Uttarakhand Board Class 12 Sample Paper 2026 Physics

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UBSE Sample Question Papers 2026
रोल नं. मु दत प ृ ठ क सं या :
RollNo. Number of printed page : 07
भौ तक व ान (सै धां तक)
2026
PHYSICS (Theory)
समय : 3 घंटे] [ पण
ू ाक :70
Time :3 Hours] [ Max. Marks70

नदश : (i) इस नi= म कुल 26 न है aA सभी न अ नवाय है I
Directions :There are in all 26 questions in the question paper. All questions are
compulsory.
(ii) न हे तु नधा रत अंक उनके स मुख अं कत है l
Marks allotted to the questions are mentioned against them.
)iii) येक न को यानपूवक प ढ़ए तथा समु चत उ र द िजएI
Read each question carefully and answer to the point.
(iv) न सं या 1 बहु वक पीय न है I इस न के येक ख ड के उ र म चार वक प दए गए हI
सह वक प अपनी उ र पिु तका म ल खएI न सं या 2से 5तक नि चत उ र य न है a l
Question No. 1 is multiple choice question. Four options are given in answer of each part of this
question.Write correct option in your answer book.Question No. 2 to 5 are definite answer type
questions.
(v) न सं या 1 का येक ख ड एक अंक का है I न सं या 2से 5तक एक अंक के न है I
न सं या 6से 15तक दो तक अंक के न है I न सं या 16से 23तक तीन अंक के न है l
न सं या 24से 26तक चार अंक के न है , िजसम न सं या 26केस/ ोत आधा रत न है I
Each part of Question No. 1 carries one mark. Question No. 2 to 5 are of one marks each. Question
No. 6 to 15 are of two marks each. Question No. 16 to 23 are of three marks each. Question No. 24 to
26 are of four marks each, in which Question No. 26 is Case/ Source based question.
(vi) इस न प म सम पर कोई वक प नह ं है तथा प क तपय न म आंत रक वक प दान
कया गया है । ऐसे न म केवल एक वक प का ह उ र द िजए।
There is no overall choice in this question paper, however, an internal choice has been provided in few
questions. Attempt only one of the given choices in such questions.
(vii) जहाँ आव यक हो आप न न ल खत भौ तक नयतांक के मान का उपयोग कर सकते हI
Wherever necessary, you may use the values of following physical constants-
e=3x108ms-1, h=6.6x10-34Js, e =1.6x10-19C,μ0 =4πx10-7 TmA-1 , =9x109N m2c-2
इले ॉन क संह त (mass of electron) me= 9.1x10-31kg, यू ॉन क संह त )mass of neutron)

mn=1.67x10-27Kg, बो जमान नयतांक(Boltzmann’s Constant) k=1.381x10-23JK-1,
आवोगा ो सं या(Avogadro Number) NA=6.02x1023 mol-1.

[Physics] [1] [P.T.O.

1. (keâ) Skeâ meceevlej huesš mebOeeefj$e keâer Oeeefjlee efveYe&j keâjleer nw- 1
The capacitance of a parallel plate capacitor depends on-
(i) huesšesb kesâ yeerÛe he=Lekeâve hej (ii) DeeJesMe hej
Separation between the plates Charge
(iii) huesšeW kesâ efmejeW kesâ yeerÛe efJeYeJeeblej hej (iv) Ùes meYeer
Potential difference across plates All of these
(Ke) peye DeeJesefMele keâCeeW kesâ yeerÛe keâer otjer DeeOeer keâj oer peeleer nw lees Gvekesâ yeerÛe yeue nes peelee nw- 1
When the distance between the charged particles is halved, the force between them
becomes.
(i) Skeâ ÛeewLeeF& (ii) DeeOee (iii) oesiegvee (iv) Ûeej iegvee
One-fourth Half Double Four times
(ie) efvecve ceW mener mecyevOe nw- 1
In following, the correct relation is-
(i) 1 šsmuee =10–4 ieeGme (ii) 1 šsmuee =1000 ieeGme
1 tesla=10–4 gauss 1 tesla=1000 gauss
(iii) 1 šsmuee =10 ieeGme 4
(iv)1 šsmuee =10–3 ieeGme
1 tesla=104 gauss 1 tesla=10–3 gauss
(Ie) Skeâ DeeJesMe q, Skeâ meceeve ÛegcyekeâerÙe #es$e ceW ieefle keâj jne nw, Fme hej keâeÙe& keâjves Jeeuee ÛegcyekeâerÙe yeue efveYe&j veneR
keâjlee nw- 1
A charge q is moving in a uniform magnetic field. The magnetic force acting on it does
not depend on-
(i) Jesie hej (ii) õJÙeceeve hej (iii) DeeJesMe hej (iv) ÛegbyekeâerÙe #es$e hej
Velocity Mass Charge Magnetic field
(*) efkeâmeer JewÅegle ÛegcyekeâerÙe lejbie ceW efJeÅegleerÙe SJeb ÛegcyekeâerÙe #es$e nesles nQ- 1
In an electromagnetic wave, the electric and magnetic field are-
(i) hejmhej meceeblej (ii) hejmhej uebyeJele
Mutually parallel Mutually perpendicular
(iii) hejmhej efJehejerle (iv) hejmhej eflejÚs
Mutually opposite Mutually oblique
(Ûe) efvecve ceW mes keâewve mee mebyebOe ‘cesueme keâe efveÙece’ ØeoefMe&le keâjlee nw- 1
Which one of the following relation represents the 'Malus law'-
(i) I=I0 sin  (ii) I=I0 cos  (iii) I=I0 sin2 (iv) I=I0 cos2
(Ú) ØekeâeefMekeâ leblegDeeW ceW GheÙeesie keâer peeves Jeeueer heefjIešvee nw- 1
The phenomenon used in optical fibres is-
(i) hetCe& Deevleefjkeâ hejeJele&ve (ii) ØekeâeMe keâe efJeJele&ve
Total internal reflection Diffraction of light
(iii) mebhees<eer JÙeeflekeâjCe (iv) ØekeâeMe keâe JeCe& efJe#esheCe

Constructive interference Dispersion of light
(pe) efkeâmeer veeefYekeâ keâes mebkesâle efÛeåve AZX Éeje ØeoefMe&le efkeâÙee peelee nQ FmeceW vÙetefkeäueÙee@veeW keâer mebKÙee nw- 1
A
A nucleus is shown by the notation ZX. The number of nucleons in it is-

(i) Z (ii) A (iii) A+Z (iv) A–Z
[Physics] [2]

efveoxMe : ØeMve mebKÙee-1 kesâ Deieues oes KeC[eW ceW, oes keâLeveeW keâes DeefYekeâLeve (A) leLee keâejCe (R)kesâ ¤he ceW efÛeefvnle efkeâÙee ieÙee nw~
efvecveefueefKele efJekeâuheeW (i), (ii), (iii) leLee (iv) ceW mes Ûegvekeâj Fvekeâe mener Gòej oerefpeS~
Direction : In next two parts of Question No.-1, there are two statements labelled as
Assertion (A) and Reason (R). From the following options (i), (ii), (iii) and (iv),
select their correct answer.
(i) A leLee R oesveeW mener nQ leLee R, A keâer mener JÙeeKÙee keâjlee nw~
Both A and R are correct and R is the correct explanation of A.
(ii) A leLee R oesveeW mener nQ hejvleg R, A keâer mener JÙeeKÙee veneR keâjlee nw~
Both A and R are correct but R is not the correct explanation of A.
(iii) A mener nw hejvleg R ieuele nw~
A is correct but R is incorrect.
(iv) AleLee R oesveeW ieuele nQ~
Both A and R are incorrect.
(Pe) DeefYekeâLeve (A) : n-Øekeâej kesâ Deæ&ÛeeuekeâeW ceW Fuewkeäš^e@ve, yengmebKÙekeâ DeeJesMe Jeenkeâ nesles nQ
keâejCe (R) : n-Øekeâej kesâ Deæ&ÛeeuekeâeW ceW ef$emebÙeespeer hejceeCeg Deheefceßekeâ nw~ 1
Assertion (A): Electrons are majority charge carrier in n-type semiconductors.
Reason (R) : In n-type semiconductors, trivalent atoms are the dopants.
(_e) DeefYekeâLeve (A) : hejceeCeg kegâue efceueekeâj JewÅegle Goemeerve neslee nw~
keâejCe(R) : hejceeCeg ceW OeveeJesMe Deewj $e+CeeJesMe keâer cee$eeSb meceeve nesleer nQ~ 1
Assertion (A): Atom, as a whole, is electrically neutral.
Reason (R) : Atom contains equal amount of positive and negative charges.
2. ketâuee@ce keâe efveÙece, vÙetšve kesâ ieefle kesâ efkeâme efveÙece kesâ Deveg™he nw? 1
Coulomb's law agrees with which Newton's law of motion?
3. ‘š^ebmeheâece&j, DevÙeesvÙe ØesjCe kesâ efmeæevle hej DeeOeeefjle Skeâ Ùegefòeâ nw~’ Ùen keâLeve melÙe nw Ùee DemelÙe? 1
'Transformer is a device based on the principle of mutual induction'. Is this statement True
or False?
4. efjòeâ mLeeve keâer hetefle& keâerefpeS- 1
Fill in the blank-
Ùeefo ceeOÙece ceW lejbieW Skeâ efyevog-œeesle mes Glmeefpe&le nes jner neW lees lejbiee«e keâe Deekeâej ..............neslee nw~
In a medium, if waves emit from a point-source then the shape of wavefront is ________.
5. DeheõJÙeer Deæ&Ûeeuekeâ kesâ oes Øekeâej keâewve mes nQ? 1
Which are the two types of extrinsic semiconductors?
6. Tve mes jieÌ[s peeves hej keâesF& hee@ueerLeerve keâe šgkeâÌ[e 3×10–7 C kesâ $e+CeeJesMe mes DeeJesefMele heeÙee ieÙee~ mLeeveevleefjle Fuewkeäš^e@veeW keâer
mebKÙee Deekeâefuele keâerefpeS~ 2
–7
A polythene piece rubbed with wool is found to have a negative charge of 3×10 C. Estimate

the number of electrons transferred.
7. pees Jeenve pJeueveMeerue heoeLe& ues peeles nQ, Gvekeâer Oeeleg keâer pebpeerjW Jeenve kesâ ieefleceÙe nesves hej Oejleer Útleer jnleer nQ~ keäÙeeW?
2
Vehicles carrying inflammable materials usually have metallic ropes touching the ground
during motion. Why?
[Physics] [3] [P.T.O.

8. Ùeefo e1 Je e2 efJeÅegle Jeenkeâ yeue Deewj r1 Je r2 Deebleefjkeâ ØeeflejesOe Jeeues oes mesue heeMJe& ›eâce ceW mebÙeesefpele nes lees Gvekesâ heeMJe&
mebÙeespeve kesâ leguÙe efJeÅegle Jeenkeâ yeue SJeb leguÙe Deebleefjkeâ ØeeflejesOe keâe JÙebpekeâ efueefKeS~ 2
If two cells of emf e1& e2 and internal resistance r1& r2 are connected in parallel order, then
write the expression for equivalent emf and equivalent internal resistance of their parallel
combination.
9. Skeâ uebyes, meerOes leej ceW 35A efJeÅegle Oeeje ØeJeeefnle nes jner nw, leej mes 20 cm otjer hej efmLele efkeâmeer efyevog hej ÛegbyekeâerÙe #es$e
keâe heefjCeece keäÙee nw? 2
A long straight wire carries a current of 35A. What is the magnitude of magnetic field at a
point 20 cm from the wire?
DeLeJee / OR
ÛegcyekeâerÙe ØeJe=efòe keäÙee nw? Fmekesâ DeeOeej hej ØeefleÛegbyekeâerÙe Je DevegÛegbyekeâerÙe heoeLe& ceW efJeYeso keâerefpeS~
What is magnetic susceptibility? Distinguish between diamagnetic and paramagnetic
substance on its basis.
10. Øesefjle efJeÅegle Jeenkeâ yeue Glhevve keâjves keâer efkeâvneR oes lekeâveerkeâeW keâe GuuesKe keâerefpeS~ 2
Elucidate any two techniques for generating induced electromotive force.
11. efveJee&le ceW cewkeämeJesue kesâ meceerkeâjCeeW keâes efueefKeÙes~ 2
State the Maxwell's equations in vacuum.
12. Ùeefo keâesF& ves$e efÛeefkeâlmekeâ +2.5D #ecelee keâe mebMeesOekeâ ueWme efveOee&efjle keâjlee nw leye ueWme keâer heâeskeâme otjer SJeb Øeke=âefle keäÙee
nesieer? 2
If an optician prescribes a corrective lens of power +2.5D, then what will be focal length
and nature of lens?
13. efkeâmeer Oeeleg kesâ ‘keâeÙe&heâueve’ keâes heefjYeeef<ele keâerefpeS~ Ùen Fuewkeäš^e@veeW kesâ Glmepe&ve mes efkeâme Øekeâej mecyeefvOele nw? 2
Define the 'work function' on a metal. How is it related to the emission of electrons?
14. neF[^espeve hejceeCeg kesâ efueS yeesnj kesâ Gme DeefYeie=nerle keâes yeleeFÙes pees meb›eâceCe ceW Glmeefpe&le heâesše@ve keâer DeeJe=efòe kesâ efueS mebyebOe
oslee nw~ 2
State Bohr postulate of hydrogen atom that gives the relationship for the frequency of
emitted photon in a transition.
DeLeJee / OR
1 gm heoeLe& kesâ meceleguÙe Tpee& keâes heefjkeâefuele keâerefpeS~
Calculate the energy equivalent to 1 gm to substance.
15. Deæ&-lejbie efo°keâjCe ceW- 2
(i) Ùeefo efveJesMeer DeeJe=efòe 50Hz nw lees efveie&le DeeJe=efòe keäÙee nw?
(ii) meceeve efveJesMeer DeeJe=efòe kesâ efueS hetCe& lejbie efo°keâejer keâer efveie&le DeeJe=efòe keäÙee nw?
In half-wave rectification-
(i) What is the output frequency if the input frequency is 50Hz?
(ii) What is the output frequency of a full wave rectifier for the same input frequency?

16. ieeGme kesâ efveÙece keâer meneÙelee mes Deveble uecyeeF& kesâ Skeâ meceeve DeeJesefMele leej kesâ efvekeâš JewÅegle #es$e keâer leer›elee kesâ efueS JÙebpekeâ
Øeehle keâerefpeS~ 3
Find the expression for electric field intensity near an infinitely long straight uniformly
charged wire with the help of Gauss's law.

[Physics] [4]

DeLeJee / OR
efkeâmeer Jee¢e JewÅegle #es$e ceW keâesF& hejeJewÅegle efkeâme Øekeâej Skeâ vewš efÉOeÇgJe DeeIetCe& efJekeâefmele keâjlee nw? efÛe$e meefnle mhe° keâerefpeS~
How does a dielectric develop net dipole moment in an external electric field? Clarify with
figure.
17. Skeâ iewuJesveesceeršj keâes efkeâme Øekeâej Ssceeršj leLee Jeesušceeršj ceW ™heebleefjle efkeâÙee peelee nw? DeeJeMÙekeâ DeejsKe osles ngS mecePeeFS~
3
How is the conversion of a galvanometer into an ammeter and a voltmeter take-place?
Explain with necessary diagram.
18. 15 F keâe Skeâ mebOeeefj$e 220 V, 50 Hz œeesle mes peesÌ[e ieÙee nw, heefjheLe keâe mebOeeefj$eerÙe ØeefleIeele leLee FmeceW ØeJeeefnle nesves
Jeeueer (rms SJeb efMeKej) Oeeje keâe ceeve yeleeFS, Ùeefo DeeJe=efòe keâes oesiegvee keâj efoÙee peeS lees mebIeeefj$eerÙe ØeefleIeele Deewj Oeeje kesâ ceeve
hej keäÙee ØeYeeJe heÌ[siee? 3
A 15 F capacitor is connected to a 220 V, 50 Hz sources. Find the capacitive reactance and
the current (rms and peak) in the circuit. If the frequency is doubled, what happens to the
capacitive reactance and the current.
DeLeJee / OR
LCR ßesCeer heefjheLe kesâ efueS Devegveeoer DeeJe=efòe keâe JÙebpekeâ %eele keâerefpeS, jsef[Ùees Deewj šer Jeer mewš kesâ mecemJejCe keâer ef›eâÙeeefJeefOe ceW
Devegveeoer DeeJe=efòe keâe cenlJe mecePeeFS~
Find the expression of resonant frequency for a LCR series circuit. Explain the significance
of resonant frequency in tuning mechanism of a radio and TV set.
19. mebÙegkeäle met#ceoMeea Éeje Øeefleefyebye yeveves keâe efkeâjCe DeejsKe yeveeFÙes leLee yeleeFÙes efkeâ efkeâmeer mebÙegkeäle met#ceoMeea kesâ DeefYeÂMÙekeâ
ueWme leLee vesef$ekeâe ueWme oesveeW keâes ner Heâeskeâme otjer keâce keäÙeeW nesveer ÛeeefnS? 3
Draw the ray diagram for the formation of image by a compound microscope and tell why
must both the objective and eye pieces of a compound microscope have short focal lengths.
20. 1, 2SJeb 3 lejbieowOÙeeX keâer leerve JewÅegle ÛegbyekeâerÙe lejbieeW keâe GheÙeesie ›eâceMe: j[ej ØeCeeueer, peue MeesOekeâ leLee šerJeer kesâ efjceesš
efveÙeb$ekeâeW ceW neslee nw~
Electromagnetic waves of wavelengths 1, 2 and 3 are used in radar system, in water
purifiers and in remote switches of TV respectively.
(i) Fve JewÅegle ÛegbyekeâerÙe lejbieeW lejbieeW keâer henÛeeve keâerefpeS~ 1½
Identify the electromagnetic waves.
(ii) FveceW mes ØelÙeskeâ keâe Skeâ œeesle efueefKeÙes~ 1½
Write one source of each of them.
21. õJÙe keâer lejbie Øeke=âefle kesâ mecyevOe ceW os yeÇe@iueer keâe meceerkeâjCe Øemlegle keâerefpeS~ Ssmeer oes heefjIešveeDeeW keâe GuuesKe keâerefpeS pees
efJeefkeâjCe keâer keâCe Øeke=âefle keâer hegef° keâjleer nQ~ 3
Give de-Broglie's relation in context of wave nature of matter. State two phenomenons
which verify the particle nature of radiation.

22. neF[^espeve hejceeCeg keâer efvecvelece DeJemLee ceW Tpee&-13.6 eV nw, Fme DeJemLee ceW Fuewkeäš^e@ve keâer ieeflepe Deewj efmLeeflepe Tpee&Sb keäÙee
nesieer? 3
The ground state energy of hydrogen atom is -13.6 eV. What are the kinetic and potential
energies of electron in this state.

[Physics] [5] [P.T.O.

DeLeJee / OR
DeeJeMÙekeâ DeefYeef›eâÙeeÙeW osles ngS mecePeeFÙes efkeâ veeefYekeâerÙe efJeKeC[ve ceW Tpee& kewâmes efveÙegkeäle nesleer nw~
Explain giving necessary reactions, how energy is released during nuclear fission.
23. Tpee&yeQ[ mes keäÙee DeefYeØeeÙe nw? Tpee&yeQ[ Deblejeue, heoeLe& keâer efJeÅegle Ûeeuekeâlee keâes efkeâme Øekeâej ØeYeeefJele keâjlee nw? 3
What is meant by Energy Band? How does the energy band gap affect the electrical
conductivity of the material.
24. JewÅegle #es$e ceW efkeâmeer efyevog hej efmLej JewÅegle efJeYeJe mes Deehe keäÙee mecePeles nQ, oMee&FS efkeâ JewÅegle efÉOeÇgJe kesâ keâejCe efkeâmeer efyevog hej
efJeYeJe kesâJeue otjer r hej ner efveYe&j veneR keâjlee, Jejved efmLeefle meefoMe leLee efÉOeÇgJe DeeIetCe& kesâ yeerÛe kesâ keâesCe hej Yeer efveYe&j keâjlee
nw~ 4
What do you understand by electrostatic potential at a point in an electric field. Show that
the potential at a point due to electric dipole depends not just on distance r but also on the
angle between the position vector and the dipole moment .
DeLeJee / OR
Jneršmšesve mesleg keâer MetvÙe efJe#eshe DeJemLee kesâ efueS meblegueve ØeefleyebOe efueefKeS~ Skeâ Jneršmšesve mesleg keâer Ûeej YegpeeDeeW kesâ ØeeflejesOe
efvecveJele nQ:
AB=100, BC=10, CD=5leLee DA=60, 15 ØeeflejesOe kesâ Skeâ iewuJesveesceeršj keâes BD kesâ yeerÛe ceW peesÌ[e ieÙee
nw~ iewuJesveesceeršj mes ØeJeeefnle nesves Jeeueer Oeeje keâes heefjkeâefuele keâerefpeS Ùeefo AC kesâ ceOÙe 10V efJeYeJeevlej nw~
Write the balance condition for null deflection position of Wheatstone Bridge.
The four arms of a Wheatstone Bridge have the following resistances AB=100, BC=10,
CD=5 and DA=60. A galvanometer of 15 resistance is connected across BD. Calculate
the current through the galvanometer when a potential differences of 10V is maintained
across AC.

25. oes uecyes meceevlej OeejeJeener ÛeeuekeâeW kesâ yeerÛe keâeÙe& keâjves Jeeues yeue kesâ efueS JÙebpekeâ Øeehle keâerefpeS~ efkeâve efmLeefleÙeeW ceW Ùen yeue
Deekeâ<e&Ce DeLeJee Øeeflekeâ<e&Ce keâe neslee nw? efJeÅegle Oeeje kesâ SI cee$ekeâ keâer heefjYee<ee mLeeefhele keâjves kesâ efueS Fme meceerkeâjCe keâe

GheÙeesie keâerefpeS~ 4
Obtain an expression for the force acting between two lengthy, parallel conductors carrying
electric current. In which conditions, this force is attractive on repulsive? Utilize this
equation to establish the definition of the SI unit of electric current.
[Physics] [6]

DeLeJee / OR
Deehe kewâmes mecePeeÙeWies efkeâ ÚÌ[ Ûegcyekeâ, Skeâ OeejeJeener heefjveeefuekeâe keâer lejn JÙeJenej keâjlee nw? efkeâmeer Úesšs ÚÌ[ Ûegcyekeâ keâe
ÛegcyekeâerÙe DeeIetCe&0.48 JT–1 nw, Ûegbyekeâ kesâ kesâvõ mes 10 cm keâer otjer hej efmLele efkeâmeer efyevog hej Fmekesâ ÛegbyekeâerÙe #es$e keâe
heefjCeece SJeb efoMee yeleeFÙes Ùeefo Ùen efyevog -
How will you explain that a bar magnet acts as a current-carrying solenoid?
A short bar magnet has a magnetic moment of 0.48 JT –1. Give the direction and magnitude
of the magnetic field produced by the magnet at a distance of 10 cm from the centre of
magnet.
(i) Ûegcyekeâ kesâ De#e hej efmLele nes~
On the axis of magnet
(ii) Ûegcyekeâ kesâ DeefYeuebye meceefÉYeepekeâ hej efmLele nes~
On the equatorial line (normal bisector) of magent
26. efvecveefueefKele DevegÛÚso keâes OÙeevehetJe&keâ heefÌ{Ùes leLee Fmekesâ veerÛes efoÙes ieS ØeMveeW kesâ Gòej efueefKeÙes~
Read the following passage carefully and answer the questions given below:
peye oes Ùee oes mes DeefOekeâ ØekeâeMe œeesle Skeâ ner efyevog keâes Øeoerhle keâjles nQ lees lejbieeW kesâ DeOÙeejesheCe keâe efmeæevle ueeiet neslee nw,
Deye Ùeefo oes œeesle keâueemebyebæ nQ lees efkeâmeer Yeer efyevog hej keâueevlej meceÙe kesâ meeLe veneR yeouesiee leLee nceW efmLej JÙeeflekeâjCe
hewšve& Øeehle nesiee, DeLee&le meceÙe kesâ meeLe GefÛÛe‰ leLee efveefcve‰ keâer efmLeefleÙeeB veneR yeoueWieer, he=Lekeâlee d Jeeueer še@ceme Ùebie keâer
efÉefPejer mes meceeve Deblejeue keâer JÙeeflekeâjCe eføebâpeW Øeehle nesleer nQ~
The principle of superposition of waves applies whenever two or more sources of light
illuminate the same point. Now if the two sources are coherent then the phase difference 
at any point will not change with time and we will have a stable interference pattern i.e. the
positions of maxima and minima will not change with time. Thomas Young's double slit of
separation d gives equally spaced interference fringes.
(i) lejbieeW kesâ DeOÙeejesheCe keâe efmeæevle yeleeFÙes~ 1
State the principle of superposition of waves.
(ii) mLeeÙeer JÙeeflekeâjCe hewšve& kesâ efueS DeeJeMÙekeâ Mele& keäÙee nw? 1
What is the essential condition for sustained interference pattern?
(iii) Ùebie kesâ efÉefPejer ØeÙeesie ceW hejos hej Øeehle nesves Jeeues oerhle leLee Deoerhle #es$e keâer efmLeefleÙeeW kesâ efueS ØeefleyevOe efueefKeS~
2
State the condition for position of bright and dark regions obtained on screen in
Youngs' double slit experiment.

[Physics] [7] [P.T.O.
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