NCERT Solutions for Class 7 Science Chapter 9 Motion and Time
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Book Name: Science
Subject: Science
Chapter Number: 13
Chapter Name: Motion and Time
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Book Name: Science
Subject: Science
Chapter Number: 13
Chapter Name: Motion and Time
You can also bookmark this page by clicking + Save to Library icon and refer to these NCERT Solutions anytime from your account. More Detail
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NCERT Solutions for Class 7 Science Chapter 9 Motion and Time – Text
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Page 1
NCERT
SOLUTIONS
CLASS - 7TH
aglase .co
SOLUTIONS
CLASS - 7TH
aglase .co
Page 2
Book : Science Ncert Solutions | Chapter-13 Science
Class : 7th
Subject : Science
Chapter : 13
Chapter Name : Motion and Time
Q1 Classify the following as motion along a straight line, circular or oscillatory motion:
(i) Motion of your hands while running.
(ii) Motion of a horse pulling a cart on a straight road.
(iii) Motion of a child in a merry-go-round.
(iv) Motion of a child on a see-saw.
(v) Motion of the hammer of an electric bell.
(vi) Motion of a train on a straight bridge.
Answer. (i) Oscillatory motion
While running, the hands move to and fro and repeat their motion after a given interval of
time. Hence, it is an oscillatory motion.
(ii)Straight line
The horse is pulling a cart on a straight road. Therefore, it has a motion along a straight line.
(iii)Circular motion
Merry-go-round has a circular motion. Therefore, a child sitting inside it will also have a
circular motion.
(iv) Oscillatory motion
The child on a see-saw goes up and down continuously. It oscillates up-down. Therefore, it is
an
oscillatory motion.
(v)OsciIIatory motion
The hammer hits the electric bell and vibrates rapidly. Therefore, it is an oscillatory motion.
(vi) Straight line
The train is moving on a straight bridge. Therefore, it has a motion along a straight line.
Page : 156 , Block Name : Exercise
Q2 Which of the following are not correct?
(i) The basic unit of time is second.
(ii) Every object moves with a constant speed.
(iii) Distances between two cities are measured in kilometres.
(iv) The time period of a given pendulum is not constant.
(v) The speed of a train is expressed in m/h.
Answer. (i) Correct
Second is the Sl unit of time.
Page 1 of 9 Aglasem Schools
Class : 7th
Subject : Science
Chapter : 13
Chapter Name : Motion and Time
Q1 Classify the following as motion along a straight line, circular or oscillatory motion:
(i) Motion of your hands while running.
(ii) Motion of a horse pulling a cart on a straight road.
(iii) Motion of a child in a merry-go-round.
(iv) Motion of a child on a see-saw.
(v) Motion of the hammer of an electric bell.
(vi) Motion of a train on a straight bridge.
Answer. (i) Oscillatory motion
While running, the hands move to and fro and repeat their motion after a given interval of
time. Hence, it is an oscillatory motion.
(ii)Straight line
The horse is pulling a cart on a straight road. Therefore, it has a motion along a straight line.
(iii)Circular motion
Merry-go-round has a circular motion. Therefore, a child sitting inside it will also have a
circular motion.
(iv) Oscillatory motion
The child on a see-saw goes up and down continuously. It oscillates up-down. Therefore, it is
an
oscillatory motion.
(v)OsciIIatory motion
The hammer hits the electric bell and vibrates rapidly. Therefore, it is an oscillatory motion.
(vi) Straight line
The train is moving on a straight bridge. Therefore, it has a motion along a straight line.
Page : 156 , Block Name : Exercise
Q2 Which of the following are not correct?
(i) The basic unit of time is second.
(ii) Every object moves with a constant speed.
(iii) Distances between two cities are measured in kilometres.
(iv) The time period of a given pendulum is not constant.
(v) The speed of a train is expressed in m/h.
Answer. (i) Correct
Second is the Sl unit of time.
Page 1 of 9 Aglasem Schools
Page 3
Book : Science Ncert Solutions | Chapter-13 Science
(ii) Not correct
An object can move with constant or variable speed.
(iii) Correct
The distance between two cities can be very large. Since kilometre is a bigger unit of distance,
the distance between two cities is measured in kilometres.
(iv) Not correct
Time period of a pendulum depends on the length of the thread. Hence, it is constant for a
particular pendulum.
(v) Not correct
The speed of a train is measured either in km/h or in m/s.
Page : 156 , Block Name : Exercise
Q3 A simple pendulum takes 32 s to complete 20 oscillations. What is the time period of the
pendulum?
Answer. Number 0T oscillations =20
Total time taken to complete 20 oscillations 32 s
Page : 156 , Block Name : Exercise
Q4 The distance between two stations is 240 km. A train takes 4 hours to cover this distance.
Calculate the speed of the train.
Answer. Distance between the two stations = 240 km
Time taken = 4 h
Page : 156 , Block Name : Exercise
Q5 The odometer of a car reads 57321.0 km when the clock shows the time 08:30 AM. What is
the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 57336.0
km? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.
Answer. Initial reading of the odometer of the car = 57321.0 km v
Page 2 of 9 Aglasem Schools
(ii) Not correct
An object can move with constant or variable speed.
(iii) Correct
The distance between two cities can be very large. Since kilometre is a bigger unit of distance,
the distance between two cities is measured in kilometres.
(iv) Not correct
Time period of a pendulum depends on the length of the thread. Hence, it is constant for a
particular pendulum.
(v) Not correct
The speed of a train is measured either in km/h or in m/s.
Page : 156 , Block Name : Exercise
Q3 A simple pendulum takes 32 s to complete 20 oscillations. What is the time period of the
pendulum?
Answer. Number 0T oscillations =20
Total time taken to complete 20 oscillations 32 s
Page : 156 , Block Name : Exercise
Q4 The distance between two stations is 240 km. A train takes 4 hours to cover this distance.
Calculate the speed of the train.
Answer. Distance between the two stations = 240 km
Time taken = 4 h
Page : 156 , Block Name : Exercise
Q5 The odometer of a car reads 57321.0 km when the clock shows the time 08:30 AM. What is
the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 57336.0
km? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.
Answer. Initial reading of the odometer of the car = 57321.0 km v
Page 2 of 9 Aglasem Schools
Page 4
Book : Science Ncert Solutions | Chapter-13 Science
Final reading of the odometer of the car = 57336.0 km
Distance covered by the car
= Final reading of the odometer of the car — Initial reading of the odometer of the car
= 57336.0 - 57321.0 = 15 km
The given car starts at 8:30 a.m. and stops at 8:50 a.m.
Therefore, time taken by the car to cover the distance is (8:50- 8:30) min= 20 min
Distance covered by the car = 15 km
Time taken by the car = 20 min
Again,
60 min=1 h
Time taken by the car =
Page : 156 , Block Name : Exercise
Q6 Salma takes 15 minutes from her house to reach her school on a bicycle. If the bicycle has a
speed of 2 m/s, calculate the distance between her house and the school.
Answer. Time taken by Salma to reach her school from her home = 15 min = 15 x 60 = 900 s
Speed of her bicycle = 2 m/s
Distance covered = Speed x Time taken = 2 x 900 = 1800 m
Page 3 of 9 Aglasem Schools
Final reading of the odometer of the car = 57336.0 km
Distance covered by the car
= Final reading of the odometer of the car — Initial reading of the odometer of the car
= 57336.0 - 57321.0 = 15 km
The given car starts at 8:30 a.m. and stops at 8:50 a.m.
Therefore, time taken by the car to cover the distance is (8:50- 8:30) min= 20 min
Distance covered by the car = 15 km
Time taken by the car = 20 min
Again,
60 min=1 h
Time taken by the car =
Page : 156 , Block Name : Exercise
Q6 Salma takes 15 minutes from her house to reach her school on a bicycle. If the bicycle has a
speed of 2 m/s, calculate the distance between her house and the school.
Answer. Time taken by Salma to reach her school from her home = 15 min = 15 x 60 = 900 s
Speed of her bicycle = 2 m/s
Distance covered = Speed x Time taken = 2 x 900 = 1800 m
Page 3 of 9 Aglasem Schools
Page 5
Book : Science Ncert Solutions | Chapter-13 Science
1000 m = 1 km
Page : 156 , Block Name : Exercise
Q7 Show the shape of the distance-time graph for the motion in the following cases:
(i) A car moving with a constant speed.
(ii) A car parked on a side road.
Answer. (i)A car moving with a constant speed covers equal distance in equal intervals of time.
Such motion of car is represented in the given distance-time graph.
(ii)The distance-time graph of a car parked on a road side is such that with the increase in
time, there is no change in distance, as shown in the given gure.
Page : 156 , Block Name : Exercise
Q8 Which of the following relations is correct?
(i) Speed = Distance x Time
Page 4 of 9 Aglasem Schools
1000 m = 1 km
Page : 156 , Block Name : Exercise
Q7 Show the shape of the distance-time graph for the motion in the following cases:
(i) A car moving with a constant speed.
(ii) A car parked on a side road.
Answer. (i)A car moving with a constant speed covers equal distance in equal intervals of time.
Such motion of car is represented in the given distance-time graph.
(ii)The distance-time graph of a car parked on a road side is such that with the increase in
time, there is no change in distance, as shown in the given gure.
Page : 156 , Block Name : Exercise
Q8 Which of the following relations is correct?
(i) Speed = Distance x Time
Page 4 of 9 Aglasem Schools
Page 6
Book : Science Ncert Solutions | Chapter-13 Science
Answer. (ii) Speed of an object is given by the relation
Speed= Distance
Time
Page : 156 , Block Name : Exercise
Q9 The basic unit of speed is:
(i) km/min
(ii) m/min
(iii) km/h
(iv) m/s
Answer. (iv) m/s
The basic unit of distance is metre (m).
The basic unit of time is second (s).
Speed= Distance
Time
Therefore, the basic unit of speed is m/s.
Page : 157 , Block Name : Exercise
Q10 A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for
the next 15 minutes. The total distance covered by the car is:
(i) 100 km
(ii) 25 km
(iii) 15 km
(iv) 10 km
Answer. (ii) 25 km
Case I
Speed of the car = 40 km/h
Page 5 of 9 Aglasem Schools
Answer. (ii) Speed of an object is given by the relation
Speed= Distance
Time
Page : 156 , Block Name : Exercise
Q9 The basic unit of speed is:
(i) km/min
(ii) m/min
(iii) km/h
(iv) m/s
Answer. (iv) m/s
The basic unit of distance is metre (m).
The basic unit of time is second (s).
Speed= Distance
Time
Therefore, the basic unit of speed is m/s.
Page : 157 , Block Name : Exercise
Q10 A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for
the next 15 minutes. The total distance covered by the car is:
(i) 100 km
(ii) 25 km
(iii) 15 km
(iv) 10 km
Answer. (ii) 25 km
Case I
Speed of the car = 40 km/h
Page 5 of 9 Aglasem Schools
Page 7
Book : Science Ncert Solutions | Chapter-13 Science
Time taken = 15 min =
15
= 0.25h
60
Speed= Distance
Time
Distance covered, dl = Speed x Time taken = 40 x 0.25 = 10 km
Case II
Speed of the car = 60 km/h
Time taken = 15 min =
15
= 0.25h
60
Speed=
Distance
Time
Distance covered, d2 = Speed x Time taken = 60 x 0.25 = 15 km
Total distance covered by the car, d = dl + d2 = 10 + 15 = 25 km
Therefore, the total distance covered by the car is 25 km.
Page : 157 , Block Name : Exercise
Q11 Suppose the two photographs, shown in Figure 1 and Figure 2, had been taken at an
interval of 10 seconds. If a distance of 100 metres is shown by 1 cm in these photographs,
calculate the speed of the blue car.
Figure I Vehicles moving in the same direction of on a road
Figure 2 Position of vehicles shown in Figure 1 after some time
Answer. The distance covered by the blue car (as evident from the photograph) from one white
Page 6 of 9 Aglasem Schools
Time taken = 15 min =
15
= 0.25h
60
Speed= Distance
Time
Distance covered, dl = Speed x Time taken = 40 x 0.25 = 10 km
Case II
Speed of the car = 60 km/h
Time taken = 15 min =
15
= 0.25h
60
Speed=
Distance
Time
Distance covered, d2 = Speed x Time taken = 60 x 0.25 = 15 km
Total distance covered by the car, d = dl + d2 = 10 + 15 = 25 km
Therefore, the total distance covered by the car is 25 km.
Page : 157 , Block Name : Exercise
Q11 Suppose the two photographs, shown in Figure 1 and Figure 2, had been taken at an
interval of 10 seconds. If a distance of 100 metres is shown by 1 cm in these photographs,
calculate the speed of the blue car.
Figure I Vehicles moving in the same direction of on a road
Figure 2 Position of vehicles shown in Figure 1 after some time
Answer. The distance covered by the blue car (as evident from the photograph) from one white
Page 6 of 9 Aglasem Schools
Page 8
Book : Science Ncert Solutions | Chapter-13 Science
strip to another, which is measured by scale is 1.4 cm.
It is given that I cm is equivalent to 100 m.
Therefore, 1.4 cm is equivalent to 140 m.
Distance travelled by the car = 140 m
Time interval between the two photographs = 10 s
Speed = Distance covered
Time taken
=
140
10
= 14m/s
Page : 157 , Block Name : Exercise
Q12 Figure shows the distance-time graph for the motion of two vehicles A and B. Which one
of them is moving faster?
Distance-time graph for the motion of two cars
Answer. Vehicle A is moving faster than vehicle B.
Speed is given by the relation
Speed= Distance
Time
This relation shows that speed of a vehicle is greater if it covers maximum distance in
a given interval of time. To compare the distance, draw a line perpendicular to the
timeaxis, as shown in the following distance-time graph.
Page 7 of 9 Aglasem Schools
strip to another, which is measured by scale is 1.4 cm.
It is given that I cm is equivalent to 100 m.
Therefore, 1.4 cm is equivalent to 140 m.
Distance travelled by the car = 140 m
Time interval between the two photographs = 10 s
Speed = Distance covered
Time taken
=
140
10
= 14m/s
Page : 157 , Block Name : Exercise
Q12 Figure shows the distance-time graph for the motion of two vehicles A and B. Which one
of them is moving faster?
Distance-time graph for the motion of two cars
Answer. Vehicle A is moving faster than vehicle B.
Speed is given by the relation
Speed= Distance
Time
This relation shows that speed of a vehicle is greater if it covers maximum distance in
a given interval of time. To compare the distance, draw a line perpendicular to the
timeaxis, as shown in the following distance-time graph.
Page 7 of 9 Aglasem Schools
Page 9
Book : Science Ncert Solutions | Chapter-13 Science
From the graph, it is evident that for a given time t, the distance covered by vehicle A
is more than vehicle B. Hence, vehicle A is moving faster than vehicle B.
Page : 157 , Block Name : Exercise
Q13 WhiCh of the following distance-time graphs Shows a truck moving with
speed which is not constant?
Answer. Graph (iii)
In a distance-time graph, the constant speed of a truck will be represented by a straight line.
Page 8 of 9 Aglasem Schools
From the graph, it is evident that for a given time t, the distance covered by vehicle A
is more than vehicle B. Hence, vehicle A is moving faster than vehicle B.
Page : 157 , Block Name : Exercise
Q13 WhiCh of the following distance-time graphs Shows a truck moving with
speed which is not constant?
Answer. Graph (iii)
In a distance-time graph, the constant speed of a truck will be represented by a straight line.
Page 8 of 9 Aglasem Schools
Page 10
Book : Science Ncert Solutions | Chapter-13 Science
In a distance-time graph, a straight line parallel to the time axis indicates that the truck is not
moving. A curved line on the distance-time graph indicates that the truck is moving with a
speed which is not constant.
Page : 157 , Block Name : Exercise
Page 9 of 9 Aglasem Schools
In a distance-time graph, a straight line parallel to the time axis indicates that the truck is not
moving. A curved line on the distance-time graph indicates that the truck is moving with a
speed which is not constant.
Page : 157 , Block Name : Exercise
Page 9 of 9 Aglasem Schools
Document Details
| Board / Org | NCERT |
| Exam | Class 7 |
| Type | Solution |
| Pages | 10 |
| Updated | 30 Apr 2026 |