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Uttarakhand Board Class 12 Sample Paper 2026 Chemistry

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Page 1

AGLASEM

UBSE
MODEL
Papers
2026

DOWNLOAD

Page 2

UBSE Sample Question Papers 2026

jksy ua0 eqfnzr i`’Bksa dh la[;k %
Roll N0. No. of printed pages :
130
Sample Paper (2026)
jlk;u foKku ¼lS)kfUrd½
CHEMISTRY (Theory)

le; & 3 ?k.Vs A iw.kkaZd: 70

Time : 3 Hours | Max. Marks : 70

funsZ'k % ¼i½ bl ç'u&i= esa dqy 26 ç'u gSAa lHkh ç'u vfuok;Z gSAa
Directions: There are in all 26 questions in this question paper. *All* questions are
*compulsory*.
(ii) ç'uksa gsrq fu/kkZfjr vad muds lEeq[k vafdr gSaA
Marks allotted to the questions are mentioned against them.
(iii) çR;sd ç'u dks /;kuiwoZd if<+;s rFkk leqfpr mÙkj nhft,A
Read each question carefully and answer to the point.
(iv) ç'u la[;k 1 cgqfodYih; ç'u gSA bl ç'u ds çR;sd [k.M ds mÙkj esa pkj fodYi fn;s x, gSaA
lgh fodYi viuh mÙkj iqfLrdk esa fyf[k,A ç'u la[;k 2 ls 5 rd fuf'pr mÙkjh; ç'u gS A

Question No.1 is a multiple choice question. 4 option are given in answer of each
part of this question. Write the correct option in your answer book. Question No.
2 to 5 are definite answer type question.

Page 3

(v) ç'u la[;k ,d dk çR;sd [kaM ,d vad dk gSA ç'u la[;k 2 ls 5 rd ,d vad ds ç'u gSA ç'u
la[;k 6 ls 15 rd nks vad ds ç'u gSA ç'u la[;k 16 ls 23 rd rhu vad ds ç'u gSA ç'u la[;k
24 ls 26 rd pkj vad ds ç'u gS ] ftlesa ç'u la[;k 26 dsl@ lzkrs vk/kkfjr ç'u gSA
Each part of the question No 1 carries one marks . Question No.2 to 5 are of 1
mark each . Question No.6 to 15 are of 2 marks each. Question No.16 to 23 are of
3 marks each. Question No. 24 to 26 are of 4 marks each, in which question No.
26 is case / source based question.
(vi) bl ç'u i= esa lexz ij dksbZ fodYi ugha gS rFkkfi dfri; ç'uksa esa vkarfjd fodYi çnku fd;k
x;k gSA ,sls ç'uksa esa dsoy ,d fodYi dk gh lgh mÙkj nhft,A
There is no overall choice in this question paper, however ,an internal choice has
been provided in few questions . Attempt only one of the given choices in such
question.
1. ¼d½ çFke dksfV dh vfHkfØ;k ds fy, osx fLFkjkad dk ek=d gksxk &

What is the unit of rate constant for first order reaction-
(i) mole lit -1 sec-1
(ii) sec-1
(iii) mol-2 lit² sec-2
(iv) mole/lit
¼[k ½ ,d jklk;fud inkFkZ ftldk mi;ksx tSfod uewuksa ds laj{k.k esa fd;k tkrk gS &
A chemical compound which is used for preservation of biological specimen called
-
(i) 40% aqueous solution of HCHO - Formalin

40 % Tkyh; foy;u HCHO QksesZfyu

(ii) Phenol

fQuksy
(iii) Ethanol

Page 4

bFksu‚y
(iv) Ethanoic Acid
,Fksuksbd ,flM
¼x½ ,d dhVuk'kh daiuh Mh Mh Vh dk mRiknu djrh gSA Mh -Mh -Vh dk çeq[k i;kZoj.kh; çHkko D;k
gS&
A pesticide company produces D.D.T what is the major environmental impact of
D.D.T
(i) ;g feêh dh moZjrk dks c<+krk gSA
It enhances soil Fertility
(ii) ;g ty lzksrksa dks çnwf"kr djrk gS vkSj tSo ladsæa .k djrk gSA
It contaminates water source and bioaccumulate
(iii) ;g ikS/kksa dh o`f) dks mÙksftr djrk gS
It promotes plants growth
(Iv) ;g iwjh rjg tSo vi?kVuh; gSA
It is completely biodegradable.
¼?k½ gsujh dk fu;e dgrk gS fd fdlh æo esa xSl dh foys;rk ds lekuqikrh gksrh gSA
Henry’s law states that the solubility of a gas in a liquid is directly proportional to
its:
(A) Temperature / rkieku
(B) Pressure / nkc
(C) Volume / vk;ru
(D) Density / ?kuRo
¼³½ vLirky esa ç;ksx gksus okyh —f=e jax ,ehu O;qRiUu ;kSfxd gksrs gSa bu jaxksa dks la'ysf"kr djus esa

e/;orhZ ;ksfxd gS A

Page 5

Hospitals use synthetic dyes which are amine derivative compounds. These dyes
are synthesized using intermediate compounds
(i) Anilene / ,sfuyhu
(ii) Diazonium Salt / Mkb,stksfu;e yo.k
(iii) Phenol/ fQuksy
(iv )Benzene Sulphonic Acid / cst
a hu lYQksfud ,flM
¼p ½ Mh Cy‚d rRo laØe.k rRo dgykrs gSa ysfdu fuEu rRoksa esa ls ,d rRo laØe.k rRo ugha gS
D block elements are called as transition elements but which among of the
following elements is not a transition element
(i )Cu
(ii )Mn
(iii )Zn
(iv )Cr
¼N½ fdlh bysDVªksM dh ekud bysDVªksM {kerk dks fdlds lkis{k ekik tkrk gS
Standard Electrode Potential of an electrode is measured relative to
¼i½ ekud gkbMªkstu bysDVªksM

/Standard Hydrogen Electrode

(ii) ftad bysDVªksM / Znic Electrode

(iii) d‚ij bysDVªksM / Copper Electrode

s /Sodium Electrode
(iv) lksfM;e bysDVªkM

¼t½ fdl milgla;kstu ;ksfxd milgla;kstu la[;k 6 gS

Which of the following Coordination Compound have 6 as there Coordination
Number

Page 6

(i ) [ Cu(NH3)4]+²
(ii) [ Fe (CN)6]-³
(iii)[ Ag (NH3)2 ]+¹
(iv)[ NiCl4 ]-²
funsZ'k % uhps fn, x, çR;sd ç'u esa ,d vfHkdFku ¼A½ vkSj ,d dkj.k ¼R½ fn;k x;k gSA bu dFkuksa
dks /;kuiwoZd i<+sa vkSj uhps fn, x, fodYiksa esa ls lgh mÙkj dk p;u djsaA
Direction : In each of the following questions, a statement of Assertion (A) is given
followed by a corresponding statement of Reason (R). Read both statements
carefully and choose the correct option from the choices given below.
(a) Both (A) and (R) are true, and (R) is the correct explanation of (A).

(A) vkSj (R)nksuksa lR; gSA, vkSj (R), (A) dk lgh O;k[;k djrk gSA

(b) Both (A) and (R) are true, but (R) is not the correct explanation of (A).

(A) vkSj (R)nksuksa lR; gS]ijUrq (R), (A) dh lgh O;k[;k ugh djrk gSA

(c) (A) is true, but (R) is false.

(A) lR; gS vkSj (R) vlR; gSA,

(d) Both (A) and (R) are false .

(A) vkSj (R) nksuksa vlR; gSA,

(>) vfHkdFku (A): fQuksy vYdksgy dh rqyuk esa vf/kd vEyh; gksrs gSa

Assertion (A): Phenol are more acidic than Ethanol

dkj.k (R): fQuksy ds vk;uu ds ckn cus QsuksDlkbM vk;u vuqukn }kjk LFkkbZ jgrk gSA

Reason (R): After the ionization of Phenol, Phenoxide ion is stable by Resonance .

(ञ) vfHkdFku (A) : foVkfeu (C) ¼,Ldksjfcd ,flM ½ ikuh esa ?kqyu'khy foVkfeu gS

Page 7

Assertion (A): Vitamin C (Ascorbic Acid )is a water soluble vitamin .

dkj.k (R): lHkh foVkfeu olk esa ?kqyu'khy gksrs gSaA

Reason (R): All vitamins are fat soluble
2- dkSu lk lsy iqu% fjpktZ fd;k tk ldrk gS
Which cell can be recharged
vFkok / OR
fdlh fOky;u dh fo|qr pkydrk fdl ij fuHkZj djrh gS
On what factor does the Electrical Conductivity of a solution depends .
3. D.N.A es dkSu lh lh 'kdZjk ikbZ tkrh gS
Which sugar is found in D.N.A
4. E.D.T.A fdl çdkj dk fyxsMa gS
Which type of ligand is E.D.T.A ?
5 . dksbZ Hkh v.kqla[;d xq.k fdl ij fuHkZj djrk gSA
On what factor does colligative property depends .

6. ySFa ksu‚bM ladqpu ds dkj.k LdSafM;e vkSj vkSj bfVª;e dh leku jklk;fud xq.k fn[kkrk gS A
bl ladqpu ds çHkko dks le>kb, A
Due to Lanthenoid contractions Scendium and Yttrium shows similar chemical
properties. Explain the effect of this contraction.
7. 25⁰ C rki ij Zn(s)|Zn++ (0.01M) || Cu++(0.1M) | Cu(s) ds fy, E.M.F fd x.kuk
fdft,A
E⁰cell = Zn++|Zn = -0.76v
Cu++| Cu = +0.34v

Calculate E.M.F of a given cell at 25⁰C Zn(s)|Zn++ (0.01M) || Cu++(0.1M) | Cu(s)
Given E⁰cell =

Page 8

Zn++|Zn = -0.76v
Cu++| Cu = +0.34v

8. 20 xzke lksfM;e gkbMª‚DlkbM (NaOH) dks i;kZIr ikuh esa ?kksydj 250 feyhyhVj dk ?kksy
cuk;k x;k gSA bl ?kksy dh eksyjrk D;k gS\
(ijek.kq Hkkj : Na = 23 u, O = 16 u, H = 1 u) .

What is the molarity of a solution made by dissolving 20 grams of sodium
hydroxide (NaOH) in enough water to make 250 mL of solution?
(Atomic masses: Na = 23 u, O = 16 u, H = 1 u)
9. gsyks ,jhu gsyks ,Ydsu dh rqyuk esa ukfHkd jkxh çfrLFkkiu vfHkfØ;kvksa ds çfr de fØ;k'khy
gksrs gSa D;ksa\
Explain why heloarenes are less reactive towards nucleophilic substitution
reaction then haloalkanes?
10. vUur ruqrk ij eksyj pkydrk Λ∞m fu/kkZj.k fdl fu;e ls fd;k tkrk gS ml fu;e dks

fyf[k, rFkk mldk ,d vuqç;ksx Hkh nhft,A
At infinite dilution, the molar conductivity Λ∞m is determined by which law?
Write that law and also give one application of it.

vFkok / OR

,d fo|qrh; vi?kVuh; lsy ds dSFkksM rFkk ,uksM ij vipf;r ,oa vkDlh—r gksus okys inkFkZ dh
ek=k Kkr djus okys lw= dks fyf[k, ,oa ;g fdl fu;e ij vk/kkfjr gS fu;e Hkh fyf[k, A
Write the formula for determining the amount of substance reduced at the
cathode and oxidized at the anode in an electrolytic cell, and state the law on
which it is based. Also, write the law.
11- tc vaMk mckyk tkrk gS mldk lQsn Hkkx ,Ycqfeu Bksl gks tkrk gS bls çksVhu lajpuk ds lanHkZ
esa le>kb, ] bl ?kVuk dks D;k dgrs gSAa

When an egg is boiled, the white part (albumen) containing albumin becomes
solid. Explain this phenomenon in terms of protein structure and name this
process.

Page 9

12-¼d½ xsfcz;y IFkkyhekbM vfHkfØ;k }kjk ,jksesfVd çkFkfed mEehn ugha cuk, tkrs gSa D;ksa

¼[k½ cst
a hu Mk;tksfu;e yo.k ds mi;ksx fyf[k, A
(a) Why are aromatic primary amines not prepared by Gabriel phthalimide
reaction?
(b) Write the uses of benzene diazonium salts.
13- vnZ~/kvk;qdky fdls dgrs gSAa fl) dhft, dh çFke dksfV ds vnZ~/kvk;qdky (t1/2) dk eku
vfHkdkjd inkFkZ dh çkjafHkd lkaærk ij fuHkZj ugha djrk gSA
What is half-life period? Prove that for a first-order reaction, the half-life period
(t½) is independent of the initial concentration of the reactant.
14- bFksu‚y 443K rki ij lkanz lYQ;qfjd vEy ds lkFk fØ;k dj futZyhdj.k ds Qy Lo#i
,Ydhu curk gS bl vfHkfØ;k dh fØ;kfof/k nhft,A
Ethanol reacts with concentrated H₂SO₄ acid at 443K temperature to form an
alkene through dehydration. Provide the mechanism of this reaction.
vFkok / OR
¼d½ ,Ydksgy ty esa vR;f/kd foy; gksrs gSa D;ksa\
¼[k½ lefer bZFkj vkSj vlefer bZFkj D;k gksrs gSa mnkgj.k nhft, A
(a) Why are alcohols highly soluble in water?
(b) What are symmetrical ethers and unsymmetrical ethers? Give examples.
15. [ Fe(CN)6]⁴- çfrpqca dh; gS tcfd [ Fe (CN)6]³- vupqca dh; gksrk gS D;ksa \

Why [ Fe(CN)6]⁴- Diamagnetic but [ Fe (CN)6]³- is Paramagnetic
vFkok / OR
fØLVy {ks= foikVu ÅtkZ (Δ𝑜) dks dkSu ls dkjd çHkkfor djrs gSa A
What factors influence the crystal field splitting energy (Δ₀)?

16 . lhlk lapk;d lsy dh vkos”ku ,oa fujkos'ku dh fØ;kfof/k dk jklk;fud lehdj.k lfgr O;k[;k

dhft, A

Page 10

Explain the mechanism of charging and discharging of a lead-acid storage cell with
chemical equations.
vFkok / OR
,d bZ/a ku lsy dh lsy vfHkfØ;k ds lkFk fp= vkjsf[kr dhft, tks mPp n{krk çnku dj ldsA
Draw a diagram of a fuel cell with its cell reaction that can provide high efficiency.
17- ijklj.k nko dks mi;qä mnkgj.k lfgr le>kb, bl foy; ds v.kqHkkj ds fu/kkZj.k ds fy, dSls
ç;ksx fd;k tkrk gS O;k[;k dhft,A
Explain osmotic pressure with a suitable example and describe how it is used for
determining the molecular weight of a solute . Explain.
vFkok / OR
jkmYV ds fu;e ls fopyu dks foLr`r :i esa le>kb, vkSj bldk mi;ksx m|ksxksa esa dgka fd;k
tkrk gS crkb, A
Explain Raoult's law deviation in detail and describe its application in industries.
18- milgla;kstu ;kSfxdksa esa fyxsaM~l dh D;k Hkwfedk gksrhA fofHkUu çdkj ds fyxsM
a ds çdkj ,oa
mnkgj.k nhft,A
What is the role of ligands in coordination compounds? Describe different types of
ligands with examples.
vFkok / OR
¼d½ K3[ Fe (CN)6] ,oa [ Cr(en)3]Cl3 dk I.U.P.A.C uke fyf[k,A

Write the I.U.P.A.C Name of K3[ Fe (CN)6] And [ Cr(en)3]Cl3.

¼[k½ [PtCl₂(NH₃)₂] }kjk çnf'kZr leko;ork dk o.kZu dhft,

Describe the isomerism exhibited by [PtCl₂(NH₃)₂].

19- fuEu jklk;fud vfHkfØ;k dks iw.kZ dhft,

(d) CH3-CH=CH2 + HBr peroxide →_______________________

(ख)C6H5X + CH3X + Na ----Dry ether------> _________________

Page 11

(ग) R-OH+ SOCl2 ---Pyridine------> _______ +___________ +__________

Complete the following Reactions
1.CH3-CH=CH2 + HBr ---peroxide-------> ______________
2.C6H5X + CH3X + Na ----Dry ether------> _________________
3. R-OH+ SOCl2 ---Pyridine------> _______ +___________ +__________

vFkok / OR

DyksjksQ‚eZ dks çdk'k vkSj ok;q dh mifLFkfr esa D;ksa laxfz gr ugha fd;k tkrk çfØ;k esa cuus okys
mRikn dk uke vkSj lw= fy[ksa rFkk blls cpus ds fy, D;k mik; fd, tkrs gSa ] fyf[k, A
Why is chloroform not stored in the presence of light and air? Write the name and
formula of the product formed in the process and describe the measures taken to
prevent it.
20- ,Ydksgy D;k gksrs gSa 1⁰ 2⁰ rFkk 3⁰ ,Ydksgy gkbMªkstuhdj.k ds Qy Lo#i vyx&vyx
mRikn curs gSa vius mÙkj dh iqf"V vfHkfØ;k nsdj dhft,A
What are alcohols? 1°, 2°, and 3° alcohols give different products upon
dehydrogenation. Justify your answer with a Suitable Reaction.
vFkok / OR

fQukWy dk mi;ksx ,aVhlsfIVd vkSj vkS"kf/k vuqç;ksxksa ds fy, fd;k tkrk gSA fQukWy ds lksfM;e
yo.k lksfM;e QsuksDlkbM dh fØ;k CO2 ls dh tkrh gS vfHkfØ;k dk uke nsrs gq, çkIr mRikn dk
uke ,oa lajpuk lw= nhft,A
Phenol is used for antiseptic and medicinal applications. When sodium phenoxide
reacts with CO₂, a product is formed. Give the name of the reaction, the product
formed, and its structural formula.
21- ,fYMgkbM vkSj dhVksu dh ukfHkd jkxh ;ksxkRed vfHkfØ;kvksa dh lajpukRed –f"Vdks.k ls rqyuk
dhft, A;g Hkh Li"V dhft, fd ,fYMgkbM dh vis{kk dhVksu ukfHkd jkxh vfHkfØ;kvksa ls de

fØ;k'khy D;ksa gksrs gSAa

Page 12

Compare the nucleophilic addition reactions of aldehydes and ketones from a
structural perspective. Also, explain why ketones are less reactive than aldehydes
towards nucleophilic addition reactions.
vFkok / OR

fuEu vfHkfØ;kvksa ds jklk;fud lehdj.k ,oa uke nhft,A
¼d½ ,d α gkbMªkstu ;qä ,fYMgkbM ruq {kkj dh mifLFkfr esa fØ;k dj β gkbMªksDlhC;wVsuy curk gS
ftldk ruq vEy ds lkFk vi?kVu djus ij vlar`Ir ,fYMgkbM nsrk gSA
¼[k½ cst
a yfMgkbM ds nks v.kq dh {kkj ds lkFk fØ;k djus ij ,d v.kq dk vip;u vkSj ,d v.kq
dk lksfM;e csatks,V esa v‚Dlhdj.k gksrk gSA
¼x½ α gkbMªkstu ;qä dkckWZDlhfyd vEy dk yky QkLQksjl dh mifLFkfr esa Dyksjhu ls fØ;kA
(a) An aldehyde with an α-hydrogen reacts in the presence of dilute alkali to form
β-hydroxybutanal, which upon treatment with dilute acid gives an unsaturated
aldehyde.
(b) Two molecules of benzaldehyde react with alkali, resulting in the reduction of
one molecule and the oxidation of the other to sodium benzoate. (c) Reaction of a
carboxylic acid with α-hydrogen with chlorine in the presence of red phosphorus.
22- fgalcxZ vfHkdeZd dk lw= fyf[k, bl vfHkdeZd ls 1⁰] 2⁰ rFkk 3⁰vehu esa fdl çdkj foHksn
djsx
a As
Write the formula of Hinsberg reagent and describe how it is used to distinguish
between 1°, 2° and 3° amines.
23. D.N.A rFkk R.N.A nksuksa U;wfDyd vEy gS ysfdu dk;Z fHkUu&fHkUu gS vuqokaf'kd lwpuk çaLdj.k
esa D.N.A rFkk R.N.A dh Hkwfedkvksa dh rqyuk dhft,A
Both DNA and RNA are nucleic acids but have different functions. Compare the
roles of DNA and RNA in the transmission of genetic information.

vFkok / OR

Xywdkst dh [kqyh lajpuk dh O;k[;k ds fy, fuEu ls lacaf/kr vfHkfØ;kvksa dks nhft,

Page 13

¼d½ ,fYMgkbM lewg dh mifLFkfrA
¼[k½ 5-OH lewg dh mifLFkfrA
¼x½ 5& dkcZu ;qä J`[a kyk dh mifLFkfrA
Explain the open-chain structure of glucose with the help of reactions related to
(a) the presence of an aldehyde group.
(b) the presence of 5 hydroxyl (-OH) groups
(c) the presence of a 6-carbon chain .
24 -¼d½ nj lehdj.k
K = 2.303/t log e [Ro]/ [ R ]
dks O;qfRir fdl çdkj fd;k tkrk gS vkSj ;g fdl dksfV dh nj lehdj.k gSA
¼[k½ çFke dksfV dh vfHkfØ;k ds fy, osx fLFkjkad dk eku 60 izfr lsdM
a gS vfHkdkjd dh çkjafHkd
lkaærk dk 1@16th Hkkx 'ks"k jgus rd vfHkfØ;k dks fdruk le; yxsxkA
(a) How is the rate equation K = 2.303 logₑ [R₀]ₜ [R] derived, and what order of
reaction does it represent?
(b) For a first-order reaction with a rate constant of 60 s⁻¹, how long will it take for
the concentration of the reactant to reduce to 1/16th of its initial concentration?

vFkok / OR

la?kV~V fl)kar ds vk/kkj ij le>kb, fd dqN vfHkfØ;k,a mPp rkieku ij vf/kd rhozrk ls gksrh gSA
Explain, based on the collision theory, why some reactions occur more rapidly at
higher temperatures.
25- ,d ç;ksx'kkyk esa ,d vKkr dkcZfud ;kSfxd us 2] 4 Mk;ukbVªks Qsfuy gkbMªsthu¼ 2] 4 DNP½ ds
lkFk ihyk vo{ksi fn;k ysfdu Qsgfyax fcy;u dks vipf;r ugha fd;kA

¼d½ ;kSfxd dh igpku dhft,A
¼[k½ mÙkj dh iqf"V ds fy, jklk;fud lehdj.k nhft,A
¼x½ vKkr ;ksfxd dk uke ,oa lajpuk lw= nhft,A

Page 14

In a laboratory, an unknown organic compound gave a yellow precipitate with 2,4-
dinitrophenylhydrazine (2,4-DNP) but did not reduce Fehling's solution. (a)
Identify the compound. (b) Provide chemical equations to confirm the answer.
(c) Give the name and structural formula of the unknown compound.

vFkok / OR

¼d ½ fuEufyf[kr ;kSfxdksa ds lajpuk lw= nhft,A
¼d½ 3 gkbMªkt
s h;C;wVsuy
¼[k½ 2&2 MkbZDyksjks,Fksuksbd vEy
¼[k½ D;k dkj.k gS fd cst
a ksbd vEy fÝMy Øk¶V vfHkfØ;k ugha nsrk gSA
¼x ½ HCOOH rFkk CH3COOH eSa dkSu çcy vEy gS A
(a) Write the the structure of the following compound
(i) 3 hydroxybuetenal
(ii) 2,2dichloroethanoic Acid
(b) What is the reason that benzoic acid does not give the Friedel-Crafts reaction?
(c) Which is the stronger acid between HCOOH and CH₃COOH?
26. Case Study:
A textile industry uses Potassium Dichromate (K₂Cr₂O₇) and Potassium
Permanganate (KMnO₄) for dyeing fabrics and as oxidizing agents. Aman, a
chemistry student, observed that K₂Cr₂O₇ is orange in colour, while KMnO₄ is deep
purple. His professor explained that these compounds undergo redox reactions,
making them useful in volumetric analysis and various industrial processes.

,d oL= m|ksx diM+kas dks jaxus vkSj v‚Dlhdkjd ds :i esa iksVSf'k;e MkbØkseVs (K₂Cr₂O₇ ) vkSj

iksVsf'k;e ijeSXusV (KMnO4 ) dk mi;ksx djrk gSA veu] ,d jlk;u foKku Nk= us ns[kk fd
K2Cr2O7ukjaxh jax dk gksrk gS] tcfd KMnO4 xgjs cSaxuh jax dk gksrk gSA muds çksQl
s j us le>k;k

Page 15

fd ;g ;ksfxd jsM‚Dl vfHkfØ;k,a djrs gSa ]ftlls og ek=kRed fo'ys"k.k vkSj fofHkUu vkS|ksfxd
çfØ;kvksa esa mi;ksxh gksrk gS A
1- Why is K2Cr2O7 used as an oxidizing agent? (1 mark)

K2Cr2O7 dks v‚Dlhdkjd ds :i esa D;ksa ç;ksx fd;k tkrk gS \¼1vad½
2 - What is the colour change when KMnO4 acts as an oxidizing agent in an acidic
medium? (1marks)
KMnO4 ds vEyh; ek/;e esa v‚Dlhdkjd ds :i esa dk;Z djrs le; jax ifjorZu D;k gksrk gS \¼ 1
vad½
3 - Write the balanced chemical equation for the reaction of KMnO 4 in acidic
medium. (2 marks)
KMnO4 dh vEyh; ek/;e ls vfHkfØ;k ds fy, larqfyr jklk;fud lehdj.k fy[ks \¼2 vad½

Page 16

jksy ua- eqfnzr i`’Bksa dh la[;k % 8
Roll No. No. of printed pages : 8
130 vkn”kZ iz”u i=&2026
jlk;u foKku ¼lS)kfUrd½
CHEMISTRY (THEORY)
le; % 3 ?k.Vs iw.kkZad % 70
Time : 3 Hours Max. Marks : 70

funsZ'k %&(i) bl iz”u&i= esa dqy 26 iz”u gSaA lHkh iz”u vfuok;Z gSaA
Directions: There are in all 26 questions in this question paper. All questions are
compulsory.
(ii) ç'uksa gsrq fu/kkZfjr vad muds lEeq[k vafdr gSaA
Marks alloted to the questions are mentioned against them.
(iii) çR;sd ç'u dks /;kuiwoZd if<+;s rFkk leqfpr mÙkj nhft,A
Read each question carefully and answer to the point.
(iv) ç'u la[;k 1 cgqfodYih; ç'u gSA bl ç'u ds çR;sd [k.M ds mÙkj esa pkj fodYi
fn;s x, gSaA lgh fodYi viuh mÙkjiqfLrdk esa fyf[k,A ç'u la[;k 2 ls 5 rd
fuf'pr mÙkjh; ç'u gSaA
Question No.1 is multiple choice question. Four options are given in answer of each part
of this question. Write correct option in your answer book. Question No. 2 to 5 are
definite answer type questions.
(v) ç'u la[;k 1 dk çR;sd [k.M ,d vad dk gSA ç'u la[;k 2 ls 5 rd ,d vad ds
ç'u gSaA ç'u la[;k 6 ls 15 rd nks vad ds ç'u gSaA ç'u la[;k 16 ls 23 rd rhu
vad ds ç'u gSaA ç'u la[;k 24 ls 26 rd pkj vad ds ç'u gSa] ftlesa ç'u la[;k 26
dsl@lzksr vk/kkfjr ç'u gSA
Each part of Question No. 1 carries one mark. Question No. 2 to 5 are of one
mark each. Question No. 6 to 15 are of two marks each. Question No. 16 to 23 are
of three marks each. Question No. 24 to 26 are of four marks each, in which
Question No. 26 is Case/Source based question.
(vi) bl ç'u&i= esa lexz ij dksbZ fodYi ugha gS rFkkfi dfri; ç'uksa esa vkarfjd fodYi
çnku fd;k x;k gSA ,sls ç'uksa esa dsoy ,d fodYi dk gh mÙkj nhft,A
There is no overall choice in this question paper, however, an internal choice has
been provided in few questions. Attempt only one of the given choices in such
questions.

Q. 1. ¼d½ foVkfeu B1 dk jklk;fud uke D;k gS & (1)
Chemical name of Vitamin B1 is.
(i) ,LdkfcZd vEy (ii) ,fMfid vEy (iii) jkbcks¶ysfcu (iv) Fkk;ehu
Ascorbic Acid Adipic Acid Riboflavin Thiamine

¼[k½ ;fn v)Z vk;qdky vfHkdkjd dh izkjfEHkd lkUnzrk ij fuHkZj ugah djrk gS rks vfHkfØ;k dh

dksfV gksxhA (1)
If the half life does not depend on the initial concentration of the reaction, then the order of
reaction will be.
(i) “kwU; (ii) izFke (iii) f}rh; (iv) r`rh;
Zero First Second Third
1|Page

Page 17

¼x½ K4 [Fe (CN) 6] esa ‘Fe’ dh mi lgla;kstu la[;k gS & (1)
Co-Ordination number of ‘Fe’ in K4 [Fe (CN)6]
(a) 4 (ii) 5 (iii) 6 (iv) 8

¼?k½ gsujh fLFkjkad KH dk eku (1)
Value of Henry’s Constant KH

(i) rki c<+us ij c<+rk gSA (ii) rki c<+kus ij de gksrk gSA
Increase with Increase in temperature  Decreases with Increase in temperature
(iii) fLFkj jgrk gSA (iv) igys c<+rk gS fQj ?kVrk gSA
Remains constant first increase then decreases

¼M+½ QSjkMs ds fo|qr vi?kVu ds izFke fu;e ds vuqlkj & (1)
According to Faraday’s first law of electrolysis
(i) V  I (ii) Q  t (iii) W  Q (iv) W  E

¼p½ iksVsf”k;e gkbMªkWDlkbM ds lkFk xeZ djus ij QkesZfYMgkbM nsrk gSA (1)
Formaldehyde on heating with potassium hydroxide given.
(i) esfFky ,YdksgkWy (ii) bFkkby QkesZV (iii) esFksu (iv) ,flfVyhu
Methyl alcohol Ethyl Formate Methane Acetylene

¼N½ ,sekbMks ls ,ehu cukus esa iz;qDr vfHkdeZd gSA (1)
Reagent used to converted amine from amide.
(i) Br2 / KOH (ii) NaOH / CaO (iii) HCl/ZnCl2 (iv) K2Cr2O7/H2SO4

¼t½ QkWLthu gS & Phosgene is
(a) PH3 (ii) POCl3 (iii) CS2 (iv) COCl2

funsZ”k& iz”u la[;k&1 ds vxys nks [k.Mksa esas] nks dFkuksa dks vfHkdFku (A) rFkk dkj.k (R) ds :Ik esa
fpfUgr fd;k x;k gSA fuEufyf[kr fodYiksa (i), (ii), (iii) rFkk (iv) esa ls pqudj budk lgh
mÙkj nhft,A

Direction : In next two parts of Question No. 1, there are two statements labeled as Assertion (A)
and Reason (R). From the following option (i), (ii), (iii) and (iv), select their correct
answers.
(i) A rFkk R nksuksa lgh gSa rFkk R, A dh lgh O;k[;k djrk gSA
Both A and R are correct and R is the correct explanation of A.
(ii) A rFkk R nksuksa lgh gSa ijUrq R, A dh lgh O;k[;k ugha djrk gSA
Both A and R are correct but R is not the correct explanation of A.

(iii) A lgh gS ijUrq R xyr gSA
A is correct but R is incorrect.
(iv) A rFkk R nksuksa xyr gSaA
Both A and R are incorrect.

2|Page

Page 18

¼>½ vfHkdFku (A) : d vkSj f CykWd ds ry jaxhu vk;u cukrs gSaA (1)
dkj.k (R) : bu rRoksa esa v;qfXer bysDVªkWu mifLFkr gksrs gSaA
Assertion(A) : The elements of d and f blocks produce coloured ions.
Reason (R) : Unpaired electrons are present in these elements.

¼¥½ vfHkdFku (A) : ekYVksl vkSj ysDVksl vipk;d “kdZjk ds mnkgj.k gSaA
dkj.k (R) % ekYVksl vkSj ysDVksl Qsgfyax foy;u vkSj Vkysu vfHkdeZd dks vipf;r djrs gSaA
Assertion (A): Maltose and lactose are examples of reducing sugars.
Reason : Maltose and lactose reduce fehling’s solution and Tollen’s regent.

Q.2 foVkfeu ‘D’ dk jklk;fud uke D;k gS\ (1)
What is the chemical name of Vitamin D.

Q.3 okWUV gkWQ xq.kkad dks le>kb,A (1)
Explain Van’t haff factor.

Q.4 yksds esa tax yxuk] pk¡nh dk cnjax gksuk] dkWij ,oa ihry ij gjs jax dk ysi gksuk fdl
izfØ;k ds dkj.k gksrk gSA (1)
In which process the rusting of icon, tarnishing of silver and the formation of a green coating
on copper and brass occur.

Q.5 milgla;ksth ;ksSfxd K2 [Zn (OH)4] dk IUPAC uke crkb,A (1)
Give the IUPAC name of coordination compound K2 [Zn (OH)4]

Q.6 uhps nh xbZ izFke dksfV dh vfHkfØ;k ds osx fLFkjkad ls v)kZ;q dh x.kuk dhft,A (2)
Calculate the half life of a first order reaction from their rate constants given below.
(i) 200 s-1 (ii) 2 min-1

Q.7 fuEu inksa dks le>kb, & (2)
Explain the following terms.
(i) fof”k’V pkydrk (ii) ekud bysDVªksM foHko
Specific conductivity Standard electrode Potential

Q.8 fuEu vfHkfØ;kvksa ls lEcfU/kr jklk;fud lehdj.k fyf[k,A (2)
Write chemical equation pertaining to following reactions.
(i) dkfcZy ,ehu vfHkfØ;k (ii) gSy oksYgkMZ tSfyaLdh vfHkfØ;k
(Carbyl amine reaction) (Hell Vollhard Zelinsky reaction)

vFkok OR

Q.8¼d½ fQukWy vEyh; O;ogkj iznf”kZr djrk gS D;ksa\ (1)
Phenol is acidic in nature why.

¼[k½ Mkb ,fFky bZFkj dh Lo% vkWDlhdj.k vfHkfØ;k fyf[k,A (1)

3|Page

Page 19

Write auto oxidation reaction of diethyl either.

Q.9 fuEu dks le>kb, & Explain the following. (2x1=2)
¼d½ vf/kdka”k laØe.k rRo fofHkUu vkWDlhdj.k voLFkk;sa iznf”kZr djrs gSaA
Most of the transition elements show variable oxidation states.

¼[k½ laØe.k rRoksas ds vf/kdrj ;kSfxd jaxhu gksrs gS\
Most of the compounds of transition elements are coloured.

Q.10 ,d narqj vkSj mHk; narqj fyxUM ls D;k rkRi;Z gS] izR;sd dk mnkgj.k nhft,A (2)
What is meant by unidentate and ambidentate legands ? Give example for each.

Q.11 fuEu dks cukus ds fy, jklk;fud vfHkfØ;k esas fyf[k,A (2x1=2)
Write Chemical reactions for the preparation of following.

¼d½ DyksjkscsUthu ls Mh0Mh0Vh0 ¼[k½ DyksjkscsUthu ls MkbQsfuy
D.D.T. from chlorobenzene Diphenyl from Chlorobenzene.

Q.12 lqØksl rFkk ySDVksl ds ty vi?kVu ls dkSu ls mRikn izkIr gksrs gS\ jklk;fud vfHkfØ;k
nsdj le>kb,A (2)
What products are formed by the hydrolysis of sucrose and lactose ? Explain with chemical
reactions.
vFkok (OR)
D;k gksrk gS tc ¼dsoy jklk;fud lehdj.k fyf[k, vkSj mRikn dk uke fyf[k,½ (1x2=2)
What happens when (Write Chemical equation only and name the product).

D - Xywdksl fuEu ls vfHkfØ;k djrk gS &
D - Glucose reacts with the following.
¼d½ HNO3 ¼[k½ Qsgfyax foy;u
Fehling Solution

Q.13 ,d ,sjksesfVd ;kSfxd ‘A’ tyh; veksfu;k ds lkFk xeZ djus ij ;kSfxd ‘B’ cukrk gS tks Br2
,oa KOH ds lkFk xeZ djus ij v.kqlw= C6H7N okyk ;kSfxd ‘C’ cukrk gSA A, B rFkk C
;kSfxdksa dh lajpuk ,oa buds IUPAC uke fyf[k,A (2)
An aromatic compound ‘A’ on treatment with aqueous ammonia and heating form compound
‘B’ which on heating with Br2 and KOH forms a compound ‘C’ of molecular formula
C6H7N. Write the structures and IUPAC names of compounds (A) (B) and (C)

Q.14 ,d inkFkZ ds 10 xzke dks 100 xzke foyk;d esa ?kksyus ij DoFkukad esa 10c dh o`f) ik;h tkrh
gSA inkFkZ ds v.kqHkkj dh x.kuk dhft,A ¼foyk;d gsrq Kb = 2.53 k kg mol-1½ (2)

When 10 gm of a substance was dissolved in 100 gm solvent, observed elevation is boiling
point was 10C. Calculate the molecular weight of the substance. [K b for solvent is 2.53 k
kg mol-1]

4|Page

Page 20

Q.15 HCl, NaCl rFkk CH3 COONa ds fy,  m ds eku Øe”k% 426-1] 126-5 rFkk 91-0 mho cm2
0

mol-1 gSA CH3 COOH ds fy,  m ds eku dh x.kuk dhft,A
0
(2)
0m of HCl, NaCl and CH3COONa are 426.1, 126.5 and 91.0 mho cm2 mol-1 respectively.
Calculate 0 m for CH3 COOH.

Q.16 fuEu vfHkfØ;kvksa dks iw.kZ dhft,A (3)
Complete the following reactions.
(i) C2H5 OH + NH3 Al2O3 ………….
4500C

(ii) RNH2 + CHCl3 + 3 KOH (alc) …..…..

(iii) C6 H5 NH2 + HCl ……… + HNO2 273K ………. + 2H2O

Q.17 ¼d½ fn;s x;s lsy dh lsy vfHkfØ;k;sa fyf[k,A (1)
Write Cell reactions of the given Cell.
Zn (S) ǀ Zn++ (aq) ǀǀ Ag+ (aq) ǀ Ag (s)

¼[k½ “kq’d lsy dh lajpuk fyf[k, rFkk lsy vfHkfØ;k,sa nhft,A (2)
Describe the construction of a dry cell and write the cell reactions.

Q.18 fuEufyf[kr inkssa dks ifjHkkf’kr dhft,A (1x3=3)
Define the following terms.
¼d½ eksy va”k (Mole fraction) ¼[k½ eksyyrk (Molality)
¼x½ nzO;eku izfr”kr (Mass Percentage) (3)

vFkok (OR)

2.5gm ,sFksuksbd vEy (CH3COOH) ds 75 xzke csUthu esa foy;u dh eksyyrk dh x.kuk
dhft,A (3)
Calculate molality of 2.5 gm ethanoic acid (CH3COOH) in 75 gm of benzene.

Q.19 la;kstdrk vkca/k fl)kUr dks la{ksi esa le>kb,A bl fl)kUr ds vk/kkj ij ladqy vk;u
[Fe(CN)6]4 - ds T;kferh; rFkk pqEcdh; O;ogkj dks Li’V dhft,A (3)

Briefly explain the Valence Bond theory. Explain the geometrical and magnetic behavior of
complex ion [Fe(CN)6]4 - on the basis of this theory.

vFkok (OR)

fuEufyf[kr dks mnkgj.k lfgr le>kb, & Explain the following with example.
¼d½ leUo; lewg ¼[k½ fyxUM ¼x½ milgla;kstu la[;k
Co-ordination Entity Ligand Co-ordination number

5|Page

Page 21

Q.20 fuEufyf[kr ij laf{kIr fVIi.kh fyf[k,A Write short notes on following. (3)
¼d½ ,YMksy la?kuu ¼[k½ vehuksvi?kVu ¼x½ Mkb,stksdj.k
Aldol Condensation Ammonolysis Diazotisation

Q.21 fuEu uke vfHkfØ;k;sa ds jklk;fud lehdj.k nhft,A (3)
Give Chemical equations for the following name reactions.

¼i½ oksYQ fd”uj vip;u (ii) fofy;elu bZFkj la”ys’k.k (iii) dksYcs f”eV vfHkfØ;k
Wolff Kishner reduction Williamson Ether Synthesis (Kolbe Schmitt reaction)

Q.22 iz;ksx”kkyk esa DyksjksQkeZ cukus dh fof/k ds jklk;fud lehdj.k fyf[k,A (3)
Write Chemical reactions for the preparation of chloroform in the laboratory.

Q.23 fuEufyf[kr ij laf{kIr fVIi.kh fyf[k,A Write Short notes on following. (3)
¼d½ fToVj vk;u ¼[k½ U;qfDy;ksVkbM ¼x½ XykbdkslkbfMd cU/k
Zwitter ion Nucleotide Glycosidic bond

Q.24 ¼d½ izFke dksfV dh vfHkfØ;k ds fy, lekdfyr osx lehdj.k dh O;qRifRr dhft,A (3)
Derive the integrated rate equation for the first order reaction.

¼[k½ izFke dksfV dh vfHkfØ;k ds fy, osx fLFkjkad K dk eku 5.5x10–14 s-1 ik;k x;kA bl
vfHkfØ;k ds fy, v)Zvk;q dh x.kuk dhft,A (1)
A first order reaction is found to have rate constant K = 5.5x10 –14 s-1. Calculate half life of the
reaction.
vFkok (OR)
¼d½ n”kkZb, fd izFke dksfV dh vfHkfØ;k esa 99.9% vfHkfØ;k iw.kZ gksus esa yxk le; v)Zvk;q
(t1/2) dk 10 xquk gksrk gSA (2)
Show that in a first order reaction the time taken to complete 99.9%. the reaction is 10 times
the half life (t1/2).

¼[k½ H2O2 ds fo?kVu dh cyxfrdh dk v/;;u fdl izdkj fd;k tkrk gSA (2)
How the study of Kinetics is made for decomposition of H 2O2.

Q.25 ,d dkcZu ;kSfxd [A] ftldk v.kqlw= C3H6O gSA vk;MksQkeZ vfHkfØ;k nsrk gS vkSj ;kSfxd
[B] cukrk gSA ;kSfxd [B] pk¡nh ds pw.kZ ds lkFk xeZ djus ij ;kSfxd [C] esa cny tkrk gSA
;kSfxd [C] dh vfHkfØ;k ruq lY¶;qfjd vEy o eD;Zqfjd lYQsV ls djus ij ;kSfxd [D]
izkIr gksrk gS] tks ,YMksy la?kuu vfHkfØ;k nsrk gSa] ;kSfxd [A] ls ;kSfxd [D] rd lHkh ds
uke fyf[k, rFkk izR;sd in ds ifjorZu ds fy, jk;klfud lehdj.k fyf[k,A (4)

An Organic compound [A] whose molecular formula is C3H6O, gives Iodoform reaction and
forms compound [B]. Compound [B], when heated with silver powder converts into
compound [C] reacts with dil. Sulphuric acid and Mercuric Sulphate to obtain compound
[D], which gives Aldol condensation reaction. Write down the name of all compounds from
[A] to [D] and write chemical equation for each step.
6|Page

Page 22

vFkok / OR
fuEu jklk;fud vfHkfØ;k esa cuus okys izeq[k mRiknksa ds uke fyf[k, vkSj izR;sd vfHkfØ;k ds
fy, jklk;fud lehdj.k fyf[k,A (1x4=4)

Name the main products formed in following chemical reaction and write the chemical
equation for each reaction.

¼d½ ,slhVksu dks fojatd pw.kZ ds lkFk xeZ djrs gSaA
Acetone is heated with bleaching powder.

¼[k½ QkesZfYMgkbM dh fØ;k veksfu;k ls gksrh gSA
Formalrehyde is treated with ammonia.

¼x½ lksfM;e ,lhVsV] lksMkykbe ls fØ;k djrk gSA
Sodium acetate to treated with sodalime.

¼?k½ csUtksby DyksjkbM] Pd / BaSO4 dh mifLFkfr esa gkbMªkstu ls fØ;k djrk gSA
Benzoyle chloride reacts with hydrogen in presence of Pd/BaSO 4

Q.26 fuEufyf[kr vuqPNsn dks /;kuiwoZd if<+, rFkk blds uhps fn;s x;s iz”uksa ds mRrj nhft,A
Read the following passage carefully and answer the questions given below.

f – CykWd rRo os gksrs gSa] ftuesa foHksnd bysDVªkWu (n-2) f d{kkvksa esa izos”k djrs gSaA f – CykWd
rRoksa dh nks Jsf.k;k¡ gksrh gS tks Øe”k% 4f vkSj 5f d{kkvksa ds Hkjus ls lEcfU/kr gSA 4f d{kkvksa
dh J`a[kyk dks ySaFksukbM~l (Larthanides) dgk tkrk gSA yaSFksukbM~l fofHkUu vkWDlhdj.k
voLFkk,sa iznf”kZr djrs gSa tks f0 f7 vkSj f14 foU;klksa dh fLFkjrk ij fuHkZj djrh gS gkykafd
lcls lkekU; vkWDlhdj.k voLFkk +3 gksrh gSA ijek.kq la[;k c<+us ds lkFk ySaFksukbM vk;uksa
ds vkdkj esa ,d fu;fer deh gksrh gS] ftls ySaFksukbM ladqpu (Lanthanide Contraction) dgk
tkrk gSA
The f block elements are those in which the differentiating electron enters the (n-2) f orbital.
There are two series of f-block elements corresponding to fitting of 4 f and 5f orbitals. The
series of 4f orbital is called lanthanoids. Lanthanoids show different oxidation states
depending upon stability of f0 f7 and f14 configurations though the most common oxidation
state is +3. There is a regular decrease in the size of Lanthanoids ions with increase in atomic
number which is known as lanthanoid contraction. (4x1=4)

¼d½ rhu ySaFksukbM rRo X, Y vkSj Z ftudh ijek.kq la[;k,sa Øe”k% 65] 68 vkSj 70 gSa] muds Ln3+
vk;uksa dk bysDVªkWfud foU;kl gS &

The atomic number of three lanthanoid elements X, Y and Z are 65, 68 and 70 respectively,
their Ln3+ electronic configuration is.
(a) 4f8, 4f11, 4f13 (b) 4f11, 4f8, 4f13
(c) 4f0, 4f2, 4f11 (d) 4f3, 4f7, 4f9

7|Page

Page 23

¼[k½ ySaFksukbM ladqpu (Lanthanoid Contraction) ns[kk tkrk gSA
Lanthanoid Contraction is observed in
(a) Gd (b) At (c) Xe (d) Te

¼x½ ySaFksukbM Js.kh dk og lnL; crkb, tks $ 4 vkWDlhdj.k voLFkk dks vPNh rjg iznf”kZr
djrk gSA
Name a number of the lanthanoids series which is well known to exhibit +4 oxidation state.

¼d½ lsfj;e (Cerium, Z = 58) ¼[k½ ;wjksfi;e (Europium, Z = 63)
¼x½ ySaFksue (Lanthanum, Z = 57) ¼?k½ xSMksfyfu;e (Gadolinium Z = 64)
¼?k½ fuEufyf[kr esa ls dkSu lk foU;kl ySaFksukbM dk ugha gS\
Which of the following is not the configuration of Lanthanoid ?
(a) [Xe] 4f10 6s2 (b) [Xe] 4f1 5 d1 6s2
(c) [Xe] 4f14, 5d10 6s2 (d) [Xe] 4f7 5d1 6s2

-x-x-x-x-x-x-x-x-

8|Page

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Study Materials
Notes

Model Papers Class 6 Notes

Sample Papers Class 7 Notes
Half Yearly Sample Papers Class 8 Notes

Class 9 Notes
Important Resources
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Document Details

Board / OrgUttarakhand Board
ExamClass 12
TypeSample Paper
Pages25
Updated24 Sep 2026