CBSE Class 12 Odia Question Paper 2019

SET-4

Series BVM Code No. 13
Candidates must write the Code on
the title page of the answer-book.
Roll No.

 ¨÷ɧ¨†ÿ÷sç 7 ¨õÏæ ¯ÿçÉçÎ Lÿç œÿæ ’ÿßæLÿÀÿç {’ÿQ#œÿçA >ÿ
 ¨÷ɧ¨†ÿ÷Àÿ ÝæÜÿæ~ ¨s {Lÿæ~{Àÿ ’ÿçAæ¾æB$#¯ÿæ {Lÿæxÿ œÿºÀÿ DˆÿÀÿ ¨†ÿ÷Àÿ ¨÷$þ
¨õÏæ{Àÿ ÀÿÜÿç¯ÿæ Aæ¯ÿÉ¿Lÿ >
 ¨÷ɧ¨†ÿ÷{Àÿ 14sç ¨÷ɧ Adç Lÿç œÿæ AæÀÿ»Àÿë {’ÿQ#œÿçA >
 ¨÷ɧ¨†ÿ÷Àÿ Lÿ÷þæZÿ DˆÿÀÿ {àÿQæ AæÀÿ» LÿÀÿç¯ÿæ ¨í¯ÿöÀÿë D¨¾ëNÿ ×æœÿ{Àÿ
{àÿQ >
 ¨÷ɧ¨†ÿ÷ ¨|ÿç¯ÿæ¨æBô 15 þçœÿçsú Óþß ’ÿçAæ¾ç¯ÿ > ¨÷ɧ¨†ÿ÷ 10.15 þçœÿçsú Óþß{Àÿ ¯ÿ~cœÿ
LÿÀÿæ¾ç¯ÿ > {†ÿ~ë 10.15 vÿæÀÿë 10.30 þçœÿçsú ¨¾ö¿;ÿ ¨Àÿêäæ$öê {Lÿ¯ÿÁÿ ¨÷ɧ¨†ÿ÷ ¨|ÿç{¯ÿ
F¯ÿó F Óþß{Àÿ DˆÿÀÿ ¨ëÖçLÿæ{Àÿ {LÿÜÿç Lÿçdç {àÿQç ¨æÀÿç{¯ÿ œÿæÜÿ] >
 Please check that this question paper contains 7 printed pages.
 Code number given on the right hand side of the question paper should be
written on the title page of the answer-book by the candidate.
 Please check that this question paper contains 14 questions.
 Please write down the Serial Number of the question before
attempting it.
 15 minute time has been allotted to read this question paper. The question
paper will be distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the
students will read the question paper only and will not write any answer on
the answer-book during this period.

HÝçAæ
ODIA
Óþß : 3 W+æ ¨í‚ÿö ÓóQ¿æ : 100
Time allowed : 3 hours Maximum Marks : 100

13 1 P.T.O.

‘Lÿ’ ¯ÿçµÿæS
1. A[ÿë{bÿ’ÿsç ¨Þç ¨÷ÉS § ëÝçLÿÀÿ DˆÿÀÿ ’ÿçA > 5 2=10

SóS H Sf¨†ÿç Àÿæf†ÿ´ LÿæÁÿÀÿë LÿsLÿ $#àÿæ HÝçÉæÀÿ Àÿæf[ÿê†ÿçLÿ
{Lÿ¢ÿ÷×Áÿê > {Óvÿæ{Àÿ {µÿæ[ÿúÓàÿæ¯ÿ ¨÷†ÿç[ÿç™# Àÿí{¨ f{~ Óë{¯ÿ’ÿæÀÿ
A¯ÿ×æ[ÿ LÿÀÿë$#{àÿ > ¯ÿæÀÿ¯ÿæsê ’ÿëSö †ÿæZÿÀÿ [ÿç¯ÿæÓ×Áÿê $#àÿæ > Lÿçdç {Óð[ÿ¿
ÓÜÿ {Óvÿæ{Àÿ ÀÿÜÿç {Ó ÉæÓ[ÿ Lÿæ¾ö¿ ¨Àÿç Áÿ[ÿæ LÿÀÿë$#{àÿ > ¨ëÀÿê ¾ç¯ÿæ
¨æBô fSŸæ$ ÓÝLÿ LÿsLÿLÿë ØÉö LÿÀÿë$#àÿæ > ÓæþÀÿçLÿ ’ÿõÎç{Lÿæ~Àÿë
ÓëÀÿäç†ÿ H Àÿæf[ÿê†ÿçÀÿ SëÀÿë†ÿ´ ¯ÿÜÿ[ÿ LÿÀÿç LÿsLÿ FLÿ Óþõ• [ÿSÀÿê $#àÿæ >
LÿsLÿ A™#LÿæÀÿ [ÿ Lÿ{àÿ HÝçÉæ A™#Lÿõ†ÿ {ÜÿæB¨æÀÿë [ÿ$#àÿæ, {Ó$#¨æBô
HÝçÉæLÿë þÀÿÜÿtæ AþÁÿ{Àÿ LÿsLÿ ¨÷{’ÿÉ LÿëÜÿæ¾æB$#àÿæ > HÝçAæþæ[ÿZÿ
ÓóÔÿõ†ÿç H A$ö[ÿê†ÿçLÿë þš LÿsLÿ ¨÷µÿæ¯ÿç†ÿ LÿÀÿë$#àÿæ, ¨í¯ÿö D¨LÿíÁÿ H
¨ÊÿçþæoÁÿÀÿ SÝfæ†ÿÀÿæf¿þæ[ÿZÿ µÿç†ÿ{Àÿ LÿsLÿ{Àÿ ¨÷¯ÿæÜÿç†ÿ þÜÿæ[ÿ’ÿê
Sþ[ÿæSþ[ÿ ¨æBô ¯ÿ¿¯ÿÜÿõ†ÿ {ÜÿæB$#àÿæ > Bó{Àÿf ¯ÿ~çLÿþæ{[ÿ þÜÿæ[ÿ’ÿê
¨${Àÿ Óºàÿ¨ëÀÿLÿë ÜÿêÀÿæ Óó™æ[ÿ{Àÿ ¾æB$#{àÿ > LÿsLÿ{Àÿ {Óþæ[ÿZÿÀÿ
¯ÿæ~çf¿ {Lÿævÿç $#àÿæ > ¯ÿæÀÿ¯ÿæsê ’ÿëSöÀÿ Óë¯ÿæ’ÿæÀÿ þæ{[ÿ D¨LÿíÁÿ AoÁÿ{Àÿ
Bó{Àÿf ¯ÿ~çLÿþæ[ÿZÿë ÓëÀÿäæ ¨÷’ÿæ[ÿ LÿÀÿç¯ÿæ ¨æBô ’ÿæßê $#{àÿ > {†ÿ~ë
LÿsLÿÀÿ ¨÷æ™æ[ÿ¿ AÓæ™æÀÿ~ $#àÿæ LÿÜÿç{àÿ A†ÿ¿ëNÿç {Üÿ¯ÿ [ÿæÜÿ] >
BÎBƒçAæ Lÿ¸æ[ÿê ¯ÿó{Sæ¨ÓæSÀÿÀÿ D¨LÿíÁÿ AoÁÿ þæ[ÿZÿ{Àÿ {¾Dô
¯ÿæ~çf¿ ¯ÿ¿¯ÿÓæß `ÿÁÿæB$#{àÿ †ÿæÜÿæ HÝçÉæÀÿ ¯ÿ¢ÿÀÿ þæ[ÿZÿ ’ÿ´æÀÿæ [ÿçߦç†ÿ
{ÜÿD$#àÿæ > ’ÿäç~ µÿæÀÿ†ÿÀÿ LÿÀÿþƒÁÿ H Lÿ~öæsLÿ Aæ’ÿç ×æ[ÿ{Àÿ àÿç$#¯ÿæ
¾ë• ¨æBô Lÿ¸æ[ÿê {Lÿ¯ÿÁÿ þæ’ÿ÷æf ’ÿëSö D¨{Àÿ Óó¨í~ö [ÿçµÿöÀÿ LÿÀÿë
[ÿ$#àÿæ >
¨÷ɧæ¯ÿÁÿê :
(Lÿ) LÿsLÿ LÿæÜÿ]Lÿç SëÀÿë†ÿ´¨~í ö $#àÿæ ?
(Q) Óë{¯ÿ’ÿæÀÿþæ{[ÿ {LÿDô Lÿæ¾ö¿ LÿÀÿë$#{àÿ ?
(S) þÜÿæ[ÿ’ÿêLÿë LÿæÜÿ]Lÿç SëÀÿë†ÿ´ ’ÿçAæ ¾æB$#àÿæ ?
(W) LÿsLÿÀÿ ¨÷æ™æ[ÿ¿ AÓæ™æÀÿ~ $#àÿæ {¯ÿæàÿç LÿæÜÿ]Lÿç LÿëÜÿæ¾æBdç ?
(Yÿ) HÝçÉæÀÿ ¯ÿ¢ÿÀÿ SëÝçLÿ Lÿç µÿíþçLÿæ [ÿç¯ÿöæÜÿ LÿÀÿë$#{àÿ ?
13 2

‘Q’ ¯ÿçµÿæS
2. {SæsçF ¯ÿçÌß{Àÿ ¨÷¯ÿ¤ÿ {àÿQ > 8

(Lÿ) HÝçÉæÀÿ ¨æBLÿ ¯ÿç{’ÿ÷æÜÿ
(Q) [ÿæÀÿê ÓÉNÿêLÿÀÿ~
(S) Óêþæ;ÿ{Àÿ ¯ÿçd矆ÿæ¯ÿæ’ÿê Lÿæ¾ö¿LÿÁÿæ¨
3. †ÿëþ AoÁÿ{Àÿ A¨¨ëÎçÀÿ ÉçLÿæÀÿ {ÜÿD$#¯ÿæ ÉçÉëþæ[ÿóLÿÀÿ ÓëÀÿäæ àÿæSç
fçàÿâæ¨æÁÿZÿë [ÿç{¯ÿ’ÿ[ÿ ¨†ÿ÷ {àÿQ > 7

Lÿçºæ
†ÿëþ AoÁÿÀÿ Éçäæ¯ÿ¿¯ÿ×æ{Àÿ {’ÿQæ {’ÿB$#¯ÿæ {Éæ`ÿ[ÿêß A¯ÿ×æ
Óó¨Lÿö{Àÿ DaÿÉçäæ™#LÿæÀÿêZÿÿ ’ÿõÎç AæLÿÌö~ LÿÀÿç ¨÷†ÿçLÿæÀÿ ¨æBô [ÿç{¯ÿ’ÿ[ÿ
LÿÀÿ >
‘S’ ¯ÿçµÿæS

4. (Lÿ) ¯ÿç¨Àÿê†ÿæ$ö{¯ÿæ™Lÿ ɱÿ {àÿQ > (5sçÀÿ) 5

ÿD’ÿæÀÿ, ™æþ}Lÿ, [ÿçÀÿ{¨ä†ÿæ, D’ÿú¯ÿçS§, Lÿõ†ÿ÷çþ, Óþ, {ÀÿæSê
(Q) A$öS†ÿ ¨æ$öLÿ¿ ’ÿÉöæA > (5sçÀÿ) 5

SçÀÿçÉ-SçÀÿêÉ, {SæàÿLÿ-{Sæ{àÿæLÿ, {LÿæÉ-{LÿæÌ,
Aµÿç[ÿß-Aµÿç{[ÿß, †ÿíÁÿæ-†ÿëÁÿæ, †ÿÀÿ~ç-†ÿÀÿ~ê, ¯ÿçÌ-¯ÿçÓ
5. (Lÿ) µÿ÷þ Óó{Éæ™[ÿ LÿÀÿ > (5sçÀÿ) 5

¨çßíÌ, ¯ÿçÌ~ö, µÿíþçÎ, ¯ÿÌ}ßæ[ÿ, ¯ÿçÉë•çLÿÀÿ~, AS÷êþ, þíˆÿöê
(Q) FLÿ ¨’ÿ{Àÿ ¨÷LÿæÉ LÿÀÿ > (5sçÀÿ) 5

ÉÀÿêÀÿ Óó¯ÿó™êß; ¾æÜÿæ ¨í¯ÿöÀÿë Éë~æ¾æB[ÿ$#àÿæ; ¨ç†ÿæZÿÀÿ µÿ÷æ†ÿæ;
µÿæÌæ ÉæÚ{Àÿ ¨÷¯ÿê~; ÚêÀÿ A[ÿëSæþê; A[ÿëÓ¤ÿæ[ÿ LÿÀÿç¯ÿæÀÿ Bbÿæ;
Óëf[ÿÀÿ µÿæ¯ÿ
13 3 P.T.O.

‘W’ ¯ÿçµÿæS

6. ‘‘Ó´fæ†ÿçÀÿ B†ÿçÜÿæÓ ¯ÿç{ÉÌ µÿæ{¯ÿ Éçäæ LÿÀÿç¯ÿæ ¨÷{†ÿ¿ß Ó´fæ†ÿç¯ÿûÁÿ
¯ÿ¿NÿçÀÿ Lÿˆÿö¯ÿ¿’’ — Aæ{àÿæ`ÿ[ÿæ LÿÀÿ > 8

Lÿçºæ
ÉçäæLÿë Aæþ {’ÿÉ{Àÿ {ÉÌ ×æ[ÿ [ÿ {’ÿB ÉêÌö×Áÿ ’ÿçAæ¾ç¯ÿ > Àÿ`ÿç†ÿ
{¯ÿæàÿç {àÿQLÿ LÿæÜÿ]Lÿç þ{[ÿæNÿ LÿÀÿçd;ÿç ?
7. Ó¨÷Óèÿ ÓÀÿÁÿæ$ö {àÿQ > 5

¨ë~ç [ÿí†ÿ[ÿ Aµÿç[ÿß AæÀÿ» {ÜÿD vÿçLÿú {ÓÜÿç Þèÿ{Àÿ >
{ÓÜÿç f[ÿ†ÿæ, {ÓÜÿç ¨÷†ÿç[ÿç™#, ¯ÿ¿¯ÿ™æ[ÿ {Lÿ¯ÿÁÿ Óþß >
Lÿçºæ
þæ†ÿ÷ {¾Dô ¯ÿæßë, ÓàÿçÁÿ, Aæ{àÿæLÿ H Dˆÿæ¨ ¨æBô {Ó fê¯ÿþæ[ÿóLÿÀÿ
¯ÿæÓµÿíþç{ÜÿæBdç, {Ó$#Àÿë {SæsçF D~æ {Üÿ{àÿ Lÿ~ AæD {Ó ¯ÿæÓµÿíþç
{ÜÿæB ÀÿÜÿç¯ÿ ?
8. [ÿç{þ§æNÿ ¨÷ɧSÝë çLÿÀÿ DˆÿÀÿ Óó{ä¨{Àÿ ’ÿçA > (3sçÀÿ) 3 2=6

(Lÿ) ÓLÿÁÿ ¨÷LÿæÀÿ ¯ÿç¨È¯ÿ þíÁÿ{Àÿ {LÿDô [ÿçSíÞ LÿæÀÿ~ ¯ÿç’ÿ¿þæ[ÿ ?
(Q) Óþ{Ö ¨ævÿ ¨ÞçÓæÀÿç¯ÿæ ¨¾ö¿;ÿ {¾æf[ÿæLÿë ¨LÿæB ÀÿQ#{àÿ Lÿ~
AÓë¯ÿç™æ {Üÿ¯ÿ ?
(S) ¯ÿæÀÿç¯ÿæÜÿLÿë {Lÿæ~æLÿö þ¢ÿçÀÿ Lÿç ¯ÿæˆÿöæ H Sæ$æ Éë~æB¯ÿ ?
(W) ¨÷{†ÿ¿Lÿ fæ†ÿçÀÿ ¨÷æ`ÿê[ÿ B†ÿçÜÿæÓ{Àÿ Lÿ~ D¨×æ¨[ÿ LÿÀÿæ¾æBdç >
(Yÿ) µÿæÀÿ†ÿêß {àÿæ{Lÿ LÿæÜÿ]Lÿç ¨ævÿ ¨ÞçÓæÀÿçàÿæ ¨{Àÿ Aæ{þÀÿçLÿæ
dæÝçAæÓç¯ÿæLÿë Üÿë[ÿæÜÿæ;ÿç ?

13 4

9. DˆÿÀÿ ¨¾ö¿æßÀÿë vÿçLÿú DˆÿÀÿsç ¯ÿædç {àÿQ > 4 1 =4

(Lÿ) AæS LÿæÁÿ{Àÿ ¨Àÿêäæ üÿÁÿ {Lÿ{†ÿ$Àÿ{Àÿ ¯ÿæÜÿæÀÿë$#àÿæ ?
(i) FLÿæ $Àÿ{Lÿÿ
(ii) ’ÿëB$Àÿ{Àÿ
(iii) †ÿç[ÿç$Àÿ{Àÿ
(iv) Àÿç$Àÿ{Àÿ
(Q) {LÿDô {’ÿÉ{Àÿ Së~ A{¨äæ {¨÷æ¨æSƒæ Üÿ] ¯ÿç{ÉÌ Lÿæþ Lÿ{Àÿÿ ?
(i) Aæ{þÀÿçLÿæ{Àÿ
(ii) µÿæÀÿ†ÿ{Àÿ
(iii) `ÿê[ÿú{Àÿ
(iv) {¾Dô {’ÿÉ{Àÿ {àÿæ{Lÿ [ÿçfÀÿ Lÿˆÿö¯ÿ¿ H A™#LÿæÀÿ
Óó¨Lÿö{Àÿ Aj
(S) LÿçF DLÿ#ÁÿÀÿ B†ÿçÜÿæÓ {¯ÿæàÿç {àÿQLÿ LÿÜÿçd;ÿç ?
(i) [ÿêÁÿæ`ÿÁÿ [ÿæ$ÿ
(ii) fSŸæ$
(iii) ¨†ÿç†ÿ¨æ¯ÿ[ÿ
(iv) [ÿêÁÿæ’ÿ÷ç[ÿæ$ÿ

(W) LÿçF ’ÿ´ç†ÿêß ÉçäLÿ †ÿëàÿ¿ ?
(i) ÓæÜÿç†ÿ¿
(ii) ™þö
(iii) B†ÿçÜÿæÓ
(iv) ’ÿÉö[ÿ

10. þ[ÿëÌ¿-fê¯ÿ[ÿÀÿ DˆÿÀÿ~ ‘‘¨çèÿÁÿæÀÿ AµÿçÓæÀÿ’’ Lÿ¯ÿç†ÿæ{Àÿ Lÿç¨Àÿç
¨÷†ÿçüÿÁÿç†ÿ ’ÿÉöæA > 7
Lÿçºæ
‘‘¯ÿ¢ÿêÀÿ ¯ÿçÀÿÜÿ`ÿç;ÿæ’’ Lÿ¯ÿç†ÿæ{Àÿ f[ÿ½µÿíþçÀÿ A[ÿëÀÿæS ÓÜÿç†ÿ ¨÷Lÿõ†ÿç A[ÿëÀÿæS
Óþ[ÿ´ç†ÿ — Aæ{àÿæ`ÿ[ÿæ LÿÀÿ >
13 5 P.T.O.

11. Ó¨÷ÓóS ÓÀÿÁÿæ$ö {àÿQ > ({SæsçF) 5

(i) Ɇÿæ±ÿêÀÿ ÓçóÜÿ’ÿ´æÀÿë AæÓçAdç ’ÿí†ÿ
Aæ~çAdç ¯ÿæˆÿöæ µÿ¯ÿçÌ¿†ÿ
fê¯ÿ[ÿÀÿ Óóµÿæ¯ÿ[ÿæ ¾Üÿ] þíˆÿ}þæ[ÿ
[ÿæB ¾Üÿ] ¨÷æ`ÿêÀÿ ¨÷æ;ÿÀÿ >
(ii) ¯ÿݨ~ {ÓÜÿç A{;ÿ Óë•æ ¾æÀÿ
{ÓòÀÿµÿ ãÜÿsë$æF F ÓóÓæÀÿ
12. [ÿç{þ§æNÿ ¨÷ɧ SëÝçLÿÀÿ DˆÿÀÿ Óó{ä¨{Àÿ ’ÿçA > (3sçÀÿ) 3 2=6

(Lÿ) Óí¾ö¿ZÿÀÿ ¯ÿç’ÿæßLÿæÁÿê[ÿ ’ÿõÉ¿ Lÿç¨Àÿç $#àÿæ ?
(Q) †ÿ¨Ó´ç[ÿê Óê†ÿæ {LÿDô D{”É¿{Àÿ ¨†ÿ÷ {àÿQ#$#{àÿ ?
(S) ¨çèÿÁÿæ LÿæÜÿ]Lÿç [ÿçfLÿë Ó¨}~ê {¯ÿæàÿç LÿÜÿçdç ?
(W) ¾ëS¾ëS ™Àÿç þæ[ÿ¯ÿAæŠæLÿë LÿçF ¨êÝæ {’ÿBdç ?
(Yÿ) Àÿæfæþæ{[ÿ LÿæÜÿæLÿë {ÉæÌ~ LÿÀÿç LÿæÜÿæLÿë {¨æÌ~ LÿÀÿëd;ÿç ?
13. DˆÿÀÿ ¨¾öæßÀÿë vÿçLÿú DˆÿÀÿ ¯ÿædç {àÿQ > 4 1 =4

(Lÿ) Lÿ¯ÿçóLÿ Óþß{Àÿ Àÿæfæ-¨÷fæóLÿ Óó¨Lÿö Lÿç¨Àÿç $#àÿæ ?
(i) ¨ç†ÿæ-¨ë†ÿ÷ ¨Àÿç
(ii) ÓçóÜÿ-ÉÉLÿ ¨Àÿç
(iii) ¯ÿæf-¨æÀÿæ ¨Àÿç

(iv) ¨÷µÿë-µÿõ†ÿ¿ ¨Àÿç

(Q) Óê†ÿæ Lÿç¨Àÿç ¨†ÿ÷ {àÿQë$#{àÿ ?
(i) {ÉæLÿæµÿçµÿí†ÿæ{ÜÿæB
(ii) Üÿõ’ÿß ¯ÿçLÿÁÿ{Àÿÿ
(iii) CÌöæ[ÿ´ç†ÿæ {ÜÿæB

(iv) µÿæ¯ÿ¨÷¯ÿ~†ÿæ{Àÿ

13 6

(S) ¨çèÿÁÿæÀÿ AóS Lÿç¨Àÿç ¨ëàÿLÿç†ÿ {ÜÿD$#àÿæ ?
(i) ¯ÿÀÿÌæÀÿ [ÿê¨ üÿëàÿ ¨Àÿç
(ii) ¯ÿÓ;ÿÀÿ ¨’ÿ½ ¨Àÿç
(iii) S÷ê̽Àÿ þàÿâêüÿëàÿ ¨Àÿç

(iv) ¯ÿÌöæÀÿ Lÿëþ’ë ÿ ¨Àÿç
(W) {LÿDô J†ÿë{Àÿ {S樯ÿ¤ÿëZÿ Üÿõ’ÿß{¯ÿ’ÿ[ÿæ D’ÿú{¯ÿÁÿç†ÿÿ
{ÜÿæBDvÿç$#àÿæ ?
(i) S÷ê̽
(ii) ¯ÿÌöæ
(iii) Éê†ÿ

(iv) ¯ÿÓ;ÿ

14. {¾ {Lÿò~Óç ’ÿëBsç ¨÷ɧÀÿ DˆÿÀÿ ’ÿçA > 2 5=10

(Lÿ) Àÿæfê¯ÿ{àÿæ`ÿ[ÿóLÿ D†ÿú$æ[ÿ H ¨†ÿ[ÿÀÿ LÿæÀÿ~ Lÿ~ ?
(Q) ‘‘†ÿ$æ¨ç {†ÿæÀÿ ¨†ÿæLÿæÀÿ fß {ÜÿD’’ — FÜÿæ {LÿDô ¨÷ÓóS{Àÿ
LÿëÜÿæ¾æBdç >
(S) SóSæ[ÿ’ÿê{Àÿ {[ÿòµÿ÷þ~ LÿÀÿç¯ÿæ Ws~æ Óó¨Lÿ}†ÿ Ó½õ†ÿç A{ÉæLÿLÿë
Lÿç¨Àÿç ¨÷µÿæ¯ÿç†ÿ LÿÀÿç$#àÿæ ?
(W) Lÿbÿ¨þæóÓ µÿä~ Óó¨Lÿö{Àÿ Àÿæfæ Lÿç [ÿçшÿç {[ÿ{àÿ ?

13 7 P.T.O.