rs 44
Total money spent = 44 x (40 + 50) = 44 x 90 = Rs 3960
Page : 40 , Block Name : Exercise 2.2
Q6 A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in
the evening. If the milk costs 45 per litre, how much money is due to the vendor per day?
Answer. Quantity of milk supplied in the morning = 32 l
Quantity of milk supplied in the evening = 68 l
Total of milk per litre = (32 + 68) l
Cost of milk per litre = Rs 15
Total cost per day = 15 x (32 + 68)
= 15 x 100 = Rs 1500
Page : 41 , Block Name : Exercise 2.2
Q7 Match the following:
Answer. (i) 425 x 136 = 425 x (6 + 30 + 100) [Distributivity of multiplication over addition]
Hence, (c)
(ii) 2 x 49 x 50 = 2 x 50 x 49 [Commutative under multiplication]
Hence, (a)
(iii) 80 + 2005 + 20 = 80 + 20 + 2005 [Commutative under addition]
Hence, (b)
Page : 41 , Block Name : Exercise 2.2
Exercise 2.3
Q1 Which of the following will not represent zero:
(a) 1 + 0
Page 6 of 9 Aglasem Schools
Page 8
Book: Mathematics NCERT Solutions | Chapter - 2 Maths
(b) 0 × 0
0
(c) 2
10−10
(d) 2
Answer. (a) 1 + 0
It does not represent zero.
(b) 0 × 0
It represents zero.
0
(c) 2
It represents zero.
10−10
(d) 2
It represents zero.
Page : 43 , Block Name : Exercise 2.3
Q2 If the product of two whole numbers is zero, can we say that one or both of them will
be zero? Justify through examples.
Answer. If the product of 2 whole numbers is zero, then one of them is de�nitely zero.
For example, 0 x 2 = 0 and 17 x 0 = 0
If the product of 2 whole numbers is zero, then both of them may be zero.
0x0=0
However, 2 x 3 = 6
(Since numbers to be multiplied are not equal to zero, the result of the product will
also be non-zero.)
Page : 43 , Block Name : Exercise 2.3
Q3 If the product of two whole numbers is 1, can we say that one or both of them will be
1? Justify through examples.
Answer. If the product of 2 numbers is 1, then both the numbers have to equal to 1.
For example, 1 x 1 = 1
However, 1 x 6 = 6
Clearly, the product of two whole numbers will be 1 in the situation when both
numbers to be multiplied are 1.
Page : 44 , Block Name : Exercise 2.3
Page 7 of 9 Aglasem Schools
(b) 0 × 0
0
(c) 2
10−10
(d) 2
Answer. (a) 1 + 0
It does not represent zero.
(b) 0 × 0
It represents zero.
0
(c) 2
It represents zero.
10−10
(d) 2
It represents zero.
Page : 43 , Block Name : Exercise 2.3
Q2 If the product of two whole numbers is zero, can we say that one or both of them will
be zero? Justify through examples.
Answer. If the product of 2 whole numbers is zero, then one of them is de�nitely zero.
For example, 0 x 2 = 0 and 17 x 0 = 0
If the product of 2 whole numbers is zero, then both of them may be zero.
0x0=0
However, 2 x 3 = 6
(Since numbers to be multiplied are not equal to zero, the result of the product will
also be non-zero.)
Page : 43 , Block Name : Exercise 2.3
Q3 If the product of two whole numbers is 1, can we say that one or both of them will be
1? Justify through examples.
Answer. If the product of 2 numbers is 1, then both the numbers have to equal to 1.
For example, 1 x 1 = 1
However, 1 x 6 = 6
Clearly, the product of two whole numbers will be 1 in the situation when both
numbers to be multiplied are 1.
Page : 44 , Block Name : Exercise 2.3
Page 7 of 9 Aglasem Schools
Page 9
Book: Mathematics NCERT Solutions | Chapter - 2 Maths
Q4 Find using distributive property :
(a) 728 × 101
(b) 5437 × 1001
(c) 824 × 25 (d) 4275 × 125
(e) 504 × 35
Answer. (a) 728 x 101= 728 x (100 + 1)
= 728 x 100 + 728 x 1
= 72800 + 728 = 73528
(b) 5437 x 1001 = 5437 x (1000 + 1)
= 5437 x 1000 + 5437 x 1
= 5437000 + 5437 = 5442437
(c) 824 x 25 (800 + 24) x 25
= (800 + 25 - 1) 25
-800x25+25 x 25-1x25
= 20000 + 625 - 25
= 20000 + 600 = 20600
(d) 4275 x 125 = (4000 + 200 + 100 - 25) x 125
= 4000 x 125 + 200 x 125 + 100 x 125 - 25 x 125
= 500000 + 25000 + 12500 - 3125
= 534375
(e) 504 x 35 = (500 + 4) x 35
= 500 x 35 +4 x 35
= 17500 + 140 = 17640
Page : 44 , Block Name : Exercise 2.3
Q5 Study the pattern :
1 × 8 + 1 = 9 1234 × 8 + 4 = 9876
12 × 8 + 2 = 98 12345 × 8 + 5 = 98765
123 × 8 + 3 = 987
Write the next two steps. Can you say how the pattern works?
(Hint: 12345 = 11111 + 1111 + 111 + 11 + 1).
Answer. 123456 x 8 + 6 = 987648 + 6 = 987654
1234567 x 8 + 7 = 9876536 + 7 = 9876543
Page 8 of 9 Aglasem Schools
Q4 Find using distributive property :
(a) 728 × 101
(b) 5437 × 1001
(c) 824 × 25 (d) 4275 × 125
(e) 504 × 35
Answer. (a) 728 x 101= 728 x (100 + 1)
= 728 x 100 + 728 x 1
= 72800 + 728 = 73528
(b) 5437 x 1001 = 5437 x (1000 + 1)
= 5437 x 1000 + 5437 x 1
= 5437000 + 5437 = 5442437
(c) 824 x 25 (800 + 24) x 25
= (800 + 25 - 1) 25
-800x25+25 x 25-1x25
= 20000 + 625 - 25
= 20000 + 600 = 20600
(d) 4275 x 125 = (4000 + 200 + 100 - 25) x 125
= 4000 x 125 + 200 x 125 + 100 x 125 - 25 x 125
= 500000 + 25000 + 12500 - 3125
= 534375
(e) 504 x 35 = (500 + 4) x 35
= 500 x 35 +4 x 35
= 17500 + 140 = 17640
Page : 44 , Block Name : Exercise 2.3
Q5 Study the pattern :
1 × 8 + 1 = 9 1234 × 8 + 4 = 9876
12 × 8 + 2 = 98 12345 × 8 + 5 = 98765
123 × 8 + 3 = 987
Write the next two steps. Can you say how the pattern works?
(Hint: 12345 = 11111 + 1111 + 111 + 11 + 1).
Answer. 123456 x 8 + 6 = 987648 + 6 = 987654
1234567 x 8 + 7 = 9876536 + 7 = 9876543
Page 8 of 9 Aglasem Schools
Page 10
Book: Mathematics NCERT Solutions | Chapter - 2 Maths
Yes, the pattern works.
As 123456 = 111111 + 11111 + 1111 + 111 + 11 + 1,
123456 x 8 = (111111 + 11111 + 1111 + 111 + 11 + 1) x 8
= 111111 x 8 + 11111 x 8 + 1111 x 8 + 111 x 8 + 11 x 8 + 1 x 8
= 888888 + 88888 + 8888 + 888 + 88 + 8 = 987648
123456 x 8 + 6 = 987648 + 6 = 987648
Page : 44 , Block Name : Exercise 2.3
Page 9 of 9 Aglasem Schools
Yes, the pattern works.
As 123456 = 111111 + 11111 + 1111 + 111 + 11 + 1,
123456 x 8 = (111111 + 11111 + 1111 + 111 + 11 + 1) x 8
= 111111 x 8 + 11111 x 8 + 1111 x 8 + 111 x 8 + 11 x 8 + 1 x 8
= 888888 + 88888 + 8888 + 888 + 88 + 8 = 987648
123456 x 8 + 6 = 987648 + 6 = 987648
Page : 44 , Block Name : Exercise 2.3
Page 9 of 9 Aglasem Schools
Document Details
| Board / Org | NCERT |
| Exam | Class 6 |
| Type | Solution |
| Pages | 10 |
| Updated | 22 Jul 2026 |