CBSE Class 12 Question Paper 2022 Solution Sanskrit Core

AMk¹yaaojanaa³Marking Scheme´ XII Class 2022
saMskRtma\ koind`kma\ ( Sanskrit Core)
(QP Code 22) Series %BAB%I5 Set 4 MM 40
General Instructions: -

1. You are aware that evaluation is the most important process in the actual and correct assessment of the
candidates. A small mistake in evaluation may lead to serious problems which may affect the future of
the candidates, education system and teaching profession. To avoid mistakes, it is requested that before
starting evaluation, you must read and understand the spot evaluation guidelines carefully.

2. “Evaluation policy is a confidential policy as it is related to the confidentiality of the examinations
conducted, Evaluation done and several other aspects. Its’ leakage to public in any manner could
lead to derailment of the examination system and affect the life and future of millions of
candidates. Sharing this policy/document to anyone, publishing in any magazine and printing in
News Paper/Website etc may invite action under IPC.”

3. Evaluation is to be done as per instructions provided in the Marking Scheme. It should not be done
according to one’s own interpretation or any other consideration. Marking Scheme should be strictly
adhered to and religiously followed. However, while evaluating, answers which are based on latest
information or knowledge and/or are innovative, they may be assessed for their correctness
otherwise and marks be awarded to them. In class-XII, while evaluating two competency based
questions, please try to understand given answer and even if reply is not from marking scheme
but correct competency is enumerated by the candidate, marks should be awarded.

4. The Head-Examiner must go through the first five answer books evaluated by each evaluator on the first
day, to ensure that evaluation has been carried out as per the instructions given in the Marking Scheme.
The remaining answer books meant for evaluation shall be given only after ensuring that there is no
significant variation in the marking of individual evaluators.

5. Evaluators will mark( √ ) wherever answer is correct. For wrong answer ‘X’ be marked. Evaluators will
not put right kind of mark while evaluating which gives an impression that answer is correct and no marks
are awarded. This is most common mistake which evaluators are committing.

6. If a question has parts, please award marks on the right-hand side for each part. Marks awarded for
different parts of the question should then be totaled up and written in the left-hand margin and encircled.
This may be followed strictly.

7. If a question does not have any parts, marks must be awarded in the left-hand margin and encircled.
This may also be followed strictly.

8. If a student has attempted an extra question, answer of the question deserving more marks should be
retained and the other answer scored out.

9. No marks to be deducted for the cumulative effect of an error. It should be penalized only once.

10. A full scale of marks __________(example 0-40 marks as given in Question Paper) has to be used.
Please do not hesitate to award full marks if the answer deserves it.

11. Every examiner has to necessarily do evaluation work for full working hours i.e. 8 hours every day and
evaluate 30 answer books per day in main subjects and 35 answer books per day in other subjects
(Details are given in Spot Guidelines).This is in view of the reduced syllabus and number of questions
in question paper.

12. Ensure that you do not make the following common types of errors committed by the Examiner in the
past:-
• Leaving answer or part thereof unassessed in an answer book.
• Giving more marks for an answer than assigned to it.

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• Wrong totaling of marks awarded on a reply.
• Wrong transfer of marks from the inside pages of the answer book to the title page.
• Wrong question wise totaling on the title page.
• Wrong totaling of marks of the two columns on the title page.
• Wrong grand total.
• Marks in words and figures not tallying.
• Wrong transfer of marks from the answer book to online award list.
• Answers marked as correct, but marks not awarded. (Ensure that the right tick mark is correctly
and clearly indicated. It should merely be a line. Same is with the X for incorrect answer.)
• Half or a part of answer marked correct and the rest as wrong, but no marks awarded.

13.While evaluating the answer books if the answer is found to be totally incorrect, it should be marked
as cross (X) and awarded zero (0)Marks.

14.Any unassessed portion, non-carrying over of marks to the title page, or totaling error detected by
the candidate shall damage the prestige of all the personnel engaged in the evaluation work as also
of the Board. Hence, in order to uphold the prestige of all concerned, it is again reiterated that the
instructions be followed meticulously and judiciously.

15.The Examiners should acquaint themselves with the guidelines given in the Guidelines for spot
Evaluation before starting the actual evaluation.

16.Every Examiner shall also ensure that all the answers are evaluated, marks carried over to the title
page, correctly totaled and written in figures and words.

17.The Board permits candidates to obtain photocopy of the Answer Book on request in an RTI
application and also separately as a part of the re-evaluation process on payment of the processing
charges.

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kRpyaa Qyaana dIijae:
1. kuC p`SnaaoM ko ivaklpa%mak ]<ar BaI hao sakto hOM.[sa A=\k yaaojanaa maoM ide gae ]<ar inadSa-naa%mak hMO.[nako Aitir> BaI saMdBaa-nausaar sahI
]<ar hao sakto hOMÊ At: A=\k ide jaaeÐ.
2. AnaucCod Aqavaa SlaaokaoM pr AaQaairt p`Sna AvabaaoQanaa%mak hOM.ivaVaqaI- AnaucCod maoM ide gae SabdaoM ko sqaana pr pyaa-yavaacaI SabdaoM ka p`yaaoga
BaI kr sakto hOM Ê [sako ilae BaI A=\k ide jaaeÐ.ivaVaqaI- ]<ar doto samaya ]pyau> ivaBai> Aqavaa vacana ka p`yaaoga nahIM krto tao AMSat:
A=\k kaTo jaaeÐÊ saMpUNa- nahIM.
3. ~uiTpUNa- vat-naI Aqavaa ASauw vyaakrNaa%mak p`yaaogaaoM ko ilae Anaupatt: A=\k kaTo jaaeÐ na ik pUro A=\k.
4. AaMiSak dRiYT sao sahI ]<araoM ko ilae BaI AMSat: A=\k AvaSya ide jaaeÐ.
5. #aND ‘#a’ maoM ³rcanaa%makM kaya-ma\´ ko Antga-t ‘saUcanaa’ va iva&apna’ maoM ivaklp samaJaa jaae.baccaaoM nao jaao BaI ivaklp ikyaa haoÊ A=\k ide
jaaeÐ.ivaYayap`itpadna AaOr vaa@ya saMrcanaa p`mau#a hOÊ na ik vaa@ya ka saaOMdya- t<va. AaMiSak vaa@ya­Sauwta ko ilae BaI A=\k ide jaaeÐ.

saMkota%mak ]<ar va AMk ivaBaajana :

Section A vaNa-naa%maka: p`Snaa: (ApiztavabaaoQanama\) 10 A=\ka:
1. ³A´ ekpdona ]<art.p`%yaok p`Sna ko ilae ½ AMk. ³kovalaM catuYTyama\´ 4×½Ä2
³i´ AitcaHcalama\ ³ii´ pvanasaMyamanama\ À pvana [va
³iii´ manasa: ³iv´ sa=\klpSai>:
³v´ sa=\klp­ivaklpyaao: À dRZsa=\klp­ivaklpyaao:

³Aa´ pUNa-vaa@yaona ]<art . p`%yaok p`Sna ko ilae 2 AMk. ³kovalaM p`SnaWyama\´ 2×2Ä4
³i´ ºººº[dma\ AByaasaona vaOragyaoNa ca inaga`hItuM Sa@yama\ .
³ii´ ººººyaoYaaM EaoYzpuÉYaaNaaM saMklpSai>: p`balaa Bavait to svamana: jayaint.
³iii´ ººººyao janaa: ]%saahrihta: inajamaanaisakbalasya ººººpraijata: Bavaint.
³ [´ mana:ÀAitcaHcalaM mana:À‘manasa: Sai>:’À ‘AsmaakM mana:’ Aqavaa AnaucCod pr AaQaairt Anya ]pyau> SaIYa-k.
1×1Ä1
³ [-´ yaqaainado-Sama\ ]<art . p`%yaok p`Sna ko ilae 1 AMk. ³kovalaM p`Sna~yama\´ 3×1Ä3
³i´ mana: ³ii´ kiznatmama\
³iii´ yao Àjanaa: ³iv´ pvana:

Section B (rcanaa%makM kaya-ma\) 15 A=\ka:
2. p~lao#anama\ ¹ 10 ir>sqaana . p`%yaok p`Sna ko ilae ½ AMk. 10×½Ä5
³i´ p`yaagat: ³ii´ saaqa-k ² ³iii´ ]<armaNDlao ³iv´ labQavaana\ ³V´ A%yaiQakM

³vi´ Éica: ³vii´ p`stuit: ³viii´ vaQaa-pnama\ ³ix´ p`Naamaa: ³x´ ANa-va:

3.³k´ laGaukqaa lao#ana. 10 ir>sqaana . p`%yaok ir>sqaanapUit- ko ilae ½ AMk. 10×½Ä

³i´Aaga%ya ³ii´ ËaoQasya. ³iii´ Saantica<a:À ËaoQaSaUnya: ³iv´ ËaoQaSaUnya:ÀSaantica<a: ³V´ p`it&ama\

³vi´ BaU%vaa ³vii´sasnaohma\. ³viii´ sah ³ix´ Saant: ³x´ saovaaBaavanayaa

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Aqavaa ³OR´
³#a´ saMvaad lao#ana. naIcao ide gae ]<ar inadSa-naa%mak hMO.[nako Aitir> BaI saMdBaa-nausaar sahI ]<ar hao sakto hOMÊ At: A=\k ide
jaaeÐ.5 ir>sqaana . p`%yaok ir>sqaanapUit- ko ilae 1 AMk. 5×1Ä5
³i´ mahaodya² (: mama iptRvya: sapirvaar: samaagat:.
³ii´ AhM (: iptRvyaona sah r>duga-M d`YTuM gatvaana\.
³iii´ t~ maInaabaajaar: dRYT:.
³iv´ t~ Ahma\ ekM ËIDnakM ËItvaana\.Àt~ mayaa ekM ËIDnakM ËItma\.
³V´ r>duga-M bahuSaaoBanama\ eoithaisak­dRYT\yaa ca AtIva mah<vapUNa-ma\ Aist.

4 ³k´ AnaucCodlao#anama\ 1×5Ä5
[sa p`Sna maoM ide gae ivaYaya “BaartdoSa:” pr ek AnaucCod ila#anaa hO.baccaaoM sao sarlaÊsaMixaPt vaa@yarcanaa Apoixat hO.kovala vaa@ya kI Sauwta do#aI
jaae.[sa p`Sna ka p`mau#a ]_oSya ivaYaya sao sambaw vaa@yaaoM kI rcanaa hO.vaa@ya laGau Aqavaa dIGa- hao Ê yah mah%vapUNa- nahIM. vyaakriNak dRiYT sao Sauw haonao
pr pUNa- A=\k ide jaaeÐ .maHjaUYaa maoM ide gae Sabd sahayataqa- hOMÊ baccao [naka p`yaaoga kroM Aqavaa nahIMÊ yah AavaSyak nahIM.vao svatn~ $p sao ApnaI
icantnaxamata sao vaa@ya ¹inamaa-Na kr sakto hOM. baccao Apnao SabdaoM ka p`yaaoga kr ivaYayaanausaar vaa@yaaoM ka inamaa-Na kr sakto hOM At: A=\k ide
jaaeÐ.~uiTyaaoM ko A=\k AMSat: kaTo jaaeÐ.pUNa-tyaa Sauw haonao pr hI 5 A=\k ide jaaeÐ. p`%yaok vaa@ya ko ilae 1 A=\k hOM.
Aqavaa ³OR´
4 ³#a´saMskRt Anauvaad ko p`Sna maoM baccao saMskRt maoM pyaa-yavaacaI SabdaoM ka p`yaaoga kr sakto hOM Ê At: A=\k ide jaaeÐ.~uiTpUNa- vat-naI Aqavaa
vyaakrNaa%mak p`yaaogaaoM ko ilae Anaupatt: A=\k kaTo jaaeÐ. AaMiSak $p sao sahI ]<araoM ko ilae BaI AMSat: A=\k AvaSya ide jaaeÐ.
p`%yaok Baaga ko ilae 1 A=\k. ³kovalaM vaa@yapHcakma\´ 5×1Ä5
³i´ Aaid%ya: AV ga`amaM gaimaYyait.
³ii´ baalak: ima~O: sah Qaavait .
³iii´ idllaI Baartsya rajaQaanaI Aist.
³iv´ ga=\gaa savaa-sau nadIYauÀ savaa-saaM nadInaaM piva~aÀ piva~tmaa Aist.
³V´ nadIma\ ]Bayat: ÀAiBat: vaRxaa: saint.
³vi´ rajaa yaacakaya vas~MÀvas~aiNa yacCitÀddait.
³vii´ vaRxaat\ p~aiNa ptint.

Section C (pizt¹AvabaaoQanama\) 15 AMka:
5. gaVaMSa: [sa p`Sna ka maUla ]_oSya AvabaaoQana prIxaNa hO .baccao pyaa-yavaacaI SabdaoM ka p`yaaoga kr sakto hOM.pUNa- A=\k ide
jaaeÐ.AaMiSak ]<ar sahI haonao pr AaMiSak A=\k ide jaaeÐ.
³A´ ekpdona ]<art. p`%yaok p`Sna ko ilae ½ A=\k. ³kovalaM p`SnaWyama\´ 2×½Ä1
³i´ Baaoja:
³ii´ isanQaulasaM&:
³iii´ pHcavaaiYa-k:
³Aa´pUNa-vaa@yaona ]<art . p`Sna ko ilae 2 A=\k. ³kovalaM p`SnaOkma\´ 1×2Ä2
³i´ ººººyaVhM rajyalaxmaIººººtda laaokapvaad: .
³ii´ ººººpu~hainava-MSaaocCod:ºººº.

6. pVaMSa:
³A´ ekpdona ]<art. p`%yaok p`Sna ko ilae ½ A=\k. ³kovalaM p`SnaWyama\´ 2×½Ä1
³i´ saupu~oNa
³ii´ cand`oNa
³iii´ Aa*laaidtma\

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³Aa´pUNa-vaa@yaona ]<art . p`Sna ko ilae 2 A=\k. ³kovalaM p`SnaOkma\´ 1×2Ä2
³i´ ººººivaVayau>ona saaQaunaa saupu~oNaºººº .
³ii´ ººººSava-rIoºººº.

7. naaT\yaaMSa:
³A´ ekpdona ]<art. p`%yaok p`Sna ko ilae ½ A=\k. ³kovalaM p`SnaWyama\´ 2×½Ä1
³i´ iSaSaUnaama\ÀsvaiSaSaUnaama\
³ii´ Baayaa-yaama\
³iii´ SaOvyaa
³Aa´ pUNa-vaa@yaona ]<art . p`Sna ko ilae 2 A=\k. ³kovalaM p`SnaOkma\´ 1×2Ä2

³i´ ºººº d`aOpdIM VUtoºººº .
³ii´ ººººsvap%naIM SaOvyaaM pu~M raoihtM ca ºººº.

8. Baavaaqa-¹sambanQaI [sa p`Sna ko ]<ar maoM baccao kovala pd BaI ila#a sakto hoOM. 4×½Ä2
³k´ ³i´ baaoQayait ³ii´ laaoBa: ³iii´ WaraiNa ³iv´ %yajaot\
Aqavaa ³OR´
[sa p`Sna ko ]<ar maoM baccao ide gae tIna ivaklpaoM sao ek Sauw Baavaaqa- ila#a sakto hoOM. 2×1Ä2

³#a´ ³I´ ³i´ [h saMsaaro sa%yayaugasya BaUYaNa$p: maanQaata naRp: Aip Amarao na jaat:.
³II´ ³iii´ duYT: jana: सह#ैःiSaxaaivad\iBa: iSaxamaaNa: Aip sva svaBaavaM na %yajait.

9. Anvaya¹sambanQaI [sa p`Sna ko ]<ar maoM baccao kovala pd BaI ila#a sakto hoOM. 4×½Ä2
³i´ Baaojarajaona ³ii´ pHcaaSat\ ³iii´ saPtmaasa ³iv´ Baao>vya:

10 . vaa@yaaMSa¹sambanQaI [sa p`Sna ko ]<ar maoM baccao kovala ]<ar sa=\#yaa BaI ila#a sakto hoOM. 4×½Ä2
³i´ svaaya<amaokantgauNaM ivaQaa~a ³A´ ivainaima-tM Cadnama&tayaa:.
³ii´ naOkonaaip samaM gata vasaumatI ³ba´ naUnaM %vayaa yaasyait.
³iii´ prIxaaqa-mauVtao|isma ³sa´ gaRhsqaaEama­p`yaaogaSaalaayaama\.
³iv´ [dmaV mayaa labQa ³d´ imamaM p`aPsyao manaaorqama\.

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