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Class 10 Sample Paper 2022 Solution Maths Term 2

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Class 10 Sample Paper 2022 Solution Maths Term 2 – Text

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Page 1

गिणत अयास  प (स II) क ा – X (2021-22) उरमाला बेलन का आयतन 1. = = 3.5 ⟹ r = 7 ; h:d= 3:7 बेलन का व प ृ ठ य े फल अथवा चबत ू रे को बनाने म' (य* ु त +म,ी का आयतन= कुएं से 1नकल2 +म,ी का आयतन चबत ू रे का े फल × चबत 2 ू रे क3 ऊंचाई = π× r ×h ⇒ 22 × 14 ×H = π×(7/2)2 ×20 ⇒ H = × × = मी = 2.5 मी × 2 2. x + k(2x + k – 1) + 2 = 0 को सरल करने पर x2 + 2kx + k(k – 1) + 2 = 0 यहाँ a= 1, b = 2k, c = k(k – 1) + 2 = k2-k+2 ू के +लए b - 4ac < 0 ⟹ 4k - 4(k -k+2) < 0 ⟹ k < 2 2 2 2 अवाIतJवक मल 3. AD=AC और BE=BC परRतु AB = AC + BC ⟹ AD+BE 10 4. sin 60 = 0 ⟹ l = √ 187 5. माXय = = 3.1 60 अथवा उपर2 सीमा 1न^न सीमा वग[-\चRह = 18 ⟹ = 18 ⟹ उपर2 सीमा + 1न^न सीमा = 36 वग[-माप =10 ⟹ उपर2 सीमा − 1न^न सीमा = 10 अतः वग[-अRतराल = 13-23 ू यक समान हa ⇒ b -4ac = 0 2 6. शR 7. an = a+(n-1)d ⇒ 93 = 17+4(n-1) ⇒ n = 20 अंत से सातवां पद = 20-7+1 = a14 = a+13d = 69 8. वजन (eकfा म') 45-55 55-65 65-75 75-85 85-95 95-105 105-115 Weight (in kg) कम[चाkरयl क3 संmया 7 12 17 z 32 6 10 No. of employees संचयी बारं बारता 7 19 36 36+z 68+z 74+z 84+z cf uदया है माXयक = 82 जोeक वग[-अंतराल 75-85 म' शा+मल है। 84 z 36 माXयक = l + { }× ℎ ⇒ 82 = 75 + [ ] × 10 हल करने पर z = 30 9. उ\चत रचना docs. 10. PQ = PR = 12 सेमी , चतभ ु ज ु[ का े फल = 60 वग[ सेमी अथवा उ\चत (माण

Page 2

11. उ\चत रचना XY 12. ∆XYA म' = tan 45० ⟹ XY = YA X Z YA XY ∆XYB म' = tan 30 ⟹ YB = √3XY ० Y 83 XY = मी √3 1 अथवा 45० 30० Y A 83 मी B माना AB भवन तथा CD (काश-Iत^भ है l C AB 60 ∆ABD म' B = tan 60 ⟹ BD = √ मी ० CE ∆ACE म' = tan 30० ⟹ AE = √3CE AE uदया है AE=BD ⇒ CE = 20 मी A 30० E ० 60 B D 13. (i) यहाँ a = 1500, d = 105, an = 2445 ⇒ n = 10 फ़रवर2 क3 तार2ख = 19 (ii) 10 तार2ख से फ़रवर2 म' शेष uदन = 20 फ़रवर2 क3 कुल फ3स = 1500 + (20-1) × 105 = 3495 1 माच[ को द2 गई कुल फ3स = 3495 + 1500 = 4995 ˆ 14. (i) बेलनाकार टं क3 भरने के बाद भ+ू मगत टं क3 म' बचे पानी का आयतन = [(1.57 × 1.44 × 0.95) – (3.14 × 0.6 × 0.6 × 0.7)] = 1.36 m3 छत क3 टं क3 का आयतन . × ." × ." × . (ii) भ+ू मगत टं क3 क3 मता = . × . × . = ⇒ 2 × छत क3 टं क3 का आयतन = भू+मगत टं क3 क3 मता अतः भ+ू मगत टं क3 से बेलनाकार टं क3 को दो बार भरा जा सकता है l docs.

Document Details

Board / OrgAglasem
ExamClass 10
TypeSolution
Pages2
Updated22 Jul 2026