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CBSE Class 12 Marking Scheme 2021 for Physics

CBSE Class 12 Marking Scheme for Physics is available here. Use these marking scheme to understand the best way to answer the Sample Paper provided for practice. More Detail
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About CBSE Class 12 Marking Scheme 2021 for Physics

CBSE Class 12 Marking Scheme 2021 for Physics is available here for free download. Published by CBSE for Class 12, this sample paper can be viewed online or downloaded as a PDF (7 pages). Candidates preparing for Class 12 can use CBSE Class 12 Marking Scheme 2021 for Physics to understand the exam pattern, the type of questions asked, and the overall difficulty level.

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CBSE Class 12 Marking Scheme 2021 for Physics – Text

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Page 1

Class –XII

PHYSICS (Theory)

SQP Marking Scheme 2020-21

Sr. VALUE POINTS Marks
No.
1 Magnetic dipole moment 1

2 Any one use of micro waves 1

OR

1:1

3 zero 1

4 Remains same 1

OR

7.707A, 50Hz ½+½

5 h/2 1

6 4eV 1

7 Antinutrino 1

OR

Electron

8 Decreases 1

OR

25Hz

9 Dynamic resistance =change in voltage/change in current=1ohm 1

10 Photodiode 1

11 a) Both A and R are true and R is the correct explanation of A 1

12 b)Both A and R are true and R is the correct explanation of A 1

13 c)A is true but R is false 1

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Page 2

14 b) Both A and R are true but R is NOT the correct explanation of A 1

15 1.c) Copper 4x1 =
4
2.a) car

3.c) zero

4.a) -q

5 b)1.9105 Nm2/C leaving the surface

(any 4 parts to be attempted)

16 1. b) Its critical angle with reference to air is too small 4x1=4

2. a) 2.42

3. c) high refractive index
4. d) increase

5. d) less than first

(any 4 parts to be attempted)

17 Explanation by showing magnetic field directions in all three regions 1
Concluding left of region 1 1

18 Plot of Intensity distribution of diffraction with proper labeling 2

OR

n/d=2/a
n=2d/a ,where d is separation between slit and a width of slit

19 Derivation including both terms electrostatic energy in system and in 1+1
external field

OR

Derivation of relation E=-dV/dr 1+1
Diagram of equipotential surfaces

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Page 3

20 Circuit diagram showing biasing of LED in F.B ½
Action of LED 1
For emission in visible range least band energy required is1.8eV ½

21 Calculation of magnetic flux =BA cos ,where =300 =√3/2^10-11Wb 1
Calculation of induced emf E=A cosdB/dt=0.5V 1

22 Path difference=3/2 1
Putting value we will get=3cm 1

23 Well labeled energy band diagram of n-type semiconductor 1

n-type semiconductor ½

electrons-majority charge carriers ½

24 Definition of each term ½+½
Diagram showing relation 1

OR

Bv/BH=tan 1
Putting values,=300 1

25 Two characteristics- virtual and enlarged image and same side of 1
object.
As u and v both negative, we get 1/v=1/u-1/f 1
Interpret y=mx+c ,plot of the graph

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Page 4

26 ½
for
each
plot

Induced current and power, sketch is same as shown above. 1
In case of circular coil, rate of change of area of the loop during its
passage out of field is not constant, hence induced current varies
accordingly.

½

t

27 Circuit diagram 1

1

1
Maximum current drawn will be at R=0

OR
1
Circuit diagram
½
Applying correct formula
½
And caluation of p.d=11.5V

Series resistor limits the current drawn from source 1

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Page 5

28 De-Broglie reasoned out that nature was symmetrical and two basic 1
physical entities –mass and radiation must be symmetrical.If radiation
shows shows dual aspect than matter should do so.

De-Broglie equation- 1
=h/P
For photon –
P=h/C
Therefore,h/P=C/=
As =h/√2mk

So,alpha particle will be having shortest de-Broglie wavelength 1
compared to deutrons.

OR

Main implications-
1. kinetic energy of emitted electrons depends upon frequency,but not
on intensisty of radiation 1
2.there exist a frequency of radiation below which no photoemission
takes place, how high intensity of radiation may be. 1
Explanation wave nature of radiation fails to explain photoelectric
effect 1

29 Derivation of frequency of radiation emitted when a hydrogen atom de 2
excites from level n to level (n-1).

 = me4 (2n-1) / (4)3 (h/2)3 n2 (n-1)2 1
Comparing for large values of n, with classical freuency  = v / 2r

30 One difference between nuclear fission and nuclear fusion 1

Calculating Q=((m) Fe-2(m) Al)C2 =26.90MeV 1
Justification not possible 1

31 (a) Statement of Gauss law 1

Proof of outward flux due to a point charge Q ,in vacuum within 2
gaussian surface, is independent of its size and shape

(b) Net electric field towards left=/ left 1

Net electric field towards right=/ right 1

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Page 6

OR

Definitionof ideal dipole +example ½+
½

Derivation of torque 2

Putting values in correct formula and solving,value of charge and 1
potential energy
Q=810-3 C 1
U=-8J

32 (a) Derivation of instantaneous current i=iosin (ωt +/2) 1

Reactance XC=1/C 1

Phasor diagram showing v and i relation in pure C 1

(b) Explanation that adding R it will behave RC series ac circuit 1+1
Calcuation of current and phase angie

OR

(a)Principle of ac generator 1
(b)Well labelled diagram 1
Brief working and emf expression
2
(c) reason
1
33 (a) Definition of wavefront 1

(b) Ray diagram showing shapes of wavefront

1

1

(c) Proof of Snell’s law 2

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Page 7

OR

(a) choice of objective 1

(b) ray diagram of reflecting type telescope 2+1
Formula of magnifying power

(c) stating two advantages 2

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Document Details

Board / OrgCBSE
ExamClass 12
TypeMarking Scheme
Pages7
Updated30 Apr 2026