NCERT Solutions for Class 6 Maths Chapter 7 Fractions

NCERT
SOLUTIONS
CLASS - 6TH

aglase .co

Book: Mathematics NCERT Solutions | Chapter - 7 Maths

Class : 6th
Subject : Maths
Chapter : 7
Chapter Name : FRACTIONS

Exercise 7.1

Q1 Write the fraction representing the shaded portion.

Answer. (i) The given �gure represents 2 shaded parts out of 4 equal parts.
Hence, 24
(ii) The given �gure represents 8 shaded parts out of 9 equal parts.
8
Hence, 9
(iii) The given �gure represents 4 shaded parts out of 8 equal parts.
Hence, 48
(iv) The given �gure represents 1 shaded parts out of 4 equal parts.
Hence, 14
(v) The given �gure represents 3 shaded parts out of 7 equal parts.
Hence, 37
(vi) The given �gure represents 3 shaded parts out of 12 equal parts.
3
Hence, 12
(vii) The given �gure represents 10 shaded parts out of 10 equal parts.
10
Hence, 10
(viii) The given �gure represents 4 shaded parts out of 9 equal parts.
Hence, 49
(ix) The given �gure represents 4 shaded parts out of 8 equal parts.
Hence, 48
(x) The given �gure represents 1 shaded parts out of 2 equal parts.

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Book: Mathematics NCERT Solutions | Chapter - 7 Maths

Hence, 12

Page : 135 , Block Name : Exercise 7.1

Q2 Colour the part according to the given fraction.

Answer.

Page : 135 , Block Name : Exercise 7.1

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Q3 Identify the error, if any.

Answer. The given �gures do not represent the fractions as here each shape is not
divided in equal parts.

Page : 136 , Block Name : Exercise 7.1

Q4 What fraction of a day is 8 hours?

8
Answer. There are 24 hours in a day. Therefore, 8 hours Of a day represent 24

Page : 136 , Block Name : Exercise 7.1

Q5 What fraction of an hour is 40 minutes?

40
Answer. There are 60 minutes in an hour. Therefore, 40 minutes of an hour represent 60

Page : 136 , Block Name : Exercise 7.1

Q6 Arya, Abhimanyu, and Vivek shared lunch. Arya has brought two sandwiches, one
made of vegetable and one of jam. The other two boys forgot to bring their lunch. Arya
agreed to share his sandwiches so that each person will have an equal share of each
sandwich.
(a) How can Arya divide his sandwiches so that each person has an equal share?
(b) What part of a sandwich will each boy receive?

Answer. (a) Arya will divide each sandwich in three equal parts. Then, he will give one
part of each sandwich to each one of them.
(b) Each boy will receive 13 part of each sandwich.

Page : 136 , Block Name : Exercise 7.1

Q7 Kanchan dyes dresses. She had to dye 30 dresses. She has so far �nished 20 dresses.
What fraction of dresses has she �nished?

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Book: Mathematics NCERT Solutions | Chapter - 7 Maths

Answer. Dress dyed so far = 20
Total dresses = 30
20
Fraction = 30 = 23

Page : 136 , Block Name : Exercise 7.1

Q8 Write the natural numbers from 2 to 12. What fraction of them are prime numbers?

Answer. Natural numbers from 2 to 12 are 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and 12.
Prime numbers among these are 2, 3. 5, 7, and 11.
5
Therefore, out of 11 numbers, 5 are prime numbers. It represents a fraction 11

Page : 136 , Block Name : Exercise 7.1

Q9 Write the natural numbers from 102 to 113. What fraction of them are prime
numbers?

Answer. Natural numbers from 102 to 113 are 102, 103, 104, 105, 106, 107, 108, 109, 110,
111, 112, 113
Among these numbers, the prime numbers are 103, 107, 109, and 113.
4
Therefore, out of 12 numbers, 4 are prime numbers. It represents a fraction 12

Page : 136 , Block Name : Exercise 7.1

Q10 What fraction of these circles have X’s in them?

Answer. There are 4 circles, out of 8, having X's in them. Therefore, it represents a
fraction 48

Page : 136 , Block Name : Exercise 7.1

Q11 Kristin received a CD player for her birthday. She bought 3 CDs and received 5 others
as gifts. What fraction of her total CDs did she buy and what fraction did she receive as
gifts?

Answer. Total CDs Kristin had on her birthday = 3 + 5 = 8
Out of 8 CDs, she bought 3 CDs and also got 5 CDs as gifts. Therefore, she bought and
5
received CDs as gifts in a fraction of 38 and 8 respectively.

Page : 136 , Block Name : Exercise 7.1

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Book: Mathematics NCERT Solutions | Chapter - 7 Maths

Exercise 7.2

Q1 Draw number lines and locate the points on them :
(a) 12 , 14 , 34 , 44
7
(b) 18 , 28 , 38 , 8
8
(c) 25 , 35 , 5 , 45

Answer.

Page : 141 , Block Name : Exercise 7.2

Q2 Express the following as mixed fractions :
20
(a) 3
(b) 11
5
17
(c) 7
28
(d) 5
19
(e) 6
35
(f) 9

18+2
20 18
Answer. (a) 3 = 3
= 3 + 23 = 6 + 23 = 6 23
10+1 10
(b) 11
5
= 5 = 5 + 15 = 2 + 15 = 2 15
17 14+3
(c) 7 = 7 = 14 7
+ 37 = 2 + 37 = 2 37
28 25+3 28
(d) 5 = 5 = 5 + 35 = 5 + 35 = 5 35
19 18+1 18 19
(e) 6 = 6 = 6 + 16 = 3 + 16 = 3 6
35 27+8 27 8 8 8
(f) 9 = 9 = 9 + 9 = 3 + 9 = 3 9

Page : 141 , Block Name : Exercise 7.2

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Q3 Express the following as improper fractions :
(a) 7 34
6
(b) 5 7
5
(c) 2 6
(d) 10 35
(e) 9 37
(f) 8 49

(4∗7)+3 31
Answer. (a) 7 34 = 4
= 4
6 (7∗5)+6
(b) 5 7 = 7
= 41
7
5 (6∗2)+5 17
(c) 2 6 = 6
= 6
(5∗10)+3 53
(d) 10 35 = 5
= 5
(7∗9)+3 66
(e) 9 37 = 7
= 7
(8∗9)+4 76
(f) 8 49 = 9
= 9

Page : 141 , Block Name : Exercise 7.2

Exercise 7.3

Q1 Write the fractions. Are all these fractions equivalent?
(a)

(b)

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Answer. (a) In the given circles, 1 out of 2, 2 out of 4, 3 out of 6, and 4 out of 8 equal pans
are shaded respectively. Therefore, these circles represent

(b) In the given rectangles, 4 out of 12, 3 out Of 9, 2 out Of 6, 1 out Of 3, and 6 out Of 15
equal parts (i.e., circles) are shaded respectively. Therefore, these rectangles represent

Page : 146 , Block Name : Exercise 7.3

Q2 Write the fractions and pair up the equivalent fractions from each row.

Answer. (a) Here, 1 part is shaded out Of 2 equal parts (i.e., rectangle). Hence, this

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Book: Mathematics NCERT Solutions | Chapter - 7 Maths

�gure represents a fraction 12
(b) Here, 4 parts are shaded out of 6 equal parts (i.e., rectangle). Hence, this �gure
represents a traction 46 = 23
(c) Here, 3 parts are shaded out ot 9 equal parts (i.e., squares). Hence, this �gure
represents a fraction 39 = 13
(d) Here, 2 parts are shaded Out Of 8 equal parts (i.e., rectangle). Hence, this �gure a
fraction 28 = 14
(e) Here, 3 parts are shaded out Of 4 equal parts (i.e., squares). Hence, this �gure
represents a fraction 34
(i) Here, 6 parts are shaded out of 18 equal parts (i.e., triangles). Hence, this �gure
6
represents a fraction 18 = 13
(ii) Here, 4 parts are shaded out of 8 equal parts (I.e., rectangles), Hence, this �gure
represents a fraction 48 = 12
(iii) Here, 12 parts are shaded out of 16 equal parts (i.e., squares). Hence, this �gure
represents a fraction 1216
= 34
(iv) Here, 8 parts are shaded out of 12 equal parts (i.e., rectangles). Hence, this �gure
8
represents a fraction 12 = 23
(v) Here, 4 parts are shaded out of 16 equal parts (i.e., triangles). Hence, this �gure
4
represents a fraction 16 = 14
Now, these �gures can be matched correctly as
(a) (ii), (b) (iv), (c) (i), (d) (v), (e) (iii)

Page : 146 , Block Name : Exercise 7.3

Q3 Replace □ in each of the following by the correct number :
8
(a) 27 = □
5 10
(b) 8 = □
□
(c) 35 = 20
45 15
(d) 60 = □
(e) 24 = □
18
4

8
Answer. (a) 27 = □
8
2
7
* 44 = 28
Hence, &mnSq2 can be replaced by 28.
5 10
(b) 8 = □
5 10
8
* 22 = 16
Hence, &mnSq2 can be replaced by 16.
□
(c) 35 = 20

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Book: Mathematics NCERT Solutions | Chapter - 7 Maths

3
5
* 44 = 12
20
Hence, &mnSq2 can be replaced by 12. ’
45 15
(d) 60 = □
45 15
60
= 20 * 33
Hence, &mnSq2 can be replaced by 20.
(e) 24 = □
18
4
18 6
24
= 34 * 6
Hence, &mnSq2 can be replaced by 3.

Page : 147 , Block Name : Exercise 7.3

Q4 Find the equivalent fraction of 35 having
(a) denominator 20
(b) numerator 9
(c) denominator 30
(d) numerator 27

□
Answer. (a) 35 = 20
3 * 20 = 5 * □
3*2*2*5=5*□
12 = □
Hence, the required fraction is 12
20
9
(b) 35 = □
3*□=5*9
3*□=5*3*3
□ = 15
9
Hence, the required fraction is 15
□
(c) 35 = 30
3 * 30 = 5 * □
3*2*3*5=5*□
18 = □
18
Hence, the required fraction is 30
27
(d) 35 = □
3 * □ = 5 * 27
3*□=5*3*3*3
□ = 45
27
Hence, the required fraction is 45

Page : 147 , Block Name : Exercise 7.3

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Book: Mathematics NCERT Solutions | Chapter - 7 Maths

36
Q5 Find the equivalent fraction of 48 with
(a) numerator 9
(b) denominator 4

36 9
Answer. (a) 48 = □
36 * □ = 48 * 9
3*3*2*2*□=2*2*2*2*3*3*3
□ = 12
9
Hence, the required fraction is 12
(b) 48 = □
36
4
36 * 4 = 48 * □
3*3*2*2*2*2=2*2*2*2*3*□
3=□
Hence, the required fraction is 34

Page : 147 , Block Name : Exercise 7.3

Q6 Check whether the given fractions are equivalent :
5 30
(a) 9 , 54
3
(b) 10 , 12
50
7 5
(c) 13 , 11

5 30
Answer. (a) 9 , 54
30 5∗6 5
54
= 9∗6 = 9
Clearly, both the fractions are equivalent.
3
(b) 10 , 12
50
3 3∗2 6
10
= 10∗2 = 20
12 6∗2 6
50
= 25∗2 = 25
Clearly, both the fractions are not equivalent.
7 5
(c) 13 , 11
7 7∗11 77
13
= 13∗11 = 143
5 5∗13 65
11
= 11∗13 = 143
Clearly, both the fractions are not equivalent.

Page : 147 , Block Name : Exercise 7.3

Q7 Reduce the following fractions to simplest form :

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Book: Mathematics NCERT Solutions | Chapter - 7 Maths

48
(a) 60
150
(b) 60
84
(c) 98
(d) 12
52
7
(e) 28

48
Answer. (a) 60 = 12∗4
12∗5
= 45
150 30∗5 5
(b) 60 = 30∗2 = 2
84 14∗6 6
(c) 98 = 14∗7 = 7
3∗4 3
(d) 12
52
= 13∗4 = 13
7 7
(e) 28 = 7∗4 = 14

Page : 147 , Block Name : Exercise 7.3

Q8 Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4
months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaal used up 40
pencils. What fraction did each use up? Check if each has used up an equal fraction of
her/his pencils?

10
Answer. Fraction used by Ramesh = 20 = 12
25
Fraction used by Sheelu = 50 = 12
40
Fraction used by Jamaal = 80 = 12
Yes, all Of them used equal fraction Of pencils i.e., 12 .

Page : 147 , Block Name : Exercise 7.3

Q9 Match the equivalent fractions and write two more for each.
250
(i) 400 (a) 23
180
(ii) 200 (b) 25
660
(iii) 990 (c) 12
180 5
(iv) 360 (d) 8
220 9
(v) 550 (e) 10

250 5∗50 5
Answer. (i) 400 = 8∗50 = 8
25 30
Two more fractions are 40 , 48 .
180 9∗20 9
(ii) 200 = 10∗20 = 10
18 27
Two more fractions are 20 , 30 .

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Book: Mathematics NCERT Solutions | Chapter - 7 Maths

660 2∗330
(iii) 990 = 3∗330 = 23
20 200
Two more fractions are 30 , 300 .
180 1∗180
(iv) 360 = 2∗180 = 12
20 30
Two more fractions are 40 , 60 .
220 2∗110
(v) 550 = 5∗110 = 25
20 40
Two more fractions are 50 , 100 .
Now, these can be matched as

Page : 147 , Block Name : Exercise 7.3

Exercise 7.4

Q1 Write shaded portion as fraction. Arrange them in ascending and descending order
using correct sign ‘<’, ‘=’, ‘>’ between the fractions:

8 6
(c) Show 26 , 46 , 6 and 6 on the number line. Put appropriate signs between the
fractions given.
5
6
□ 26
3
6
□0
1
6
□ 66
8
6
□ 56

Answer. (a)
(i)

Here, 1st circle represents 3 shaded parts out ot 8 equal parts. Therefore, it represents a
fraction 38 .
(ii)

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Here, 2nd circle represents 6 shaded parts out ot 8 equal parts. Therefore, it represents a
6
fraction 8 .
(iii)

Here, 3rd circle represents 4 shaded parts out ot 8 equal parts. Therefore, it represents a
fraction 48 .
(iv)

Here, 4th circle represents 1 shaded parts out ot 8 equal parts. Therefore, it represents a
fraction 18 .
Now, these fractions may be arranged as
6
1
8
< 38 < 48 < 8

(b)
(i)

Here, 1st square represents 8 shaded parts out of 9 equal parts. Therefore, It represents a
8
fraction 9 .
(ii)

Here, 2nd square represents 4 shaded parts out of 9 equal parts. Therefore, It represents
a fraction 49 .
(iii)

Here, 3rd square represents 3 shaded parts out of 9 equal parts. Therefore, It represents a
fraction 39 .
(iv)

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Here, 4th square represents 6 shaded parts out of 9 equal parts. Therefore, It represents a
6
fraction 9 .
Now, these fractions may be arranged as
3 6 8
9
< 49 < 9 < 9
8 6
(c) To represent the given fractions 26 , 46 , 6 and 6 on number line, each unit length
should be divided in 6 equal parts. Now, these fractions can be represented as

5
6
> 26
3
6
>0
1 6
6
< 6
8 5
6
> 6

Page : 152 , Block Name : Exercise 7.4

Q2 Compare the fractions and put an appropriate sign.
5
(a) 36 □ 6
(b) 17 □ 14
5
(c) 45 □ 5
(d) 35 □ 37

3 5
Answer. (a) 6 < 6
Here, the denominators are same. Therefore, the fraction having the greater numerator
will be greater.

(b) 17 = 1∗4
7∗4
4
= 28
1 1∗7 7
4
= 4∗7 = 28
As 4 < 7,
1
7
< 14

5
(c) 45 < 5
Here, the denominators are same. Therefore, the fraction having the greater numerator
will be greater.

(d) 35 > 37

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Here, the numerators are same. Therefore, the fraction having the greater denominator
will be greater.

Page : 153 , Block Name : Exercise 7.4

Q3 Make �ve more such pairs and put appropriate signs.

6 8
Answer. (i) 7 < 7
Here, the denominators are same. Therefore, the fraction having the greater numerator
will be greater.
5
(ii) 8 > 38
Here, the denominators are same. Therefore, the fraction having the greater numerator
will be greater.
6 6
(iii) 13 > 17
Here, the numerators are same. Therefore, the fraction having the lesser denominator
will be greater.
5 3
(iv) 22 > 22
Here, the denominators are same. Therefore, the fraction having the greater numerator
will be greater.
9 9
(v) 47 < 42
Here, the numerators are same. Therefore, the fraction having the lesser denominator
will be greater.

Page : 153 , Block Name : Exercise 7.4

Q4 Look at the �gures and write ‘<’ or ‘>’, ‘=’ between the given pairs of fractions.

(a)
1
6
□ 13
(b)
3
4
□ 26
(c)
2
3
□ 24
(d)

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Book: Mathematics NCERT Solutions | Chapter - 7 Maths

6
6
□ 33
(e)
5
6
□ 55
Make �ve more such problems and solve them with your friends.

Answer. (a) Here, the numerators are same, Therefore, the fraction having the lesser
denominator will be greater.
Hence, 16 < 13
(b)
3 9
4
= 3∗3
4∗3
= 12
2 4
6
= 2∗2
6∗2
= 12
9 4
As the denominators of 12 , 12 are same, the fraction having the greater numerator will
be greater.
Hence, 34 > 26

(c)
Here, the numerators are same, Therefore, the fraction having the lesser denominator
will be greater.
Hence, 23 > 24

6
(d) As 6 = 1, 33 =1
6
6
= 33

(e) Here, the numerators are same, Therefore, the fraction having the lesser denominator
will be greater.
5 5
Hence, 6 < 5

Page : 153 , Block Name : Exercise 7.4

Q5 How quickly can you do this? Fill appropriate sign. ( ‘<’, ‘=’, ‘>’)
(a) 12 □ 15
(b) 24 □ 36
(c) 35 □ 23
(d) 34 □ 28
6
(e) 35 □ 5
7
(f) 9 □ 39
(g) 14 □ 28
6
(h) 10 □ 45

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Book: Mathematics NCERT Solutions | Chapter - 7 Maths

7
(i) 34 □ 8
6
(j) 10 □ 35
5 15
(k) 7 □ 21

Answer. (a) Here, the numerators are same, Therefore, the fraction having the lesser
denominator will be greater.
Hence, 12 > 15

(b)
2
4
= 12 and 36 = 12
Hence, 24 = 36

9
(c) 35 = 3∗3
5∗3
= 15
2 2∗5 10
3
= 3∗5 = 15
9 10
As the denominators of 15 and 15 are same, the fraction having the greater numerator
will be greater.
Hence, 35 < 23

(d) 28 = 14
As the denominators of 34 and 14 are same, the fraction having the greater numerator
Will be greater.
Hence, 34 > 28

(e) Here, the denominators are same. Therefore, the fraction having the greater
numerator will be greater.
6
Hence, 35 < 5

(f) Here, the denominators are same. Therefore, the fraction having the greater
numerator will be greater.
7
Hence, 9 > 39

(g) 28 = 14
1
4
= 28

6 3∗2
(h) 10 = 5∗2 = 35
As the denominators of 35 and 45 are same, the fraction having the greater numerator
Will be greater.
6
Hence, 10 < 45

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Book: Mathematics NCERT Solutions | Chapter - 7 Maths

3∗2 6
(i) 34 = 4∗2 = 8
6 7
As the denominators of 8 and 8 are same, the fraction having the greater numerator
will be greater.
7
Hence, 34 < 8

6 3∗2
(j) 10 = 5∗2 = 35
As the denominators of 35 and 45 are same, the fraction having the greater numerator
will be greater.
6
Hence, 10 < 45

5 5∗3 15
(k) 7 = 7∗3 = 21
5 15
Hence, 7 = 21

Page : 153 , Block Name : Exercise 7.4

Q6 The following fractions represent just three different numbers. Separate them into
three groups of equivalent fractions, by changing each one to its simplest form.
2
(a) 12
3
(b) 15
8
(c) 50
16
(d) 100
10
(e) 60
15
(f) 75
(g) 12
60
16
(h) 96
(i) 12
75
(j) 12
72
3
(k) 18
4
(l) 25

Answer. (a)
2
12
= 1∗2
6∗2
= 16

(b)
3 1∗3
15
= 5∗3 = 15

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(c)
8 4∗2 4
50
= 25∗2 = 25

(d)
16 4∗4 4
100
= 25∗4 = 25

(e)
10 1∗10
60
= 6∗10 = 16

(f)
15 1∗15
75
= 5∗15 = 15

(g)
12
60
= 1∗12
5∗12
= 15

(h)
16 1∗16
96
= 6∗16 = 16

(i)
12 4∗3 4
75
= 25∗3 = 25

(j)
12
72
= 1∗12
6∗12
= 16

(k)
3 1∗3
18
= 6∗3 = 16

(l)
4
25
There are 3 groups of equivalent fractions
1
6
--> (a), (e), (h), (j), (k)
1
5
--> (b), (f), (g)
4
25
--> (c), (d), (i), (l)

Page : 154 , Block Name : Exercise 7.4

Q7 Find answers to the following. Write and indicate how you solved them.
5
(a) Is 9 equal to 45 ?

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9 5
(b) Is 16 equal to 9 ?
16
(c) Is 45 equal to 20 ?
1 4
(d) Is 15 equal to 30 ?

5
Answer. (a) 9 , 45
Converting these into like fractions,
5 5 5 25
9
= 9 * 5 = 45
4 9 36
5
= 45 * 9 = 45
36 25
As, 45 ≠ 45 ,
5
Therefore, 9 is not equal to 45 .

9 5
(b) 16 , 9
Converting these into like fractions,
9 9 9 81
16
= 16 * 9 = 144
5 5 16 80
9
= 9 * 16 = 144
81 80
As, 144 ≠ 144 .
81 80
Therefore, 144 is not equal to 144 .

16
(c) 45 , 20
16
20
= 4∗4
5∗4
= 45
16
Therefore, 45 = 20

1 4
(d) 15 , 30
4 2∗2 2
30
= 15∗2 = 15
1 4
Therefore, 15 is not equal to 30
Page : 154 , Block Name : Exercise 7.4

Q8 Ila read 25 pages of a book containing 100 pages. Lalita read 25 of the same book.
Who read less?

Answer. Numbers of pages read bv Lalita = 25 * 100 = 40
Number of pages read by Ila = 25
Hence, Ila has read less number of pages.

Page : 154 , Block Name : Exercise 7.4

Q9 Ra�q exercised for 36 of an hour, while Rohit exercised for 34 of an hour. Who

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Book: Mathematics NCERT Solutions | Chapter - 7 Maths

exercised for a longer time?

Answer. Ratiq exercised for 36 hr and Rohit exercised for 34 hr. Converting these into like
fractions,
3 3∗2 6
6
= 6∗2 = 12
3 9
4
= 3∗3
4∗3
= 12
9 6
12
> 12 ⇒ 34 > 36
Hence, Rohit exercised for a longer time.

Page : 154 , Block Name : Exercise 7.4

Q10 In a class A of 25 students, 20 passed with 60% or more marks; in another class B of
30 students, 24 passed with 60% or more marks. In which class was a greater fraction of
students getting with 60% or more marks?

20
Answer. Fraction of students of class A who passed in 1st class = 25 = 45
Fraction of students of class B who passed in 1st class = 24
30
= 45
From both classes, an equal fraction of students passed in �rst class.

Page : 154 , Block Name : Exercise 7.4

Exercise 7.5

Q1 Write these fractions appropriately as additions or subtractions :

Answer. (a) Here, it can be Observed that 1st, 2nd, and 3rd rectangles are representing 1,
2, and 3 shaded parts out of 5 equal parts respectively. Clearly, the fraction represented
by 3rd rectangle is the sum of the fractions represented by 1st and 2nd rectangles.
Hence, 15 + 25 = 35

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(b) Here, it can be observed that 1st, 2nd, and 3rd circles are representing 5, 3, and 2
shaded parts out of 5 equal parts respectively. Clearly, the fraction represented by 3rd
circle is the difference between the fractions represented by 1st and 2nd circles.
5
Hence, 5 - 35 = 25
(c) Here, it can be observed that 1st, 2nd, and 3rd rectangles are representing 2, 3, and 5
shaded parts out of 6 equal parts respectively. Clearly, the fraction represented by 3rd
rectangle is the sum of the fractions represented by 1st and 2nd rectangles.
5
Hence, 26 + 36 = 6

Page : 157 , Block Name : Exercise 7.5

Q2 Solve:
1 1 8 3 7 5 1
(a) 18 + 18 (b) 15 + 15 (c) 7 - 7 (d) 22 + 21
22
7 5 0
(e) 12
15
- 15 (f) 8 + 38 (g) 1 - 23 ( 1 = 33 (h) 14 + 4
(i) 3 - 12
5

1 1 1+1 2
Answer. (a) 18 + 18 = 18
= 18 = 19
8 3 8+3
(b) 15 + 15 = 15
= 11
15
7 5 7−5 2
(c) 7 - 7 = 7 = 7
1 1+21
(d) 22 + 2122
= 22 = 22 22
=1
7 12−7 5
(e) 12
15
- 15 = 15 = 15 = 13
5 5+3 8
(f) 8 + 38 = 8 = 8 = 1
3−2
(g) 1 - 23 = 33 - 23 = 3 = 13
0
(h) 14 + 4 = 14 + 0 = 14
15 15−12
(i) 3 - 12
5
= 5 - 12 5
= 5 = 35

Page : 158 , Block Name : Exercise 7.5

Q3 Shubham painted 23 of the wall space in his room. His sister Madhavi helped and
painted 13 of the wall space. How much did they paint together?

Answer. Space painted by Shubham= 23 of the room
Space painted by Madhavi = 13 of the room
Hence, together they painted = ( 23 + 13 ) of the room =1 = the complete wall

Page : 158 , Block Name : Exercise 7.5

Page 22 of 29 Aglasem Schools

Book: Mathematics NCERT Solutions | Chapter - 7 Maths

Q4 Fill in the missing fractions.
7 3
(a) 10 - □ = 10
3 5
(b) □ - 21 = 21
(c) □ - 36 = 36
5
(d) □ + 27 = 12
27

7 3
Answer. (a) 10 - □ = 10
7 3 7−3 4
□ = 10 - 10 = 10 = 10 = 25
3 5
(b) □ - 21 = 21
5 3 5+3 8
□ = = 21 + = 21 = = 21 = = 21
(c) □ - 36 = 36
□ = 36 + 36 = 3+3
6
6
=6 =1
5
(d) □ + 27 = 12
27
5 12−5 7
□ = 12
27
- 27 = 27 = 27

Page : 158 , Block Name : Exercise 7.5

5
Q5 . Javed was given 7 of a basket of oranges. What fraction of oranges was left in the
basket?

5
Answer. Fractions given to Javed = 7
5 7 5 7−5
Fraction left in the basket = 1 - 7 = 7 - 7 = 7
= 27

Page : 158 , Block Name : Exercise 7.5

Exercise 7.6

Q1 Solve
(a) 23 + 17
3 7
(b) 10 + 15
(c) 49 + 27
5
(d) 7 + 13
(e) 25 + 16
(f) 45 + 23

Page 23 of 29 Aglasem Schools

Book: Mathematics NCERT Solutions | Chapter - 7 Maths

(g) 34 - 13
5
(h) 6 - 13
(i) 23 + 34 + 12
(j) 12 + 13 + 16
(k) 1 13 + 3 23
(l) 4 23 + 3 14
16 7
(m) 5 - 5
(n) 43 - 12

Answer. (a) 23 + 17
(2∗7)+(1∗3)
21
( Taking LCM as 21)
14+3
21
17
21

3 7
(b) 10 + 15
(3∗3)+(7∗2)
30
(Taking 30 as LCM)
9+14
30
23
30

4 2
(c) 9 + 7
(4×7)+(2×9)
= 63
28+18
= 63 = 46 63

5 1
(d) 7 + 3
(5×3)+(1×7)
= 21
15+7
= 21 = 22 21

(e) 25 + 16
(2×6)+(1×5)
= 30
= 17
30

(f) 45 + 23
(4×3)+(2×5)
= 15
= 22
15

Page 24 of 29 Aglasem Schools

Book: Mathematics NCERT Solutions | Chapter - 7 Maths

(g) 34 − 13
(3×3)−(1×4)
= 12
9−4 5
= 12 = 12

5 1
(h) 6 − 3
5−(1×2)
= 6
5−2
= 6 = 36 = 12

2 3 1
(i) 3 + 4 + 2
(2×4)+(3×3)+(1×6)
= 12
8+9+6
= 12 = 23 12

(j) 12 + 13 + 16
(1×3)+(1×2)+(1×1)
= 6

= 3+2+1
6
= 66 = 1

1 2
(k)1 3 +3 3
(3×1)+1 (3×3)+2
= 3
+ 3
4 11 15
= 3 + 3 = 3 =5

4 23 + 3 14
(3×4)+2 (3×4)+1
= 3
+ 4
(l)
14 13
= 3 + 4
(14×4)+(13×3)
= 12
= 56+39
12
= 95
12

(m) 16
5
− 75 = 16−7
5
= 95

(n) 43 − 12
(4×2)−(1×3)
= 6
= 8−3
6
= 56

Page 25 of 29 Aglasem Schools

Book: Mathematics NCERT Solutions | Chapter - 7 Maths

Page : 160 , Block Name : Exercise 7.6

Q2 Sarita bought 25 metre of ribbon and Lalita 34 metre of ribbon. What is the total
length of the ribbon they bought?

Answer. Length of ribbon bought by Savita = 25 m
Length of ribbon bought by Lalita = 34
(2∗4)+(3∗5) 8+15 23
Total length of ribbon bought by them = 25 + 34 = 20
= 20 = 20 m

Page : 160 , Block Name : Exercise 7.6

Q3 Naina was given 1 12 piece of cake and Najma was given 1 13 piece of cake. Find the
total amount of cake was given to both of them.

Answer. Fraction Naina got = 1 12 = 32
Fraction Najma got = 1 13 = 43
3∗3+4∗2 9+8 17 5
Total amount of cake given to them : 32 + 43 = 6
= 6 = 6 =26

Page : 160 , Block Name : Exercise 7.6

Q4 Fill in the boxes :
5
(a) □ - 8 = 14
(b) □ - 15 = 12
(c) 12 - □ = 16

5
Answer. (a) □ - 8 = 14
□ = 14 + 58 = 1∗2+5
8
2+5 7
= 8 = 8
(b) □ - 15 = 12
(1∗5)+(1∗2) 5+2 7
□ = 12 + 15 = 10
= 10 = 10
(c) 12 - □ = 16
(1∗3)−1 3−1
□ = 12 - 16 = 6
= 6 = 26 = 13

Page : 161 , Block Name : Exercise 7.6

Q5 Complete the addition-subtraction box.

Page 26 of 29 Aglasem Schools

Book: Mathematics NCERT Solutions | Chapter - 7 Maths

Answer. (a)

(b)

Page 27 of 29 Aglasem Schools

Book: Mathematics NCERT Solutions | Chapter - 7 Maths

Page : 161 , Block Name : Exercise 7.6

7
Q6 A piece of wire 8 metre long broke into two pieces. One piece was 14 metre long. How
long is the other piece?

Answer. Length Of one piece = 14
The length of the other piece of wire will be the difference of the lengths of the original
wire and this piece of wire,
7 7−(1∗2) 7−2 5
Hence, length of the other piece of wire = 8 - 14 = 8
= 8 = 8 m

Page : 161 , Block Name : Exercise 7.6

9
Q7 Nandini’s house is 10 km from her school. She walked some distance and then took a
bus for 12 km to reach the school. How far did she walk?

Answer. Distance walked by Nandini = Total distance — Distance for which she took the
bus
9 9−5 4
10
- 12 = 10 = 10 = 25 km

Page : 161 , Block Name : Exercise 7.6

Q8 Asha and Samuel have bookshelves of the same size partly �lled with books. Asha’s
5
shelf is 6 th full and Samuel’s shelf is 25 th full. Whose bookshelf is more full? By what
fraction?

5
Answer. Fraction Of Asha's shelf = 6
Fraction of Samuel's shelf = 25
Converting these into like fractions,

Clearly, Asha's bookshelf is more full.
5 25 13
Difference = 6 - 25 = 30 - 12
30
= 30

Page : 161 , Block Name : Exercise 7.6

7
Q9 Jaidev takes 2 15 minutes to walk across the school ground. Rahul takes 4 minutes to

Page 28 of 29 Aglasem Schools

Book: Mathematics NCERT Solutions | Chapter - 7 Maths

do the same. Who takes less time and by what fraction?

Answer. Time taken by Jaidev = 2 15 = 11
5
min.
7
Time taken by Rahul = 4 min.
Converting these into like fractions,

Hence, Rahul takes lesser time.
7 35 9
Difference = 11
5
- 4 = 44
20
- 20 = 20 min.

Page : 161 , Block Name : Exercise 7.6

Page 29 of 29 Aglasem Schools